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-{

- "metadata": {

-  "name": ""

- },

- "nbformat": 3,

- "nbformat_minor": 0,

- "worksheets": [

-  {

-   "cells": [

-    {

-     "cell_type": "heading",

-     "level": 1,

-     "metadata": {},

-     "source": [

-      "Chapter 16 : Signal generators"

-     ]

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 16.1, Page No 668"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "import math\n",

-      "#initialisation of variables\n",

-      "\n",

-      "Vcc=10.0\n",

-      "Ib=500.0*10**-9\n",

-      "Acl=29.0\n",

-      "f=1.0*10**3\n",

-      "\n",

-      "#Calculations\n",

-      "print(\" phase shift  oscillator\")\n",

-      "I1=100*Ib\n",

-      "vo=Vcc-1\n",

-      "vi=vo/Acl\n",

-      "R1=vi/I1\n",

-      "R1=5.6*10**3#use standard value 5.6Kohm\n",

-      "R2=Acl*R1\n",

-      "R2=180*10**3#use satndard value 180Kohm to give Acl>180\n",

-      "R3=R2R=R1\n",

-      "C=1.0/(2*3.14*R3*f*math.sqrt(6))\n",

-      "\n",

-      "#Results\n",

-      "print(\"The value of C = %.2f  \" %(C*10**9))"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        " phase shift  oscillator\n",

-        "The value of C = 11.61  \n"

-       ]

-      }

-     ],

-     "prompt_number": 28

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 16.2, Page No 672"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "import math\n",

-      "\n",

-      "#initialisation of variables\n",

-      "\n",

-      "f=40.0*10**3\n",

-      "L=100.0*10**-3\n",

-      "vp=8.0\n",

-      "\n",

-      "#Calculations\n",

-      "print(\"colpitts oscillator\")\n",

-      "Ct=1/(4*3.14*3.14*(f**2)*L)\n",

-      "C1=10*Ct\n",

-      "C2=1/((1/Ct)-(1/C1))\n",

-      "C2=180*10**-12#use standard value\n",

-      "Xc2=1/(2*3.14*f*C2)\n",

-      "Xc1=1/(2*3.14*f*C1)\n",

-      "R1=10*Xc1\n",

-      "R1=27*10**3#use standard value\n",

-      "Acl=C1/C2\n",

-      "R2=Acl*R1\n",

-      "R2=270*10**3#use stabdard value\n",

-      "R3=(R1*R2)/(R1+R2)\n",

-      "f2=Acl*f\n",

-      "SR=2*3.14*f*vp\n",

-      "\n",

-      "#Results\n",

-      "print(\"The value of SR is %.2f \" %(SR/1000))"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "colpitts oscillator\n",

-        "The value of SR is 2009.60 \n"

-       ]

-      }

-     ],

-     "prompt_number": 29

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 16.3 Page No 678"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "import math\n",

-      "\n",

-      "#initialisation of variables\n",

-      "\n",

-      "vo=8.0\n",

-      "f=100.0*10**3\n",

-      "print(\" hartley oscillator\")\n",

-      "Vcc=vo+1\n",

-      "Xl2=1.0*10**3\n",

-      "\n",

-      "#Calculations\n",

-      "L2=Xl2/(2*3.14*f)\n",

-      "L2=1.5*10**-3#use standard value\n",

-      "L1=L2/10.0\n",

-      "Lt=L1+L2#(assuming M=0)\n",

-      "C1=1/(4*(3.14**2)*(f**2)*Lt)\n",

-      "C1=1500*10**-12#use 1500pF with aadditional parallel capacitance if necessary\n",

-      "#C1>>stray capacitance\n",

-      "Xl1=2*3.14*f*L1#R1>>Xl1\n",

-      "R1=1*10**3\n",

-      "Acl=L2/L1\n",

-      "R2=Acl*R1\n",

-      "R3=(R1*R2)/(R1+R2)\n",

-      "print(\"full power bandwidth \")\n",

-      "f2=Acl*f\n",

-      "SR=2*3.14*f*vo\n",

-      "\n",

-      "#Results\n",

-      "print(\"The value of SR is %.2f \" %(SR/1000))"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        " hartley oscillator\n",

-        "full power bandwidth \n",

-        "The value of SR is 5024.00 \n"

-       ]

-      }

-     ],

-     "prompt_number": 30

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 16.4, Page No 680"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "import math\n",

-      "#initialisation of variables\n",

-      "\n",

-      "f=100.0*10**3\n",

-      "Vo=9.0\n",

-      "Acl=3.0\n",

-      "\n",

-      "#Calculations\n",

-      "print(\" design of wein bridge oscillator\")\n",

-      "Vcc=Vo+1\n",

-      "C1=1000.0*10**-12#standard value\n",

-      "C2=C1\n",

-      "R1=1.0/(2*3.14*f*C1)\n",

-      "R2=R1\n",

-      "R4=R2\n",

-      "R3=2*R4\n",

-      "R3=3.3*10**3#use standard value\n",

-      "print(\" minimum full power bandwidth\")\n",

-      "f2=Acl*f\n",

-      "SR=2*3.14*f*Vo\n",

-      "\n",

-      "#Results\n",

-      "print(\"The value of SR is %.2f \" %(SR/1000))"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        " design of wein bridge oscillator\n",

-        " minimum full power bandwidth\n",

-        "The value of SR is 5652.00 \n"

-       ]

-      }

-     ],

-     "prompt_number": 31

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 16.5 Page No 683"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "import math\n",

-      "#initialisation of variables\n",

-      "\n",

-      "f=5.0*10**3\n",

-      "vo=5.0\n",

-      "I1=1.0*10**-3\n",

-      "Vf=0.7\n",

-      "\n",

-      "#Calculations\n",

-      "print(\"phase shift oscillator\")\n",

-      "R1=(vo/29.0)/I1\n",

-      "R1=150#use standard value\n",

-      "R2=29*R1\n",

-      "R4=(2*Vf)/I1\n",

-      "R4=1.5*10**3#use 1.5kohm standard value\n",

-      "R5=R2-R4\n",

-      "R6=.4*R5\n",

-      "R7=.8*R5\n",

-      "R=R1\n",

-      "C=1.0/(2*3.14*R*f*math.sqrt(6))\n",

-      "\n",

-      "#Results\n",

-      "print(\"The value of C is %.2f mF\" %(C*10**9))"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "phase shift oscillator\n",

-        "The value of C is 86.68 mF\n"

-       ]

-      }

-     ],

-     "prompt_number": 32

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 16.6 Page No 686"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "import math\n",

-      "\n",

-      "#initialisation of variables\n",

-      "\n",

-      "rds=600.0\n",

-      "Vgs=1.0\n",

-      "Vd1=0.7\n",

-      "f=100.0*10**3\n",

-      "\n",

-      "#Calculations\n",

-      "print(\"wien bridge ocillator\")\n",

-      "R4=560.0\n",

-      "R3=2*((R4*rds)/(R4+rds))\n",

-      "I5=200.0*10**-6\n",

-      "Vo=6\n",

-      "R6=Vgs/I5\n",

-      "R5=(Vo-(Vgs+Vd1))/I5\n",

-      "print(\" C4 discharge voltage \")\n",

-      "Vc=.1*Vgs\n",

-      "print(\"C4 discharge time\")\n",

-      "T=1/f\n",

-      "Ic=I5\n",

-      "C4=(Ic*T)/Vc\n",

-      "Xc3=rds/10#at oscillating frequency\n",

-      "C3=1/(2*3.14*f*Xc3)\n",

-      "\n",

-      "#Results\n",

-      "print(\"The value of C3 is %.2f mF\" %(C3*10**9))"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "wien bridge ocillator\n",

-        " C4 discharge voltage \n",

-        "C4 discharge time\n",

-        "The value of C3 is 26.54 mF\n"

-       ]

-      }

-     ],

-     "prompt_number": 33

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 16.7, Page No 689"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "import math\n",

-      "#initialisation of variables\n",

-      "\n",

-      "Vo=14.0\n",

-      "Vr3=.5\n",

-      "Ib=500.0*10**-9\n",

-      "f=1.0*10**3\n",

-      "\n",

-      "#Calculations\n",

-      "print(\"square wave generator\")\n",

-      "Vcc=Vo+1\n",

-      "UTP=Vr3\n",

-      "LTP=UTP\n",

-      "I2=100*Ib\n",

-      "R3=Vr3/I2\n",

-      "R2=(Vo-Vr3)/I2\n",

-      "t=1/(2*f)\n",

-      "V=UTP-(-LTP)\n",

-      "C1=.1*10**-6\n",

-      "I1=(C1*V)/t\n",

-      "R1=Vo/I1\n",

-      "\n",

-      "#Results\n",

-      "print(\"The value of R1 is %.2f kohm\" %(R1/1000))"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "square wave generator\n",

-        "The value of R1 is 70.00 kohm\n"

-       ]

-      }

-     ],

-     "prompt_number": 34

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 16.8 Page No 694"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "import math \n",

-      "\n",

-      "#initialisation of variables\n",

-      "\n",

-      "R1=2.2*10**3\n",

-      "R2=2.7*10**3\n",

-      "C2=.5*10**-6\n",

-      "Vcc=15.0\n",

-      "\n",

-      "#Calculations\n",

-      "t1=.693*C2*(R1+R2)\n",

-      "t2=.693*C2*R2\n",

-      "T=t1+t2\n",

-      "f=1/T\n",

-      "Ic1=(Vcc/3)/(R1+R2)\n",

-      "\n",

-      "#Results\n",

-      "print(\"The value of Ic1 is %.2f mA\" %(Ic1*10**3))"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "The value of Ic1 is 1.02 mA\n"

-       ]

-      }

-     ],

-     "prompt_number": 35

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 16.10 Page No 699"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "import math\n",

-      "#initialisation of variables\n",

-      "\n",

-      "Vcc=9.0\n",

-      "Vo=3\n",

-      "I1=1.0*10**-3\n",

-      "f=500.0\n",

-      "UTP=3.0\n",

-      "\n",

-      "#Calculations\n",

-      "print(\"design the triangular wave\")\n",

-      "Vi=Vcc-1\n",

-      "V=Vo-(-Vo)\n",

-      "print(\" I1>>Ibmax for op-amp\")\n",

-      "R1=Vi/I1\n",

-      "t=1.0/(2*f)\n",

-      "C1=(I1*t)/V\n",

-      "print(\"schmitt design\")\n",

-      "I2=1.0*10**-3\n",

-      "R2=UTP/I2\n",

-      "R3=(Vcc-1)/I2\n",

-      "\n",

-      "#Results\n",

-      "print(\"The value of R3 is %.2f kohm\" %(R3/1000))"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "design the triangular wave\n",

-        " I1>>Ibmax for op-amp\n",

-        "schmitt design\n",

-        "The value of R3 is 8.00 kohm\n"

-       ]

-      }

-     ],

-     "prompt_number": 36

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 16.11 Page No 705"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "import math\n",

-      "\n",

-      "#initialisation of variables\n",

-      "\n",

-      "f=100.0*10**3\n",

-      "Rs=1.5*10**3\n",

-      "R1=2.0*Rs\n",

-      "\n",

-      "\n",

-      "#Calculations\n",

-      "R1=2.7*10**3#use standard value\n",

-      "R2=R1+Rs\n",

-      "C1=1/(2*3.14*f*R2)\n",

-      "R4=R2\n",

-      "R3=2*R4\n",

-      "\n",

-      "#Results\n",

-      "print(\"The value of R3 is %.2f kohm\" %(R3/1000))"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "The value of R3 is 8.40 kohm\n"

-       ]

-      }

-     ],

-     "prompt_number": 37

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 16.12, Page No 705"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "import math\n",

-      "\n",

-      "#initialisation of variables\n",

-      "\n",

-      "fs=1.0*10**6\n",

-      "Rs=700.0\n",

-      "C1=1000.0*10**-12\n",

-      "C2=100.0*10**-12\n",

-      "R1=1.0*10**6\n",

-      "R2=10.0*10**3\n",

-      "Rs=700.0\n",

-      "Vdd=5\n",

-      "\n",

-      "#Calculations\n",

-      "Ct=(C1*C2)/(C1+C2)\n",

-      "print(\" at resonance Xl=Xct    2*pi*f*L=1/2*pi*f*Ct\")\n",

-      "L=1/(((2*3.14*f)**2)*Ct)\n",

-      "ip=Vdd/(R1+R2+Rs)\n",

-      "Pd=(((.707*ip)**2)*Rs)*10**9\n",

-      "\n",

-      "#Results\n",

-      "print(\" peak power dissipated is %.3fnW \" %Pd)"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        " at resonance Xl=Xct    2*pi*f*L=1/2*pi*f*Ct\n",

-        " peak power dissipated is 8.563nW \n"

-       ]

-      }

-     ],

-     "prompt_number": 38

-    }

-   ],

-   "metadata": {}

-  }

- ]

-}
\ No newline at end of file