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+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:f6da3400e962f069ab8b21139258f5f7cf61e5a3c236ae304fff64bfb1520423"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter 18 - Refrigeration"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example 1 - Pg 347"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate the cop, hp required, work of compression and expansion\n",

+      "#Initialization of variables\n",

+      "Ta=500. #R\n",

+      "Tr=540. #R\n",

+      "#calculations\n",

+      "cop=Ta/(Tr-Ta)\n",

+      "hp=4.71/cop\n",

+      "print '%s' %(\"From steam tables,\")\n",

+      "ha=48.02\n",

+      "hb=46.6\n",

+      "hc=824.1\n",

+      "hd=886.9\n",

+      "Wc=-(hd-hc)\n",

+      "We=-(hb-ha)\n",

+      "#results\n",

+      "print '%s %.1f' %(\"Coefficient of performance =\",cop)\n",

+      "print '%s %.3f %s' %(\"\\n horsepower required per ton of refrigeration =\",hp,\" hp/ton refrigeration\")\n",

+      "print '%s %.1f %s' %(\"\\n Work of compression =\",Wc,\" Btu/lbm\")\n",

+      "print '%s %.2f %s' %(\"\\n Work of expansion =\",We,\"Btu/lbm\")"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "From steam tables,\n",

+        "Coefficient of performance = 12.5\n",

+        "\n",

+        " horsepower required per ton of refrigeration = 0.377  hp/ton refrigeration\n",

+        "\n",

+        " Work of compression = -62.8  Btu/lbm\n",

+        "\n",

+        " Work of expansion = 1.42 Btu/lbm\n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example 2 - Pg 349"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate the cop\n",

+      "#Initialization of variables\n",

+      "x=0.8\n",

+      "he=26.28 #Btu/lbm\n",

+      "hb=26.28 #Btu/lbm\n",

+      "pe=98.76 #psia\n",

+      "pc=51.68 #psia\n",

+      "hc=82.71 #Btu/lbm\n",

+      "hf=86.80+0.95\n",

+      "#calculations\n",

+      "dwisen=-(hf-hc)\n",

+      "dwact=dwisen/x\n",

+      "hd=hc-dwact\n",

+      "cop=(hc-hb)/(hd-hc)\n",

+      "#results\n",

+      "print '%s %.2f' %(\"Coefficient of performance = \",cop)\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Coefficient of performance =  8.96\n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example 3 - Pg 351"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate the work done, hp required, relative efficiency and mass flow rate, Compressor capacity\n",

+      "#Initialization of variables\n",

+      "hc=613.3#btu/lbm\n",

+      "hb=138.9#btu/lbm\n",

+      "ha=138.9#btu/lbm\n",

+      "hd=713.4 #btu/lbm\n",

+      "ta=464.7 #R\n",

+      "t0=545.7 #R\n",

+      "v=8.150 #ft^3/lbm\n",

+      "#calculations\n",

+      "Qa=hc-hb\n",

+      "Qr=ha-hd\n",

+      "Wcd=Qa+Qr\n",

+      "cop=abs(Qa/Wcd)\n",

+      "hp=abs(4.71/cop)\n",

+      "carnot=abs(ta/(t0-ta))\n",

+      "rel=abs(cop/carnot)\n",

+      "mass=200/Qa\n",

+      "C=mass*v\n",

+      "#results\n",

+      "print '%s %.1f %s' %(\"Work done =\",Wcd,\"Btu/lbm\")\n",

+      "print '%s %.3f %s' %(\"\\n horsepower required per ton of refrigeration =\",hp,\" hp/ton refrigeration\")\n",

+      "print '%s %.2f' %(\"\\n Coefficient of performance actual = \",cop)\n",

+      "print '%s %.3f' %(\"\\n Ideal cop = \",carnot)\n",

+      "print '%s %.3f' %(\"\\n relative efficiency =\",rel)\n",

+      "print '%s %.3f %s' %(\"\\n Mass flow rate =\",mass,\"lbm/min ton\")\n",

+      "print '%s %.2f %s' %(\"\\n Compressor capacity =\",C,\"cfm/ton\")\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Work done = -100.1 Btu/lbm\n",

+        "\n",

+        " horsepower required per ton of refrigeration = 0.994  hp/ton refrigeration\n",

+        "\n",

+        " Coefficient of performance actual =  4.74\n",

+        "\n",

+        " Ideal cop =  5.737\n",

+        "\n",

+        " relative efficiency = 0.826\n",

+        "\n",

+        " Mass flow rate = 0.422 lbm/min ton\n",

+        "\n",

+        " Compressor capacity = 3.44 cfm/ton\n"

+       ]

+      }

+     ],

+     "prompt_number": 3

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example 4 - Pg 355"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#calculate the Pressure ratio, Heat, Water make up required and Volume of vapor entering ejector\n",

+      "#Initialization of variables\n",

+      "pc=0.6982 #psia\n",

+      "pe=0.1217 #psia\n",

+      "m=200 #gal/min\n",

+      "qual=0.98\n",

+      "h1=23.07 #Btu/lbm\n",

+      "h2=8.05  #Btu/lbm\n",

+      "hw=1071.3\n",

+      "#calculations\n",

+      "rp=pc/pe\n",

+      "m2=m/0.01602 *0.1388 #Conversion of units \n",

+      "m2=1670\n",

+      "dh=15.02\n",

+      "Qa=m2*(h1-h2)\n",

+      "h3=h2 + qual*hw\n",

+      "m3=Qa/(h3-h1)\n",

+      "v=0.016+ qual*2444\n",

+      "C=m3*v\n",

+      "#results\n",

+      "print '%s %.2f' %(\"Pressure ratio =\",rp)\n",

+      "print '%s %d %s' %(\"\\n Heat =\",Qa,\"Btu/min\")\n",

+      "print '%s %.2f %s' %(\"\\n Water make up required =\",m3,\"lbm/min\")\n",

+      "print '%s %d %s' %(\"\\n Volume of vapor entering ejector =\",C,\"cfm\")\n",

+      "print '%s' %(\"The answers are a bit different due to rounding off error in textbook\")"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Pressure ratio = 5.74\n",

+        "\n",

+        " Heat = 25083 Btu/min\n",

+        "\n",

+        " Water make up required = 24.24 lbm/min\n",

+        "\n",

+        " Volume of vapor entering ejector = 58054 cfm\n",

+        "The answers are a bit different due to rounding off error in textbook\n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
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