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| author | Thomas Stephen Lee | 2015-09-04 22:04:10 +0530 |
|---|---|---|
| committer | Thomas Stephen Lee | 2015-09-04 22:04:10 +0530 |
| commit | 41f1f72e9502f5c3de6ca16b303803dfcf1df594 (patch) | |
| tree | f4bf726a3e3ce5d7d9ee3781cbacfe3116115a2c /Engineering_Economics/Chapter3.ipynb | |
| parent | 9c9779ba21b9bedde88e1e8216f9e3b4f8650b0e (diff) | |
| download | Python-Textbook-Companions-41f1f72e9502f5c3de6ca16b303803dfcf1df594.tar.gz Python-Textbook-Companions-41f1f72e9502f5c3de6ca16b303803dfcf1df594.tar.bz2 Python-Textbook-Companions-41f1f72e9502f5c3de6ca16b303803dfcf1df594.zip | |
add/remove/update books
Diffstat (limited to 'Engineering_Economics/Chapter3.ipynb')
| -rwxr-xr-x | Engineering_Economics/Chapter3.ipynb | 360 |
1 files changed, 0 insertions, 360 deletions
diff --git a/Engineering_Economics/Chapter3.ipynb b/Engineering_Economics/Chapter3.ipynb deleted file mode 100755 index b94c5fa1..00000000 --- a/Engineering_Economics/Chapter3.ipynb +++ /dev/null @@ -1,360 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:5b530b225e354d5204b6b04a92931fcee5b92fa42094bc3f03e4022169e39d78"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Interest Formulas and their Application"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.1 Page 29"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variable\n",
- "P=20000.0;#in rupees\n",
- "n=10.0;#in years\n",
- "i=18.0;#% per annum\n",
- "\n",
- "#calculation\n",
- "F=P*(1+i/100)**n;\n",
- "\n",
- "#result\n",
- "print \"Maturity value after 18 years is \", round(F,3),\" Rupees.\";\n",
- "print \" Ans in the book is not correct\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Maturity value after 18 years is : 104676.711 Rupees.\n",
- " Ans in the book is not correct\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.2 Page 30"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variable\n",
- "F=100000.0;#in rupees\n",
- "n=10.0;#in years\n",
- "i=15.0;#% per annum\n",
- "\n",
- "#calculation\n",
- "P=F/((1.0+i/100.0)**n);\n",
- "\n",
- "#result\n",
- "print \"The person has to invest \", round(P,3),\" Rupees.\";\n",
- "print \" Ans in the book is not correct\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The person has to invest 24718.471 Rupees.\n",
- " Ans in the book is not correct\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.3 Page 31"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variable\n",
- "A=10000.0;#in rupees\n",
- "n=25.0;#in years\n",
- "i=20.0;#% per annum\n",
- "\n",
- "#calculation\n",
- "F=A*(((1+i/100)**n-1)/(i/100));\n",
- "\n",
- "#result\n",
- "print \"The future sum of the annual equal payment after 25 years is \",round(F,3),\" Rupees.\";"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The future sum of the annual equal payment after 25 years is 4719810.832 Rupees.\n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.4 Page 32"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variable\n",
- "F=500000.0;#in rupees\n",
- "n=15.0;#in years\n",
- "i=18.0;#% per annum\n",
- "\n",
- "#calculation\n",
- "A=F*((i/100)/((1+i/100)**n-1));\n",
- "\n",
- "#result\n",
- "print \"The annual equal ammount which must be deposited for 15 years is \",round(A,3),\" Rupees.\";"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The annual equal ammount which must be deposited for 15 years is 8201.391 Rupees.\n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.5 Page 33"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initiasation of variable\n",
- "A=1000000.0;#in rupees\n",
- "n=20.0;#in years\n",
- "i=15.0;#% per annum\n",
- "\n",
- "#calculation\n",
- "P=A*(((1+i/100)**n-1)/((i/100)*(1+i/100)**n));\n",
- "\n",
- "#result\n",
- "print \"The amount of reserve which must be setup now is : \",round(P,3),\" Rupees\";\n",
- "print \" Ans in the book is not correct\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The amount of reserve which must be setup now is : 6259331.474 Rupees\n",
- " Ans in the book is not correct\n"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.6 Page 34"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initialisation of variable\n",
- "P=1000000.0;#in rupees\n",
- "n=15.0;#in years\n",
- "i=18.0;#% per annum\n",
- "\n",
- "#calculation\n",
- "A=P*(((i/100)*(1+i/100)**n)/((1+i/100)**n-1));\n",
- "\n",
- "#result\n",
- "print \"The annual equivalent installment to be paid by the company to the bank is \",round(A),\" Rupees.\";"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The annual equivalent installment to be paid by the company to the bank is : 196403.0 Rupees.\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.7 Page 35"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initiation of variable\n",
- "A1=4000.0;#in rupees\n",
- "G=500.0;#in rupees\n",
- "n=10.0;#in years\n",
- "i=15.0;#% per annum\n",
- "\n",
- "#calculation\n",
- "A=A1+G*(((1+i/100)**n-(i/100)*n-1)/((i/100)*(1+i/100)**n-(i/100)));\n",
- "F=A*(((1+i/100)**n-1)/(i/100));\n",
- "\n",
- "#result\n",
- "print \"At the end of 10th year, the compound amountr of all his payments will be : \",round(F,3),\" Rupees.\";"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "At the end of 10th year, the compound amountr of all his payments will be : 115560.6 Rupees.\n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.8 Page 36"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initiation of variable\n",
- "A1=8500.0;#in rupees\n",
- "G=-500.0;#in rupees\n",
- "n=10.0;#in years\n",
- "i=15.0;#% per annum\n",
- "\n",
- "#calculation\n",
- "A=A1+G*(((1+i/100)**n-(i/100)*n-1)/((i/100)*(1+i/100)**n-(i/100)));\n",
- "F=A*(((1+i/100)**n-1)/(i/100));\n",
- "\n",
- "#result\n",
- "print \"At the end of 10th year, the compound amountr of all his payments will be : \",round(F,3),\" Rupees.\";"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "At the end of 10th year, the compound amountr of all his payments will be : 138235.878 Rupees.\n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3.9 Page 38"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#initiation of variable\n",
- "P=5000.0;#in rupees\n",
- "n=10.0;#in years\n",
- "i=12.0;#% per annum\n",
- "m=4.0;#no. of interest periods per year for quarterly\n",
- "\n",
- "#calculation\n",
- "N=n*m;\n",
- "r=i/m;\n",
- "F=P*(1+r/100)**N;\n",
- "\n",
- "#result\n",
- "print\"Maturity value after 10 years is \",round(F,3),\" Rupees.\";"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Maturity value after 10 years is : 16310.189 Rupees.\n"
- ]
- }
- ],
- "prompt_number": 18
- }
- ],
- "metadata": {}
- }
- ]
-}
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