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authorhardythe12015-06-11 17:31:11 +0530
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+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:22a4fbff9c8897e342a78bd9c8e48f9f093d2131b002f5667d92f4929ec8b5e4"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter14:Operational Amplifiers"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E1 - Pg 474"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate voltage gain and input and output resistance\n",
+ "#given\n",
+ "R1=20.*10.**3.;#ohm\n",
+ "Rf=2000.*10.**3.;#ohm\n",
+ "Acl=-Rf/R1;\n",
+ "Ricl=R1;\n",
+ "Ro=0;\n",
+ "print '%s %.f %s' %(\"The voltage gain =\",Acl,\"\\n\");\n",
+ "print '%s %.f %s' %(\"The input resistance =\",R1/1000,\"kohm\\n\");\n",
+ "print '%s %.f %s' %(\"The output resistance =\",Ro,\"ohm\\n\");\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The voltage gain = -100 \n",
+ "\n",
+ "The input resistance = 20 kohm\n",
+ "\n",
+ "The output resistance = 0 ohm\n",
+ "\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E2 - Pg 474"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Find the output voltage\n",
+ "#given\n",
+ "R1=20.*10.**3.;#ohm\n",
+ "Rf=2000.*10.**3.;#ohm\n",
+ "v1=4.;#V\n",
+ "v2=3.8;#V\n",
+ "vo=v2*(1.+Rf/R1)-(Rf/R1)*v1;\n",
+ "print '%s %.1f %s' %(\"The output voltage =\",vo,\"V\");\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The output voltage = -16.2 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E4 - Pg 475"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Design an adder circuit using an op amp\n",
+ "#given\n",
+ "#Vo=-(V1+10*V2+100*V3)\n",
+ "Rf=100.*10.**3.;#ohm\n",
+ "C1=1.;#coefficient of V1\n",
+ "C2=10.;#coefficient of V2\n",
+ "C3=100.;#coefficient of V3\n",
+ "R1=Rf/C1;\n",
+ "R2=Rf/C2;\n",
+ "R3=Rf/C3;\n",
+ "print '%s %.f %s' %(\"R1 =\",R1/1000,\"kohm\\n\");\n",
+ "print '%s %.f %s' %(\"R2 =\",R2/1000,\"kohm\\n\");\n",
+ "print '%s %.f %s' %(\"R3 =\",R3/1000,\"kohm\\n\");\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "R1 = 100 kohm\n",
+ "\n",
+ "R2 = 10 kohm\n",
+ "\n",
+ "R3 = 1 kohm\n",
+ "\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E5 - Pg 484"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate CMRR in dB\n",
+ "#given\n",
+ "import math\n",
+ "Ad=100.;#differential mode gain\n",
+ "Ac=0.01;#common mode gain\n",
+ "CMRR=20.*math.log10(Ad/Ac);\n",
+ "print '%s %.f %s' %(\"The CMRR in dB =\",CMRR,\"dB\");\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The CMRR in dB = 80 dB\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example E6 - Pg 484"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate the output voltage\n",
+ "#given\n",
+ "Ad=2000.;#differential mode gain\n",
+ "CMRR=10000.;\n",
+ "V1=10.**-3.;#V\n",
+ "V2=0.9*10.**-3.;#V\n",
+ "Vd=V1-V2;\n",
+ "Vc=(V1+V2)/2.;\n",
+ "Vo=Ad*Vd*(1.+Vc/(CMRR*Vd));\n",
+ "print '%s %.2f %s' %(\"The output voltage is =\",Vo*1000,\"mV\");\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The output voltage is = 200.19 mV\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file