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+{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter No.1: Special Diodes"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 1.1, Page No. 9"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Reverse Saturation current of diode\n",
+ "import math\n",
+ "\n",
+ "#variable declaration\n",
+ "\n",
+ "I=40*10**-3 #forword bias current in A\n",
+ "V=0.25 #forword bias voltage in Volt\n",
+ "T=20 #junction temperature in degree C\n",
+ "T=T+273 #junction temperature in degree K\n",
+ "ETA=1 #For Ge\n",
+ "e=1.6*10**-19 #in Coulamb(electronic charge)\n",
+ "k=1.38*10**-23 #in J/K(Boltzman Constant)\n",
+ "\n",
+ "#Calculation\n",
+ "#Formula : I=Io*(exp(e*V/(ETA*k*T))-1)\n",
+ "x=math.ceil((e*V/(ETA*k*T)))\n",
+ "Io=I/(math.exp(x)-1)\n",
+ "Io=math.ceil(Io*10**8)/10**8\n",
+ "\n",
+ "#Result\n",
+ "print(\"Reverse saturation current in micro Ampere : %.2f \"%(Io*10**6))\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Reverse saturation current in micro Ampere : 1.82 \n"
+ ]
+ }
+ ],
+ "prompt_number": 14
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 1.2, Page No. 9"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Value of forword voltage\n",
+ "import math\n",
+ "#variable declaration\n",
+ "Io=10*10**-6 # reverse saturation currrent in A\n",
+ "I=1 # forword current in Ampere\n",
+ "ETA=2 # For Si\n",
+ "T=27 # room temperature in degree C\n",
+ "T=T+273 # room temperature in degree K\n",
+ "e=1.6*10**-19 # in Coulamb(electronic charge)\n",
+ "k=1.38*10**-23 # in J/K(Boltzman Constant)\n",
+ "\n",
+ "#Calculation\n",
+ "#Formula : I=Io*(exp(%e*V/(ETA*k*T))-1)\n",
+ "V=(ETA*k*T/e)*math.log(I/(Io)+1)\n",
+ "V=math.floor(V*100)/100\n",
+ "#result\n",
+ "print(\"Forward Voltage across the diode in Volt :%.2f\"%V)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Forward Voltage across the diode in Volt :0.59\n"
+ ]
+ }
+ ],
+ "prompt_number": 21
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 1.3 , Page No. 23"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#DC Current, DC Voltage, Ripple Factor\n",
+ "import math\n",
+ "#Variable Declaration\n",
+ "RL=1 #load resistance in kOhm\n",
+ "#rf<<RL\n",
+ "Vrms=200 #in Volt\n",
+ "\n",
+ "#Part (i)\n",
+ "Vo=Vrms*math.sqrt(2) #in volt\n",
+ "Idc=Vo/(RL*10**3*math.pi) #in Ampere\n",
+ "print(\"(i)\\nDC current in load in mA :%.0f\"%(math.floor((Idc*10**3))))\n",
+ "\n",
+ "#Part (ii)\n",
+ "Vdc=RL*10**3*Idc #in Volt\n",
+ "print(\"\\n(ii)\\nDC voltage across load in volt :%.0f\"%(math.floor(Vdc)))\n",
+ "\n",
+ "#Part (iii)\n",
+ "#Gamma=sqrt((Irms/Idc)^2-1)=sqrt((Io/2)/(Io/%pi)-1)=sqrt((%pi/2)^2-1)\n",
+ "Gamma=math.sqrt((math.pi/2)**2-1) #unitless\n",
+ "print(\"\\n(iii)\\nRipple factor :%.2f \"%(math.floor(Gamma*100)/100))\n",
+ "\n",
+ "#Part (iv)\n",
+ "PIV=Vrms*math.sqrt(2) #in volt\n",
+ "print(\"\\n(iv)\\nPeak Inverse Voltage in volt :%.0f\"%(math.floor(PIV)))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(i)\n",
+ "DC current in load in mA :90\n",
+ "\n",
+ "(ii)\n",
+ "DC voltage across load in volt :90\n",
+ "\n",
+ "(iii)\n",
+ "Ripple factor :1.21 \n",
+ "\n",
+ "(iv)\n",
+ "Peak Inverse Voltage in volt :282\n"
+ ]
+ }
+ ],
+ "prompt_number": 31
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 1.4 , Page No. 23"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Average dc current rms current rectifcation efcieny PIV\n",
+ "import math\n",
+ "#variable declaration\n",
+ "rf=20.0 #in ohm\n",
+ "RL=980.0 #in Ohm\n",
+ "Vrms=50.0 #in Volt\n",
+ "Vo=Vrms*math.sqrt(2) #in Volt\n",
+ "Io=Vo/(RL+rf) #in Ampere\n",
+ "\n",
+ "#Part (i)\n",
+ "Idc=2*Io/math.pi #in Ampere\n",
+ "print(\"(i)\\nAverage DC current in mA :%.0f\"%(math.floor(Idc*10**3)))\n",
+ "\n",
+ "#Part (ii)\n",
+ "Irms=Io/math.sqrt(2) #in Ampere\n",
+ "print(\"\\n(ii)\\nrms value of load current in mA :%.0f\"%(math.ceil(Irms*1000)))\n",
+ "\n",
+ "#Part (iii)\n",
+ "Vdc=RL*Idc #in Volt\n",
+ "print(\"\\n(iii)\\nDC output voltage in volt :%.1f\"%(math.floor(Vdc*10)/10))\n",
+ "\n",
+ "#Part (iv)\n",
+ "ETA=(Idc**2*RL/(Irms**2*(RL+rf)))*100 #Rectification Efficiency in %\n",
+ "print(\"\\n(iv)\\nRectification Efficiency is %.1f%%\"%(math.ceil(ETA*10)/10))\n",
+ "\n",
+ "#Part (v)\n",
+ "PIV=2*Vo #in volt\n",
+ "print(\"\\n(v)\\nPeak Inverse Voltage in volt :%.1f\"%PIV)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(i)\n",
+ "Average DC current in mA :45\n",
+ "\n",
+ "(ii)\n",
+ "rms value of load current in mA :50\n",
+ "\n",
+ "(iii)\n",
+ "DC output voltage in volt :44.1\n",
+ "\n",
+ "(iv)\n",
+ "Rectification Efficiency is 79.5%\n",
+ "\n",
+ "(v)\n",
+ "Peak Inverse Voltage in volt :141.4\n"
+ ]
+ }
+ ],
+ "prompt_number": 38
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 1.5, Page No.26"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Minimum value of resistance\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "\n",
+ "Vin=40 #in volt\n",
+ "VZ=10 #in volt\n",
+ "Vo=10 #in volt\n",
+ "IZmax=50 #in mA\n",
+ "IL=0 #in mA\n",
+ "\n",
+ "#calculation\n",
+ "#Formula : I=IZ+IL=IZmax+0\n",
+ "I=IZmax+0 #in mA\n",
+ "#Formula : VZ=Vin-R*I\n",
+ "Rmin=(Vin-VZ)/(I*10**-3) #in Ohm\n",
+ "#Result\n",
+ "print(\"Minimum value of resistance in Ohm :%.0f \"%Rmin)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Minimum value of resistance in Ohm :600 \n"
+ ]
+ }
+ ],
+ "prompt_number": 40
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 1.6, Page No.26"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Value of series resistor\n",
+ "import math\n",
+ "#variable declaration\n",
+ "Vmin=15 #Minimum input voltage in volt\n",
+ "VZ=6.8 #Voltage across zener in volt\n",
+ "Vo=VZ #output voltage in volt\n",
+ "Vsr1=Vmin-Vo #Voltage aross series resistance in volt\n",
+ "print(\"If R is the series resistance, Total current in series resistance in Ampere : I=Vsr/R=8.2/R \")\n",
+ "ILmin=5 #in mA\n",
+ "print(\"current in zener diode in Ampere :IZ=I-IL=(8.2/R-IL*10-3).............eqn(1)\\n\");\n",
+ "Vmax=20 #mximum output voltage\n",
+ "Vo=VZ #output voltage in volt\n",
+ "Vsr2=Vmax-Vo #Voltage aross series resistance in volt\n",
+ "print(\"Current in series resistance circuit in Ampere : I=Vsr/R\\n\")\n",
+ "ILmax=15 #in mA\n",
+ "print(\"current in zener diode in Ampere :IZ=I-IL=(Rs/R-IL*10-3)..............eqn(2)\\n\")\n",
+ "print(\"For Zener diode to work as voltage regulator,(1) and (2) must be same.\");\n",
+ "print(\"(8.2/R-IL*10-3)=(13.2/R-IL*10-3)\")\n",
+ "R=(Vsr2-Vsr1)/(ILmax*10**-3-ILmin*10**-3) #in Ohm\n",
+ "print(\"\\nRequired value of Series Resistor in ohm : %.0f\"%R)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "If R is the series resistance, Total current in series resistance in Ampere : I=Vsr/R=8.2/R \n",
+ "current in zener diode in Ampere :IZ=I-IL=(8.2/R-IL*10-3).............eqn(1)\n",
+ "\n",
+ "Current in series resistance circuit in Ampere : I=Vsr/R\n",
+ "\n",
+ "current in zener diode in Ampere :IZ=I-IL=(Rs/R-IL*10-3)..............eqn(2)\n",
+ "\n",
+ "For Zener diode to work as voltage regulator,(1) and (2) must be same.\n",
+ "(8.2/R-IL*10-3)=(13.2/R-IL*10-3)\n",
+ "\n",
+ "Required value of Series Resistor in ohm : 500\n"
+ ]
+ }
+ ],
+ "prompt_number": 51
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 1.7 Page No.27"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Current limiting resistance and dissipated power\n",
+ "import math\n",
+ "#variable declaration\n",
+ "\n",
+ "Vin=18 #in volt\n",
+ "IZ=20 #in mA\n",
+ "ILav=(5+35)/2 #in mA\n",
+ "VZ=12 #in volt\n",
+ "Vo=12 #in volt\n",
+ "\n",
+ "#Calculation\n",
+ "I=IZ+ILav #in mA\n",
+ "R=(Vin-Vo)/(I*10**-3) #in Ohm\n",
+ "P=(I*10**-3)**2*R #in Watts\n",
+ "\n",
+ "#Result\n",
+ "print(\"Current limiting resistance in Ohm : %.0f\"%R);\n",
+ "print(\"Power disspation in resistance in Watt :%.2f \"%P);"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Current limiting resistance in Ohm : 150\n",
+ "Power disspation in resistance in Watt :0.24 \n"
+ ]
+ }
+ ],
+ "prompt_number": 45
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 1.8, Page No. 28"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Maximum and minimum input supply voltage\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "R=1 #in kOhm\n",
+ "RL=5 #in kOhm\n",
+ "VZ=10 #in volt\n",
+ "Vo=10 #in volt\n",
+ "P=250 #in mW\n",
+ "\n",
+ "#Calculation\n",
+ "IL=Vo/RL #in mA\n",
+ "IZmin=0 #in mA\n",
+ "IZmax=P/VZ #in mA\n",
+ "Imin=IZmin+IL #in mA\n",
+ "Imax=IZmax+IL #in mA\n",
+ "Vin_min=VZ+Imin*10**-3*R*10**3 #in volt\n",
+ "Vin_max=VZ+Imax*10**-3*R*10**3 #in volt\n",
+ "\n",
+ "#Result\n",
+ "print(\"The input voltage ranges from %.0fV to %.0fV\"%(Vin_min,Vin_max));"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The input voltage ranges from 12V to 37V\n"
+ ]
+ }
+ ],
+ "prompt_number": 53
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 1.9, Page No.28"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Output voltage voltage drop and current in zener diode\n",
+ "import math\n",
+ "#Variable Declaration\n",
+ "R=5 #in kOhm\n",
+ "R=R*1000 #in Ohm\n",
+ "RL=10.0 #in kOhm\n",
+ "RL=RL*1000 #in Ohm\n",
+ "Vin=120.0 #in Volt\n",
+ "VZ=50.0 #in Volt\n",
+ "\n",
+ "#Part (i)\n",
+ "\n",
+ "#calculation\n",
+ "Vo=VZ #in Volt\n",
+ "#Result\n",
+ "print(\"\\n(i)\\nOutput voltage in volt :%.0f\"%Vo)\n",
+ "\n",
+ "#Part (ii)\n",
+ "\n",
+ "#calculation\n",
+ "VR=Vin-VZ #in Volt\n",
+ "#Result\n",
+ "print(\"\\n(ii)\\nVoltage drop across series resistance in volt :%.0f\"%VR);\n",
+ "\n",
+ "\n",
+ "\n",
+ "#Part (iii) \n",
+ "\n",
+ "#Calculation\n",
+ "IL=Vo/RL #in Ampere\n",
+ "I=VR/R #in Ampere\n",
+ "IZ=I-IL #in Ampere\n",
+ "#Result\n",
+ "print(\"\\n(iii)\\nLoad Current in mA :%.0f\"%(IL*1000))\n",
+ "print(\"Current through resistance R in mA :%.0f\"%(I*1000));\n",
+ "print(\"Load Current in mA :%.0f\"%(IZ*1000))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "\n",
+ "(i)\n",
+ "Output voltage in volt :50\n",
+ "\n",
+ "(ii)\n",
+ "Voltage drop across series resistance in volt :70\n",
+ "\n",
+ "(iii)\n",
+ "Load Current in mA :5\n",
+ "Current through resistance R in mA :14\n",
+ "Load Current in mA :9\n"
+ ]
+ }
+ ],
+ "prompt_number": 61
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 1.10, Page No. 30"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Maximum and Minimum LED current\n",
+ "import math\n",
+ "\n",
+ "#Variable declaration\n",
+ "VDmin=1.5 #in Volt\n",
+ "VDmax=2.3 #in Volt\n",
+ "VS=5.0 #in Volt\n",
+ "RS=270.0 #in Ohm\n",
+ "\n",
+ "#Calculation\n",
+ "Imin=(VS-VDmax)/RS #in Ampere\n",
+ "Imax=(VS-VDmin)/RS #in Ampere\n",
+ "\n",
+ "#Result\n",
+ "print(\"Minimum value of LED current in mA : %.0f\"%(Imin*1000))\n",
+ "print(\"Maximum value of LED current in mA : %.0f\"%(math.ceil(Imax*1000)))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Minimum value of LED current in mA : 10\n",
+ "Maximum value of LED current in mA : 13\n"
+ ]
+ }
+ ],
+ "prompt_number": 65
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 1.11, Page No. 33"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Frequency range of tuning circuit\n",
+ "import math\n",
+ "\n",
+ "#VAriable declarion\n",
+ "C1min=10 #in pF\n",
+ "C2max=50 #in pF\n",
+ "L=5 #in mH\n",
+ "L=L*10**-3 #in H\n",
+ "\n",
+ "#Calculation\n",
+ "\n",
+ "#Formula : CT=C1*C2/(C1+C2)\n",
+ "#Minimum\n",
+ "C1=10 #in pF\n",
+ "C2=10 #in pF\n",
+ "CTmin=C1*C2/(C1+C2) #in pF\n",
+ "CTmin=CTmin*10**-12 #in F\n",
+ "#Maximum\n",
+ "C1=50 #in pF\n",
+ "C2=50 #in pF\n",
+ "CTmax=C1*C2/(C1+C2) #in pF\n",
+ "CTmax=CTmax*10**-12 #in F\n",
+ "\n",
+ "#Formula : f=1/(2*%pi*sqrt(L*C))\n",
+ "#maximum :\n",
+ "fmax=1/(2*math.pi*math.sqrt(L*CTmin));\n",
+ "#minimum :\n",
+ "fmin=1/(2*math.pi*math.sqrt(L*CTmax));\n",
+ "\n",
+ "#Result\n",
+ "print(\"The frequency of tuning circuit ranges from %.3fMHz to %.3fMHz.\"%(fmin/10**6,fmax/10**6));\n",
+ "#Note : Answer in the book is wrong."
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The frequency of tuning circuit ranges from 0.450MHz to 1.007MHz.\n"
+ ]
+ }
+ ],
+ "prompt_number": 68
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 1.12, page No.33"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Diode Capacitance\n",
+ "import math\n",
+ "\n",
+ "#Variable Declaration\n",
+ "C1=21.0 # in pF\n",
+ "V1=4.0 # in volt\n",
+ "V2=9.0 # in volt\n",
+ "\n",
+ "#Calculations\n",
+ "print(\"C is proportional to 1/sqrt(V)\")\n",
+ "print(\"So, C2/C1=sqrt(V1/V2)\")\n",
+ "C2=math.sqrt(V1/V2)*C1 #in pF\n",
+ "\n",
+ "#Result\n",
+ "print(\"At reverse bias 9V, Diode capacitance in pF : %.0f\"%math"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "C is proportional to 1/sqrt(V)\n",
+ "So, C2/C1=sqrt(V1/V2)\n",
+ "At reverse bias 9V, Diode capacitance in pF : 14\n"
+ ]
+ }
+ ],
+ "prompt_number": 72
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 1.13, Page No.39"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Photocurrent\n",
+ "import math\n",
+ "#Variable Declaration\n",
+ "R=0.90 #in A/W\n",
+ "Pop=1.0 #in mW\n",
+ "\n",
+ "#Part (i)\n",
+ "#calculation\n",
+ "IP=R*Pop #in mA\n",
+ "#Result\n",
+ "print(\"(i)\\nPower of incident light 1mW, Photocurrent in mA is :%.2f\"%IP);\n",
+ "\n",
+ "#Part (ii)\n",
+ "#Result\n",
+ "print(\"\\n(ii)\\nHere IP is not proportional to Pop(for Pop>1.5mW)\")\n",
+ "print(\"Hence Photourrent can not be calculated.\")"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(i)\n",
+ "Power of incident light 1mW, Photocurrent in mA is :0.90\n",
+ "\n",
+ "(ii)\n",
+ "Here IP is not proportional to Pop(for Pop>1.5mW)\n",
+ "Hence Photourrent can not be calculated.\n"
+ ]
+ }
+ ],
+ "prompt_number": 74
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 1.14, Page No. 39"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Responsivity of InGaAs photodiode\n",
+ "import math\n",
+ "#variable declaration\n",
+ "ETA=70.0 #in %\n",
+ "Eg=0.75 #in eV\n",
+ "Eg=Eg*1.6*10**-19 #in Joule\n",
+ "h=6.63*10**-34 #Planks constant in J-s\n",
+ "c=3*10**8 #speed of light in m/s\n",
+ "e=1.6*10**-19 #in coulamb\n",
+ "\n",
+ "#Calcualtions\n",
+ "lambda1=h*c/Eg #in meter\n",
+ "R=(ETA/100)*e*lambda1/(h*c) #in A/W\n",
+ "\n",
+ "#Result\n",
+ "print(\"Wavelength in nm :%.1f\"%(lambda1*10**9))\n",
+ "print(\"Responsivity of InGaAs photodiode in A/W :%.3f\"%R)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Wavelength in nm :1657.5\n",
+ "Responsivity of InGaAs photodiode in A/W :0.933\n"
+ ]
+ }
+ ],
+ "prompt_number": 78
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "example 1.15, Page No. 41"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Equilibrium contact potential\n",
+ "import math\n",
+ "#variable declaration\n",
+ "W1=2.5 #in eV\n",
+ "W2=1.9 #in eV\n",
+ "\n",
+ "#Calculation\n",
+ "ContactPotential=W1-W2 #in Volt\n",
+ "\n",
+ "#Result\n",
+ "print(\"Contact potential in Volts :%.1f \"%ContactPotential)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Contact potential in Volts :0.6 \n"
+ ]
+ }
+ ],
+ "prompt_number": 80
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file