removing unwanted files

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diff --git a/Fluid_Mechanics_/Chapter4.ipynb b/Fluid_Mechanics_/Chapter4.ipynb
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+++ /dev/null
@@ -1,529 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:1587038d9ed42ba6cd2ab38d651a00ef2c4ed8f4723b6c6b72bdf9880d8ef943"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Chapter 4 : Fluid Dynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 3,
-     "metadata": {},
-     "source": [
-      "Example 4.1 Page no 159"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "from math import *\n",
-      "\n",
-      "from __future__ import division\n",
-      "\n",
-      "\n",
-      "d1 = 0.1                     # diameter in m\n",
-      "\n",
-      "d2 = 0.05                     # diameter in m\n",
-      "\n",
-      "Q = 0.1                      # discharge in m**3/s\n",
-      "\n",
-      "A1 = pi*d1**2/4\n",
-      "\n",
-      "A2 = pi*d2**2/4\n",
-      "\n",
-      "gma =9810                   # specific weight\n",
-      "\n",
-      "z= 6                        # difference in the height\n",
-      "\n",
-      "g = 9.81\n",
-      "\n",
-      "\n",
-      "V1 = Q/A1                    # velocity at section 1\n",
-      "\n",
-      "V2 = Q/A2                    # velocity at section 2\n",
-      "\n",
-      "dP = gma*((V2**2/(2*g))-(V1**2/(2*g))-z)/1000\n",
-      "\n",
-      "print \"Difference in pressure in section 1 and 2 = \",round(dP,1),\"kN/m**2\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Difference in pressure in section 1 and 2 =  1157.0 kN/m**2\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 3,
-     "metadata": {},
-     "source": [
-      "Example 4.2 Page no 160"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "from math import *\n",
-      "\n",
-      "from __future__ import division\n",
-      "\n",
-      "\n",
-      "d = 2.5                 # diameter in cm\n",
-      "\n",
-      "h =200                        # head in cm\n",
-      "\n",
-      "Cd = 0.65                   # coefficient of discharge\n",
-      "\n",
-      "A  =pi*d**2/4\n",
-      "\n",
-      "g = 9.81                  # acceleration due to gravity in m/s**2 \n",
-      "\n",
-      "\n",
-      "Q = Cd*A*sqrt(2*g*h)/100\n",
-      "\n",
-      "print \"Actual discharge =\",round(Q,2),\"l/s\"\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Actual discharge = 2.0 l/s\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 3,
-     "metadata": {},
-     "source": [
-      "Example 4.3 Page no 162"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "from __future__ import division\n",
-      "\n",
-      "from math import *\n",
-      "\n",
-      "from scipy import integrate\n",
-      "\n",
-      "import numpy as np\n",
-      "\n",
-      "\n",
-      "H1 = 3               # height in m\n",
-      "\n",
-      "H2 = 4               # height in m\n",
-      "\n",
-      "b = 0.5              # width in m\n",
-      "\n",
-      "Cd = 0.65            # co-efficient of discharge \n",
-      "\n",
-      "g = 9.81             # acceleration due to grvity in m/s**2\n",
-      "\n",
-      "\n",
-      "q = lambda h: h**(1/2)\n",
-      "    \n",
-      "Q,err = integrate.quad(q, H1, H2)\n",
-      "\n",
-      "Qt = Cd*b*sqrt(2*g)*Q\n",
-      "\n",
-      "print \"Discharge through the orifice =\",round(Qt,2),\"m**3/s\"\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Discharge through the orifice = 2.69 m**3/s\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 3,
-     "metadata": {},
-     "source": [
-      "Example 4.4 Page no 163"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "    \n",
-      "from math import *\n",
-      "\n",
-      "from scipy import integrate\n",
-      "\n",
-      "from __future__ import division\n",
-      "\n",
-      "import numpy as np\n",
-      "\n",
-      "\n",
-      "b = 1                  # bredth of the tank\n",
-      "\n",
-      "d = 0.5                # depth of the tank\n",
-      "\n",
-      "h1 = 0.2                 # height of the orifice in m\n",
-      "\n",
-      "Cd = 0.6               # coefficient of discharge\n",
-      "\n",
-      "H1 = 2                 # height in m\n",
-      "\n",
-      "H2 = 2+h1               # height in m\n",
-      "\n",
-      "g = 9.81               # acceleration due to gravity in m/s**2\n",
-      "\n",
-      "A = 1*0.3              # area of submerged section in m**2\n",
-      "\n",
-      "\n",
-      "q = lambda h: h**(1/2)\n",
-      "    \n",
-      "Q,err = integrate.quad(q, H1, H2)\n",
-      "\n",
-      "Q1 = Cd*b*sqrt(2*g)*(Q) # Flow through area 1\n",
-      "\n",
-      "Q2 = Cd*sqrt(2*g*H2)*A\n",
-      "\n",
-      "Td = Q1+Q2\n",
-      "\n",
-      "print \"Total Discharge =\",round(Td,2),\"m**3/s\"\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Total Discharge = 1.95 m**3/s\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 3,
-     "metadata": {},
-     "source": [
-      "Example 4.5 Page no 165"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "from math import *\n",
-      "\n",
-      "from __future__ import division\n",
-      "\n",
-      "\n",
-      "d1 = 2               # radius of pipe\n",
-      "\n",
-      "d2 = 1               # radius of throat\n",
-      "\n",
-      "D1 = 40\n",
-      "\n",
-      "D2 = 20\n",
-      "\n",
-      "A1 = pi*D1**2/4\n",
-      "\n",
-      "A2 = pi*D2**2/4\n",
-      "\n",
-      "Cd = 0.95\n",
-      "\n",
-      "\n",
-      "V2 = sqrt(21582/0.9375)\n",
-      "\n",
-      "Q = 1.52*pi*(d1/100)**2/4\n",
-      "\n",
-      "Qa = Q*Cd\n",
-      "\n",
-      "print \"Actual discharge =\",round(Qa,6),\"m**3/s\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Actual discharge = 0.000454 m**3/s\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 3,
-     "metadata": {},
-     "source": [
-      "Example 4.6 Page no 166"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "from math import *\n",
-      "\n",
-      "from __future__ import division\n",
-      "\n",
-      "\n",
-      "dx = 0.5              # in ft\n",
-      "\n",
-      "K = 1                 # constant\n",
-      "\n",
-      "g = 32.2              # acceleration due to gravity in ft/s**2\n",
-      "\n",
-      "\n",
-      "V = sqrt(2*g*dx)\n",
-      "\n",
-      "print \"velocity at the dept of 1 ft =\",round(V,2),\"ft/s\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "velocity at the dept of 1 ft = 5.67 ft/s\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 3,
-     "metadata": {},
-     "source": [
-      "Example no 4.7 Page no 172"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "from math import *\n",
-      "\n",
-      "from __future__ import division\n",
-      "\n",
-      "gma= 0.8      # specific weight\n",
-      "\n",
-      "V2 = 40       # velocity in m/s\n",
-      "\n",
-      "z1 =25        # height at point 1\n",
-      "\n",
-      "g = 9.81      # acceleration due to gravity in m/s**2\n",
-      "\n",
-      "d = 15        # diameter of the nozzle in cm\n",
-      "\n",
-      "\n",
-      "V2 = sqrt(2*g*z1/4.25)\n",
-      "\n",
-      "A = pi*(d/100)**2/4\n",
-      "\n",
-      "Q = A*V2*1000\n",
-      "\n",
-      "print \"Discharge throught the system =\",round(Q,0),\"l/s\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Discharge throught the system = 190.0 l/s\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 3,
-     "metadata": {},
-     "source": [
-      "Example 4.8 Page no 174"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "from math import *\n",
-      "\n",
-      "from __future__ import division\n",
-      "\n",
-      "\n",
-      "\n",
-      "Eff = 0.8     # pump efficiency\n",
-      "\n",
-      "Hl = 30       # head loss in m\n",
-      "\n",
-      "D1 =6         # diameter in cm\n",
-      "\n",
-      "D2 = 2        # diameter in cm\n",
-      "\n",
-      "gma = 9810    # specific weight in N/m**3\n",
-      "\n",
-      "V2 = 40       # velocity in m/s\n",
-      "\n",
-      "P1 = -50      # pressure at point 1 in N/m**2\n",
-      "\n",
-      "z2 = 100      # height at point 2\n",
-      "\n",
-      "g = 9.8       # acceleration due to gravity in m/s**2\n",
-      "\n",
-      "z1 = 30       # height in m\n",
-      "\n",
-      "\n",
-      "V1=(2/6)**2*V2\n",
-      "\n",
-      "Q = (pi*6**2/4)*V1*10**-4\n",
-      "\n",
-      "Hs = z2 + (V2**2/(2*g)) + z1 + (50/gma) -(V1**2/(2*g))\n",
-      "\n",
-      "P = gma*Q*Hs\n",
-      "\n",
-      "Pi = (P/Eff)/1000\n",
-      "\n",
-      "print \"Power input = \",round(Pi,1),\"kW\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Power input =  32.5 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 3,
-     "metadata": {},
-     "source": [
-      "Example 4.9 Page no 176"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "from math import *\n",
-      "\n",
-      "\n",
-      "Q = 0.2           # discharge in m**3/s\n",
-      "\n",
-      "d1 = 0.25           # diameter of the pipe in m\n",
-      "\n",
-      "A = pi*d1**2/4    # area of the pipe\n",
-      "\n",
-      "za = 480          # height in m\n",
-      "\n",
-      "z1 = 500          # height in m\n",
-      "\n",
-      "z3 = 550          # elevation in m\n",
-      "\n",
-      "gma =9810         # specific weight in N/m**2\n",
-      "\n",
-      "g =9.81           # acceleration due to gravity in m/s**2\n",
-      "\n",
-      "\n",
-      "V=Q/A           # Velocity of in m/s\n",
-      "\n",
-      "Hl1 = (0.02*100*V**2/(0.25*2*9.81))\n",
-      "\n",
-      "\n",
-      "Pa =(z1-za-(V**2/(2*g))-Hl1)\n",
-      "\n",
-      "El = za+Pa\n",
-      "\n",
-      "print \"Elevation at height A =\",round(El,2),\"m\"\n",
-      "\n",
-      "\n",
-      "hs = z3 - z1 + (0.02*(500/0.25)*(V**2/(2*g))) \n",
-      "\n",
-      "El2 = El+hs\n",
-      "\n",
-      "print \"Elevation at height B =\",round(El2,2),\"m\"\n",
-      "\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Elevation at height A = 492.39 m\n",
-        "Elevation at height B = 576.23 m\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [],
-     "language": "python",
-     "metadata": {},
-     "outputs": []
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
\ No newline at end of file