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+{
+ "metadata": {
+  "celltoolbar": "Raw Cell Format",
+  "name": "",
+  "signature": "sha256:14402c55600f1e126f448a3051d0be67f94e08a364b1fb28e55e9829f2141c24"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 1: Elements of Optics And Quantum Physics"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.1,Page number 5"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#Given\n",
+      "\n",
+      "print\"(i)  t1=d/c\";\n",
+      "print\"(ii) t2=[(d-5)/c]+[5/v2]\";\n",
+      "print\"     v2=c/n2\";\n",
+      "print\"     t2=(d+2.5)/c\";\n",
+      "print\"(iii)delta_t=t2-t1=(d+2.5-d)/c\";\n",
+      "c=3*10**8;                       #Speed of light in m/s\n",
+      "delta_t=2.5*10**-2/c;            #converted 2.5 cm into meters\n",
+      "print\"The time difference\",\"{0:.3e}\".format(delta_t),\"s\" ;\n",
+      "print\"Arrival time difference of two monochromatic beams is\",delta_t*10**12,\"ps\";\n",
+      "# Answer misprinted in the book\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "(i)  t1=d/c\n",
+        "(ii) t2=[(d-5)/c]+[5/v2]\n",
+        "     v2=c/n2\n",
+        "     t2=(d+2.5)/c\n",
+        "(iii)delta_t=t2-t1=(d+2.5-d)/c\n",
+        "The time difference 8.333e-11 s\n",
+        "Arrival time difference of two monochromatic beams is 83.3333333333 ps\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.2,Page number 5"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given \n",
+      "\n",
+      "#Applying Snell's law\n",
+      "a=1*math.sin(428)/1.333;      #a=sin(w2)\n",
+      "print\"Angle of refraction is\",round(math.degrees(math.asin(a)),3),\"degree\";\n",
+      "\n",
+      "c=3*10**8;          #speed of light in m/s\n",
+      "n2=1.333;           #refractive index of 2nd medium\n",
+      "v2=c/n2;            #velocity in second medium in m/s\n",
+      "n1=1;               #refractive index of 1st medium\n",
+      "l1=620;             #in nm   wavelength\n",
+      "\n",
+      "print\"Velocity of optical ray through medium second\",\"{0:.3e}\".format(v2),\"m/s\";\n",
+      "\n",
+      "l2= (n1*l1)/n2;     #wavelength in 2nd medium in nm\n",
+      "print\"Wavelenght of optical ray through medium second\",round(l2,4),\"nm\";       #Result\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Angle of refraction is 30.512 degree\n",
+        "Velocity of optical ray through medium second 2.251e+08 m/s\n",
+        "Wavelenght of optical ray through medium second 465.1163 nm\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.3,Page number 5"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given \n",
+      "\n",
+      "n1=1;                   #refractive index of air\n",
+      "n2=1.56;                #refractive index of medium\n",
+      "w1=60;                  #in deg C\n",
+      "#using snell's law\n",
+      "a= n1*sin(w1*math.pi/180)/n2;             #a=sin(w1)\n",
+      "w2=math.degrees(math.asin(a));            #in degree\n",
+      "print\"Angle of refraction is\",round(w2,4),\"degree\";\n",
+      "B=w1-w2;                                  #in degree\n",
+      "print\"Angle of deviation is\",round(B,4),\"degree\";\n",
+      "# The answer doesn't match because of priting errorsin calculation as sin(608)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Angle of refraction is 33.7207 degree\n",
+        "Angle of deviation is 26.2793 degree\n"
+       ]
+      }
+     ],
+     "prompt_number": 12
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.4,Page number 6"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given \n",
+      "\n",
+      "print\"Solution (i)\";\n",
+      "w=5/12.5;                     #tan(w)=5/12.5;\n",
+      "print\"The value of tan(w2) is\",w;\n",
+      "w2=math.atan(w)*180/math.pi;\n",
+      "\n",
+      "print\"The value of w2 is\",round(w2,4),\"degree\";\n",
+      "print\"The value of sin(w2) is\",round(math.sin(w2*math.pi/180),4);\n",
+      "\n",
+      "print\"Solution (ii)\";\n",
+      "#Applying snell's law\n",
+      "n1=1.05;\n",
+      "n2=1.5;\n",
+      "w1=(n2*sin(w2*math.pi/180))/n1;  #a=sin(w1)\n",
+      "print\"The value of sin(w1) is\",round(w1,4);\n",
+      "print\"The value of w1 is\",round(math.degrees(math.asin(w1)),4),\"degree\";\n",
+      "#value of w1\n",
+      "#tan(w1)=(p-x)12.5;\n",
+      "k=0.62*12.5;\n",
+      "d=1.05*((12.5)**2+(k)**2)**0.5 +1.5*(12.5**2+5**2)**0.5;       #d=1.05[(h1)^2+(k)^2]^0.5 +n2(h2**2+x**2)^0.5;\n",
+      "print\"The optical distance is\",round(d,4),\"cm\";\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Solution (i)\n",
+        "The value of tan(w2) is 0.4\n",
+        "The value of w2 is 21.8014 degree\n",
+        "The value of sin(w2) is 0.3714\n",
+        "Solution (ii)\n",
+        "The value of sin(w1) is 0.5306\n",
+        "The value of w1 is 32.0432 degree\n",
+        "The optical distance is 35.6373 cm\n"
+       ]
+      }
+     ],
+     "prompt_number": 22
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.5,Page number 11"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given \n",
+      "\n",
+      "c=3*10**8;\n",
+      "print\"Solution (i)\";\n",
+      "ri=1.5;          #refractive index\n",
+      "u=830;           # in nm\n",
+      "l=u/ri;          #in nm\n",
+      "print\"Wavelength is\",round(l,4),\"nm\\n\";\n",
+      "\n",
+      "print\"Solution (ii)\";\n",
+      "l=round(l);                 # rounding to nearest integer\n",
+      "f=c/(l*10**-9)*10**-12;     #in THz\n",
+      "print\"frequency is\",round(f,4),\"THz\\n\";\n",
+      "\n",
+      "print\"Solution (iii)\";\n",
+      "f=round(f);                 #rounding to nearest integer\n",
+      "v=l*10**-9*f*10**12;        #in m/s\n",
+      "print\"phase velocity is\",\"{0:.3e}\".format(v),\"m/s\";\n",
+      "\n",
+      "#answer is getting rounding off due to larger calculation\n",
+      "\n",
+      "\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Solution (i)\n",
+        "Wavelength is 553.3333 nm\n",
+        "\n",
+        "Solution (ii)\n",
+        "frequency is 542.4955 THz\n",
+        "\n",
+        "Solution (iii)\n",
+        "phase velocity is 2.997e+08 m/s\n"
+       ]
+      }
+     ],
+     "prompt_number": 24
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.6,Page number 12"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given \n",
+      "\n",
+      "print\"Solution (i)\";\n",
+      "l=720;          #wavelength in nm\n",
+      "n=1.5;          #refractive index\n",
+      "lm=l/n;\n",
+      "print\"Wavelenth is\",lm,\"nm\";       #result\n",
+      "\n",
+      "print\"Solution (ii)\";\n",
+      "c=3*10**8;      #in m/s speed of light\n",
+      "u=c/n;\n",
+      "print\"Velocity  is\",\"{0:.3e}\".format(u),\"m/s\";       #result\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Solution (i)\n",
+        "Wavelenth is 480.0 nm\n",
+        "Solution (ii)\n",
+        "Velocity  is 2.000e+08 m/s\n"
+       ]
+      }
+     ],
+     "prompt_number": 26
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.7,Page number 12"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given \n",
+      "\n",
+      "print\"Solution (i)\";\n",
+      "c=3*10**8;       #in m/s speed of light\n",
+      "l=640;           #in nm\n",
+      "u=2.2*10**8;     #in m/s\n",
+      "lm=u*l/c;        #wavelenth in medium\n",
+      "print\"The wavelength is\",round(lm,4),\"nm\";       #The answer in the book is misprinted\n",
+      "\n",
+      "print\"Solution (ii)\";\n",
+      "n=l/lm;         #refractive index\n",
+      "print\"Refractive Index is\",round(n,4);        #The answer in the book is misprinted\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Solution (i)\n",
+        "The wavelength is 469.3333 nm\n",
+        "Solution (ii)\n",
+        "Refractive Index is 1.3636\n"
+       ]
+      }
+     ],
+     "prompt_number": 29
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.8,Page number 12"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given \n",
+      "\n",
+      "#k=aa+as=6.3;\n",
+      "#Given values from research\n",
+      "k=6.3;      #combined attenuation due to absorption and scattering\n",
+      "d=25;       #in cm\n",
+      "print\"Solution (ii)\";\n",
+      "#Io/Ii=exp(-(ao+ai)*d);  d in m\n",
+      "j=math.e**(-(k)*d/100);  #Io/Ii ratio\n",
+      "print\"Io is\",round(j,4),\"of Ii\";       #result"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Solution (ii)\n",
+        "Io is 0.207 of Ii\n"
+       ]
+      }
+     ],
+     "prompt_number": 30
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.9,Page number 13"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given \n",
+      "\n",
+      "# Given formula   Io/Ii=exp(-(ao+ai)*d);\n",
+      "# k=aa+as=63.1;\n",
+      "# Io/Ii=1.5\n",
+      "d=log(0.15)/-63.1;       #length of tube\n",
+      "print\"Length of tube, d =\",round(d*100,4),\"cm\";      #Result\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Length of tube, d = 3.0065 cm\n"
+       ]
+      }
+     ],
+     "prompt_number": 32
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.10,Page number 26"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given\n",
+      "\n",
+      "#p=m/{m+[2*n/(1-n)^2]^2};\n",
+      "\n",
+      "m=5;            #no. of reflective plates\n",
+      "n=1.33;         #refractive indices\n",
+      "p=m/(m+(2*n/(1-(n)**2))**2); #degree of polarisation\n",
+      "print\"The degree of polarisation is\",round(p,1);\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The degree of polarisation is 0.3\n"
+       ]
+      }
+     ],
+     "prompt_number": 35
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.11,Page number 26"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given\n",
+      "\n",
+      "#m= p*{m+[2*n/(1-n)^2]^2};\n",
+      "\n",
+      "n=1.5;          #refractive indices\n",
+      "p=0.45;         #degree of polarisation\n",
+      "m=(p*(2*n/(1-n**2))**2)/(1-p);\n",
+      "print\"Thus it will require\",round(m,4),\"reflective plate to achive a degree of polarization equal to 0.45\";  \n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Thus it will require 4.7127 reflective plate to achive a degree of polarization equal to 0.45\n"
+       ]
+      }
+     ],
+     "prompt_number": 41
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.12,Page number 27"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given\n",
+      "#I1/I0=cos(w)^2\n",
+      "#k=I1/I0;\n",
+      "\n",
+      "w=30;               #angle bw polarizer and analyser in degee\n",
+      "k=math.cos(w*math.pi/180)**2;\n",
+      "print\"The ratio of optical ray intensity ,I1/I0=\",k;           #Result\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The ratio of optical ray intensity ,I1/I0= 0.75\n"
+       ]
+      }
+     ],
+     "prompt_number": 43
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.13,Page number 27"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given data\n",
+      "\n",
+      "#I1/I0=cos(w)^2\n",
+      "#Given I1/I0=0.55\n",
+      "\n",
+      "k=math.sqrt(0.55);         #from above formulae\n",
+      "\n",
+      "print\"The angle bw polarizer and analyser , w is\",round(math.degrees(math.acos(k)),4),\"degree\";\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The angle bw polarizer and analyser , w is 42.1304 degree\n"
+       ]
+      }
+     ],
+     "prompt_number": 48
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.14,Page number 29"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given \n",
+      "\n",
+      "print\"Solution (i)\";\n",
+      "ne=1.4;             #refractive index\n",
+      "no=1.25;            #refractive index\n",
+      "c=3*10**8;                   #in m/s\n",
+      "T=2*10**-5;  #in m\n",
+      "l=740;       #in nm\n",
+      "t=(ne-no)*T/c;      #time difference\n",
+      "print\"Time difference, t is\",t*10**12,\"ps\";\n",
+      "print\"Solution (ii)\";\n",
+      "le=l/ne; \n",
+      "lo=l/no;\n",
+      "fi=2*math.pi*T*(1/le-1/lo)*10**9;\n",
+      "print\"Phase difference is\",round(fi,4),\"rad\"; \n",
+      "# Answer misprinted in book"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Solution (i)\n",
+        "Time difference, t is 0.01 ps\n",
+        "Solution (ii)\n",
+        "Phase difference is 25.4724 rad\n"
+       ]
+      }
+     ],
+     "prompt_number": 51
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.15,Page number 31"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given \n",
+      "\n",
+      "#E=h*v=h*c/l;\n",
+      "\n",
+      "E=3;       #In KeV\n",
+      "#1eV=1.6*10^-19\n",
+      "h=6.63*10**-34;      #plank constant in J/s\n",
+      "c=3*10**8;           # speed of light in m/s\n",
+      "l=h*c/(E*10**3*1.6*10**-19);     #wavelength  in nm\n",
+      "print\"wavelength of a electromagnetic radiation is\",round(l*10**9,4),\"nm\";\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "wavelength of a electromagnetic radiation is 0.4144 nm\n"
+       ]
+      }
+     ],
+     "prompt_number": 53
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.16,Page number 31"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given\n",
+      "\n",
+      "print\"Solution (i)\";\n",
+      "l=670            #in nm\n",
+      "h=6.63*10**-34;  #plank constant in J/s\n",
+      "c=3*10**17       #speed of light in nm/sec\n",
+      "Ek=0.75          #In eV\n",
+      "phi=(h*c/l)/(1.6*10**-19) -Ek;\n",
+      "phi=round(phi*10)/10;           #round to 1 decimal point\n",
+      "print\"Characteristic of material =\",phi,\"eV\";\n",
+      "\n",
+      "print\"Solution (ii)\";\n",
+      "fc=phi*1.6*10**-19/h*10**-12;   #frequency in THz#result\n",
+      "fc=round(fc);\n",
+      "print\"Cuttoff frequency is =\",fc,\"THz\";\n",
+      "lc=c/(fc*10**12);       #in nm\n",
+      "print\"Cuttoff wavelength is =\",round(lc,4),\"nm\";\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Solution (i)\n",
+        "Characteristic of material = 1.1 eV\n",
+        "Solution (ii)\n",
+        "Cuttoff frequency is = 265.0 THz\n",
+        "Cuttoff wavelength is = 1132.0755 nm\n"
+       ]
+      }
+     ],
+     "prompt_number": 62
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.17,Page number 31"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given\n",
+      "\n",
+      "print\"Solution (i)\";\n",
+      "l=0.045;              #wavelength in nm\n",
+      "h=6.63*10**-34;       #planks constant in J/s\n",
+      "c=3*10**8;            #speed of light in m/s\n",
+      "E=h*c/l/10**-9;       #energy of photon in eV\n",
+      "print\"E =\",\"{0:.3e}\".format(E),\"J\";\n",
+      "\n",
+      "E1=E/(1.6*10**-19);    # energy in joule\n",
+      "print\"E =\",\"{0:.3e}\".format(E1),\"eV\";\n",
+      "        \n",
+      "e=1.6*10**-19;    # charge of electron\n",
+      "\n",
+      "print\"Solution (ii)\";\n",
+      "V=E/e;\n",
+      "print\"Required voltage is =\",V/1000,\"KV\";\n",
+      "\n",
+      "#Value of wavelenght in problem is .45 but in the solution is .045 \n",
+      "#the value considered above is .045\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Solution (i)\n",
+        "E = 4.420e-15 J\n",
+        "E = 2.762e+04 eV\n",
+        "Solution (ii)\n",
+        "Required voltage is = 27.625 KV\n"
+       ]
+      }
+     ],
+     "prompt_number": 59
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.18,Page number 36"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#given\n",
+      "\n",
+      "print\"Solution (i)\";\n",
+      "x=620                 # difference in particle momentum In nm\n",
+      "h=6.63*10**-34        # planks constant In J/s\n",
+      "#p=h/(4*pi*x);\n",
+      "#m*v=h/(4*pi*x);\n",
+      "m=9.11*10**-31        #mass of electron in kg \n",
+      "v=h /(4*math.pi* x *10**-9*m);   #electron velocity\n",
+      "print\"The uncertanity in electron velocity is\",round(v,4),\"m/s\";\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Solution (i)\n",
+        "The uncertanity in electron velocity is 93.41 m/s\n"
+       ]
+      }
+     ],
+     "prompt_number": 61
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [],
+     "language": "python",
+     "metadata": {},
+     "outputs": []
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
\ No newline at end of file