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author | Trupti Kini | 2017-03-07 09:55:18 +0600 |
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committer | Trupti Kini | 2017-03-07 09:55:18 +0600 |
commit | 856d4f871db9401d568629b88509a8aaf4c20626 (patch) | |
tree | 5dc225deca939bf8629e233e6433a2f9b5d17ae6 /Engineering_Mechanics_by_R.K_Bansal/chapter_17.ipynb | |
parent | d05f35e060ec21522792779655b2d69057caa8fe (diff) | |
download | Python-Textbook-Companions-856d4f871db9401d568629b88509a8aaf4c20626.tar.gz Python-Textbook-Companions-856d4f871db9401d568629b88509a8aaf4c20626.tar.bz2 Python-Textbook-Companions-856d4f871db9401d568629b88509a8aaf4c20626.zip |
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A BSc_3rd_Year_Physics(Paper-4)_by_Sanjeeva_Rao,_Bhikshmaiah,_Ramakrishna_Reddy,_Ananta_Ramaiah/Chapter8.ipynb
A BSc_3rd_Year_Physics(Paper-4)_by_Sanjeeva_Rao,_Bhikshmaiah,_Ramakrishna_Reddy,_Ananta_Ramaiah/Chapter9.ipynb
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A Electric_Drives_Concepts_And_Applications_by_Vedam_Subrahmanyam/Chapter01.ipynb
A Electric_Drives_Concepts_And_Applications_by_Vedam_Subrahmanyam/Chapter03.ipynb
A Electric_Drives_Concepts_And_Applications_by_Vedam_Subrahmanyam/Chapter04.ipynb
A Electric_Drives_Concepts_And_Applications_by_Vedam_Subrahmanyam/Chapter05.ipynb
A Electric_Drives_Concepts_And_Applications_by_Vedam_Subrahmanyam/screenshots/Ex3.4.png
A Electric_Drives_Concepts_And_Applications_by_Vedam_Subrahmanyam/screenshots/Ex4.4.png
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A Electronic_Communication_Systems_by_Roy_Blake/Chapter1.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter12.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter13.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter14.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter15.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter16.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter17.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter18.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter19.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter2.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter20.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter21.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter22.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter23.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter24.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter25.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter3.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter4.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter5.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter6.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter7.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter8.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/Chapter9.ipynb
A Electronic_Communication_Systems_by_Roy_Blake/screenshots/Chapter12.png
A Electronic_Communication_Systems_by_Roy_Blake/screenshots/Chapter13.png
A Electronic_Communication_Systems_by_Roy_Blake/screenshots/chapter1.png
A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./CHAPTER1.ipynb
A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./CHAPTER2.ipynb
A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./CHAPTER3.ipynb
A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./CHAPTER4.ipynb
A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./CHAPTER5.ipynb
A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./CHAPTER6.ipynb
A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./CHAPTER7.ipynb
A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./CHAPTER8.ipynb
A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./screenshots/figure1.png
A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./screenshots/figure2.png
A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./screenshots/figure3.png
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_10_Moments_of_Inertia.ipynb
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_11__Virtual_Work.ipynb
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_12_Kinematics_o_KMlkVxo.ipynb
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_13_Kinetics_of__QCPBknl.ipynb
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_14_Kinetics_of__nM3MpcX.ipynb
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A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_16_Planar_Kinem_iVoLBQW.ipynb
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_17_Planar_Kinet_WgJywgt.ipynb
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_18_Planar_Kinet_zX8jNLD.ipynb
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A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_1_General_Principles.ipynb
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_2_Force_Vectors.ipynb
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_3_Equilibrium_o_hYESk4B.ipynb
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_4_Force_System__zCBXq4n.ipynb
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_5_Equilibrium_o_wA2OXD7.ipynb
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_6_Structural_Analysis.ipynb
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_7_Internal_Forces.ipynb
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_8_Friction.ipynb
A Engineering_Mechanics_(Statics,_Dynamics),_by_Hibler_and_Gupta/Chapter_9_Center_of_Gra_jwxxiZg.ipynb
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A Engineering_Mechanics_by_R.K_Bansal/chapter_1.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_11.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_12.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_13.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_14.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_15.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_16.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_17.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_18.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_2.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_20.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_3.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_4.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_5.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_6.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_7.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_8.ipynb
A Engineering_Mechanics_by_R.K_Bansal/chapter_9.ipynb
A Engineering_Mechanics_by_R.K_Bansal/screenshots/bmd1.png
A Engineering_Mechanics_by_R.K_Bansal/screenshots/sfd.png
A Introduction_to_Heat_Transfer_by_S._K._Som/Chapter10_ljUjU8j.ipynb
A Introduction_to_Heat_Transfer_by_S._K._Som/Chapter11_5r7Matr.ipynb
A Introduction_to_Heat_Transfer_by_S._K._Som/Chapter12.ipynb
A Introduction_to_Heat_Transfer_by_S._K._Som/Chapter1_QhYeq33.ipynb
A Introduction_to_Heat_Transfer_by_S._K._Som/Chapter2_GK3uH9r.ipynb
A Introduction_to_Heat_Transfer_by_S._K._Som/Chapter3_18OmDFC.ipynb
A Introduction_to_Heat_Transfer_by_S._K._Som/Chapter4_fMX8RWT.ipynb
A Introduction_to_Heat_Transfer_by_S._K._Som/Chapter5_2AAnLS8.ipynb
A Introduction_to_Heat_Transfer_by_S._K._Som/Chapter6_lGPDUWp.ipynb
A Introduction_to_Heat_Transfer_by_S._K._Som/Chapter7_Ie2FcUI.ipynb
A Introduction_to_Heat_Transfer_by_S._K._Som/Chapter8_vyeGLD8.ipynb
A Introduction_to_Heat_Transfer_by_S._K._Som/Chapter9_4YOTRPU.ipynb
A Introduction_to_Heat_Transfer_by_S._K._Som/screenshots/9.7_xRDyNJc.png
A Introduction_to_Heat_Transfer_by_S._K._Som/screenshots/Ex10.7_G48Lnpj.png
A Introduction_to_Heat_Transfer_by_S._K._Som/screenshots/Ex11.4_8WqJsrO.png
A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_10_pO7WExy.ipynb
A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_2_FxNgKwZ.ipynb
A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_3_xv1zQ8m.ipynb
A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_4_HtsOENB.ipynb
A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_5_nuHXFeE.ipynb
A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_6_Ffb7zrN.ipynb
A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_7_GmkvL5A.ipynb
A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_8_BLulAvR.ipynb
A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_9_YALeeEe.ipynb
A Strength_Of_Materials_by_S_S_Bhavikatti/screenshots/BMD_dLcLPep.JPG
A Strength_Of_Materials_by_S_S_Bhavikatti/screenshots/SFD_1.JPG
A Strength_Of_Materials_by_S_S_Bhavikatti/screenshots/SFD_2.JPG
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter1.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter10.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter11.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter12.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter13.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter14.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter15.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter16.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter17.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter18.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter19.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter4.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter5.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter6.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter7.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter8.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter9.ipynb
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/screenshots/Chapter4.png
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/screenshots/Chapter5.png
A The_Elements_of_Physical_Chemistry_by_S._Glasstone/screenshots/Chapter6.png
A "sample_notebooks/Sushovan Jena/Chapter1.ipynb"
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diff --git a/Engineering_Mechanics_by_R.K_Bansal/chapter_17.ipynb b/Engineering_Mechanics_by_R.K_Bansal/chapter_17.ipynb new file mode 100644 index 00000000..45f94035 --- /dev/null +++ b/Engineering_Mechanics_by_R.K_Bansal/chapter_17.ipynb @@ -0,0 +1,873 @@ +{
+ "metadata": {
+ "name": "chapter 17.ipynb"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 17:Collision of Elastic Bodies"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.1,Page No.650"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "m1=1 #Kg #MAss of ball A\n",
+ "u1=2 #m/s #Initial velocity of ball A\n",
+ "v1=0 #Final velocity of ball A\n",
+ "\n",
+ "#Ball-2\n",
+ "m2=2 #kg #mass\n",
+ "u2=0 #m/s #Initial velocity\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#Total Initial momentum\n",
+ "V1=m1*u1+m2*u2 #kg*m/s\n",
+ "\n",
+ "#Total Initial momentum\n",
+ "#V2=m1*v1+m2*u2 #kg*m/s\n",
+ "\n",
+ "#Final velocity of ball B\n",
+ "v2=V1*2**-1 #m/s\n",
+ "\n",
+ "#Coefficient of restitution\n",
+ "e=(v2-v1)*(u1-u2)**-1 \n",
+ "\n",
+ "#Result\n",
+ "print\"Final velocity of ball B is\",round(v2,2),\"m/s\"\n",
+ "print\"Coefficient of restitution is\",round(e,2)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Final velocity of ball B is 1.0 m/s\n",
+ "Coefficient of restitution is 0.5\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.2,Page No.650"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "#first body\n",
+ "m1=50 #kg #mass\n",
+ "u1=6 #m/s #Initial velocity\n",
+ "\n",
+ "#second body\n",
+ "m2=30 #kg #mass\n",
+ "u2=0 #m/s #Initial velocity\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#MAss of two bodies\n",
+ "M=m1+m2 #kg\n",
+ "\n",
+ "#Total momentum before impact\n",
+ "M2=m1*u1+m2*u2 #kg*m/s\n",
+ "\n",
+ "#Total momentum after impact\n",
+ "#M3=(m1+m2)*V #kg*m/s\n",
+ "\n",
+ "#Velocitites of two bodies\n",
+ "V=M2*80**-1 #m/s\n",
+ "\n",
+ "#Result\n",
+ "print\"Common Velocity is\",round(V,2),\"m/s\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Common Velocity is 3.75 m/s\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.3,Page No.651"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "#Bullet\n",
+ "m1=0.05 #Kg #mass\n",
+ "\n",
+ "#Target\n",
+ "m2=5 #kg #mass\n",
+ "u2=0 #m/s #Initital Velocity\n",
+ "v=7 #m/s #Final Velocity\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "m=m1+m2 #kg #total mass\n",
+ "\n",
+ "#total Initial momentum\n",
+ "#v1=m1*u1+m2*u2\n",
+ "#After sub values and further simplifying we get\n",
+ "#v1=0.05*u1\n",
+ "\n",
+ "#Total Final momentum\n",
+ "v2=m*v #kg*m/s\n",
+ "\n",
+ "#Velocity of bullet\n",
+ "u1=v2*0.05**-1 #m/s\n",
+ "\n",
+ "#Result\n",
+ "print\"Velocity of bullet is\",round(u1,2),\"m/s\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Velocity of bullet is 707.0 m/s\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.4,Page No.651"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "m1=20 #kg #MAss of first ball\n",
+ "u1=5 #m/s #Initital velocity of first ball\n",
+ "\n",
+ "#second ball\n",
+ "m2=10 #kg #mass \n",
+ "u2=-10 #m/s #Velocity\n",
+ "e=5*6**-1 #coefficient of restitution\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#Total momentum before impact\n",
+ "v1=m1*u1+m2*u2 #m/s\n",
+ "\n",
+ "\n",
+ "#Total momentum after impact\n",
+ "#v2=m1*v1+m2*v2\n",
+ "\n",
+ "#Velocity of second ball after impact\n",
+ "V2=25*3**-1 #m/s \n",
+ "\n",
+ "#Velocity of first ball after impact\n",
+ "V1=-V2*2**-1 #m/s\n",
+ "\n",
+ "#Result\n",
+ "print\"Velocity of first ball after impact is\",round(V1,2),\"m/s\"\n",
+ "print\"Velocity of second ball after impact is\",round(V2,2),\"m/s\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Velocity of first ball after impact is -4.17 m/s\n",
+ "Velocity of second ball after impact is 8.33 m/s\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.6,Page No.654"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "m1=1 #kg #mass of first ball\n",
+ "m2=2 #kg #mass of second ball\n",
+ "u1=6 #m/s #Initial velocity of first ball\n",
+ "u2=2 #m/s #Initial velocity of second ball\n",
+ "theta1=30 #degrees #angle made by first ball\n",
+ "theta2=30 #degrees #angle made by second ball\n",
+ "e=0.5 #coefficient of restitutiion\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#for ball A\n",
+ "#v1*sin(phi1)=3 .............1\n",
+ "\n",
+ "#for ball B\n",
+ "#v2*sin(phi)=1 .............2\n",
+ "\n",
+ "#according to lwa of conservation of momentum\n",
+ "#v1*cos(ph11)+2*v2*cos(phi2)=8.66 ..............3\n",
+ "\n",
+ "#coefficient of restitution for this case\n",
+ "#v2*cos(ph12)-v1*cos(phi1)=1.732 .........4\n",
+ "\n",
+ "#Adding equation 3 and 4 we get\n",
+ "#v2*cos(ph2)=3.464 ....................5\n",
+ " \n",
+ "#sub values in equation 3 we get\n",
+ "#v1*cos(ph1)=1.732 .................6\n",
+ "\n",
+ "#dividing equation 1 by equation6\n",
+ "phi1=arctan(3*1.732**-1)*(180*pi**-1)\n",
+ "\n",
+ "#dividing equation 2 by 5 we get\n",
+ "phi2=arctan(1*3.464**-1)*(pi**-1*180)\n",
+ "\n",
+ "#sub value of phi2 in equation 5\n",
+ "v2=3.464*(cos(phi2*pi*180**-1))**-1\n",
+ "\n",
+ "#sub value in equation 1\n",
+ "v1=1.732*(cos(phi1*pi*180**-1))**-1\n",
+ "\n",
+ "#Result\n",
+ "print\"velocity of 1Kg ball is\",round(v1,2),\"m/s\"\n",
+ "print\"velocity of 2nd ball is\",round(v2,2),\"m/s\"\n",
+ "print\"Direction of 1Kg ball is\",round(phi1,2),\"degrees\"\n",
+ "print\"Direction of 2nd ball is\",round(phi2,2),\"Degrees\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "velocity of 1Kg ball is 3.46 m/s\n",
+ "velocity of 2nd ball is 3.61 m/s\n",
+ "Direction of 1Kg ball is 60.0 degrees\n",
+ "Direction of 2nd ball is 16.1 Degrees\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.7,Page No.656"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "m1=2 #kg #mass of first ball\n",
+ "m2=2 #kg #mass of second ball\n",
+ "u1=20 #m/s #Initial velocity of first ball\n",
+ "u2=30 #m/s #Initial velocity of second ball\n",
+ "theta1=30 #degrees #angle made by first ball\n",
+ "theta2=60 #degrees #angle made by second ball\n",
+ "e=0.9 #coefficient of restitutiion\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#for ball A\n",
+ "#v1*sin(phi1)=10 .............1\n",
+ "\n",
+ "#for ball B\n",
+ "#v2*sin(phi)=25.98 .............2\n",
+ "\n",
+ "#according to lwa of conservation of momentum\n",
+ "#v1*cos(ph11)+2*v2*cos(phi2)=2.32 ..............3\n",
+ "\n",
+ "#coefficient of restitution for this case\n",
+ "#v2*cos(ph12)-v1*cos(phi1)=29.08 .........4\n",
+ "\n",
+ "#Adding equation 3 and 4 we get\n",
+ "#v2*cos(ph2)=15.7 ....................5\n",
+ " \n",
+ "#sub values in equation 3 we get\n",
+ "#v1*cos(ph1)=13.38 .................6\n",
+ "\n",
+ "#dividing equation 1 by equation6\n",
+ "phi1=arctan(10*13.38**-1)*(180*pi**-1)\n",
+ "\n",
+ "#dividing equation 2 by 5 we get\n",
+ "phi2=arctan(25.98*15.7**-1)*(pi**-1*180)\n",
+ "\n",
+ "#sub value of phi2 in equation 5\n",
+ "v2=25.98*(sin(phi2*pi*180**-1))**-1\n",
+ "\n",
+ "#sub value in equation 1\n",
+ "v1=13.38*(cos(phi1*pi*180**-1))**-1\n",
+ "\n",
+ "#Result\n",
+ "print\"velocity of 1Kg ball is\",round(v1,2),\"m/s\"\n",
+ "print\"velocity of 2nd ball is\",round(v2,2),\"m/s\"\n",
+ "print\"Direction of 1Kg ball is\",round(phi1,2),\"degrees\"\n",
+ "print\"Direction of 2nd ball is\",round(phi2,2),\"Degrees\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "velocity of 1Kg ball is 16.7 m/s\n",
+ "velocity of 2nd ball is 30.36 m/s\n",
+ "Direction of 1Kg ball is 36.77 degrees\n",
+ "Direction of 2nd ball is 58.85 Degrees\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.8,Page No.658"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "#First vechile\n",
+ "m1=600 #kg #mass\n",
+ "u1=12 #m/s #Initial velocity\n",
+ "\n",
+ "#Second vechile\n",
+ "m2=400 #kg #mass\n",
+ "u2=9 #m/s #initial velocity\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#Total mass\n",
+ "M=m1+m2 #kg\n",
+ "\n",
+ "#Total Momentum before impact\n",
+ "v1=m1*u1+m2*u2\n",
+ "\n",
+ "#Total momentum\n",
+ "#v=M*V\n",
+ "\n",
+ "#By law of conservation of momentum\n",
+ "V=v1*1000**-1 #m/s\n",
+ "\n",
+ "#Kinetic Energy before impact\n",
+ "KE1=(m1*u1**2+m2*u2**2)*2**-1 #N*m\n",
+ "\n",
+ "#Total KE after impact\n",
+ "KE2=M*V**2*2**-1 #N*m\n",
+ "\n",
+ "#Loss of KE\n",
+ "KE3=KE1-KE2 #N*m\n",
+ "\n",
+ "#Result\n",
+ "print\"Loss of Kinetic Energy due to impact is\",round(KE3,2),\"N*m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Loss of Kinetic Energy due to impact is 1080.0 N*m\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.9,Page No.659"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "m1=0.1 #kg #MAss of bullet\n",
+ "m2=10 #kg #mass of target\n",
+ "u2=0 #Initial velocity of target\n",
+ "v=7 #m/s #common velocity\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#Total momentum before impact\n",
+ "#v1=0.1*u1\n",
+ "\n",
+ "#Total momentum after impact\n",
+ "v2=(m1+m2)*v\n",
+ "\n",
+ "#Initial velocity of bullet\n",
+ "u1=v2*0.1**-1 #m/s\n",
+ "\n",
+ "#Total KE before impact\n",
+ "KE=(m1*u1**2+m2*u2**2)*2**-1\n",
+ "\n",
+ "#Total KE after impact\n",
+ "KE2=(m1+m2)*v**2*2**-1 #m/s\n",
+ "\n",
+ "#Loss of KE\n",
+ "KE3=KE-KE2 #N*m\n",
+ "\n",
+ "#Result\n",
+ "print\"Loss of Kinetic Energy is\",round(KE3,2),\"N*m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Loss of Kinetic Energy is 24745.0 N*m\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.12,Page No.662"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "e=0.75 #coefficient of restitution\n",
+ "m1=1 #kg #MAss of first sphere\n",
+ "m2=5 #kg #mass of second sphere\n",
+ "u1=3 #m/s #Initial velocity of 1st sphere\n",
+ "u2=0.6 #m/s #Initial velocity of 2nd sphere\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#From law of conservation of momentum equation we get\n",
+ "#v1+5*v2=6 ..................1\n",
+ "\n",
+ "#Form coefficient of restitution formula we get\n",
+ "#v2-v1=1.8 ........................2\n",
+ "\n",
+ "#Adding equations 1 and 2 we get\n",
+ "v2=7.8*6**-1 #m/s\n",
+ "\n",
+ "#sub in equation 2 we get\n",
+ "v1=1.8-v2 #m/s\n",
+ "\n",
+ "#Loss of KE during impact\n",
+ "KE=((m1*u1**2+m2*u2**2)-(m1*v1**2+m2*v2**2))*2**-1\n",
+ "\n",
+ "#Result\n",
+ "print\"Loss of Kinetic Energy during impact is\",round(KE,2),\"N*m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Loss of Kinetic Energy during impact is 1.05 N*m\n"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.13,Page No.664"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "m=0.5 #kg #mass of ball\n",
+ "H=18 #m #Height from which the ball is dropped\n",
+ "h=8 # #Height to which ball rebounds\n",
+ "g=9.81 #m/s**2 \n",
+ "\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#Velocity with which ball strikes the floor\n",
+ "u=(2*g*H)**0.5 #m/s\n",
+ "\n",
+ "#Velocty of ball after impact\n",
+ "v=(2*g*h)**0.5 #m/s\n",
+ "\n",
+ "#Coefficient of restitution\n",
+ "e=v*u**-1\n",
+ "\n",
+ "#Result\n",
+ "print\"coefficient of restitution between floor and ball\",round(e,2)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "coefficient of restitution between floor and ball 0.67\n"
+ ]
+ }
+ ],
+ "prompt_number": 10
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.13(A),Page No.664"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "H1=1.6 #m #Initial Height\n",
+ "H2=0.9 #m #Height after rebound\n",
+ "g=9.81 #m/s**2\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#Consider motion of ball from height H1, wwe get\n",
+ "v1=(2*g*H1)**0.5 #m/s ................................1\n",
+ "\n",
+ "#Consider motion of ball from floor to a height H2\n",
+ "u2=(2*g*H2)**0.5 #m/s .........................2\n",
+ "\n",
+ "#Dividing equation 2 by 1 we get\n",
+ "e=u2*v1**-1 \n",
+ "\n",
+ "#Result\n",
+ "print\"Coefficient of restitution is\",round(e,2)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Coefficient of restitution is 0.75\n"
+ ]
+ }
+ ],
+ "prompt_number": 11
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.14,Page No.665"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "h=16 #m #Height after impact\n",
+ "e=0.8 #coeficient of restitution\n",
+ "g=9.81 #m/s**2\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#Velocity with which ball strikes the floor\n",
+ "u=(2*g*h)**0.5 #m/s \n",
+ "\n",
+ "#Height from which ball is dropped\n",
+ "H=2*g*h*(e**2*2*g)**-1 #m\n",
+ "\n",
+ "#Result\n",
+ "print\"Height from which the ball is dropped is\",round(H,2),\"m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Height from which the ball is dropped is 25.0 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.15,Page No.665"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "H=13.5 #Height from which ball is dropped\n",
+ "h=9 #m #Height to which ball rebounds\n",
+ "g=9.81 #m/s**2\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#velocity with which ball stirkes the floor\n",
+ "u=(2*g*H)**0.5 #m/s\n",
+ "\n",
+ "#velocity of ball after impact\n",
+ "v=(2*g*h)**0.5 #m/s\n",
+ "\n",
+ "#Coefficient of restitution \n",
+ "e=(v*u**-1)\n",
+ "\n",
+ "#Height of second rebound\n",
+ "\n",
+ "#velocity with which ball stirkes the floor second time\n",
+ "u1=(2*g*h) #m/s ..............1\n",
+ "\n",
+ "#velocity of ball after impact rebounds second time\n",
+ "#v1=(2*g*h2) ....................2\n",
+ " \n",
+ "#After simplifying equation 1 and 2 we get\n",
+ "h2=e**2*u1*(2*g)**-1 #m\n",
+ "\n",
+ "#Result\n",
+ "print\"Height of second rebound is\",round(h2,2),\"m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Height of second rebound is 6.0 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 13
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.16,Page No.667"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "u=10 #m/s #Initial velocity of ball\n",
+ "alpha=30 #degrees #angle made by intial velocity\n",
+ "theta=60 #degrees\n",
+ "e=0.5 #coefficient of restitution\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#As components of intial velocity and final velocity with line of impact is same at right angles\n",
+ "#v*sin(phi)=8.66 ........1\n",
+ "\n",
+ "#v*cos(phi)=2.5 ................2\n",
+ "\n",
+ "#Dividing equation 1 by 2\n",
+ "phi=arctan(8.66*2.5**-1)*(180*pi**-1)\n",
+ "\n",
+ "#Sub value in equation 1 we get\n",
+ "v=8.66*(sin(phi*pi*180**-1))**-1 #m/s\n",
+ "\n",
+ "#Result\n",
+ "print\"Direction of ball after impact is\",round(phi,2),\"Degrees\"\n",
+ "print\"Velocity of ball after impact\",round(v,2),\"m/s\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Direction of ball after impact is 73.9 Degrees\n",
+ "Velocity of ball after impact 9.01 m/s\n"
+ ]
+ }
+ ],
+ "prompt_number": 14
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.17,Page No.667"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Initilization of Variables\n",
+ "\n",
+ "u=5 #m/s #Initial velocity of body\n",
+ "alpha=30 #Degrees #Angle made by initial velocity with fixed plane\n",
+ "theta=60 #degrees\n",
+ "phi=45 #degrees #angle made by final velocity\n",
+ "beta=45 #degrees #Angle made by final velocity with line of impact\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#Components of final velocity and initial velocity at right angles to line of impact\n",
+ "v=u*sin(alpha*pi*180**-1)*(sin(phi*pi*180**-1))**-1 #m/s\n",
+ "\n",
+ "#For indirect impacton a fixed plane\n",
+ "e=v*cos(phi*pi*180**-1)*(u*cos(theta*pi*180**-1))**-1\n",
+ "\n",
+ "#Result\n",
+ "print\"coefficient of restitution between ball and fixed plane is\",round(e,2)\n",
+ "print\"velocity of body after impact is\",round(v,2),\"m/s\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "coefficient of restitution between ball and fixed plane is 1.0\n",
+ "velocity of body after impact is 3.54 m/s\n"
+ ]
+ }
+ ],
+ "prompt_number": 15
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |