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+{
+ "metadata": {
+  "name": "Chapter2"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": "2: Electromagnetic Theory"
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": "Example number 2.1, Page number 46"
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": "#To determine the peak value of displacement current\n\n#importing modules\nfrom __future__ import division\nfrom sympy import *\nimport math\n\n#Variable declaration\nC = 10;    #Capacitance of the capacitor(pF)\n#given V=0.2*sin(120*math.pi*t) in volts\n\n#Calculation\nC=C*10**-12;     #Capacitance of the capacitor(F)\nx, y, z, t = symbols('x y z t')\nk, m, n = symbols('k m n', integer=True)\nf, g, h = symbols('f g h', cls=Function)\n#I = C*dV/dt\n#let dV/dt be a\na=diff(0.2*sin(120*math.pi*t),t)     #dV/dt\n#value of dV/dt is 75.398223686155*cos(376.991118430775*t)\n#for cosine function peak value occurs when 120*math.pi*t = 0\n#therefore value of dV/dt becomes d = 75.398223686155\nd = 75.398223686155;    #value of dV/dt \nI=C*d;     #displacement current(A)\n\n#Result\nprint \"value of dV/dt is\",a\nprint \"displacement current is\",I, \"A\"",
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": "value of dV/dt is 75.398223686155*cos(376.991118430775*t)\ndisplacement current is 7.53982236862e-10 A\n"
+      }
+     ],
+     "prompt_number": 2
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": "Example number 2.2, Page number 46"
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": "#To calculate the peak value of displacement current density in a good conductor\n\n#importing modules\nfrom __future__ import division\nfrom sympy import *\nimport math\n\n#Variable declaration\nepsilon_r = 1;    #Relative electrical permittivity of free space\nepsilon_0 = 8.854*10**-12;    #Absolute electrical permittivity of free space(F/m)\n#given E=sin(120*math.pi*t) in volts\n\n#Calculation\nx, y, z, t = symbols('x y z t')\nk, m, n = symbols('k m n', integer=True)\nf, g, h = symbols('f g h', cls=Function)\n#J2 = epsilon*dE/dt\nepsilon=epsilon_0*epsilon_r;\n#let dE/dt be a\na=diff(sin(120*math.pi*t),t)     #dE/dt\n#value of dE/dt is 376.991118430775*cos(376.991118430775*t)\n#for cosine function peak value occurs when 120*math.pi*t = 0\n#therefore value of dE/dt becomes d = 376.991118430775\nd = 376.991118430775;    #value of dE/dt\nJ2=epsilon*d;     #displacement current density(A/m**2)\n\n#Result\nprint \"value of dE/dt is\",a\nprint \"The peak value of displacement current density is\",J2, \"A/m**2\"",
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": "value of dE/dt is 376.991118430775*cos(376.991118430775*t)\nThe peak value of displacement current density is 3.33787936259e-09 A/m**2\n"
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": "Example number 2.3, Page number 47 (Theoritical proof)"
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": "Example number 2.4, Page number 47"
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": "#To determine the peak value of displacement current\n\n#importing modules\nfrom __future__ import division\nimport math\n\n#Variable declaration\np = 60;    #Power rating of bulb(W)\nd = 0.5;    #Distance from the bulb(m)\n\n#Calculation\nA=4*math.pi*d**2;    #area(m**2)\nP = p/A;    #Value of Poynting vector(W/m**2)\nP = math.ceil(P*100)/100;    #rounding off value of P to 1 decimal\n\n#Result\nprint \"The value of Poynting vector is\",P, \"W/m**2\"",
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": "The value of Poynting vector is 19.1 W/m**2\n"
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": "Example number 2.5, Page number 47"
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": "#To determine the velocity of wave, intrinsic impedence and peak value of magnetic intensity\n\n#importing modules\nfrom __future__ import division\nimport math\n\n#Variable declaration\nE_peak = 6;    #Peak value of electric field intensity(V/m)\nc = 3*10**8;    #Speed of electromagnetic wave in free space(m/s)\nmew_0 = 4*math.pi*10**-7;    #Absolute permeability of free space(Tm/A)\nepsilon_0 = 8.854*10**-12;    #Absolute permittivity of free space(F/m)\nmew_r = 1;    #Relative permeability of medium\nepsilon_r = 3;    #Relative permittivity of the medium\n\n#Calculation\nv = c/math.sqrt(mew_r*epsilon_r);    #Wave velocity(m/s)\nv = v/10**8;\nv = math.ceil(v*10**4)/10**4;     #rounding off the value of v to 4 decimals\neta = math.sqrt((mew_0/epsilon_0)*(mew_r/epsilon_r));    #Intrinsic impedance of the medium(ohm)\neta = math.ceil(eta*10)/10;     #rounding off the value of v to 1 decimal\nH_P = E_peak/eta;     #Peak value of the magnetic intensity(A/m)\nH_P = H_P*10**2;\nH_P = math.ceil(H_P*10**2)/10**2;     #rounding off the value of v to 2 decimals\n\n#Result\nprint \"The wave velocity is\",v,\"*10**8 m/s\"\nprint \"The intrinsic impedance of the medium is\",eta, \"ohm\"\nprint \"The peak value of the magnetic intensity is\",H_P,\"*10**-2 A/m\"",
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": "The wave velocity is 1.7321 *10**8 m/s\nThe intrinsic impedance of the medium is 217.6 ohm\nThe peak value of the magnetic intensity is 2.76 *10**-2 A/m\n"
+      }
+     ],
+     "prompt_number": 11
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": "",
+     "language": "python",
+     "metadata": {},
+     "outputs": []
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
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