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| author | hardythe1 | 2015-04-07 15:58:05 +0530 |
|---|---|---|
| committer | hardythe1 | 2015-04-07 15:58:05 +0530 |
| commit | 92cca121f959c6616e3da431c1e2d23c4fa5e886 (patch) | |
| tree | 205e68d0ce598ac5caca7de839a2934d746cce86 /Engineering_Economics/Chapter3.ipynb | |
| parent | b14c13fcc6bb6d01c468805d612acb353ec168ac (diff) | |
| download | Python-Textbook-Companions-92cca121f959c6616e3da431c1e2d23c4fa5e886.tar.gz Python-Textbook-Companions-92cca121f959c6616e3da431c1e2d23c4fa5e886.tar.bz2 Python-Textbook-Companions-92cca121f959c6616e3da431c1e2d23c4fa5e886.zip | |
added books
Diffstat (limited to 'Engineering_Economics/Chapter3.ipynb')
| -rwxr-xr-x | Engineering_Economics/Chapter3.ipynb | 360 |
1 files changed, 360 insertions, 0 deletions
diff --git a/Engineering_Economics/Chapter3.ipynb b/Engineering_Economics/Chapter3.ipynb new file mode 100755 index 00000000..b94c5fa1 --- /dev/null +++ b/Engineering_Economics/Chapter3.ipynb @@ -0,0 +1,360 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:5b530b225e354d5204b6b04a92931fcee5b92fa42094bc3f03e4022169e39d78"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Interest Formulas and their Application"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3.1 Page 29"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#initialisation of variable\n",
+ "P=20000.0;#in rupees\n",
+ "n=10.0;#in years\n",
+ "i=18.0;#% per annum\n",
+ "\n",
+ "#calculation\n",
+ "F=P*(1+i/100)**n;\n",
+ "\n",
+ "#result\n",
+ "print \"Maturity value after 18 years is \", round(F,3),\" Rupees.\";\n",
+ "print \" Ans in the book is not correct\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Maturity value after 18 years is : 104676.711 Rupees.\n",
+ " Ans in the book is not correct\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3.2 Page 30"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#initialisation of variable\n",
+ "F=100000.0;#in rupees\n",
+ "n=10.0;#in years\n",
+ "i=15.0;#% per annum\n",
+ "\n",
+ "#calculation\n",
+ "P=F/((1.0+i/100.0)**n);\n",
+ "\n",
+ "#result\n",
+ "print \"The person has to invest \", round(P,3),\" Rupees.\";\n",
+ "print \" Ans in the book is not correct\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The person has to invest 24718.471 Rupees.\n",
+ " Ans in the book is not correct\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3.3 Page 31"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#initialisation of variable\n",
+ "A=10000.0;#in rupees\n",
+ "n=25.0;#in years\n",
+ "i=20.0;#% per annum\n",
+ "\n",
+ "#calculation\n",
+ "F=A*(((1+i/100)**n-1)/(i/100));\n",
+ "\n",
+ "#result\n",
+ "print \"The future sum of the annual equal payment after 25 years is \",round(F,3),\" Rupees.\";"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The future sum of the annual equal payment after 25 years is 4719810.832 Rupees.\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3.4 Page 32"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#initialisation of variable\n",
+ "F=500000.0;#in rupees\n",
+ "n=15.0;#in years\n",
+ "i=18.0;#% per annum\n",
+ "\n",
+ "#calculation\n",
+ "A=F*((i/100)/((1+i/100)**n-1));\n",
+ "\n",
+ "#result\n",
+ "print \"The annual equal ammount which must be deposited for 15 years is \",round(A,3),\" Rupees.\";"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The annual equal ammount which must be deposited for 15 years is 8201.391 Rupees.\n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3.5 Page 33"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#initiasation of variable\n",
+ "A=1000000.0;#in rupees\n",
+ "n=20.0;#in years\n",
+ "i=15.0;#% per annum\n",
+ "\n",
+ "#calculation\n",
+ "P=A*(((1+i/100)**n-1)/((i/100)*(1+i/100)**n));\n",
+ "\n",
+ "#result\n",
+ "print \"The amount of reserve which must be setup now is : \",round(P,3),\" Rupees\";\n",
+ "print \" Ans in the book is not correct\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The amount of reserve which must be setup now is : 6259331.474 Rupees\n",
+ " Ans in the book is not correct\n"
+ ]
+ }
+ ],
+ "prompt_number": 13
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3.6 Page 34"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#initialisation of variable\n",
+ "P=1000000.0;#in rupees\n",
+ "n=15.0;#in years\n",
+ "i=18.0;#% per annum\n",
+ "\n",
+ "#calculation\n",
+ "A=P*(((i/100)*(1+i/100)**n)/((1+i/100)**n-1));\n",
+ "\n",
+ "#result\n",
+ "print \"The annual equivalent installment to be paid by the company to the bank is \",round(A),\" Rupees.\";"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The annual equivalent installment to be paid by the company to the bank is : 196403.0 Rupees.\n"
+ ]
+ }
+ ],
+ "prompt_number": 14
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3.7 Page 35"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#initiation of variable\n",
+ "A1=4000.0;#in rupees\n",
+ "G=500.0;#in rupees\n",
+ "n=10.0;#in years\n",
+ "i=15.0;#% per annum\n",
+ "\n",
+ "#calculation\n",
+ "A=A1+G*(((1+i/100)**n-(i/100)*n-1)/((i/100)*(1+i/100)**n-(i/100)));\n",
+ "F=A*(((1+i/100)**n-1)/(i/100));\n",
+ "\n",
+ "#result\n",
+ "print \"At the end of 10th year, the compound amountr of all his payments will be : \",round(F,3),\" Rupees.\";"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "At the end of 10th year, the compound amountr of all his payments will be : 115560.6 Rupees.\n"
+ ]
+ }
+ ],
+ "prompt_number": 15
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3.8 Page 36"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#initiation of variable\n",
+ "A1=8500.0;#in rupees\n",
+ "G=-500.0;#in rupees\n",
+ "n=10.0;#in years\n",
+ "i=15.0;#% per annum\n",
+ "\n",
+ "#calculation\n",
+ "A=A1+G*(((1+i/100)**n-(i/100)*n-1)/((i/100)*(1+i/100)**n-(i/100)));\n",
+ "F=A*(((1+i/100)**n-1)/(i/100));\n",
+ "\n",
+ "#result\n",
+ "print \"At the end of 10th year, the compound amountr of all his payments will be : \",round(F,3),\" Rupees.\";"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "At the end of 10th year, the compound amountr of all his payments will be : 138235.878 Rupees.\n"
+ ]
+ }
+ ],
+ "prompt_number": 17
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3.9 Page 38"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#initiation of variable\n",
+ "P=5000.0;#in rupees\n",
+ "n=10.0;#in years\n",
+ "i=12.0;#% per annum\n",
+ "m=4.0;#no. of interest periods per year for quarterly\n",
+ "\n",
+ "#calculation\n",
+ "N=n*m;\n",
+ "r=i/m;\n",
+ "F=P*(1+r/100)**N;\n",
+ "\n",
+ "#result\n",
+ "print\"Maturity value after 10 years is \",round(F,3),\" Rupees.\";"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Maturity value after 10 years is : 16310.189 Rupees.\n"
+ ]
+ }
+ ],
+ "prompt_number": 18
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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