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| author | Thomas Stephen Lee | 2015-08-28 16:53:23 +0530 |
|---|---|---|
| committer | Thomas Stephen Lee | 2015-08-28 16:53:23 +0530 |
| commit | db0855dbeb41ecb8a51dde8587d43e5d7e83620f (patch) | |
| tree | b95975d958cba9af36cb1680e3f77205354f6512 /Engineering_Physics_by_S._Mani_Naidu/Chapter14_1.ipynb | |
| parent | 5a86a20b9de487553d4ef88719fb0fd76a5dd6a7 (diff) | |
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diff --git a/Engineering_Physics_by_S._Mani_Naidu/Chapter14_1.ipynb b/Engineering_Physics_by_S._Mani_Naidu/Chapter14_1.ipynb new file mode 100644 index 00000000..cea37dd0 --- /dev/null +++ b/Engineering_Physics_by_S._Mani_Naidu/Chapter14_1.ipynb @@ -0,0 +1,494 @@ +{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "#14: Optics"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example number 14.1, Page number 14.41"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 39,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "ratio of maximum intensity to minimum intensity is 19.727\n",
+ "answer varies due to rounding off errors\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "I1=10; #intensity(w/m**2)\n",
+ "I2=25; #intensity(w/m**2)\n",
+ "\n",
+ "#Calculation\n",
+ "a1bya2=math.sqrt(I1/I2); \n",
+ "I=((1+a1bya2)**2)/((a1bya2-1)**2); #ratio of maximum intensity to minimum intensity\n",
+ "\n",
+ "#Result\n",
+ "print \"ratio of maximum intensity to minimum intensity is\",round(I,3)\n",
+ "print \"answer varies due to rounding off errors\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example number 14.2, Page number 14.42"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 40,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "angular position of 10th maximum is 3 degrees 7 minutes 30.887 seconds\n",
+ "answer varies due to rounding off errors\n",
+ "angular position of 1st minimum is 0 degrees 9 minutes 23 seconds\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "lamda=5460*10**-10; #wavelength(m)\n",
+ "d=1*10**-4; #seperation(m)\n",
+ "D=2; #distance(m)\n",
+ "n=10; #position\n",
+ "\n",
+ "#Calculation\n",
+ "Xmax10=n*lamda*D/d;\n",
+ "tan_phi=Xmax10/D; \n",
+ "phi_max10=math.atan(tan_phi);\n",
+ "phi_max10=phi_max10*180/math.pi; #angular position of 10th maximum(degrees)\n",
+ "phim=60*(phi_max10-int(phi_max10));\n",
+ "phis=60*(phim-int(phim));\n",
+ "xmin1=lamda*D/(2*d); \n",
+ "tan_phi1=xmin1/D;\n",
+ "phi_min1=math.atan(tan_phi1);\n",
+ "phi_min1=phi_min1*180/math.pi; #angular position of 1st minimum(degrees)\n",
+ "phi_m=60*(phi_min1-int(phi_min1));\n",
+ "phi_s=60*(phi_m-int(phi_m));\n",
+ "\n",
+ "#Result\n",
+ "print \"angular position of 10th maximum is\",int(phi_max10),\"degrees\",int(phim),\"minutes\",round(phis,3),\"seconds\"\n",
+ "print \"answer varies due to rounding off errors\"\n",
+ "print \"angular position of 1st minimum is\",int(phi_min1),\"degrees\",int(phi_m),\"minutes\",int(phi_s),\"seconds\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example number 14.3, Page number 14.43"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 41,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "5320.0 angstrom lies in the visible region\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "mew=1.33; #refractive index of soap\n",
+ "t=5000*10**-10; #thickness(m)\n",
+ "n0=0;\n",
+ "n1=1;\n",
+ "n2=2;\n",
+ "n3=3;\n",
+ "\n",
+ "#Calculation\n",
+ "x=4*mew*t;\n",
+ "lamda1=x/((2*n0)+1); #for n=0\n",
+ "lamda2=x/((2*n1)+1); #for n=1\n",
+ "lamda3=x/((2*n2)+1); #for n=2\n",
+ "lamda4=x/((2*n3)+1); #for n=3\n",
+ "\n",
+ "#Result\n",
+ "print lamda3*10**10,\"angstrom lies in the visible region\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example number 14.4, Page number 14.43"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 42,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "wavelength of light is 5880 angstrom\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "D15=0.59*10**-2; #diameter of 15th ring(m)\n",
+ "D5=0.336*10**-2; #diameter of 5th ring(m)\n",
+ "R=1; #radius(m)\n",
+ "m=10;\n",
+ "\n",
+ "#Calculation\n",
+ "lamda=((D15**2)-(D5**2))/(4*m*R); #wavelength of light(m)\n",
+ "\n",
+ "#Result\n",
+ "print \"wavelength of light is\",int(lamda*10**10),\"angstrom\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example number 14.5, Page number 14.44"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 43,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "radius of curvature is 1.059 m\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "D10=0.5*10**-2; #diameter of 10th ring(m)\n",
+ "lamda=5900*10**-10; #wavelength of light(m)\n",
+ "n=10;\n",
+ "\n",
+ "#Calculation\n",
+ "R=D10**2/(4*n*lamda); #radius of curvature(m)\n",
+ "\n",
+ "#Result\n",
+ "print \"radius of curvature is\",round(R,3),\"m\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example number 14.6, Page number 14.44"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 44,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "least distance of the point is 13 mm\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "lamda1=650*10**-9; #wavelength(m)\n",
+ "lamda2=500*10**-9; #wavelength(m)\n",
+ "D=1; #distance(m)\n",
+ "d=0.5*10**-3; #seperation(m)\n",
+ "n=10;\n",
+ "\n",
+ "#Calculation\n",
+ "x=n*lamda1*D/d; #least distance of the point(m)\n",
+ "\n",
+ "#Result\n",
+ "print \"least distance of the point is\",int(x*10**3),\"mm\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example number 14.7, Page number 14.45"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 45,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "thickness is 2.5 micro m\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "lamda=500*10**-9; #wavelength(m)\n",
+ "n=10;\n",
+ "D10=2*10**-3; #diameter(m)\n",
+ "\n",
+ "#Calculation\n",
+ "r10=D10/2; #radius(m)\n",
+ "R=D10**2/(4*n*lamda);\n",
+ "t=r10**2/(2*R); #thickness(m)\n",
+ "\n",
+ "#Result\n",
+ "print \"thickness is\",t*10**6,\"micro m\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example number 14.8, Page number 14.45"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 46,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "fringe width is 2.75 mm\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "d=0.2*10**-3; #seperation(m)\n",
+ "lamda=550*10**-9; #wavelength(m)\n",
+ "D=1; #diameter(m)\n",
+ "\n",
+ "#Calculation\n",
+ "beta=lamda*D/d; #fringe width(m)\n",
+ "\n",
+ "#Result\n",
+ "print \"fringe width is\",beta*10**3,\"mm\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example number 14.9, Page number 14.45"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 47,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "separation between slits is 2 mm\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "lamda=500*10**-9; #wavelength(m)\n",
+ "D=2; #diameter(m)\n",
+ "beta=(5/100)*10**-2; #fringe width(m)\n",
+ "\n",
+ "#Calculation\n",
+ "d=lamda*D/beta; #separation between slits(m)\n",
+ "\n",
+ "#Result\n",
+ "print \"separation between slits is\",int(d*10**3),\"mm\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example number 14.10, Page number 14.46"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 48,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "ratio of maximum intensity to minimum intensity is 2.0\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "a12=36; #intensity 1\n",
+ "a22=1; #intensity 2\n",
+ "\n",
+ "#Calculation\n",
+ "a1=math.sqrt(a12);\n",
+ "a2=math.sqrt(a22);\n",
+ "Imin=(a1-a2)**2; #minimum intensity\n",
+ "Imax=(a1+a2)**2; #maximum intensity\n",
+ "r=Imax/Imin;\n",
+ "\n",
+ "#Result\n",
+ "print \"ratio of maximum intensity to minimum intensity is\",round(r)"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "##Example number 14.11, Page number 14.46"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 51,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "diameter of 25th ring is 0.8239 cm\n"
+ ]
+ }
+ ],
+ "source": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "D5=0.3; #diameter of 5th ring(cm)\n",
+ "D15=0.62; #diameter of 15th ring(cm)\n",
+ "\n",
+ "#Calculation\n",
+ "D_25=2*(D15**2)-(D5**2);\n",
+ "D25=math.sqrt(D_25); #diameter of 25th ring(cm)\n",
+ "\n",
+ "#Result\n",
+ "print \"diameter of 25th ring is\",round(D25,4),\"cm\""
+ ]
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
+ "version": "2.7.9"
+ }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}
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