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Electronic_Communication_Systems_by_Roy_Blake/Chapter15.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter16.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter17.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter18.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter19.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter2.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter20.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter21.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter22.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter23.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter24.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter25.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter3.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter4.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter5.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter6.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter7.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter8.ipynb A Electronic_Communication_Systems_by_Roy_Blake/Chapter9.ipynb A Electronic_Communication_Systems_by_Roy_Blake/screenshots/Chapter12.png A Electronic_Communication_Systems_by_Roy_Blake/screenshots/Chapter13.png A Electronic_Communication_Systems_by_Roy_Blake/screenshots/chapter1.png A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./CHAPTER1.ipynb A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./CHAPTER2.ipynb A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./CHAPTER3.ipynb A Engineering_Mechanics:_Statics_&_Engineering_Mechanics:_Dynamics_by_Meriam,_J._L.,_&_Kraige,_L._G./CHAPTER4.ipynb A 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Introduction_to_Heat_Transfer_by_S._K._Som/Chapter8_vyeGLD8.ipynb A Introduction_to_Heat_Transfer_by_S._K._Som/Chapter9_4YOTRPU.ipynb A Introduction_to_Heat_Transfer_by_S._K._Som/screenshots/9.7_xRDyNJc.png A Introduction_to_Heat_Transfer_by_S._K._Som/screenshots/Ex10.7_G48Lnpj.png A Introduction_to_Heat_Transfer_by_S._K._Som/screenshots/Ex11.4_8WqJsrO.png A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_10_pO7WExy.ipynb A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_2_FxNgKwZ.ipynb A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_3_xv1zQ8m.ipynb A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_4_HtsOENB.ipynb A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_5_nuHXFeE.ipynb A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_6_Ffb7zrN.ipynb A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_7_GmkvL5A.ipynb A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_8_BLulAvR.ipynb A Strength_Of_Materials_by_S_S_Bhavikatti/chapter_9_YALeeEe.ipynb A 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The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter4.ipynb A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter5.ipynb A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter6.ipynb A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter7.ipynb A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter8.ipynb A The_Elements_of_Physical_Chemistry_by_S._Glasstone/Chapter9.ipynb A The_Elements_of_Physical_Chemistry_by_S._Glasstone/screenshots/Chapter4.png A The_Elements_of_Physical_Chemistry_by_S._Glasstone/screenshots/Chapter5.png A The_Elements_of_Physical_Chemistry_by_S._Glasstone/screenshots/Chapter6.png A "sample_notebooks/Sushovan Jena/Chapter1.ipynb"
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+{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "# Chapter 15 : Radio Wave Propagation"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 1 : pg 517"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 1,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The charasteristic impedance of polyethylene is 248.586 ohm\n"
+ ]
+ }
+ ],
+ "source": [
+ "#page no 517\n",
+ "#calculate the characteristic impedance of polyethylene\n",
+ "#prob no. 15.1\n",
+ "from math import sqrt\n",
+ "#Dielectric constt=2.3\n",
+ "#given\n",
+ "er=2.3;\n",
+ "#calculations\n",
+ "#Determination of characteristic impedance\n",
+ "Z=377./sqrt(er);\n",
+ "#results\n",
+ "print 'The charasteristic impedance of polyethylene is',round(Z,3),'ohm'"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 2 : pg 518"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 2,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The max power density is 23.873 GW/m2\n"
+ ]
+ }
+ ],
+ "source": [
+ "#calculate the max power density \n",
+ "#page no 518\n",
+ "#prob no. 15.2\n",
+ "#given\n",
+ "#Dielelectric strength of air=3MV/m\n",
+ "e=3*10**6;#electric field strength\n",
+ "Z=377.;#impedance of air\n",
+ "#calculations\n",
+ "Pd=(e**2)/Z;#Determination of power density\n",
+ "#results\n",
+ "print 'The max power density is',round(Pd/10**9,3),'GW/m2'"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 3 : pg 520"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 3,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "Power density at a point 10km 79.5774715459 nW/m2\n"
+ ]
+ }
+ ],
+ "source": [
+ "#calculate the power density \n",
+ "#page no 520\n",
+ "#prob no. 15.3\n",
+ "from math import pi\n",
+ "#given\n",
+ "#An isotropic radiator with power 100W & dist given is 10km\n",
+ "Pt=100;r=10*10**3;\n",
+ "#calculations\n",
+ "#Determination of power density at r=10km\n",
+ "Pd=Pt/(4*pi*(r**2));\n",
+ "#results\n",
+ "print 'Power density at a point 10km',Pd*10**9,'nW/m2'"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 4 : pg 521"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 4,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The electric field strength is 5.47722557505 mW/m\n"
+ ]
+ }
+ ],
+ "source": [
+ "#calculate the electric field strength \n",
+ "#page no 521\n",
+ "#prob no. 15.4\n",
+ "from math import sqrt\n",
+ "#given\n",
+ "#An isotropic radiator radiates power=100W at point 10km\n",
+ "Pt=100.;r=10.*10**3;\n",
+ "#calculations\n",
+ "#Determination of electric field strength\n",
+ "e=sqrt(30*Pt)/r;\n",
+ "#results\n",
+ "print 'The electric field strength is',e*1000,'mW/m'"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 5 : pg 525"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 5,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The power delivered to receiver is 405.812 nW\n"
+ ]
+ }
+ ],
+ "source": [
+ "#calculate the power delivered \n",
+ "#page no 525\n",
+ "#prob no. 15.5\n",
+ "from math import log10\n",
+ "#A transmitter with power o/p=150W at fc=325MHz.antenna gain=12dBi receiver antenna gain=5dBi at 10km away\n",
+ "#given\n",
+ "#considering no loss in the system\n",
+ "d=10.;Gt_dBi=12.;Gr_dBi=5.;fc=325.;Pt=150.;\n",
+ "#calculations\n",
+ "#Determination of power delivered\n",
+ "Lfs=32.44+(20*log10(d))+(20*log10(fc))-(Gt_dBi)-(Gr_dBi);\n",
+ "Pr=Pt/(10**(Lfs/10));\n",
+ "#results\n",
+ "print 'The power delivered to receiver is',round(Pr*10**9,3),'nW'"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 6 : pg 525"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 7,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The power delivered to receiver is 2.04329571558e-09 W\n"
+ ]
+ }
+ ],
+ "source": [
+ "#calculate the power delivered to receiver \n",
+ "#page no 525\n",
+ "#prob no. 15.6\n",
+ "#given\n",
+ "from math import log10\n",
+ "#A transmitter with o/p power=10W at fc=250MHz,connected to Tx 10m line with loss=3dB/100m t0 antenna with gain=6dBi.\n",
+ "#Rx antenna 20km away with gain=4dBi \n",
+ "#Refer fig.15.6,assuming free space propagation\n",
+ "d=20;fc=250.;Gt_dBi=6.;Gr_dBi=4.;loss=3./100;Zl=75.;Zo=50.;L=10.;Pt=10.;\n",
+ "#calculations\n",
+ "Lfs=32.44+(20*log10(d))+(20*log10(fc))-Gt_dBi-Gr_dBi;#path loss\n",
+ "\n",
+ "L_tx=L*loss;#Determination of loss\n",
+ "ref_coe=(Zl-Zo)/(Zl+Zo);#Reflection coefficient\n",
+ "L_rx=1-(ref_coe**2);#Proportion of incident power that reaches load\n",
+ "L_rx_dB=-10*log10(L_rx);#Converting that proportion in dB\n",
+ "#Determination of total loss Lt\n",
+ "Lt=(Lfs)+(L_tx)+(L_rx_dB);\n",
+ "#Determination of power delivered to receiver\n",
+ "Pt_Pr=10**(Lt/10);#Power ratio\n",
+ "Pr=Pt/Pt_Pr;\n",
+ "#results\n",
+ "print 'The power delivered to receiver is',Pr,'W'"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 7 : pg 530"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 8,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The angle of refraction is 10.313 degree\n"
+ ]
+ }
+ ],
+ "source": [
+ "#calculate the angle of refraction \n",
+ "#page no 530\n",
+ "#prob no. 15.7\n",
+ "#given\n",
+ "from math import sqrt, sin, asin,pi\n",
+ "#A radio wave moves from air(er=1) to glass(er=7.8).angle of incidence=30 deg\n",
+ "theta_i=30.;er1=1;er2=7.8;\n",
+ "#calculations\n",
+ "#determination of angle of refraction\n",
+ "theta_r=asin((sin(theta_i*pi/180.))/(sqrt(er2/er1)));\n",
+ "#results\n",
+ "print 'The angle of refraction is',round(theta_r*180/pi,3),'degree'"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8 : pg 537"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 9,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The max usable freq MUF is 33.92 MHz\n"
+ ]
+ }
+ ],
+ "source": [
+ "#calculate the max usable freq \n",
+ "#page no 537\n",
+ "#prob no. 15.8\n",
+ "#given\n",
+ "from math import cos,pi\n",
+ "#A Tx statn with fc=11.6MHz & angle of incidence=70 degree\n",
+ "theta_i=70.;fc=11.6;#in MHz\n",
+ "#calculations\n",
+ "#determination of max usable freq(MUF)\n",
+ "MUF=fc/(cos(theta_i*pi/180.));\n",
+ "#results\n",
+ "print 'The max usable freq MUF is',round(MUF,2),'MHz'"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 9 : pg 539"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 12,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "a)The max common distance between dispatcher & taxi 21.018 km\n",
+ "The max common distance between two taxi is 10.1 km\n"
+ ]
+ }
+ ],
+ "source": [
+ "#calculate the max common distance in both cases \n",
+ "#page no 539\n",
+ "#prob no. 15.9\n",
+ "#given\n",
+ "from math import sqrt\n",
+ "#A taxi compony using central dispatcher with antenna height=15m & taxi antenna height=1.5m\n",
+ "ht=15.;hr=1.5;\n",
+ "#calculations and results\n",
+ "#a)Determination of max commn dist betn dispatcher and taxi\n",
+ "d1=sqrt(17*ht)+sqrt(17*hr);\n",
+ "print 'a)The max common distance between dispatcher & taxi',round(d1,3),'km'\n",
+ "#b)Determination of max ommn dist betn 2 taxis\n",
+ "d2=sqrt(17*hr)+sqrt(17*hr);#ht=hr=height of antenna of taxi cab\n",
+ "print 'The max common distance between two taxi is',round(d2,3),'km'"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 11 : pg 545"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 13,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The fading period is 0.01125 sec\n",
+ "The fading period is 0.00474 sec\n"
+ ]
+ }
+ ],
+ "source": [
+ "#calculate the fading period in both cases \n",
+ "# page no 545\n",
+ "# prob no 15.11\n",
+ "#given\n",
+ "# An automobile travels at 60km/hr\n",
+ "v=60.*10**3/(60*60);#conversion of car's speedto m/s\n",
+ "c=3.*10**8;#speed of light\n",
+ "#part a) calculation of time between fades if car uses a cell phone at 800*10**6Hz\n",
+ "f=800.*10**6;\n",
+ "#calculations and results\n",
+ "T=c/(2*f*v);\n",
+ "print 'The fading period is',T,'sec'\n",
+ "#part b) calculation of time between fades if car uses a PCS phone at 1900*10**6Hz\n",
+ "f=1900.*10**6;\n",
+ "T=c/(2*f*v);\n",
+ "print 'The fading period is',round(T,5),'sec'\n",
+ "# Note that the rapidity of the fading increases with both the frequency of the transmissions and the speed of the vehicle"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 12 : pg 550"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 14,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "Number of cell sites are 72.0\n"
+ ]
+ }
+ ],
+ "source": [
+ "#calculate the no. of cell sites \n",
+ "#page no 550\n",
+ "#given\n",
+ "# problem no 15.12\n",
+ "A=1000.;#metropolitian area expressed in sq. km\n",
+ "r=2;#radius of cell in km\n",
+ "#calculations\n",
+ "# Number of cell sites given as\n",
+ "N=A/(3.464*r**2);\n",
+ "#results\n",
+ "print 'Number of cell sites are',round(N)"
+ ]
+ }
+ ],
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+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
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+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
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