Revised list of TBCs

author: kinitrupti 2017-05-12 18:40:35 +0530
committer: kinitrupti 2017-05-12 18:40:35 +0530
commit: 64d949698432e05f2a372d9edc859c5b9df1f438 (patch)
tree: 012fd5b4ac9102cdcf5bc56305e49d6714fa5951 /Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen
parent: 9c6ab8cbf3e1a84c780386abf4852d84cdd32d56 (diff)
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diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter1.ipynb
deleted file mode 100755
index 5dae57eb..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter1.ipynb
+++ /dev/null
@@ -1,474 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:ee4acc9fe033182686c067f9b51c12e7f872f20a61bb079c1ca29002499b1ddd"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter1-Semiconductor materials and diodes"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg6"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.1\n",
-      "T=300.;##((K)temperature)\n",
-      "##for silicon\n",
-      "B=5.23*10**(15);##Constant (per centimeter cube degree kelvin)\n",
-      "Eg=1.1;##bandgap energy in electrovolt(eV)\n",
-      "k=86.*10**(-6);##Boltzmann's constant(eV per degree kelvin)\n",
-      "n_i=B*T**(3/2.)*math.exp(-Eg/(2.*k*T));##intrinsic carrier concentration\n",
-      "print\"%s %.2f %s\"%('intrinsic carrier concentration= ',n_i,' cm^-3');\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "intrinsic carrier concentration=  14995738948.72  cm^-3\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg8"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import math\n",
-      "\n",
-      "#calculate the\n",
-      "\n",
-      "##Example 1.2 \n",
-      "T=300.;##(K)Given Temperature\n",
-      "Nd=10**16;##(cm^-3)Donor concentration\n",
-      "n_i=1.5*10**10;##(cm^-3)intrinsic carrier concentration\n",
-      "##since Nd>>n_i\n",
-      "n_o=10**16;##(cm^-3)electron concentration\n",
-      "##by using formula ::n_i^2=n_o*p_o\n",
-      "p_o=(n_i)**2/Nd;##hole concentration\n",
-      "print\"%s %.2e %s\"%('\\nelectron concentration= ',n_o,' cm^-3');\n",
-      "print\"%s %.2e %s\"%('\\nhole concentration = ',p_o,' cm^-3');\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "electron concentration=  1.00e+16  cm^-3\n",
-        "\n",
-        "hole concentration =  2.25e+04  cm^-3\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg13"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example1.3\n",
-      "T=300;##(K)Given Temperature\n",
-      "Na=10**16;##(cm^-3)Acceptor concentration in p region\n",
-      "Nd=10**17;##(cm^-3)Donor concentration in n region\n",
-      "n_i=1.5*10**10;##(cm^-3)intrinsic carrier concentration\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "##built-in potential\n",
-      "V_bi=V_T*math.log(Na*Nd/(n_i)**2);\n",
-      "print\"%s %.2f %s\"%('\\nthe built-in potential= ',V_bi,'V')\n",
-      "\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the built-in potential=  0.76 V\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg15"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.4\n",
-      "T=300.;##(K)Given Temperature\n",
-      "Na=10**16;##(cm**-3)Acceptor concentration in p region\n",
-      "Nd=10**15;##(cm**-3)Donor concentration in n region\n",
-      "n_i=1.5*10**10;##(cm**-3)intrinsic carrier concentration\n",
-      "C_jo=0.5;##(pF)junction capacitance at zero applied voltage\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "##built-in potential\n",
-      "V_bi=V_T*math.log(Na*Nd/(n_i)**2);\n",
-      "print\"%s %.2f %s\"%(\"the built-in potential(V)\",V_bi,\"\")\n",
-      "##the junction capacitance for\n",
-      "V_R=1.;##(V)reverse bias voltage\n",
-      "Cj=C_jo*(1.+V_R/V_bi)**(-1/2.);\n",
-      "print\"%s %.2f %s\"%('\\nthe junction capacitance for V_R=1V= ',Cj,' pF\\n')\n",
-      "V_R=5.;##(V)reverse bias voltage\n",
-      "Cj=C_jo*(1.+V_R/V_bi)**(-1/2.);\n",
-      "print\"%s %.2f %s\"%('\\nthe junction capacitance for V_R=5V = ',Cj,' pF')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "the built-in potential(V) 0.64 \n",
-        "\n",
-        "the junction capacitance for V_R=1V=  0.31  pF\n",
-        "\n",
-        "\n",
-        "the junction capacitance for V_R=5V =  0.17  pF\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg17"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.5\n",
-      "T=300.;##(K)Given Temperature\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "Is=10**-11;##(mA)reverse bias saturation current\n",
-      "n=1.;##emission coefficient\n",
-      "v_D=+0.7;##(V)applied voltage\n",
-      "##pn junction is forward biased\n",
-      "i_D=Is*(math.exp(v_D/V_T)-1.);##diode current\n",
-      "print\"%s %.2f %s\"%('\\ndiode current= ',i_D,' mA\\n')\n",
-      "v_D=-0.7;##(V)pn junction is reverse biased\n",
-      "Is=10**-14##A;\n",
-      "i_D=Is*(math.exp(v_D/V_T)-1);##diode current\n",
-      "print\"%s %.2e %s\"%('\\ndiode current= ',i_D,' A')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "diode current=  4.93  mA\n",
-        "\n",
-        "\n",
-        "diode current=  -1.00e-14  A\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg25"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.6\n",
-      "Is=10**-13;##(A)reverse saturation current\n",
-      "V_PS=5.;##(V)applied voltage\n",
-      "R=2;##(KOhm)Resistance in circuit\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "##V_PS=Is*R*(exp(V_D/V_T)-1)+V_D\n",
-      "##5=(10^-13)*(2000)*(exp(V_D/V_T)-1)+V_D\n",
-      "##let right side of equation be x=(10^-13)*(2000)*(exp(V_D/V_T)-1)+V_D\n",
-      "V_D=0.6;##(V)\n",
-      "x=(10**-13)*(2000.)*(math.exp(V_D/V_T)-1.)+V_D\n",
-      "##so the equation is not balanced\n",
-      "V_D=0.65;##(V)\n",
-      "x=(10**-13)*(2000.)*(math.exp(V_D/V_T)-1.)+V_D\n",
-      "##again equation is not balanced .solution for V_D is between 0.6V and 0.65V\n",
-      "V_D=0.619;##(V)\n",
-      "x=(10**-13)*(2000.)*(math.exp(V_D/V_T)-1.)+V_D\n",
-      "##essentially equal to the value of the left side of the equation i.e 5V\n",
-      "print\"%s %.2f %s\"%('\\ndiode voltage= ',V_D,' V')\n",
-      "I_D=(V_PS-V_D)/R;##(A)diode current\n",
-      "print\"%s %.2f %s\"%('\\nthe diode current= ',I_D,' mA')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "diode voltage=  0.62  V\n",
-        "\n",
-        "the diode current=  2.19  mA\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.7\n",
-      "##piecewise linear diode parameters\n",
-      "V_Y=0.6;##(V)\n",
-      "r_f=0.010;##(KOhm)\n",
-      "V_PS=5.;##(V)applied voltage\n",
-      "R=2.;##(KOhm)Resistance in circuit\n",
-      "I_D=(V_PS-V_Y)/(R+r_f);##(A)diode current\n",
-      "print\"%s %.2f %s\"%('\\nthe diode current= ',I_D,' mA\\n')\n",
-      "V_D=V_Y+I_D*r_f;##(V)diode voltage\n",
-      "print\"%s %.2f %s\"%('\\ndiode voltage= ',V_D,' V')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the diode current=  2.19  mA\n",
-        "\n",
-        "\n",
-        "diode voltage=  0.62  V\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg33"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.9 \n",
-      "##circuit and diode parameters \n",
-      "V_PS=5.;##(V)\n",
-      "R=5;##(KOhm)\n",
-      "V_Y=0.6;##(V)\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "v_i=0.1##*sin(wt)Volt\n",
-      "##dc analysis\n",
-      "I_DQ=(V_PS-V_Y)/R;\n",
-      "print\"%s %.2f %s\"%('\\ndc quiescent current= ',I_DQ,' mA\\n')\n",
-      "V_O=I_DQ*R;\n",
-      "print\"%s %.2f %s\"%('\\ndc output voltage= ',V_O,' V\\n')\n",
-      "##ac analysis\n",
-      "V_PS=0.;\n",
-      "##Kirchhoff voltage law equation becomes\n",
-      "##v_i=i_d*r_d+i_d*R\n",
-      "r_d=V_T/I_DQ##(Ohm)small signal diode diffusion resistance\n",
-      "i_d=v_i/(r_d+R);##ac diode current\n",
-      "print\"%s %.2f %s\"%('\\nac diode current= ',i_d,'sin(wt) A\\n')\n",
-      "\n",
-      "v_o=i_d*R;##ac output voltage\n",
-      "print\"%s %.2f %s\"%('\\nac output voltage= ',v_o,'sin(wt) V')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "dc quiescent current=  0.88  mA\n",
-        "\n",
-        "\n",
-        "dc output voltage=  4.40  V\n",
-        "\n",
-        "\n",
-        "ac diode current=  0.02 sin(wt) A\n",
-        "\n",
-        "\n",
-        "ac output voltage=  0.10 sin(wt) V\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg38"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.10\n",
-      "V_Y=0.7;##(V)cut in voltage for pn junction\n",
-      "r_f=0.;\n",
-      "V_PS=4;##(V)\n",
-      "R1=4.\n",
-      "R2=4.##(KOhm) from given circuit\n",
-      "I1=(V_PS-V_Y)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent through pn junction diode= ',I1,' mA\\n')\n",
-      "V_Y=0.3;##(V)cut in voltage for Schottky diode\n",
-      "I2=(V_PS-V_Y)/R2;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent through Schottky diode= ',I2,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "current through pn junction diode=  0.82  mA\n",
-        "\n",
-        "\n",
-        "current through Schottky diode=  0.93  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg40"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.11 \n",
-      "V_Z=5.6;##(V)Zener diode breakdown voltage\n",
-      "r_z=0.;##(Ohm)Zener resistance\n",
-      "I=3.;##(mA)current in the diode\n",
-      "V_PS=10.;##(V)\n",
-      "##I=(V_PS-V_Z)/R\n",
-      "R=(V_PS-V_Z)/I;\n",
-      "print\"%s %.2f %s\"%('\\nresistance= ',R,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "resistance=  1.47  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter10.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter10.ipynb
deleted file mode 100755
index d37bb7d2..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter10.ipynb
+++ /dev/null
@@ -1,593 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:4114bb4b96c500253f7e5458fac8496808721f37dbe4f7191c0a067f28a0192a"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter10-Integrated Circuit Biasing and Active Loads "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg580"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.1\n",
-      "Vbe=0.6;##(V)\n",
-      "b=100.;\n",
-      "V1=5.;\n",
-      "Io=200.;##micro A\n",
-      "Iref=Io*(1.+2./b);\n",
-      "print\"%s %.2f %s\"%('\\nreference current= ',Iref,' microA\\n')\n",
-      "Iref=Iref*0.001;##mA\n",
-      "R1=(V1-Vbe)/Iref;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "reference current=  204.00  microA\n",
-        "\n",
-        "\n",
-        "R1=  21.57  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg582"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.2\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "R1=9.3;\n",
-      "b=50.;\n",
-      "Vbe=0.7;\n",
-      "Va=80.;\n",
-      "Iref=(V1-Vbe-V2)/R1;\n",
-      "print\"%s %.2f %s\"%('\\nreference current = ',Iref,'mA\\n')\n",
-      "Io=Iref/(1.+2./b);\n",
-      "print\"%s %.2f %s\"%('\\noutput current= ',Io,'mA\\n')\n",
-      "ro=Va/Io;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal output resistance= ',ro,' KOhm\\n')\n",
-      "##dIo=dVce2/ro\n",
-      "Vce2=0.7;\n",
-      "dIo=(V1-Vce2)/ro;\n",
-      "print\"%s %.2f %s\"%('\\nchange in load current= ',dIo,' mA\\n')\n",
-      "x=dIo/Io;\n",
-      "x=x*100.;\n",
-      "print\"%s %.2f %s\"%('\\npercent change in output current= ',x,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "reference current =  1.00 mA\n",
-        "\n",
-        "\n",
-        "output current=  0.96 mA\n",
-        "\n",
-        "\n",
-        "small signal output resistance=  83.20  KOhm\n",
-        "\n",
-        "\n",
-        "change in load current=  0.05  mA\n",
-        "\n",
-        "\n",
-        "percent change in output current=  5.38  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg591"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.4\n",
-      "Iref=1.;\n",
-      "Io=12.*10**-3;\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "Vt=0.026;\n",
-      "Vbe=0.7;\n",
-      "R1=(V1-Vbe-V2)/Iref;\n",
-      "print\"%s %.2f %s\"%('\\nResistance R1 = ',R1,'KOhm\\n')\n",
-      "Re=(Vt/Io)*math.log(Iref/Io);\n",
-      "print\"%s %.2f %s\"%('\\nResistance Re = ',Re,'KOhm\\n')\n",
-      "Vbe=Io*Re;\n",
-      "print\"%s %.2f %s\"%('\\ndifference between two B-E voltages= ',Vbe,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Resistance R1 =  9.30 KOhm\n",
-        "\n",
-        "\n",
-        "Resistance Re =  9.58 KOhm\n",
-        "\n",
-        "\n",
-        "difference between two B-E voltages=  0.11  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg593"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.5\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "R1=9.3;\n",
-      "Re=9.580;\n",
-      "Vt=0.026;\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Va=80.;\n",
-      "Io=12.;\n",
-      "ro2=Va/Io;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal collector resistance= ',ro2,' MOhm\\n')\n",
-      "Io=12.*0.001;##mA\n",
-      "gm2=Io/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm2,' mA/V\\n')\n",
-      "r=b*Vt/Io;\n",
-      "print\"%s %.2f %s\"%('\\nResistance= ',r,' KOhm\\n')\n",
-      "Ro=ro2*(1.+gm2*Re*r/(Re+r));\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' MOhm\\n')\n",
-      "dVc2=4.;\n",
-      "dIo=dVc2/Ro;\n",
-      "print\"%s %.2f %s\"%('\\nchange in load current= ',dIo,' microA\\n')\n",
-      "Io=12.;##micro A\n",
-      "x=dIo/Io;\n",
-      "x=x*100.;\n",
-      "print\"%s %.2f %s\"%('\\npercent change in output current =\\n',x,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal collector resistance=  6.67  MOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  0.46  mA/V\n",
-        "\n",
-        "\n",
-        "Resistance=  216.67  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  34.90  MOhm\n",
-        "\n",
-        "\n",
-        "change in load current=  0.11  microA\n",
-        "\n",
-        "\n",
-        "percent change in output current =\n",
-        " 0.96 \n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg597"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.6\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "Vbe=0.6;\n",
-      "Veb=0.6;\n",
-      "Iq2=400.*10**-3;##mA\n",
-      "Iref=200.*10**-3;##mA\n",
-      "Iq1=Iref;\n",
-      "Iq3=Iq1;\n",
-      "Iq4=600.*10**-6;\n",
-      "R1=(V1-Veb-Vbe-V2)/Iref;\n",
-      "print\"%s %.2f %s\"%('\\nResistance R1= ',R1,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Resistance R1=  44.00  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg601"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 10.7\n",
-      "##uox*Cox/2=x\n",
-      "x=20.*10**-6;##A/V^2\n",
-      "Vtn=1.;\n",
-      "V1=5.;\n",
-      "V2=0.;\n",
-      "Iref=0.25*10**-3;\n",
-      "Io=0.1*10**-3;\n",
-      "Vgs2=1.85;\n",
-      "##let y=W/L\n",
-      "y2=Io/(x*(Vgs2-Vtn)**2);\n",
-      "print\"%s %.2f %s\"%('\\nwidth per length 2= ',y2,'\\n')\n",
-      "y1=Iref/(x*(Vgs2-Vtn)**2);\n",
-      "print\"%s %.2f %s\"%('\\nwidth per length 1= ',y1,'\\n')\n",
-      "Vgs1=Vgs2;\n",
-      "Vgs3=V1-V2-Vgs1;\n",
-      "print\"%s %.2f %s\"%('\\nVgs3= ',Vgs3,' V\\n')\n",
-      "y3=Iref/(x*(Vgs3-Vtn)**2);\n",
-      "print\"%s %.2f %s\"%('\\nwidth per length 3= ',y3,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "width per length 2=  6.92 \n",
-        "\n",
-        "\n",
-        "width per length 1=  17.30 \n",
-        "\n",
-        "\n",
-        "Vgs3=  3.15  V\n",
-        "\n",
-        "\n",
-        "width per length 3=  2.70 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg604"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.8\n",
-      "Iref=100.;\n",
-      "Io=Iref;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "gm=0.5*10**3;\n",
-      "ro=1./(y*Iref);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' MOhm\\n')\n",
-      "ro2=1.;\n",
-      "ro4=1.;\n",
-      "Ro=ro4+ro2*(1.+gm*ro4);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of cascode circuit= ',Ro,' MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance=  1.00  MOhm\n",
-        "\n",
-        "\n",
-        "output resistance of cascode circuit=  502.00  MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg609"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.9\n",
-      "Idss1=2.;\n",
-      "Idss2=1.;\n",
-      "Vp1=-1.5;\n",
-      "Vp2=Vp1;\n",
-      "##lambda=y\n",
-      "y1=0.05;\n",
-      "y2=y1;\n",
-      "V2=-5.;\n",
-      "Vds=1.5;\n",
-      "Vsmin=Vds+V2;\n",
-      "print\"%s %.2f %s\"%('\\nminimum value of Vs= ',Vsmin,' V\\n')\n",
-      "Io=Idss2*(1.+y1*Vds);\n",
-      "print\"%s %.2f %s\"%('\\noutput current= ',Io,' mA\\n')\n",
-      "Vgs1=(1.-math.sqrt(Io/Idss1))*Vp1;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage of Q1= ',Vgs1,' V\\n')\n",
-      "V1=Vgs1+Vsmin;\n",
-      "print\"%s %.2f %s\"%('\\nV1= ',V1,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "minimum value of Vs=  -3.50  V\n",
-        "\n",
-        "\n",
-        "output current=  1.07  mA\n",
-        "\n",
-        "\n",
-        "gate to source voltage of Q1=  -0.40  V\n",
-        "\n",
-        "\n",
-        "V1=  -3.90  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg615"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.10\n",
-      "Vt=0.026;\n",
-      "Van=120.;\n",
-      "Vap=80.;\n",
-      "Av=-(1./Vt)/(1./Van+1./Vap);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal open circuit voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal open circuit voltage gain=\n",
-        " -1846.15 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg620"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.11\n",
-      "Van=120.;\n",
-      "Vap=80.;\n",
-      "Vt=0.026;\n",
-      "Ico=0.001;\n",
-      "##Rl=infinity\n",
-      "Av=-(1./Vt)/(1./Van+1./Vap);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal open circuit voltage gain=\\n',Av,'')\n",
-      "Rl=100.;\n",
-      "Av1=-(1./Vt)/(1./Van+1./Vap+1./Rl);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal open circuit voltage gain=',Av1,'')\n",
-      "Rl=10.;\n",
-      "Av2=-(1./Vt)/(1./Van+1./Vap+1./Rl);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal open circuit voltage gain=\\n',Av2,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal open circuit voltage gain=\n",
-        " -1846.15 \n",
-        "\n",
-        "small signal open circuit voltage gain= -1247.40 \n",
-        "\n",
-        "small signal open circuit voltage gain=\n",
-        " -318.30 \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg623"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 10.12\n",
-      "##lambda=y\n",
-      "yn=0.01;\n",
-      "yp=0.01;\n",
-      "Vtn=1.;\n",
-      "Kn=1.;\n",
-      "Iref=0.5;\n",
-      "gm=2.*math.sqrt(Kn*Iref);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "go=yn*Iref;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal transistor conductance= ',go,' mA/V\\n')\n",
-      "go2=go;\n",
-      "##for Rl=infinity\n",
-      "Av=-gm/(go+go2);\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain= ',Av,' \\n')\n",
-      "Rl=100.;##Kohm\n",
-      "gl=0.01;\n",
-      "Av=-gm/(go+gl+go2);\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance =  1.41 mA/V\n",
-        "\n",
-        "\n",
-        "small signal transistor conductance=  0.01  mA/V\n",
-        "\n",
-        "\n",
-        "voltage gain=  -141.42  \n",
-        "\n",
-        "\n",
-        "voltage gain= \n",
-        " -70.71 \n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter10_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter10_1.ipynb
deleted file mode 100755
index d37bb7d2..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter10_1.ipynb
+++ /dev/null
@@ -1,593 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:4114bb4b96c500253f7e5458fac8496808721f37dbe4f7191c0a067f28a0192a"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter10-Integrated Circuit Biasing and Active Loads "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg580"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.1\n",
-      "Vbe=0.6;##(V)\n",
-      "b=100.;\n",
-      "V1=5.;\n",
-      "Io=200.;##micro A\n",
-      "Iref=Io*(1.+2./b);\n",
-      "print\"%s %.2f %s\"%('\\nreference current= ',Iref,' microA\\n')\n",
-      "Iref=Iref*0.001;##mA\n",
-      "R1=(V1-Vbe)/Iref;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "reference current=  204.00  microA\n",
-        "\n",
-        "\n",
-        "R1=  21.57  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg582"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.2\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "R1=9.3;\n",
-      "b=50.;\n",
-      "Vbe=0.7;\n",
-      "Va=80.;\n",
-      "Iref=(V1-Vbe-V2)/R1;\n",
-      "print\"%s %.2f %s\"%('\\nreference current = ',Iref,'mA\\n')\n",
-      "Io=Iref/(1.+2./b);\n",
-      "print\"%s %.2f %s\"%('\\noutput current= ',Io,'mA\\n')\n",
-      "ro=Va/Io;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal output resistance= ',ro,' KOhm\\n')\n",
-      "##dIo=dVce2/ro\n",
-      "Vce2=0.7;\n",
-      "dIo=(V1-Vce2)/ro;\n",
-      "print\"%s %.2f %s\"%('\\nchange in load current= ',dIo,' mA\\n')\n",
-      "x=dIo/Io;\n",
-      "x=x*100.;\n",
-      "print\"%s %.2f %s\"%('\\npercent change in output current= ',x,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "reference current =  1.00 mA\n",
-        "\n",
-        "\n",
-        "output current=  0.96 mA\n",
-        "\n",
-        "\n",
-        "small signal output resistance=  83.20  KOhm\n",
-        "\n",
-        "\n",
-        "change in load current=  0.05  mA\n",
-        "\n",
-        "\n",
-        "percent change in output current=  5.38  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg591"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.4\n",
-      "Iref=1.;\n",
-      "Io=12.*10**-3;\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "Vt=0.026;\n",
-      "Vbe=0.7;\n",
-      "R1=(V1-Vbe-V2)/Iref;\n",
-      "print\"%s %.2f %s\"%('\\nResistance R1 = ',R1,'KOhm\\n')\n",
-      "Re=(Vt/Io)*math.log(Iref/Io);\n",
-      "print\"%s %.2f %s\"%('\\nResistance Re = ',Re,'KOhm\\n')\n",
-      "Vbe=Io*Re;\n",
-      "print\"%s %.2f %s\"%('\\ndifference between two B-E voltages= ',Vbe,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Resistance R1 =  9.30 KOhm\n",
-        "\n",
-        "\n",
-        "Resistance Re =  9.58 KOhm\n",
-        "\n",
-        "\n",
-        "difference between two B-E voltages=  0.11  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg593"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.5\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "R1=9.3;\n",
-      "Re=9.580;\n",
-      "Vt=0.026;\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Va=80.;\n",
-      "Io=12.;\n",
-      "ro2=Va/Io;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal collector resistance= ',ro2,' MOhm\\n')\n",
-      "Io=12.*0.001;##mA\n",
-      "gm2=Io/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm2,' mA/V\\n')\n",
-      "r=b*Vt/Io;\n",
-      "print\"%s %.2f %s\"%('\\nResistance= ',r,' KOhm\\n')\n",
-      "Ro=ro2*(1.+gm2*Re*r/(Re+r));\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' MOhm\\n')\n",
-      "dVc2=4.;\n",
-      "dIo=dVc2/Ro;\n",
-      "print\"%s %.2f %s\"%('\\nchange in load current= ',dIo,' microA\\n')\n",
-      "Io=12.;##micro A\n",
-      "x=dIo/Io;\n",
-      "x=x*100.;\n",
-      "print\"%s %.2f %s\"%('\\npercent change in output current =\\n',x,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal collector resistance=  6.67  MOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  0.46  mA/V\n",
-        "\n",
-        "\n",
-        "Resistance=  216.67  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  34.90  MOhm\n",
-        "\n",
-        "\n",
-        "change in load current=  0.11  microA\n",
-        "\n",
-        "\n",
-        "percent change in output current =\n",
-        " 0.96 \n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg597"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.6\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "Vbe=0.6;\n",
-      "Veb=0.6;\n",
-      "Iq2=400.*10**-3;##mA\n",
-      "Iref=200.*10**-3;##mA\n",
-      "Iq1=Iref;\n",
-      "Iq3=Iq1;\n",
-      "Iq4=600.*10**-6;\n",
-      "R1=(V1-Veb-Vbe-V2)/Iref;\n",
-      "print\"%s %.2f %s\"%('\\nResistance R1= ',R1,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Resistance R1=  44.00  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg601"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 10.7\n",
-      "##uox*Cox/2=x\n",
-      "x=20.*10**-6;##A/V^2\n",
-      "Vtn=1.;\n",
-      "V1=5.;\n",
-      "V2=0.;\n",
-      "Iref=0.25*10**-3;\n",
-      "Io=0.1*10**-3;\n",
-      "Vgs2=1.85;\n",
-      "##let y=W/L\n",
-      "y2=Io/(x*(Vgs2-Vtn)**2);\n",
-      "print\"%s %.2f %s\"%('\\nwidth per length 2= ',y2,'\\n')\n",
-      "y1=Iref/(x*(Vgs2-Vtn)**2);\n",
-      "print\"%s %.2f %s\"%('\\nwidth per length 1= ',y1,'\\n')\n",
-      "Vgs1=Vgs2;\n",
-      "Vgs3=V1-V2-Vgs1;\n",
-      "print\"%s %.2f %s\"%('\\nVgs3= ',Vgs3,' V\\n')\n",
-      "y3=Iref/(x*(Vgs3-Vtn)**2);\n",
-      "print\"%s %.2f %s\"%('\\nwidth per length 3= ',y3,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "width per length 2=  6.92 \n",
-        "\n",
-        "\n",
-        "width per length 1=  17.30 \n",
-        "\n",
-        "\n",
-        "Vgs3=  3.15  V\n",
-        "\n",
-        "\n",
-        "width per length 3=  2.70 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg604"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.8\n",
-      "Iref=100.;\n",
-      "Io=Iref;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "gm=0.5*10**3;\n",
-      "ro=1./(y*Iref);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' MOhm\\n')\n",
-      "ro2=1.;\n",
-      "ro4=1.;\n",
-      "Ro=ro4+ro2*(1.+gm*ro4);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of cascode circuit= ',Ro,' MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance=  1.00  MOhm\n",
-        "\n",
-        "\n",
-        "output resistance of cascode circuit=  502.00  MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg609"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.9\n",
-      "Idss1=2.;\n",
-      "Idss2=1.;\n",
-      "Vp1=-1.5;\n",
-      "Vp2=Vp1;\n",
-      "##lambda=y\n",
-      "y1=0.05;\n",
-      "y2=y1;\n",
-      "V2=-5.;\n",
-      "Vds=1.5;\n",
-      "Vsmin=Vds+V2;\n",
-      "print\"%s %.2f %s\"%('\\nminimum value of Vs= ',Vsmin,' V\\n')\n",
-      "Io=Idss2*(1.+y1*Vds);\n",
-      "print\"%s %.2f %s\"%('\\noutput current= ',Io,' mA\\n')\n",
-      "Vgs1=(1.-math.sqrt(Io/Idss1))*Vp1;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage of Q1= ',Vgs1,' V\\n')\n",
-      "V1=Vgs1+Vsmin;\n",
-      "print\"%s %.2f %s\"%('\\nV1= ',V1,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "minimum value of Vs=  -3.50  V\n",
-        "\n",
-        "\n",
-        "output current=  1.07  mA\n",
-        "\n",
-        "\n",
-        "gate to source voltage of Q1=  -0.40  V\n",
-        "\n",
-        "\n",
-        "V1=  -3.90  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg615"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.10\n",
-      "Vt=0.026;\n",
-      "Van=120.;\n",
-      "Vap=80.;\n",
-      "Av=-(1./Vt)/(1./Van+1./Vap);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal open circuit voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal open circuit voltage gain=\n",
-        " -1846.15 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg620"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.11\n",
-      "Van=120.;\n",
-      "Vap=80.;\n",
-      "Vt=0.026;\n",
-      "Ico=0.001;\n",
-      "##Rl=infinity\n",
-      "Av=-(1./Vt)/(1./Van+1./Vap);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal open circuit voltage gain=\\n',Av,'')\n",
-      "Rl=100.;\n",
-      "Av1=-(1./Vt)/(1./Van+1./Vap+1./Rl);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal open circuit voltage gain=',Av1,'')\n",
-      "Rl=10.;\n",
-      "Av2=-(1./Vt)/(1./Van+1./Vap+1./Rl);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal open circuit voltage gain=\\n',Av2,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal open circuit voltage gain=\n",
-        " -1846.15 \n",
-        "\n",
-        "small signal open circuit voltage gain= -1247.40 \n",
-        "\n",
-        "small signal open circuit voltage gain=\n",
-        " -318.30 \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg623"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 10.12\n",
-      "##lambda=y\n",
-      "yn=0.01;\n",
-      "yp=0.01;\n",
-      "Vtn=1.;\n",
-      "Kn=1.;\n",
-      "Iref=0.5;\n",
-      "gm=2.*math.sqrt(Kn*Iref);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "go=yn*Iref;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal transistor conductance= ',go,' mA/V\\n')\n",
-      "go2=go;\n",
-      "##for Rl=infinity\n",
-      "Av=-gm/(go+go2);\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain= ',Av,' \\n')\n",
-      "Rl=100.;##Kohm\n",
-      "gl=0.01;\n",
-      "Av=-gm/(go+gl+go2);\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance =  1.41 mA/V\n",
-        "\n",
-        "\n",
-        "small signal transistor conductance=  0.01  mA/V\n",
-        "\n",
-        "\n",
-        "voltage gain=  -141.42  \n",
-        "\n",
-        "\n",
-        "voltage gain= \n",
-        " -70.71 \n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter10_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter10_1_1.ipynb
deleted file mode 100755
index d06c15b2..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter10_1_1.ipynb
+++ /dev/null
@@ -1,593 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:6b7c754b6ed46e47374605eefbbcd7d3c6bec34fcb694974971d2be63bb15a17"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter10-Integrated Circuit Biasing and Active Loads "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg580"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.1\n",
-      "Vbe=0.6;##(V)\n",
-      "b=100.;\n",
-      "V1=5.;\n",
-      "Io=200.;##micro A\n",
-      "Iref=Io*(1.+2./b);\n",
-      "print\"%s %.2f %s\"%('\\nreference current= ',Iref,' microA\\n')\n",
-      "Iref=Iref*0.001;##mA\n",
-      "R1=(V1-Vbe)/Iref;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "reference current=  204.00  microA\n",
-        "\n",
-        "\n",
-        "R1=  21.57  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg582"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.2\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "R1=9.3;\n",
-      "b=50.;\n",
-      "Vbe=0.7;\n",
-      "Va=80.;\n",
-      "Iref=(V1-Vbe-V2)/R1;\n",
-      "print\"%s %.2f %s\"%('\\nreference current = ',Iref,'mA\\n')\n",
-      "Io=Iref/(1.+2./b);\n",
-      "print\"%s %.2f %s\"%('\\noutput current= ',Io,'mA\\n')\n",
-      "ro=Va/Io;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal output resistance= ',ro,' KOhm\\n')\n",
-      "##dIo=dVce2/ro\n",
-      "Vce2=0.7;\n",
-      "dIo=(V1-Vce2)/ro;\n",
-      "print\"%s %.2f %s\"%('\\nchange in load current= ',dIo,' mA\\n')\n",
-      "x=dIo/Io;\n",
-      "x=x*100.;\n",
-      "print\"%s %.2f %s\"%('\\npercent change in output current= ',x,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "reference current =  1.00 mA\n",
-        "\n",
-        "\n",
-        "output current=  0.96 mA\n",
-        "\n",
-        "\n",
-        "small signal output resistance=  83.20  KOhm\n",
-        "\n",
-        "\n",
-        "change in load current=  0.05  mA\n",
-        "\n",
-        "\n",
-        "percent change in output current=  5.38  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg591"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.4\n",
-      "Iref=1.;\n",
-      "Io=12.*10**-3;\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "Vt=0.026;\n",
-      "Vbe=0.7;\n",
-      "R1=(V1-Vbe-V2)/Iref;\n",
-      "print\"%s %.2f %s\"%('\\nResistance R1 = ',R1,'KOhm\\n')\n",
-      "Re=(Vt/Io)*math.log(Iref/Io);\n",
-      "print\"%s %.2f %s\"%('\\nResistance Re = ',Re,'KOhm\\n')\n",
-      "Vbe=Io*Re;\n",
-      "print\"%s %.2f %s\"%('\\ndifference between two B-E voltages= ',Vbe,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Resistance R1 =  9.30 KOhm\n",
-        "\n",
-        "\n",
-        "Resistance Re =  9.58 KOhm\n",
-        "\n",
-        "\n",
-        "difference between two B-E voltages=  0.11  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg593"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.5\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "R1=9.3;\n",
-      "Re=9.580;\n",
-      "Vt=0.026;\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Va=80.;\n",
-      "Io=12.;\n",
-      "ro2=Va/Io;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal collector resistance= ',ro2,' MOhm\\n')\n",
-      "Io=12.*0.001;##mA\n",
-      "gm2=Io/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm2,' mA/V\\n')\n",
-      "r=b*Vt/Io;\n",
-      "print\"%s %.2f %s\"%('\\nResistance= ',r,' KOhm\\n')\n",
-      "Ro=ro2*(1.+gm2*Re*r/(Re+r));\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' MOhm\\n')\n",
-      "dVc2=4.;\n",
-      "dIo=dVc2/Ro;\n",
-      "print\"%s %.2f %s\"%('\\nchange in load current= ',dIo,' microA\\n')\n",
-      "Io=12.;##micro A\n",
-      "x=dIo/Io;\n",
-      "x=x*100.;\n",
-      "print\"%s %.2f %s\"%('\\npercent change in output current =\\n',x,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal collector resistance=  6.67  MOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  0.46  mA/V\n",
-        "\n",
-        "\n",
-        "Resistance=  216.67  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  34.90  MOhm\n",
-        "\n",
-        "\n",
-        "change in load current=  0.11  microA\n",
-        "\n",
-        "\n",
-        "percent change in output current =\n",
-        " 0.96 \n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg597"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.6\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "Vbe=0.6;\n",
-      "Veb=0.6;\n",
-      "Iq2=400.*10**-3;##mA\n",
-      "Iref=200.*10**-3;##mA\n",
-      "Iq1=Iref;\n",
-      "Iq3=Iq1;\n",
-      "Iq4=600.*10**-6;\n",
-      "R1=(V1-Veb-Vbe-V2)/Iref;\n",
-      "print\"%s %.2f %s\"%('\\nResistance R1= ',R1,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Resistance R1=  44.00  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg601"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 10.7\n",
-      "##uox*Cox/2=x\n",
-      "x=20.*10**-6;##A/V^2\n",
-      "Vtn=1.;\n",
-      "V1=5.;\n",
-      "V2=0.;\n",
-      "Iref=0.25*10**-3;\n",
-      "Io=0.1*10**-3;\n",
-      "Vgs2=1.85;\n",
-      "##let y=W/L\n",
-      "y2=Io/(x*(Vgs2-Vtn)**2);\n",
-      "print\"%s %.2f %s\"%('\\nwidth per length 2= ',y2,'\\n')\n",
-      "y1=Iref/(x*(Vgs2-Vtn)**2);\n",
-      "print\"%s %.2f %s\"%('\\nwidth per length 1= ',y1,'\\n')\n",
-      "Vgs1=Vgs2;\n",
-      "Vgs3=V1-V2-Vgs1;\n",
-      "print\"%s %.2f %s\"%('\\nVgs3= ',Vgs3,' V\\n')\n",
-      "y3=Iref/(x*(Vgs3-Vtn)**2);\n",
-      "print\"%s %.2f %s\"%('\\nwidth per length 3= ',y3,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "width per length 2=  6.92 \n",
-        "\n",
-        "\n",
-        "width per length 1=  17.30 \n",
-        "\n",
-        "\n",
-        "Vgs3=  3.15  V\n",
-        "\n",
-        "\n",
-        "width per length 3=  2.70 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg604"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.8\n",
-      "Iref=100.;\n",
-      "Io=Iref;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "gm=0.5*10**3;\n",
-      "ro=1./(y*Iref);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' MOhm\\n')\n",
-      "ro2=1.;\n",
-      "ro4=1.;\n",
-      "Ro=ro4+ro2*(1.+gm*ro4);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of cascode circuit= ',Ro,' MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance=  1.00  MOhm\n",
-        "\n",
-        "\n",
-        "output resistance of cascode circuit=  502.00  MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg609"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.9\n",
-      "Idss1=2.;\n",
-      "Idss2=1.;\n",
-      "Vp1=-1.5;\n",
-      "Vp2=Vp1;\n",
-      "##lambda=y\n",
-      "y1=0.05;\n",
-      "y2=y1;\n",
-      "V2=-5.;\n",
-      "Vds=1.5;\n",
-      "Vsmin=Vds+V2;\n",
-      "print\"%s %.2f %s\"%('\\nminimum value of Vs= ',Vsmin,' V\\n')\n",
-      "Io=Idss2*(1.+y1*Vds);\n",
-      "print\"%s %.2f %s\"%('\\noutput current= ',Io,' mA\\n')\n",
-      "Vgs1=(1.-math.sqrt(Io/Idss1))*Vp1;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage of Q1= ',Vgs1,' V\\n')\n",
-      "V1=Vgs1+Vsmin;\n",
-      "print\"%s %.2f %s\"%('\\nV1= ',V1,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "minimum value of Vs=  -3.50  V\n",
-        "\n",
-        "\n",
-        "output current=  1.07  mA\n",
-        "\n",
-        "\n",
-        "gate to source voltage of Q1=  -0.40  V\n",
-        "\n",
-        "\n",
-        "V1=  -3.90  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg615"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.10\n",
-      "Vt=0.026;\n",
-      "Van=120.;\n",
-      "Vap=80.;\n",
-      "Av=-(1./Vt)/(1./Van+1./Vap);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal open circuit voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal open circuit voltage gain=\n",
-        " -1846.15 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg620"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 10.11\n",
-      "Van=120.;\n",
-      "Vap=80.;\n",
-      "Vt=0.026;\n",
-      "Ico=0.001;\n",
-      "##Rl=infinity\n",
-      "Av=-(1./Vt)/(1./Van+1./Vap);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal open circuit voltage gain=\\n',Av,'')\n",
-      "Rl=100.;\n",
-      "Av1=-(1./Vt)/(1./Van+1./Vap+1./Rl);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal open circuit voltage gain=',Av1,'')\n",
-      "Rl=10.;\n",
-      "Av2=-(1./Vt)/(1./Van+1./Vap+1./Rl);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal open circuit voltage gain=\\n',Av2,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal open circuit voltage gain=\n",
-        " -1846.15 \n",
-        "\n",
-        "small signal open circuit voltage gain= -1247.40 \n",
-        "\n",
-        "small signal open circuit voltage gain=\n",
-        " -318.30 \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg623"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 10.12\n",
-      "##lambda=y\n",
-      "yn=0.01;\n",
-      "yp=0.01;\n",
-      "Vtn=1.;\n",
-      "Kn=1.;\n",
-      "Iref=0.5;\n",
-      "gm=2.*math.sqrt(Kn*Iref);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "go=yn*Iref;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal transistor conductance= ',go,' mA/V\\n')\n",
-      "go2=go;\n",
-      "##for Rl=infinity\n",
-      "Av=-gm/(go+go2);\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain= ',Av,' \\n')\n",
-      "Rl=100.;##Kohm\n",
-      "gl=0.01;\n",
-      "Av=-gm/(go+gl+go2);\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance =  1.41 mA/V\n",
-        "\n",
-        "\n",
-        "small signal transistor conductance=  0.01  mA/V\n",
-        "\n",
-        "\n",
-        "voltage gain=  -141.42  \n",
-        "\n",
-        "\n",
-        "voltage gain= \n",
-        " -70.71 \n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter11.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter11.ipynb
deleted file mode 100755
index b1d5c972..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter11.ipynb
+++ /dev/null
@@ -1,809 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:53c7431959a86fc1b01c39e3e1caf278b8c9abc2f1a0ad61d8cabdf9799d6026"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter11-Differential and Multistage Amplifier"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg642"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.1\n",
-      "V1=10.;\n",
-      "V2=-10.;\n",
-      "Iq=1.;\n",
-      "Rc=10.;\n",
-      "Vbe=0.7;\n",
-      "iC1=Iq/2.;\n",
-      "iC2=iC1;\n",
-      "print\"%s %.2f %s\"%('\\ncollector currents = ',iC1,'mA\\n')\n",
-      "Vc1=V1-iC1*Rc;\n",
-      "Vc2=Vc1;\n",
-      "print\"%s %.2f %s\"%('\\ncollector voltages = ',Vc1,'V\\n')\n",
-      "Vcm=0.;\n",
-      "Ve=Vcm-Vbe;\n",
-      "Vce1=Vc1-Ve;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce1,' V\\n')\n",
-      "Vcm=-5.;\n",
-      "Ve=Vcm-Vbe;\n",
-      "Vce1=Vc1-Ve;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage = ',Vce1,'V\\n')\n",
-      "Vcm=5.;\n",
-      "Ve=Vcm-Vbe;\n",
-      "Vce1=Vc1-Ve;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce1,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector currents =  0.50 mA\n",
-        "\n",
-        "\n",
-        "collector voltages =  5.00 V\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  5.70  V\n",
-        "\n",
-        "\n",
-        "collector emitter voltage =  10.70 V\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  0.70  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg650"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.3\n",
-      "V1=10.;\n",
-      "V2=-10.;\n",
-      "Iq=0.8*10**-3;\n",
-      "Rc=12000.;\n",
-      "Ro=25000.;\n",
-      "b=100.;\n",
-      "Vt=0.026;\n",
-      "Ad=Iq*Rc/(4.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\ndifferential gain=\\n',Ad,'')\n",
-      "Acm=-(Iq*Rc/(2.*Vt))/(1.+(1.+b)*Iq*Ro/(Vt*b));\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode gain=\\n',Acm,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "differential gain=\n",
-        " 92.31 \n",
-        "\n",
-        "common mode gain=\n",
-        " -0.24 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg657"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.7\n",
-      "Ad=92.3;\n",
-      "Acm=0.237;##mod of Acm\n",
-      "CMRR=Ad/Acm;\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode rejection ratio=\\n',CMRR,'')\n",
-      "CMRRdB=20.*math.log10(CMRR);\n",
-      "print\"%s %.2f %s\"%('\\nCMRR in decibels= ',CMRRdB,' dB\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "common mode rejection ratio=\n",
-        " 389.45 \n",
-        "\n",
-        "CMRR in decibels=  51.81  dB\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg658"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.8\n",
-      "CMRRdB=90.;##dB\n",
-      "CMRR=3.16*10**4;\n",
-      "b=100.;\n",
-      "Vt=0.026;\n",
-      "Iq=0.8;\n",
-      "Ro=(2.*CMRR-1.)*Vt*b/((1.+b)*Iq);\n",
-      "Ro=Ro*10**-3;##Mohm\n",
-      "print round(Ro,2)\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "2.03\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg661"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.9\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Va=100.;\n",
-      "Vt=0.026;\n",
-      "Iref=0.5;\n",
-      "Iq=Iref;\n",
-      "I1=Iq/2.\n",
-      "Icq=I1;\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal parameter= ',r,' KOhm\\n')\n",
-      "ro=Va/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nro= ',ro,' KOhm\\n')\n",
-      "Ro=Va/Iq;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of Q4= ',Ro,' KOhm\\n')\n",
-      "Rid=2.*r;\n",
-      "print\"%s %.2f %s\"%('\\ndifferential mode input resistance = ',Rid,'KOhm\\n')\n",
-      "Ricm=(1.+b)*(Ro*ro/2.)/(Ro+ro/2.);\n",
-      "Ricm=Ricm*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode input resistance= ',Ricm,' MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal parameter=  10.40  KOhm\n",
-        "\n",
-        "\n",
-        "ro=  400.00  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance of Q4=  200.00  KOhm\n",
-        "\n",
-        "\n",
-        "differential mode input resistance =  20.80 KOhm\n",
-        "\n",
-        "\n",
-        "common mode input resistance=  10.10  MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg664"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.10\n",
-      "Kn1=0.1;\n",
-      "Kn2=Kn1;\n",
-      "Kn3=0.1;\n",
-      "Kn4=Kn3;\n",
-      "R1=30.;\n",
-      "Vtn=1.;\n",
-      "Rd=16.;\n",
-      "##I1=(20-Vgs4)/R1 and I1=Kn3*(Vgs4-Vtn)^2\n",
-      "Vgs4=poly(0,'Vgs4')\n",
-      "p=poly([-1 -17 9],'Vgs4','c')\n",
-      "print\"%s %.2f %s\"%('\\nroots= ',roots(p),'V\\n')\n",
-      "Vgs4=2.40;\n",
-      "I1=(20.-Vgs4)/R1;\n",
-      "print\"%s %.2f %s\"%('\\nI1= ',I1,' mA\\n')\n",
-      "Iq=I1;\n",
-      "Id1=Iq/2.;\n",
-      "print\"%s %.2f %s\"%('\\nId1 and Id2 = ',Id1, 'mA\\n')\n",
-      "Vgs1=math.sqrt(Id1/Kn1)+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgs1 and Vgs2 = ',Vgs1,'V\\n')\n",
-      "vo1=10.-Id1*Rd;\n",
-      "print\"%s %.2f %s\"%('\\nvo1 and vo2= ',vo1,' V\\n')\n",
-      "Vds1=Vgs1-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVds1=Vds2=Vds1(sat)= ',Vds1,' V\\n')\n",
-      "Vcm=vo1-Vds1+Vgs1;\n",
-      "print\"%s %.2f %s\"%('\\nVcm max= ',Vcm,' V\\n')\n",
-      "Vds4=Vgs4-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVds4= ',Vds4,' V\\n')\n",
-      "Vcm2=Vgs1+Vds4-10.;\n",
-      "print\"%s %.2f %s\"%('\\nVcm min= ',Vcm2,'V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "ename": "SyntaxError",
-       "evalue": "invalid syntax (<ipython-input-6-8a87abc6284c>, line 13)",
-       "output_type": "pyerr",
-       "traceback": [
-        "\u001b[1;36m  File \u001b[1;32m\"<ipython-input-6-8a87abc6284c>\"\u001b[1;36m, line \u001b[1;32m13\u001b[0m\n\u001b[1;33m    p=poly([-1 -17 9],'Vgs4','c')\u001b[0m\n\u001b[1;37m                   ^\u001b[0m\n\u001b[1;31mSyntaxError\u001b[0m\u001b[1;31m:\u001b[0m invalid syntax\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg668"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.11\n",
-      "Kn=0.5;\n",
-      "Iq=1.;\n",
-      "Vt=0.026;\n",
-      "##transconductance of the MOSFET\n",
-      "gm=2.*math.sqrt(Kn*Iq/2);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "##transconductance of the bipolar transistor \n",
-      "gm=Iq/(2.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  1.00  mA/V\n",
-        "\n",
-        "\n",
-        "transconductance=  19.23  mA/V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg670"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.12\n",
-      "Iq=0.587;\n",
-      "Kn=1.;\n",
-      "Rd=16.;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "Ro=1./(y*Iq);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance = ',Ro,'KOhm\\n')\n",
-      "Ad=math.sqrt(Kn*Iq/2.)*Rd;\n",
-      "print\"%s %.2f %s\"%('\\ndifferential mode voltage gain= \\n',Ad,'')\n",
-      "Acm=-math.sqrt(2.*Kn*Iq)*Rd/(1.+2.*math.sqrt(2.*Kn*Iq)*Ro);\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode voltage gain=\\n',Acm,'')\n",
-      "CMRR=20.*math.log10(-Ad/Acm);\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode rejection ratio= ',CMRR,' dB\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance =  170.36 KOhm\n",
-        "\n",
-        "\n",
-        "differential mode voltage gain= \n",
-        " 8.67 \n",
-        "\n",
-        "common mode voltage gain=\n",
-        " -0.05 \n",
-        "\n",
-        "common mode rejection ratio=  45.35  dB\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg678"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.13\n",
-      "Iq=0.2;\n",
-      "Va=100.;\n",
-      "Va2=Va;\n",
-      "Va4=Va;\n",
-      "Rl=100.;\n",
-      "Vt=0.026;\n",
-      "Ad=(1./Vt)/(1./Va2+1./Va4);\n",
-      "print\"%s %.2f %s\"%('\\nopen circuit voltage gain=\\n',Ad,'')\n",
-      "Ad=(Iq/(2.*Vt))/(Iq/(2.*Va2)+Iq/(2.*Va4)+1./Rl);\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "open circuit voltage gain=\n",
-        " 1923.08 \n",
-        "\n",
-        "voltage gain=\n",
-        " 320.51 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg684"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.15\n",
-      "Kn=0.2;\n",
-      "Idq=0.1;\n",
-      "ro4=1000.;##Kohm\n",
-      "ro6=1000.;##KOhm\n",
-      "ro2=ro4;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "gm=2.*math.sqrt(Kn*Idq);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "ro=1./(y*Idq);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Ro=ro4+ro6*(1.+gm*ro);\n",
-      "Ro=Ro*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of the cascode active load= ',Ro,'Mohm\\n')\n",
-      "Ro=Ro*1000.;##KOhm\n",
-      "Ad=gm*ro2*Ro/(ro4+Ro);\n",
-      "print\"%s %.2f %s\"%('\\ndifferential mode voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  0.28  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  1000.00  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance of the cascode active load=  284.84 Mohm\n",
-        "\n",
-        "\n",
-        "differential mode voltage gain=\n",
-        " 281.85 \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg693"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.16\n",
-      "Iq=0.2;\n",
-      "Ic1=Iq;\n",
-      "Icb=1.;\n",
-      "R4=10.;\n",
-      "R3=0.2;\n",
-      "b=100.;\n",
-      "Va=100.;\n",
-      "Vt=0.026;\n",
-      "Ri=2.*(1.+b)*b*Vt/Iq;\n",
-      "Ri=Ri*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri,' MOhm\\n')\n",
-      "R11=b*Vt/Iq;\n",
-      "print\"%s %.2f %s\"%('\\nresistance R11= ',R11,' KOhm\\n')\n",
-      "Re=R11*R3/(R11+R3);\n",
-      "print\"%s %.2f %s\"%('\\nRe= ',Re,' KOhm\\n')\n",
-      "gm11=Iq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ngm11= ',gm11,' mA/V\\n')\n",
-      "ro11=Va/Iq;\n",
-      "print\"%s %.2f %s\"%('\\nro11 = ',ro11,'KOhm\\n')\n",
-      "Rc11=ro11*(1+gm11*Re);\n",
-      "Rc11=Rc11*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nRc11= ',Rc11,' MOhm\\n')\n",
-      "r8=b*Vt/Icb;\n",
-      "print\"%s %.2f %s\"%('\\nresistance= ',r8,'KOhm\\n')\n",
-      "##answer of following given in the book is wrong\n",
-      "Rb8=r8+(1.+b)*R4;\n",
-      "Rb8=Rb8*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nRb8 = ',Rb8,'MOhm\\n')\n",
-      "Rl7=Rc11*Rb8/(Rc11+Rb8);\n",
-      "print\"%s %.2f %s\"%('\\nRl7= ',Rl7,' MOhm\\n')\n",
-      "Av=Iq*Rl7/(2.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input resistance=  2.63  MOhm\n",
-        "\n",
-        "\n",
-        "resistance R11=  13.00  KOhm\n",
-        "\n",
-        "\n",
-        "Re=  0.20  KOhm\n",
-        "\n",
-        "\n",
-        "gm11=  7.69  mA/V\n",
-        "\n",
-        "\n",
-        "ro11 =  500.00 KOhm\n",
-        "\n",
-        "\n",
-        "Rc11=  1.26  MOhm\n",
-        "\n",
-        "\n",
-        "resistance=  2.60 KOhm\n",
-        "\n",
-        "\n",
-        "Rb8 =  1.01 MOhm\n",
-        "\n",
-        "\n",
-        "Rl7=  0.56  MOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " 2.16 \n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg694"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.17\n",
-      "Va=100.;\n",
-      "R4=10.;\n",
-      "b=100.;\n",
-      "Rc11=1.26*10**3;\n",
-      "r8=2.6;\n",
-      "Iq=0.2;\n",
-      "Rc7=Va/Iq;\n",
-      "print\"%s %.2f %s\"%('\\nRc7= ',Rc7,' KOhm\\n')\n",
-      "Z=Rc11*Rc7/(Rc11+Rc7);\n",
-      "print\"%s %.2f %s\"%('\\nZ= ',Z,' KOhm\\n')\n",
-      "x=(r8+Z)/(1.+b);\n",
-      "Ro=R4*x/(R4+x);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Rc7=  500.00  KOhm\n",
-        "\n",
-        "\n",
-        "Z=  357.95  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  2.63  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex19-pg697"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.19\n",
-      "b=100.;\n",
-      "Vt=0.026;\n",
-      "Rc=20.;\n",
-      "Ir4=0.4;\n",
-      "Iq=Ir4;\n",
-      "Ir6=Ir4;\n",
-      "r4=b*Vt/Ir4;\n",
-      "print\"%s %.2f %s\"%('\\nr4= ',r4,' KOhm\\n')\n",
-      "r3=b**2*Vt/Ir4;\n",
-      "print\"%s %.2f %s\"%('\\nr3= ',r3,' KOhm\\n')\n",
-      "Ri2=r3+(1.+b)*r4;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri2,' KOhm\\n')\n",
-      "gm=Iq/(2.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "Ad1=gm*Rc*Ri2/(2.*(Rc+Ri2));\n",
-      "print\"%s %.2f %s\"%('\\ngain of differential amplifier stage=\\n',Ad1,'')\n",
-      "r5=b*Vt/Ir6;\n",
-      "print\"%s %.2f %s\"%('\\nr5 = ',r5,'KOhm\\n')\n",
-      "Ir7=2.;\n",
-      "r6=b*Vt/Ir7;\n",
-      "print\"%s %.2f %s\"%('\\nr6= ',r6,' KOhm\\n')\n",
-      "R6=16.5;\n",
-      "R7=5.;\n",
-      "Ri3=r5+(1.+b)*(R6+r6+(1.+b)*R7);\n",
-      "Ri3=Ri3*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nRi3= ',Ri3,' MOhm\\n')\n",
-      "Rs=5.;\n",
-      "A2=Ir4*Rs/(2.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain A2=\\n',A2,'')\n",
-      "A3=1.;##vo/vo3\n",
-      "Ad=Ad1*A2*A3;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "r4=  6.50  KOhm\n",
-        "\n",
-        "\n",
-        "r3=  650.00  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance=  1306.50  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  7.69  mA/V\n",
-        "\n",
-        "\n",
-        "gain of differential amplifier stage=\n",
-        " 75.76 \n",
-        "\n",
-        "r5 =  6.50 KOhm\n",
-        "\n",
-        "\n",
-        "r6=  1.30  KOhm\n",
-        "\n",
-        "\n",
-        "Ri3=  52.81  MOhm\n",
-        "\n",
-        "\n",
-        "voltage gain A2=\n",
-        " 38.46 \n",
-        "\n",
-        "small signal voltage gain=\n",
-        " 2913.97 \n"
-       ]
-      }
-     ],
-     "prompt_number": 13
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex20-pg702"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.20\n",
-      "Ro=10000000.;\n",
-      "Co=1.*10**-12;\n",
-      "Rb=500.;\n",
-      "r=10000.;\n",
-      "b=100.;\n",
-      "f=1./(2.*math.pi*Ro*Co);\n",
-      "f=f*0.001;##KHz\n",
-      "print\"%s %.2f %s\"%('\\nfrequency of the zero= ',f,' KHz\\n')\n",
-      "Req=Ro*(1.+Rb/r)/(1.+Rb/r+2.*(1.+b)*Ro/r);\n",
-      "print\"%s %.2f %s\"%('\\nReq= ',Req,' Ohm\\n')\n",
-      "f=1/(2.*math.pi*Req*Co);\n",
-      "f=f*10**-9;##GHz\n",
-      "print\"%s %.2f %s\"%('\\nfrequency of the pole= ',f,' GHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "frequency of the zero=  15.92  KHz\n",
-        "\n",
-        "\n",
-        "Req=  51.98  Ohm\n",
-        "\n",
-        "\n",
-        "frequency of the pole=  3.06  GHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 14
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter11_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter11_1.ipynb
deleted file mode 100755
index 2169385c..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter11_1.ipynb
+++ /dev/null
@@ -1,829 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:0fdbe6834196a025d433ba7f08db65ee9b5adb39200cf4941d120ea6aacb306c"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter11-Differential and Multistage Amplifier"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg642"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.1\n",
-      "V1=10.;\n",
-      "V2=-10.;\n",
-      "Iq=1.;\n",
-      "Rc=10.;\n",
-      "Vbe=0.7;\n",
-      "iC1=Iq/2.;\n",
-      "iC2=iC1;\n",
-      "print\"%s %.2f %s\"%('\\ncollector currents = ',iC1,'mA\\n')\n",
-      "Vc1=V1-iC1*Rc;\n",
-      "Vc2=Vc1;\n",
-      "print\"%s %.2f %s\"%('\\ncollector voltages = ',Vc1,'V\\n')\n",
-      "Vcm=0.;\n",
-      "Ve=Vcm-Vbe;\n",
-      "Vce1=Vc1-Ve;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce1,' V\\n')\n",
-      "Vcm=-5.;\n",
-      "Ve=Vcm-Vbe;\n",
-      "Vce1=Vc1-Ve;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage = ',Vce1,'V\\n')\n",
-      "Vcm=5.;\n",
-      "Ve=Vcm-Vbe;\n",
-      "Vce1=Vc1-Ve;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce1,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector currents =  0.50 mA\n",
-        "\n",
-        "\n",
-        "collector voltages =  5.00 V\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  5.70  V\n",
-        "\n",
-        "\n",
-        "collector emitter voltage =  10.70 V\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  0.70  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg650"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.3\n",
-      "V1=10.;\n",
-      "V2=-10.;\n",
-      "Iq=0.8*10**-3;\n",
-      "Rc=12000.;\n",
-      "Ro=25000.;\n",
-      "b=100.;\n",
-      "Vt=0.026;\n",
-      "Ad=Iq*Rc/(4.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\ndifferential gain=\\n',Ad,'')\n",
-      "Acm=-(Iq*Rc/(2.*Vt))/(1.+(1.+b)*Iq*Ro/(Vt*b));\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode gain=\\n',Acm,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "differential gain=\n",
-        " 92.31 \n",
-        "\n",
-        "common mode gain=\n",
-        " -0.24 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg657"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.7\n",
-      "Ad=92.3;\n",
-      "Acm=0.237;##mod of Acm\n",
-      "CMRR=Ad/Acm;\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode rejection ratio=\\n',CMRR,'')\n",
-      "CMRRdB=20.*math.log10(CMRR);\n",
-      "print\"%s %.2f %s\"%('\\nCMRR in decibels= ',CMRRdB,' dB\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "common mode rejection ratio=\n",
-        " 389.45 \n",
-        "\n",
-        "CMRR in decibels=  51.81  dB\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg658"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.8\n",
-      "CMRRdB=90.;##dB\n",
-      "CMRR=3.16*10**4;\n",
-      "b=100.;\n",
-      "Vt=0.026;\n",
-      "Iq=0.8;\n",
-      "Ro=(2.*CMRR-1.)*Vt*b/((1.+b)*Iq);\n",
-      "Ro=Ro*10**-3;##Mohm\n",
-      "print round(Ro,2)\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "2.03\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg661"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.9\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Va=100.;\n",
-      "Vt=0.026;\n",
-      "Iref=0.5;\n",
-      "Iq=Iref;\n",
-      "I1=Iq/2.\n",
-      "Icq=I1;\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal parameter= ',r,' KOhm\\n')\n",
-      "ro=Va/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nro= ',ro,' KOhm\\n')\n",
-      "Ro=Va/Iq;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of Q4= ',Ro,' KOhm\\n')\n",
-      "Rid=2.*r;\n",
-      "print\"%s %.2f %s\"%('\\ndifferential mode input resistance = ',Rid,'KOhm\\n')\n",
-      "Ricm=(1.+b)*(Ro*ro/2.)/(Ro+ro/2.);\n",
-      "Ricm=Ricm*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode input resistance= ',Ricm,' MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal parameter=  10.40  KOhm\n",
-        "\n",
-        "\n",
-        "ro=  400.00  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance of Q4=  200.00  KOhm\n",
-        "\n",
-        "\n",
-        "differential mode input resistance =  20.80 KOhm\n",
-        "\n",
-        "\n",
-        "common mode input resistance=  10.10  MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg664"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "from numpy import poly\n",
-      "##Example 11.10\n",
-      "Kn1=0.1;\n",
-      "Kn2=Kn1;\n",
-      "Kn3=0.1;\n",
-      "Kn4=Kn3;\n",
-      "R1=30.;\n",
-      "Vtn=1.;\n",
-      "Rd=16.;\n",
-      "\n",
-      "Vgs4=2.40;\n",
-      "I1=(20.-Vgs4)/R1;\n",
-      "print\"%s %.2f %s\"%('\\nI1= ',I1,' mA\\n')\n",
-      "Iq=I1;\n",
-      "Id1=Iq/2.;\n",
-      "print\"%s %.2f %s\"%('\\nId1 and Id2 = ',Id1, 'mA\\n')\n",
-      "Vgs1=math.sqrt(Id1/Kn1)+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgs1 and Vgs2 = ',Vgs1,'V\\n')\n",
-      "vo1=10.-Id1*Rd;\n",
-      "print\"%s %.2f %s\"%('\\nvo1 and vo2= ',vo1,' V\\n')\n",
-      "Vds1=Vgs1-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVds1=Vds2=Vds1(sat)= ',Vds1,' V\\n')\n",
-      "Vcm=vo1-Vds1+Vgs1;\n",
-      "print\"%s %.2f %s\"%('\\nVcm max= ',Vcm,' V\\n')\n",
-      "Vds4=Vgs4-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVds4= ',Vds4,' V\\n')\n",
-      "Vcm2=Vgs1+Vds4-10.;\n",
-      "print\"%s %.2f %s\"%('\\nVcm min= ',Vcm2,'V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "I1=  0.59  mA\n",
-        "\n",
-        "\n",
-        "Id1 and Id2 =  0.29 mA\n",
-        "\n",
-        "\n",
-        "Vgs1 and Vgs2 =  2.71 V\n",
-        "\n",
-        "\n",
-        "vo1 and vo2=  5.31  V\n",
-        "\n",
-        "\n",
-        "Vds1=Vds2=Vds1(sat)=  1.71  V\n",
-        "\n",
-        "\n",
-        "Vcm max=  6.31  V\n",
-        "\n",
-        "\n",
-        "Vds4=  1.40  V\n",
-        "\n",
-        "\n",
-        "Vcm min=  -5.89 V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg668"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.11\n",
-      "Kn=0.5;\n",
-      "Iq=1.;\n",
-      "Vt=0.026;\n",
-      "##transconductance of the MOSFET\n",
-      "gm=2.*math.sqrt(Kn*Iq/2);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "##transconductance of the bipolar transistor \n",
-      "gm=Iq/(2.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  1.00  mA/V\n",
-        "\n",
-        "\n",
-        "transconductance=  19.23  mA/V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg670"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.12\n",
-      "Iq=0.587;\n",
-      "Kn=1.;\n",
-      "Rd=16.;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "Ro=1./(y*Iq);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance = ',Ro,'KOhm\\n')\n",
-      "Ad=math.sqrt(Kn*Iq/2.)*Rd;\n",
-      "print\"%s %.2f %s\"%('\\ndifferential mode voltage gain= \\n',Ad,'')\n",
-      "Acm=-math.sqrt(2.*Kn*Iq)*Rd/(1.+2.*math.sqrt(2.*Kn*Iq)*Ro);\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode voltage gain=\\n',Acm,'')\n",
-      "CMRR=20.*math.log10(-Ad/Acm);\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode rejection ratio= ',CMRR,' dB\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance =  170.36 KOhm\n",
-        "\n",
-        "\n",
-        "differential mode voltage gain= \n",
-        " 8.67 \n",
-        "\n",
-        "common mode voltage gain=\n",
-        " -0.05 \n",
-        "\n",
-        "common mode rejection ratio=  45.35  dB\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg678"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.13\n",
-      "Iq=0.2;\n",
-      "Va=100.;\n",
-      "Va2=Va;\n",
-      "Va4=Va;\n",
-      "Rl=100.;\n",
-      "Vt=0.026;\n",
-      "Ad=(1./Vt)/(1./Va2+1./Va4);\n",
-      "print\"%s %.2f %s\"%('\\nopen circuit voltage gain=\\n',Ad,'')\n",
-      "Ad=(Iq/(2.*Vt))/(Iq/(2.*Va2)+Iq/(2.*Va4)+1./Rl);\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "open circuit voltage gain=\n",
-        " 1923.08 \n",
-        "\n",
-        "voltage gain=\n",
-        " 320.51 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg684"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.15\n",
-      "Kn=0.2;\n",
-      "Idq=0.1;\n",
-      "ro4=1000.;##Kohm\n",
-      "ro6=1000.;##KOhm\n",
-      "ro2=ro4;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "gm=2.*math.sqrt(Kn*Idq);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "ro=1./(y*Idq);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Ro=ro4+ro6*(1.+gm*ro);\n",
-      "Ro=Ro*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of the cascode active load= ',Ro,'Mohm\\n')\n",
-      "Ro=Ro*1000.;##KOhm\n",
-      "Ad=gm*ro2*Ro/(ro4+Ro);\n",
-      "print\"%s %.2f %s\"%('\\ndifferential mode voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  0.28  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  1000.00  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance of the cascode active load=  284.84 Mohm\n",
-        "\n",
-        "\n",
-        "differential mode voltage gain=\n",
-        " 281.85 \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg693"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.16\n",
-      "Iq=0.2;\n",
-      "Ic1=Iq;\n",
-      "Icb=1.;\n",
-      "R4=10.;\n",
-      "R3=0.2;\n",
-      "b=100.;\n",
-      "Va=100.;\n",
-      "Vt=0.026;\n",
-      "Ri=2.*(1.+b)*b*Vt/Iq;\n",
-      "Ri=Ri*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri,' MOhm\\n')\n",
-      "R11=b*Vt/Iq;\n",
-      "print\"%s %.2f %s\"%('\\nresistance R11= ',R11,' KOhm\\n')\n",
-      "Re=R11*R3/(R11+R3);\n",
-      "print\"%s %.2f %s\"%('\\nRe= ',Re,' KOhm\\n')\n",
-      "gm11=Iq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ngm11= ',gm11,' mA/V\\n')\n",
-      "ro11=Va/Iq;\n",
-      "print\"%s %.2f %s\"%('\\nro11 = ',ro11,'KOhm\\n')\n",
-      "Rc11=ro11*(1+gm11*Re);\n",
-      "Rc11=Rc11*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nRc11= ',Rc11,' MOhm\\n')\n",
-      "r8=b*Vt/Icb;\n",
-      "print\"%s %.2f %s\"%('\\nresistance= ',r8,'KOhm\\n')\n",
-      "##answer of following given in the book is wrong\n",
-      "Rb8=r8+(1.+b)*R4;\n",
-      "Rb8=Rb8*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nRb8 = ',Rb8,'MOhm\\n')\n",
-      "Rl7=Rc11*Rb8/(Rc11+Rb8);\n",
-      "print\"%s %.2f %s\"%('\\nRl7= ',Rl7,' MOhm\\n')\n",
-      "Av=Iq*Rl7/(2.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input resistance=  2.63  MOhm\n",
-        "\n",
-        "\n",
-        "resistance R11=  13.00  KOhm\n",
-        "\n",
-        "\n",
-        "Re=  0.20  KOhm\n",
-        "\n",
-        "\n",
-        "gm11=  7.69  mA/V\n",
-        "\n",
-        "\n",
-        "ro11 =  500.00 KOhm\n",
-        "\n",
-        "\n",
-        "Rc11=  1.26  MOhm\n",
-        "\n",
-        "\n",
-        "resistance=  2.60 KOhm\n",
-        "\n",
-        "\n",
-        "Rb8 =  1.01 MOhm\n",
-        "\n",
-        "\n",
-        "Rl7=  0.56  MOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " 2.16 \n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg694"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.17\n",
-      "Va=100.;\n",
-      "R4=10.;\n",
-      "b=100.;\n",
-      "Rc11=1.26*10**3;\n",
-      "r8=2.6;\n",
-      "Iq=0.2;\n",
-      "Rc7=Va/Iq;\n",
-      "print\"%s %.2f %s\"%('\\nRc7= ',Rc7,' KOhm\\n')\n",
-      "Z=Rc11*Rc7/(Rc11+Rc7);\n",
-      "print\"%s %.2f %s\"%('\\nZ= ',Z,' KOhm\\n')\n",
-      "x=(r8+Z)/(1.+b);\n",
-      "Ro=R4*x/(R4+x);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Rc7=  500.00  KOhm\n",
-        "\n",
-        "\n",
-        "Z=  357.95  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  2.63  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex19-pg697"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.19\n",
-      "b=100.;\n",
-      "Vt=0.026;\n",
-      "Rc=20.;\n",
-      "Ir4=0.4;\n",
-      "Iq=Ir4;\n",
-      "Ir6=Ir4;\n",
-      "r4=b*Vt/Ir4;\n",
-      "print\"%s %.2f %s\"%('\\nr4= ',r4,' KOhm\\n')\n",
-      "r3=b**2*Vt/Ir4;\n",
-      "print\"%s %.2f %s\"%('\\nr3= ',r3,' KOhm\\n')\n",
-      "Ri2=r3+(1.+b)*r4;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri2,' KOhm\\n')\n",
-      "gm=Iq/(2.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "Ad1=gm*Rc*Ri2/(2.*(Rc+Ri2));\n",
-      "print\"%s %.2f %s\"%('\\ngain of differential amplifier stage=\\n',Ad1,'')\n",
-      "r5=b*Vt/Ir6;\n",
-      "print\"%s %.2f %s\"%('\\nr5 = ',r5,'KOhm\\n')\n",
-      "Ir7=2.;\n",
-      "r6=b*Vt/Ir7;\n",
-      "print\"%s %.2f %s\"%('\\nr6= ',r6,' KOhm\\n')\n",
-      "R6=16.5;\n",
-      "R7=5.;\n",
-      "Ri3=r5+(1.+b)*(R6+r6+(1.+b)*R7);\n",
-      "Ri3=Ri3*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nRi3= ',Ri3,' MOhm\\n')\n",
-      "Rs=5.;\n",
-      "A2=Ir4*Rs/(2.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain A2=\\n',A2,'')\n",
-      "A3=1.;##vo/vo3\n",
-      "Ad=Ad1*A2*A3;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "r4=  6.50  KOhm\n",
-        "\n",
-        "\n",
-        "r3=  650.00  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance=  1306.50  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  7.69  mA/V\n",
-        "\n",
-        "\n",
-        "gain of differential amplifier stage=\n",
-        " 75.76 \n",
-        "\n",
-        "r5 =  6.50 KOhm\n",
-        "\n",
-        "\n",
-        "r6=  1.30  KOhm\n",
-        "\n",
-        "\n",
-        "Ri3=  52.81  MOhm\n",
-        "\n",
-        "\n",
-        "voltage gain A2=\n",
-        " 38.46 \n",
-        "\n",
-        "small signal voltage gain=\n",
-        " 2913.97 \n"
-       ]
-      }
-     ],
-     "prompt_number": 13
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex20-pg702"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.20\n",
-      "Ro=10000000.;\n",
-      "Co=1.*10**-12;\n",
-      "Rb=500.;\n",
-      "r=10000.;\n",
-      "b=100.;\n",
-      "f=1./(2.*math.pi*Ro*Co);\n",
-      "f=f*0.001;##KHz\n",
-      "print\"%s %.2f %s\"%('\\nfrequency of the zero= ',f,' KHz\\n')\n",
-      "Req=Ro*(1.+Rb/r)/(1.+Rb/r+2.*(1.+b)*Ro/r);\n",
-      "print\"%s %.2f %s\"%('\\nReq= ',Req,' Ohm\\n')\n",
-      "f=1/(2.*math.pi*Req*Co);\n",
-      "f=f*10**-9;##GHz\n",
-      "print\"%s %.2f %s\"%('\\nfrequency of the pole= ',f,' GHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "frequency of the zero=  15.92  KHz\n",
-        "\n",
-        "\n",
-        "Req=  51.98  Ohm\n",
-        "\n",
-        "\n",
-        "frequency of the pole=  3.06  GHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 14
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter11_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter11_1_1.ipynb
deleted file mode 100755
index 4922457d..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter11_1_1.ipynb
+++ /dev/null
@@ -1,829 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:a62c54845c7e9347a8f02d330a533f4d6528b33252a4f4b96d8c27265abd4ced"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter11-Differential and Multistage Amplifier"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg642"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.1\n",
-      "V1=10.;\n",
-      "V2=-10.;\n",
-      "Iq=1.;\n",
-      "Rc=10.;\n",
-      "Vbe=0.7;\n",
-      "iC1=Iq/2.;\n",
-      "iC2=iC1;\n",
-      "print\"%s %.2f %s\"%('\\ncollector currents = ',iC1,'mA\\n')\n",
-      "Vc1=V1-iC1*Rc;\n",
-      "Vc2=Vc1;\n",
-      "print\"%s %.2f %s\"%('\\ncollector voltages = ',Vc1,'V\\n')\n",
-      "Vcm=0.;\n",
-      "Ve=Vcm-Vbe;\n",
-      "Vce1=Vc1-Ve;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce1,' V\\n')\n",
-      "Vcm=-5.;\n",
-      "Ve=Vcm-Vbe;\n",
-      "Vce1=Vc1-Ve;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage = ',Vce1,'V\\n')\n",
-      "Vcm=5.;\n",
-      "Ve=Vcm-Vbe;\n",
-      "Vce1=Vc1-Ve;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce1,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector currents =  0.50 mA\n",
-        "\n",
-        "\n",
-        "collector voltages =  5.00 V\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  5.70  V\n",
-        "\n",
-        "\n",
-        "collector emitter voltage =  10.70 V\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  0.70  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg650"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.3\n",
-      "V1=10.;\n",
-      "V2=-10.;\n",
-      "Iq=0.8*10**-3;\n",
-      "Rc=12000.;\n",
-      "Ro=25000.;\n",
-      "b=100.;\n",
-      "Vt=0.026;\n",
-      "Ad=Iq*Rc/(4.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\ndifferential gain=\\n',Ad,'')\n",
-      "Acm=-(Iq*Rc/(2.*Vt))/(1.+(1.+b)*Iq*Ro/(Vt*b));\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode gain=\\n',Acm,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "differential gain=\n",
-        " 92.31 \n",
-        "\n",
-        "common mode gain=\n",
-        " -0.24 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg657"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.7\n",
-      "Ad=92.3;\n",
-      "Acm=0.237;##mod of Acm\n",
-      "CMRR=Ad/Acm;\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode rejection ratio=\\n',CMRR,'')\n",
-      "CMRRdB=20.*math.log10(CMRR);\n",
-      "print\"%s %.2f %s\"%('\\nCMRR in decibels= ',CMRRdB,' dB\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "common mode rejection ratio=\n",
-        " 389.45 \n",
-        "\n",
-        "CMRR in decibels=  51.81  dB\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg658"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.8\n",
-      "CMRRdB=90.;##dB\n",
-      "CMRR=3.16*10**4;\n",
-      "b=100.;\n",
-      "Vt=0.026;\n",
-      "Iq=0.8;\n",
-      "Ro=(2.*CMRR-1.)*Vt*b/((1.+b)*Iq);\n",
-      "Ro=Ro*10**-3;##Mohm\n",
-      "print round(Ro,2)\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "2.03\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg661"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.9\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Va=100.;\n",
-      "Vt=0.026;\n",
-      "Iref=0.5;\n",
-      "Iq=Iref;\n",
-      "I1=Iq/2.\n",
-      "Icq=I1;\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal parameter= ',r,' KOhm\\n')\n",
-      "ro=Va/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nro= ',ro,' KOhm\\n')\n",
-      "Ro=Va/Iq;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of Q4= ',Ro,' KOhm\\n')\n",
-      "Rid=2.*r;\n",
-      "print\"%s %.2f %s\"%('\\ndifferential mode input resistance = ',Rid,'KOhm\\n')\n",
-      "Ricm=(1.+b)*(Ro*ro/2.)/(Ro+ro/2.);\n",
-      "Ricm=Ricm*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode input resistance= ',Ricm,' MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal parameter=  10.40  KOhm\n",
-        "\n",
-        "\n",
-        "ro=  400.00  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance of Q4=  200.00  KOhm\n",
-        "\n",
-        "\n",
-        "differential mode input resistance =  20.80 KOhm\n",
-        "\n",
-        "\n",
-        "common mode input resistance=  10.10  MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg664"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "from numpy import poly\n",
-      "##Example 11.10\n",
-      "Kn1=0.1;\n",
-      "Kn2=Kn1;\n",
-      "Kn3=0.1;\n",
-      "Kn4=Kn3;\n",
-      "R1=30.;\n",
-      "Vtn=1.;\n",
-      "Rd=16.;\n",
-      "\n",
-      "Vgs4=2.40;\n",
-      "I1=(20.-Vgs4)/R1;\n",
-      "print\"%s %.2f %s\"%('\\nI1= ',I1,' mA\\n')\n",
-      "Iq=I1;\n",
-      "Id1=Iq/2.;\n",
-      "print\"%s %.2f %s\"%('\\nId1 and Id2 = ',Id1, 'mA\\n')\n",
-      "Vgs1=math.sqrt(Id1/Kn1)+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgs1 and Vgs2 = ',Vgs1,'V\\n')\n",
-      "vo1=10.-Id1*Rd;\n",
-      "print\"%s %.2f %s\"%('\\nvo1 and vo2= ',vo1,' V\\n')\n",
-      "Vds1=Vgs1-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVds1=Vds2=Vds1(sat)= ',Vds1,' V\\n')\n",
-      "Vcm=vo1-Vds1+Vgs1;\n",
-      "print\"%s %.2f %s\"%('\\nVcm max= ',Vcm,' V\\n')\n",
-      "Vds4=Vgs4-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVds4= ',Vds4,' V\\n')\n",
-      "Vcm2=Vgs1+Vds4-10.;\n",
-      "print\"%s %.2f %s\"%('\\nVcm min= ',Vcm2,'V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "I1=  0.59  mA\n",
-        "\n",
-        "\n",
-        "Id1 and Id2 =  0.29 mA\n",
-        "\n",
-        "\n",
-        "Vgs1 and Vgs2 =  2.71 V\n",
-        "\n",
-        "\n",
-        "vo1 and vo2=  5.31  V\n",
-        "\n",
-        "\n",
-        "Vds1=Vds2=Vds1(sat)=  1.71  V\n",
-        "\n",
-        "\n",
-        "Vcm max=  6.31  V\n",
-        "\n",
-        "\n",
-        "Vds4=  1.40  V\n",
-        "\n",
-        "\n",
-        "Vcm min=  -5.89 V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg668"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.11\n",
-      "Kn=0.5;\n",
-      "Iq=1.;\n",
-      "Vt=0.026;\n",
-      "##transconductance of the MOSFET\n",
-      "gm=2.*math.sqrt(Kn*Iq/2);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "##transconductance of the bipolar transistor \n",
-      "gm=Iq/(2.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  1.00  mA/V\n",
-        "\n",
-        "\n",
-        "transconductance=  19.23  mA/V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg670"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.12\n",
-      "Iq=0.587;\n",
-      "Kn=1.;\n",
-      "Rd=16.;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "Ro=1./(y*Iq);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance = ',Ro,'KOhm\\n')\n",
-      "Ad=math.sqrt(Kn*Iq/2.)*Rd;\n",
-      "print\"%s %.2f %s\"%('\\ndifferential mode voltage gain= \\n',Ad,'')\n",
-      "Acm=-math.sqrt(2.*Kn*Iq)*Rd/(1.+2.*math.sqrt(2.*Kn*Iq)*Ro);\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode voltage gain=\\n',Acm,'')\n",
-      "CMRR=20.*math.log10(-Ad/Acm);\n",
-      "print\"%s %.2f %s\"%('\\ncommon mode rejection ratio= ',CMRR,' dB\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance =  170.36 KOhm\n",
-        "\n",
-        "\n",
-        "differential mode voltage gain= \n",
-        " 8.67 \n",
-        "\n",
-        "common mode voltage gain=\n",
-        " -0.05 \n",
-        "\n",
-        "common mode rejection ratio=  45.35  dB\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg678"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.13\n",
-      "Iq=0.2;\n",
-      "Va=100.;\n",
-      "Va2=Va;\n",
-      "Va4=Va;\n",
-      "Rl=100.;\n",
-      "Vt=0.026;\n",
-      "Ad=(1./Vt)/(1./Va2+1./Va4);\n",
-      "print\"%s %.2f %s\"%('\\nopen circuit voltage gain=\\n',Ad,'')\n",
-      "Ad=(Iq/(2.*Vt))/(Iq/(2.*Va2)+Iq/(2.*Va4)+1./Rl);\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "open circuit voltage gain=\n",
-        " 1923.08 \n",
-        "\n",
-        "voltage gain=\n",
-        " 320.51 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg684"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.15\n",
-      "Kn=0.2;\n",
-      "Idq=0.1;\n",
-      "ro4=1000.;##Kohm\n",
-      "ro6=1000.;##KOhm\n",
-      "ro2=ro4;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "gm=2.*math.sqrt(Kn*Idq);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "ro=1./(y*Idq);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Ro=ro4+ro6*(1.+gm*ro);\n",
-      "Ro=Ro*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of the cascode active load= ',Ro,'Mohm\\n')\n",
-      "Ro=Ro*1000.;##KOhm\n",
-      "Ad=gm*ro2*Ro/(ro4+Ro);\n",
-      "print\"%s %.2f %s\"%('\\ndifferential mode voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  0.28  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  1000.00  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance of the cascode active load=  284.84 Mohm\n",
-        "\n",
-        "\n",
-        "differential mode voltage gain=\n",
-        " 281.85 \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg693"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.16\n",
-      "Iq=0.2;\n",
-      "Ic1=Iq;\n",
-      "Icb=1.;\n",
-      "R4=10.;\n",
-      "R3=0.2;\n",
-      "b=100.;\n",
-      "Va=100.;\n",
-      "Vt=0.026;\n",
-      "Ri=2.*(1.+b)*b*Vt/Iq;\n",
-      "Ri=Ri*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri,' MOhm\\n')\n",
-      "R11=b*Vt/Iq;\n",
-      "print\"%s %.2f %s\"%('\\nresistance R11= ',R11,' KOhm\\n')\n",
-      "Re=R11*R3/(R11+R3);\n",
-      "print\"%s %.2f %s\"%('\\nRe= ',Re,' KOhm\\n')\n",
-      "gm11=Iq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ngm11= ',gm11,' mA/V\\n')\n",
-      "ro11=Va/Iq;\n",
-      "print\"%s %.2f %s\"%('\\nro11 = ',ro11,'KOhm\\n')\n",
-      "Rc11=ro11*(1+gm11*Re);\n",
-      "Rc11=Rc11*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nRc11= ',Rc11,' MOhm\\n')\n",
-      "r8=b*Vt/Icb;\n",
-      "print\"%s %.2f %s\"%('\\nresistance= ',r8,'KOhm\\n')\n",
-      "##answer of following given in the book is wrong\n",
-      "Rb8=r8+(1.+b)*R4;\n",
-      "Rb8=Rb8*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nRb8 = ',Rb8,'MOhm\\n')\n",
-      "Rl7=Rc11*Rb8/(Rc11+Rb8);\n",
-      "print\"%s %.2f %s\"%('\\nRl7= ',Rl7,' MOhm\\n')\n",
-      "Av=Iq*Rl7/(2.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input resistance=  2.63  MOhm\n",
-        "\n",
-        "\n",
-        "resistance R11=  13.00  KOhm\n",
-        "\n",
-        "\n",
-        "Re=  0.20  KOhm\n",
-        "\n",
-        "\n",
-        "gm11=  7.69  mA/V\n",
-        "\n",
-        "\n",
-        "ro11 =  500.00 KOhm\n",
-        "\n",
-        "\n",
-        "Rc11=  1.26  MOhm\n",
-        "\n",
-        "\n",
-        "resistance=  2.60 KOhm\n",
-        "\n",
-        "\n",
-        "Rb8 =  1.01 MOhm\n",
-        "\n",
-        "\n",
-        "Rl7=  0.56  MOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " 2.16 \n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg694"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.17\n",
-      "Va=100.;\n",
-      "R4=10.;\n",
-      "b=100.;\n",
-      "Rc11=1.26*10**3;\n",
-      "r8=2.6;\n",
-      "Iq=0.2;\n",
-      "Rc7=Va/Iq;\n",
-      "print\"%s %.2f %s\"%('\\nRc7= ',Rc7,' KOhm\\n')\n",
-      "Z=Rc11*Rc7/(Rc11+Rc7);\n",
-      "print\"%s %.2f %s\"%('\\nZ= ',Z,' KOhm\\n')\n",
-      "x=(r8+Z)/(1.+b);\n",
-      "Ro=R4*x/(R4+x);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Rc7=  500.00  KOhm\n",
-        "\n",
-        "\n",
-        "Z=  357.95  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  2.63  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex19-pg697"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.19\n",
-      "b=100.;\n",
-      "Vt=0.026;\n",
-      "Rc=20.;\n",
-      "Ir4=0.4;\n",
-      "Iq=Ir4;\n",
-      "Ir6=Ir4;\n",
-      "r4=b*Vt/Ir4;\n",
-      "print\"%s %.2f %s\"%('\\nr4= ',r4,' KOhm\\n')\n",
-      "r3=b**2*Vt/Ir4;\n",
-      "print\"%s %.2f %s\"%('\\nr3= ',r3,' KOhm\\n')\n",
-      "Ri2=r3+(1.+b)*r4;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri2,' KOhm\\n')\n",
-      "gm=Iq/(2.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "Ad1=gm*Rc*Ri2/(2.*(Rc+Ri2));\n",
-      "print\"%s %.2f %s\"%('\\ngain of differential amplifier stage=\\n',Ad1,'')\n",
-      "r5=b*Vt/Ir6;\n",
-      "print\"%s %.2f %s\"%('\\nr5 = ',r5,'KOhm\\n')\n",
-      "Ir7=2.;\n",
-      "r6=b*Vt/Ir7;\n",
-      "print\"%s %.2f %s\"%('\\nr6= ',r6,' KOhm\\n')\n",
-      "R6=16.5;\n",
-      "R7=5.;\n",
-      "Ri3=r5+(1.+b)*(R6+r6+(1.+b)*R7);\n",
-      "Ri3=Ri3*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nRi3= ',Ri3,' MOhm\\n')\n",
-      "Rs=5.;\n",
-      "A2=Ir4*Rs/(2.*Vt);\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain A2=\\n',A2,'')\n",
-      "A3=1.;##vo/vo3\n",
-      "Ad=Ad1*A2*A3;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "r4=  6.50  KOhm\n",
-        "\n",
-        "\n",
-        "r3=  650.00  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance=  1306.50  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  7.69  mA/V\n",
-        "\n",
-        "\n",
-        "gain of differential amplifier stage=\n",
-        " 75.76 \n",
-        "\n",
-        "r5 =  6.50 KOhm\n",
-        "\n",
-        "\n",
-        "r6=  1.30  KOhm\n",
-        "\n",
-        "\n",
-        "Ri3=  52.81  MOhm\n",
-        "\n",
-        "\n",
-        "voltage gain A2=\n",
-        " 38.46 \n",
-        "\n",
-        "small signal voltage gain=\n",
-        " 2913.97 \n"
-       ]
-      }
-     ],
-     "prompt_number": 13
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex20-pg702"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 11.20\n",
-      "Ro=10000000.;\n",
-      "Co=1.*10**-12;\n",
-      "Rb=500.;\n",
-      "r=10000.;\n",
-      "b=100.;\n",
-      "f=1./(2.*math.pi*Ro*Co);\n",
-      "f=f*0.001;##KHz\n",
-      "print\"%s %.2f %s\"%('\\nfrequency of the zero= ',f,' KHz\\n')\n",
-      "Req=Ro*(1.+Rb/r)/(1.+Rb/r+2.*(1.+b)*Ro/r);\n",
-      "print\"%s %.2f %s\"%('\\nReq= ',Req,' Ohm\\n')\n",
-      "f=1/(2.*math.pi*Req*Co);\n",
-      "f=f*10**-9;##GHz\n",
-      "print\"%s %.2f %s\"%('\\nfrequency of the pole= ',f,' GHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "frequency of the zero=  15.92  KHz\n",
-        "\n",
-        "\n",
-        "Req=  51.98  Ohm\n",
-        "\n",
-        "\n",
-        "frequency of the pole=  3.06  GHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 14
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter12.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter12.ipynb
deleted file mode 100755
index 448e6f50..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter12.ipynb
+++ /dev/null
@@ -1,540 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:a45447f2d4288231e83b274110baf3c884392e16ba16d91e2efdd93828802282"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter12-Feedback and Stability"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg732"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.1\n",
-      "A=10**5;##open loop gain\n",
-      "Af=50.;##closed loop gain\n",
-      "b=(A/Af-1.)/A;\n",
-      "print\"%s %.2f %s\"%('\\nfeedback transfer function=\\n',b,'')\n",
-      "A=-10**5;\n",
-      "Af=-50.;\n",
-      "b=(A/Af-1.)/A;\n",
-      "print\"%s %.2f %s\"%('\\nfeedback transfer function=\\n',b,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "feedback transfer function=\n",
-        " 0.02 \n",
-        "\n",
-        "feedback transfer function=\n",
-        " -0.02 \n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg733"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.2\n",
-      "A=10**5;\n",
-      "Af=50.;\n",
-      "b=0.019999;\n",
-      "dA=10**4;\n",
-      "dAf=Af*dA/(A*(1.+b*A));\n",
-      "print\"%s %.2e %s\"%('\\ndAf ',dAf,'\\n')\n",
-      "##x=dAf/Af\n",
-      "x=dAf/Af;\n",
-      "x=x*100.;\n",
-      "print\"%s %.2e %s\"%('\\npercent change dAf/Af= ',x,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "dAf  2.50e-03 \n",
-        "\n",
-        "\n",
-        "percent change dAf/Af=  5.00e-03 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg735"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.3\n",
-      "Ao=10**4;\n",
-      "wh=2.*math.pi*100.;##rad/s\n",
-      "Af=50.;\n",
-      "##x=(1+bAo)\n",
-      "x=Ao/Af;\n",
-      "print\"%s %.2f %s\"%('\\n(1+bAo)=\\n',x,'')\n",
-      "wfh=wh*x;\n",
-      "print\"%s %.2f %s\"%('\\nclosed loop bandwidth=\\n',wfh,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "(1+bAo)=\n",
-        " 200.00 \n",
-        "\n",
-        "closed loop bandwidth=\n",
-        " 125663.71 \n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg742"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 12.5\n",
-      "Av=10**5;\n",
-      "Avf=50.;\n",
-      "Rf=10.;##Kohm\n",
-      "Ro=20000.;##Ohm\n",
-      "##x=(1+bvAv)\n",
-      "x=Av/Avf;\n",
-      "print\"%s %.2e %s\"%('\\n(1+bvAv)=\\n',x,'')\n",
-      "Rif=Rf*x;\n",
-      "Rif=Rif*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Rif,' MOhm\\n')\n",
-      "Rof=Ro/x;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Rof,' Ohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "(1+bvAv)=\n",
-        " 2.00e+03 \n",
-        "\n",
-        "input resistance=  20.00  MOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  10.00  Ohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg745"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.6\n",
-      "Af=10**5;\n",
-      "Aif=50.;\n",
-      "Rf=10000.;\n",
-      "Ro=20.;\n",
-      "##x=(1+biAi)\n",
-      "x=Af/Aif;\n",
-      "print\"%s %.2e %s\"%('\\n(1+biAi)=\\n',x,'')\n",
-      "Rif=Rf/x;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance =  ',Rif,'Ohm\\n')\n",
-      "Rof=Ro*x;\n",
-      "Rof=Rof*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Rof,' MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "(1+biAi)=\n",
-        " 2.00e+03 \n",
-        "\n",
-        "input resistance =   5.00 Ohm\n",
-        "\n",
-        "\n",
-        "output resistance=  40.00  MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg751"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.7\n",
-      "Ri=50.;\n",
-      "R1=10.;\n",
-      "R2=90.;\n",
-      "Av=10**4;\n",
-      "bv=1./(1.+R2/R1);\n",
-      "print\"%s %.2f %s\"%('\\nfeedback transfer function=\\n',bv,'')\n",
-      "Rif=Ri*(1.+bv*Av);\n",
-      "Rif=Rif*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Rif,' MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "feedback transfer function=\n",
-        " 0.10 \n",
-        "\n",
-        "input resistance=  50.05  MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg765"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 12.11\n",
-      "hFE=100.;##transistor parameter\n",
-      "Vbe=0.7;\n",
-      "Vcc=10.;\n",
-      "R1=55.;\n",
-      "R2=12.;\n",
-      "Re=1.;\n",
-      "Rc=4.;\n",
-      "Rl=4.;\n",
-      "Icq=0.983;\n",
-      "Vceq=5.08;\n",
-      "Vt=0.026;\n",
-      "r=hFE*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal parameter resistance= ',r,' KOhm\\n')\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "Agf=-gm*(Rc/(Rc+Rl))/(1.+Re*(gm+1./r));\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance transfer function= ',Agf,' mA/V\\n')\n",
-      "##as first approximation\n",
-      "Agf2=-1./Re;\n",
-      "print\"%s %.2f %s\"%('\\nAgf= ',Agf2,' mA/V\\n')\n",
-      "Avf=Agf*Rl;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain=\\n',Avf,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal parameter resistance=  2.64  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  37.81  mA/V\n",
-        "\n",
-        "\n",
-        "transconductance transfer function=  -0.48  mA/V\n",
-        "\n",
-        "\n",
-        "Agf=  -1.00  mA/V\n",
-        "\n",
-        "\n",
-        "voltage gain=\n",
-        " -1.93 \n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg777"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.15\n",
-      "##Determine the loop gain fig12.45(a)\n",
-      "hFE=100.;\n",
-      "Vbe=0.7;\n",
-      "Icq=0.492;\n",
-      "r=5.28;\n",
-      "gm=18.9;\n",
-      "Rs=10.;\n",
-      "R1=51.;\n",
-      "R2=5.5;\n",
-      "Re=0.500;\n",
-      "Rc=10.;\n",
-      "Rf=82.;\n",
-      "x=r*R2/(r+R2);\n",
-      "y=R1*x/(x+R1);\n",
-      "t=Rs*y/(y+Rs);\n",
-      "Req=t;\n",
-      "print\"%s %.2f %s\"%('\\nequivalent resistance ',t,' KOhm\\n')\n",
-      "T=gm*Rc*Req/(Rc+Rf+Req);\n",
-      "print\"%s %.2f %s\"%('\\nthe loop gain=\\n',T,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "equivalent resistance  2.04  KOhm\n",
-        "\n",
-        "\n",
-        "the loop gain=\n",
-        " 4.09 \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex19-pg791"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.19\n",
-      "##T=b*100/(sqrt(1+(f/10^5)^2) angle=-3tan^-1(f/10^5)\n",
-      "##stable at f180 at which phase becomes -180 degrees\n",
-      "##-3*atan(f180/10^5)=-180\n",
-      "f180=math.tan(60/57.3)*10**5;\n",
-      "print\"%s %.2f %s\"%('\\nfrequency at -180 degree= ',f180,'f Hz\\n')\n",
-      "b=0.2;\n",
-      "T=b*100./(math.sqrt(1.+(f180/10**5)**2))**3;\n",
-      "print\"%s %.2f %s\"%('\\nmagnitude of the loop gain=\\n',T,'')\n",
-      "b=0.02;\n",
-      "T=b*100./(math.sqrt(1.+(f180/10**5)**2))**3;\n",
-      "print\"%s %.2f %s\"%('\\nmagnitude of the loop gain=\\n',T,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "frequency at -180 degree=  173174.23 f Hz\n",
-        "\n",
-        "\n",
-        "magnitude of the loop gain=\n",
-        " 2.50 \n",
-        "\n",
-        "magnitude of the loop gain=\n",
-        " 0.25 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex22-pg798"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.22\n",
-      "Ao=10**6;\n",
-      "fPD=0.010;##KHz\n",
-      "b=0.01;\n",
-      "Af=Ao/(1.+b*Ao);\n",
-      "print\"%s %.2f %s\"%('\\nlow frequency closed loop gain=\\n',Af,'')\n",
-      "fc=fPD*(1.+b*Ao);\n",
-      "print\"%s %.2f %s\"%('\\nclosed loop 3dB frequency= ',fc,' KHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "low frequency closed loop gain=\n",
-        " 99.99 \n",
-        "\n",
-        "closed loop 3dB frequency=  100.01  KHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex23-pg799"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.23\n",
-      "A=10**3;\n",
-      "Cf=30.*10**-12;##feedback capacitor (F)\n",
-      "R2=5.*10**5;\n",
-      "Cm=Cf*(1.+A);\n",
-      "print\"%s %.2e %s\"%('\\nMiller capacitance= ',Cm,' F\\n')\n",
-      "fp=1/(2.*math.pi*R2*Cm);\n",
-      "print\"%s %.2f %s\"%('\\ndominant pole frequency = ',fp,'Hz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Miller capacitance=  3.00e-08  F\n",
-        "\n",
-        "\n",
-        "dominant pole frequency =  10.60 Hz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter12_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter12_1.ipynb
deleted file mode 100755
index 448e6f50..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter12_1.ipynb
+++ /dev/null
@@ -1,540 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:a45447f2d4288231e83b274110baf3c884392e16ba16d91e2efdd93828802282"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter12-Feedback and Stability"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg732"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.1\n",
-      "A=10**5;##open loop gain\n",
-      "Af=50.;##closed loop gain\n",
-      "b=(A/Af-1.)/A;\n",
-      "print\"%s %.2f %s\"%('\\nfeedback transfer function=\\n',b,'')\n",
-      "A=-10**5;\n",
-      "Af=-50.;\n",
-      "b=(A/Af-1.)/A;\n",
-      "print\"%s %.2f %s\"%('\\nfeedback transfer function=\\n',b,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "feedback transfer function=\n",
-        " 0.02 \n",
-        "\n",
-        "feedback transfer function=\n",
-        " -0.02 \n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg733"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.2\n",
-      "A=10**5;\n",
-      "Af=50.;\n",
-      "b=0.019999;\n",
-      "dA=10**4;\n",
-      "dAf=Af*dA/(A*(1.+b*A));\n",
-      "print\"%s %.2e %s\"%('\\ndAf ',dAf,'\\n')\n",
-      "##x=dAf/Af\n",
-      "x=dAf/Af;\n",
-      "x=x*100.;\n",
-      "print\"%s %.2e %s\"%('\\npercent change dAf/Af= ',x,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "dAf  2.50e-03 \n",
-        "\n",
-        "\n",
-        "percent change dAf/Af=  5.00e-03 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg735"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.3\n",
-      "Ao=10**4;\n",
-      "wh=2.*math.pi*100.;##rad/s\n",
-      "Af=50.;\n",
-      "##x=(1+bAo)\n",
-      "x=Ao/Af;\n",
-      "print\"%s %.2f %s\"%('\\n(1+bAo)=\\n',x,'')\n",
-      "wfh=wh*x;\n",
-      "print\"%s %.2f %s\"%('\\nclosed loop bandwidth=\\n',wfh,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "(1+bAo)=\n",
-        " 200.00 \n",
-        "\n",
-        "closed loop bandwidth=\n",
-        " 125663.71 \n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg742"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 12.5\n",
-      "Av=10**5;\n",
-      "Avf=50.;\n",
-      "Rf=10.;##Kohm\n",
-      "Ro=20000.;##Ohm\n",
-      "##x=(1+bvAv)\n",
-      "x=Av/Avf;\n",
-      "print\"%s %.2e %s\"%('\\n(1+bvAv)=\\n',x,'')\n",
-      "Rif=Rf*x;\n",
-      "Rif=Rif*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Rif,' MOhm\\n')\n",
-      "Rof=Ro/x;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Rof,' Ohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "(1+bvAv)=\n",
-        " 2.00e+03 \n",
-        "\n",
-        "input resistance=  20.00  MOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  10.00  Ohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg745"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.6\n",
-      "Af=10**5;\n",
-      "Aif=50.;\n",
-      "Rf=10000.;\n",
-      "Ro=20.;\n",
-      "##x=(1+biAi)\n",
-      "x=Af/Aif;\n",
-      "print\"%s %.2e %s\"%('\\n(1+biAi)=\\n',x,'')\n",
-      "Rif=Rf/x;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance =  ',Rif,'Ohm\\n')\n",
-      "Rof=Ro*x;\n",
-      "Rof=Rof*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Rof,' MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "(1+biAi)=\n",
-        " 2.00e+03 \n",
-        "\n",
-        "input resistance =   5.00 Ohm\n",
-        "\n",
-        "\n",
-        "output resistance=  40.00  MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg751"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.7\n",
-      "Ri=50.;\n",
-      "R1=10.;\n",
-      "R2=90.;\n",
-      "Av=10**4;\n",
-      "bv=1./(1.+R2/R1);\n",
-      "print\"%s %.2f %s\"%('\\nfeedback transfer function=\\n',bv,'')\n",
-      "Rif=Ri*(1.+bv*Av);\n",
-      "Rif=Rif*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Rif,' MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "feedback transfer function=\n",
-        " 0.10 \n",
-        "\n",
-        "input resistance=  50.05  MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg765"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 12.11\n",
-      "hFE=100.;##transistor parameter\n",
-      "Vbe=0.7;\n",
-      "Vcc=10.;\n",
-      "R1=55.;\n",
-      "R2=12.;\n",
-      "Re=1.;\n",
-      "Rc=4.;\n",
-      "Rl=4.;\n",
-      "Icq=0.983;\n",
-      "Vceq=5.08;\n",
-      "Vt=0.026;\n",
-      "r=hFE*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal parameter resistance= ',r,' KOhm\\n')\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "Agf=-gm*(Rc/(Rc+Rl))/(1.+Re*(gm+1./r));\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance transfer function= ',Agf,' mA/V\\n')\n",
-      "##as first approximation\n",
-      "Agf2=-1./Re;\n",
-      "print\"%s %.2f %s\"%('\\nAgf= ',Agf2,' mA/V\\n')\n",
-      "Avf=Agf*Rl;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain=\\n',Avf,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal parameter resistance=  2.64  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  37.81  mA/V\n",
-        "\n",
-        "\n",
-        "transconductance transfer function=  -0.48  mA/V\n",
-        "\n",
-        "\n",
-        "Agf=  -1.00  mA/V\n",
-        "\n",
-        "\n",
-        "voltage gain=\n",
-        " -1.93 \n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg777"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.15\n",
-      "##Determine the loop gain fig12.45(a)\n",
-      "hFE=100.;\n",
-      "Vbe=0.7;\n",
-      "Icq=0.492;\n",
-      "r=5.28;\n",
-      "gm=18.9;\n",
-      "Rs=10.;\n",
-      "R1=51.;\n",
-      "R2=5.5;\n",
-      "Re=0.500;\n",
-      "Rc=10.;\n",
-      "Rf=82.;\n",
-      "x=r*R2/(r+R2);\n",
-      "y=R1*x/(x+R1);\n",
-      "t=Rs*y/(y+Rs);\n",
-      "Req=t;\n",
-      "print\"%s %.2f %s\"%('\\nequivalent resistance ',t,' KOhm\\n')\n",
-      "T=gm*Rc*Req/(Rc+Rf+Req);\n",
-      "print\"%s %.2f %s\"%('\\nthe loop gain=\\n',T,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "equivalent resistance  2.04  KOhm\n",
-        "\n",
-        "\n",
-        "the loop gain=\n",
-        " 4.09 \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex19-pg791"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.19\n",
-      "##T=b*100/(sqrt(1+(f/10^5)^2) angle=-3tan^-1(f/10^5)\n",
-      "##stable at f180 at which phase becomes -180 degrees\n",
-      "##-3*atan(f180/10^5)=-180\n",
-      "f180=math.tan(60/57.3)*10**5;\n",
-      "print\"%s %.2f %s\"%('\\nfrequency at -180 degree= ',f180,'f Hz\\n')\n",
-      "b=0.2;\n",
-      "T=b*100./(math.sqrt(1.+(f180/10**5)**2))**3;\n",
-      "print\"%s %.2f %s\"%('\\nmagnitude of the loop gain=\\n',T,'')\n",
-      "b=0.02;\n",
-      "T=b*100./(math.sqrt(1.+(f180/10**5)**2))**3;\n",
-      "print\"%s %.2f %s\"%('\\nmagnitude of the loop gain=\\n',T,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "frequency at -180 degree=  173174.23 f Hz\n",
-        "\n",
-        "\n",
-        "magnitude of the loop gain=\n",
-        " 2.50 \n",
-        "\n",
-        "magnitude of the loop gain=\n",
-        " 0.25 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex22-pg798"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.22\n",
-      "Ao=10**6;\n",
-      "fPD=0.010;##KHz\n",
-      "b=0.01;\n",
-      "Af=Ao/(1.+b*Ao);\n",
-      "print\"%s %.2f %s\"%('\\nlow frequency closed loop gain=\\n',Af,'')\n",
-      "fc=fPD*(1.+b*Ao);\n",
-      "print\"%s %.2f %s\"%('\\nclosed loop 3dB frequency= ',fc,' KHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "low frequency closed loop gain=\n",
-        " 99.99 \n",
-        "\n",
-        "closed loop 3dB frequency=  100.01  KHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex23-pg799"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.23\n",
-      "A=10**3;\n",
-      "Cf=30.*10**-12;##feedback capacitor (F)\n",
-      "R2=5.*10**5;\n",
-      "Cm=Cf*(1.+A);\n",
-      "print\"%s %.2e %s\"%('\\nMiller capacitance= ',Cm,' F\\n')\n",
-      "fp=1/(2.*math.pi*R2*Cm);\n",
-      "print\"%s %.2f %s\"%('\\ndominant pole frequency = ',fp,'Hz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Miller capacitance=  3.00e-08  F\n",
-        "\n",
-        "\n",
-        "dominant pole frequency =  10.60 Hz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter12_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter12_1_1.ipynb
deleted file mode 100755
index 4335c4e4..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter12_1_1.ipynb
+++ /dev/null
@@ -1,540 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:1ace7ec8ddbfe04d19fdbb2c12f100c57a3d84e0fdba823b9d7bc82551c86874"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter12-Feedback and Stability"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg732"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.1\n",
-      "A=10**5;##open loop gain\n",
-      "Af=50.;##closed loop gain\n",
-      "b=(A/Af-1.)/A;\n",
-      "print\"%s %.2f %s\"%('\\nfeedback transfer function=\\n',b,'')\n",
-      "A=-10**5;\n",
-      "Af=-50.;\n",
-      "b=(A/Af-1.)/A;\n",
-      "print\"%s %.2f %s\"%('\\nfeedback transfer function=\\n',b,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "feedback transfer function=\n",
-        " 0.02 \n",
-        "\n",
-        "feedback transfer function=\n",
-        " -0.02 \n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg733"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.2\n",
-      "A=10**5;\n",
-      "Af=50.;\n",
-      "b=0.019999;\n",
-      "dA=10**4;\n",
-      "dAf=Af*dA/(A*(1.+b*A));\n",
-      "print\"%s %.2e %s\"%('\\ndAf ',dAf,'\\n')\n",
-      "##x=dAf/Af\n",
-      "x=dAf/Af;\n",
-      "x=x*100.;\n",
-      "print\"%s %.2e %s\"%('\\npercent change dAf/Af= ',x,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "dAf  2.50e-03 \n",
-        "\n",
-        "\n",
-        "percent change dAf/Af=  5.00e-03 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg735"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.3\n",
-      "Ao=10**4;\n",
-      "wh=2.*math.pi*100.;##rad/s\n",
-      "Af=50.;\n",
-      "##x=(1+bAo)\n",
-      "x=Ao/Af;\n",
-      "print\"%s %.2f %s\"%('\\n(1+bAo)=\\n',x,'')\n",
-      "wfh=wh*x;\n",
-      "print\"%s %.2f %s\"%('\\nclosed loop bandwidth=\\n',wfh,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "(1+bAo)=\n",
-        " 200.00 \n",
-        "\n",
-        "closed loop bandwidth=\n",
-        " 125663.71 \n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg742"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 12.5\n",
-      "Av=10**5;\n",
-      "Avf=50.;\n",
-      "Rf=10.;##Kohm\n",
-      "Ro=20000.;##Ohm\n",
-      "##x=(1+bvAv)\n",
-      "x=Av/Avf;\n",
-      "print\"%s %.2e %s\"%('\\n(1+bvAv)=\\n',x,'')\n",
-      "Rif=Rf*x;\n",
-      "Rif=Rif*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Rif,' MOhm\\n')\n",
-      "Rof=Ro/x;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Rof,' Ohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "(1+bvAv)=\n",
-        " 2.00e+03 \n",
-        "\n",
-        "input resistance=  20.00  MOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  10.00  Ohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg745"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.6\n",
-      "Af=10**5;\n",
-      "Aif=50.;\n",
-      "Rf=10000.;\n",
-      "Ro=20.;\n",
-      "##x=(1+biAi)\n",
-      "x=Af/Aif;\n",
-      "print\"%s %.2e %s\"%('\\n(1+biAi)=\\n',x,'')\n",
-      "Rif=Rf/x;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance =  ',Rif,'Ohm\\n')\n",
-      "Rof=Ro*x;\n",
-      "Rof=Rof*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Rof,' MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "(1+biAi)=\n",
-        " 2.00e+03 \n",
-        "\n",
-        "input resistance =   5.00 Ohm\n",
-        "\n",
-        "\n",
-        "output resistance=  40.00  MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg751"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.7\n",
-      "Ri=50.;\n",
-      "R1=10.;\n",
-      "R2=90.;\n",
-      "Av=10**4;\n",
-      "bv=1./(1.+R2/R1);\n",
-      "print\"%s %.2f %s\"%('\\nfeedback transfer function=\\n',bv,'')\n",
-      "Rif=Ri*(1.+bv*Av);\n",
-      "Rif=Rif*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Rif,' MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "feedback transfer function=\n",
-        " 0.10 \n",
-        "\n",
-        "input resistance=  50.05  MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg765"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 12.11\n",
-      "hFE=100.;##transistor parameter\n",
-      "Vbe=0.7;\n",
-      "Vcc=10.;\n",
-      "R1=55.;\n",
-      "R2=12.;\n",
-      "Re=1.;\n",
-      "Rc=4.;\n",
-      "Rl=4.;\n",
-      "Icq=0.983;\n",
-      "Vceq=5.08;\n",
-      "Vt=0.026;\n",
-      "r=hFE*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal parameter resistance= ',r,' KOhm\\n')\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "Agf=-gm*(Rc/(Rc+Rl))/(1.+Re*(gm+1./r));\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance transfer function= ',Agf,' mA/V\\n')\n",
-      "##as first approximation\n",
-      "Agf2=-1./Re;\n",
-      "print\"%s %.2f %s\"%('\\nAgf= ',Agf2,' mA/V\\n')\n",
-      "Avf=Agf*Rl;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain=\\n',Avf,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal parameter resistance=  2.64  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  37.81  mA/V\n",
-        "\n",
-        "\n",
-        "transconductance transfer function=  -0.48  mA/V\n",
-        "\n",
-        "\n",
-        "Agf=  -1.00  mA/V\n",
-        "\n",
-        "\n",
-        "voltage gain=\n",
-        " -1.93 \n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg777"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.15\n",
-      "##Determine the loop gain fig12.45(a)\n",
-      "hFE=100.;\n",
-      "Vbe=0.7;\n",
-      "Icq=0.492;\n",
-      "r=5.28;\n",
-      "gm=18.9;\n",
-      "Rs=10.;\n",
-      "R1=51.;\n",
-      "R2=5.5;\n",
-      "Re=0.500;\n",
-      "Rc=10.;\n",
-      "Rf=82.;\n",
-      "x=r*R2/(r+R2);\n",
-      "y=R1*x/(x+R1);\n",
-      "t=Rs*y/(y+Rs);\n",
-      "Req=t;\n",
-      "print\"%s %.2f %s\"%('\\nequivalent resistance ',t,' KOhm\\n')\n",
-      "T=gm*Rc*Req/(Rc+Rf+Req);\n",
-      "print\"%s %.2f %s\"%('\\nthe loop gain=\\n',T,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "equivalent resistance  2.04  KOhm\n",
-        "\n",
-        "\n",
-        "the loop gain=\n",
-        " 4.09 \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex19-pg791"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.19\n",
-      "##T=b*100/(sqrt(1+(f/10^5)^2) angle=-3tan^-1(f/10^5)\n",
-      "##stable at f180 at which phase becomes -180 degrees\n",
-      "##-3*atan(f180/10^5)=-180\n",
-      "f180=math.tan(60/57.3)*10**5;\n",
-      "print\"%s %.2f %s\"%('\\nfrequency at -180 degree= ',f180,'f Hz\\n')\n",
-      "b=0.2;\n",
-      "T=b*100./(math.sqrt(1.+(f180/10**5)**2))**3;\n",
-      "print\"%s %.2f %s\"%('\\nmagnitude of the loop gain=\\n',T,'')\n",
-      "b=0.02;\n",
-      "T=b*100./(math.sqrt(1.+(f180/10**5)**2))**3;\n",
-      "print\"%s %.2f %s\"%('\\nmagnitude of the loop gain=\\n',T,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "frequency at -180 degree=  173174.23 f Hz\n",
-        "\n",
-        "\n",
-        "magnitude of the loop gain=\n",
-        " 2.50 \n",
-        "\n",
-        "magnitude of the loop gain=\n",
-        " 0.25 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex22-pg798"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.22\n",
-      "Ao=10**6;\n",
-      "fPD=0.010;##KHz\n",
-      "b=0.01;\n",
-      "Af=Ao/(1.+b*Ao);\n",
-      "print\"%s %.2f %s\"%('\\nlow frequency closed loop gain=\\n',Af,'')\n",
-      "fc=fPD*(1.+b*Ao);\n",
-      "print\"%s %.2f %s\"%('\\nclosed loop 3dB frequency= ',fc,' KHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "low frequency closed loop gain=\n",
-        " 99.99 \n",
-        "\n",
-        "closed loop 3dB frequency=  100.01  KHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex23-pg799"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 12.23\n",
-      "A=10**3;\n",
-      "Cf=30.*10**-12;##feedback capacitor (F)\n",
-      "R2=5.*10**5;\n",
-      "Cm=Cf*(1.+A);\n",
-      "print\"%s %.2e %s\"%('\\nMiller capacitance= ',Cm,' F\\n')\n",
-      "fp=1/(2.*math.pi*R2*Cm);\n",
-      "print\"%s %.2f %s\"%('\\ndominant pole frequency = ',fp,'Hz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Miller capacitance=  3.00e-08  F\n",
-        "\n",
-        "\n",
-        "dominant pole frequency =  10.60 Hz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter13.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter13.ipynb
deleted file mode 100755
index 2505f949..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter13.ipynb
+++ /dev/null
@@ -1,804 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:d79e0ffa0dc246919c405ced6f920658f107cc2f3da7e821333d37e6758e0306"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter13-Operational Amplifier Circuits "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg824"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "\n",
-      "V1=15.;##positive supply voltage\n",
-      "V2=-15.;##negative supply voltage\n",
-      "Veb12=-0.6;\n",
-      "Vbe11=0.6;\n",
-      "Rs=40.;\n",
-      "Iref=(V1-V2-Veb12-Vbe11)/Rs;\n",
-      "print\"%s %.2f %s\"%('\\nreference current= ',Iref,' mA\\n')\n",
-      "Ic10=19.;\n",
-      "Ic1=Ic10/2.;\n",
-      "print\"%s %.2f %s\"%('\\nIc1=Ic2=Ic3=Ic4= ',Ic1,'microA\\n')\n",
-      "Ic1=Ic1*0.001;##mA\n",
-      "Vbe7=0.6;\n",
-      "Vbe6=0.6;\n",
-      "Ic6=Ic1;\n",
-      "R2=1.;\n",
-      "Vc6=Vbe7+Vbe6+Ic6*R2+V2;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at collector of Q6= ',Vc6,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "reference current=  0.75  mA\n",
-        "\n",
-        "\n",
-        "Ic1=Ic2=Ic3=Ic4=  9.50 microA\n",
-        "\n",
-        "\n",
-        "voltage at collector of Q6=  -13.79  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg827"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.2\n",
-      "Iref=0.72;\n",
-      "Ic17=0.75*Iref;\n",
-      "print\"%s %.2f %s\"%('\\ncollector currents in Q17= ',Ic17,' mA\\n')\n",
-      "b=200.;\n",
-      "Ib17=Ic17/b;\n",
-      "Ie17=Ic17;\n",
-      "R8=0.100;\n",
-      "Vbe17=0.6;\n",
-      "R9=50.;\n",
-      "Ic16=Ib17+(Ie17*R8+Vbe17)/R9;\n",
-      "Ic16=Ic16*1000.;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current in Q16= ',Ic16,' microA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector currents in Q17=  0.54  mA\n",
-        "\n",
-        "\n",
-        "collector current in Q16=  15.78  microA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg829"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.3\n",
-      "Is1=10**-14;##reverse saturation currents for Q18 Q19\n",
-      "Is2=3*10**-14;##reverse saturation currents for Q14 Q20\n",
-      "Iref=0.72;\n",
-      "Vt=0.026;\n",
-      "Ic13a=0.25*Iref;\n",
-      "print\"%s %.2f %s\"%('\\nIc13a= ',Ic13a,' mA\\n')\n",
-      "Vbe19=0.6;\n",
-      "R10=50.;\n",
-      "Ir1o=Vbe19/R10;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent in Ro= ',Ir1o,' mA\\n')\n",
-      "Ic19=Ic13a-Ir1o;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent in Q19 = ',Ic19,'mA\\n')\n",
-      "Ic19=Ic19*0.001;##A\n",
-      "Vbe19=Vt*math.log(Ic19/Is1);\n",
-      "print\"%s %.2f %s\"%('\\nB-E voltage of Q19= ',Vbe19,' V\\n')\n",
-      "b=200.;\n",
-      "Ic19=Ic19*10**6;##micro A\n",
-      "Iv19=Ic19*1000.;\n",
-      "Ib18=Ic19/b;\n",
-      "Ir1o=Ir1o*1000.;\n",
-      "print\"%s %.2f %s\"%('\\nbase current in Q18= ',Ib18,' microA\\n')\n",
-      "Ic18=Ir1o+Ib18;\n",
-      "print\"%s %.2f %s\"%('\\ncurrents in Q18= ',Ic18,' microA\\n')\n",
-      "Ic18=Ic18*10**-6;\n",
-      "Vbe18=Vt*math.log(Ic18/Is1);\n",
-      "print\"%s %.2f %s\"%('\\nB-E voltage of Q18= ',Vbe18,' V\\n')\n",
-      "Vbb=Vbe18+Vbe19;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage difference Vbb= ',Vbb,' V\\n')\n",
-      "Ic14=Is2*math.exp(Vbb/(2.*Vt));\n",
-      "Ic14=Ic14*10**6;##micro A\n",
-      "print\"%s %.2f %s\"%('\\nquiescent currents in Q14 and Q20  ',Ic14,'microA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Ic13a=  0.18  mA\n",
-        "\n",
-        "\n",
-        "current in Ro=  0.01  mA\n",
-        "\n",
-        "\n",
-        "current in Q19 =  0.17 mA\n",
-        "\n",
-        "\n",
-        "B-E voltage of Q19=  0.61  V\n",
-        "\n",
-        "\n",
-        "base current in Q18=  0.84  microA\n",
-        "\n",
-        "\n",
-        "currents in Q18=  12.84  microA\n",
-        "\n",
-        "\n",
-        "B-E voltage of Q18=  0.55  V\n",
-        "\n",
-        "\n",
-        "voltage difference Vbb=  1.16  V\n",
-        "\n",
-        "\n",
-        "quiescent currents in Q14 and Q20   139.33 microA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg832"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.4\n",
-      "b=200.;\n",
-      "Va=50.\n",
-      "Vt=0.026;\n",
-      "R2=1.;\n",
-      "Ic6=0.0095;\n",
-      "Ic4=Ic6;\n",
-      "Ic16=0.0158;\n",
-      "Ic17=0.54;\n",
-      "r17=b*Vt/Ic17;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to gain stage= ',r17,' KOhm\\n')\n",
-      "R9=50.;\n",
-      "R8=0.100;\n",
-      "x=r17+(1.+b)*R8;\n",
-      "Re=x*R9/(x+R9);\n",
-      "print\"%s %.2f %s\"%('\\nRe= ',Re,' KOhm\\n')\n",
-      "r16=b*Vt/Ic16;\n",
-      "print\"%s %.2f %s\"%('\\nr16= ',r16,' KOhm\\n')\n",
-      "Ri2=r16+(1.+b)*Re;\n",
-      "Ri2=Ri2*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nRi2= ',Ri2,' KOhm\\n')\n",
-      "r6=b*Vt/Ic6;\n",
-      "print\"%s %.2f %s\"%('\\nresistance of the active load= ',r6,' KOhm\\n')\n",
-      "gm=Ic6/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "ro6=Va/Ic6;\n",
-      "ro6=ro6*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nro6= ',ro6,' MOhm\\n')\n",
-      "R=ro6*(1.+gm*R2*r6/(R2+r6));\n",
-      "print\"%s %.2f %s\"%('\\neffective resistance of active load= ',R,' MOhm\\n')\n",
-      "ro4=Va/Ic4;\n",
-      "ro4=ro4*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\nResistance ro4= ',ro4,' KOhm\\n')\n",
-      "Icq=9.5;\n",
-      "x=Ri2*R/(R+Ri2);\n",
-      "y=ro4*x/(ro4+x);\n",
-      "Ad=-y*Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal differential voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input resistance to gain stage=  9.63  KOhm\n",
-        "\n",
-        "\n",
-        "Re=  18.64  KOhm\n",
-        "\n",
-        "\n",
-        "r16=  329.11  KOhm\n",
-        "\n",
-        "\n",
-        "Ri2=  4.08  KOhm\n",
-        "\n",
-        "\n",
-        "resistance of the active load=  547.37  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance =  0.37 mA/V\n",
-        "\n",
-        "\n",
-        "ro6=  5.26  MOhm\n",
-        "\n",
-        "\n",
-        "effective resistance of active load=  7.18  MOhm\n",
-        "\n",
-        "\n",
-        "Resistance ro4=  5.26  KOhm\n",
-        "\n",
-        "\n",
-        "small signal differential voltage gain=\n",
-        " -635.97 \n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg835"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.5\n",
-      "bp=50.;\n",
-      "bn=200.;\n",
-      "Va=50.;\n",
-      "R9=50.;\n",
-      "R8=0.100;\n",
-      "Rl=2.;\n",
-      "Vt=0.026;\n",
-      "Ri2=4070.;\n",
-      "Ic20=0.138;\n",
-      "r20=bp*Vt/Ic20;\n",
-      "print\"%s %.2f %s\"%('\\nr20= ',r20,' KOhm\\n')\n",
-      "R20=r20+(1.+bp)*Rl;\n",
-      "print\"%s %.2f %s\"%('\\nR20= ',R20,' KOhm\\n')\n",
-      "Ic13A=0.18;\n",
-      "R19=Va/Ic13A;\n",
-      "print\"%s %.2f %s\"%('\\nR19= ',R19,' KOhm\\n')\n",
-      "r22=bp*Vt/Ic13A;\n",
-      "print\"%s %.2f %s\"%('\\nr22= ',r22,' KOhm\\n')\n",
-      "Ri3=r22+(1.+bp)*R19*R20/(R19+R20);\n",
-      "Ri3=Ri3*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the output stage= ',Ri3,' MOhm\\n')\n",
-      "Ic13B=0.54;\n",
-      "R=Va/Ic13B;\n",
-      "print\"%s %.2f %s\"%('\\neffective resistance of the active load= ',R,' KOhm\\n')\n",
-      "Ic17=Ic13B;\n",
-      "R17=Va/Ic17;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance Ro17 = ',R17,'KOhm\\n')\n",
-      "Ri3=Ri3*1000.;##KOhm\n",
-      "r17=9.63;\n",
-      "x=R17*Ri3/(Ri3+R17);\n",
-      "y=x*R/(R+x);\n",
-      "A=-bn*R9*(1.+bn)*y/(Ri2*(R9+r17+(1.+bn)*R8));\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',A,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "r20=  9.42  KOhm\n",
-        "\n",
-        "\n",
-        "R20=  111.42  KOhm\n",
-        "\n",
-        "\n",
-        "R19=  277.78  KOhm\n",
-        "\n",
-        "\n",
-        "r22=  7.22  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance to the output stage=  4.06  MOhm\n",
-        "\n",
-        "\n",
-        "effective resistance of the active load=  92.59  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance Ro17 =  92.59 KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " -283.53 \n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg837"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.6\n",
-      "Ic20=2.;\n",
-      "bn=200.;\n",
-      "bp=50.;\n",
-      "Va=50.;\n",
-      "r17=9.63;\n",
-      "r22=7.22;\n",
-      "R20=0.260;\n",
-      "gm17=20.8;\n",
-      "ro17=92.6;\n",
-      "Ro13B=92.6;\n",
-      "R8=0.100;\n",
-      "Rc17=ro17*(1.+gm17*R8*r17/(R8+r17));\n",
-      "print\"%s %.2f %s\"%('\\nRc17= ',Rc17,' KOhm\\n')\n",
-      "Rc22=(r22+Rc17*Ro13B/(Rc17+Ro13B))/(1.+bp);\n",
-      "print\"%s %.2f %s\"%('\\nRc22= ',Rc22,' KOhm\\n')\n",
-      "Ic13A=0.18;\n",
-      "Rc19=Va/Ic13A;\n",
-      "print\"%s %.2f %s\"%('\\nRc19= ',Rc19,' KOhm\\n')\n",
-      "Rc20=(R20+Rc22*Rc19/(Rc22+Rc19))/(1.+bp);\n",
-      "print\"%s %.2f %s\"%('\\nRc20= ',Rc20,' KOhm\\n')\n",
-      "Rc20=Rc20*1000.;##Ohm\n",
-      "R3=22.;\n",
-      "Ro=R3+Rc20;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' Ohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Rc17=  283.23  KOhm\n",
-        "\n",
-        "\n",
-        "Rc22=  1.51  KOhm\n",
-        "\n",
-        "\n",
-        "Rc19=  277.78  KOhm\n",
-        "\n",
-        "\n",
-        "Rc20=  0.03  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  56.54  Ohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg838"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.7\n",
-      "Av2=285.;\n",
-      "C1=30.;\n",
-      "Ci=C1*(1.+Av2);\n",
-      "print\"%s %.2f %s\"%('\\ninput capacitance= ',Ci,' pF\\n')\n",
-      "Ri2=4.07;\n",
-      "Ract=7.18;\n",
-      "ro4=5.26;\n",
-      "Ro1=Ract*ro4/(Ract+ro4);\n",
-      "print\"%s %.2f %s\"%('\\ngate stage input resistance= ',Ro1,' MOhm \\n')\n",
-      "Req=Ro1*Ri2/(Ri2+Ro1);\n",
-      "print\"%s %.2f %s\"%('\\nequivalent resistance= ',Req,' MOhm\\n')\n",
-      "Req=Req*10**6;##Ohm\n",
-      "Ci=Ci*10**-12;##F\n",
-      "fPD=1/(2.*math.pi*Req*Ci);\n",
-      "print\"%s %.2f %s\"%('\\ndominant pole frequency = ',fPD,' Hz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input capacitance=  8580.00  pF\n",
-        "\n",
-        "\n",
-        "gate stage input resistance=  3.04  MOhm \n",
-        "\n",
-        "\n",
-        "equivalent resistance=  1.74  MOhm\n",
-        "\n",
-        "\n",
-        "dominant pole frequency =  10.67  Hz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg842"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 13.9\n",
-      "##lambda=y\n",
-      "y=0.02;\n",
-      "##W/L=x and u*Cox/2=t\n",
-      "x=12.5;\n",
-      "t=10.;\n",
-      "Kp1=x*t;\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameters of M1 and M2= ',Kp1,' microA/V^2\\n')\n",
-      "Kp1=Kp1*0.001;##mA/V^2\n",
-      "Id=0.0199;\n",
-      "ro2=1./(y*Id);\n",
-      "ro2=ro2*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= MOhm\\n',ro2,'')\n",
-      "Iq=0.0397;\n",
-      "ro2=ro2*1000.;##Kohm\n",
-      "ro4=ro2;\n",
-      "Ad=math.sqrt(2.*Kp1*Iq)*ro2*ro4/(ro2+ro4);\n",
-      "print\"%s %.2f %s\"%('\\nthe gain of input stage= \\n',Ad,'')\n",
-      "Kn7=0.250;\n",
-      "Id7=Iq;\n",
-      "gm7=2.*math.sqrt(Kn7*Id7)\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance of M7= ',gm7,' mA/V\\n')\n",
-      "ro7=1./(y*Id7);\n",
-      "ro7=ro7*0.001;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of M7 and M8 = ',ro7,'MOhm\\n')\n",
-      "ro7=ro7*1000.;##Kohm\n",
-      "ro8=ro7;\n",
-      "Av2=gm7*ro7*ro8/(ro7+ro8);\n",
-      "print\"%s %.2f %s\"%('\\ngain of the second stage=\\n',Av2,'')\n",
-      "Av=Ad*Av2;\n",
-      "print\"%s %.2f %s\"%('\\noverall voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "conduction parameters of M1 and M2=  125.00  microA/V^2\n",
-        "\n",
-        "\n",
-        "output resistance= MOhm\n",
-        " 2.51 \n",
-        "\n",
-        "the gain of input stage= \n",
-        " 125.16 \n",
-        "\n",
-        "transconductance of M7=  0.20  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance of M7 and M8 =  1.26 MOhm\n",
-        "\n",
-        "\n",
-        "gain of the second stage=\n",
-        " 125.47 \n",
-        "\n",
-        "overall voltage gain=\n",
-        " 15703.52 \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg845"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.10\n",
-      "Iref=100;\n",
-      "Kn=80;\n",
-      "Kp=40;\n",
-      "##W/L=x\n",
-      "x=25;\n",
-      "##lambda=y\n",
-      "y=0.02;\n",
-      "Id=Iref/2.;\n",
-      "gm1=2.*math.sqrt(Kp*x*Id/2.);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance gm1=gm8= ',gm1,' microA/V\\n')\n",
-      "gm6=2.*math.sqrt(Kn*x*Id/2.);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm6,' microA/V\\n')\n",
-      "ro1=1./(y*Id);\n",
-      "ro8=ro1;\n",
-      "ro6=ro1;\n",
-      "ro10=ro1;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance ro1=ro8=ro6=ro10= ',ro1,' MOhm\\n')\n",
-      "Id4=Iref;\n",
-      "ro4=1./(y*Id4);\n",
-      "print\"%s %.2f %s\"%('\\nro4= ',ro4,' MOhm\\n')\n",
-      "Ro8=gm1*ro8*ro10;\n",
-      "print\"%s %.2f %s\"%('\\ncomposite output resistances = ',Ro8,'MOhm\\n')\n",
-      "Ro6=gm6*ro6*ro4*ro1/(ro4+ro1);\n",
-      "print\"%s %.2f %s\"%('\\ncomposite output resistances= ',Ro6,' MOhm\\n')\n",
-      "Ad=gm1*Ro6*Ro8/(Ro6+Ro8);\n",
-      "print\"%s %.2f %s\"%('\\ndifferential voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance gm1=gm8=  316.23  microA/V\n",
-        "\n",
-        "\n",
-        "transconductance=  447.21  microA/V\n",
-        "\n",
-        "\n",
-        "output resistance ro1=ro8=ro6=ro10=  1.00  MOhm\n",
-        "\n",
-        "\n",
-        "ro4=  0.50  MOhm\n",
-        "\n",
-        "\n",
-        "composite output resistances =  316.23 MOhm\n",
-        "\n",
-        "\n",
-        "composite output resistances=  149.07  MOhm\n",
-        "\n",
-        "\n",
-        "differential voltage gain=\n",
-        " 32037.72 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg854"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.12\n",
-      "Kp=0.6;\n",
-      "bn=200.;\n",
-      "Va=50.;\n",
-      "Vt=0.026;\n",
-      "Ic13=0.20;\n",
-      "Ri2=bn*Vt/Ic13;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the gain stage= ',Ri2,' KOhm\\n')\n",
-      "Iq5=Ic13;\n",
-      "Ad=math.sqrt(2.*Kp*Iq5)*Ri2;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input resistance to the gain stage=  26.00  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " 12.74 \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg855"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.13\n",
-      "Va=150.;\n",
-      "Vt=0.026;\n",
-      "Ic13=0.2;\n",
-      "gm13=Ic13/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm13,' mA/V\\n')\n",
-      "ro13=Va/Ic13;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro13,' KOhm\\n')\n",
-      "Av2=gm13*ro13;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain= \\n',Av2,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  7.69  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  750.00  KOhm\n",
-        "\n",
-        "\n",
-        "voltage gain= \n",
-        " 5769.23 \n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg856"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.14\n",
-      "Av2=5768.;\n",
-      "C1=12.;\n",
-      "Ci=C1*(1.+Av2);\n",
-      "print\"%s %.2f %s\"%('\\neffective input capacitance= ',Ci,' pF\\n')\n",
-      "Ri2=26000.;##gain stage input resistance (Ohm)\n",
-      "Ci=Ci*10**-12;##F\n",
-      "fPD=1/(2.*math.pi*Ri2*Ci);\n",
-      "print\"%s %.2f %s\"%('\\ndominant pole frequency= ',fPD,' Hz\\n')\n",
-      "Av=73254.;\n",
-      "fT=fPD*Av;\n",
-      "fT=fT*10**-6;##MHz\n",
-      "print\"%s %.2f %s\"%('\\nunity gain bandwidth= ',fT,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "effective input capacitance=  69228.00  pF\n",
-        "\n",
-        "\n",
-        "dominant pole frequency=  88.42  Hz\n",
-        "\n",
-        "\n",
-        "unity gain bandwidth=  6.48  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter13_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter13_1.ipynb
deleted file mode 100755
index 2505f949..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter13_1.ipynb
+++ /dev/null
@@ -1,804 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:d79e0ffa0dc246919c405ced6f920658f107cc2f3da7e821333d37e6758e0306"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter13-Operational Amplifier Circuits "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg824"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "\n",
-      "V1=15.;##positive supply voltage\n",
-      "V2=-15.;##negative supply voltage\n",
-      "Veb12=-0.6;\n",
-      "Vbe11=0.6;\n",
-      "Rs=40.;\n",
-      "Iref=(V1-V2-Veb12-Vbe11)/Rs;\n",
-      "print\"%s %.2f %s\"%('\\nreference current= ',Iref,' mA\\n')\n",
-      "Ic10=19.;\n",
-      "Ic1=Ic10/2.;\n",
-      "print\"%s %.2f %s\"%('\\nIc1=Ic2=Ic3=Ic4= ',Ic1,'microA\\n')\n",
-      "Ic1=Ic1*0.001;##mA\n",
-      "Vbe7=0.6;\n",
-      "Vbe6=0.6;\n",
-      "Ic6=Ic1;\n",
-      "R2=1.;\n",
-      "Vc6=Vbe7+Vbe6+Ic6*R2+V2;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at collector of Q6= ',Vc6,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "reference current=  0.75  mA\n",
-        "\n",
-        "\n",
-        "Ic1=Ic2=Ic3=Ic4=  9.50 microA\n",
-        "\n",
-        "\n",
-        "voltage at collector of Q6=  -13.79  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg827"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.2\n",
-      "Iref=0.72;\n",
-      "Ic17=0.75*Iref;\n",
-      "print\"%s %.2f %s\"%('\\ncollector currents in Q17= ',Ic17,' mA\\n')\n",
-      "b=200.;\n",
-      "Ib17=Ic17/b;\n",
-      "Ie17=Ic17;\n",
-      "R8=0.100;\n",
-      "Vbe17=0.6;\n",
-      "R9=50.;\n",
-      "Ic16=Ib17+(Ie17*R8+Vbe17)/R9;\n",
-      "Ic16=Ic16*1000.;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current in Q16= ',Ic16,' microA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector currents in Q17=  0.54  mA\n",
-        "\n",
-        "\n",
-        "collector current in Q16=  15.78  microA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg829"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.3\n",
-      "Is1=10**-14;##reverse saturation currents for Q18 Q19\n",
-      "Is2=3*10**-14;##reverse saturation currents for Q14 Q20\n",
-      "Iref=0.72;\n",
-      "Vt=0.026;\n",
-      "Ic13a=0.25*Iref;\n",
-      "print\"%s %.2f %s\"%('\\nIc13a= ',Ic13a,' mA\\n')\n",
-      "Vbe19=0.6;\n",
-      "R10=50.;\n",
-      "Ir1o=Vbe19/R10;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent in Ro= ',Ir1o,' mA\\n')\n",
-      "Ic19=Ic13a-Ir1o;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent in Q19 = ',Ic19,'mA\\n')\n",
-      "Ic19=Ic19*0.001;##A\n",
-      "Vbe19=Vt*math.log(Ic19/Is1);\n",
-      "print\"%s %.2f %s\"%('\\nB-E voltage of Q19= ',Vbe19,' V\\n')\n",
-      "b=200.;\n",
-      "Ic19=Ic19*10**6;##micro A\n",
-      "Iv19=Ic19*1000.;\n",
-      "Ib18=Ic19/b;\n",
-      "Ir1o=Ir1o*1000.;\n",
-      "print\"%s %.2f %s\"%('\\nbase current in Q18= ',Ib18,' microA\\n')\n",
-      "Ic18=Ir1o+Ib18;\n",
-      "print\"%s %.2f %s\"%('\\ncurrents in Q18= ',Ic18,' microA\\n')\n",
-      "Ic18=Ic18*10**-6;\n",
-      "Vbe18=Vt*math.log(Ic18/Is1);\n",
-      "print\"%s %.2f %s\"%('\\nB-E voltage of Q18= ',Vbe18,' V\\n')\n",
-      "Vbb=Vbe18+Vbe19;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage difference Vbb= ',Vbb,' V\\n')\n",
-      "Ic14=Is2*math.exp(Vbb/(2.*Vt));\n",
-      "Ic14=Ic14*10**6;##micro A\n",
-      "print\"%s %.2f %s\"%('\\nquiescent currents in Q14 and Q20  ',Ic14,'microA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Ic13a=  0.18  mA\n",
-        "\n",
-        "\n",
-        "current in Ro=  0.01  mA\n",
-        "\n",
-        "\n",
-        "current in Q19 =  0.17 mA\n",
-        "\n",
-        "\n",
-        "B-E voltage of Q19=  0.61  V\n",
-        "\n",
-        "\n",
-        "base current in Q18=  0.84  microA\n",
-        "\n",
-        "\n",
-        "currents in Q18=  12.84  microA\n",
-        "\n",
-        "\n",
-        "B-E voltage of Q18=  0.55  V\n",
-        "\n",
-        "\n",
-        "voltage difference Vbb=  1.16  V\n",
-        "\n",
-        "\n",
-        "quiescent currents in Q14 and Q20   139.33 microA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg832"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.4\n",
-      "b=200.;\n",
-      "Va=50.\n",
-      "Vt=0.026;\n",
-      "R2=1.;\n",
-      "Ic6=0.0095;\n",
-      "Ic4=Ic6;\n",
-      "Ic16=0.0158;\n",
-      "Ic17=0.54;\n",
-      "r17=b*Vt/Ic17;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to gain stage= ',r17,' KOhm\\n')\n",
-      "R9=50.;\n",
-      "R8=0.100;\n",
-      "x=r17+(1.+b)*R8;\n",
-      "Re=x*R9/(x+R9);\n",
-      "print\"%s %.2f %s\"%('\\nRe= ',Re,' KOhm\\n')\n",
-      "r16=b*Vt/Ic16;\n",
-      "print\"%s %.2f %s\"%('\\nr16= ',r16,' KOhm\\n')\n",
-      "Ri2=r16+(1.+b)*Re;\n",
-      "Ri2=Ri2*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nRi2= ',Ri2,' KOhm\\n')\n",
-      "r6=b*Vt/Ic6;\n",
-      "print\"%s %.2f %s\"%('\\nresistance of the active load= ',r6,' KOhm\\n')\n",
-      "gm=Ic6/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "ro6=Va/Ic6;\n",
-      "ro6=ro6*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nro6= ',ro6,' MOhm\\n')\n",
-      "R=ro6*(1.+gm*R2*r6/(R2+r6));\n",
-      "print\"%s %.2f %s\"%('\\neffective resistance of active load= ',R,' MOhm\\n')\n",
-      "ro4=Va/Ic4;\n",
-      "ro4=ro4*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\nResistance ro4= ',ro4,' KOhm\\n')\n",
-      "Icq=9.5;\n",
-      "x=Ri2*R/(R+Ri2);\n",
-      "y=ro4*x/(ro4+x);\n",
-      "Ad=-y*Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal differential voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input resistance to gain stage=  9.63  KOhm\n",
-        "\n",
-        "\n",
-        "Re=  18.64  KOhm\n",
-        "\n",
-        "\n",
-        "r16=  329.11  KOhm\n",
-        "\n",
-        "\n",
-        "Ri2=  4.08  KOhm\n",
-        "\n",
-        "\n",
-        "resistance of the active load=  547.37  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance =  0.37 mA/V\n",
-        "\n",
-        "\n",
-        "ro6=  5.26  MOhm\n",
-        "\n",
-        "\n",
-        "effective resistance of active load=  7.18  MOhm\n",
-        "\n",
-        "\n",
-        "Resistance ro4=  5.26  KOhm\n",
-        "\n",
-        "\n",
-        "small signal differential voltage gain=\n",
-        " -635.97 \n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg835"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.5\n",
-      "bp=50.;\n",
-      "bn=200.;\n",
-      "Va=50.;\n",
-      "R9=50.;\n",
-      "R8=0.100;\n",
-      "Rl=2.;\n",
-      "Vt=0.026;\n",
-      "Ri2=4070.;\n",
-      "Ic20=0.138;\n",
-      "r20=bp*Vt/Ic20;\n",
-      "print\"%s %.2f %s\"%('\\nr20= ',r20,' KOhm\\n')\n",
-      "R20=r20+(1.+bp)*Rl;\n",
-      "print\"%s %.2f %s\"%('\\nR20= ',R20,' KOhm\\n')\n",
-      "Ic13A=0.18;\n",
-      "R19=Va/Ic13A;\n",
-      "print\"%s %.2f %s\"%('\\nR19= ',R19,' KOhm\\n')\n",
-      "r22=bp*Vt/Ic13A;\n",
-      "print\"%s %.2f %s\"%('\\nr22= ',r22,' KOhm\\n')\n",
-      "Ri3=r22+(1.+bp)*R19*R20/(R19+R20);\n",
-      "Ri3=Ri3*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the output stage= ',Ri3,' MOhm\\n')\n",
-      "Ic13B=0.54;\n",
-      "R=Va/Ic13B;\n",
-      "print\"%s %.2f %s\"%('\\neffective resistance of the active load= ',R,' KOhm\\n')\n",
-      "Ic17=Ic13B;\n",
-      "R17=Va/Ic17;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance Ro17 = ',R17,'KOhm\\n')\n",
-      "Ri3=Ri3*1000.;##KOhm\n",
-      "r17=9.63;\n",
-      "x=R17*Ri3/(Ri3+R17);\n",
-      "y=x*R/(R+x);\n",
-      "A=-bn*R9*(1.+bn)*y/(Ri2*(R9+r17+(1.+bn)*R8));\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',A,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "r20=  9.42  KOhm\n",
-        "\n",
-        "\n",
-        "R20=  111.42  KOhm\n",
-        "\n",
-        "\n",
-        "R19=  277.78  KOhm\n",
-        "\n",
-        "\n",
-        "r22=  7.22  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance to the output stage=  4.06  MOhm\n",
-        "\n",
-        "\n",
-        "effective resistance of the active load=  92.59  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance Ro17 =  92.59 KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " -283.53 \n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg837"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.6\n",
-      "Ic20=2.;\n",
-      "bn=200.;\n",
-      "bp=50.;\n",
-      "Va=50.;\n",
-      "r17=9.63;\n",
-      "r22=7.22;\n",
-      "R20=0.260;\n",
-      "gm17=20.8;\n",
-      "ro17=92.6;\n",
-      "Ro13B=92.6;\n",
-      "R8=0.100;\n",
-      "Rc17=ro17*(1.+gm17*R8*r17/(R8+r17));\n",
-      "print\"%s %.2f %s\"%('\\nRc17= ',Rc17,' KOhm\\n')\n",
-      "Rc22=(r22+Rc17*Ro13B/(Rc17+Ro13B))/(1.+bp);\n",
-      "print\"%s %.2f %s\"%('\\nRc22= ',Rc22,' KOhm\\n')\n",
-      "Ic13A=0.18;\n",
-      "Rc19=Va/Ic13A;\n",
-      "print\"%s %.2f %s\"%('\\nRc19= ',Rc19,' KOhm\\n')\n",
-      "Rc20=(R20+Rc22*Rc19/(Rc22+Rc19))/(1.+bp);\n",
-      "print\"%s %.2f %s\"%('\\nRc20= ',Rc20,' KOhm\\n')\n",
-      "Rc20=Rc20*1000.;##Ohm\n",
-      "R3=22.;\n",
-      "Ro=R3+Rc20;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' Ohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Rc17=  283.23  KOhm\n",
-        "\n",
-        "\n",
-        "Rc22=  1.51  KOhm\n",
-        "\n",
-        "\n",
-        "Rc19=  277.78  KOhm\n",
-        "\n",
-        "\n",
-        "Rc20=  0.03  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  56.54  Ohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg838"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.7\n",
-      "Av2=285.;\n",
-      "C1=30.;\n",
-      "Ci=C1*(1.+Av2);\n",
-      "print\"%s %.2f %s\"%('\\ninput capacitance= ',Ci,' pF\\n')\n",
-      "Ri2=4.07;\n",
-      "Ract=7.18;\n",
-      "ro4=5.26;\n",
-      "Ro1=Ract*ro4/(Ract+ro4);\n",
-      "print\"%s %.2f %s\"%('\\ngate stage input resistance= ',Ro1,' MOhm \\n')\n",
-      "Req=Ro1*Ri2/(Ri2+Ro1);\n",
-      "print\"%s %.2f %s\"%('\\nequivalent resistance= ',Req,' MOhm\\n')\n",
-      "Req=Req*10**6;##Ohm\n",
-      "Ci=Ci*10**-12;##F\n",
-      "fPD=1/(2.*math.pi*Req*Ci);\n",
-      "print\"%s %.2f %s\"%('\\ndominant pole frequency = ',fPD,' Hz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input capacitance=  8580.00  pF\n",
-        "\n",
-        "\n",
-        "gate stage input resistance=  3.04  MOhm \n",
-        "\n",
-        "\n",
-        "equivalent resistance=  1.74  MOhm\n",
-        "\n",
-        "\n",
-        "dominant pole frequency =  10.67  Hz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg842"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 13.9\n",
-      "##lambda=y\n",
-      "y=0.02;\n",
-      "##W/L=x and u*Cox/2=t\n",
-      "x=12.5;\n",
-      "t=10.;\n",
-      "Kp1=x*t;\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameters of M1 and M2= ',Kp1,' microA/V^2\\n')\n",
-      "Kp1=Kp1*0.001;##mA/V^2\n",
-      "Id=0.0199;\n",
-      "ro2=1./(y*Id);\n",
-      "ro2=ro2*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= MOhm\\n',ro2,'')\n",
-      "Iq=0.0397;\n",
-      "ro2=ro2*1000.;##Kohm\n",
-      "ro4=ro2;\n",
-      "Ad=math.sqrt(2.*Kp1*Iq)*ro2*ro4/(ro2+ro4);\n",
-      "print\"%s %.2f %s\"%('\\nthe gain of input stage= \\n',Ad,'')\n",
-      "Kn7=0.250;\n",
-      "Id7=Iq;\n",
-      "gm7=2.*math.sqrt(Kn7*Id7)\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance of M7= ',gm7,' mA/V\\n')\n",
-      "ro7=1./(y*Id7);\n",
-      "ro7=ro7*0.001;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of M7 and M8 = ',ro7,'MOhm\\n')\n",
-      "ro7=ro7*1000.;##Kohm\n",
-      "ro8=ro7;\n",
-      "Av2=gm7*ro7*ro8/(ro7+ro8);\n",
-      "print\"%s %.2f %s\"%('\\ngain of the second stage=\\n',Av2,'')\n",
-      "Av=Ad*Av2;\n",
-      "print\"%s %.2f %s\"%('\\noverall voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "conduction parameters of M1 and M2=  125.00  microA/V^2\n",
-        "\n",
-        "\n",
-        "output resistance= MOhm\n",
-        " 2.51 \n",
-        "\n",
-        "the gain of input stage= \n",
-        " 125.16 \n",
-        "\n",
-        "transconductance of M7=  0.20  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance of M7 and M8 =  1.26 MOhm\n",
-        "\n",
-        "\n",
-        "gain of the second stage=\n",
-        " 125.47 \n",
-        "\n",
-        "overall voltage gain=\n",
-        " 15703.52 \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg845"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.10\n",
-      "Iref=100;\n",
-      "Kn=80;\n",
-      "Kp=40;\n",
-      "##W/L=x\n",
-      "x=25;\n",
-      "##lambda=y\n",
-      "y=0.02;\n",
-      "Id=Iref/2.;\n",
-      "gm1=2.*math.sqrt(Kp*x*Id/2.);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance gm1=gm8= ',gm1,' microA/V\\n')\n",
-      "gm6=2.*math.sqrt(Kn*x*Id/2.);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm6,' microA/V\\n')\n",
-      "ro1=1./(y*Id);\n",
-      "ro8=ro1;\n",
-      "ro6=ro1;\n",
-      "ro10=ro1;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance ro1=ro8=ro6=ro10= ',ro1,' MOhm\\n')\n",
-      "Id4=Iref;\n",
-      "ro4=1./(y*Id4);\n",
-      "print\"%s %.2f %s\"%('\\nro4= ',ro4,' MOhm\\n')\n",
-      "Ro8=gm1*ro8*ro10;\n",
-      "print\"%s %.2f %s\"%('\\ncomposite output resistances = ',Ro8,'MOhm\\n')\n",
-      "Ro6=gm6*ro6*ro4*ro1/(ro4+ro1);\n",
-      "print\"%s %.2f %s\"%('\\ncomposite output resistances= ',Ro6,' MOhm\\n')\n",
-      "Ad=gm1*Ro6*Ro8/(Ro6+Ro8);\n",
-      "print\"%s %.2f %s\"%('\\ndifferential voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance gm1=gm8=  316.23  microA/V\n",
-        "\n",
-        "\n",
-        "transconductance=  447.21  microA/V\n",
-        "\n",
-        "\n",
-        "output resistance ro1=ro8=ro6=ro10=  1.00  MOhm\n",
-        "\n",
-        "\n",
-        "ro4=  0.50  MOhm\n",
-        "\n",
-        "\n",
-        "composite output resistances =  316.23 MOhm\n",
-        "\n",
-        "\n",
-        "composite output resistances=  149.07  MOhm\n",
-        "\n",
-        "\n",
-        "differential voltage gain=\n",
-        " 32037.72 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg854"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.12\n",
-      "Kp=0.6;\n",
-      "bn=200.;\n",
-      "Va=50.;\n",
-      "Vt=0.026;\n",
-      "Ic13=0.20;\n",
-      "Ri2=bn*Vt/Ic13;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the gain stage= ',Ri2,' KOhm\\n')\n",
-      "Iq5=Ic13;\n",
-      "Ad=math.sqrt(2.*Kp*Iq5)*Ri2;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input resistance to the gain stage=  26.00  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " 12.74 \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg855"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.13\n",
-      "Va=150.;\n",
-      "Vt=0.026;\n",
-      "Ic13=0.2;\n",
-      "gm13=Ic13/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm13,' mA/V\\n')\n",
-      "ro13=Va/Ic13;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro13,' KOhm\\n')\n",
-      "Av2=gm13*ro13;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain= \\n',Av2,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  7.69  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  750.00  KOhm\n",
-        "\n",
-        "\n",
-        "voltage gain= \n",
-        " 5769.23 \n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg856"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.14\n",
-      "Av2=5768.;\n",
-      "C1=12.;\n",
-      "Ci=C1*(1.+Av2);\n",
-      "print\"%s %.2f %s\"%('\\neffective input capacitance= ',Ci,' pF\\n')\n",
-      "Ri2=26000.;##gain stage input resistance (Ohm)\n",
-      "Ci=Ci*10**-12;##F\n",
-      "fPD=1/(2.*math.pi*Ri2*Ci);\n",
-      "print\"%s %.2f %s\"%('\\ndominant pole frequency= ',fPD,' Hz\\n')\n",
-      "Av=73254.;\n",
-      "fT=fPD*Av;\n",
-      "fT=fT*10**-6;##MHz\n",
-      "print\"%s %.2f %s\"%('\\nunity gain bandwidth= ',fT,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "effective input capacitance=  69228.00  pF\n",
-        "\n",
-        "\n",
-        "dominant pole frequency=  88.42  Hz\n",
-        "\n",
-        "\n",
-        "unity gain bandwidth=  6.48  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter13_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter13_1_1.ipynb
deleted file mode 100755
index 192e847c..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter13_1_1.ipynb
+++ /dev/null
@@ -1,804 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:2a940490296bbeac10456bf5a339ec669001e8073eddecdfff753904e075bb2b"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter13-Operational Amplifier Circuits "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg824"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "\n",
-      "V1=15.;##positive supply voltage\n",
-      "V2=-15.;##negative supply voltage\n",
-      "Veb12=-0.6;\n",
-      "Vbe11=0.6;\n",
-      "Rs=40.;\n",
-      "Iref=(V1-V2-Veb12-Vbe11)/Rs;\n",
-      "print\"%s %.2f %s\"%('\\nreference current= ',Iref,' mA\\n')\n",
-      "Ic10=19.;\n",
-      "Ic1=Ic10/2.;\n",
-      "print\"%s %.2f %s\"%('\\nIc1=Ic2=Ic3=Ic4= ',Ic1,'microA\\n')\n",
-      "Ic1=Ic1*0.001;##mA\n",
-      "Vbe7=0.6;\n",
-      "Vbe6=0.6;\n",
-      "Ic6=Ic1;\n",
-      "R2=1.;\n",
-      "Vc6=Vbe7+Vbe6+Ic6*R2+V2;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at collector of Q6= ',Vc6,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "reference current=  0.75  mA\n",
-        "\n",
-        "\n",
-        "Ic1=Ic2=Ic3=Ic4=  9.50 microA\n",
-        "\n",
-        "\n",
-        "voltage at collector of Q6=  -13.79  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg827"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.2\n",
-      "Iref=0.72;\n",
-      "Ic17=0.75*Iref;\n",
-      "print\"%s %.2f %s\"%('\\ncollector currents in Q17= ',Ic17,' mA\\n')\n",
-      "b=200.;\n",
-      "Ib17=Ic17/b;\n",
-      "Ie17=Ic17;\n",
-      "R8=0.100;\n",
-      "Vbe17=0.6;\n",
-      "R9=50.;\n",
-      "Ic16=Ib17+(Ie17*R8+Vbe17)/R9;\n",
-      "Ic16=Ic16*1000.;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current in Q16= ',Ic16,' microA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector currents in Q17=  0.54  mA\n",
-        "\n",
-        "\n",
-        "collector current in Q16=  15.78  microA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg829"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.3\n",
-      "Is1=10**-14;##reverse saturation currents for Q18 Q19\n",
-      "Is2=3*10**-14;##reverse saturation currents for Q14 Q20\n",
-      "Iref=0.72;\n",
-      "Vt=0.026;\n",
-      "Ic13a=0.25*Iref;\n",
-      "print\"%s %.2f %s\"%('\\nIc13a= ',Ic13a,' mA\\n')\n",
-      "Vbe19=0.6;\n",
-      "R10=50.;\n",
-      "Ir1o=Vbe19/R10;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent in Ro= ',Ir1o,' mA\\n')\n",
-      "Ic19=Ic13a-Ir1o;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent in Q19 = ',Ic19,'mA\\n')\n",
-      "Ic19=Ic19*0.001;##A\n",
-      "Vbe19=Vt*math.log(Ic19/Is1);\n",
-      "print\"%s %.2f %s\"%('\\nB-E voltage of Q19= ',Vbe19,' V\\n')\n",
-      "b=200.;\n",
-      "Ic19=Ic19*10**6;##micro A\n",
-      "Iv19=Ic19*1000.;\n",
-      "Ib18=Ic19/b;\n",
-      "Ir1o=Ir1o*1000.;\n",
-      "print\"%s %.2f %s\"%('\\nbase current in Q18= ',Ib18,' microA\\n')\n",
-      "Ic18=Ir1o+Ib18;\n",
-      "print\"%s %.2f %s\"%('\\ncurrents in Q18= ',Ic18,' microA\\n')\n",
-      "Ic18=Ic18*10**-6;\n",
-      "Vbe18=Vt*math.log(Ic18/Is1);\n",
-      "print\"%s %.2f %s\"%('\\nB-E voltage of Q18= ',Vbe18,' V\\n')\n",
-      "Vbb=Vbe18+Vbe19;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage difference Vbb= ',Vbb,' V\\n')\n",
-      "Ic14=Is2*math.exp(Vbb/(2.*Vt));\n",
-      "Ic14=Ic14*10**6;##micro A\n",
-      "print\"%s %.2f %s\"%('\\nquiescent currents in Q14 and Q20  ',Ic14,'microA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Ic13a=  0.18  mA\n",
-        "\n",
-        "\n",
-        "current in Ro=  0.01  mA\n",
-        "\n",
-        "\n",
-        "current in Q19 =  0.17 mA\n",
-        "\n",
-        "\n",
-        "B-E voltage of Q19=  0.61  V\n",
-        "\n",
-        "\n",
-        "base current in Q18=  0.84  microA\n",
-        "\n",
-        "\n",
-        "currents in Q18=  12.84  microA\n",
-        "\n",
-        "\n",
-        "B-E voltage of Q18=  0.55  V\n",
-        "\n",
-        "\n",
-        "voltage difference Vbb=  1.16  V\n",
-        "\n",
-        "\n",
-        "quiescent currents in Q14 and Q20   139.33 microA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg832"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.4\n",
-      "b=200.;\n",
-      "Va=50.\n",
-      "Vt=0.026;\n",
-      "R2=1.;\n",
-      "Ic6=0.0095;\n",
-      "Ic4=Ic6;\n",
-      "Ic16=0.0158;\n",
-      "Ic17=0.54;\n",
-      "r17=b*Vt/Ic17;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to gain stage= ',r17,' KOhm\\n')\n",
-      "R9=50.;\n",
-      "R8=0.100;\n",
-      "x=r17+(1.+b)*R8;\n",
-      "Re=x*R9/(x+R9);\n",
-      "print\"%s %.2f %s\"%('\\nRe= ',Re,' KOhm\\n')\n",
-      "r16=b*Vt/Ic16;\n",
-      "print\"%s %.2f %s\"%('\\nr16= ',r16,' KOhm\\n')\n",
-      "Ri2=r16+(1.+b)*Re;\n",
-      "Ri2=Ri2*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nRi2= ',Ri2,' KOhm\\n')\n",
-      "r6=b*Vt/Ic6;\n",
-      "print\"%s %.2f %s\"%('\\nresistance of the active load= ',r6,' KOhm\\n')\n",
-      "gm=Ic6/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "ro6=Va/Ic6;\n",
-      "ro6=ro6*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\nro6= ',ro6,' MOhm\\n')\n",
-      "R=ro6*(1.+gm*R2*r6/(R2+r6));\n",
-      "print\"%s %.2f %s\"%('\\neffective resistance of active load= ',R,' MOhm\\n')\n",
-      "ro4=Va/Ic4;\n",
-      "ro4=ro4*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\nResistance ro4= ',ro4,' KOhm\\n')\n",
-      "Icq=9.5;\n",
-      "x=Ri2*R/(R+Ri2);\n",
-      "y=ro4*x/(ro4+x);\n",
-      "Ad=-y*Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal differential voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input resistance to gain stage=  9.63  KOhm\n",
-        "\n",
-        "\n",
-        "Re=  18.64  KOhm\n",
-        "\n",
-        "\n",
-        "r16=  329.11  KOhm\n",
-        "\n",
-        "\n",
-        "Ri2=  4.08  KOhm\n",
-        "\n",
-        "\n",
-        "resistance of the active load=  547.37  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance =  0.37 mA/V\n",
-        "\n",
-        "\n",
-        "ro6=  5.26  MOhm\n",
-        "\n",
-        "\n",
-        "effective resistance of active load=  7.18  MOhm\n",
-        "\n",
-        "\n",
-        "Resistance ro4=  5.26  KOhm\n",
-        "\n",
-        "\n",
-        "small signal differential voltage gain=\n",
-        " -635.97 \n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg835"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.5\n",
-      "bp=50.;\n",
-      "bn=200.;\n",
-      "Va=50.;\n",
-      "R9=50.;\n",
-      "R8=0.100;\n",
-      "Rl=2.;\n",
-      "Vt=0.026;\n",
-      "Ri2=4070.;\n",
-      "Ic20=0.138;\n",
-      "r20=bp*Vt/Ic20;\n",
-      "print\"%s %.2f %s\"%('\\nr20= ',r20,' KOhm\\n')\n",
-      "R20=r20+(1.+bp)*Rl;\n",
-      "print\"%s %.2f %s\"%('\\nR20= ',R20,' KOhm\\n')\n",
-      "Ic13A=0.18;\n",
-      "R19=Va/Ic13A;\n",
-      "print\"%s %.2f %s\"%('\\nR19= ',R19,' KOhm\\n')\n",
-      "r22=bp*Vt/Ic13A;\n",
-      "print\"%s %.2f %s\"%('\\nr22= ',r22,' KOhm\\n')\n",
-      "Ri3=r22+(1.+bp)*R19*R20/(R19+R20);\n",
-      "Ri3=Ri3*0.001;##MOhm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the output stage= ',Ri3,' MOhm\\n')\n",
-      "Ic13B=0.54;\n",
-      "R=Va/Ic13B;\n",
-      "print\"%s %.2f %s\"%('\\neffective resistance of the active load= ',R,' KOhm\\n')\n",
-      "Ic17=Ic13B;\n",
-      "R17=Va/Ic17;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance Ro17 = ',R17,'KOhm\\n')\n",
-      "Ri3=Ri3*1000.;##KOhm\n",
-      "r17=9.63;\n",
-      "x=R17*Ri3/(Ri3+R17);\n",
-      "y=x*R/(R+x);\n",
-      "A=-bn*R9*(1.+bn)*y/(Ri2*(R9+r17+(1.+bn)*R8));\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',A,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "r20=  9.42  KOhm\n",
-        "\n",
-        "\n",
-        "R20=  111.42  KOhm\n",
-        "\n",
-        "\n",
-        "R19=  277.78  KOhm\n",
-        "\n",
-        "\n",
-        "r22=  7.22  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance to the output stage=  4.06  MOhm\n",
-        "\n",
-        "\n",
-        "effective resistance of the active load=  92.59  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance Ro17 =  92.59 KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " -283.53 \n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg837"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.6\n",
-      "Ic20=2.;\n",
-      "bn=200.;\n",
-      "bp=50.;\n",
-      "Va=50.;\n",
-      "r17=9.63;\n",
-      "r22=7.22;\n",
-      "R20=0.260;\n",
-      "gm17=20.8;\n",
-      "ro17=92.6;\n",
-      "Ro13B=92.6;\n",
-      "R8=0.100;\n",
-      "Rc17=ro17*(1.+gm17*R8*r17/(R8+r17));\n",
-      "print\"%s %.2f %s\"%('\\nRc17= ',Rc17,' KOhm\\n')\n",
-      "Rc22=(r22+Rc17*Ro13B/(Rc17+Ro13B))/(1.+bp);\n",
-      "print\"%s %.2f %s\"%('\\nRc22= ',Rc22,' KOhm\\n')\n",
-      "Ic13A=0.18;\n",
-      "Rc19=Va/Ic13A;\n",
-      "print\"%s %.2f %s\"%('\\nRc19= ',Rc19,' KOhm\\n')\n",
-      "Rc20=(R20+Rc22*Rc19/(Rc22+Rc19))/(1.+bp);\n",
-      "print\"%s %.2f %s\"%('\\nRc20= ',Rc20,' KOhm\\n')\n",
-      "Rc20=Rc20*1000.;##Ohm\n",
-      "R3=22.;\n",
-      "Ro=R3+Rc20;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' Ohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Rc17=  283.23  KOhm\n",
-        "\n",
-        "\n",
-        "Rc22=  1.51  KOhm\n",
-        "\n",
-        "\n",
-        "Rc19=  277.78  KOhm\n",
-        "\n",
-        "\n",
-        "Rc20=  0.03  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  56.54  Ohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg838"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.7\n",
-      "Av2=285.;\n",
-      "C1=30.;\n",
-      "Ci=C1*(1.+Av2);\n",
-      "print\"%s %.2f %s\"%('\\ninput capacitance= ',Ci,' pF\\n')\n",
-      "Ri2=4.07;\n",
-      "Ract=7.18;\n",
-      "ro4=5.26;\n",
-      "Ro1=Ract*ro4/(Ract+ro4);\n",
-      "print\"%s %.2f %s\"%('\\ngate stage input resistance= ',Ro1,' MOhm \\n')\n",
-      "Req=Ro1*Ri2/(Ri2+Ro1);\n",
-      "print\"%s %.2f %s\"%('\\nequivalent resistance= ',Req,' MOhm\\n')\n",
-      "Req=Req*10**6;##Ohm\n",
-      "Ci=Ci*10**-12;##F\n",
-      "fPD=1/(2.*math.pi*Req*Ci);\n",
-      "print\"%s %.2f %s\"%('\\ndominant pole frequency = ',fPD,' Hz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input capacitance=  8580.00  pF\n",
-        "\n",
-        "\n",
-        "gate stage input resistance=  3.04  MOhm \n",
-        "\n",
-        "\n",
-        "equivalent resistance=  1.74  MOhm\n",
-        "\n",
-        "\n",
-        "dominant pole frequency =  10.67  Hz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg842"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 13.9\n",
-      "##lambda=y\n",
-      "y=0.02;\n",
-      "##W/L=x and u*Cox/2=t\n",
-      "x=12.5;\n",
-      "t=10.;\n",
-      "Kp1=x*t;\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameters of M1 and M2= ',Kp1,' microA/V^2\\n')\n",
-      "Kp1=Kp1*0.001;##mA/V^2\n",
-      "Id=0.0199;\n",
-      "ro2=1./(y*Id);\n",
-      "ro2=ro2*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= MOhm\\n',ro2,'')\n",
-      "Iq=0.0397;\n",
-      "ro2=ro2*1000.;##Kohm\n",
-      "ro4=ro2;\n",
-      "Ad=math.sqrt(2.*Kp1*Iq)*ro2*ro4/(ro2+ro4);\n",
-      "print\"%s %.2f %s\"%('\\nthe gain of input stage= \\n',Ad,'')\n",
-      "Kn7=0.250;\n",
-      "Id7=Iq;\n",
-      "gm7=2.*math.sqrt(Kn7*Id7)\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance of M7= ',gm7,' mA/V\\n')\n",
-      "ro7=1./(y*Id7);\n",
-      "ro7=ro7*0.001;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of M7 and M8 = ',ro7,'MOhm\\n')\n",
-      "ro7=ro7*1000.;##Kohm\n",
-      "ro8=ro7;\n",
-      "Av2=gm7*ro7*ro8/(ro7+ro8);\n",
-      "print\"%s %.2f %s\"%('\\ngain of the second stage=\\n',Av2,'')\n",
-      "Av=Ad*Av2;\n",
-      "print\"%s %.2f %s\"%('\\noverall voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "conduction parameters of M1 and M2=  125.00  microA/V^2\n",
-        "\n",
-        "\n",
-        "output resistance= MOhm\n",
-        " 2.51 \n",
-        "\n",
-        "the gain of input stage= \n",
-        " 125.16 \n",
-        "\n",
-        "transconductance of M7=  0.20  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance of M7 and M8 =  1.26 MOhm\n",
-        "\n",
-        "\n",
-        "gain of the second stage=\n",
-        " 125.47 \n",
-        "\n",
-        "overall voltage gain=\n",
-        " 15703.52 \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg845"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.10\n",
-      "Iref=100;\n",
-      "Kn=80;\n",
-      "Kp=40;\n",
-      "##W/L=x\n",
-      "x=25;\n",
-      "##lambda=y\n",
-      "y=0.02;\n",
-      "Id=Iref/2.;\n",
-      "gm1=2.*math.sqrt(Kp*x*Id/2.);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance gm1=gm8= ',gm1,' microA/V\\n')\n",
-      "gm6=2.*math.sqrt(Kn*x*Id/2.);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm6,' microA/V\\n')\n",
-      "ro1=1./(y*Id);\n",
-      "ro8=ro1;\n",
-      "ro6=ro1;\n",
-      "ro10=ro1;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance ro1=ro8=ro6=ro10= ',ro1,' MOhm\\n')\n",
-      "Id4=Iref;\n",
-      "ro4=1./(y*Id4);\n",
-      "print\"%s %.2f %s\"%('\\nro4= ',ro4,' MOhm\\n')\n",
-      "Ro8=gm1*ro8*ro10;\n",
-      "print\"%s %.2f %s\"%('\\ncomposite output resistances = ',Ro8,'MOhm\\n')\n",
-      "Ro6=gm6*ro6*ro4*ro1/(ro4+ro1);\n",
-      "print\"%s %.2f %s\"%('\\ncomposite output resistances= ',Ro6,' MOhm\\n')\n",
-      "Ad=gm1*Ro6*Ro8/(Ro6+Ro8);\n",
-      "print\"%s %.2f %s\"%('\\ndifferential voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance gm1=gm8=  316.23  microA/V\n",
-        "\n",
-        "\n",
-        "transconductance=  447.21  microA/V\n",
-        "\n",
-        "\n",
-        "output resistance ro1=ro8=ro6=ro10=  1.00  MOhm\n",
-        "\n",
-        "\n",
-        "ro4=  0.50  MOhm\n",
-        "\n",
-        "\n",
-        "composite output resistances =  316.23 MOhm\n",
-        "\n",
-        "\n",
-        "composite output resistances=  149.07  MOhm\n",
-        "\n",
-        "\n",
-        "differential voltage gain=\n",
-        " 32037.72 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg854"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.12\n",
-      "Kp=0.6;\n",
-      "bn=200.;\n",
-      "Va=50.;\n",
-      "Vt=0.026;\n",
-      "Ic13=0.20;\n",
-      "Ri2=bn*Vt/Ic13;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the gain stage= ',Ri2,' KOhm\\n')\n",
-      "Iq5=Ic13;\n",
-      "Ad=math.sqrt(2.*Kp*Iq5)*Ri2;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Ad,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input resistance to the gain stage=  26.00  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " 12.74 \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg855"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.13\n",
-      "Va=150.;\n",
-      "Vt=0.026;\n",
-      "Ic13=0.2;\n",
-      "gm13=Ic13/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm13,' mA/V\\n')\n",
-      "ro13=Va/Ic13;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro13,' KOhm\\n')\n",
-      "Av2=gm13*ro13;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage gain= \\n',Av2,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  7.69  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  750.00  KOhm\n",
-        "\n",
-        "\n",
-        "voltage gain= \n",
-        " 5769.23 \n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg856"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 13.14\n",
-      "Av2=5768.;\n",
-      "C1=12.;\n",
-      "Ci=C1*(1.+Av2);\n",
-      "print\"%s %.2f %s\"%('\\neffective input capacitance= ',Ci,' pF\\n')\n",
-      "Ri2=26000.;##gain stage input resistance (Ohm)\n",
-      "Ci=Ci*10**-12;##F\n",
-      "fPD=1/(2.*math.pi*Ri2*Ci);\n",
-      "print\"%s %.2f %s\"%('\\ndominant pole frequency= ',fPD,' Hz\\n')\n",
-      "Av=73254.;\n",
-      "fT=fPD*Av;\n",
-      "fT=fT*10**-6;##MHz\n",
-      "print\"%s %.2f %s\"%('\\nunity gain bandwidth= ',fT,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "effective input capacitance=  69228.00  pF\n",
-        "\n",
-        "\n",
-        "dominant pole frequency=  88.42  Hz\n",
-        "\n",
-        "\n",
-        "unity gain bandwidth=  6.48  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter14.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter14.ipynb
deleted file mode 100755
index 9940398c..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter14.ipynb
+++ /dev/null
@@ -1,385 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:0ef8833f45f1abc63222145a7e21a8f8259a2762d408e245d2dc7a9c312f8db4"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter14-Nonideal Effects in Operational Amplifier Circuits"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg880"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "\n",
-      "##Example 14.2\n",
-      "R2=10000.;\n",
-      "Ri=10000.\n",
-      "Aol=10**5;\n",
-      "Rif=1./(1./Ri+(1.+Aol)/R2);\n",
-      "print\"%s %.2f %s\"%('\\nclosed loop input resistance = ',Rif,'Ohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "closed loop input resistance =  0.10 Ohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg883"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 14.3\n",
-      "Aol=10**5;\n",
-      "Ri=10.;\n",
-      "R1=10.;\n",
-      "R2=R1;\n",
-      "Rif=(Ri*(1.+Aol)+R2*(1.+Ri/R1))/(1.+R2/R1);\n",
-      "Rif=Rif*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance  ',Rif,'MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input resistance   500.01 MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg888"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 14.5\n",
-      "Ao=2*10**5;\n",
-      "fPD=5.;\n",
-      "fT=fPD*Ao;\n",
-      "print\"%s %.2f %s\"%('\\nunity gain bandwidth= ',fT,' Hz\\n')\n",
-      "f3dB=20.*10**3;\n",
-      "Acl=fT/f3dB;\n",
-      "print\"%s %.2f %s\"%('\\nclosed loop gain=\\n',Acl,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "unity gain bandwidth=  1000000.00  Hz\n",
-        "\n",
-        "\n",
-        "closed loop gain=\n",
-        " 50.00 \n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg890"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.6\n",
-      "Iq=19*10**-6;\n",
-      "C1=30*10**-12;\n",
-      "SR=Iq/C1;\n",
-      "SR=SR*10**-6;\n",
-      "print\"%s %.2f %s\"%('\\nslew rate= ',SR,' V/micros\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "slew rate=  0.63  V/micros\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg892"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.7\n",
-      "fT=1000.;##KHz\n",
-      "Aclo=10.;\n",
-      "SR=1.*10**3;\n",
-      "Vpo=10.;\n",
-      "f3dB=fT/Aclo;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal closed loop bandwidth= ',f3dB,' KHz\\n')\n",
-      "fmax=SR/(2.*math.pi*Vpo);\n",
-      "print\"%s %.2f %s\"%('\\nfull power bandwidth= ',fmax,' KHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal closed loop bandwidth=  100.00  KHz\n",
-        "\n",
-        "\n",
-        "full power bandwidth=  15.92  KHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg895"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 14.8\n",
-      "Is1=10**-14;\n",
-      "Is2=1.05*10**-14;\n",
-      "Vt=0.026;\n",
-      "Vos=Vt*math.log(Is2/Is1);\n",
-      "print\"%s %.2e %s\"%('\\nthe offset voltage =  ',Vos,'V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the offset voltage =   1.27e-03 V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg900"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.10\n",
-      "Kn1=105.;\n",
-      "Kn2=100.;\n",
-      "Iq=200.;\n",
-      "dKn=Kn1-Kn2;\n",
-      "print\"%s %.2f %s\"%('\\ndifference in conduction parameter= ',dKn,' microA/V^2\\n')\n",
-      "Kn=(Kn1+Kn2)/2.;\n",
-      "print\"%s %.2f %s\"%('\\naverage of the conduction parameter= ',Kn,' microA/V^2\\n')\n",
-      "Vos=math.sqrt(Iq/(2.*Kn))*dKn/(2.*Kn);\n",
-      "print\"%s %.2f %s\"%('\\noffset voltage= ',Vos,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "difference in conduction parameter=  5.00  microA/V^2\n",
-        "\n",
-        "\n",
-        "average of the conduction parameter=  102.50  microA/V^2\n",
-        "\n",
-        "\n",
-        "offset voltage=  0.02  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg901"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.11\n",
-      "Rs=100.;\n",
-      "R4=100000.;\n",
-      "R3=100000.;\n",
-      "V1=15.;\n",
-      "V2=-15.;\n",
-      "Vy=Rs*V1/(Rs+R4);\n",
-      "Vy=Vy*1000.;##mV\n",
-      "print\"%s %.2f %s\"%('\\nVoltage Vy = ',Vy,'mV\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Voltage Vy =  14.99 mV\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg908"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.13\n",
-      "R1=10.;\n",
-      "R2=100.;\n",
-      "Ib1=1.1*10**-3;\n",
-      "Ib2=1.*10**-3;\n",
-      "vo=Ib1*R2;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage = ',vo,'V\\n')\n",
-      "R3=R1*R2/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nR3= ',R3,' KOhm\\n')\n",
-      "vo=R2*(Ib1-Ib2);\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',vo,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output voltage =  0.11 V\n",
-        "\n",
-        "\n",
-        "R3=  9.09  KOhm\n",
-        "\n",
-        "\n",
-        "output voltage=  0.01  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter14_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter14_1.ipynb
deleted file mode 100755
index 9940398c..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter14_1.ipynb
+++ /dev/null
@@ -1,385 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:0ef8833f45f1abc63222145a7e21a8f8259a2762d408e245d2dc7a9c312f8db4"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter14-Nonideal Effects in Operational Amplifier Circuits"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg880"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "\n",
-      "##Example 14.2\n",
-      "R2=10000.;\n",
-      "Ri=10000.\n",
-      "Aol=10**5;\n",
-      "Rif=1./(1./Ri+(1.+Aol)/R2);\n",
-      "print\"%s %.2f %s\"%('\\nclosed loop input resistance = ',Rif,'Ohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "closed loop input resistance =  0.10 Ohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg883"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 14.3\n",
-      "Aol=10**5;\n",
-      "Ri=10.;\n",
-      "R1=10.;\n",
-      "R2=R1;\n",
-      "Rif=(Ri*(1.+Aol)+R2*(1.+Ri/R1))/(1.+R2/R1);\n",
-      "Rif=Rif*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance  ',Rif,'MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input resistance   500.01 MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg888"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 14.5\n",
-      "Ao=2*10**5;\n",
-      "fPD=5.;\n",
-      "fT=fPD*Ao;\n",
-      "print\"%s %.2f %s\"%('\\nunity gain bandwidth= ',fT,' Hz\\n')\n",
-      "f3dB=20.*10**3;\n",
-      "Acl=fT/f3dB;\n",
-      "print\"%s %.2f %s\"%('\\nclosed loop gain=\\n',Acl,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "unity gain bandwidth=  1000000.00  Hz\n",
-        "\n",
-        "\n",
-        "closed loop gain=\n",
-        " 50.00 \n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg890"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.6\n",
-      "Iq=19*10**-6;\n",
-      "C1=30*10**-12;\n",
-      "SR=Iq/C1;\n",
-      "SR=SR*10**-6;\n",
-      "print\"%s %.2f %s\"%('\\nslew rate= ',SR,' V/micros\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "slew rate=  0.63  V/micros\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg892"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.7\n",
-      "fT=1000.;##KHz\n",
-      "Aclo=10.;\n",
-      "SR=1.*10**3;\n",
-      "Vpo=10.;\n",
-      "f3dB=fT/Aclo;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal closed loop bandwidth= ',f3dB,' KHz\\n')\n",
-      "fmax=SR/(2.*math.pi*Vpo);\n",
-      "print\"%s %.2f %s\"%('\\nfull power bandwidth= ',fmax,' KHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal closed loop bandwidth=  100.00  KHz\n",
-        "\n",
-        "\n",
-        "full power bandwidth=  15.92  KHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg895"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 14.8\n",
-      "Is1=10**-14;\n",
-      "Is2=1.05*10**-14;\n",
-      "Vt=0.026;\n",
-      "Vos=Vt*math.log(Is2/Is1);\n",
-      "print\"%s %.2e %s\"%('\\nthe offset voltage =  ',Vos,'V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the offset voltage =   1.27e-03 V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg900"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.10\n",
-      "Kn1=105.;\n",
-      "Kn2=100.;\n",
-      "Iq=200.;\n",
-      "dKn=Kn1-Kn2;\n",
-      "print\"%s %.2f %s\"%('\\ndifference in conduction parameter= ',dKn,' microA/V^2\\n')\n",
-      "Kn=(Kn1+Kn2)/2.;\n",
-      "print\"%s %.2f %s\"%('\\naverage of the conduction parameter= ',Kn,' microA/V^2\\n')\n",
-      "Vos=math.sqrt(Iq/(2.*Kn))*dKn/(2.*Kn);\n",
-      "print\"%s %.2f %s\"%('\\noffset voltage= ',Vos,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "difference in conduction parameter=  5.00  microA/V^2\n",
-        "\n",
-        "\n",
-        "average of the conduction parameter=  102.50  microA/V^2\n",
-        "\n",
-        "\n",
-        "offset voltage=  0.02  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg901"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.11\n",
-      "Rs=100.;\n",
-      "R4=100000.;\n",
-      "R3=100000.;\n",
-      "V1=15.;\n",
-      "V2=-15.;\n",
-      "Vy=Rs*V1/(Rs+R4);\n",
-      "Vy=Vy*1000.;##mV\n",
-      "print\"%s %.2f %s\"%('\\nVoltage Vy = ',Vy,'mV\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Voltage Vy =  14.99 mV\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg908"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.13\n",
-      "R1=10.;\n",
-      "R2=100.;\n",
-      "Ib1=1.1*10**-3;\n",
-      "Ib2=1.*10**-3;\n",
-      "vo=Ib1*R2;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage = ',vo,'V\\n')\n",
-      "R3=R1*R2/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nR3= ',R3,' KOhm\\n')\n",
-      "vo=R2*(Ib1-Ib2);\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',vo,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output voltage =  0.11 V\n",
-        "\n",
-        "\n",
-        "R3=  9.09  KOhm\n",
-        "\n",
-        "\n",
-        "output voltage=  0.01  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter14_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter14_1_1.ipynb
deleted file mode 100755
index af5ad5a1..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter14_1_1.ipynb
+++ /dev/null
@@ -1,385 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:346bac54aa836b30505ba957f43799ddc8ade182f697449e8221de9753ec8a1b"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter14-Nonideal Effects in Operational Amplifier Circuits"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg880"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "\n",
-      "##Example 14.2\n",
-      "R2=10000.;\n",
-      "Ri=10000.\n",
-      "Aol=10**5;\n",
-      "Rif=1./(1./Ri+(1.+Aol)/R2);\n",
-      "print\"%s %.2f %s\"%('\\nclosed loop input resistance = ',Rif,'Ohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "closed loop input resistance =  0.10 Ohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg883"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 14.3\n",
-      "Aol=10**5;\n",
-      "Ri=10.;\n",
-      "R1=10.;\n",
-      "R2=R1;\n",
-      "Rif=(Ri*(1.+Aol)+R2*(1.+Ri/R1))/(1.+R2/R1);\n",
-      "Rif=Rif*0.001;##Mohm\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance  ',Rif,'MOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input resistance   500.01 MOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg888"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 14.5\n",
-      "Ao=2*10**5;\n",
-      "fPD=5.;\n",
-      "fT=fPD*Ao;\n",
-      "print\"%s %.2f %s\"%('\\nunity gain bandwidth= ',fT,' Hz\\n')\n",
-      "f3dB=20.*10**3;\n",
-      "Acl=fT/f3dB;\n",
-      "print\"%s %.2f %s\"%('\\nclosed loop gain=\\n',Acl,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "unity gain bandwidth=  1000000.00  Hz\n",
-        "\n",
-        "\n",
-        "closed loop gain=\n",
-        " 50.00 \n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg890"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.6\n",
-      "Iq=19*10**-6;\n",
-      "C1=30*10**-12;\n",
-      "SR=Iq/C1;\n",
-      "SR=SR*10**-6;\n",
-      "print\"%s %.2f %s\"%('\\nslew rate= ',SR,' V/micros\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "slew rate=  0.63  V/micros\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg892"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.7\n",
-      "fT=1000.;##KHz\n",
-      "Aclo=10.;\n",
-      "SR=1.*10**3;\n",
-      "Vpo=10.;\n",
-      "f3dB=fT/Aclo;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal closed loop bandwidth= ',f3dB,' KHz\\n')\n",
-      "fmax=SR/(2.*math.pi*Vpo);\n",
-      "print\"%s %.2f %s\"%('\\nfull power bandwidth= ',fmax,' KHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal closed loop bandwidth=  100.00  KHz\n",
-        "\n",
-        "\n",
-        "full power bandwidth=  15.92  KHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg895"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 14.8\n",
-      "Is1=10**-14;\n",
-      "Is2=1.05*10**-14;\n",
-      "Vt=0.026;\n",
-      "Vos=Vt*math.log(Is2/Is1);\n",
-      "print\"%s %.2e %s\"%('\\nthe offset voltage =  ',Vos,'V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the offset voltage =   1.27e-03 V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg900"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.10\n",
-      "Kn1=105.;\n",
-      "Kn2=100.;\n",
-      "Iq=200.;\n",
-      "dKn=Kn1-Kn2;\n",
-      "print\"%s %.2f %s\"%('\\ndifference in conduction parameter= ',dKn,' microA/V^2\\n')\n",
-      "Kn=(Kn1+Kn2)/2.;\n",
-      "print\"%s %.2f %s\"%('\\naverage of the conduction parameter= ',Kn,' microA/V^2\\n')\n",
-      "Vos=math.sqrt(Iq/(2.*Kn))*dKn/(2.*Kn);\n",
-      "print\"%s %.2f %s\"%('\\noffset voltage= ',Vos,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "difference in conduction parameter=  5.00  microA/V^2\n",
-        "\n",
-        "\n",
-        "average of the conduction parameter=  102.50  microA/V^2\n",
-        "\n",
-        "\n",
-        "offset voltage=  0.02  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg901"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.11\n",
-      "Rs=100.;\n",
-      "R4=100000.;\n",
-      "R3=100000.;\n",
-      "V1=15.;\n",
-      "V2=-15.;\n",
-      "Vy=Rs*V1/(Rs+R4);\n",
-      "Vy=Vy*1000.;##mV\n",
-      "print\"%s %.2f %s\"%('\\nVoltage Vy = ',Vy,'mV\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Voltage Vy =  14.99 mV\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg908"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 14.13\n",
-      "R1=10.;\n",
-      "R2=100.;\n",
-      "Ib1=1.1*10**-3;\n",
-      "Ib2=1.*10**-3;\n",
-      "vo=Ib1*R2;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage = ',vo,'V\\n')\n",
-      "R3=R1*R2/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nR3= ',R3,' KOhm\\n')\n",
-      "vo=R2*(Ib1-Ib2);\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',vo,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output voltage =  0.11 V\n",
-        "\n",
-        "\n",
-        "R3=  9.09  KOhm\n",
-        "\n",
-        "\n",
-        "output voltage=  0.01  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter15.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter15.ipynb
deleted file mode 100755
index 3980c758..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter15.ipynb
+++ /dev/null
@@ -1,452 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:3265ac4a672eddbdc33f1f3fbb2e748facf5a170a65e7d4c4c98fc93c38a4905"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter15-Applications and Design of Integrated Circuits"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg935"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import math\n",
-      "\n",
-      "##Example 15.2\n",
-      "C=20.*10**-6;\n",
-      "Req=1000.;\n",
-      "fC=1./(C*Req);\n",
-      "print\"%s %.2f %s\"%('\\nclock frequency = ',fC,' KHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "clock frequency =  50.00  KHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg936"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.3\n",
-      "fC=10000.;\n",
-      "f3dB=1000.;\n",
-      "##x=C2/C1\n",
-      "x=2.*math.pi*f3dB/fC;\n",
-      "print\"%s %.2f %s\"%('\\ncapacitances C2/C1= \\n',x,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "capacitances C2/C1= \n",
-        " 0.63 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg940"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.4\n",
-      "C=0.1*10**-6;\n",
-      "R=1000.;\n",
-      "fo=1/(2.*math.pi*R*C*math.sqrt(3.));\n",
-      "print\"%s %.2f %s\"%('\\nthe oscillation frequency =  ',fo,'Hz\\n')\n",
-      "##minimum amplifier gain=8\n",
-      "R=1.;##KOhm\n",
-      "R2=8.*R;\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the oscillation frequency =   918.88 Hz\n",
-        "\n",
-        "\n",
-        "R2=  8.00  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg953"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.6\n",
-      "R1=10000.;\n",
-      "R2=90000.;\n",
-      "Vh=10.;\n",
-      "Vl=-10.;\n",
-      "Vth=R1*Vh/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nupper crossover voltage= ',Vth,' V\\n')\n",
-      "Vtl=R1*Vl/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nlower crossover voltage= ',Vtl,' V\\n')\n",
-      "x=Vth-Vtl;\n",
-      "print\"%s %.2f %s\"%('\\nhysteresis width =  ',x,'V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "upper crossover voltage=  1.00  V\n",
-        "\n",
-        "\n",
-        "lower crossover voltage=  -1.00  V\n",
-        "\n",
-        "\n",
-        "hysteresis width =   2.00 V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg958"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.7\n",
-      "Vs=2.;\n",
-      "Vh=15.;\n",
-      "Vl=-15.;\n",
-      "##hysteresis width=x\n",
-      "x=60.*0.001;##(V)\n",
-      "##Vth-Vtl=(R1/(R1+R2))*(Vh-Vl)\n",
-      "##R2/R=y\n",
-      "y=(Vh-Vl)/x-1.;\n",
-      "print\"%s %.2f %s\"%('\\nR2/R1= \\n',y,'')\n",
-      "Vref=(1.+1./y)*Vs;\n",
-      "print\"%s %.2f %s\"%('\\nreference voltage= ',Vref,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "R2/R1= \n",
-        " 499.00 \n",
-        "\n",
-        "reference voltage=  2.00  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg969"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.10\n",
-      "C=15.*10**-9;\n",
-      "T=100.*10**-6;##(s) time\n",
-      "R=T/(1.1*C);\n",
-      "R=R*0.001;##Kohm\n",
-      "print\"%s %.2f %s\"%('\\nResistance R= ',R,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Resistance R=  6.06  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg974"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.13\n",
-      "Rl=10.;##load resistance \n",
-      "Pl=20.;##power delivered to the load\n",
-      "Ps=20.;##(W)\n",
-      "Vp=math.sqrt(2.*Rl*Pl);\n",
-      "print\"%s %.2f %s\"%('\\npeak output voltage= ',Vp,' V\\n')\n",
-      "Ip=Vp/Rl;\n",
-      "print\"%s %.2f %s\"%('\\npeak load current = ',Ip,'A\\n')\n",
-      "Vs=math.pi*Rl*Ps/Vp;\n",
-      "print\"%s %.2f %s\"%('\\nrequired supply voltage= ',Vs,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "peak output voltage=  20.00  V\n",
-        "\n",
-        "\n",
-        "peak load current =  2.00 A\n",
-        "\n",
-        "\n",
-        "required supply voltage=  31.42  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg979"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.14\n",
-      "Vonl=5;\n",
-      "Vofl=4.96;\n",
-      "I1=0.005;\n",
-      "I2=1.5;\n",
-      "dVo=Vonl-Vofl;\n",
-      "dIo=I1-I2;\n",
-      "Rvf=-dVo/dIo;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Rvf,' Ohm\\n')\n",
-      "LR=100.*(Vonl-Vofl)/Vonl;\n",
-      "print\"%s %.2f %s\"%('\\nload regulation =\\n',LR,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance=  0.03  Ohm\n",
-        "\n",
-        "\n",
-        "load regulation =\n",
-        " 0.80 \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg982"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.15\n",
-      "Aol=1000.;\n",
-      "Vref=5.;\n",
-      "Vo=10.;\n",
-      "Io=0.1*0.001;\n",
-      "Vt=0.026;\n",
-      "Rof=2.*Vt*Vo/(Io*Vref*Aol);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Rof,' mOhm\\n')\n",
-      "##dVo/Vo=V  and dIo/Io=I\n",
-      "##V=-I*2*Vt/(Vref*Aol)\n",
-      "##V/I=x\n",
-      "x=-2.*Vt/(Vref*Aol);\n",
-      "print\"%s %.2e %s\"%('\\npercent change=\\n',x,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance=  1.04  mOhm\n",
-        "\n",
-        "\n",
-        "percent change=\n",
-        " -1.04e-05 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg984"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.16\n",
-      "Vz=6.3;\n",
-      "Vbe=0.6;\n",
-      "Veb=0.6;\n",
-      "Vo=8.;\n",
-      "R1=3.9;\n",
-      "R2=3.4;\n",
-      "R3=0.576;\n",
-      "Ic3=(Vz-3.*Vbe)/(R1+R2+R3);\n",
-      "print\"%s %.2f %s\"%('\\nbias current = ',Ic3,' mA\\n')\n",
-      "Vb7=Ic3*R1+2.*Vbe;\n",
-      "print\"%s %.2f %s\"%('\\ntemperature compensated reference voltage= ',Vb7,' V\\n')\n",
-      "R13=2.23;\n",
-      "R12=R13*Vo/Vb7-R13;\n",
-      "print\"%s %.2f %s\"%('\\nR12= ',R12,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "bias current =  0.57  mA\n",
-        "\n",
-        "\n",
-        "temperature compensated reference voltage=  3.43  V\n",
-        "\n",
-        "\n",
-        "R12=  2.97  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter15_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter15_1.ipynb
deleted file mode 100755
index 3980c758..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter15_1.ipynb
+++ /dev/null
@@ -1,452 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:3265ac4a672eddbdc33f1f3fbb2e748facf5a170a65e7d4c4c98fc93c38a4905"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter15-Applications and Design of Integrated Circuits"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg935"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import math\n",
-      "\n",
-      "##Example 15.2\n",
-      "C=20.*10**-6;\n",
-      "Req=1000.;\n",
-      "fC=1./(C*Req);\n",
-      "print\"%s %.2f %s\"%('\\nclock frequency = ',fC,' KHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "clock frequency =  50.00  KHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg936"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.3\n",
-      "fC=10000.;\n",
-      "f3dB=1000.;\n",
-      "##x=C2/C1\n",
-      "x=2.*math.pi*f3dB/fC;\n",
-      "print\"%s %.2f %s\"%('\\ncapacitances C2/C1= \\n',x,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "capacitances C2/C1= \n",
-        " 0.63 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg940"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.4\n",
-      "C=0.1*10**-6;\n",
-      "R=1000.;\n",
-      "fo=1/(2.*math.pi*R*C*math.sqrt(3.));\n",
-      "print\"%s %.2f %s\"%('\\nthe oscillation frequency =  ',fo,'Hz\\n')\n",
-      "##minimum amplifier gain=8\n",
-      "R=1.;##KOhm\n",
-      "R2=8.*R;\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the oscillation frequency =   918.88 Hz\n",
-        "\n",
-        "\n",
-        "R2=  8.00  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg953"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.6\n",
-      "R1=10000.;\n",
-      "R2=90000.;\n",
-      "Vh=10.;\n",
-      "Vl=-10.;\n",
-      "Vth=R1*Vh/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nupper crossover voltage= ',Vth,' V\\n')\n",
-      "Vtl=R1*Vl/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nlower crossover voltage= ',Vtl,' V\\n')\n",
-      "x=Vth-Vtl;\n",
-      "print\"%s %.2f %s\"%('\\nhysteresis width =  ',x,'V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "upper crossover voltage=  1.00  V\n",
-        "\n",
-        "\n",
-        "lower crossover voltage=  -1.00  V\n",
-        "\n",
-        "\n",
-        "hysteresis width =   2.00 V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg958"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.7\n",
-      "Vs=2.;\n",
-      "Vh=15.;\n",
-      "Vl=-15.;\n",
-      "##hysteresis width=x\n",
-      "x=60.*0.001;##(V)\n",
-      "##Vth-Vtl=(R1/(R1+R2))*(Vh-Vl)\n",
-      "##R2/R=y\n",
-      "y=(Vh-Vl)/x-1.;\n",
-      "print\"%s %.2f %s\"%('\\nR2/R1= \\n',y,'')\n",
-      "Vref=(1.+1./y)*Vs;\n",
-      "print\"%s %.2f %s\"%('\\nreference voltage= ',Vref,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "R2/R1= \n",
-        " 499.00 \n",
-        "\n",
-        "reference voltage=  2.00  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg969"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.10\n",
-      "C=15.*10**-9;\n",
-      "T=100.*10**-6;##(s) time\n",
-      "R=T/(1.1*C);\n",
-      "R=R*0.001;##Kohm\n",
-      "print\"%s %.2f %s\"%('\\nResistance R= ',R,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Resistance R=  6.06  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg974"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.13\n",
-      "Rl=10.;##load resistance \n",
-      "Pl=20.;##power delivered to the load\n",
-      "Ps=20.;##(W)\n",
-      "Vp=math.sqrt(2.*Rl*Pl);\n",
-      "print\"%s %.2f %s\"%('\\npeak output voltage= ',Vp,' V\\n')\n",
-      "Ip=Vp/Rl;\n",
-      "print\"%s %.2f %s\"%('\\npeak load current = ',Ip,'A\\n')\n",
-      "Vs=math.pi*Rl*Ps/Vp;\n",
-      "print\"%s %.2f %s\"%('\\nrequired supply voltage= ',Vs,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "peak output voltage=  20.00  V\n",
-        "\n",
-        "\n",
-        "peak load current =  2.00 A\n",
-        "\n",
-        "\n",
-        "required supply voltage=  31.42  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg979"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.14\n",
-      "Vonl=5;\n",
-      "Vofl=4.96;\n",
-      "I1=0.005;\n",
-      "I2=1.5;\n",
-      "dVo=Vonl-Vofl;\n",
-      "dIo=I1-I2;\n",
-      "Rvf=-dVo/dIo;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Rvf,' Ohm\\n')\n",
-      "LR=100.*(Vonl-Vofl)/Vonl;\n",
-      "print\"%s %.2f %s\"%('\\nload regulation =\\n',LR,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance=  0.03  Ohm\n",
-        "\n",
-        "\n",
-        "load regulation =\n",
-        " 0.80 \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg982"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.15\n",
-      "Aol=1000.;\n",
-      "Vref=5.;\n",
-      "Vo=10.;\n",
-      "Io=0.1*0.001;\n",
-      "Vt=0.026;\n",
-      "Rof=2.*Vt*Vo/(Io*Vref*Aol);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Rof,' mOhm\\n')\n",
-      "##dVo/Vo=V  and dIo/Io=I\n",
-      "##V=-I*2*Vt/(Vref*Aol)\n",
-      "##V/I=x\n",
-      "x=-2.*Vt/(Vref*Aol);\n",
-      "print\"%s %.2e %s\"%('\\npercent change=\\n',x,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance=  1.04  mOhm\n",
-        "\n",
-        "\n",
-        "percent change=\n",
-        " -1.04e-05 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg984"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.16\n",
-      "Vz=6.3;\n",
-      "Vbe=0.6;\n",
-      "Veb=0.6;\n",
-      "Vo=8.;\n",
-      "R1=3.9;\n",
-      "R2=3.4;\n",
-      "R3=0.576;\n",
-      "Ic3=(Vz-3.*Vbe)/(R1+R2+R3);\n",
-      "print\"%s %.2f %s\"%('\\nbias current = ',Ic3,' mA\\n')\n",
-      "Vb7=Ic3*R1+2.*Vbe;\n",
-      "print\"%s %.2f %s\"%('\\ntemperature compensated reference voltage= ',Vb7,' V\\n')\n",
-      "R13=2.23;\n",
-      "R12=R13*Vo/Vb7-R13;\n",
-      "print\"%s %.2f %s\"%('\\nR12= ',R12,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "bias current =  0.57  mA\n",
-        "\n",
-        "\n",
-        "temperature compensated reference voltage=  3.43  V\n",
-        "\n",
-        "\n",
-        "R12=  2.97  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter15_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter15_1_1.ipynb
deleted file mode 100755
index 7e7356d2..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter15_1_1.ipynb
+++ /dev/null
@@ -1,452 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:8d0dd3bab90dc7613b5ca5489532f94ae244e073567e3fb2fd8cc9148ba4ba3a"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter15-Applications and Design of Integrated Circuits"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg935"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import math\n",
-      "\n",
-      "##Example 15.2\n",
-      "C=20.*10**-6;\n",
-      "Req=1000.;\n",
-      "fC=1./(C*Req);\n",
-      "print\"%s %.2f %s\"%('\\nclock frequency = ',fC,' KHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "clock frequency =  50.00  KHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg936"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.3\n",
-      "fC=10000.;\n",
-      "f3dB=1000.;\n",
-      "##x=C2/C1\n",
-      "x=2.*math.pi*f3dB/fC;\n",
-      "print\"%s %.2f %s\"%('\\ncapacitances C2/C1= \\n',x,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "capacitances C2/C1= \n",
-        " 0.63 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg940"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.4\n",
-      "C=0.1*10**-6;\n",
-      "R=1000.;\n",
-      "fo=1/(2.*math.pi*R*C*math.sqrt(3.));\n",
-      "print\"%s %.2f %s\"%('\\nthe oscillation frequency =  ',fo,'Hz\\n')\n",
-      "##minimum amplifier gain=8\n",
-      "R=1.;##KOhm\n",
-      "R2=8.*R;\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the oscillation frequency =   918.88 Hz\n",
-        "\n",
-        "\n",
-        "R2=  8.00  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg953"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.6\n",
-      "R1=10000.;\n",
-      "R2=90000.;\n",
-      "Vh=10.;\n",
-      "Vl=-10.;\n",
-      "Vth=R1*Vh/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nupper crossover voltage= ',Vth,' V\\n')\n",
-      "Vtl=R1*Vl/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nlower crossover voltage= ',Vtl,' V\\n')\n",
-      "x=Vth-Vtl;\n",
-      "print\"%s %.2f %s\"%('\\nhysteresis width =  ',x,'V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "upper crossover voltage=  1.00  V\n",
-        "\n",
-        "\n",
-        "lower crossover voltage=  -1.00  V\n",
-        "\n",
-        "\n",
-        "hysteresis width =   2.00 V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg958"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.7\n",
-      "Vs=2.;\n",
-      "Vh=15.;\n",
-      "Vl=-15.;\n",
-      "##hysteresis width=x\n",
-      "x=60.*0.001;##(V)\n",
-      "##Vth-Vtl=(R1/(R1+R2))*(Vh-Vl)\n",
-      "##R2/R=y\n",
-      "y=(Vh-Vl)/x-1.;\n",
-      "print\"%s %.2f %s\"%('\\nR2/R1= \\n',y,'')\n",
-      "Vref=(1.+1./y)*Vs;\n",
-      "print\"%s %.2f %s\"%('\\nreference voltage= ',Vref,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "R2/R1= \n",
-        " 499.00 \n",
-        "\n",
-        "reference voltage=  2.00  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg969"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.10\n",
-      "C=15.*10**-9;\n",
-      "T=100.*10**-6;##(s) time\n",
-      "R=T/(1.1*C);\n",
-      "R=R*0.001;##Kohm\n",
-      "print\"%s %.2f %s\"%('\\nResistance R= ',R,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Resistance R=  6.06  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg974"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.13\n",
-      "Rl=10.;##load resistance \n",
-      "Pl=20.;##power delivered to the load\n",
-      "Ps=20.;##(W)\n",
-      "Vp=math.sqrt(2.*Rl*Pl);\n",
-      "print\"%s %.2f %s\"%('\\npeak output voltage= ',Vp,' V\\n')\n",
-      "Ip=Vp/Rl;\n",
-      "print\"%s %.2f %s\"%('\\npeak load current = ',Ip,'A\\n')\n",
-      "Vs=math.pi*Rl*Ps/Vp;\n",
-      "print\"%s %.2f %s\"%('\\nrequired supply voltage= ',Vs,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "peak output voltage=  20.00  V\n",
-        "\n",
-        "\n",
-        "peak load current =  2.00 A\n",
-        "\n",
-        "\n",
-        "required supply voltage=  31.42  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg979"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.14\n",
-      "Vonl=5;\n",
-      "Vofl=4.96;\n",
-      "I1=0.005;\n",
-      "I2=1.5;\n",
-      "dVo=Vonl-Vofl;\n",
-      "dIo=I1-I2;\n",
-      "Rvf=-dVo/dIo;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Rvf,' Ohm\\n')\n",
-      "LR=100.*(Vonl-Vofl)/Vonl;\n",
-      "print\"%s %.2f %s\"%('\\nload regulation =\\n',LR,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance=  0.03  Ohm\n",
-        "\n",
-        "\n",
-        "load regulation =\n",
-        " 0.80 \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg982"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.15\n",
-      "Aol=1000.;\n",
-      "Vref=5.;\n",
-      "Vo=10.;\n",
-      "Io=0.1*0.001;\n",
-      "Vt=0.026;\n",
-      "Rof=2.*Vt*Vo/(Io*Vref*Aol);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Rof,' mOhm\\n')\n",
-      "##dVo/Vo=V  and dIo/Io=I\n",
-      "##V=-I*2*Vt/(Vref*Aol)\n",
-      "##V/I=x\n",
-      "x=-2.*Vt/(Vref*Aol);\n",
-      "print\"%s %.2e %s\"%('\\npercent change=\\n',x,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance=  1.04  mOhm\n",
-        "\n",
-        "\n",
-        "percent change=\n",
-        " -1.04e-05 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg984"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 15.16\n",
-      "Vz=6.3;\n",
-      "Vbe=0.6;\n",
-      "Veb=0.6;\n",
-      "Vo=8.;\n",
-      "R1=3.9;\n",
-      "R2=3.4;\n",
-      "R3=0.576;\n",
-      "Ic3=(Vz-3.*Vbe)/(R1+R2+R3);\n",
-      "print\"%s %.2f %s\"%('\\nbias current = ',Ic3,' mA\\n')\n",
-      "Vb7=Ic3*R1+2.*Vbe;\n",
-      "print\"%s %.2f %s\"%('\\ntemperature compensated reference voltage= ',Vb7,' V\\n')\n",
-      "R13=2.23;\n",
-      "R12=R13*Vo/Vb7-R13;\n",
-      "print\"%s %.2f %s\"%('\\nR12= ',R12,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "bias current =  0.57  mA\n",
-        "\n",
-        "\n",
-        "temperature compensated reference voltage=  3.43  V\n",
-        "\n",
-        "\n",
-        "R12=  2.97  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter16.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter16.ipynb
deleted file mode 100755
index 2d0de40c..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter16.ipynb
+++ /dev/null
@@ -1,428 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:2c1f0572305869070ba4c4550f2c2ddcdc134200c33890cfededcae546a1a172"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter16-MOSFET Digital Circuits "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg1013"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 16.3\n",
-      "Vdd=5.;\n",
-      "Vtnd=0.8;\n",
-      "Vtnl=0.8;\n",
-      "Kn=35.;\n",
-      "Vo=0.1;\n",
-      "Vi=4.2;\n",
-      "##W/L=Y\n",
-      "yl=0.5;\n",
-      "##Kd/Kl=x\n",
-      "x=(Vdd-Vo-Vtnl)**2/(2.*Vo*(Vi-Vtnd)-Vo**2);\n",
-      "print\"%s %.2f %s\"%('\\nKd/Kl=\\n',x,'')\n",
-      "##Kd/Kl=yd/yl\n",
-      "yd=12.6\n",
-      "yl=0.5\n",
-      "iD=Kn*yl*(Vdd-Vo-Vtnl)**2/2.;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current = ',iD,' microA\\n')\n",
-      "P=iD*Vdd;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Kd/Kl=\n",
-        " 25.09 \n",
-        "\n",
-        "drain current =  147.09  microA\n",
-        "\n",
-        "\n",
-        "power dissipation=  735.44  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg1017"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 16.4\n",
-      "Vdd=5.;\n",
-      "Vtnd=0.8;\n",
-      "Vtnl=-2.;\n",
-      "Kn=35.;\n",
-      "Vo=0.1;\n",
-      "Vi=5.;\n",
-      "##W/L=Y\n",
-      "yl=0.5;\n",
-      "##Kd/Kl=x\n",
-      "x=(-Vtnl)**2/(2.*Vo*(Vi-Vtnd)-Vo**2);\n",
-      "print\"%s %.2f %s\"%('\\nKd/Kl=\\n',x,'')\n",
-      "##Kd/Kl=yd/yl\n",
-      "yd=2.41\n",
-      "yl=0.5\n",
-      "iD=Kn*yl*(-Vtnl)**2/2.;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',iD,' microA\\n')\n",
-      "P=iD*Vdd;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation = ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Kd/Kl=\n",
-        " 4.82 \n",
-        "\n",
-        "drain current=  35.00  microA\n",
-        "\n",
-        "\n",
-        "power dissipation =  175.00  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg1021"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 16.5\n",
-      "Voh=4.2;\n",
-      "Vol=0.1;\n",
-      "##x=Kd/Kl\n",
-      "x=25.1;\n",
-      "Vdd=5.;\n",
-      "Vtnl=0.8;\n",
-      "Vohu=4.2;\n",
-      "Vil=0.8;\n",
-      "Vtnd=0.8;\n",
-      "Vih=Vtnd+(Vdd-Vtnl)/x*((1+2*x)/math.sqrt(1.+3.*x)-1.);\n",
-      "print\"%s %.2f %s\"%('\\nVih= ',Vih,' V\\n')\n",
-      "Volu=(Vdd-Vtnl+x*(Vih-Vtnd))/(1.+2.*x);\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage corresponding to Vih= ',Volu,' V\\n')\n",
-      "NMl=Vil-Volu;\n",
-      "print\"%s %.2f %s\"%('\\nnoise margin= ',NMl,' V\\n')\n",
-      "NMh=Vohu-Vih;\n",
-      "print\"%s %.2f %s\"%('\\nnoise margin= ',NMh,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vih=  1.61  V\n",
-        "\n",
-        "\n",
-        "output voltage corresponding to Vih=  0.48  V\n",
-        "\n",
-        "\n",
-        "noise margin=  0.32  V\n",
-        "\n",
-        "\n",
-        "noise margin=  2.59  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg1041"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 16.9\n",
-      "Vdd=5.;\n",
-      "Vtn=1.;\n",
-      "Vtp=-1.;\n",
-      "##Kn=Kp hence Kn/Kp=x=1;\n",
-      "x=1.;\n",
-      "Vit=(Vdd+Vtp+math.sqrt(x)*Vtn)/(1.+math.sqrt(x));\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage= ',Vit,' V\\n')\n",
-      "Vipt=Vit;\n",
-      "Vopt=Vipt-Vtp;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage at the transition point for PMOS = ',Vopt,' V\\n')\n",
-      "Vint=Vit;\n",
-      "Vont=Vint-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage at the transition point for NMOS= ',Vont,' V\\n')\n",
-      "Vdd=10.;\n",
-      "Vit=(Vdd+Vtp+math.sqrt(x)*Vtn)/(1.+math.sqrt(x));\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage = ',Vit,'V\\n')\n",
-      "Vipt=Vit;\n",
-      "Vint=Vit;\n",
-      "Vopt=Vipt-Vtp;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage at the transition point for PMOS = ',Vopt,'   V\\n')\n",
-      "Vont=Vint-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage at the transition point for NMOS = ',Vont,'   V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input voltage=  2.50  V\n",
-        "\n",
-        "\n",
-        "output voltage at the transition point for PMOS =  3.50  V\n",
-        "\n",
-        "\n",
-        "output voltage at the transition point for NMOS=  1.50  V\n",
-        "\n",
-        "\n",
-        "input voltage =  5.00 V\n",
-        "\n",
-        "\n",
-        "output voltage at the transition point for PMOS =  6.00    V\n",
-        "\n",
-        "\n",
-        "output voltage at the transition point for NMOS =  4.00    V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg1045"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 16.10\n",
-      "Cl=2.*10**-6;\n",
-      "Vdd=5.;\n",
-      "f=100000.;\n",
-      "P=f*Cl*Vdd**2;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation in the CMOS inverter= ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "power dissipation in the CMOS inverter=  5.00  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg1047"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 16.11\n",
-      "Vtn=1.;\n",
-      "Vtp=-1.;\n",
-      "Vdd=5.;\n",
-      "Vth=1.;\n",
-      "Vil=Vtn+3.*(Vdd+Vtp-Vth)/8.;\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage at the transition points Vil= ',Vil,' V\\n')\n",
-      "Vih=Vtn+5.*(Vdd+Vtp-Vtn)/8.;\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage at the transition points Vih= ',Vih,'  V\\n')\n",
-      "Vohu=1.*(2.*Vil+Vdd-Vtn-Vtp)/2.;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage = ',Vohu,' V\\n')\n",
-      "Volu=1.*(2.*Vih-Vdd-Vtn-Vtp)/2.;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage = ',Volu,' V\\n')\n",
-      "NML=Vil-Volu;\n",
-      "print\"%s %.2f %s\"%('\\nnoise margin = ',NML,' V\\n')\n",
-      "NMH=Vohu-Vih;\n",
-      "print\"%s %.2f %s\"%('\\nnoise margin= ',NML,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input voltage at the transition points Vil=  2.12  V\n",
-        "\n",
-        "\n",
-        "input voltage at the transition points Vih=  2.88   V\n",
-        "\n",
-        "\n",
-        "output voltage =  4.62  V\n",
-        "\n",
-        "\n",
-        "output voltage =  0.38  V\n",
-        "\n",
-        "\n",
-        "noise margin =  1.75  V\n",
-        "\n",
-        "\n",
-        "noise margin=  1.75  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg1080"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 16.15\n",
-      "Vdd=3.;\n",
-      "Kn=60.;\n",
-      "Vtnd=0.5;\n",
-      "##W/L=x\n",
-      "xd=2.;\n",
-      "Vtnl=-1.;\n",
-      "xl=0.5;\n",
-      "R=2.;##(MOhm)\n",
-      "Vgsl=0.;\n",
-      "##solution with Depletion load\n",
-      "iD=Kn*xl*(Vgsl-Vtnl)**2/2.;\n",
-      "print\"%s %.2f %s\"%('\\nfrain currents in M1 and M3 = ',iD,' microA\\n')\n",
-      "P=iD*Vdd;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation in the circuit= ',P,'microW\\n')\n",
-      "##iD=Kn/2*x*(2*Vgsd-Vtnd)Vdsd-Vdsd^2\n",
-      "Q=50.5\n",
-      "p=0.25 - 5*(50.5) + 50.5\n",
-      "print(p)\n",
-      "\n",
-      "##solution with Resistor load\n",
-      "##(Vdd-Q)/R=Kn/2*xd*(2*Vgsd-Vtnd)Q-Q^2\n",
-      "\n",
-      "\n",
-      "Q=0.005;\n",
-      "p1=0.25 - 5*(0.005) + 0.005\n",
-      "print(p1)\n",
-      "iD=(Vdd-Q)/R;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current = ',iD,' microA\\n')\n",
-      "P=iD*Vdd;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation in the circuit = ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "frain currents in M1 and M3 =  15.00  microA\n",
-        "\n",
-        "\n",
-        "power dissipation in the circuit=  45.00 microW\n",
-        "\n",
-        "-201.75\n",
-        "0.23\n",
-        "\n",
-        "drain current =  1.50  microA\n",
-        "\n",
-        "\n",
-        "power dissipation in the circuit =  4.49  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter16_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter16_1.ipynb
deleted file mode 100755
index 2d0de40c..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter16_1.ipynb
+++ /dev/null
@@ -1,428 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:2c1f0572305869070ba4c4550f2c2ddcdc134200c33890cfededcae546a1a172"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter16-MOSFET Digital Circuits "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg1013"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 16.3\n",
-      "Vdd=5.;\n",
-      "Vtnd=0.8;\n",
-      "Vtnl=0.8;\n",
-      "Kn=35.;\n",
-      "Vo=0.1;\n",
-      "Vi=4.2;\n",
-      "##W/L=Y\n",
-      "yl=0.5;\n",
-      "##Kd/Kl=x\n",
-      "x=(Vdd-Vo-Vtnl)**2/(2.*Vo*(Vi-Vtnd)-Vo**2);\n",
-      "print\"%s %.2f %s\"%('\\nKd/Kl=\\n',x,'')\n",
-      "##Kd/Kl=yd/yl\n",
-      "yd=12.6\n",
-      "yl=0.5\n",
-      "iD=Kn*yl*(Vdd-Vo-Vtnl)**2/2.;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current = ',iD,' microA\\n')\n",
-      "P=iD*Vdd;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Kd/Kl=\n",
-        " 25.09 \n",
-        "\n",
-        "drain current =  147.09  microA\n",
-        "\n",
-        "\n",
-        "power dissipation=  735.44  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg1017"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 16.4\n",
-      "Vdd=5.;\n",
-      "Vtnd=0.8;\n",
-      "Vtnl=-2.;\n",
-      "Kn=35.;\n",
-      "Vo=0.1;\n",
-      "Vi=5.;\n",
-      "##W/L=Y\n",
-      "yl=0.5;\n",
-      "##Kd/Kl=x\n",
-      "x=(-Vtnl)**2/(2.*Vo*(Vi-Vtnd)-Vo**2);\n",
-      "print\"%s %.2f %s\"%('\\nKd/Kl=\\n',x,'')\n",
-      "##Kd/Kl=yd/yl\n",
-      "yd=2.41\n",
-      "yl=0.5\n",
-      "iD=Kn*yl*(-Vtnl)**2/2.;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',iD,' microA\\n')\n",
-      "P=iD*Vdd;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation = ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Kd/Kl=\n",
-        " 4.82 \n",
-        "\n",
-        "drain current=  35.00  microA\n",
-        "\n",
-        "\n",
-        "power dissipation =  175.00  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg1021"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 16.5\n",
-      "Voh=4.2;\n",
-      "Vol=0.1;\n",
-      "##x=Kd/Kl\n",
-      "x=25.1;\n",
-      "Vdd=5.;\n",
-      "Vtnl=0.8;\n",
-      "Vohu=4.2;\n",
-      "Vil=0.8;\n",
-      "Vtnd=0.8;\n",
-      "Vih=Vtnd+(Vdd-Vtnl)/x*((1+2*x)/math.sqrt(1.+3.*x)-1.);\n",
-      "print\"%s %.2f %s\"%('\\nVih= ',Vih,' V\\n')\n",
-      "Volu=(Vdd-Vtnl+x*(Vih-Vtnd))/(1.+2.*x);\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage corresponding to Vih= ',Volu,' V\\n')\n",
-      "NMl=Vil-Volu;\n",
-      "print\"%s %.2f %s\"%('\\nnoise margin= ',NMl,' V\\n')\n",
-      "NMh=Vohu-Vih;\n",
-      "print\"%s %.2f %s\"%('\\nnoise margin= ',NMh,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vih=  1.61  V\n",
-        "\n",
-        "\n",
-        "output voltage corresponding to Vih=  0.48  V\n",
-        "\n",
-        "\n",
-        "noise margin=  0.32  V\n",
-        "\n",
-        "\n",
-        "noise margin=  2.59  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg1041"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 16.9\n",
-      "Vdd=5.;\n",
-      "Vtn=1.;\n",
-      "Vtp=-1.;\n",
-      "##Kn=Kp hence Kn/Kp=x=1;\n",
-      "x=1.;\n",
-      "Vit=(Vdd+Vtp+math.sqrt(x)*Vtn)/(1.+math.sqrt(x));\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage= ',Vit,' V\\n')\n",
-      "Vipt=Vit;\n",
-      "Vopt=Vipt-Vtp;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage at the transition point for PMOS = ',Vopt,' V\\n')\n",
-      "Vint=Vit;\n",
-      "Vont=Vint-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage at the transition point for NMOS= ',Vont,' V\\n')\n",
-      "Vdd=10.;\n",
-      "Vit=(Vdd+Vtp+math.sqrt(x)*Vtn)/(1.+math.sqrt(x));\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage = ',Vit,'V\\n')\n",
-      "Vipt=Vit;\n",
-      "Vint=Vit;\n",
-      "Vopt=Vipt-Vtp;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage at the transition point for PMOS = ',Vopt,'   V\\n')\n",
-      "Vont=Vint-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage at the transition point for NMOS = ',Vont,'   V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input voltage=  2.50  V\n",
-        "\n",
-        "\n",
-        "output voltage at the transition point for PMOS =  3.50  V\n",
-        "\n",
-        "\n",
-        "output voltage at the transition point for NMOS=  1.50  V\n",
-        "\n",
-        "\n",
-        "input voltage =  5.00 V\n",
-        "\n",
-        "\n",
-        "output voltage at the transition point for PMOS =  6.00    V\n",
-        "\n",
-        "\n",
-        "output voltage at the transition point for NMOS =  4.00    V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg1045"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 16.10\n",
-      "Cl=2.*10**-6;\n",
-      "Vdd=5.;\n",
-      "f=100000.;\n",
-      "P=f*Cl*Vdd**2;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation in the CMOS inverter= ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "power dissipation in the CMOS inverter=  5.00  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg1047"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 16.11\n",
-      "Vtn=1.;\n",
-      "Vtp=-1.;\n",
-      "Vdd=5.;\n",
-      "Vth=1.;\n",
-      "Vil=Vtn+3.*(Vdd+Vtp-Vth)/8.;\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage at the transition points Vil= ',Vil,' V\\n')\n",
-      "Vih=Vtn+5.*(Vdd+Vtp-Vtn)/8.;\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage at the transition points Vih= ',Vih,'  V\\n')\n",
-      "Vohu=1.*(2.*Vil+Vdd-Vtn-Vtp)/2.;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage = ',Vohu,' V\\n')\n",
-      "Volu=1.*(2.*Vih-Vdd-Vtn-Vtp)/2.;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage = ',Volu,' V\\n')\n",
-      "NML=Vil-Volu;\n",
-      "print\"%s %.2f %s\"%('\\nnoise margin = ',NML,' V\\n')\n",
-      "NMH=Vohu-Vih;\n",
-      "print\"%s %.2f %s\"%('\\nnoise margin= ',NML,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input voltage at the transition points Vil=  2.12  V\n",
-        "\n",
-        "\n",
-        "input voltage at the transition points Vih=  2.88   V\n",
-        "\n",
-        "\n",
-        "output voltage =  4.62  V\n",
-        "\n",
-        "\n",
-        "output voltage =  0.38  V\n",
-        "\n",
-        "\n",
-        "noise margin =  1.75  V\n",
-        "\n",
-        "\n",
-        "noise margin=  1.75  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg1080"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 16.15\n",
-      "Vdd=3.;\n",
-      "Kn=60.;\n",
-      "Vtnd=0.5;\n",
-      "##W/L=x\n",
-      "xd=2.;\n",
-      "Vtnl=-1.;\n",
-      "xl=0.5;\n",
-      "R=2.;##(MOhm)\n",
-      "Vgsl=0.;\n",
-      "##solution with Depletion load\n",
-      "iD=Kn*xl*(Vgsl-Vtnl)**2/2.;\n",
-      "print\"%s %.2f %s\"%('\\nfrain currents in M1 and M3 = ',iD,' microA\\n')\n",
-      "P=iD*Vdd;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation in the circuit= ',P,'microW\\n')\n",
-      "##iD=Kn/2*x*(2*Vgsd-Vtnd)Vdsd-Vdsd^2\n",
-      "Q=50.5\n",
-      "p=0.25 - 5*(50.5) + 50.5\n",
-      "print(p)\n",
-      "\n",
-      "##solution with Resistor load\n",
-      "##(Vdd-Q)/R=Kn/2*xd*(2*Vgsd-Vtnd)Q-Q^2\n",
-      "\n",
-      "\n",
-      "Q=0.005;\n",
-      "p1=0.25 - 5*(0.005) + 0.005\n",
-      "print(p1)\n",
-      "iD=(Vdd-Q)/R;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current = ',iD,' microA\\n')\n",
-      "P=iD*Vdd;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation in the circuit = ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "frain currents in M1 and M3 =  15.00  microA\n",
-        "\n",
-        "\n",
-        "power dissipation in the circuit=  45.00 microW\n",
-        "\n",
-        "-201.75\n",
-        "0.23\n",
-        "\n",
-        "drain current =  1.50  microA\n",
-        "\n",
-        "\n",
-        "power dissipation in the circuit =  4.49  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter16_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter16_1_1.ipynb
deleted file mode 100755
index a7c194d9..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter16_1_1.ipynb
+++ /dev/null
@@ -1,428 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:967330d5e3a998fb6f78e20c34781eef3a87e37f117b0ab752e2b4eb4123a177"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter16-MOSFET Digital Circuits "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg1013"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 16.3\n",
-      "Vdd=5.;\n",
-      "Vtnd=0.8;\n",
-      "Vtnl=0.8;\n",
-      "Kn=35.;\n",
-      "Vo=0.1;\n",
-      "Vi=4.2;\n",
-      "##W/L=Y\n",
-      "yl=0.5;\n",
-      "##Kd/Kl=x\n",
-      "x=(Vdd-Vo-Vtnl)**2/(2.*Vo*(Vi-Vtnd)-Vo**2);\n",
-      "print\"%s %.2f %s\"%('\\nKd/Kl=\\n',x,'')\n",
-      "##Kd/Kl=yd/yl\n",
-      "yd=12.6\n",
-      "yl=0.5\n",
-      "iD=Kn*yl*(Vdd-Vo-Vtnl)**2/2.;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current = ',iD,' microA\\n')\n",
-      "P=iD*Vdd;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Kd/Kl=\n",
-        " 25.09 \n",
-        "\n",
-        "drain current =  147.09  microA\n",
-        "\n",
-        "\n",
-        "power dissipation=  735.44  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg1017"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 16.4\n",
-      "Vdd=5.;\n",
-      "Vtnd=0.8;\n",
-      "Vtnl=-2.;\n",
-      "Kn=35.;\n",
-      "Vo=0.1;\n",
-      "Vi=5.;\n",
-      "##W/L=Y\n",
-      "yl=0.5;\n",
-      "##Kd/Kl=x\n",
-      "x=(-Vtnl)**2/(2.*Vo*(Vi-Vtnd)-Vo**2);\n",
-      "print\"%s %.2f %s\"%('\\nKd/Kl=\\n',x,'')\n",
-      "##Kd/Kl=yd/yl\n",
-      "yd=2.41\n",
-      "yl=0.5\n",
-      "iD=Kn*yl*(-Vtnl)**2/2.;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',iD,' microA\\n')\n",
-      "P=iD*Vdd;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation = ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Kd/Kl=\n",
-        " 4.82 \n",
-        "\n",
-        "drain current=  35.00  microA\n",
-        "\n",
-        "\n",
-        "power dissipation =  175.00  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg1021"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 16.5\n",
-      "Voh=4.2;\n",
-      "Vol=0.1;\n",
-      "##x=Kd/Kl\n",
-      "x=25.1;\n",
-      "Vdd=5.;\n",
-      "Vtnl=0.8;\n",
-      "Vohu=4.2;\n",
-      "Vil=0.8;\n",
-      "Vtnd=0.8;\n",
-      "Vih=Vtnd+(Vdd-Vtnl)/x*((1+2*x)/math.sqrt(1.+3.*x)-1.);\n",
-      "print\"%s %.2f %s\"%('\\nVih= ',Vih,' V\\n')\n",
-      "Volu=(Vdd-Vtnl+x*(Vih-Vtnd))/(1.+2.*x);\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage corresponding to Vih= ',Volu,' V\\n')\n",
-      "NMl=Vil-Volu;\n",
-      "print\"%s %.2f %s\"%('\\nnoise margin= ',NMl,' V\\n')\n",
-      "NMh=Vohu-Vih;\n",
-      "print\"%s %.2f %s\"%('\\nnoise margin= ',NMh,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vih=  1.61  V\n",
-        "\n",
-        "\n",
-        "output voltage corresponding to Vih=  0.48  V\n",
-        "\n",
-        "\n",
-        "noise margin=  0.32  V\n",
-        "\n",
-        "\n",
-        "noise margin=  2.59  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg1041"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 16.9\n",
-      "Vdd=5.;\n",
-      "Vtn=1.;\n",
-      "Vtp=-1.;\n",
-      "##Kn=Kp hence Kn/Kp=x=1;\n",
-      "x=1.;\n",
-      "Vit=(Vdd+Vtp+math.sqrt(x)*Vtn)/(1.+math.sqrt(x));\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage= ',Vit,' V\\n')\n",
-      "Vipt=Vit;\n",
-      "Vopt=Vipt-Vtp;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage at the transition point for PMOS = ',Vopt,' V\\n')\n",
-      "Vint=Vit;\n",
-      "Vont=Vint-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage at the transition point for NMOS= ',Vont,' V\\n')\n",
-      "Vdd=10.;\n",
-      "Vit=(Vdd+Vtp+math.sqrt(x)*Vtn)/(1.+math.sqrt(x));\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage = ',Vit,'V\\n')\n",
-      "Vipt=Vit;\n",
-      "Vint=Vit;\n",
-      "Vopt=Vipt-Vtp;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage at the transition point for PMOS = ',Vopt,'   V\\n')\n",
-      "Vont=Vint-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage at the transition point for NMOS = ',Vont,'   V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input voltage=  2.50  V\n",
-        "\n",
-        "\n",
-        "output voltage at the transition point for PMOS =  3.50  V\n",
-        "\n",
-        "\n",
-        "output voltage at the transition point for NMOS=  1.50  V\n",
-        "\n",
-        "\n",
-        "input voltage =  5.00 V\n",
-        "\n",
-        "\n",
-        "output voltage at the transition point for PMOS =  6.00    V\n",
-        "\n",
-        "\n",
-        "output voltage at the transition point for NMOS =  4.00    V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg1045"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 16.10\n",
-      "Cl=2.*10**-6;\n",
-      "Vdd=5.;\n",
-      "f=100000.;\n",
-      "P=f*Cl*Vdd**2;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation in the CMOS inverter= ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "power dissipation in the CMOS inverter=  5.00  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg1047"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 16.11\n",
-      "Vtn=1.;\n",
-      "Vtp=-1.;\n",
-      "Vdd=5.;\n",
-      "Vth=1.;\n",
-      "Vil=Vtn+3.*(Vdd+Vtp-Vth)/8.;\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage at the transition points Vil= ',Vil,' V\\n')\n",
-      "Vih=Vtn+5.*(Vdd+Vtp-Vtn)/8.;\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage at the transition points Vih= ',Vih,'  V\\n')\n",
-      "Vohu=1.*(2.*Vil+Vdd-Vtn-Vtp)/2.;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage = ',Vohu,' V\\n')\n",
-      "Volu=1.*(2.*Vih-Vdd-Vtn-Vtp)/2.;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage = ',Volu,' V\\n')\n",
-      "NML=Vil-Volu;\n",
-      "print\"%s %.2f %s\"%('\\nnoise margin = ',NML,' V\\n')\n",
-      "NMH=Vohu-Vih;\n",
-      "print\"%s %.2f %s\"%('\\nnoise margin= ',NML,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "input voltage at the transition points Vil=  2.12  V\n",
-        "\n",
-        "\n",
-        "input voltage at the transition points Vih=  2.88   V\n",
-        "\n",
-        "\n",
-        "output voltage =  4.62  V\n",
-        "\n",
-        "\n",
-        "output voltage =  0.38  V\n",
-        "\n",
-        "\n",
-        "noise margin =  1.75  V\n",
-        "\n",
-        "\n",
-        "noise margin=  1.75  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg1080"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 16.15\n",
-      "Vdd=3.;\n",
-      "Kn=60.;\n",
-      "Vtnd=0.5;\n",
-      "##W/L=x\n",
-      "xd=2.;\n",
-      "Vtnl=-1.;\n",
-      "xl=0.5;\n",
-      "R=2.;##(MOhm)\n",
-      "Vgsl=0.;\n",
-      "##solution with Depletion load\n",
-      "iD=Kn*xl*(Vgsl-Vtnl)**2/2.;\n",
-      "print\"%s %.2f %s\"%('\\nfrain currents in M1 and M3 = ',iD,' microA\\n')\n",
-      "P=iD*Vdd;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation in the circuit= ',P,'microW\\n')\n",
-      "##iD=Kn/2*x*(2*Vgsd-Vtnd)Vdsd-Vdsd^2\n",
-      "Q=50.5\n",
-      "p=0.25 - 5*(50.5) + 50.5\n",
-      "print(p)\n",
-      "\n",
-      "##solution with Resistor load\n",
-      "##(Vdd-Q)/R=Kn/2*xd*(2*Vgsd-Vtnd)Q-Q^2\n",
-      "\n",
-      "\n",
-      "Q=0.005;\n",
-      "p1=0.25 - 5*(0.005) + 0.005\n",
-      "print(p1)\n",
-      "iD=(Vdd-Q)/R;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current = ',iD,' microA\\n')\n",
-      "P=iD*Vdd;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation in the circuit = ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "frain currents in M1 and M3 =  15.00  microA\n",
-        "\n",
-        "\n",
-        "power dissipation in the circuit=  45.00 microW\n",
-        "\n",
-        "-201.75\n",
-        "0.23\n",
-        "\n",
-        "drain current =  1.50  microA\n",
-        "\n",
-        "\n",
-        "power dissipation in the circuit =  4.49  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter17.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter17.ipynb
deleted file mode 100755
index 36f2555a..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter17.ipynb
+++ /dev/null
@@ -1,647 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:abf15ae78837b656bd4ca10fb9d29bc4f18126add8de13c4bce16bc14f199d7a"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter17-Bipolar Digital Circuits"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg1115"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.1\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "Rc1=1.;\n",
-      "Rc2=Rc1;\n",
-      "Rc=Rc1;\n",
-      "Re=2.150;\n",
-      "v2=0.;\n",
-      "##for v1=0\n",
-      "vE=-0.7;\n",
-      "iE=(vE-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' mA\\n')\n",
-      "iC=1.;\n",
-      "Vcc=5.;\n",
-      "vo1=Vcc-iC*Rc;\n",
-      "print\"%s %.2f %s\"%('\\nvo1=vo2= ',vo1,' V\\n')\n",
-      "##for v2=-1\n",
-      "vE=-0.7;\n",
-      "iE=2.;\n",
-      "iC2=2.;\n",
-      "vo1=5.;\n",
-      "vo2=Vcc-iC2*Rc;\n",
-      "print\"%s %.2f %s\"%('\\nvo2= ',vo2,' V\\n')\n",
-      "v1=1.;\n",
-      "Vbe=0.7;\n",
-      "vE=v1-Vbe;\n",
-      "iE=(vE-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current =',iE,' mA\\n')\n",
-      "iC1=iE;\n",
-      "vo1=Vcc-iC1*Rc;\n",
-      "print\"%s %.2f %s\"%('\\nvo1= ',vo1,' V\\n')\n",
-      "vo2=Vcc\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter current=  2.00  mA\n",
-        "\n",
-        "\n",
-        "vo1=vo2=  4.00  V\n",
-        "\n",
-        "\n",
-        "vo2=  3.00  V\n",
-        "\n",
-        "\n",
-        "emitter current = 2.47  mA\n",
-        "\n",
-        "\n",
-        "vo1=  2.53  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg1118"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.2\n",
-      "Vx=-0.7;\n",
-      "Vy=Vx;\n",
-      "Vbe=0.7;\n",
-      "V2=-5.2;\n",
-      "Re=1.180;\n",
-      "vE=Vx-Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nemitter voltage = ',vE,'  V\\n')\n",
-      "iE=(vE-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' mA\\n')\n",
-      "Icxy=iE;\n",
-      "vo1=-0.7;\n",
-      "Rc1=-vo1/Icxy;\n",
-      "print\"%s %.2f %s\"%('\\nRc1= ',Rc1,' KOhm\\n')\n",
-      "Vnor=vo1-Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nNOR output logic 0 value= ',Vnor,' V\\n')\n",
-      "Vr=(vo1+Vnor)/2.;\n",
-      "vE=Vr-Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nvE= ',vE,' V\\n')\n",
-      "iE=(vE-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\niE= ',iE,' mA\\n')\n",
-      "vo2=-0.7;\n",
-      "iC2=iE;\n",
-      "Rc2=-vo2/iC2;\n",
-      "print\"%s %.2f %s\"%('\\nRc2= ',Rc2,' KOhm\\n')\n",
-      "Vor=vo2-Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nOR logic 0 value is= ',Vor,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter voltage =  -1.40   V\n",
-        "\n",
-        "\n",
-        "emitter current=  3.22  mA\n",
-        "\n",
-        "\n",
-        "Rc1=  0.22  KOhm\n",
-        "\n",
-        "\n",
-        "NOR output logic 0 value=  -1.40  V\n",
-        "\n",
-        "\n",
-        "vE=  -1.75  V\n",
-        "\n",
-        "\n",
-        "iE=  2.92  mA\n",
-        "\n",
-        "\n",
-        "Rc2=  0.24  KOhm\n",
-        "\n",
-        "\n",
-        "OR logic 0 value is=  -1.40  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg1120"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.3\n",
-      "Vr=-1.05;\n",
-      "Vbe=0.7;\n",
-      "Vb5=Vr+Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nVb5 = ',Vb5,' V\\n')\n",
-      "R1=0.250;\n",
-      "i1=-Vb5/R1;\n",
-      "print\"%s %.2f %s\"%('\\ni1= ',i1,' mA\\n')\n",
-      "Vy=0.7;\n",
-      "V2=-5.2;\n",
-      "##let R1+R2=x\n",
-      "x=(-2.*Vy-V2)/i1;\n",
-      "R2=x-R1;\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n",
-      "iS=i1;\n",
-      "Rs=(Vr-V2)/iS;\n",
-      "print\"%s %.2f %s\"%('\\nRs= ',Rs,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vb5 =  -0.35  V\n",
-        "\n",
-        "\n",
-        "i1=  1.40  mA\n",
-        "\n",
-        "\n",
-        "R2=  2.46  KOhm\n",
-        "\n",
-        "\n",
-        "Rs=  2.96  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg1121"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.4\n",
-      "Vx=-0.7;\n",
-      "Vy=-0.7;\n",
-      "iCxy=3.22;##(mA)\n",
-      "iCR=0.;\n",
-      "i5=1.40;\n",
-      "i1=1.40;\n",
-      "Vor=-0.7;\n",
-      "R4=1.500;\n",
-      "Vnor=-1.4;\n",
-      "V2=-5.2;\n",
-      "R3=1.500;\n",
-      "i3=(Vor-V2)/R3;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i3= ',i3,' mA\\n')\n",
-      "i4=(Vnor-V2)/R4;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i4 = ',i4, 'mA')\n",
-      "P=(iCxy+iCR+i5+i1+i3+i4)*(0.-V2);\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',P,' mW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "current i3=  3.00  mA\n",
-        "\n",
-        "\n",
-        "current i4 =  2.53 mA\n",
-        "\n",
-        "power dissipation=  60.08  mW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg1122"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.5\n",
-      "b=50.;\n",
-      "V2=-5.2;\n",
-      "Vbe=0.7;\n",
-      "Rc2=0.240;\n",
-      "Vor=-0.75;\n",
-      "Re=1.180;\n",
-      "iE=(Vor-Vbe-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' mA\\n')\n",
-      "iB=iE/(1.+b);\n",
-      "iB=iB*1000.;##micro A\n",
-      "print\"%s %.2f %s\"%('\\ninput base current= ',iB,' microA\\n')\n",
-      "R3=1.500;\n",
-      "i3=(Vor-V2)/R3;\n",
-      "print\"%s %.2f %s\"%('\\ni3= ',i3,' mA\\n')\n",
-      "iB=iB*0.001;##mA\n",
-      "N=(-(Vor+Vbe)*(1.+b)/(Rc2)-i3)/iB;\n",
-      "print\"%s %.2f %s\"%('\\nN\\n',N,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter current=  3.18  mA\n",
-        "\n",
-        "\n",
-        "input base current=  62.31  microA\n",
-        "\n",
-        "\n",
-        "i3=  2.97  mA\n",
-        "\n",
-        "\n",
-        "N\n",
-        " 122.90 \n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg1127"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 17.7\n",
-      "Vcc=1.7;\n",
-      "Re=0.008;##mohm\n",
-      "Rc=0.008;##mohm\n",
-      "Vy=0.4;\n",
-      "Vbe=0.7;\n",
-      "Vor=Vcc##logic 1\n",
-      "Vor=Vcc-Vy##logic 0\n",
-      "Vr=1.5;\n",
-      "iE=(Vr-Vbe)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' microA\\n')\n",
-      "iR=Vy/Rc;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum current in Rc = ',iR,' microA\\n')\n",
-      "iD=iE-iR;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent through the diode= ',iD,' microA\\n')\n",
-      "P=iE*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',P,' microW\\n')\n",
-      "Vv=1.7;\n",
-      "iE=(Vv-Vbe)/Re;\n",
-      "print\"%s %.2f %s\"%('\\niE = ',iE,' microA\\n')\n",
-      "P=iE*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation = ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter current=  100.00  microA\n",
-        "\n",
-        "\n",
-        "maximum current in Rc =  50.00  microA\n",
-        "\n",
-        "\n",
-        "current through the diode=  50.00  microA\n",
-        "\n",
-        "\n",
-        "power dissipation=  170.00  microW\n",
-        "\n",
-        "\n",
-        "iE =  125.00  microA\n",
-        "\n",
-        "\n",
-        "power dissipation =  212.50  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg1142"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.9\n",
-      "bf=25.;\n",
-      "b=bf;\n",
-      "br=0.1;\n",
-      "Vcc=5.;\n",
-      "R1=4.;\n",
-      "Vbc=0.7;\n",
-      "Vy=0.1;\n",
-      "Vx=0.1;\n",
-      "R2=1.6;\n",
-      "Vbe=0.8;\n",
-      "Rc=4.;\n",
-      "Vce=0.1;\n",
-      "vB2=Vx+Vce;\n",
-      "print\"%s %.2f %s\"%('\\nvB2= ',vB2,' V\\n')\n",
-      "vB1=Vx+Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nbase voltage= ',vB1,' V\\n')\n",
-      "i1=(Vcc-vB1)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i1= ',i1,' mA\\n')\n",
-      "vB1=Vbe+Vbe+Vbc;\n",
-      "print\"%s %.2f %s\"%('\\nvB1= ',vB1,' V\\n')\n",
-      "vC2=Vbe+Vce;\n",
-      "print\"%s %.2f %s\"%('\\ncollector voltage= ',vC2,' V\\n')\n",
-      "i1=(Vcc-vB1)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i1 = ',i1,' mA\\n')\n",
-      "iB2=(1.+2.*br)*i1;\n",
-      "print\"%s %.2f %s\"%('\\niB2= ',iB2,' mA\\n')\n",
-      "i2=(Vcc-vC2)/R2;\n",
-      "print\"%s %.2f %s\"%('\\ni2 = ',i2,' mA\\n')\n",
-      "iE2=i2+iB2;\n",
-      "print\"%s %.2f %s\"%('\\niE2= ',iE2,' mA\\n')\n",
-      "Rb=1.;\n",
-      "i4=Vbe/Rb;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent in the pull down resistor= ',i4,' mA\\n')\n",
-      "iBo=iE2-i4;\n",
-      "print\"%s %.2f %s\"%('\\nbase drive to the output transistor= ',iBo,' mA\\n')\n",
-      "i1=(Vcc-Vce)/Rc;\n",
-      "print\"%s %.2f %s\"%('\\ni1= ',i1,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "vB2=  0.20  V\n",
-        "\n",
-        "\n",
-        "base voltage=  0.90  V\n",
-        "\n",
-        "\n",
-        "current i1=  1.02  mA\n",
-        "\n",
-        "\n",
-        "vB1=  2.30  V\n",
-        "\n",
-        "\n",
-        "collector voltage=  0.90  V\n",
-        "\n",
-        "\n",
-        "current i1 =  0.68  mA\n",
-        "\n",
-        "\n",
-        "iB2=  0.81  mA\n",
-        "\n",
-        "\n",
-        "i2 =  2.56  mA\n",
-        "\n",
-        "\n",
-        "iE2=  3.37  mA\n",
-        "\n",
-        "\n",
-        "current in the pull down resistor=  0.80  mA\n",
-        "\n",
-        "\n",
-        "base drive to the output transistor=  2.57  mA\n",
-        "\n",
-        "\n",
-        "i1=  1.23  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg1150"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.11\n",
-      "b=25.;\n",
-      "iB=1.;\n",
-      "iC=2.;\n",
-      "ic=(iB+iC)/(1.+1./b);\n",
-      "print\"%s %.2f %s\"%('\\ninternal collector current= ',ic,' mA\\n',)\n",
-      "ib=ic/b;\n",
-      "print\"%s %.2f %s\"%('\\ninternal base current = ',ib,' mA\\n')\n",
-      "iD=iB-ib;\n",
-      "print\"%s %.2f %s\"%('\\nSchottky diode current= ',iD,' mA\\n')\n",
-      "iC=20.;\n",
-      "ic=(iB+iC)/(1.+1./b);\n",
-      "print\"%s %.2f %s\"%('\\ninternal collector current= ',ic,' mA\\n')\n",
-      "ib=ic/b;\n",
-      "print\"%s %.2f %s\"%('\\ninternal base current = ',ib,' mA\\n')\n",
-      "iD=iB-ib;\n",
-      "print\"%s %.2f %s\"%('\\nSchottky diode current= ',iD,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "internal collector current=  2.88  mA\n",
-        "\n",
-        "\n",
-        "internal base current =  0.12  mA\n",
-        "\n",
-        "\n",
-        "Schottky diode current=  0.88  mA\n",
-        "\n",
-        "\n",
-        "internal collector current=  20.19  mA\n",
-        "\n",
-        "\n",
-        "internal base current =  0.81  mA\n",
-        "\n",
-        "\n",
-        "Schottky diode current=  0.19  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg1154"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.12\n",
-      "Vy=0.3;\n",
-      "Vbe=0.7;\n",
-      "vx=0.4;\n",
-      "R2=8.;\n",
-      "Vce=0.4;\n",
-      "Vcc=5.;\n",
-      "b=25.;\n",
-      "Vce=0.4;\n",
-      "Vbe1=0.7;\n",
-      "Vbe2=0.7;\n",
-      "Vcc=5.;\n",
-      "R1=20.;\n",
-      "v1=Vce+Vy;\n",
-      "i1=(Vcc-v1)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ni1= ',i1,' mA\\n')\n",
-      "Pl=i1*(Vcc-vx);\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',Pl,' mW\\n')\n",
-      "v1=Vbe1+Vbe2;\n",
-      "print\"%s %.2f %s\"%('\\nv1= ',v1,' V\\n')\n",
-      "vC2=Vbe1+Vce;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage vC2  =',vC2,' V\\n')\n",
-      "i1=(Vcc-v1)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i1 = ',i1,' mA\\n')\n",
-      "i2=(Vcc-vC2)/R2;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i2 = ',i2,' mA\\n')\n",
-      "P=(i1+i2)*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation for high input condition= ',P,' mW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "i1=  0.21  mA\n",
-        "\n",
-        "\n",
-        "power dissipation=  0.99  mW\n",
-        "\n",
-        "\n",
-        "v1=  1.40  V\n",
-        "\n",
-        "\n",
-        "voltage vC2  = 1.10  V\n",
-        "\n",
-        "\n",
-        "current i1 =  0.18  mA\n",
-        "\n",
-        "\n",
-        "current i2 =  0.49  mA\n",
-        "\n",
-        "\n",
-        "power dissipation for high input condition=  3.34  mW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter17_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter17_1.ipynb
deleted file mode 100755
index 36f2555a..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter17_1.ipynb
+++ /dev/null
@@ -1,647 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:abf15ae78837b656bd4ca10fb9d29bc4f18126add8de13c4bce16bc14f199d7a"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter17-Bipolar Digital Circuits"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg1115"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.1\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "Rc1=1.;\n",
-      "Rc2=Rc1;\n",
-      "Rc=Rc1;\n",
-      "Re=2.150;\n",
-      "v2=0.;\n",
-      "##for v1=0\n",
-      "vE=-0.7;\n",
-      "iE=(vE-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' mA\\n')\n",
-      "iC=1.;\n",
-      "Vcc=5.;\n",
-      "vo1=Vcc-iC*Rc;\n",
-      "print\"%s %.2f %s\"%('\\nvo1=vo2= ',vo1,' V\\n')\n",
-      "##for v2=-1\n",
-      "vE=-0.7;\n",
-      "iE=2.;\n",
-      "iC2=2.;\n",
-      "vo1=5.;\n",
-      "vo2=Vcc-iC2*Rc;\n",
-      "print\"%s %.2f %s\"%('\\nvo2= ',vo2,' V\\n')\n",
-      "v1=1.;\n",
-      "Vbe=0.7;\n",
-      "vE=v1-Vbe;\n",
-      "iE=(vE-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current =',iE,' mA\\n')\n",
-      "iC1=iE;\n",
-      "vo1=Vcc-iC1*Rc;\n",
-      "print\"%s %.2f %s\"%('\\nvo1= ',vo1,' V\\n')\n",
-      "vo2=Vcc\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter current=  2.00  mA\n",
-        "\n",
-        "\n",
-        "vo1=vo2=  4.00  V\n",
-        "\n",
-        "\n",
-        "vo2=  3.00  V\n",
-        "\n",
-        "\n",
-        "emitter current = 2.47  mA\n",
-        "\n",
-        "\n",
-        "vo1=  2.53  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg1118"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.2\n",
-      "Vx=-0.7;\n",
-      "Vy=Vx;\n",
-      "Vbe=0.7;\n",
-      "V2=-5.2;\n",
-      "Re=1.180;\n",
-      "vE=Vx-Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nemitter voltage = ',vE,'  V\\n')\n",
-      "iE=(vE-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' mA\\n')\n",
-      "Icxy=iE;\n",
-      "vo1=-0.7;\n",
-      "Rc1=-vo1/Icxy;\n",
-      "print\"%s %.2f %s\"%('\\nRc1= ',Rc1,' KOhm\\n')\n",
-      "Vnor=vo1-Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nNOR output logic 0 value= ',Vnor,' V\\n')\n",
-      "Vr=(vo1+Vnor)/2.;\n",
-      "vE=Vr-Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nvE= ',vE,' V\\n')\n",
-      "iE=(vE-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\niE= ',iE,' mA\\n')\n",
-      "vo2=-0.7;\n",
-      "iC2=iE;\n",
-      "Rc2=-vo2/iC2;\n",
-      "print\"%s %.2f %s\"%('\\nRc2= ',Rc2,' KOhm\\n')\n",
-      "Vor=vo2-Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nOR logic 0 value is= ',Vor,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter voltage =  -1.40   V\n",
-        "\n",
-        "\n",
-        "emitter current=  3.22  mA\n",
-        "\n",
-        "\n",
-        "Rc1=  0.22  KOhm\n",
-        "\n",
-        "\n",
-        "NOR output logic 0 value=  -1.40  V\n",
-        "\n",
-        "\n",
-        "vE=  -1.75  V\n",
-        "\n",
-        "\n",
-        "iE=  2.92  mA\n",
-        "\n",
-        "\n",
-        "Rc2=  0.24  KOhm\n",
-        "\n",
-        "\n",
-        "OR logic 0 value is=  -1.40  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg1120"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.3\n",
-      "Vr=-1.05;\n",
-      "Vbe=0.7;\n",
-      "Vb5=Vr+Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nVb5 = ',Vb5,' V\\n')\n",
-      "R1=0.250;\n",
-      "i1=-Vb5/R1;\n",
-      "print\"%s %.2f %s\"%('\\ni1= ',i1,' mA\\n')\n",
-      "Vy=0.7;\n",
-      "V2=-5.2;\n",
-      "##let R1+R2=x\n",
-      "x=(-2.*Vy-V2)/i1;\n",
-      "R2=x-R1;\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n",
-      "iS=i1;\n",
-      "Rs=(Vr-V2)/iS;\n",
-      "print\"%s %.2f %s\"%('\\nRs= ',Rs,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vb5 =  -0.35  V\n",
-        "\n",
-        "\n",
-        "i1=  1.40  mA\n",
-        "\n",
-        "\n",
-        "R2=  2.46  KOhm\n",
-        "\n",
-        "\n",
-        "Rs=  2.96  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg1121"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.4\n",
-      "Vx=-0.7;\n",
-      "Vy=-0.7;\n",
-      "iCxy=3.22;##(mA)\n",
-      "iCR=0.;\n",
-      "i5=1.40;\n",
-      "i1=1.40;\n",
-      "Vor=-0.7;\n",
-      "R4=1.500;\n",
-      "Vnor=-1.4;\n",
-      "V2=-5.2;\n",
-      "R3=1.500;\n",
-      "i3=(Vor-V2)/R3;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i3= ',i3,' mA\\n')\n",
-      "i4=(Vnor-V2)/R4;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i4 = ',i4, 'mA')\n",
-      "P=(iCxy+iCR+i5+i1+i3+i4)*(0.-V2);\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',P,' mW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "current i3=  3.00  mA\n",
-        "\n",
-        "\n",
-        "current i4 =  2.53 mA\n",
-        "\n",
-        "power dissipation=  60.08  mW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg1122"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.5\n",
-      "b=50.;\n",
-      "V2=-5.2;\n",
-      "Vbe=0.7;\n",
-      "Rc2=0.240;\n",
-      "Vor=-0.75;\n",
-      "Re=1.180;\n",
-      "iE=(Vor-Vbe-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' mA\\n')\n",
-      "iB=iE/(1.+b);\n",
-      "iB=iB*1000.;##micro A\n",
-      "print\"%s %.2f %s\"%('\\ninput base current= ',iB,' microA\\n')\n",
-      "R3=1.500;\n",
-      "i3=(Vor-V2)/R3;\n",
-      "print\"%s %.2f %s\"%('\\ni3= ',i3,' mA\\n')\n",
-      "iB=iB*0.001;##mA\n",
-      "N=(-(Vor+Vbe)*(1.+b)/(Rc2)-i3)/iB;\n",
-      "print\"%s %.2f %s\"%('\\nN\\n',N,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter current=  3.18  mA\n",
-        "\n",
-        "\n",
-        "input base current=  62.31  microA\n",
-        "\n",
-        "\n",
-        "i3=  2.97  mA\n",
-        "\n",
-        "\n",
-        "N\n",
-        " 122.90 \n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg1127"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 17.7\n",
-      "Vcc=1.7;\n",
-      "Re=0.008;##mohm\n",
-      "Rc=0.008;##mohm\n",
-      "Vy=0.4;\n",
-      "Vbe=0.7;\n",
-      "Vor=Vcc##logic 1\n",
-      "Vor=Vcc-Vy##logic 0\n",
-      "Vr=1.5;\n",
-      "iE=(Vr-Vbe)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' microA\\n')\n",
-      "iR=Vy/Rc;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum current in Rc = ',iR,' microA\\n')\n",
-      "iD=iE-iR;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent through the diode= ',iD,' microA\\n')\n",
-      "P=iE*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',P,' microW\\n')\n",
-      "Vv=1.7;\n",
-      "iE=(Vv-Vbe)/Re;\n",
-      "print\"%s %.2f %s\"%('\\niE = ',iE,' microA\\n')\n",
-      "P=iE*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation = ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter current=  100.00  microA\n",
-        "\n",
-        "\n",
-        "maximum current in Rc =  50.00  microA\n",
-        "\n",
-        "\n",
-        "current through the diode=  50.00  microA\n",
-        "\n",
-        "\n",
-        "power dissipation=  170.00  microW\n",
-        "\n",
-        "\n",
-        "iE =  125.00  microA\n",
-        "\n",
-        "\n",
-        "power dissipation =  212.50  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg1142"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.9\n",
-      "bf=25.;\n",
-      "b=bf;\n",
-      "br=0.1;\n",
-      "Vcc=5.;\n",
-      "R1=4.;\n",
-      "Vbc=0.7;\n",
-      "Vy=0.1;\n",
-      "Vx=0.1;\n",
-      "R2=1.6;\n",
-      "Vbe=0.8;\n",
-      "Rc=4.;\n",
-      "Vce=0.1;\n",
-      "vB2=Vx+Vce;\n",
-      "print\"%s %.2f %s\"%('\\nvB2= ',vB2,' V\\n')\n",
-      "vB1=Vx+Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nbase voltage= ',vB1,' V\\n')\n",
-      "i1=(Vcc-vB1)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i1= ',i1,' mA\\n')\n",
-      "vB1=Vbe+Vbe+Vbc;\n",
-      "print\"%s %.2f %s\"%('\\nvB1= ',vB1,' V\\n')\n",
-      "vC2=Vbe+Vce;\n",
-      "print\"%s %.2f %s\"%('\\ncollector voltage= ',vC2,' V\\n')\n",
-      "i1=(Vcc-vB1)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i1 = ',i1,' mA\\n')\n",
-      "iB2=(1.+2.*br)*i1;\n",
-      "print\"%s %.2f %s\"%('\\niB2= ',iB2,' mA\\n')\n",
-      "i2=(Vcc-vC2)/R2;\n",
-      "print\"%s %.2f %s\"%('\\ni2 = ',i2,' mA\\n')\n",
-      "iE2=i2+iB2;\n",
-      "print\"%s %.2f %s\"%('\\niE2= ',iE2,' mA\\n')\n",
-      "Rb=1.;\n",
-      "i4=Vbe/Rb;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent in the pull down resistor= ',i4,' mA\\n')\n",
-      "iBo=iE2-i4;\n",
-      "print\"%s %.2f %s\"%('\\nbase drive to the output transistor= ',iBo,' mA\\n')\n",
-      "i1=(Vcc-Vce)/Rc;\n",
-      "print\"%s %.2f %s\"%('\\ni1= ',i1,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "vB2=  0.20  V\n",
-        "\n",
-        "\n",
-        "base voltage=  0.90  V\n",
-        "\n",
-        "\n",
-        "current i1=  1.02  mA\n",
-        "\n",
-        "\n",
-        "vB1=  2.30  V\n",
-        "\n",
-        "\n",
-        "collector voltage=  0.90  V\n",
-        "\n",
-        "\n",
-        "current i1 =  0.68  mA\n",
-        "\n",
-        "\n",
-        "iB2=  0.81  mA\n",
-        "\n",
-        "\n",
-        "i2 =  2.56  mA\n",
-        "\n",
-        "\n",
-        "iE2=  3.37  mA\n",
-        "\n",
-        "\n",
-        "current in the pull down resistor=  0.80  mA\n",
-        "\n",
-        "\n",
-        "base drive to the output transistor=  2.57  mA\n",
-        "\n",
-        "\n",
-        "i1=  1.23  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg1150"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.11\n",
-      "b=25.;\n",
-      "iB=1.;\n",
-      "iC=2.;\n",
-      "ic=(iB+iC)/(1.+1./b);\n",
-      "print\"%s %.2f %s\"%('\\ninternal collector current= ',ic,' mA\\n',)\n",
-      "ib=ic/b;\n",
-      "print\"%s %.2f %s\"%('\\ninternal base current = ',ib,' mA\\n')\n",
-      "iD=iB-ib;\n",
-      "print\"%s %.2f %s\"%('\\nSchottky diode current= ',iD,' mA\\n')\n",
-      "iC=20.;\n",
-      "ic=(iB+iC)/(1.+1./b);\n",
-      "print\"%s %.2f %s\"%('\\ninternal collector current= ',ic,' mA\\n')\n",
-      "ib=ic/b;\n",
-      "print\"%s %.2f %s\"%('\\ninternal base current = ',ib,' mA\\n')\n",
-      "iD=iB-ib;\n",
-      "print\"%s %.2f %s\"%('\\nSchottky diode current= ',iD,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "internal collector current=  2.88  mA\n",
-        "\n",
-        "\n",
-        "internal base current =  0.12  mA\n",
-        "\n",
-        "\n",
-        "Schottky diode current=  0.88  mA\n",
-        "\n",
-        "\n",
-        "internal collector current=  20.19  mA\n",
-        "\n",
-        "\n",
-        "internal base current =  0.81  mA\n",
-        "\n",
-        "\n",
-        "Schottky diode current=  0.19  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg1154"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.12\n",
-      "Vy=0.3;\n",
-      "Vbe=0.7;\n",
-      "vx=0.4;\n",
-      "R2=8.;\n",
-      "Vce=0.4;\n",
-      "Vcc=5.;\n",
-      "b=25.;\n",
-      "Vce=0.4;\n",
-      "Vbe1=0.7;\n",
-      "Vbe2=0.7;\n",
-      "Vcc=5.;\n",
-      "R1=20.;\n",
-      "v1=Vce+Vy;\n",
-      "i1=(Vcc-v1)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ni1= ',i1,' mA\\n')\n",
-      "Pl=i1*(Vcc-vx);\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',Pl,' mW\\n')\n",
-      "v1=Vbe1+Vbe2;\n",
-      "print\"%s %.2f %s\"%('\\nv1= ',v1,' V\\n')\n",
-      "vC2=Vbe1+Vce;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage vC2  =',vC2,' V\\n')\n",
-      "i1=(Vcc-v1)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i1 = ',i1,' mA\\n')\n",
-      "i2=(Vcc-vC2)/R2;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i2 = ',i2,' mA\\n')\n",
-      "P=(i1+i2)*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation for high input condition= ',P,' mW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "i1=  0.21  mA\n",
-        "\n",
-        "\n",
-        "power dissipation=  0.99  mW\n",
-        "\n",
-        "\n",
-        "v1=  1.40  V\n",
-        "\n",
-        "\n",
-        "voltage vC2  = 1.10  V\n",
-        "\n",
-        "\n",
-        "current i1 =  0.18  mA\n",
-        "\n",
-        "\n",
-        "current i2 =  0.49  mA\n",
-        "\n",
-        "\n",
-        "power dissipation for high input condition=  3.34  mW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter17_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter17_1_1.ipynb
deleted file mode 100755
index 0913e184..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter17_1_1.ipynb
+++ /dev/null
@@ -1,647 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:abb54176eeb369f0f245b707b98b6a093b5c09d2bb0c269e911dfcaf8a6dfa9d"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter17-Bipolar Digital Circuits"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg1115"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.1\n",
-      "V1=5.;\n",
-      "V2=-5.;\n",
-      "Rc1=1.;\n",
-      "Rc2=Rc1;\n",
-      "Rc=Rc1;\n",
-      "Re=2.150;\n",
-      "v2=0.;\n",
-      "##for v1=0\n",
-      "vE=-0.7;\n",
-      "iE=(vE-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' mA\\n')\n",
-      "iC=1.;\n",
-      "Vcc=5.;\n",
-      "vo1=Vcc-iC*Rc;\n",
-      "print\"%s %.2f %s\"%('\\nvo1=vo2= ',vo1,' V\\n')\n",
-      "##for v2=-1\n",
-      "vE=-0.7;\n",
-      "iE=2.;\n",
-      "iC2=2.;\n",
-      "vo1=5.;\n",
-      "vo2=Vcc-iC2*Rc;\n",
-      "print\"%s %.2f %s\"%('\\nvo2= ',vo2,' V\\n')\n",
-      "v1=1.;\n",
-      "Vbe=0.7;\n",
-      "vE=v1-Vbe;\n",
-      "iE=(vE-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current =',iE,' mA\\n')\n",
-      "iC1=iE;\n",
-      "vo1=Vcc-iC1*Rc;\n",
-      "print\"%s %.2f %s\"%('\\nvo1= ',vo1,' V\\n')\n",
-      "vo2=Vcc\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter current=  2.00  mA\n",
-        "\n",
-        "\n",
-        "vo1=vo2=  4.00  V\n",
-        "\n",
-        "\n",
-        "vo2=  3.00  V\n",
-        "\n",
-        "\n",
-        "emitter current = 2.47  mA\n",
-        "\n",
-        "\n",
-        "vo1=  2.53  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg1118"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.2\n",
-      "Vx=-0.7;\n",
-      "Vy=Vx;\n",
-      "Vbe=0.7;\n",
-      "V2=-5.2;\n",
-      "Re=1.180;\n",
-      "vE=Vx-Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nemitter voltage = ',vE,'  V\\n')\n",
-      "iE=(vE-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' mA\\n')\n",
-      "Icxy=iE;\n",
-      "vo1=-0.7;\n",
-      "Rc1=-vo1/Icxy;\n",
-      "print\"%s %.2f %s\"%('\\nRc1= ',Rc1,' KOhm\\n')\n",
-      "Vnor=vo1-Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nNOR output logic 0 value= ',Vnor,' V\\n')\n",
-      "Vr=(vo1+Vnor)/2.;\n",
-      "vE=Vr-Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nvE= ',vE,' V\\n')\n",
-      "iE=(vE-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\niE= ',iE,' mA\\n')\n",
-      "vo2=-0.7;\n",
-      "iC2=iE;\n",
-      "Rc2=-vo2/iC2;\n",
-      "print\"%s %.2f %s\"%('\\nRc2= ',Rc2,' KOhm\\n')\n",
-      "Vor=vo2-Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nOR logic 0 value is= ',Vor,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter voltage =  -1.40   V\n",
-        "\n",
-        "\n",
-        "emitter current=  3.22  mA\n",
-        "\n",
-        "\n",
-        "Rc1=  0.22  KOhm\n",
-        "\n",
-        "\n",
-        "NOR output logic 0 value=  -1.40  V\n",
-        "\n",
-        "\n",
-        "vE=  -1.75  V\n",
-        "\n",
-        "\n",
-        "iE=  2.92  mA\n",
-        "\n",
-        "\n",
-        "Rc2=  0.24  KOhm\n",
-        "\n",
-        "\n",
-        "OR logic 0 value is=  -1.40  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg1120"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.3\n",
-      "Vr=-1.05;\n",
-      "Vbe=0.7;\n",
-      "Vb5=Vr+Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nVb5 = ',Vb5,' V\\n')\n",
-      "R1=0.250;\n",
-      "i1=-Vb5/R1;\n",
-      "print\"%s %.2f %s\"%('\\ni1= ',i1,' mA\\n')\n",
-      "Vy=0.7;\n",
-      "V2=-5.2;\n",
-      "##let R1+R2=x\n",
-      "x=(-2.*Vy-V2)/i1;\n",
-      "R2=x-R1;\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n",
-      "iS=i1;\n",
-      "Rs=(Vr-V2)/iS;\n",
-      "print\"%s %.2f %s\"%('\\nRs= ',Rs,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vb5 =  -0.35  V\n",
-        "\n",
-        "\n",
-        "i1=  1.40  mA\n",
-        "\n",
-        "\n",
-        "R2=  2.46  KOhm\n",
-        "\n",
-        "\n",
-        "Rs=  2.96  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg1121"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.4\n",
-      "Vx=-0.7;\n",
-      "Vy=-0.7;\n",
-      "iCxy=3.22;##(mA)\n",
-      "iCR=0.;\n",
-      "i5=1.40;\n",
-      "i1=1.40;\n",
-      "Vor=-0.7;\n",
-      "R4=1.500;\n",
-      "Vnor=-1.4;\n",
-      "V2=-5.2;\n",
-      "R3=1.500;\n",
-      "i3=(Vor-V2)/R3;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i3= ',i3,' mA\\n')\n",
-      "i4=(Vnor-V2)/R4;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i4 = ',i4, 'mA')\n",
-      "P=(iCxy+iCR+i5+i1+i3+i4)*(0.-V2);\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',P,' mW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "current i3=  3.00  mA\n",
-        "\n",
-        "\n",
-        "current i4 =  2.53 mA\n",
-        "\n",
-        "power dissipation=  60.08  mW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg1122"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.5\n",
-      "b=50.;\n",
-      "V2=-5.2;\n",
-      "Vbe=0.7;\n",
-      "Rc2=0.240;\n",
-      "Vor=-0.75;\n",
-      "Re=1.180;\n",
-      "iE=(Vor-Vbe-V2)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' mA\\n')\n",
-      "iB=iE/(1.+b);\n",
-      "iB=iB*1000.;##micro A\n",
-      "print\"%s %.2f %s\"%('\\ninput base current= ',iB,' microA\\n')\n",
-      "R3=1.500;\n",
-      "i3=(Vor-V2)/R3;\n",
-      "print\"%s %.2f %s\"%('\\ni3= ',i3,' mA\\n')\n",
-      "iB=iB*0.001;##mA\n",
-      "N=(-(Vor+Vbe)*(1.+b)/(Rc2)-i3)/iB;\n",
-      "print\"%s %.2f %s\"%('\\nN\\n',N,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter current=  3.18  mA\n",
-        "\n",
-        "\n",
-        "input base current=  62.31  microA\n",
-        "\n",
-        "\n",
-        "i3=  2.97  mA\n",
-        "\n",
-        "\n",
-        "N\n",
-        " 122.90 \n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg1127"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 17.7\n",
-      "Vcc=1.7;\n",
-      "Re=0.008;##mohm\n",
-      "Rc=0.008;##mohm\n",
-      "Vy=0.4;\n",
-      "Vbe=0.7;\n",
-      "Vor=Vcc##logic 1\n",
-      "Vor=Vcc-Vy##logic 0\n",
-      "Vr=1.5;\n",
-      "iE=(Vr-Vbe)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' microA\\n')\n",
-      "iR=Vy/Rc;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum current in Rc = ',iR,' microA\\n')\n",
-      "iD=iE-iR;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent through the diode= ',iD,' microA\\n')\n",
-      "P=iE*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',P,' microW\\n')\n",
-      "Vv=1.7;\n",
-      "iE=(Vv-Vbe)/Re;\n",
-      "print\"%s %.2f %s\"%('\\niE = ',iE,' microA\\n')\n",
-      "P=iE*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation = ',P,' microW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter current=  100.00  microA\n",
-        "\n",
-        "\n",
-        "maximum current in Rc =  50.00  microA\n",
-        "\n",
-        "\n",
-        "current through the diode=  50.00  microA\n",
-        "\n",
-        "\n",
-        "power dissipation=  170.00  microW\n",
-        "\n",
-        "\n",
-        "iE =  125.00  microA\n",
-        "\n",
-        "\n",
-        "power dissipation =  212.50  microW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg1142"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.9\n",
-      "bf=25.;\n",
-      "b=bf;\n",
-      "br=0.1;\n",
-      "Vcc=5.;\n",
-      "R1=4.;\n",
-      "Vbc=0.7;\n",
-      "Vy=0.1;\n",
-      "Vx=0.1;\n",
-      "R2=1.6;\n",
-      "Vbe=0.8;\n",
-      "Rc=4.;\n",
-      "Vce=0.1;\n",
-      "vB2=Vx+Vce;\n",
-      "print\"%s %.2f %s\"%('\\nvB2= ',vB2,' V\\n')\n",
-      "vB1=Vx+Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nbase voltage= ',vB1,' V\\n')\n",
-      "i1=(Vcc-vB1)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i1= ',i1,' mA\\n')\n",
-      "vB1=Vbe+Vbe+Vbc;\n",
-      "print\"%s %.2f %s\"%('\\nvB1= ',vB1,' V\\n')\n",
-      "vC2=Vbe+Vce;\n",
-      "print\"%s %.2f %s\"%('\\ncollector voltage= ',vC2,' V\\n')\n",
-      "i1=(Vcc-vB1)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i1 = ',i1,' mA\\n')\n",
-      "iB2=(1.+2.*br)*i1;\n",
-      "print\"%s %.2f %s\"%('\\niB2= ',iB2,' mA\\n')\n",
-      "i2=(Vcc-vC2)/R2;\n",
-      "print\"%s %.2f %s\"%('\\ni2 = ',i2,' mA\\n')\n",
-      "iE2=i2+iB2;\n",
-      "print\"%s %.2f %s\"%('\\niE2= ',iE2,' mA\\n')\n",
-      "Rb=1.;\n",
-      "i4=Vbe/Rb;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent in the pull down resistor= ',i4,' mA\\n')\n",
-      "iBo=iE2-i4;\n",
-      "print\"%s %.2f %s\"%('\\nbase drive to the output transistor= ',iBo,' mA\\n')\n",
-      "i1=(Vcc-Vce)/Rc;\n",
-      "print\"%s %.2f %s\"%('\\ni1= ',i1,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "vB2=  0.20  V\n",
-        "\n",
-        "\n",
-        "base voltage=  0.90  V\n",
-        "\n",
-        "\n",
-        "current i1=  1.02  mA\n",
-        "\n",
-        "\n",
-        "vB1=  2.30  V\n",
-        "\n",
-        "\n",
-        "collector voltage=  0.90  V\n",
-        "\n",
-        "\n",
-        "current i1 =  0.68  mA\n",
-        "\n",
-        "\n",
-        "iB2=  0.81  mA\n",
-        "\n",
-        "\n",
-        "i2 =  2.56  mA\n",
-        "\n",
-        "\n",
-        "iE2=  3.37  mA\n",
-        "\n",
-        "\n",
-        "current in the pull down resistor=  0.80  mA\n",
-        "\n",
-        "\n",
-        "base drive to the output transistor=  2.57  mA\n",
-        "\n",
-        "\n",
-        "i1=  1.23  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg1150"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.11\n",
-      "b=25.;\n",
-      "iB=1.;\n",
-      "iC=2.;\n",
-      "ic=(iB+iC)/(1.+1./b);\n",
-      "print\"%s %.2f %s\"%('\\ninternal collector current= ',ic,' mA\\n',)\n",
-      "ib=ic/b;\n",
-      "print\"%s %.2f %s\"%('\\ninternal base current = ',ib,' mA\\n')\n",
-      "iD=iB-ib;\n",
-      "print\"%s %.2f %s\"%('\\nSchottky diode current= ',iD,' mA\\n')\n",
-      "iC=20.;\n",
-      "ic=(iB+iC)/(1.+1./b);\n",
-      "print\"%s %.2f %s\"%('\\ninternal collector current= ',ic,' mA\\n')\n",
-      "ib=ic/b;\n",
-      "print\"%s %.2f %s\"%('\\ninternal base current = ',ib,' mA\\n')\n",
-      "iD=iB-ib;\n",
-      "print\"%s %.2f %s\"%('\\nSchottky diode current= ',iD,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "internal collector current=  2.88  mA\n",
-        "\n",
-        "\n",
-        "internal base current =  0.12  mA\n",
-        "\n",
-        "\n",
-        "Schottky diode current=  0.88  mA\n",
-        "\n",
-        "\n",
-        "internal collector current=  20.19  mA\n",
-        "\n",
-        "\n",
-        "internal base current =  0.81  mA\n",
-        "\n",
-        "\n",
-        "Schottky diode current=  0.19  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg1154"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 17.12\n",
-      "Vy=0.3;\n",
-      "Vbe=0.7;\n",
-      "vx=0.4;\n",
-      "R2=8.;\n",
-      "Vce=0.4;\n",
-      "Vcc=5.;\n",
-      "b=25.;\n",
-      "Vce=0.4;\n",
-      "Vbe1=0.7;\n",
-      "Vbe2=0.7;\n",
-      "Vcc=5.;\n",
-      "R1=20.;\n",
-      "v1=Vce+Vy;\n",
-      "i1=(Vcc-v1)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ni1= ',i1,' mA\\n')\n",
-      "Pl=i1*(Vcc-vx);\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',Pl,' mW\\n')\n",
-      "v1=Vbe1+Vbe2;\n",
-      "print\"%s %.2f %s\"%('\\nv1= ',v1,' V\\n')\n",
-      "vC2=Vbe1+Vce;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage vC2  =',vC2,' V\\n')\n",
-      "i1=(Vcc-v1)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i1 = ',i1,' mA\\n')\n",
-      "i2=(Vcc-vC2)/R2;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent i2 = ',i2,' mA\\n')\n",
-      "P=(i1+i2)*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation for high input condition= ',P,' mW\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "i1=  0.21  mA\n",
-        "\n",
-        "\n",
-        "power dissipation=  0.99  mW\n",
-        "\n",
-        "\n",
-        "v1=  1.40  V\n",
-        "\n",
-        "\n",
-        "voltage vC2  = 1.10  V\n",
-        "\n",
-        "\n",
-        "current i1 =  0.18  mA\n",
-        "\n",
-        "\n",
-        "current i2 =  0.49  mA\n",
-        "\n",
-        "\n",
-        "power dissipation for high input condition=  3.34  mW\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter1_1.ipynb
deleted file mode 100755
index 5dae57eb..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter1_1.ipynb
+++ /dev/null
@@ -1,474 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:ee4acc9fe033182686c067f9b51c12e7f872f20a61bb079c1ca29002499b1ddd"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter1-Semiconductor materials and diodes"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg6"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.1\n",
-      "T=300.;##((K)temperature)\n",
-      "##for silicon\n",
-      "B=5.23*10**(15);##Constant (per centimeter cube degree kelvin)\n",
-      "Eg=1.1;##bandgap energy in electrovolt(eV)\n",
-      "k=86.*10**(-6);##Boltzmann's constant(eV per degree kelvin)\n",
-      "n_i=B*T**(3/2.)*math.exp(-Eg/(2.*k*T));##intrinsic carrier concentration\n",
-      "print\"%s %.2f %s\"%('intrinsic carrier concentration= ',n_i,' cm^-3');\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "intrinsic carrier concentration=  14995738948.72  cm^-3\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg8"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import math\n",
-      "\n",
-      "#calculate the\n",
-      "\n",
-      "##Example 1.2 \n",
-      "T=300.;##(K)Given Temperature\n",
-      "Nd=10**16;##(cm^-3)Donor concentration\n",
-      "n_i=1.5*10**10;##(cm^-3)intrinsic carrier concentration\n",
-      "##since Nd>>n_i\n",
-      "n_o=10**16;##(cm^-3)electron concentration\n",
-      "##by using formula ::n_i^2=n_o*p_o\n",
-      "p_o=(n_i)**2/Nd;##hole concentration\n",
-      "print\"%s %.2e %s\"%('\\nelectron concentration= ',n_o,' cm^-3');\n",
-      "print\"%s %.2e %s\"%('\\nhole concentration = ',p_o,' cm^-3');\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "electron concentration=  1.00e+16  cm^-3\n",
-        "\n",
-        "hole concentration =  2.25e+04  cm^-3\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg13"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example1.3\n",
-      "T=300;##(K)Given Temperature\n",
-      "Na=10**16;##(cm^-3)Acceptor concentration in p region\n",
-      "Nd=10**17;##(cm^-3)Donor concentration in n region\n",
-      "n_i=1.5*10**10;##(cm^-3)intrinsic carrier concentration\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "##built-in potential\n",
-      "V_bi=V_T*math.log(Na*Nd/(n_i)**2);\n",
-      "print\"%s %.2f %s\"%('\\nthe built-in potential= ',V_bi,'V')\n",
-      "\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the built-in potential=  0.76 V\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg15"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.4\n",
-      "T=300.;##(K)Given Temperature\n",
-      "Na=10**16;##(cm**-3)Acceptor concentration in p region\n",
-      "Nd=10**15;##(cm**-3)Donor concentration in n region\n",
-      "n_i=1.5*10**10;##(cm**-3)intrinsic carrier concentration\n",
-      "C_jo=0.5;##(pF)junction capacitance at zero applied voltage\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "##built-in potential\n",
-      "V_bi=V_T*math.log(Na*Nd/(n_i)**2);\n",
-      "print\"%s %.2f %s\"%(\"the built-in potential(V)\",V_bi,\"\")\n",
-      "##the junction capacitance for\n",
-      "V_R=1.;##(V)reverse bias voltage\n",
-      "Cj=C_jo*(1.+V_R/V_bi)**(-1/2.);\n",
-      "print\"%s %.2f %s\"%('\\nthe junction capacitance for V_R=1V= ',Cj,' pF\\n')\n",
-      "V_R=5.;##(V)reverse bias voltage\n",
-      "Cj=C_jo*(1.+V_R/V_bi)**(-1/2.);\n",
-      "print\"%s %.2f %s\"%('\\nthe junction capacitance for V_R=5V = ',Cj,' pF')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "the built-in potential(V) 0.64 \n",
-        "\n",
-        "the junction capacitance for V_R=1V=  0.31  pF\n",
-        "\n",
-        "\n",
-        "the junction capacitance for V_R=5V =  0.17  pF\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg17"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.5\n",
-      "T=300.;##(K)Given Temperature\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "Is=10**-11;##(mA)reverse bias saturation current\n",
-      "n=1.;##emission coefficient\n",
-      "v_D=+0.7;##(V)applied voltage\n",
-      "##pn junction is forward biased\n",
-      "i_D=Is*(math.exp(v_D/V_T)-1.);##diode current\n",
-      "print\"%s %.2f %s\"%('\\ndiode current= ',i_D,' mA\\n')\n",
-      "v_D=-0.7;##(V)pn junction is reverse biased\n",
-      "Is=10**-14##A;\n",
-      "i_D=Is*(math.exp(v_D/V_T)-1);##diode current\n",
-      "print\"%s %.2e %s\"%('\\ndiode current= ',i_D,' A')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "diode current=  4.93  mA\n",
-        "\n",
-        "\n",
-        "diode current=  -1.00e-14  A\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg25"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.6\n",
-      "Is=10**-13;##(A)reverse saturation current\n",
-      "V_PS=5.;##(V)applied voltage\n",
-      "R=2;##(KOhm)Resistance in circuit\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "##V_PS=Is*R*(exp(V_D/V_T)-1)+V_D\n",
-      "##5=(10^-13)*(2000)*(exp(V_D/V_T)-1)+V_D\n",
-      "##let right side of equation be x=(10^-13)*(2000)*(exp(V_D/V_T)-1)+V_D\n",
-      "V_D=0.6;##(V)\n",
-      "x=(10**-13)*(2000.)*(math.exp(V_D/V_T)-1.)+V_D\n",
-      "##so the equation is not balanced\n",
-      "V_D=0.65;##(V)\n",
-      "x=(10**-13)*(2000.)*(math.exp(V_D/V_T)-1.)+V_D\n",
-      "##again equation is not balanced .solution for V_D is between 0.6V and 0.65V\n",
-      "V_D=0.619;##(V)\n",
-      "x=(10**-13)*(2000.)*(math.exp(V_D/V_T)-1.)+V_D\n",
-      "##essentially equal to the value of the left side of the equation i.e 5V\n",
-      "print\"%s %.2f %s\"%('\\ndiode voltage= ',V_D,' V')\n",
-      "I_D=(V_PS-V_D)/R;##(A)diode current\n",
-      "print\"%s %.2f %s\"%('\\nthe diode current= ',I_D,' mA')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "diode voltage=  0.62  V\n",
-        "\n",
-        "the diode current=  2.19  mA\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.7\n",
-      "##piecewise linear diode parameters\n",
-      "V_Y=0.6;##(V)\n",
-      "r_f=0.010;##(KOhm)\n",
-      "V_PS=5.;##(V)applied voltage\n",
-      "R=2.;##(KOhm)Resistance in circuit\n",
-      "I_D=(V_PS-V_Y)/(R+r_f);##(A)diode current\n",
-      "print\"%s %.2f %s\"%('\\nthe diode current= ',I_D,' mA\\n')\n",
-      "V_D=V_Y+I_D*r_f;##(V)diode voltage\n",
-      "print\"%s %.2f %s\"%('\\ndiode voltage= ',V_D,' V')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the diode current=  2.19  mA\n",
-        "\n",
-        "\n",
-        "diode voltage=  0.62  V\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg33"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.9 \n",
-      "##circuit and diode parameters \n",
-      "V_PS=5.;##(V)\n",
-      "R=5;##(KOhm)\n",
-      "V_Y=0.6;##(V)\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "v_i=0.1##*sin(wt)Volt\n",
-      "##dc analysis\n",
-      "I_DQ=(V_PS-V_Y)/R;\n",
-      "print\"%s %.2f %s\"%('\\ndc quiescent current= ',I_DQ,' mA\\n')\n",
-      "V_O=I_DQ*R;\n",
-      "print\"%s %.2f %s\"%('\\ndc output voltage= ',V_O,' V\\n')\n",
-      "##ac analysis\n",
-      "V_PS=0.;\n",
-      "##Kirchhoff voltage law equation becomes\n",
-      "##v_i=i_d*r_d+i_d*R\n",
-      "r_d=V_T/I_DQ##(Ohm)small signal diode diffusion resistance\n",
-      "i_d=v_i/(r_d+R);##ac diode current\n",
-      "print\"%s %.2f %s\"%('\\nac diode current= ',i_d,'sin(wt) A\\n')\n",
-      "\n",
-      "v_o=i_d*R;##ac output voltage\n",
-      "print\"%s %.2f %s\"%('\\nac output voltage= ',v_o,'sin(wt) V')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "dc quiescent current=  0.88  mA\n",
-        "\n",
-        "\n",
-        "dc output voltage=  4.40  V\n",
-        "\n",
-        "\n",
-        "ac diode current=  0.02 sin(wt) A\n",
-        "\n",
-        "\n",
-        "ac output voltage=  0.10 sin(wt) V\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg38"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.10\n",
-      "V_Y=0.7;##(V)cut in voltage for pn junction\n",
-      "r_f=0.;\n",
-      "V_PS=4;##(V)\n",
-      "R1=4.\n",
-      "R2=4.##(KOhm) from given circuit\n",
-      "I1=(V_PS-V_Y)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent through pn junction diode= ',I1,' mA\\n')\n",
-      "V_Y=0.3;##(V)cut in voltage for Schottky diode\n",
-      "I2=(V_PS-V_Y)/R2;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent through Schottky diode= ',I2,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "current through pn junction diode=  0.82  mA\n",
-        "\n",
-        "\n",
-        "current through Schottky diode=  0.93  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg40"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.11 \n",
-      "V_Z=5.6;##(V)Zener diode breakdown voltage\n",
-      "r_z=0.;##(Ohm)Zener resistance\n",
-      "I=3.;##(mA)current in the diode\n",
-      "V_PS=10.;##(V)\n",
-      "##I=(V_PS-V_Z)/R\n",
-      "R=(V_PS-V_Z)/I;\n",
-      "print\"%s %.2f %s\"%('\\nresistance= ',R,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "resistance=  1.47  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter1_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter1_1_1.ipynb
deleted file mode 100755
index d1c77068..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter1_1_1.ipynb
+++ /dev/null
@@ -1,474 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:12fda3be337124becb50b8ef7de2608c3b358deb143d70552beef4ab1e72fe80"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter1-Semiconductor materials and diodes"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg6"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.1\n",
-      "T=300.;##((K)temperature)\n",
-      "##for silicon\n",
-      "B=5.23*10**(15);##Constant (per centimeter cube degree kelvin)\n",
-      "Eg=1.1;##bandgap energy in electrovolt(eV)\n",
-      "k=86.*10**(-6);##Boltzmann's constant(eV per degree kelvin)\n",
-      "n_i=B*T**(3/2.)*math.exp(-Eg/(2.*k*T));##intrinsic carrier concentration\n",
-      "print\"%s %.2f %s\"%('intrinsic carrier concentration= ',n_i,' cm^-3');\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "intrinsic carrier concentration=  14995738948.72  cm^-3\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg8"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import math\n",
-      "\n",
-      "#calculate the\n",
-      "\n",
-      "##Example 1.2 \n",
-      "T=300.;##(K)Given Temperature\n",
-      "Nd=10**16;##(cm^-3)Donor concentration\n",
-      "n_i=1.5*10**10;##(cm^-3)intrinsic carrier concentration\n",
-      "##since Nd>>n_i\n",
-      "n_o=10**16;##(cm^-3)electron concentration\n",
-      "##by using formula ::n_i^2=n_o*p_o\n",
-      "p_o=(n_i)**2/Nd;##hole concentration\n",
-      "print\"%s %.2e %s\"%('\\nelectron concentration= ',n_o,' cm^-3');\n",
-      "print\"%s %.2e %s\"%('\\nhole concentration = ',p_o,' cm^-3');\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "electron concentration=  1.00e+16  cm^-3\n",
-        "\n",
-        "hole concentration =  2.25e+04  cm^-3\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg13"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example1.3\n",
-      "T=300;##(K)Given Temperature\n",
-      "Na=10**16;##(cm^-3)Acceptor concentration in p region\n",
-      "Nd=10**17;##(cm^-3)Donor concentration in n region\n",
-      "n_i=1.5*10**10;##(cm^-3)intrinsic carrier concentration\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "##built-in potential\n",
-      "V_bi=V_T*math.log(Na*Nd/(n_i)**2);\n",
-      "print\"%s %.2f %s\"%('\\nthe built-in potential= ',V_bi,'V')\n",
-      "\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the built-in potential=  0.76 V\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg15"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.4\n",
-      "T=300.;##(K)Given Temperature\n",
-      "Na=10**16;##(cm**-3)Acceptor concentration in p region\n",
-      "Nd=10**15;##(cm**-3)Donor concentration in n region\n",
-      "n_i=1.5*10**10;##(cm**-3)intrinsic carrier concentration\n",
-      "C_jo=0.5;##(pF)junction capacitance at zero applied voltage\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "##built-in potential\n",
-      "V_bi=V_T*math.log(Na*Nd/(n_i)**2);\n",
-      "print\"%s %.2f %s\"%(\"the built-in potential(V)\",V_bi,\"\")\n",
-      "##the junction capacitance for\n",
-      "V_R=1.;##(V)reverse bias voltage\n",
-      "Cj=C_jo*(1.+V_R/V_bi)**(-1/2.);\n",
-      "print\"%s %.2f %s\"%('\\nthe junction capacitance for V_R=1V= ',Cj,' pF\\n')\n",
-      "V_R=5.;##(V)reverse bias voltage\n",
-      "Cj=C_jo*(1.+V_R/V_bi)**(-1/2.);\n",
-      "print\"%s %.2f %s\"%('\\nthe junction capacitance for V_R=5V = ',Cj,' pF')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "the built-in potential(V) 0.64 \n",
-        "\n",
-        "the junction capacitance for V_R=1V=  0.31  pF\n",
-        "\n",
-        "\n",
-        "the junction capacitance for V_R=5V =  0.17  pF\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg17"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.5\n",
-      "T=300.;##(K)Given Temperature\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "Is=10**-11;##(mA)reverse bias saturation current\n",
-      "n=1.;##emission coefficient\n",
-      "v_D=+0.7;##(V)applied voltage\n",
-      "##pn junction is forward biased\n",
-      "i_D=Is*(math.exp(v_D/V_T)-1.);##diode current\n",
-      "print\"%s %.2f %s\"%('\\ndiode current= ',i_D,' mA\\n')\n",
-      "v_D=-0.7;##(V)pn junction is reverse biased\n",
-      "Is=10**-14##A;\n",
-      "i_D=Is*(math.exp(v_D/V_T)-1);##diode current\n",
-      "print\"%s %.2e %s\"%('\\ndiode current= ',i_D,' A')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "diode current=  4.93  mA\n",
-        "\n",
-        "\n",
-        "diode current=  -1.00e-14  A\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg25"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.6\n",
-      "Is=10**-13;##(A)reverse saturation current\n",
-      "V_PS=5.;##(V)applied voltage\n",
-      "R=2;##(KOhm)Resistance in circuit\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "##V_PS=Is*R*(exp(V_D/V_T)-1)+V_D\n",
-      "##5=(10^-13)*(2000)*(exp(V_D/V_T)-1)+V_D\n",
-      "##let right side of equation be x=(10^-13)*(2000)*(exp(V_D/V_T)-1)+V_D\n",
-      "V_D=0.6;##(V)\n",
-      "x=(10**-13)*(2000.)*(math.exp(V_D/V_T)-1.)+V_D\n",
-      "##so the equation is not balanced\n",
-      "V_D=0.65;##(V)\n",
-      "x=(10**-13)*(2000.)*(math.exp(V_D/V_T)-1.)+V_D\n",
-      "##again equation is not balanced .solution for V_D is between 0.6V and 0.65V\n",
-      "V_D=0.619;##(V)\n",
-      "x=(10**-13)*(2000.)*(math.exp(V_D/V_T)-1.)+V_D\n",
-      "##essentially equal to the value of the left side of the equation i.e 5V\n",
-      "print\"%s %.2f %s\"%('\\ndiode voltage= ',V_D,' V')\n",
-      "I_D=(V_PS-V_D)/R;##(A)diode current\n",
-      "print\"%s %.2f %s\"%('\\nthe diode current= ',I_D,' mA')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "diode voltage=  0.62  V\n",
-        "\n",
-        "the diode current=  2.19  mA\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.7\n",
-      "##piecewise linear diode parameters\n",
-      "V_Y=0.6;##(V)\n",
-      "r_f=0.010;##(KOhm)\n",
-      "V_PS=5.;##(V)applied voltage\n",
-      "R=2.;##(KOhm)Resistance in circuit\n",
-      "I_D=(V_PS-V_Y)/(R+r_f);##(A)diode current\n",
-      "print\"%s %.2f %s\"%('\\nthe diode current= ',I_D,' mA\\n')\n",
-      "V_D=V_Y+I_D*r_f;##(V)diode voltage\n",
-      "print\"%s %.2f %s\"%('\\ndiode voltage= ',V_D,' V')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the diode current=  2.19  mA\n",
-        "\n",
-        "\n",
-        "diode voltage=  0.62  V\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg33"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.9 \n",
-      "##circuit and diode parameters \n",
-      "V_PS=5.;##(V)\n",
-      "R=5;##(KOhm)\n",
-      "V_Y=0.6;##(V)\n",
-      "V_T=0.026;##(Volt)terminal voltage\n",
-      "v_i=0.1##*sin(wt)Volt\n",
-      "##dc analysis\n",
-      "I_DQ=(V_PS-V_Y)/R;\n",
-      "print\"%s %.2f %s\"%('\\ndc quiescent current= ',I_DQ,' mA\\n')\n",
-      "V_O=I_DQ*R;\n",
-      "print\"%s %.2f %s\"%('\\ndc output voltage= ',V_O,' V\\n')\n",
-      "##ac analysis\n",
-      "V_PS=0.;\n",
-      "##Kirchhoff voltage law equation becomes\n",
-      "##v_i=i_d*r_d+i_d*R\n",
-      "r_d=V_T/I_DQ##(Ohm)small signal diode diffusion resistance\n",
-      "i_d=v_i/(r_d+R);##ac diode current\n",
-      "print\"%s %.2f %s\"%('\\nac diode current= ',i_d,'sin(wt) A\\n')\n",
-      "\n",
-      "v_o=i_d*R;##ac output voltage\n",
-      "print\"%s %.2f %s\"%('\\nac output voltage= ',v_o,'sin(wt) V')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "dc quiescent current=  0.88  mA\n",
-        "\n",
-        "\n",
-        "dc output voltage=  4.40  V\n",
-        "\n",
-        "\n",
-        "ac diode current=  0.02 sin(wt) A\n",
-        "\n",
-        "\n",
-        "ac output voltage=  0.10 sin(wt) V\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg38"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.10\n",
-      "V_Y=0.7;##(V)cut in voltage for pn junction\n",
-      "r_f=0.;\n",
-      "V_PS=4;##(V)\n",
-      "R1=4.\n",
-      "R2=4.##(KOhm) from given circuit\n",
-      "I1=(V_PS-V_Y)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent through pn junction diode= ',I1,' mA\\n')\n",
-      "V_Y=0.3;##(V)cut in voltage for Schottky diode\n",
-      "I2=(V_PS-V_Y)/R2;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent through Schottky diode= ',I2,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "current through pn junction diode=  0.82  mA\n",
-        "\n",
-        "\n",
-        "current through Schottky diode=  0.93  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg40"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 1.11 \n",
-      "V_Z=5.6;##(V)Zener diode breakdown voltage\n",
-      "r_z=0.;##(Ohm)Zener resistance\n",
-      "I=3.;##(mA)current in the diode\n",
-      "V_PS=10.;##(V)\n",
-      "##I=(V_PS-V_Z)/R\n",
-      "R=(V_PS-V_Z)/I;\n",
-      "print\"%s %.2f %s\"%('\\nresistance= ',R,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "resistance=  1.47  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter2.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter2.ipynb
deleted file mode 100755
index deae3c71..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter2.ipynb
+++ /dev/null
@@ -1,407 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:230e38613ff389c9b83b1ccaac7bd389b698eb1c9fba0f06950798a22a773eaf"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter2-Diode Circuits"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg55"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 2.1\n",
-      "v_I=120.;##(V)rms primary input  \n",
-      "v_o=9.;##(V)peak output voltage\n",
-      "V_Y=0.7;##(V)diode cut in voltage\n",
-      "##for center-tapped transformer circuit in fig.2.6(a)\n",
-      "v_S=v_o+V_Y##(V)peak value of secondary voltage\n",
-      "print\"%s %.2f %s\"%('\\npeak value of secondary voltage= ',v_S,' V\\n')\n",
-      "v_S_rms=v_S/math.sqrt(2)##for a sinusoidal signal rms value of v_S\n",
-      "print\"%s %.2f %s\"%('\\nrms value of v_S= ',v_S_rms,' V\\n')\n",
-      "##let turns ratio of the primary to secondary winding be x=N1/N2\n",
-      "x=v_I/v_S_rms;\n",
-      "print\"%s %.2f %s\"%('\\nturns ratio= \\n',x,'')\n",
-      "##for the bridge circuit in fig.2.7(a)\n",
-      "v_Sb=v_o+2*V_Y;##(V)peak value of secondary voltage\n",
-      "print\"%s %.2f %s\"%('\\npeak value of secondary voltage= ',v_Sb,' V\\n')\n",
-      "v_S_rms=v_Sb/math.sqrt(2.);##for a sinusoidal signal rms value of v_S\n",
-      "print\"%s %.2f %s\"%('\\nrms value of v_S= ',v_S_rms,' V\\n')\n",
-      "##let turns ratio of the primary to secondary winding be x=N1/N2\n",
-      "x=v_I/v_S_rms;\n",
-      "print\"%s %.2f %s\"%('\\nturns ratio=\\n',x,'')\n",
-      "##for center tapped rectifier\n",
-      "PIV=2*v_S-V_Y;\n",
-      "print\"%s %.2f %s\"%('\\npeak inverse voltage of a diode= ',PIV,' V\\n')\n",
-      "##for the bridge rectifier peak inverse voltage of a diode\n",
-      "PIV=v_Sb-V_Y;\n",
-      "print\"%s %.2f %s\"%('\\npeak inverse voltage of a diode=\\n',PIV,'V')\n",
-      "##advantage of bridge rectifier over center tapped rectifier is it requies only half of the turns\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "peak value of secondary voltage=  9.70  V\n",
-        "\n",
-        "\n",
-        "rms value of v_S=  6.86  V\n",
-        "\n",
-        "\n",
-        "turns ratio= \n",
-        " 17.50 \n",
-        "\n",
-        "peak value of secondary voltage=  10.40  V\n",
-        "\n",
-        "\n",
-        "rms value of v_S=  7.35  V\n",
-        "\n",
-        "\n",
-        "turns ratio=\n",
-        " 16.32 \n",
-        "\n",
-        "peak inverse voltage of a diode=  18.70  V\n",
-        "\n",
-        "\n",
-        "peak inverse voltage of a diode=\n",
-        " 9.70 V\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg59"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.2\n",
-      "##full wave rectifier circuit with 60Hz input signal\n",
-      "V_M=10.;##(V)peak output voltage\n",
-      "R=0.01;##(MOhm)output load resistance\n",
-      "f=60.;##Hz\n",
-      "V_r=0.2;##(V)ripple voltage\n",
-      "C=V_M/(2.*f*R*V_r);##capacitance\n",
-      "print\"%s %.2f %s\"%('\\ncapacitance= ',C,' microF\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "capacitance=  41.67  microF\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg61"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 2.3\n",
-      "V_O=12.;##(V)peak output voltage\n",
-      "I_L=0.12;##(A)current delivered to the load\n",
-      "R=V_O/I_L;\n",
-      "print\"%s %.2f %s\"%('\\neffective load resistance= ',R,' Ohm\\n')\n",
-      "V_Y=0.7;##(V)diode cut in voltage\n",
-      "v_S=V_O+2.*V_Y;\n",
-      "print\"%s %.2f %s\"%('\\npeak value of v_S= ',v_S,' V\\n')\n",
-      "v_Srms=v_S/math.sqrt(2.);\n",
-      "print\"%s %.2f %s\"%('\\nrms voltage= ',v_Srms,' V\\n')\n",
-      "##let x=N1/N2\n",
-      "Vin=120.;##(V)input line voltage\n",
-      "x=Vin/v_Srms;\n",
-      "print\"%s %.2f %s\"%('\\nturns ratio= \\n',x,'')\n",
-      "VM=12.;##(V)\n",
-      "Vr=5/100.*VM;\n",
-      "print\"%s %.2f %s\"%('\\nripple voltage= ',Vr,' V\\n')\n",
-      "f=60.;##(Hz) input frequency\n",
-      "C=VM/(2.*R*Vr*f);\n",
-      "print\"%s %.2f %s\"%('\\nfilter capacitance= ',C,' F\\n')\n",
-      "i_Dmax=(VM/R)*(1+2*math.pi*math.sqrt(VM/(2.*Vr)));\n",
-      "print\"%s %.2f %s\"%('\\npeak diode current= ',i_Dmax,' A\\n')\n",
-      "R=0.1;##Kohm\n",
-      "i_Davg=(1/(2.*math.pi))*math.sqrt(2.*Vr/VM)*((VM/R)*(1.+math.pi*math.sqrt(VM/(2.*Vr))));\n",
-      "print\"%s %.2f %s\"%('\\naverage diode current= ',i_Davg,' mA\\n')\n",
-      "PIV=v_S-V_Y;\n",
-      "print\"%s %.2f %s\"%('\\npeak inverse voltage= ',PIV,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "effective load resistance=  100.00  Ohm\n",
-        "\n",
-        "\n",
-        "peak value of v_S=  13.40  V\n",
-        "\n",
-        "\n",
-        "rms voltage=  9.48  V\n",
-        "\n",
-        "\n",
-        "turns ratio= \n",
-        " 12.66 \n",
-        "\n",
-        "ripple voltage=  0.60  V\n",
-        "\n",
-        "\n",
-        "filter capacitance=  0.00  F\n",
-        "\n",
-        "\n",
-        "peak diode current=  2.50  A\n",
-        "\n",
-        "\n",
-        "average diode current=  66.04  mA\n",
-        "\n",
-        "\n",
-        "peak inverse voltage=  12.70  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg68"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.5\n",
-      "rZ=4.;##(Ohm) Zener resistance\n",
-      "V_Lnom=9.;##(V) nominal output voltage\n",
-      "Izmax=0.3;##(A) maximum zener diode current\n",
-      "Izmin=0.03;##(A) minimum zener diode current\n",
-      "V_Lmax=V_Lnom+Izmax*rZ\n",
-      "V_Lmin=V_Lnom+Izmin*rZ\n",
-      "##percent regulation R\n",
-      "R=((V_Lmax-V_Lmin)/V_Lnom)*100.;\n",
-      "print\"%s %.2f %s\"%('\\npercent regulation= ',R,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "percent regulation=  12.00  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg77"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.8\n",
-      "R1=5.;R2=10.;##(KOhm) \n",
-      "V_Y=0.7;##(V)diode cut in voltage\n",
-      "V1=5.;V2=-5;##(V)\n",
-      "vt=0.;##(V)\n",
-      "##asssuming initially diode D1 is off\n",
-      "##iR1=iD2=iR2=V1-V2-V_Y/(R1+R2)\n",
-      "iD2=(V1-V2-V_Y)/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\ndiode current= ',iD2,'mA\\n')\n",
-      "iR1=iD2;\n",
-      "vo=V1-iR1*R1;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',vo,' V\\n')\n",
-      "v=vo-V_Y;##v=v'\n",
-      "print\"%s %.2f %s\"%('\\nVoltage= ',v,' V\\n')\n",
-      "vt=4.;##(V)fig.2.33\n",
-      "##both D1 and D2 are on\n",
-      "vo==vt;\n",
-      "vo=4.;\n",
-      "iD2=(V1-vo)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ndiode current= ',iD2,' mA\\n')\n",
-      "iR1==iD2;\n",
-      "v=vo-V_Y;\n",
-      "print\"%s %.2f %s\"%('\\nV= ',v,' V\\n')\n",
-      "iR2=(v-V2)/R2;\n",
-      "print\"%s %.2f %s\"%('\\niR2= ',iR2,' mA\\n')\n",
-      "iD1=iR2-iD2;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent through D1= ',iD1,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "diode current=  0.62 mA\n",
-        "\n",
-        "\n",
-        "output voltage=  1.90  V\n",
-        "\n",
-        "\n",
-        "Voltage=  1.20  V\n",
-        "\n",
-        "\n",
-        "diode current=  0.20  mA\n",
-        "\n",
-        "\n",
-        "V=  3.30  V\n",
-        "\n",
-        "\n",
-        "iR2=  0.83  mA\n",
-        "\n",
-        "\n",
-        "current through D1=  0.63  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg83"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.10\n",
-      "n=1.;##quantum efficiency\n",
-      "A=10**-2;##cm^2 junction area\n",
-      "p=5*10**17;##(cm^-2-s^-1) incident photon flux\n",
-      "e=1.6*10**-16;##charge of an electron\n",
-      "Iph=n*e*p*A;\n",
-      "print\"%s %.2f %s\"%('\\nphotocurrent= ',Iph,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "photocurrent=  0.80  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg84"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.11\n",
-      "I=0.01;##(A) diode current\n",
-      "V_Y=1.7;##(V) forward bias voltage drop\n",
-      "Vt=0.2;##(V)\n",
-      "R=(5.-V_Y-Vt)/I;\n",
-      "print\"%s %.2f %s\"%('\\nresistance= ',R,' Ohm')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "resistance=  310.00  Ohm\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter2_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter2_1.ipynb
deleted file mode 100755
index deae3c71..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter2_1.ipynb
+++ /dev/null
@@ -1,407 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:230e38613ff389c9b83b1ccaac7bd389b698eb1c9fba0f06950798a22a773eaf"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter2-Diode Circuits"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg55"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 2.1\n",
-      "v_I=120.;##(V)rms primary input  \n",
-      "v_o=9.;##(V)peak output voltage\n",
-      "V_Y=0.7;##(V)diode cut in voltage\n",
-      "##for center-tapped transformer circuit in fig.2.6(a)\n",
-      "v_S=v_o+V_Y##(V)peak value of secondary voltage\n",
-      "print\"%s %.2f %s\"%('\\npeak value of secondary voltage= ',v_S,' V\\n')\n",
-      "v_S_rms=v_S/math.sqrt(2)##for a sinusoidal signal rms value of v_S\n",
-      "print\"%s %.2f %s\"%('\\nrms value of v_S= ',v_S_rms,' V\\n')\n",
-      "##let turns ratio of the primary to secondary winding be x=N1/N2\n",
-      "x=v_I/v_S_rms;\n",
-      "print\"%s %.2f %s\"%('\\nturns ratio= \\n',x,'')\n",
-      "##for the bridge circuit in fig.2.7(a)\n",
-      "v_Sb=v_o+2*V_Y;##(V)peak value of secondary voltage\n",
-      "print\"%s %.2f %s\"%('\\npeak value of secondary voltage= ',v_Sb,' V\\n')\n",
-      "v_S_rms=v_Sb/math.sqrt(2.);##for a sinusoidal signal rms value of v_S\n",
-      "print\"%s %.2f %s\"%('\\nrms value of v_S= ',v_S_rms,' V\\n')\n",
-      "##let turns ratio of the primary to secondary winding be x=N1/N2\n",
-      "x=v_I/v_S_rms;\n",
-      "print\"%s %.2f %s\"%('\\nturns ratio=\\n',x,'')\n",
-      "##for center tapped rectifier\n",
-      "PIV=2*v_S-V_Y;\n",
-      "print\"%s %.2f %s\"%('\\npeak inverse voltage of a diode= ',PIV,' V\\n')\n",
-      "##for the bridge rectifier peak inverse voltage of a diode\n",
-      "PIV=v_Sb-V_Y;\n",
-      "print\"%s %.2f %s\"%('\\npeak inverse voltage of a diode=\\n',PIV,'V')\n",
-      "##advantage of bridge rectifier over center tapped rectifier is it requies only half of the turns\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "peak value of secondary voltage=  9.70  V\n",
-        "\n",
-        "\n",
-        "rms value of v_S=  6.86  V\n",
-        "\n",
-        "\n",
-        "turns ratio= \n",
-        " 17.50 \n",
-        "\n",
-        "peak value of secondary voltage=  10.40  V\n",
-        "\n",
-        "\n",
-        "rms value of v_S=  7.35  V\n",
-        "\n",
-        "\n",
-        "turns ratio=\n",
-        " 16.32 \n",
-        "\n",
-        "peak inverse voltage of a diode=  18.70  V\n",
-        "\n",
-        "\n",
-        "peak inverse voltage of a diode=\n",
-        " 9.70 V\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg59"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.2\n",
-      "##full wave rectifier circuit with 60Hz input signal\n",
-      "V_M=10.;##(V)peak output voltage\n",
-      "R=0.01;##(MOhm)output load resistance\n",
-      "f=60.;##Hz\n",
-      "V_r=0.2;##(V)ripple voltage\n",
-      "C=V_M/(2.*f*R*V_r);##capacitance\n",
-      "print\"%s %.2f %s\"%('\\ncapacitance= ',C,' microF\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "capacitance=  41.67  microF\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg61"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 2.3\n",
-      "V_O=12.;##(V)peak output voltage\n",
-      "I_L=0.12;##(A)current delivered to the load\n",
-      "R=V_O/I_L;\n",
-      "print\"%s %.2f %s\"%('\\neffective load resistance= ',R,' Ohm\\n')\n",
-      "V_Y=0.7;##(V)diode cut in voltage\n",
-      "v_S=V_O+2.*V_Y;\n",
-      "print\"%s %.2f %s\"%('\\npeak value of v_S= ',v_S,' V\\n')\n",
-      "v_Srms=v_S/math.sqrt(2.);\n",
-      "print\"%s %.2f %s\"%('\\nrms voltage= ',v_Srms,' V\\n')\n",
-      "##let x=N1/N2\n",
-      "Vin=120.;##(V)input line voltage\n",
-      "x=Vin/v_Srms;\n",
-      "print\"%s %.2f %s\"%('\\nturns ratio= \\n',x,'')\n",
-      "VM=12.;##(V)\n",
-      "Vr=5/100.*VM;\n",
-      "print\"%s %.2f %s\"%('\\nripple voltage= ',Vr,' V\\n')\n",
-      "f=60.;##(Hz) input frequency\n",
-      "C=VM/(2.*R*Vr*f);\n",
-      "print\"%s %.2f %s\"%('\\nfilter capacitance= ',C,' F\\n')\n",
-      "i_Dmax=(VM/R)*(1+2*math.pi*math.sqrt(VM/(2.*Vr)));\n",
-      "print\"%s %.2f %s\"%('\\npeak diode current= ',i_Dmax,' A\\n')\n",
-      "R=0.1;##Kohm\n",
-      "i_Davg=(1/(2.*math.pi))*math.sqrt(2.*Vr/VM)*((VM/R)*(1.+math.pi*math.sqrt(VM/(2.*Vr))));\n",
-      "print\"%s %.2f %s\"%('\\naverage diode current= ',i_Davg,' mA\\n')\n",
-      "PIV=v_S-V_Y;\n",
-      "print\"%s %.2f %s\"%('\\npeak inverse voltage= ',PIV,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "effective load resistance=  100.00  Ohm\n",
-        "\n",
-        "\n",
-        "peak value of v_S=  13.40  V\n",
-        "\n",
-        "\n",
-        "rms voltage=  9.48  V\n",
-        "\n",
-        "\n",
-        "turns ratio= \n",
-        " 12.66 \n",
-        "\n",
-        "ripple voltage=  0.60  V\n",
-        "\n",
-        "\n",
-        "filter capacitance=  0.00  F\n",
-        "\n",
-        "\n",
-        "peak diode current=  2.50  A\n",
-        "\n",
-        "\n",
-        "average diode current=  66.04  mA\n",
-        "\n",
-        "\n",
-        "peak inverse voltage=  12.70  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg68"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.5\n",
-      "rZ=4.;##(Ohm) Zener resistance\n",
-      "V_Lnom=9.;##(V) nominal output voltage\n",
-      "Izmax=0.3;##(A) maximum zener diode current\n",
-      "Izmin=0.03;##(A) minimum zener diode current\n",
-      "V_Lmax=V_Lnom+Izmax*rZ\n",
-      "V_Lmin=V_Lnom+Izmin*rZ\n",
-      "##percent regulation R\n",
-      "R=((V_Lmax-V_Lmin)/V_Lnom)*100.;\n",
-      "print\"%s %.2f %s\"%('\\npercent regulation= ',R,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "percent regulation=  12.00  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg77"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.8\n",
-      "R1=5.;R2=10.;##(KOhm) \n",
-      "V_Y=0.7;##(V)diode cut in voltage\n",
-      "V1=5.;V2=-5;##(V)\n",
-      "vt=0.;##(V)\n",
-      "##asssuming initially diode D1 is off\n",
-      "##iR1=iD2=iR2=V1-V2-V_Y/(R1+R2)\n",
-      "iD2=(V1-V2-V_Y)/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\ndiode current= ',iD2,'mA\\n')\n",
-      "iR1=iD2;\n",
-      "vo=V1-iR1*R1;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',vo,' V\\n')\n",
-      "v=vo-V_Y;##v=v'\n",
-      "print\"%s %.2f %s\"%('\\nVoltage= ',v,' V\\n')\n",
-      "vt=4.;##(V)fig.2.33\n",
-      "##both D1 and D2 are on\n",
-      "vo==vt;\n",
-      "vo=4.;\n",
-      "iD2=(V1-vo)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ndiode current= ',iD2,' mA\\n')\n",
-      "iR1==iD2;\n",
-      "v=vo-V_Y;\n",
-      "print\"%s %.2f %s\"%('\\nV= ',v,' V\\n')\n",
-      "iR2=(v-V2)/R2;\n",
-      "print\"%s %.2f %s\"%('\\niR2= ',iR2,' mA\\n')\n",
-      "iD1=iR2-iD2;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent through D1= ',iD1,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "diode current=  0.62 mA\n",
-        "\n",
-        "\n",
-        "output voltage=  1.90  V\n",
-        "\n",
-        "\n",
-        "Voltage=  1.20  V\n",
-        "\n",
-        "\n",
-        "diode current=  0.20  mA\n",
-        "\n",
-        "\n",
-        "V=  3.30  V\n",
-        "\n",
-        "\n",
-        "iR2=  0.83  mA\n",
-        "\n",
-        "\n",
-        "current through D1=  0.63  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg83"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.10\n",
-      "n=1.;##quantum efficiency\n",
-      "A=10**-2;##cm^2 junction area\n",
-      "p=5*10**17;##(cm^-2-s^-1) incident photon flux\n",
-      "e=1.6*10**-16;##charge of an electron\n",
-      "Iph=n*e*p*A;\n",
-      "print\"%s %.2f %s\"%('\\nphotocurrent= ',Iph,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "photocurrent=  0.80  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg84"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.11\n",
-      "I=0.01;##(A) diode current\n",
-      "V_Y=1.7;##(V) forward bias voltage drop\n",
-      "Vt=0.2;##(V)\n",
-      "R=(5.-V_Y-Vt)/I;\n",
-      "print\"%s %.2f %s\"%('\\nresistance= ',R,' Ohm')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "resistance=  310.00  Ohm\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter2_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter2_1_1.ipynb
deleted file mode 100755
index 324bce27..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter2_1_1.ipynb
+++ /dev/null
@@ -1,407 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:77e57590b67964207d6f9870670ae0e0da31a20ccd56c5e90b158890f9c8ff6f"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter2-Diode Circuits"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg55"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 2.1\n",
-      "v_I=120.;##(V)rms primary input  \n",
-      "v_o=9.;##(V)peak output voltage\n",
-      "V_Y=0.7;##(V)diode cut in voltage\n",
-      "##for center-tapped transformer circuit in fig.2.6(a)\n",
-      "v_S=v_o+V_Y##(V)peak value of secondary voltage\n",
-      "print\"%s %.2f %s\"%('\\npeak value of secondary voltage= ',v_S,' V\\n')\n",
-      "v_S_rms=v_S/math.sqrt(2)##for a sinusoidal signal rms value of v_S\n",
-      "print\"%s %.2f %s\"%('\\nrms value of v_S= ',v_S_rms,' V\\n')\n",
-      "##let turns ratio of the primary to secondary winding be x=N1/N2\n",
-      "x=v_I/v_S_rms;\n",
-      "print\"%s %.2f %s\"%('\\nturns ratio= \\n',x,'')\n",
-      "##for the bridge circuit in fig.2.7(a)\n",
-      "v_Sb=v_o+2*V_Y;##(V)peak value of secondary voltage\n",
-      "print\"%s %.2f %s\"%('\\npeak value of secondary voltage= ',v_Sb,' V\\n')\n",
-      "v_S_rms=v_Sb/math.sqrt(2.);##for a sinusoidal signal rms value of v_S\n",
-      "print\"%s %.2f %s\"%('\\nrms value of v_S= ',v_S_rms,' V\\n')\n",
-      "##let turns ratio of the primary to secondary winding be x=N1/N2\n",
-      "x=v_I/v_S_rms;\n",
-      "print\"%s %.2f %s\"%('\\nturns ratio=\\n',x,'')\n",
-      "##for center tapped rectifier\n",
-      "PIV=2*v_S-V_Y;\n",
-      "print\"%s %.2f %s\"%('\\npeak inverse voltage of a diode= ',PIV,' V\\n')\n",
-      "##for the bridge rectifier peak inverse voltage of a diode\n",
-      "PIV=v_Sb-V_Y;\n",
-      "print\"%s %.2f %s\"%('\\npeak inverse voltage of a diode=\\n',PIV,'V')\n",
-      "##advantage of bridge rectifier over center tapped rectifier is it requies only half of the turns\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "peak value of secondary voltage=  9.70  V\n",
-        "\n",
-        "\n",
-        "rms value of v_S=  6.86  V\n",
-        "\n",
-        "\n",
-        "turns ratio= \n",
-        " 17.50 \n",
-        "\n",
-        "peak value of secondary voltage=  10.40  V\n",
-        "\n",
-        "\n",
-        "rms value of v_S=  7.35  V\n",
-        "\n",
-        "\n",
-        "turns ratio=\n",
-        " 16.32 \n",
-        "\n",
-        "peak inverse voltage of a diode=  18.70  V\n",
-        "\n",
-        "\n",
-        "peak inverse voltage of a diode=\n",
-        " 9.70 V\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg59"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.2\n",
-      "##full wave rectifier circuit with 60Hz input signal\n",
-      "V_M=10.;##(V)peak output voltage\n",
-      "R=0.01;##(MOhm)output load resistance\n",
-      "f=60.;##Hz\n",
-      "V_r=0.2;##(V)ripple voltage\n",
-      "C=V_M/(2.*f*R*V_r);##capacitance\n",
-      "print\"%s %.2f %s\"%('\\ncapacitance= ',C,' microF\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "capacitance=  41.67  microF\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg61"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 2.3\n",
-      "V_O=12.;##(V)peak output voltage\n",
-      "I_L=0.12;##(A)current delivered to the load\n",
-      "R=V_O/I_L;\n",
-      "print\"%s %.2f %s\"%('\\neffective load resistance= ',R,' Ohm\\n')\n",
-      "V_Y=0.7;##(V)diode cut in voltage\n",
-      "v_S=V_O+2.*V_Y;\n",
-      "print\"%s %.2f %s\"%('\\npeak value of v_S= ',v_S,' V\\n')\n",
-      "v_Srms=v_S/math.sqrt(2.);\n",
-      "print\"%s %.2f %s\"%('\\nrms voltage= ',v_Srms,' V\\n')\n",
-      "##let x=N1/N2\n",
-      "Vin=120.;##(V)input line voltage\n",
-      "x=Vin/v_Srms;\n",
-      "print\"%s %.2f %s\"%('\\nturns ratio= \\n',x,'')\n",
-      "VM=12.;##(V)\n",
-      "Vr=5/100.*VM;\n",
-      "print\"%s %.2f %s\"%('\\nripple voltage= ',Vr,' V\\n')\n",
-      "f=60.;##(Hz) input frequency\n",
-      "C=VM/(2.*R*Vr*f);\n",
-      "print\"%s %.2f %s\"%('\\nfilter capacitance= ',C,' F\\n')\n",
-      "i_Dmax=(VM/R)*(1+2*math.pi*math.sqrt(VM/(2.*Vr)));\n",
-      "print\"%s %.2f %s\"%('\\npeak diode current= ',i_Dmax,' A\\n')\n",
-      "R=0.1;##Kohm\n",
-      "i_Davg=(1/(2.*math.pi))*math.sqrt(2.*Vr/VM)*((VM/R)*(1.+math.pi*math.sqrt(VM/(2.*Vr))));\n",
-      "print\"%s %.2f %s\"%('\\naverage diode current= ',i_Davg,' mA\\n')\n",
-      "PIV=v_S-V_Y;\n",
-      "print\"%s %.2f %s\"%('\\npeak inverse voltage= ',PIV,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "effective load resistance=  100.00  Ohm\n",
-        "\n",
-        "\n",
-        "peak value of v_S=  13.40  V\n",
-        "\n",
-        "\n",
-        "rms voltage=  9.48  V\n",
-        "\n",
-        "\n",
-        "turns ratio= \n",
-        " 12.66 \n",
-        "\n",
-        "ripple voltage=  0.60  V\n",
-        "\n",
-        "\n",
-        "filter capacitance=  0.00  F\n",
-        "\n",
-        "\n",
-        "peak diode current=  2.50  A\n",
-        "\n",
-        "\n",
-        "average diode current=  66.04  mA\n",
-        "\n",
-        "\n",
-        "peak inverse voltage=  12.70  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg68"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.5\n",
-      "rZ=4.;##(Ohm) Zener resistance\n",
-      "V_Lnom=9.;##(V) nominal output voltage\n",
-      "Izmax=0.3;##(A) maximum zener diode current\n",
-      "Izmin=0.03;##(A) minimum zener diode current\n",
-      "V_Lmax=V_Lnom+Izmax*rZ\n",
-      "V_Lmin=V_Lnom+Izmin*rZ\n",
-      "##percent regulation R\n",
-      "R=((V_Lmax-V_Lmin)/V_Lnom)*100.;\n",
-      "print\"%s %.2f %s\"%('\\npercent regulation= ',R,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "percent regulation=  12.00  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg77"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.8\n",
-      "R1=5.;R2=10.;##(KOhm) \n",
-      "V_Y=0.7;##(V)diode cut in voltage\n",
-      "V1=5.;V2=-5;##(V)\n",
-      "vt=0.;##(V)\n",
-      "##asssuming initially diode D1 is off\n",
-      "##iR1=iD2=iR2=V1-V2-V_Y/(R1+R2)\n",
-      "iD2=(V1-V2-V_Y)/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\ndiode current= ',iD2,'mA\\n')\n",
-      "iR1=iD2;\n",
-      "vo=V1-iR1*R1;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',vo,' V\\n')\n",
-      "v=vo-V_Y;##v=v'\n",
-      "print\"%s %.2f %s\"%('\\nVoltage= ',v,' V\\n')\n",
-      "vt=4.;##(V)fig.2.33\n",
-      "##both D1 and D2 are on\n",
-      "vo==vt;\n",
-      "vo=4.;\n",
-      "iD2=(V1-vo)/R1;\n",
-      "print\"%s %.2f %s\"%('\\ndiode current= ',iD2,' mA\\n')\n",
-      "iR1==iD2;\n",
-      "v=vo-V_Y;\n",
-      "print\"%s %.2f %s\"%('\\nV= ',v,' V\\n')\n",
-      "iR2=(v-V2)/R2;\n",
-      "print\"%s %.2f %s\"%('\\niR2= ',iR2,' mA\\n')\n",
-      "iD1=iR2-iD2;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent through D1= ',iD1,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "diode current=  0.62 mA\n",
-        "\n",
-        "\n",
-        "output voltage=  1.90  V\n",
-        "\n",
-        "\n",
-        "Voltage=  1.20  V\n",
-        "\n",
-        "\n",
-        "diode current=  0.20  mA\n",
-        "\n",
-        "\n",
-        "V=  3.30  V\n",
-        "\n",
-        "\n",
-        "iR2=  0.83  mA\n",
-        "\n",
-        "\n",
-        "current through D1=  0.63  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg83"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.10\n",
-      "n=1.;##quantum efficiency\n",
-      "A=10**-2;##cm^2 junction area\n",
-      "p=5*10**17;##(cm^-2-s^-1) incident photon flux\n",
-      "e=1.6*10**-16;##charge of an electron\n",
-      "Iph=n*e*p*A;\n",
-      "print\"%s %.2f %s\"%('\\nphotocurrent= ',Iph,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "photocurrent=  0.80  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg84"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 2.11\n",
-      "I=0.01;##(A) diode current\n",
-      "V_Y=1.7;##(V) forward bias voltage drop\n",
-      "Vt=0.2;##(V)\n",
-      "R=(5.-V_Y-Vt)/I;\n",
-      "print\"%s %.2f %s\"%('\\nresistance= ',R,' Ohm')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "resistance=  310.00  Ohm\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter3.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter3.ipynb
deleted file mode 100755
index 2cf8c2a1..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter3.ipynb
+++ /dev/null
@@ -1,990 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:28e8a6daf4511e5943012a63f0712d999ea35abe1d000868606263c23a5458a4"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter3-The Bipolar Junction Transistor"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pgpg104"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "\n",
-      "##Example 3.1\n",
-      "##let beta be \"b\"\n",
-      "b=150.;##common emitter current gain\n",
-      "iB=15*10**-3;##(mA) base current\n",
-      "##assume transistor biased in forward active mode\n",
-      "iC=b*iB;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',iC,' mA\\n')\n",
-      "iE=(1.+b)*iB;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' mA\\n')\n",
-      "a=b/(1.+b);\n",
-      "print\"%s %.2f %s\"%('\\ncommon base current gain=',a,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector current=  2.25  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  2.27  mA\n",
-        "\n",
-        "\n",
-        "common base current gain= 0.99 \n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg113"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 3.2\n",
-      "b=100.;##common emitter current gain\n",
-      "BVcbo=120.;##(V) break down voltage of the B-C junction\n",
-      "n=3.;##empirical constant\n",
-      "BVceo=BVcbo/(b)**(1./n);\n",
-      "print\"%s %.2f %s\"%('\\nbreakdown voltage= ',BVceo,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "breakdown voltage=  25.85  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg115"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.3\n",
-      "Vbb=4.;##(V)\n",
-      "Rb=220.##(KOhm);\n",
-      "Rc=2.;##(KOhm)\n",
-      "Vcc=10.;##(V)\n",
-      "Vbe=0.7;##(V)\n",
-      "b=200.;\n",
-      "##from fig.3.19(b)\n",
-      "Ib=(Vbb-Vbe)/Rb;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Ie=(1.+b)*Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n",
-      "Vce=Vcc-Ic*Rc;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  3.00  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  3.01  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  4.00  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg116"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.4\n",
-      "Vbb=1.5;##(V)\n",
-      "Rb=580.;##(KOhm)\n",
-      "Veb=0.6;##(V)\n",
-      "Vcc=5.;##(V)\n",
-      "b=100.;\n",
-      "##writing Kirchhoff voltage law equation around E-B loop\n",
-      "Ib=(Vcc-Veb-Vbb)/Rb;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Ie=(1.+b)*Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current=',Ie,' mA\\n')\n",
-      "Vec=(1./2.)*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\nce voltage= ',Vec,' V\\n')\n",
-      "Rc=(Vcc-Vec)/Ic;\n",
-      "print\"%s %.2f %s\"%('\\ncollector resistance= ',Rc,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  0.50  mA\n",
-        "\n",
-        "\n",
-        "emitter current= 0.51  mA\n",
-        "\n",
-        "\n",
-        "ce voltage=  2.50  V\n",
-        "\n",
-        "\n",
-        "collector resistance=  5.00  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg119"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.5\n",
-      "b=100.;\n",
-      "Vbe=0.7;##(V)\n",
-      "Vce=0.2;##(V)\n",
-      "Vbb=8.;##(v)\n",
-      "Rb=220.;##(KOhm)\n",
-      "Ib=(Vbb-Vbe)/Rb\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "##transistor in active region\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Vcc=10.;##(V)\n",
-      "Rc=4.;##(KOhm)\n",
-      "Vce=Vcc-Ic*Rc;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n",
-      "##saturation\n",
-      "Vce=0.2;##(V)\n",
-      "Ic=(Vcc-Vce)/Rc;\n",
-      "print\"%s %.2f %s\"%('\\nsaturation collector current= ',Ic,' mA\\n')\n",
-      "x=Ic/Ib\n",
-      "##which is <b\n",
-      "Ie=Ic+Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.03  mA\n",
-        "\n",
-        "\n",
-        "collector current=  3.32  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  -3.27  V\n",
-        "\n",
-        "\n",
-        "saturation collector current=  2.45  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  2.48  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg122"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import numpy\n",
-      "import matplotlib\n",
-      "from matplotlib import pyplot\n",
-      "import math\n",
-      "%matplotlib inline\n",
-      "import warnings\n",
-      "warnings.filterwarnings('ignore')\n",
-      "#calculate the \n",
-      "##Example 3.6\n",
-      "Vbe=0.7;\n",
-      "b=75.;\n",
-      "##Q point values::\n",
-      "##using KVL eq around the B-E loop\n",
-      "##Vbb=Ib*Re+Vbe+Ie*Re\n",
-      "##assuming transistor is in forward biased mode we can write Ie=(1+b)*Ib\n",
-      "Vbb=6.;\n",
-      "Rb=25.;##KOhm\n",
-      "Re=0.6;##KOhm\n",
-      "Ib=(Vbb-Vbe)/(Rb+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Ie=(1+b)*Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n",
-      "Vcc=12.;\n",
-      "Rc=0.4;\n",
-      "Vce=Vcc-Ic*Rc-Ie*Re;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n",
-      "##load line::\n",
-      "##using KVL law around C-E loop\n",
-      "##Vce=Vcc-(Ic*(Rc+((1+B)/B)*Re));\n",
-      "Ic=numpy.array([0.12,5.63])\n",
-      "Vce=12.-(Ic)*1\n",
-      "pyplot.plot(Vce,Ic)\n",
-      "pyplot.xlabel(\"Vce\")\n",
-      "pyplot.ylabel(\"Ic\")\n",
-      "pyplot.show()\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.08  mA\n",
-        "\n",
-        "\n",
-        "collector current=  5.63  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  5.71  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  6.32  V\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "display_data",
-       "png": 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GW/K7wEcO94S2JvptwMnAOVV1MvB9+v1Px1UlOQZ4LtDi97/P33Qp49XA8cDDgHsneUmr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\n",
-       "text": [
-        "<matplotlib.figure.Figure at 0x71a3ed0>"
-       ]
-      }
-     ],
-     "prompt_number": 14
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg123"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "import matplotlib\n",
-      "from matplotlib import pyplot\n",
-      "#calculate the \n",
-      "##Example 3.7\n",
-      "Vbe=0.65;\n",
-      "Vcc=5.;\n",
-      "Rc=0.5;##KOhm\n",
-      "b=100.;\n",
-      "V1=-5.;\n",
-      "Re=1.;##KOhm\n",
-      "## Q-point values :: writing KVL eq around B-E loop\n",
-      "Ie=(-V1-Vbe)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n",
-      "Ib=(Ie/(1.+b));\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=(b/(1.+b))*Ie;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Vce=Vcc-Ic*Rc-Ie*Re-V1;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n",
-      "##load line::\n",
-      "##Vce=Vcc-V1-(Ic*(Rc+((1+B)/B)*Re));\n",
-      "\n",
-      "Vce=numpy.array([0,2,3.5,4,6,8,10])\n",
-      "Ic=(10.-Vce)/1.51;\n",
-      "\n",
-      "\n",
-      "pyplot.plot(Vce,Ic)\n",
-      "pyplot.xlabel(\"Vce\")\n",
-      "pyplot.ylabel(\"Ic\")\n",
-      "\n",
-      "pyplot.title(\"load line\")\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter current=  4.35  mA\n",
-        "\n",
-        "\n",
-        "base current=  0.04  mA\n",
-        "\n",
-        "\n",
-        "collector current=  4.31  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  3.50  V\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 20,
-       "text": [
-        "<matplotlib.text.Text at 0x6f909d0>"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "display_data",
-       "png": 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nAqNyj0cBZ23rd8RK9LqZagtylUtHYEbcSKIaCnwHWB87kMgOBd41s4fNbI6Z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\n/T96Dpvfmjsi0wAAAABJRU5ErkJggg==\n",
-       "text": [
-        "<matplotlib.figure.Figure at 0x6f80db0>"
-       ]
-      }
-     ],
-     "prompt_number": 20
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg128"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "import matplotlib\n",
-      "from matplotlib import pyplot\n",
-      "#calculate the \n",
-      "##Example 3.9\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "V1=-5.;\n",
-      "V2=12.;\n",
-      "Rb=10.;\n",
-      "Re=5.;\n",
-      "Rc=5.;\n",
-      "Rl=5.;\n",
-      "##Q point values:: using KVL eq around B-E loop\n",
-      "Ib=-(V1+Vbe)/(Rb+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Ie=(1.+b)*Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n",
-      "##at collector node we can write Ic=(V2-Vo)/Rc-Vo/Rl\n",
-      "Vo=(V2/Rc-Ic)*Rc*Rl/(Rc+Rl);\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',Vo,' V\\n')\n",
-      "Vce=Vo-Ie*Re-V1;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n",
-      "##load line::\n",
-      "Rth=Rl*Rc/(Rl+Rc);\n",
-      "print\"%s %.2f %s\"%('\\nThevenin rquivalent resistance= ',Rth,' KOhm\\n')\n",
-      "Vth=(Rl/(Rl+Rc))*V2;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin equivalent voltage= ',Vth,' V\\n')\n",
-      "##fig.3.36(c) KVL law\n",
-      "##Vce=6-V1-Ic*Rth-Ie*Re;\n",
-      "\n",
-      "\n",
-      "\n",
-      "Vce=numpy.array([0,2,4.7,3.5,4,6,8,10])\n",
-      "Ic=(11.-Vce)/7.5;\n",
-      "\n",
-      "\n",
-      "pyplot.plot(Vce,Ic)\n",
-      "pyplot.xlabel(\"Vce\")\n",
-      "pyplot.ylabel(\"Ic\")\n",
-      "pyplot.title(\"load line\")\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  0.83  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  0.84  mA\n",
-        "\n",
-        "\n",
-        "output voltage=  3.91  V\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  4.70  V\n",
-        "\n",
-        "\n",
-        "Thevenin rquivalent resistance=  2.50  KOhm\n",
-        "\n",
-        "\n",
-        "Thevenin equivalent voltage=  6.00  V\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 21,
-       "text": [
-        "<matplotlib.text.Text at 0x6fe9af0>"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "display_data",
-       "png": 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P2hM2BGkEGTxrIVptCEnWJLkjyV1JLpxlTC/JliRfTTLZZj3SuFm9Gtav7+cLGzf29xg2\nbepnDtJ0rYXKSfYGvga8CLgf+BJwalXdPmXMAcBngRdX1fYkK6vqOzNsy1BZ2kMGz+NnkELl44G7\nq+qeqnoM2Ai8fNqY04Brq2o7wEzNQNLiMHjWXNpsCKuAbVOWtzfPTXU48Iwkn05yc5LfbLEeSRg8\na3bLWtz2fI7xLAeOBV4I7At8PsnfV9Vd0wdOTEw8+bjX69Hr9RanSmlM7QieX/tauOiifvA8MQFn\nnQXL2vxmUGsmJyeZnJxc8OvbzBBOACaqak2z/EbgiapaN2XMhcDTqmqiWf4QcGNVXTNtW2YIUsuc\n8Tx6BilDuBk4PMlhSfYBXgVcN23MXwG/lGTvJPsCvwDc1mJNkmZx3HGweTNccgmcey6ceCJs3dp1\nVVpKrTWEqnoceB3wSfpf8h+rqtuTrE2ythlzB3Aj8BXgC8CVVWVDkDpi8DzevJaRpFk9/DCsW9ef\n1HbOOXDBBbD//l1XpfkapENGkoacM57Hi3sIkubN4Hm4ePlrSa1yxvPw8JCRpFZNDZ5f+UqD51Fi\nQ5C0IMuXw9lnO+N5lNgQJO0Rg+fRYYYgaVEZPA8OQ2VJnTN4HgyGypI6Z/A8nGwIklpj8DxcbAiS\nWmfwPBzMECQtOYPnpWGoLGkoGDy3z1BZ0lAweB48NgRJndoRPN95p8Fz12wIkgbCihUGz10zQ5A0\nkAye95yhsqSRYfC8ZwyVJY0Mg+el1WpDSLImyR1J7kpy4S7G/XySx5O8os16JA0ng+el0VpDSLI3\n8AFgDfBc4NQkz5ll3DrgRsAjhJJmZfDcrjb3EI4H7q6qe6rqMWAj8PIZxr0euAb4dou1SBohq1fD\n+vX9fGHjxv4ew6ZN/cxBC9dmQ1gFbJuyvL157klJVtFvEpc2T/m/U9K8HXccbN4Ml1wC554LJ54I\nW7d2XdXwWtbitufz5f5e4I+qqpKEXRwympiYePJxr9ej1+vtaX2SRsCO4HnNGrjyyv5/TzoJ3va2\n/plJ42RycpLJyckFv761006TnABMVNWaZvmNwBNVtW7KmK+zswmsBH4A/G5VXTdtW552KmleHnkE\n1q2Dyy6Dc86BCy6A/ffvuqpuDNJppzcDhyc5LMk+wKuAH/mir6qfqqpnVdWz6OcIZ09vBpK0O1as\ngIsvNnheiNYaQlU9DrwO+CRwG/Cxqro9ydoka9t6X0kCg+eFcKaypJE3rjOeB+mQkSQNBGc8z48N\nQdLYmDrj+eCDnfE8nQ1B0tgxeJ6ZGYKksXfLLXDeeaN3qW0vfy1JCzCKwbOhsiQtgMGzDUGSfsQ4\nB882BEmawTgGz2YIkjQPwxg8GypLUkuGLXg2VJaklox68GxDkKTdNKrBsw1BkhZo1IJnMwRJWiSD\nFjwbKktShwYpeDZUlqQOzRQ8/87vDEfwbEOQpBZMDZ5XrRqO4NmGIEktGqbgufWGkGRNkjuS3JXk\nwhnWn57ky0m+kuSzSY5quyZJWmo77vH8iU8M7j2eWw2Vk+wNfA14EXA/8CXg1Kq6fcqY/wjcVlUP\nJ1kDTFTVCdO2Y6gsaWRU9RvD+ef3Dye1FTwPWqh8PHB3Vd1TVY8BG4GXTx1QVZ+vqoebxS8Ah7Rc\nkyR1KoGTTx684LnthrAK2DZleXvz3GzOAja1WpEkDYhlywYreG67Icz7OE+SXwXOBJ6SM0jSKBuU\n4HlZy9u/Hzh0yvKh9PcSfkQTJF8JrKmqh2ba0MTExJOPe70evV5vMeuUpM7tCJ53zHh+//t3b8bz\n5OQkk5OTC37/tkPlZfRD5RcC3wS+yFND5dXAZuA1VfX3s2zHUFnSWFmM4HmgQuWqehx4HfBJ4Dbg\nY1V1e5K1SdY2w94MHAhcmmRLki+2WZMkDYMugmevZSRJQ+CRR2DdOrjssn4QfeGFsP/+u37NQO0h\nSJIWx9Tg+b772gme3UOQpCE0n0tte/lrSRoTcwXPHjKSpDGx2MGzDUGShtxMM54vumj3t2NDkKQR\nsSN43roVtm2be/x0ZgiSNKLMECRJC2JDkCQBNgRJUsOGIEkCbAiSpIYNQZIE2BAkSQ0bgiQJsCFI\nkho2BEkSYEOQJDVsCJIkoOWGkGRNkjuS3JXkwlnGvL9Z/+Ukz2+zHknS7FprCEn2Bj4ArAGeC5ya\n5DnTxrwE+JmqOhz4PeDStuoZFZOTk12XMDD8LHbys9jJz2Lh2txDOB64u6ruqarHgI3Ay6eNeRnw\nEYCq+gJwQJJntljT0PMv+05+Fjv5WezkZ7FwbTaEVcDUWzRsb56ba8whLdYkSZpFmw1hvne0mX7z\nBu+EI0kdaO2OaUlOACaqak2z/EbgiapaN2XMZcBkVW1slu8AXlBVD0zblk1CkhZgd+6YtqzFOm4G\nDk9yGPBN4FXAqdPGXAe8DtjYNJB/md4MYPf+QJKkhWmtIVTV40leB3wS2Bv4cFXdnmRts/7yqtqU\n5CVJ7gYeBc5oqx5J0q61dshIkjRcBnqm8nwmto2LJIcm+XSSf0zy1ST/veuaupRk7yRbklzfdS1d\nSnJAkmuS3J7ktubQ61hK8sbm9+PWJB9N8mNd17RUklyV5IEkt0557hlJbkpyZ5K/SXLAXNsZ2IYw\nn4ltY+Yx4A+q6nnACcB/G/PP4/eB2/CstPcBm6rqOcBRwO0d19OJJqv8XeDYqjqS/mHqV3dZ0xK7\nmv535VR/BNxUVUcAf9ss79LANgTmN7FtbFTVt6pqa/P4+/R/8Q/utqpuJDkEeAnwIZ562vLYSPJ0\n4Jer6iro53ZV9XDHZXXlEfr/aNo3yTJgX+D+bktaOlX1GeChaU8/OfG3+e9/nms7g9wQ5jOxbSw1\n/xp6PvCFbivpzHuA84Enui6kY88Cvp3k6iS3JLkyyb5dF9WFqvou8KfAffTPavyXqvpUt1V17plT\nztp8AJjzKhCD3BDG/VDAjJLsB1wD/H6zpzBWkpwMPFhVWxjjvYPGMuBY4INVdSz9M/XmPCwwipL8\nNPAG4DD6e877JTm906IGSPXPHprzO3WQG8L9wKFTlg+lv5cwtpIsB64F/qKq/nfX9XTkPwEvS/IN\nYAPwa0nWd1xTV7YD26vqS83yNfQbxDj6OeBzVfXPVfU48HH6f1fG2QNJ/j1AkoOAB+d6wSA3hCcn\ntiXZh/7Etus6rqkzSQJ8GLitqt7bdT1dqao/rqpDq+pZ9EPDzVX1W13X1YWq+hawLckRzVMvAv6x\nw5K6dAdwQpKnNb8rL6J/0sE4uw747ebxbwNz/iOyzZnKe2S2iW0dl9WlXwReA3wlyZbmuTdW1Y0d\n1jQIxv3Q4uuB/9n8o+n/MaaTO6vqy82e4s30s6VbgCu6rWrpJNkAvABYmWQb8GbgEuAvk5wF3AP8\n1zm348Q0SRIM9iEjSdISsiFIkgAbgiSpYUOQJAE2BElSw4YgSQJsCNKskmxO8uvTnntDkg92VZPU\nJhuCNLsNPPUSyq8CPtpBLVLrbAjS7K4FXtpcTnnHVWYPrqr/m+TCJF9JsjXJO5v1P53kr5PcnOTv\nkjy7u9Kl3Tewl66QulZV303yRfr3XriO/t7Cx5KcRP9a88dX1b9OuRPVFcDaqro7yS8AHwRe2EXt\n0kJ46QppF5KcBpxcVac115A6EzgduL2qPjxl3H70ryb5tSkv36e5w500FNxDkHbtOuA9SZ4P7FtV\nW5rr7E+/F8Ne9G/K8vwlr1BaJGYI0i40NyH6NP171u4Ik28CzkjyNIAkB1bVI8A3kvyX5rkkOaqL\nmqWFsiFIc9sAHNn8l6r6JP09h5ubw0jnNeNOB85KshX4Kv2cQRoaZgiSJMA9BElSw4YgSQJsCJKk\nhg1BkgTYECRJDRuCJAmwIUiSGjYESRIA/x+o/vcOVxPvBAAAAABJRU5ErkJggg==\n",
-       "text": [
-        "<matplotlib.figure.Figure at 0x6f80950>"
-       ]
-      }
-     ],
-     "prompt_number": 21
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg132"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 3.10\n",
-      "Rb=0.24;\n",
-      "Vcc=12.;\n",
-      "Vbe=0.7;\n",
-      "Vce=0.1;\n",
-      "b=75.;\n",
-      "Rc=5.;##Ohm\n",
-      "##for Vt=0 ,transistor is cut off,Ib=Ic=0,Vo=Vcc=12 V,power dissipation is zero\n",
-      "Vt=12.;##(V)\n",
-      "Ib=(Vt-Vbe)/Rb;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=(Vcc-Vce)/Rc;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,'A\\n')\n",
-      "Ib=0.0471;##A\n",
-      "x=Ic/Ib\n",
-      "##since Ic/Ib<b transistor is in saturation\n",
-      "##Vo==Vcc;\n",
-      "Vo=0.1;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',Vo,' V\\n')\n",
-      "P=Ic*Vce+Ib*Vbe;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',P,' W\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  47.08  mA\n",
-        "\n",
-        "\n",
-        "collector current=  2.38 A\n",
-        "\n",
-        "\n",
-        "output voltage=  0.10  V\n",
-        "\n",
-        "\n",
-        "power dissipation=  0.27  W\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 22
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg138"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.13\n",
-      "b=100.;\n",
-      "Vcc=12.;\n",
-      "Vbe=0.7;\n",
-      "Icq=1.;##mA\n",
-      "Vceq=6.;\n",
-      "Rc=(Vcc-Vceq)/Icq;\n",
-      "print\"%s %.2f %s\"%('\\ncollector resistance= ',Rc,' KOhms\\n')\n",
-      "Ibq=Icq/b;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ibq,' mA\\n')\n",
-      "Rb=(Vcc-Vbe)/Ibq;\n",
-      "print\"%s %.2f %s\"%('\\nbase resistance= ',Rb,' KOhms\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector resistance=  6.00  KOhms\n",
-        "\n",
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "base resistance=  1130.00  KOhms\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 23
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg141"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.14\n",
-      "R1=56.;\n",
-      "R2=12.2;\n",
-      "Rc=2.;\n",
-      "Re=.4;\n",
-      "Vcc=10.;\n",
-      "Vbe=0.7;\n",
-      "b=100.;\n",
-      "##fig.3.53(b)\n",
-      "Rth=R2*R1/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nThevenin rquivalent resistance= ',Rth,' KOhm\\n')\n",
-      "Vth=(R2/(R1+R2))*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin equivalent voltage= ',Vth,' V\\n')\n",
-      "Ibq=(Vth-Vbe)/(Rth+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ibq,' mA\\n')\n",
-      "Icq=b*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Icq,' mA\\n')\n",
-      "Ieq=(1.+b)*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ieq,' mA\\n')\n",
-      "Vceq=Vcc-Icq*Rc-Ieq*Re;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vceq,' V\\n')\n",
-      "b=numpy.array([50,100,150])\n",
-      "for x in range(0,150):\n",
-      "    Ibq=(Vth-Vbe)/(Rth+(1.+x)*Re);\n",
-      "print(\"Ibeq,Iceq,Ieq,Vceq\")\n",
-      "print(Ibq)\n",
-      "Icq=x*Ibq;\n",
-      "print(Icq)\n",
-      "Ieq=(1+x)*Ibq;\n",
-      "print(Ieq)\n",
-      "Vceq=Vcc-Icq*Rc-Ieq*Re;\n",
-      "print(Vceq)\n",
-      "print(\"\")\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Thevenin rquivalent resistance=  10.02  KOhm\n",
-        "\n",
-        "\n",
-        "Thevenin equivalent voltage=  1.79  V\n",
-        "\n",
-        "\n",
-        "base current=  0.02  mA\n",
-        "\n",
-        "\n",
-        "collector current=  2.16  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  2.18  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  4.81  V\n",
-        "\n",
-        "Ibeq,Iceq,Ieq,Vceq\n",
-        "0.0155511811024\n",
-        "2.31712598425\n",
-        "2.33267716535\n",
-        "4.43267716535\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 28
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg142"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.15\n",
-      "Vcc=5.;\n",
-      "Rc=1.;##KOhm\n",
-      "Vbe=0.7;\n",
-      "b=120.;\n",
-      "Vceq=3.;\n",
-      "Re=.510;\n",
-      "Icq=(Vcc-Vceq)/(Rc+Re);\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Icq,' mA\\n')\n",
-      "Ibq=Icq/b;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ibq,' mA\\n')\n",
-      "##for bias stable circuit\n",
-      "Rth=0.1*(1.+b)*Re;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin rquivalent resistance= ',Rth,' KOhm\\n')\n",
-      "##Ibq=(Vth-Vbe)/(Rth+(1+b)*Re)\n",
-      "Vth=Ibq*(Rth+(1.+b)*Re)+Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin equivalent voltage= ',Vth,' V\\n')\n",
-      "##Vth=(R2/(R1+R2))*Vcc\n",
-      "##let x=(R2/(R1+R2))\n",
-      "x=Vth/Vcc\n",
-      "##Rth=6050=R1*x\n",
-      "R1=6.05/x;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,'KOhms\\n')\n",
-      "R2=x*R1/(1-x);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,'KOhms\\'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector current=  1.32  mA\n",
-        "\n",
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "Thevenin rquivalent resistance=  6.17  KOhm\n",
-        "\n",
-        "\n",
-        "Thevenin equivalent voltage=  1.45  V\n",
-        "\n",
-        "\n",
-        "R1=  20.87 KOhms\n",
-        "\n",
-        "\n",
-        "R2=  8.52 KOhms'\n"
-       ]
-      }
-     ],
-     "prompt_number": 29
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg146"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.16\n",
-      "R1=10.;\n",
-      "b=50.;\n",
-      "Vbe=0.7;\n",
-      "V1=-5.;\n",
-      "I1=-(V1+Vbe)/R1;\n",
-      "print\"%s %.2f %s\"%('\\nreference current= ',I1,' mA\\n')\n",
-      "Iq=I1/(1.+2./b);\n",
-      "print\"%s %.2f %s\"%('\\nbias current= ',Iq,' mA\\n')\n",
-      "##Ib=Ib1=Ib2\n",
-      "Ib=Iq/b;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "reference current=  0.43  mA\n",
-        "\n",
-        "\n",
-        "bias current=  0.41  mA\n",
-        "\n",
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 30
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg148"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 3.17\n",
-      "Vbe=0.7;\n",
-      "Vcc=10.;\n",
-      "V2=5.;\n",
-      "b=100.;\n",
-      "R1=100.;\n",
-      "R2=50.;\n",
-      "Re1=2.;\n",
-      "Rth=R2*R1/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nThevenin rquivalent resistance= ',Rth,' KOhm\\n')\n",
-      "Vth=(R2/(R1+R2))*Vcc-V2;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin equivalent voltage= ',Vth,' V\\n')\n",
-      "##Vth=Ib1*Rth+Vbe+Ie1*Re1-5 and Ie1=(1+b)*Ib1\n",
-      "Ib1=(Vth+5-Vbe)/(Rth+(1+b)*Re1);\n",
-      "print\"%s %.2f %s\"%('\\nIb1= ',Ib1,' mA\\n')\n",
-      "Ic1=b*Ib1;\n",
-      "print\"%s %.2f %s\"%('\\nIc1= ',Ic1,' mA\\n')\n",
-      "Ie1=(1.+b)*Ib1;\n",
-      "print\"%s %.2f %s\"%('\\nIe1= ',Ie1,' mA\\n')\n",
-      "##summing the currents at the collector of Q1,Ir1+Ib2=Ic1\n",
-      "##(5-Vc1)/Rc1+Ib2=Ic1\n",
-      "##also Ib2=Ie2/(1+b)=(5-(Vc1+0.7))/(1+b)*Re2\n",
-      "Rc1=5.;\n",
-      "Re1=2.;\n",
-      "Re2=2.;\n",
-      "Rc2=1.5;\n",
-      "Vc1=Rc1*(1.+b)*Re2*((5./Rc1)+(4.3/((1.+b)*Re2))-Ic1)/(((1.+b)*Re2)+Rc1);\n",
-      "print\"%s %.2f %s\"%('\\nVc1= ',Vc1,' V\\n')\n",
-      "Ir1=(5.-Vc1)/Rc1;\n",
-      "print\"%s %.2f %s\"%('\\nIr1= ',Ir1,' mA\\n')\n",
-      "Ve2=Vc1+Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nVe2= ',Ve2,' V\\n')\n",
-      "Ie2=(5-Ve2)/Re1;\n",
-      "print\"%s %.2f %s\"%('\\nIe2= ',Ie2,' mA\\n')\n",
-      "Ic2=Ie2*b/(1.+b);\n",
-      "print\"%s %.2f %s\"%('\\nIc2= ',Ic2,' mA\\n')\n",
-      "Ib2=Ie2/(1.+b);\n",
-      "print\"%s %.2f %s\"%('\\nIb2 ',Ib2,' mA\\n')\n",
-      "Ve1=Ie1*Re1-5;\n",
-      "print\"%s %.2f %s\"%('\\nVe1= ',Ve1,' V\\n')\n",
-      "Vc2=Ic2*Rc2-5.;\n",
-      "print\"%s %.2f %s\"%('\\nVc2= ',Vc2,' V\\n')\n",
-      "Vce1=Vc1-Ve1;\n",
-      "print\"%s %.2f %s\"%('\\nVce1= ',Vce1,'V\\n')\n",
-      "Vec2=Ve2-Vc2;\n",
-      "print\"%s %.2f %s\"%('\\nVec2= ',Vec2,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Thevenin rquivalent resistance=  33.33  KOhm\n",
-        "\n",
-        "\n",
-        "Thevenin equivalent voltage=  -1.67  V\n",
-        "\n",
-        "\n",
-        "Ib1=  0.01  mA\n",
-        "\n",
-        "\n",
-        "Ic1=  1.12  mA\n",
-        "\n",
-        "\n",
-        "Ie1=  1.13  mA\n",
-        "\n",
-        "\n",
-        "Vc1=  -0.48  V\n",
-        "\n",
-        "\n",
-        "Ir1=  1.10  mA\n",
-        "\n",
-        "\n",
-        "Ve2=  0.22  V\n",
-        "\n",
-        "\n",
-        "Ie2=  2.39  mA\n",
-        "\n",
-        "\n",
-        "Ic2=  2.36  mA\n",
-        "\n",
-        "\n",
-        "Ib2  0.02  mA\n",
-        "\n",
-        "\n",
-        "Ve1=  -2.74  V\n",
-        "\n",
-        "\n",
-        "Vc2=  -1.45  V\n",
-        "\n",
-        "\n",
-        "Vce1=  2.26 V\n",
-        "\n",
-        "\n",
-        "Vec2=  1.68  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 31
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter3_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter3_1.ipynb
deleted file mode 100755
index 2cf8c2a1..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter3_1.ipynb
+++ /dev/null
@@ -1,990 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:28e8a6daf4511e5943012a63f0712d999ea35abe1d000868606263c23a5458a4"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter3-The Bipolar Junction Transistor"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pgpg104"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "\n",
-      "##Example 3.1\n",
-      "##let beta be \"b\"\n",
-      "b=150.;##common emitter current gain\n",
-      "iB=15*10**-3;##(mA) base current\n",
-      "##assume transistor biased in forward active mode\n",
-      "iC=b*iB;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',iC,' mA\\n')\n",
-      "iE=(1.+b)*iB;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' mA\\n')\n",
-      "a=b/(1.+b);\n",
-      "print\"%s %.2f %s\"%('\\ncommon base current gain=',a,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector current=  2.25  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  2.27  mA\n",
-        "\n",
-        "\n",
-        "common base current gain= 0.99 \n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg113"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 3.2\n",
-      "b=100.;##common emitter current gain\n",
-      "BVcbo=120.;##(V) break down voltage of the B-C junction\n",
-      "n=3.;##empirical constant\n",
-      "BVceo=BVcbo/(b)**(1./n);\n",
-      "print\"%s %.2f %s\"%('\\nbreakdown voltage= ',BVceo,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "breakdown voltage=  25.85  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg115"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.3\n",
-      "Vbb=4.;##(V)\n",
-      "Rb=220.##(KOhm);\n",
-      "Rc=2.;##(KOhm)\n",
-      "Vcc=10.;##(V)\n",
-      "Vbe=0.7;##(V)\n",
-      "b=200.;\n",
-      "##from fig.3.19(b)\n",
-      "Ib=(Vbb-Vbe)/Rb;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Ie=(1.+b)*Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n",
-      "Vce=Vcc-Ic*Rc;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  3.00  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  3.01  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  4.00  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg116"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.4\n",
-      "Vbb=1.5;##(V)\n",
-      "Rb=580.;##(KOhm)\n",
-      "Veb=0.6;##(V)\n",
-      "Vcc=5.;##(V)\n",
-      "b=100.;\n",
-      "##writing Kirchhoff voltage law equation around E-B loop\n",
-      "Ib=(Vcc-Veb-Vbb)/Rb;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Ie=(1.+b)*Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current=',Ie,' mA\\n')\n",
-      "Vec=(1./2.)*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\nce voltage= ',Vec,' V\\n')\n",
-      "Rc=(Vcc-Vec)/Ic;\n",
-      "print\"%s %.2f %s\"%('\\ncollector resistance= ',Rc,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  0.50  mA\n",
-        "\n",
-        "\n",
-        "emitter current= 0.51  mA\n",
-        "\n",
-        "\n",
-        "ce voltage=  2.50  V\n",
-        "\n",
-        "\n",
-        "collector resistance=  5.00  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg119"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.5\n",
-      "b=100.;\n",
-      "Vbe=0.7;##(V)\n",
-      "Vce=0.2;##(V)\n",
-      "Vbb=8.;##(v)\n",
-      "Rb=220.;##(KOhm)\n",
-      "Ib=(Vbb-Vbe)/Rb\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "##transistor in active region\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Vcc=10.;##(V)\n",
-      "Rc=4.;##(KOhm)\n",
-      "Vce=Vcc-Ic*Rc;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n",
-      "##saturation\n",
-      "Vce=0.2;##(V)\n",
-      "Ic=(Vcc-Vce)/Rc;\n",
-      "print\"%s %.2f %s\"%('\\nsaturation collector current= ',Ic,' mA\\n')\n",
-      "x=Ic/Ib\n",
-      "##which is <b\n",
-      "Ie=Ic+Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.03  mA\n",
-        "\n",
-        "\n",
-        "collector current=  3.32  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  -3.27  V\n",
-        "\n",
-        "\n",
-        "saturation collector current=  2.45  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  2.48  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg122"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import numpy\n",
-      "import matplotlib\n",
-      "from matplotlib import pyplot\n",
-      "import math\n",
-      "%matplotlib inline\n",
-      "import warnings\n",
-      "warnings.filterwarnings('ignore')\n",
-      "#calculate the \n",
-      "##Example 3.6\n",
-      "Vbe=0.7;\n",
-      "b=75.;\n",
-      "##Q point values::\n",
-      "##using KVL eq around the B-E loop\n",
-      "##Vbb=Ib*Re+Vbe+Ie*Re\n",
-      "##assuming transistor is in forward biased mode we can write Ie=(1+b)*Ib\n",
-      "Vbb=6.;\n",
-      "Rb=25.;##KOhm\n",
-      "Re=0.6;##KOhm\n",
-      "Ib=(Vbb-Vbe)/(Rb+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Ie=(1+b)*Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n",
-      "Vcc=12.;\n",
-      "Rc=0.4;\n",
-      "Vce=Vcc-Ic*Rc-Ie*Re;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n",
-      "##load line::\n",
-      "##using KVL law around C-E loop\n",
-      "##Vce=Vcc-(Ic*(Rc+((1+B)/B)*Re));\n",
-      "Ic=numpy.array([0.12,5.63])\n",
-      "Vce=12.-(Ic)*1\n",
-      "pyplot.plot(Vce,Ic)\n",
-      "pyplot.xlabel(\"Vce\")\n",
-      "pyplot.ylabel(\"Ic\")\n",
-      "pyplot.show()\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.08  mA\n",
-        "\n",
-        "\n",
-        "collector current=  5.63  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  5.71  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  6.32  V\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "display_data",
-       "png": 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GW/K7wEcO94S2JvptwMnAOVV1MvB9+v1Px1UlOQZ4LtDi97/P33Qp49XA8cDDgHsneUmr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\n",
-       "text": [
-        "<matplotlib.figure.Figure at 0x71a3ed0>"
-       ]
-      }
-     ],
-     "prompt_number": 14
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg123"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "import matplotlib\n",
-      "from matplotlib import pyplot\n",
-      "#calculate the \n",
-      "##Example 3.7\n",
-      "Vbe=0.65;\n",
-      "Vcc=5.;\n",
-      "Rc=0.5;##KOhm\n",
-      "b=100.;\n",
-      "V1=-5.;\n",
-      "Re=1.;##KOhm\n",
-      "## Q-point values :: writing KVL eq around B-E loop\n",
-      "Ie=(-V1-Vbe)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n",
-      "Ib=(Ie/(1.+b));\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=(b/(1.+b))*Ie;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Vce=Vcc-Ic*Rc-Ie*Re-V1;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n",
-      "##load line::\n",
-      "##Vce=Vcc-V1-(Ic*(Rc+((1+B)/B)*Re));\n",
-      "\n",
-      "Vce=numpy.array([0,2,3.5,4,6,8,10])\n",
-      "Ic=(10.-Vce)/1.51;\n",
-      "\n",
-      "\n",
-      "pyplot.plot(Vce,Ic)\n",
-      "pyplot.xlabel(\"Vce\")\n",
-      "pyplot.ylabel(\"Ic\")\n",
-      "\n",
-      "pyplot.title(\"load line\")\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter current=  4.35  mA\n",
-        "\n",
-        "\n",
-        "base current=  0.04  mA\n",
-        "\n",
-        "\n",
-        "collector current=  4.31  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  3.50  V\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 20,
-       "text": [
-        "<matplotlib.text.Text at 0x6f909d0>"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "display_data",
-       "png": 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nAqNyj0cBZ23rd8RK9LqZagtylUtHYEbcSKIaCnwHWB87kMgOBd41s4fNbI6Z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\n/T96Dpvfmjsi0wAAAABJRU5ErkJggg==\n",
-       "text": [
-        "<matplotlib.figure.Figure at 0x6f80db0>"
-       ]
-      }
-     ],
-     "prompt_number": 20
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg128"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "import matplotlib\n",
-      "from matplotlib import pyplot\n",
-      "#calculate the \n",
-      "##Example 3.9\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "V1=-5.;\n",
-      "V2=12.;\n",
-      "Rb=10.;\n",
-      "Re=5.;\n",
-      "Rc=5.;\n",
-      "Rl=5.;\n",
-      "##Q point values:: using KVL eq around B-E loop\n",
-      "Ib=-(V1+Vbe)/(Rb+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Ie=(1.+b)*Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n",
-      "##at collector node we can write Ic=(V2-Vo)/Rc-Vo/Rl\n",
-      "Vo=(V2/Rc-Ic)*Rc*Rl/(Rc+Rl);\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',Vo,' V\\n')\n",
-      "Vce=Vo-Ie*Re-V1;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n",
-      "##load line::\n",
-      "Rth=Rl*Rc/(Rl+Rc);\n",
-      "print\"%s %.2f %s\"%('\\nThevenin rquivalent resistance= ',Rth,' KOhm\\n')\n",
-      "Vth=(Rl/(Rl+Rc))*V2;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin equivalent voltage= ',Vth,' V\\n')\n",
-      "##fig.3.36(c) KVL law\n",
-      "##Vce=6-V1-Ic*Rth-Ie*Re;\n",
-      "\n",
-      "\n",
-      "\n",
-      "Vce=numpy.array([0,2,4.7,3.5,4,6,8,10])\n",
-      "Ic=(11.-Vce)/7.5;\n",
-      "\n",
-      "\n",
-      "pyplot.plot(Vce,Ic)\n",
-      "pyplot.xlabel(\"Vce\")\n",
-      "pyplot.ylabel(\"Ic\")\n",
-      "pyplot.title(\"load line\")\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  0.83  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  0.84  mA\n",
-        "\n",
-        "\n",
-        "output voltage=  3.91  V\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  4.70  V\n",
-        "\n",
-        "\n",
-        "Thevenin rquivalent resistance=  2.50  KOhm\n",
-        "\n",
-        "\n",
-        "Thevenin equivalent voltage=  6.00  V\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 21,
-       "text": [
-        "<matplotlib.text.Text at 0x6fe9af0>"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "display_data",
-       "png": 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P2hM2BGkEGTxrIVptCEnWJLkjyV1JLpxlTC/JliRfTTLZZj3SuFm9Gtav7+cLGzf29xg2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\n",
-       "text": [
-        "<matplotlib.figure.Figure at 0x6f80950>"
-       ]
-      }
-     ],
-     "prompt_number": 21
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg132"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 3.10\n",
-      "Rb=0.24;\n",
-      "Vcc=12.;\n",
-      "Vbe=0.7;\n",
-      "Vce=0.1;\n",
-      "b=75.;\n",
-      "Rc=5.;##Ohm\n",
-      "##for Vt=0 ,transistor is cut off,Ib=Ic=0,Vo=Vcc=12 V,power dissipation is zero\n",
-      "Vt=12.;##(V)\n",
-      "Ib=(Vt-Vbe)/Rb;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=(Vcc-Vce)/Rc;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,'A\\n')\n",
-      "Ib=0.0471;##A\n",
-      "x=Ic/Ib\n",
-      "##since Ic/Ib<b transistor is in saturation\n",
-      "##Vo==Vcc;\n",
-      "Vo=0.1;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',Vo,' V\\n')\n",
-      "P=Ic*Vce+Ib*Vbe;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',P,' W\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  47.08  mA\n",
-        "\n",
-        "\n",
-        "collector current=  2.38 A\n",
-        "\n",
-        "\n",
-        "output voltage=  0.10  V\n",
-        "\n",
-        "\n",
-        "power dissipation=  0.27  W\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 22
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg138"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.13\n",
-      "b=100.;\n",
-      "Vcc=12.;\n",
-      "Vbe=0.7;\n",
-      "Icq=1.;##mA\n",
-      "Vceq=6.;\n",
-      "Rc=(Vcc-Vceq)/Icq;\n",
-      "print\"%s %.2f %s\"%('\\ncollector resistance= ',Rc,' KOhms\\n')\n",
-      "Ibq=Icq/b;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ibq,' mA\\n')\n",
-      "Rb=(Vcc-Vbe)/Ibq;\n",
-      "print\"%s %.2f %s\"%('\\nbase resistance= ',Rb,' KOhms\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector resistance=  6.00  KOhms\n",
-        "\n",
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "base resistance=  1130.00  KOhms\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 23
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg141"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.14\n",
-      "R1=56.;\n",
-      "R2=12.2;\n",
-      "Rc=2.;\n",
-      "Re=.4;\n",
-      "Vcc=10.;\n",
-      "Vbe=0.7;\n",
-      "b=100.;\n",
-      "##fig.3.53(b)\n",
-      "Rth=R2*R1/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nThevenin rquivalent resistance= ',Rth,' KOhm\\n')\n",
-      "Vth=(R2/(R1+R2))*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin equivalent voltage= ',Vth,' V\\n')\n",
-      "Ibq=(Vth-Vbe)/(Rth+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ibq,' mA\\n')\n",
-      "Icq=b*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Icq,' mA\\n')\n",
-      "Ieq=(1.+b)*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ieq,' mA\\n')\n",
-      "Vceq=Vcc-Icq*Rc-Ieq*Re;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vceq,' V\\n')\n",
-      "b=numpy.array([50,100,150])\n",
-      "for x in range(0,150):\n",
-      "    Ibq=(Vth-Vbe)/(Rth+(1.+x)*Re);\n",
-      "print(\"Ibeq,Iceq,Ieq,Vceq\")\n",
-      "print(Ibq)\n",
-      "Icq=x*Ibq;\n",
-      "print(Icq)\n",
-      "Ieq=(1+x)*Ibq;\n",
-      "print(Ieq)\n",
-      "Vceq=Vcc-Icq*Rc-Ieq*Re;\n",
-      "print(Vceq)\n",
-      "print(\"\")\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Thevenin rquivalent resistance=  10.02  KOhm\n",
-        "\n",
-        "\n",
-        "Thevenin equivalent voltage=  1.79  V\n",
-        "\n",
-        "\n",
-        "base current=  0.02  mA\n",
-        "\n",
-        "\n",
-        "collector current=  2.16  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  2.18  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  4.81  V\n",
-        "\n",
-        "Ibeq,Iceq,Ieq,Vceq\n",
-        "0.0155511811024\n",
-        "2.31712598425\n",
-        "2.33267716535\n",
-        "4.43267716535\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 28
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg142"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.15\n",
-      "Vcc=5.;\n",
-      "Rc=1.;##KOhm\n",
-      "Vbe=0.7;\n",
-      "b=120.;\n",
-      "Vceq=3.;\n",
-      "Re=.510;\n",
-      "Icq=(Vcc-Vceq)/(Rc+Re);\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Icq,' mA\\n')\n",
-      "Ibq=Icq/b;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ibq,' mA\\n')\n",
-      "##for bias stable circuit\n",
-      "Rth=0.1*(1.+b)*Re;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin rquivalent resistance= ',Rth,' KOhm\\n')\n",
-      "##Ibq=(Vth-Vbe)/(Rth+(1+b)*Re)\n",
-      "Vth=Ibq*(Rth+(1.+b)*Re)+Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin equivalent voltage= ',Vth,' V\\n')\n",
-      "##Vth=(R2/(R1+R2))*Vcc\n",
-      "##let x=(R2/(R1+R2))\n",
-      "x=Vth/Vcc\n",
-      "##Rth=6050=R1*x\n",
-      "R1=6.05/x;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,'KOhms\\n')\n",
-      "R2=x*R1/(1-x);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,'KOhms\\'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector current=  1.32  mA\n",
-        "\n",
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "Thevenin rquivalent resistance=  6.17  KOhm\n",
-        "\n",
-        "\n",
-        "Thevenin equivalent voltage=  1.45  V\n",
-        "\n",
-        "\n",
-        "R1=  20.87 KOhms\n",
-        "\n",
-        "\n",
-        "R2=  8.52 KOhms'\n"
-       ]
-      }
-     ],
-     "prompt_number": 29
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg146"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.16\n",
-      "R1=10.;\n",
-      "b=50.;\n",
-      "Vbe=0.7;\n",
-      "V1=-5.;\n",
-      "I1=-(V1+Vbe)/R1;\n",
-      "print\"%s %.2f %s\"%('\\nreference current= ',I1,' mA\\n')\n",
-      "Iq=I1/(1.+2./b);\n",
-      "print\"%s %.2f %s\"%('\\nbias current= ',Iq,' mA\\n')\n",
-      "##Ib=Ib1=Ib2\n",
-      "Ib=Iq/b;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "reference current=  0.43  mA\n",
-        "\n",
-        "\n",
-        "bias current=  0.41  mA\n",
-        "\n",
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 30
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg148"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 3.17\n",
-      "Vbe=0.7;\n",
-      "Vcc=10.;\n",
-      "V2=5.;\n",
-      "b=100.;\n",
-      "R1=100.;\n",
-      "R2=50.;\n",
-      "Re1=2.;\n",
-      "Rth=R2*R1/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nThevenin rquivalent resistance= ',Rth,' KOhm\\n')\n",
-      "Vth=(R2/(R1+R2))*Vcc-V2;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin equivalent voltage= ',Vth,' V\\n')\n",
-      "##Vth=Ib1*Rth+Vbe+Ie1*Re1-5 and Ie1=(1+b)*Ib1\n",
-      "Ib1=(Vth+5-Vbe)/(Rth+(1+b)*Re1);\n",
-      "print\"%s %.2f %s\"%('\\nIb1= ',Ib1,' mA\\n')\n",
-      "Ic1=b*Ib1;\n",
-      "print\"%s %.2f %s\"%('\\nIc1= ',Ic1,' mA\\n')\n",
-      "Ie1=(1.+b)*Ib1;\n",
-      "print\"%s %.2f %s\"%('\\nIe1= ',Ie1,' mA\\n')\n",
-      "##summing the currents at the collector of Q1,Ir1+Ib2=Ic1\n",
-      "##(5-Vc1)/Rc1+Ib2=Ic1\n",
-      "##also Ib2=Ie2/(1+b)=(5-(Vc1+0.7))/(1+b)*Re2\n",
-      "Rc1=5.;\n",
-      "Re1=2.;\n",
-      "Re2=2.;\n",
-      "Rc2=1.5;\n",
-      "Vc1=Rc1*(1.+b)*Re2*((5./Rc1)+(4.3/((1.+b)*Re2))-Ic1)/(((1.+b)*Re2)+Rc1);\n",
-      "print\"%s %.2f %s\"%('\\nVc1= ',Vc1,' V\\n')\n",
-      "Ir1=(5.-Vc1)/Rc1;\n",
-      "print\"%s %.2f %s\"%('\\nIr1= ',Ir1,' mA\\n')\n",
-      "Ve2=Vc1+Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nVe2= ',Ve2,' V\\n')\n",
-      "Ie2=(5-Ve2)/Re1;\n",
-      "print\"%s %.2f %s\"%('\\nIe2= ',Ie2,' mA\\n')\n",
-      "Ic2=Ie2*b/(1.+b);\n",
-      "print\"%s %.2f %s\"%('\\nIc2= ',Ic2,' mA\\n')\n",
-      "Ib2=Ie2/(1.+b);\n",
-      "print\"%s %.2f %s\"%('\\nIb2 ',Ib2,' mA\\n')\n",
-      "Ve1=Ie1*Re1-5;\n",
-      "print\"%s %.2f %s\"%('\\nVe1= ',Ve1,' V\\n')\n",
-      "Vc2=Ic2*Rc2-5.;\n",
-      "print\"%s %.2f %s\"%('\\nVc2= ',Vc2,' V\\n')\n",
-      "Vce1=Vc1-Ve1;\n",
-      "print\"%s %.2f %s\"%('\\nVce1= ',Vce1,'V\\n')\n",
-      "Vec2=Ve2-Vc2;\n",
-      "print\"%s %.2f %s\"%('\\nVec2= ',Vec2,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Thevenin rquivalent resistance=  33.33  KOhm\n",
-        "\n",
-        "\n",
-        "Thevenin equivalent voltage=  -1.67  V\n",
-        "\n",
-        "\n",
-        "Ib1=  0.01  mA\n",
-        "\n",
-        "\n",
-        "Ic1=  1.12  mA\n",
-        "\n",
-        "\n",
-        "Ie1=  1.13  mA\n",
-        "\n",
-        "\n",
-        "Vc1=  -0.48  V\n",
-        "\n",
-        "\n",
-        "Ir1=  1.10  mA\n",
-        "\n",
-        "\n",
-        "Ve2=  0.22  V\n",
-        "\n",
-        "\n",
-        "Ie2=  2.39  mA\n",
-        "\n",
-        "\n",
-        "Ic2=  2.36  mA\n",
-        "\n",
-        "\n",
-        "Ib2  0.02  mA\n",
-        "\n",
-        "\n",
-        "Ve1=  -2.74  V\n",
-        "\n",
-        "\n",
-        "Vc2=  -1.45  V\n",
-        "\n",
-        "\n",
-        "Vce1=  2.26 V\n",
-        "\n",
-        "\n",
-        "Vec2=  1.68  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 31
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter3_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter3_1_1.ipynb
deleted file mode 100755
index e6fdfc33..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter3_1_1.ipynb
+++ /dev/null
@@ -1,992 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:454a57b394e23d05ed048843520d141cbdae1d1bc179f5ca99f9342e5d6f5307"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter3-The Bipolar Junction Transistor"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pgpg104"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "\n",
-      "##Example 3.1\n",
-      "##let beta be \"b\"\n",
-      "b=150.;##common emitter current gain\n",
-      "iB=15*10**-3;##(mA) base current\n",
-      "##assume transistor biased in forward active mode\n",
-      "iC=b*iB;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',iC,' mA\\n')\n",
-      "iE=(1.+b)*iB;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',iE,' mA\\n')\n",
-      "a=b/(1.+b);\n",
-      "print\"%s %.2f %s\"%('\\ncommon base current gain=',a,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector current=  2.25  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  2.27  mA\n",
-        "\n",
-        "\n",
-        "common base current gain= 0.99 \n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg113"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 3.2\n",
-      "b=100.;##common emitter current gain\n",
-      "BVcbo=120.;##(V) break down voltage of the B-C junction\n",
-      "n=3.;##empirical constant\n",
-      "BVceo=BVcbo/(b)**(1./n);\n",
-      "print\"%s %.2f %s\"%('\\nbreakdown voltage= ',BVceo,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "breakdown voltage=  25.85  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg115"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.3\n",
-      "Vbb=4.;##(V)\n",
-      "Rb=220.##(KOhm);\n",
-      "Rc=2.;##(KOhm)\n",
-      "Vcc=10.;##(V)\n",
-      "Vbe=0.7;##(V)\n",
-      "b=200.;\n",
-      "##from fig.3.19(b)\n",
-      "Ib=(Vbb-Vbe)/Rb;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Ie=(1.+b)*Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n",
-      "Vce=Vcc-Ic*Rc;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  3.00  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  3.01  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  4.00  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg116"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.4\n",
-      "Vbb=1.5;##(V)\n",
-      "Rb=580.;##(KOhm)\n",
-      "Veb=0.6;##(V)\n",
-      "Vcc=5.;##(V)\n",
-      "b=100.;\n",
-      "##writing Kirchhoff voltage law equation around E-B loop\n",
-      "Ib=(Vcc-Veb-Vbb)/Rb;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Ie=(1.+b)*Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current=',Ie,' mA\\n')\n",
-      "Vec=(1./2.)*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\nce voltage= ',Vec,' V\\n')\n",
-      "Rc=(Vcc-Vec)/Ic;\n",
-      "print\"%s %.2f %s\"%('\\ncollector resistance= ',Rc,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  0.50  mA\n",
-        "\n",
-        "\n",
-        "emitter current= 0.51  mA\n",
-        "\n",
-        "\n",
-        "ce voltage=  2.50  V\n",
-        "\n",
-        "\n",
-        "collector resistance=  5.00  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg119"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.5\n",
-      "b=100.;\n",
-      "Vbe=0.7;##(V)\n",
-      "Vce=0.2;##(V)\n",
-      "Vbb=8.;##(v)\n",
-      "Rb=220.;##(KOhm)\n",
-      "Ib=(Vbb-Vbe)/Rb\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "##transistor in active region\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Vcc=10.;##(V)\n",
-      "Rc=4.;##(KOhm)\n",
-      "Vce=Vcc-Ic*Rc;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n",
-      "##saturation\n",
-      "Vce=0.2;##(V)\n",
-      "Ic=(Vcc-Vce)/Rc;\n",
-      "print\"%s %.2f %s\"%('\\nsaturation collector current= ',Ic,' mA\\n')\n",
-      "x=Ic/Ib\n",
-      "##which is <b\n",
-      "Ie=Ic+Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.03  mA\n",
-        "\n",
-        "\n",
-        "collector current=  3.32  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  -3.27  V\n",
-        "\n",
-        "\n",
-        "saturation collector current=  2.45  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  2.48  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg122"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "\n",
-      "import numpy\n",
-      "import matplotlib\n",
-      "from matplotlib import pyplot\n",
-      "import math\n",
-      "%matplotlib inline\n",
-      "import warnings\n",
-      "warnings.filterwarnings('ignore')\n",
-      "#calculate the \n",
-      "##Example 3.6\n",
-      "Vbe=0.7;\n",
-      "b=75.;\n",
-      "##Q point values::\n",
-      "##using KVL eq around the B-E loop\n",
-      "##Vbb=Ib*Re+Vbe+Ie*Re\n",
-      "##assuming transistor is in forward biased mode we can write Ie=(1+b)*Ib\n",
-      "Vbb=6.;\n",
-      "Rb=25.;##KOhm\n",
-      "Re=0.6;##KOhm\n",
-      "Ib=(Vbb-Vbe)/(Rb+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Ie=(1+b)*Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n",
-      "Vcc=12.;\n",
-      "Rc=0.4;\n",
-      "Vce=Vcc-Ic*Rc-Ie*Re;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n",
-      "##load line::\n",
-      "##using KVL law around C-E loop\n",
-      "##Vce=Vcc-(Ic*(Rc+((1+B)/B)*Re));\n",
-      "Ic=numpy.array([0.12,5.63])\n",
-      "Vce=12.-(Ic)*1\n",
-      "pyplot.plot(Vce,Ic)\n",
-      "pyplot.xlabel(\"Vce\")\n",
-      "pyplot.ylabel(\"Ic\")\n",
-      "pyplot.show()\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.08  mA\n",
-        "\n",
-        "\n",
-        "collector current=  5.63  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  5.71  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  6.32  V\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "display_data",
-       "png": "iVBORw0KGgoAAAANSUhEUgAAAXoAAAEPCAYAAABMTw/iAAAABHNCSVQICAgIfAhkiAAAAAlwSFlz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\n",
-       "text": [
-        "<matplotlib.figure.Figure at 0x33d9e30>"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg123"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "import matplotlib\n",
-      "from matplotlib import pyplot\n",
-      "%matplotlib inline\n",
-      "#calculate the \n",
-      "##Example 3.7\n",
-      "Vbe=0.65;\n",
-      "Vcc=5.;\n",
-      "Rc=0.5;##KOhm\n",
-      "b=100.;\n",
-      "V1=-5.;\n",
-      "Re=1.;##KOhm\n",
-      "## Q-point values :: writing KVL eq around B-E loop\n",
-      "Ie=(-V1-Vbe)/Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n",
-      "Ib=(Ie/(1.+b));\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=(b/(1.+b))*Ie;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Vce=Vcc-Ic*Rc-Ie*Re-V1;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n",
-      "##load line::\n",
-      "##Vce=Vcc-V1-(Ic*(Rc+((1+B)/B)*Re));\n",
-      "\n",
-      "Vce=numpy.array([0,2,3.5,4,6,8,10])\n",
-      "Ic=(10.-Vce)/1.51;\n",
-      "\n",
-      "\n",
-      "pyplot.plot(Vce,Ic)\n",
-      "pyplot.xlabel(\"Vce\")\n",
-      "pyplot.ylabel(\"Ic\")\n",
-      "\n",
-      "pyplot.title(\"load line\")\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "emitter current=  4.35  mA\n",
-        "\n",
-        "\n",
-        "base current=  0.04  mA\n",
-        "\n",
-        "\n",
-        "collector current=  4.31  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  3.50  V\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 4,
-       "text": [
-        "<matplotlib.text.Text at 0x75078d0>"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "display_data",
-       "png": 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nAqNyj0cBZ23rd8RK9LqZagtylUtHYEbcSKIaCnwHWB87kMgOBd41s4fNbI6Z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\n/T96Dpvfmjsi0wAAAABJRU5ErkJggg==\n",
-       "text": [
-        "<matplotlib.figure.Figure at 0x75076f0>"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg128"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "import matplotlib\n",
-      "from matplotlib import pyplot\n",
-      "%matplotlib inline\n",
-      "#calculate the \n",
-      "##Example 3.9\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "V1=-5.;\n",
-      "V2=12.;\n",
-      "Rb=10.;\n",
-      "Re=5.;\n",
-      "Rc=5.;\n",
-      "Rl=5.;\n",
-      "##Q point values:: using KVL eq around B-E loop\n",
-      "Ib=-(V1+Vbe)/(Rb+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=b*Ib;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,' mA\\n')\n",
-      "Ie=(1.+b)*Ib;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ie,' mA\\n')\n",
-      "##at collector node we can write Ic=(V2-Vo)/Rc-Vo/Rl\n",
-      "Vo=(V2/Rc-Ic)*Rc*Rl/(Rc+Rl);\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',Vo,' V\\n')\n",
-      "Vce=Vo-Ie*Re-V1;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vce,' V\\n')\n",
-      "##load line::\n",
-      "Rth=Rl*Rc/(Rl+Rc);\n",
-      "print\"%s %.2f %s\"%('\\nThevenin rquivalent resistance= ',Rth,' KOhm\\n')\n",
-      "Vth=(Rl/(Rl+Rc))*V2;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin equivalent voltage= ',Vth,' V\\n')\n",
-      "##fig.3.36(c) KVL law\n",
-      "##Vce=6-V1-Ic*Rth-Ie*Re;\n",
-      "\n",
-      "\n",
-      "\n",
-      "Vce=numpy.array([0,2,4.7,3.5,4,6,8,10])\n",
-      "Ic=(11.-Vce)/7.5;\n",
-      "\n",
-      "\n",
-      "pyplot.plot(Vce,Ic)\n",
-      "pyplot.xlabel(\"Vce\")\n",
-      "pyplot.ylabel(\"Ic\")\n",
-      "pyplot.title(\"load line\")\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  0.83  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  0.84  mA\n",
-        "\n",
-        "\n",
-        "output voltage=  3.91  V\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  4.70  V\n",
-        "\n",
-        "\n",
-        "Thevenin rquivalent resistance=  2.50  KOhm\n",
-        "\n",
-        "\n",
-        "Thevenin equivalent voltage=  6.00  V\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 5,
-       "text": [
-        "<matplotlib.text.Text at 0x34068b0>"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "display_data",
-       "png": 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-       "text": [
-        "<matplotlib.figure.Figure at 0x758f0b0>"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg132"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 3.10\n",
-      "Rb=0.24;\n",
-      "Vcc=12.;\n",
-      "Vbe=0.7;\n",
-      "Vce=0.1;\n",
-      "b=75.;\n",
-      "Rc=5.;##Ohm\n",
-      "##for Vt=0 ,transistor is cut off,Ib=Ic=0,Vo=Vcc=12 V,power dissipation is zero\n",
-      "Vt=12.;##(V)\n",
-      "Ib=(Vt-Vbe)/Rb;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n",
-      "Ic=(Vcc-Vce)/Rc;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Ic,'A\\n')\n",
-      "Ib=0.0471;##A\n",
-      "x=Ic/Ib\n",
-      "##since Ic/Ib<b transistor is in saturation\n",
-      "##Vo==Vcc;\n",
-      "Vo=0.1;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',Vo,' V\\n')\n",
-      "P=Ic*Vce+Ib*Vbe;\n",
-      "print\"%s %.2f %s\"%('\\npower dissipation= ',P,' W\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=  47.08  mA\n",
-        "\n",
-        "\n",
-        "collector current=  2.38 A\n",
-        "\n",
-        "\n",
-        "output voltage=  0.10  V\n",
-        "\n",
-        "\n",
-        "power dissipation=  0.27  W\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 22
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg138"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.13\n",
-      "b=100.;\n",
-      "Vcc=12.;\n",
-      "Vbe=0.7;\n",
-      "Icq=1.;##mA\n",
-      "Vceq=6.;\n",
-      "Rc=(Vcc-Vceq)/Icq;\n",
-      "print\"%s %.2f %s\"%('\\ncollector resistance= ',Rc,' KOhms\\n')\n",
-      "Ibq=Icq/b;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ibq,' mA\\n')\n",
-      "Rb=(Vcc-Vbe)/Ibq;\n",
-      "print\"%s %.2f %s\"%('\\nbase resistance= ',Rb,' KOhms\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector resistance=  6.00  KOhms\n",
-        "\n",
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "base resistance=  1130.00  KOhms\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 23
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg141"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.14\n",
-      "R1=56.;\n",
-      "R2=12.2;\n",
-      "Rc=2.;\n",
-      "Re=.4;\n",
-      "Vcc=10.;\n",
-      "Vbe=0.7;\n",
-      "b=100.;\n",
-      "##fig.3.53(b)\n",
-      "Rth=R2*R1/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nThevenin rquivalent resistance= ',Rth,' KOhm\\n')\n",
-      "Vth=(R2/(R1+R2))*Vcc;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin equivalent voltage= ',Vth,' V\\n')\n",
-      "Ibq=(Vth-Vbe)/(Rth+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ibq,' mA\\n')\n",
-      "Icq=b*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Icq,' mA\\n')\n",
-      "Ieq=(1.+b)*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ieq,' mA\\n')\n",
-      "Vceq=Vcc-Icq*Rc-Ieq*Re;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vceq,' V\\n')\n",
-      "b=numpy.array([50,100,150])\n",
-      "for x in range(0,150):\n",
-      "    Ibq=(Vth-Vbe)/(Rth+(1.+x)*Re);\n",
-      "print(\"Ibeq,Iceq,Ieq,Vceq\")\n",
-      "print(Ibq)\n",
-      "Icq=x*Ibq;\n",
-      "print(Icq)\n",
-      "Ieq=(1+x)*Ibq;\n",
-      "print(Ieq)\n",
-      "Vceq=Vcc-Icq*Rc-Ieq*Re;\n",
-      "print(Vceq)\n",
-      "print(\"\")\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Thevenin rquivalent resistance=  10.02  KOhm\n",
-        "\n",
-        "\n",
-        "Thevenin equivalent voltage=  1.79  V\n",
-        "\n",
-        "\n",
-        "base current=  0.02  mA\n",
-        "\n",
-        "\n",
-        "collector current=  2.16  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  2.18  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  4.81  V\n",
-        "\n",
-        "Ibeq,Iceq,Ieq,Vceq\n",
-        "0.0155511811024\n",
-        "2.31712598425\n",
-        "2.33267716535\n",
-        "4.43267716535\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 28
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg142"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.15\n",
-      "Vcc=5.;\n",
-      "Rc=1.;##KOhm\n",
-      "Vbe=0.7;\n",
-      "b=120.;\n",
-      "Vceq=3.;\n",
-      "Re=.510;\n",
-      "Icq=(Vcc-Vceq)/(Rc+Re);\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Icq,' mA\\n')\n",
-      "Ibq=Icq/b;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ibq,' mA\\n')\n",
-      "##for bias stable circuit\n",
-      "Rth=0.1*(1.+b)*Re;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin rquivalent resistance= ',Rth,' KOhm\\n')\n",
-      "##Ibq=(Vth-Vbe)/(Rth+(1+b)*Re)\n",
-      "Vth=Ibq*(Rth+(1.+b)*Re)+Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin equivalent voltage= ',Vth,' V\\n')\n",
-      "##Vth=(R2/(R1+R2))*Vcc\n",
-      "##let x=(R2/(R1+R2))\n",
-      "x=Vth/Vcc\n",
-      "##Rth=6050=R1*x\n",
-      "R1=6.05/x;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,'KOhms\\n')\n",
-      "R2=x*R1/(1-x);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,'KOhms\\'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "collector current=  1.32  mA\n",
-        "\n",
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n",
-        "\n",
-        "Thevenin rquivalent resistance=  6.17  KOhm\n",
-        "\n",
-        "\n",
-        "Thevenin equivalent voltage=  1.45  V\n",
-        "\n",
-        "\n",
-        "R1=  20.87 KOhms\n",
-        "\n",
-        "\n",
-        "R2=  8.52 KOhms'\n"
-       ]
-      }
-     ],
-     "prompt_number": 29
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg146"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 3.16\n",
-      "R1=10.;\n",
-      "b=50.;\n",
-      "Vbe=0.7;\n",
-      "V1=-5.;\n",
-      "I1=-(V1+Vbe)/R1;\n",
-      "print\"%s %.2f %s\"%('\\nreference current= ',I1,' mA\\n')\n",
-      "Iq=I1/(1.+2./b);\n",
-      "print\"%s %.2f %s\"%('\\nbias current= ',Iq,' mA\\n')\n",
-      "##Ib=Ib1=Ib2\n",
-      "Ib=Iq/b;\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ib,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "reference current=  0.43  mA\n",
-        "\n",
-        "\n",
-        "bias current=  0.41  mA\n",
-        "\n",
-        "\n",
-        "base current=  0.01  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 30
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg148"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 3.17\n",
-      "Vbe=0.7;\n",
-      "Vcc=10.;\n",
-      "V2=5.;\n",
-      "b=100.;\n",
-      "R1=100.;\n",
-      "R2=50.;\n",
-      "Re1=2.;\n",
-      "Rth=R2*R1/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nThevenin rquivalent resistance= ',Rth,' KOhm\\n')\n",
-      "Vth=(R2/(R1+R2))*Vcc-V2;\n",
-      "print\"%s %.2f %s\"%('\\nThevenin equivalent voltage= ',Vth,' V\\n')\n",
-      "##Vth=Ib1*Rth+Vbe+Ie1*Re1-5 and Ie1=(1+b)*Ib1\n",
-      "Ib1=(Vth+5-Vbe)/(Rth+(1+b)*Re1);\n",
-      "print\"%s %.2f %s\"%('\\nIb1= ',Ib1,' mA\\n')\n",
-      "Ic1=b*Ib1;\n",
-      "print\"%s %.2f %s\"%('\\nIc1= ',Ic1,' mA\\n')\n",
-      "Ie1=(1.+b)*Ib1;\n",
-      "print\"%s %.2f %s\"%('\\nIe1= ',Ie1,' mA\\n')\n",
-      "##summing the currents at the collector of Q1,Ir1+Ib2=Ic1\n",
-      "##(5-Vc1)/Rc1+Ib2=Ic1\n",
-      "##also Ib2=Ie2/(1+b)=(5-(Vc1+0.7))/(1+b)*Re2\n",
-      "Rc1=5.;\n",
-      "Re1=2.;\n",
-      "Re2=2.;\n",
-      "Rc2=1.5;\n",
-      "Vc1=Rc1*(1.+b)*Re2*((5./Rc1)+(4.3/((1.+b)*Re2))-Ic1)/(((1.+b)*Re2)+Rc1);\n",
-      "print\"%s %.2f %s\"%('\\nVc1= ',Vc1,' V\\n')\n",
-      "Ir1=(5.-Vc1)/Rc1;\n",
-      "print\"%s %.2f %s\"%('\\nIr1= ',Ir1,' mA\\n')\n",
-      "Ve2=Vc1+Vbe;\n",
-      "print\"%s %.2f %s\"%('\\nVe2= ',Ve2,' V\\n')\n",
-      "Ie2=(5-Ve2)/Re1;\n",
-      "print\"%s %.2f %s\"%('\\nIe2= ',Ie2,' mA\\n')\n",
-      "Ic2=Ie2*b/(1.+b);\n",
-      "print\"%s %.2f %s\"%('\\nIc2= ',Ic2,' mA\\n')\n",
-      "Ib2=Ie2/(1.+b);\n",
-      "print\"%s %.2f %s\"%('\\nIb2 ',Ib2,' mA\\n')\n",
-      "Ve1=Ie1*Re1-5;\n",
-      "print\"%s %.2f %s\"%('\\nVe1= ',Ve1,' V\\n')\n",
-      "Vc2=Ic2*Rc2-5.;\n",
-      "print\"%s %.2f %s\"%('\\nVc2= ',Vc2,' V\\n')\n",
-      "Vce1=Vc1-Ve1;\n",
-      "print\"%s %.2f %s\"%('\\nVce1= ',Vce1,'V\\n')\n",
-      "Vec2=Ve2-Vc2;\n",
-      "print\"%s %.2f %s\"%('\\nVec2= ',Vec2,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Thevenin rquivalent resistance=  33.33  KOhm\n",
-        "\n",
-        "\n",
-        "Thevenin equivalent voltage=  -1.67  V\n",
-        "\n",
-        "\n",
-        "Ib1=  0.01  mA\n",
-        "\n",
-        "\n",
-        "Ic1=  1.12  mA\n",
-        "\n",
-        "\n",
-        "Ie1=  1.13  mA\n",
-        "\n",
-        "\n",
-        "Vc1=  -0.48  V\n",
-        "\n",
-        "\n",
-        "Ir1=  1.10  mA\n",
-        "\n",
-        "\n",
-        "Ve2=  0.22  V\n",
-        "\n",
-        "\n",
-        "Ie2=  2.39  mA\n",
-        "\n",
-        "\n",
-        "Ic2=  2.36  mA\n",
-        "\n",
-        "\n",
-        "Ib2  0.02  mA\n",
-        "\n",
-        "\n",
-        "Ve1=  -2.74  V\n",
-        "\n",
-        "\n",
-        "Vc2=  -1.45  V\n",
-        "\n",
-        "\n",
-        "Vce1=  2.26 V\n",
-        "\n",
-        "\n",
-        "Vec2=  1.68  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 31
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter4.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter4.ipynb
deleted file mode 100755
index dfbff5bf..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter4.ipynb
+++ /dev/null
@@ -1,511 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:a988599b6e2af8c15b7ef7a59b8994eb09ea352b9faa5033a7a9c0aa8c680105"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter4-Basic BJT Amplifiers"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg174"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.1\n",
-      "b=100.;\n",
-      "Vcc=12.;\n",
-      "Vbe=0.7;\n",
-      "Rc=6.;\n",
-      "Rb=50.;\n",
-      "Vbb=1.2;\n",
-      "##dc solution\n",
-      "Ibq=(Vbb-Vbe)/Rb;\n",
-      "print\"%s %.2f %s\"%('\\nbase current=  ',Ibq,' mA\\n')\n",
-      "Icq=b*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Icq,' mA\\n')\n",
-      "Vceq=Vcc-Icq*Rc;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vceq,' V\\n')\n",
-      "##transistor is forward biased\n",
-      "##ac solution \n",
-      "V_T=0.026;##(V)\n",
-      "##small signal hybrid pi parameters\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "##Av=Vo/Vs=-(g_m*Rc)*r_pi/(r_pi+Rb)\n",
-      "Av=-(g_m*Rc)*r_pi/(r_pi+Rb);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=   0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  1.00  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  6.00  V\n",
-        "\n",
-        "\n",
-        "small signal resistance=  2.60  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  38.46  mA/V\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " -11.41 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg177"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.2\n",
-      "V_pi=50.;##(V)\n",
-      "Icq=1.;##(mA)\n",
-      "ro=V_pi/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal output resistance= ',ro,' KOhm\\n')\n",
-      "Rc=6.;\n",
-      "g_m=38.5;\n",
-      "r_pi=2.6;\n",
-      "Rb=50.;\n",
-      "Av=-(g_m)*(Rc*ro/(Rc+ro))*r_pi/(r_pi+Rb);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal output resistance=  50.00  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -10.19 \n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg190"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.4\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Va=100.;\n",
-      "V_T=0.026;##(V)\n",
-      "##from dc analysis\n",
-      "Icq=0.95;\n",
-      "Vceq=6.31;\n",
-      "##ac analysis\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "Rs=0.5;\n",
-      "Rc=6.;\n",
-      "ro=Va/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nro= ',ro,' KOhm\\n')\n",
-      "Av=-g_m*(5.9*r_pi/(5.9+r_pi))/((5.9*r_pi/(r_pi+5.9))+Rs)*ro*Rc/(ro+Rc);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n",
-      "Ri=5.9*r_pi/(r_pi+5.9);\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri,' KOhm\\n')\n",
-      "Ro=ro*Rc/(ro+Rc);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal resistance=  2.74  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  36.54  mA/V\n",
-        "\n",
-        "\n",
-        "ro=  105.26  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -163.64  \n",
-        "\n",
-        "\n",
-        "input resistance=  1.87  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  5.68  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg194"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.5\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Rc=2.;\n",
-      "Rs=0.5;\n",
-      "Icq=2.16;\n",
-      "V_T=0.026;##(V)\n",
-      "Vceq=4.8\n",
-      "##ac solution\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "##since Va=infinity,ro=Va/Icq is also infinity\n",
-      "Re=0.4;\n",
-      "Rib=r_pi+(1.+b)*Re;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the base= ',Rib,' KOhm\\n')\n",
-      "##Ri=R1||R2||Rib\n",
-      "Ri=10.*Rib/(10.+Rib);\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the amplifier= ',Ri,' KOhm\\n')\n",
-      "Av=-(1./(r_pi+(1.+b)*Re))*b*Rc*Ri/(Ri+Rs);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n",
-      "##by approximate expression\n",
-      "Av=-Rc/Re;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal resistance=  1.20  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  83.08  mA/V\n",
-        "\n",
-        "\n",
-        "input resistance to the base=  41.60  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance to the amplifier=  8.06  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -4.53 \n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -5.00 \n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg199"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.7\n",
-      "Iq=0.5;\n",
-      "b=120.;\n",
-      "Va=80.;\n",
-      "V_T=0.026;##(V)\n",
-      "rc=120.;##small signal collector resistance (KOhm)\n",
-      "##Icq=Iq\n",
-      "Icq=0.5;\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=Va/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal output resistance= ',ro,' KOhm\\n')\n",
-      "Av=-g_m*ro*rc/(ro+rc);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  19.23  mA/V\n",
-        "\n",
-        "\n",
-        "small signal output resistance=  160.00  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -1318.68  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg201"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.8\n",
-      "b=150.;Veb=0.7;\n",
-      "##dc solution\n",
-      "V2=10.;\n",
-      "V1=-10.;\n",
-      "V_T=0.026;##(V)\n",
-      "Rc=5.;\n",
-      "Rb=50.;\n",
-      "Re=10.;\n",
-      "Ibq=(V2-Veb)/(Rb+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nbase current ',Ibq,' mA\\n')\n",
-      "Icq=b*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Icq,' mA\\n')\n",
-      "Ieq=(1.+b)*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ieq,' mA\\n')\n",
-      "Vecq=V2-V1-Icq*Rc-Ieq*Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter collector voltage= ',Vecq,' V\\n')\n",
-      "##ac solution\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',g_m,'mA/V\\n')\n",
-      "##since Va=infinity,ro=Va/Icq is also infinity\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current  0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  0.89  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  0.90  mA\n",
-        "\n",
-        "\n",
-        "emitter collector voltage=  6.53  V\n",
-        "\n",
-        "\n",
-        "small signal resistance=  4.36  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance =  34.39 mA/V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-203"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.9\n",
-      "Ic=0.894;\n",
-      "i_C=2.*Ic;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum possible symmetrical peak to peak ac collector current= ',i_C,' mA\\n')\n",
-      "Rc=5.;\n",
-      "Rl=2.;\n",
-      "vo=i_C*Rc*Rl/(Rc+Rl);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum possible symmetrical peak to peak output voltage= ',vo,' V\\n')\n",
-      "iC=Ic+i_C*1/2.;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum instantaneous collector current= ',iC,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "maximum possible symmetrical peak to peak ac collector current=  1.79  mA\n",
-        "\n",
-        "\n",
-        "maximum possible symmetrical peak to peak output voltage=  2.55  V\n",
-        "\n",
-        "\n",
-        "maximum instantaneous collector current=  1.79  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg206"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 4.10\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "V_T=0.026;##(V)\n",
-      "Re=2.;\n",
-      "R1=50.;\n",
-      "R2=50.;\n",
-      "Rs=0.5;\n",
-      "Va=80.;\n",
-      "##by dc analysis\n",
-      "Icq=0.793;\n",
-      "Vceq=3.4;\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=Va/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal output resistance= ',ro,' KOhm\\n')\n",
-      "Rib=r_pi+(1.+b)*Re*ro/(ro+Re);\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the base= ',Rib,' KOhm\\n')\n",
-      "##Ri=R1||R2||Rib\n",
-      "x=R1*R2/(R1+R2);\n",
-      "Ri=x*Rib/(x+Rib);\n",
-      "print\"%s %.2f %s\"%('\\nRi= ',Ri,' KOhm\\n')\n",
-      "y=ro*Re/(ro+Re);\n",
-      "Av=(1./(r_pi+(1.+b)*y))*(1.+b)*y*Ri/(Ri+Rs);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal resistance=  3.28  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  30.50  mA/V\n",
-        "\n",
-        "\n",
-        "small signal output resistance=  100.88  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance to the base=  201.35  KOhm\n",
-        "\n",
-        "\n",
-        "Ri=  22.24  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  0.96  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter4_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter4_1.ipynb
deleted file mode 100755
index dfbff5bf..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter4_1.ipynb
+++ /dev/null
@@ -1,511 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:a988599b6e2af8c15b7ef7a59b8994eb09ea352b9faa5033a7a9c0aa8c680105"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter4-Basic BJT Amplifiers"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg174"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.1\n",
-      "b=100.;\n",
-      "Vcc=12.;\n",
-      "Vbe=0.7;\n",
-      "Rc=6.;\n",
-      "Rb=50.;\n",
-      "Vbb=1.2;\n",
-      "##dc solution\n",
-      "Ibq=(Vbb-Vbe)/Rb;\n",
-      "print\"%s %.2f %s\"%('\\nbase current=  ',Ibq,' mA\\n')\n",
-      "Icq=b*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Icq,' mA\\n')\n",
-      "Vceq=Vcc-Icq*Rc;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vceq,' V\\n')\n",
-      "##transistor is forward biased\n",
-      "##ac solution \n",
-      "V_T=0.026;##(V)\n",
-      "##small signal hybrid pi parameters\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "##Av=Vo/Vs=-(g_m*Rc)*r_pi/(r_pi+Rb)\n",
-      "Av=-(g_m*Rc)*r_pi/(r_pi+Rb);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=   0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  1.00  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  6.00  V\n",
-        "\n",
-        "\n",
-        "small signal resistance=  2.60  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  38.46  mA/V\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " -11.41 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg177"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.2\n",
-      "V_pi=50.;##(V)\n",
-      "Icq=1.;##(mA)\n",
-      "ro=V_pi/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal output resistance= ',ro,' KOhm\\n')\n",
-      "Rc=6.;\n",
-      "g_m=38.5;\n",
-      "r_pi=2.6;\n",
-      "Rb=50.;\n",
-      "Av=-(g_m)*(Rc*ro/(Rc+ro))*r_pi/(r_pi+Rb);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal output resistance=  50.00  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -10.19 \n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg190"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.4\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Va=100.;\n",
-      "V_T=0.026;##(V)\n",
-      "##from dc analysis\n",
-      "Icq=0.95;\n",
-      "Vceq=6.31;\n",
-      "##ac analysis\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "Rs=0.5;\n",
-      "Rc=6.;\n",
-      "ro=Va/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nro= ',ro,' KOhm\\n')\n",
-      "Av=-g_m*(5.9*r_pi/(5.9+r_pi))/((5.9*r_pi/(r_pi+5.9))+Rs)*ro*Rc/(ro+Rc);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n",
-      "Ri=5.9*r_pi/(r_pi+5.9);\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri,' KOhm\\n')\n",
-      "Ro=ro*Rc/(ro+Rc);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal resistance=  2.74  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  36.54  mA/V\n",
-        "\n",
-        "\n",
-        "ro=  105.26  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -163.64  \n",
-        "\n",
-        "\n",
-        "input resistance=  1.87  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  5.68  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg194"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.5\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Rc=2.;\n",
-      "Rs=0.5;\n",
-      "Icq=2.16;\n",
-      "V_T=0.026;##(V)\n",
-      "Vceq=4.8\n",
-      "##ac solution\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "##since Va=infinity,ro=Va/Icq is also infinity\n",
-      "Re=0.4;\n",
-      "Rib=r_pi+(1.+b)*Re;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the base= ',Rib,' KOhm\\n')\n",
-      "##Ri=R1||R2||Rib\n",
-      "Ri=10.*Rib/(10.+Rib);\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the amplifier= ',Ri,' KOhm\\n')\n",
-      "Av=-(1./(r_pi+(1.+b)*Re))*b*Rc*Ri/(Ri+Rs);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n",
-      "##by approximate expression\n",
-      "Av=-Rc/Re;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal resistance=  1.20  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  83.08  mA/V\n",
-        "\n",
-        "\n",
-        "input resistance to the base=  41.60  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance to the amplifier=  8.06  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -4.53 \n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -5.00 \n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg199"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.7\n",
-      "Iq=0.5;\n",
-      "b=120.;\n",
-      "Va=80.;\n",
-      "V_T=0.026;##(V)\n",
-      "rc=120.;##small signal collector resistance (KOhm)\n",
-      "##Icq=Iq\n",
-      "Icq=0.5;\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=Va/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal output resistance= ',ro,' KOhm\\n')\n",
-      "Av=-g_m*ro*rc/(ro+rc);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  19.23  mA/V\n",
-        "\n",
-        "\n",
-        "small signal output resistance=  160.00  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -1318.68  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg201"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.8\n",
-      "b=150.;Veb=0.7;\n",
-      "##dc solution\n",
-      "V2=10.;\n",
-      "V1=-10.;\n",
-      "V_T=0.026;##(V)\n",
-      "Rc=5.;\n",
-      "Rb=50.;\n",
-      "Re=10.;\n",
-      "Ibq=(V2-Veb)/(Rb+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nbase current ',Ibq,' mA\\n')\n",
-      "Icq=b*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Icq,' mA\\n')\n",
-      "Ieq=(1.+b)*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ieq,' mA\\n')\n",
-      "Vecq=V2-V1-Icq*Rc-Ieq*Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter collector voltage= ',Vecq,' V\\n')\n",
-      "##ac solution\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',g_m,'mA/V\\n')\n",
-      "##since Va=infinity,ro=Va/Icq is also infinity\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current  0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  0.89  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  0.90  mA\n",
-        "\n",
-        "\n",
-        "emitter collector voltage=  6.53  V\n",
-        "\n",
-        "\n",
-        "small signal resistance=  4.36  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance =  34.39 mA/V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-203"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.9\n",
-      "Ic=0.894;\n",
-      "i_C=2.*Ic;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum possible symmetrical peak to peak ac collector current= ',i_C,' mA\\n')\n",
-      "Rc=5.;\n",
-      "Rl=2.;\n",
-      "vo=i_C*Rc*Rl/(Rc+Rl);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum possible symmetrical peak to peak output voltage= ',vo,' V\\n')\n",
-      "iC=Ic+i_C*1/2.;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum instantaneous collector current= ',iC,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "maximum possible symmetrical peak to peak ac collector current=  1.79  mA\n",
-        "\n",
-        "\n",
-        "maximum possible symmetrical peak to peak output voltage=  2.55  V\n",
-        "\n",
-        "\n",
-        "maximum instantaneous collector current=  1.79  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg206"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 4.10\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "V_T=0.026;##(V)\n",
-      "Re=2.;\n",
-      "R1=50.;\n",
-      "R2=50.;\n",
-      "Rs=0.5;\n",
-      "Va=80.;\n",
-      "##by dc analysis\n",
-      "Icq=0.793;\n",
-      "Vceq=3.4;\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=Va/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal output resistance= ',ro,' KOhm\\n')\n",
-      "Rib=r_pi+(1.+b)*Re*ro/(ro+Re);\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the base= ',Rib,' KOhm\\n')\n",
-      "##Ri=R1||R2||Rib\n",
-      "x=R1*R2/(R1+R2);\n",
-      "Ri=x*Rib/(x+Rib);\n",
-      "print\"%s %.2f %s\"%('\\nRi= ',Ri,' KOhm\\n')\n",
-      "y=ro*Re/(ro+Re);\n",
-      "Av=(1./(r_pi+(1.+b)*y))*(1.+b)*y*Ri/(Ri+Rs);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal resistance=  3.28  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  30.50  mA/V\n",
-        "\n",
-        "\n",
-        "small signal output resistance=  100.88  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance to the base=  201.35  KOhm\n",
-        "\n",
-        "\n",
-        "Ri=  22.24  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  0.96  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter4_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter4_1_1.ipynb
deleted file mode 100755
index 474a3300..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter4_1_1.ipynb
+++ /dev/null
@@ -1,511 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:6cd0454c158d13a9f3c4fd9afab45debe741070024bd59dcb697aaffd2aec82d"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter4-Basic BJT Amplifiers"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg174"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.1\n",
-      "b=100.;\n",
-      "Vcc=12.;\n",
-      "Vbe=0.7;\n",
-      "Rc=6.;\n",
-      "Rb=50.;\n",
-      "Vbb=1.2;\n",
-      "##dc solution\n",
-      "Ibq=(Vbb-Vbe)/Rb;\n",
-      "print\"%s %.2f %s\"%('\\nbase current=  ',Ibq,' mA\\n')\n",
-      "Icq=b*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Icq,' mA\\n')\n",
-      "Vceq=Vcc-Icq*Rc;\n",
-      "print\"%s %.2f %s\"%('\\ncollector emitter voltage= ',Vceq,' V\\n')\n",
-      "##transistor is forward biased\n",
-      "##ac solution \n",
-      "V_T=0.026;##(V)\n",
-      "##small signal hybrid pi parameters\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "##Av=Vo/Vs=-(g_m*Rc)*r_pi/(r_pi+Rb)\n",
-      "Av=-(g_m*Rc)*r_pi/(r_pi+Rb);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current=   0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  1.00  mA\n",
-        "\n",
-        "\n",
-        "collector emitter voltage=  6.00  V\n",
-        "\n",
-        "\n",
-        "small signal resistance=  2.60  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  38.46  mA/V\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " -11.41 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg177"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.2\n",
-      "V_pi=50.;##(V)\n",
-      "Icq=1.;##(mA)\n",
-      "ro=V_pi/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal output resistance= ',ro,' KOhm\\n')\n",
-      "Rc=6.;\n",
-      "g_m=38.5;\n",
-      "r_pi=2.6;\n",
-      "Rb=50.;\n",
-      "Av=-(g_m)*(Rc*ro/(Rc+ro))*r_pi/(r_pi+Rb);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal output resistance=  50.00  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -10.19 \n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg190"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.4\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Va=100.;\n",
-      "V_T=0.026;##(V)\n",
-      "##from dc analysis\n",
-      "Icq=0.95;\n",
-      "Vceq=6.31;\n",
-      "##ac analysis\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "Rs=0.5;\n",
-      "Rc=6.;\n",
-      "ro=Va/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nro= ',ro,' KOhm\\n')\n",
-      "Av=-g_m*(5.9*r_pi/(5.9+r_pi))/((5.9*r_pi/(r_pi+5.9))+Rs)*ro*Rc/(ro+Rc);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n",
-      "Ri=5.9*r_pi/(r_pi+5.9);\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri,' KOhm\\n')\n",
-      "Ro=ro*Rc/(ro+Rc);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal resistance=  2.74  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  36.54  mA/V\n",
-        "\n",
-        "\n",
-        "ro=  105.26  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -163.64  \n",
-        "\n",
-        "\n",
-        "input resistance=  1.87  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  5.68  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg194"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.5\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Rc=2.;\n",
-      "Rs=0.5;\n",
-      "Icq=2.16;\n",
-      "V_T=0.026;##(V)\n",
-      "Vceq=4.8\n",
-      "##ac solution\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "##since Va=infinity,ro=Va/Icq is also infinity\n",
-      "Re=0.4;\n",
-      "Rib=r_pi+(1.+b)*Re;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the base= ',Rib,' KOhm\\n')\n",
-      "##Ri=R1||R2||Rib\n",
-      "Ri=10.*Rib/(10.+Rib);\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the amplifier= ',Ri,' KOhm\\n')\n",
-      "Av=-(1./(r_pi+(1.+b)*Re))*b*Rc*Ri/(Ri+Rs);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n",
-      "##by approximate expression\n",
-      "Av=-Rc/Re;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal resistance=  1.20  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  83.08  mA/V\n",
-        "\n",
-        "\n",
-        "input resistance to the base=  41.60  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance to the amplifier=  8.06  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -4.53 \n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -5.00 \n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg199"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.7\n",
-      "Iq=0.5;\n",
-      "b=120.;\n",
-      "Va=80.;\n",
-      "V_T=0.026;##(V)\n",
-      "rc=120.;##small signal collector resistance (KOhm)\n",
-      "##Icq=Iq\n",
-      "Icq=0.5;\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=Va/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal output resistance= ',ro,' KOhm\\n')\n",
-      "Av=-g_m*ro*rc/(ro+rc);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  19.23  mA/V\n",
-        "\n",
-        "\n",
-        "small signal output resistance=  160.00  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -1318.68  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg201"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.8\n",
-      "b=150.;Veb=0.7;\n",
-      "##dc solution\n",
-      "V2=10.;\n",
-      "V1=-10.;\n",
-      "V_T=0.026;##(V)\n",
-      "Rc=5.;\n",
-      "Rb=50.;\n",
-      "Re=10.;\n",
-      "Ibq=(V2-Veb)/(Rb+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nbase current ',Ibq,' mA\\n')\n",
-      "Icq=b*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\ncollector current= ',Icq,' mA\\n')\n",
-      "Ieq=(1.+b)*Ibq;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ieq,' mA\\n')\n",
-      "Vecq=V2-V1-Icq*Rc-Ieq*Re;\n",
-      "print\"%s %.2f %s\"%('\\nemitter collector voltage= ',Vecq,' V\\n')\n",
-      "##ac solution\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',g_m,'mA/V\\n')\n",
-      "##since Va=infinity,ro=Va/Icq is also infinity\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "base current  0.01  mA\n",
-        "\n",
-        "\n",
-        "collector current=  0.89  mA\n",
-        "\n",
-        "\n",
-        "emitter current=  0.90  mA\n",
-        "\n",
-        "\n",
-        "emitter collector voltage=  6.53  V\n",
-        "\n",
-        "\n",
-        "small signal resistance=  4.36  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance =  34.39 mA/V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-203"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 4.9\n",
-      "Ic=0.894;\n",
-      "i_C=2.*Ic;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum possible symmetrical peak to peak ac collector current= ',i_C,' mA\\n')\n",
-      "Rc=5.;\n",
-      "Rl=2.;\n",
-      "vo=i_C*Rc*Rl/(Rc+Rl);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum possible symmetrical peak to peak output voltage= ',vo,' V\\n')\n",
-      "iC=Ic+i_C*1/2.;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum instantaneous collector current= ',iC,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "maximum possible symmetrical peak to peak ac collector current=  1.79  mA\n",
-        "\n",
-        "\n",
-        "maximum possible symmetrical peak to peak output voltage=  2.55  V\n",
-        "\n",
-        "\n",
-        "maximum instantaneous collector current=  1.79  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg206"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 4.10\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "V_T=0.026;##(V)\n",
-      "Re=2.;\n",
-      "R1=50.;\n",
-      "R2=50.;\n",
-      "Rs=0.5;\n",
-      "Va=80.;\n",
-      "##by dc analysis\n",
-      "Icq=0.793;\n",
-      "Vceq=3.4;\n",
-      "r_pi=b*V_T/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal resistance= ',r_pi,' KOhm\\n')\n",
-      "g_m=Icq/V_T;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=Va/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal output resistance= ',ro,' KOhm\\n')\n",
-      "Rib=r_pi+(1.+b)*Re*ro/(ro+Re);\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance to the base= ',Rib,' KOhm\\n')\n",
-      "##Ri=R1||R2||Rib\n",
-      "x=R1*R2/(R1+R2);\n",
-      "Ri=x*Rib/(x+Rib);\n",
-      "print\"%s %.2f %s\"%('\\nRi= ',Ri,' KOhm\\n')\n",
-      "y=ro*Re/(ro+Re);\n",
-      "Av=(1./(r_pi+(1.+b)*y))*(1.+b)*y*Ri/(Ri+Rs);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal resistance=  3.28  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  30.50  mA/V\n",
-        "\n",
-        "\n",
-        "small signal output resistance=  100.88  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance to the base=  201.35  KOhm\n",
-        "\n",
-        "\n",
-        "Ri=  22.24  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  0.96  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter5.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter5.ipynb
deleted file mode 100755
index 204a2063..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter5.ipynb
+++ /dev/null
@@ -1,812 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:0555012832221206e793f4fc06592e55a682a07482b8e470e5ef81f7c83915c6"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter5-The Field Effect Transistor "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg252"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.1\n",
-      "Vtn=0.75;##(V)\n",
-      "W=40.*10**-6;##(cm)\n",
-      "L=4.*10**-6;##(cm)\n",
-      "u=650.;##(cm)\n",
-      "Iox=450.*10**-11;\n",
-      "e=3.9*8.86*10**-14;\n",
-      "Kn=W*u*e/(2.*L*Iox);\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameter= ',Kn,' mA/V^2\\n')\n",
-      "Vgs=2.*Vtn;\n",
-      "i_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',i_D,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "conduction parameter=  0.25  mA/V^2\n",
-        "\n",
-        "\n",
-        "drain current=  0.14  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg256"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 5.2\n",
-      "Kp=0.2;##(mA/V^2)\n",
-      "Vtp=0.5;\n",
-      "iD=0.5;\n",
-      "Vsg=math.sqrt(iD/Kp)-Vtp;\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vsg,' V\\n')\n",
-      "##to bias in p channel MOSFET \n",
-      "Vsd=Vsg+Vtp;\n",
-      "print\"%s %.2f %s\"%('\\nVsd= ',Vsd,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  1.08  V\n",
-        "\n",
-        "\n",
-        "Vsd=  1.58  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg264"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 5.3\n",
-      "R1=30.;\n",
-      "R2=20.;\n",
-      "RD=20.;\n",
-      "Vdd=5.;\n",
-      "Vtn=1.;\n",
-      "Kn=0.1;\n",
-      "Vgs=R2*Vdd/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vgs,' V\\n')\n",
-      "I_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\nthe drain current= ',I_D,' mA\\n')\n",
-      "Vds=Vdd-I_D*RD;\n",
-      "print\"%s %.2f %s\"%('\\ndrain to source voltage= ',Vds,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  2.00  V\n",
-        "\n",
-        "\n",
-        "the drain current=  0.10  mA\n",
-        "\n",
-        "\n",
-        "drain to source voltage=  3.00  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg265"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.4\n",
-      "R1=50.;\n",
-      "R2=50.;\n",
-      "RD=7.5;\n",
-      "Vdd=5.;\n",
-      "Vtp=-0.8;\n",
-      "Vg=2.5;\n",
-      "Kp=0.2;\n",
-      "Vo=R2*Vdd/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nVo= ',Vo,' V\\n')\n",
-      "Vsg=Vdd-Vg;\n",
-      "print\"%s %.2f %s\"%('\\nsource to gate voltage= ',Vsg,' V\\n')\n",
-      "I_D=Kp*(Vsg+Vtp)**2;\n",
-      "print\"%s %.2f %s\"%('\\nthe drain current= ',I_D,' mA\\n')\n",
-      "Vsd=Vdd-I_D*RD;\n",
-      "print\"%s %.2f %s\"%('\\nsource to drain voltage= ',Vsd,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vo=  2.50  V\n",
-        "\n",
-        "\n",
-        "source to gate voltage=  2.50  V\n",
-        "\n",
-        "\n",
-        "the drain current=  0.58  mA\n",
-        "\n",
-        "\n",
-        "source to drain voltage=  0.67  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg269"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.6\n",
-      "Vtn=2.;\n",
-      "Kn=80.*10**-3;\n",
-      "##x=W/L\n",
-      "x=4.;\n",
-      "I_D=0.5;\n",
-      "##I_D=Kn*x*((Vgs-Vtn)^2)/2;\n",
-      "Vgs=math.sqrt(I_D*2./(Kn*x))+2.;\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vgs,' V\\n')\n",
-      "##y=R1+R2\n",
-      "Rs=2.;\n",
-      "y=10./0.05;\n",
-      "print\"%s %.2f %s\"%('\\nR1+R2= ',y,' Kohm\\n')\n",
-      "##Vgs=Vg-Vs=(R2/(R1+R2)*10-5)-I_D*Rs+5\n",
-      "R2=(y/10.)*(Vgs+I_D*Rs);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n",
-      "R1=y-R2;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  3.77  V\n",
-        "\n",
-        "\n",
-        "R1+R2=  200.00  Kohm\n",
-        "\n",
-        "\n",
-        "R2=  95.36  KOhm\n",
-        "\n",
-        "\n",
-        "R1=  104.64  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg270"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.7\n",
-      "Vtn=0.8;\n",
-      "Kn=80.;\n",
-      "##x=W/L\n",
-      "x=3.;\n",
-      "I_D=250.;\n",
-      "Vd=2.5;\n",
-      "##I_D=Kn/2*x*(Vgs-Vtn)^2\n",
-      "Vgs=math.sqrt(I_D*2./(Kn*x))+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vgs,' V\\n')\n",
-      "Vs=-Vgs\n",
-      "##I_D=(5-Vd)/Rd\n",
-      "Rd=(5.-Vd)/I_D;\n",
-      "print\"%s %.2f %s\"%('\\nRd= ',Rd,' KOhm\\n')\n",
-      "Vds=Vd-Vs;\n",
-      "print\"%s %.2f %s\"%('\\nVds= ',Vds,' V\\n')\n",
-      "Vdssat=Vgs-Vtn\n",
-      "##since Vds>Vdssat transistor is biased in saturation region\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  2.24  V\n",
-        "\n",
-        "\n",
-        "Rd=  0.01  KOhm\n",
-        "\n",
-        "\n",
-        "Vds=  4.74  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg272"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "from sympy import *\n",
-      "##Example 5.8\n",
-      "Vtn=0.8;\n",
-      "Kn=0.05;\n",
-      "##I_D=Kn*(Vgs-Vtn)^2\n",
-      "##Vds=Vgs=5-I_D*Rs\n",
-      "##combining these two equations we obtain 0.5(Vgs)^2+0.2Vgs-4.68\n",
-      "import numpy\n",
-      "from numpy.polynomial import Polynomial as P\n",
-      "p = P([1, 5, 6])\n",
-      "p.roots()\n",
-      "\n",
-      "\n",
-      "print('',p.roots(),' V\\n')\n",
-      "##assuming transistor is conducting ,Vgs must be greater than threshold voltage\n",
-      "Vgs=2.87;\n",
-      "I_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',I_D,' mA\\n')\n",
-      "#ans is varying due to round of error in book calculations are done wrong\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "('', array([-0.5       , -0.33333333]), ' V\\n')\n",
-        "\n",
-        "drain current=  0.21  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg277"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 5.10\n",
-      "Vtn=-2.;\n",
-      "Kn=0.1;\n",
-      "Vdd=5.;\n",
-      "Rs=5.;\n",
-      "Vgs=0.;\n",
-      "I_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',I_D,' mA\\n')\n",
-      "Vds=Vdd-I_D*Rs;\n",
-      "print\"%s %.2f %s\"%('\\ndc drain to source voltage= ',Vds,' V\\n')\n",
-      "Vdssat=Vgs-Vtn\n",
-      "##since Vds>Vdssat transisyor is biased in saturation region\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "drain current=  0.40  mA\n",
-        "\n",
-        "\n",
-        "dc drain to source voltage=  3.00  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg277"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "\n",
-      "##Example 5.11\n",
-      "Vtnd=1;\n",
-      "Vtnl=-2;\n",
-      "Knd=50;\n",
-      "Knl=10;\n",
-      "Vt=5;\n",
-      "import numpy\n",
-      "from numpy.polynomial import Polynomial as P\n",
-      "p = P([4, -40, 5])\n",
-      "p.roots()\n",
-      "\n",
-      "\n",
-      "print('\\npossible solutions ::',p.roots(),'')\n",
-      "##since output voltage cannot be greater than supply voltage 5V\n",
-      "Vo=0.1;##(V)\n",
-      "I_D=Knl*(-Vtnl)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',I_D,' microA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "('\\npossible solutions ::', array([ 0.10128226,  7.89871774]), '')\n",
-        "\n",
-        "drain current=  40.00  microA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg282"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 5.13\n",
-      "Kn1=0.2;\n",
-      "Kn2=0.1;\n",
-      "Kn3=0.1;\n",
-      "Kn4=0.1;\n",
-      "Vtn1=1.;\n",
-      "Vtn2=1.;\n",
-      "Vtn3=1.;\n",
-      "Vtn4=1.;\n",
-      "V2=-5.;\n",
-      "Vgs3=(math.sqrt(Kn4/Kn3)*(-V2-Vtn4)+Vtn3)/(1.+math.sqrt(Kn4/Kn3));\n",
-      "print\"%s %.2f %s\"%('\\nVgs3= ',Vgs3,' V\\n')\n",
-      "Iq=Kn3*(Vgs3-Vtn3)**2;\n",
-      "print\"%s %.2f %s\"%('\\nbias current= ',Iq,' mA\\n')\n",
-      "Vgs1=math.sqrt(Iq/Kn1)+Vtn1;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage on M1= ',Vgs1,' V\\n')\n",
-      "Vds2=-V2-Vgs1;\n",
-      "print\"%s %.2f %s\"%('\\ndrain to source voltage on M2= ',Vds2,' V\\n')\n",
-      "Vgs2=Vgs3;\n",
-      "Vdssat=Vgs2-Vtn2\n",
-      "##since Vds2>Vdssat M2 is biased in saturation region\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs3=  2.50  V\n",
-        "\n",
-        "\n",
-        "bias current=  0.23  mA\n",
-        "\n",
-        "\n",
-        "gate to source voltage on M1=  2.06  V\n",
-        "\n",
-        "\n",
-        "drain to source voltage on M2=  2.94  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 16
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg284"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.14\n",
-      "I_D=0.5;\n",
-      "Vds=6.;\n",
-      "Kn=80.*10**-6;\n",
-      "Vgs=5.;\n",
-      "Vtn=1.;\n",
-      "##x=W/L\n",
-      "x=I_D*2./(Kn*(Vgs-Vtn)**2);\n",
-      "print(x,\"W/L \")\n",
-      "##maximum power dissipation in transistor \n",
-      "Pmax=Vds*I_D;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipation in transistor= ',Pmax,' W\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "(781.2500000000001, 'W/L ')\n",
-        "\n",
-        "maximum power dissipation in transistor=  3.00  W\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 17
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg293"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy  \n",
-      "##Example 5.16\n",
-      "Idss=2.;##(mA) saturation current\n",
-      "Vp=-3.5;##(V) pinch off voltage\n",
-      "Vgs=numpy.array([[0, Vp/4. ,Vp/2.]])\n",
-      "I_D=Idss*(1.-Vgs/Vp)**2;\n",
-      "print (I_D)\n",
-      "Vds=Vgs-Vp;\n",
-      "print (Vds)\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "[[ 2.     1.125  0.5  ]]\n",
-        "[[ 3.5    2.625  1.75 ]]\n"
-       ]
-      }
-     ],
-     "prompt_number": 18
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg295"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.17\n",
-      "Idss=5.;##mA\n",
-      "Vp=-4.;\n",
-      "Vdd=10.;\n",
-      "I_D=2.;\n",
-      "Vds=6.;\n",
-      "##I_D=Idss*(1-Vgs/Vp)^2\n",
-      "Vgs=(1.-math.sqrt(I_D/Idss))*Vp;\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vgs,' V\\n')\n",
-      "Rs=-Vgs/I_D;\n",
-      "print\"%s %.2f %s\"%('\\nRs= ',Rs,' KOhm\\n')\n",
-      "Rd=(Vdd-Vds-I_D*Rs)/I_D;\n",
-      "print\"%s %.2f %s\"%('\\nRd= ',Rd,' KOhm\\n')\n",
-      "Vgs-Vp\n",
-      "##since Vds>Vgs-Vp JFET is biased in saturation\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  -1.47  V\n",
-        "\n",
-        "\n",
-        "Rs=  0.74  KOhm\n",
-        "\n",
-        "\n",
-        "Rd=  1.26  KOhm\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 19,
-       "text": [
-        "2.5298221281347035"
-       ]
-      }
-     ],
-     "prompt_number": 19
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex19-pg298"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.19\n",
-      "Idss=2.5;\n",
-      "Vp=2.5;\n",
-      "I_D=0.8;\n",
-      "##I_D=Iq=0.8*10^-3=(Vd-(-9))/Rd\n",
-      "Vd=0.8*4.-9;\n",
-      "print\"%s %.2f %s\"%('\\nVd = ',Vd,'V\\n')\n",
-      "##I_D=Idss*(1-Vgs/Vp)^2;\n",
-      "Vgs=(1.-math.sqrt(I_D/Idss))*Vp;\n",
-      "print\"%s %.2f %s\"%('\\nVgs = ',Vgs,'V\\n')\n",
-      "Vs=1-Vgs;\n",
-      "print\"%s %.2f %s\"%('\\nVs= ',Vs,' V\\n')\n",
-      "Vsd=Vs-Vd;\n",
-      "print\"%s %.2f %s\"%('\\nVsd= ',Vsd,' V\\n')\n",
-      "Vp-Vgs\n",
-      "##since Vsd>Vp-Vgs JFET is biased in saturation\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vd =  -5.80 V\n",
-        "\n",
-        "\n",
-        "Vgs =  1.09 V\n",
-        "\n",
-        "\n",
-        "Vs=  -0.09  V\n",
-        "\n",
-        "\n",
-        "Vsd=  5.71  V\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 20,
-       "text": [
-        "1.414213562373095"
-       ]
-      }
-     ],
-     "prompt_number": 20
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex20-pg299"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.20\n",
-      "Vtn=0.24;\n",
-      "Kn=1.1;\n",
-      "##x=R1+R2=50000\n",
-      "x=50.;\n",
-      "Vgs=0.5;\n",
-      "Vds=2.5;\n",
-      "Vdd=4.;\n",
-      "Rd=6.7;\n",
-      "I_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',I_D,' mA\\n')\n",
-      "Vd=Vdd-I_D*Rd;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at drain= ',Vd,' V\\n')\n",
-      "Vs=Vd-Vds;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at source = ',Vs,'V\\n')\n",
-      "Rs=Vs/I_D;\n",
-      "print\"%s %.2f %s\"%('\\nsource resistance = ',Rs,'KOhm\\n')\n",
-      "Vg=Vgs+Vs;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at the gate= ',Vg,' V\\n')\n",
-      "##Vg=R2*Vdd/(R2+R1)\n",
-      "R2=Vg*x/Vdd;\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n",
-      "R1=x-R2;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n",
-      "Vgs-Vtn\n",
-      "##since Vds>Vgs-Vtn transistor is biased in saturation\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "drain current=  0.07  mA\n",
-        "\n",
-        "\n",
-        "voltage at drain=  3.50  V\n",
-        "\n",
-        "\n",
-        "voltage at source =  1.00 V\n",
-        "\n",
-        "\n",
-        "source resistance =  13.47 KOhm\n",
-        "\n",
-        "\n",
-        "voltage at the gate=  1.50  V\n",
-        "\n",
-        "\n",
-        "R2=  18.77  KOhm\n",
-        "\n",
-        "\n",
-        "R1=  31.23  KOhm\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 21,
-       "text": [
-        "0.26"
-       ]
-      }
-     ],
-     "prompt_number": 21
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter5_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter5_1.ipynb
deleted file mode 100755
index 204a2063..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter5_1.ipynb
+++ /dev/null
@@ -1,812 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:0555012832221206e793f4fc06592e55a682a07482b8e470e5ef81f7c83915c6"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter5-The Field Effect Transistor "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg252"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.1\n",
-      "Vtn=0.75;##(V)\n",
-      "W=40.*10**-6;##(cm)\n",
-      "L=4.*10**-6;##(cm)\n",
-      "u=650.;##(cm)\n",
-      "Iox=450.*10**-11;\n",
-      "e=3.9*8.86*10**-14;\n",
-      "Kn=W*u*e/(2.*L*Iox);\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameter= ',Kn,' mA/V^2\\n')\n",
-      "Vgs=2.*Vtn;\n",
-      "i_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',i_D,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "conduction parameter=  0.25  mA/V^2\n",
-        "\n",
-        "\n",
-        "drain current=  0.14  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg256"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 5.2\n",
-      "Kp=0.2;##(mA/V^2)\n",
-      "Vtp=0.5;\n",
-      "iD=0.5;\n",
-      "Vsg=math.sqrt(iD/Kp)-Vtp;\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vsg,' V\\n')\n",
-      "##to bias in p channel MOSFET \n",
-      "Vsd=Vsg+Vtp;\n",
-      "print\"%s %.2f %s\"%('\\nVsd= ',Vsd,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  1.08  V\n",
-        "\n",
-        "\n",
-        "Vsd=  1.58  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg264"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 5.3\n",
-      "R1=30.;\n",
-      "R2=20.;\n",
-      "RD=20.;\n",
-      "Vdd=5.;\n",
-      "Vtn=1.;\n",
-      "Kn=0.1;\n",
-      "Vgs=R2*Vdd/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vgs,' V\\n')\n",
-      "I_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\nthe drain current= ',I_D,' mA\\n')\n",
-      "Vds=Vdd-I_D*RD;\n",
-      "print\"%s %.2f %s\"%('\\ndrain to source voltage= ',Vds,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  2.00  V\n",
-        "\n",
-        "\n",
-        "the drain current=  0.10  mA\n",
-        "\n",
-        "\n",
-        "drain to source voltage=  3.00  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg265"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.4\n",
-      "R1=50.;\n",
-      "R2=50.;\n",
-      "RD=7.5;\n",
-      "Vdd=5.;\n",
-      "Vtp=-0.8;\n",
-      "Vg=2.5;\n",
-      "Kp=0.2;\n",
-      "Vo=R2*Vdd/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nVo= ',Vo,' V\\n')\n",
-      "Vsg=Vdd-Vg;\n",
-      "print\"%s %.2f %s\"%('\\nsource to gate voltage= ',Vsg,' V\\n')\n",
-      "I_D=Kp*(Vsg+Vtp)**2;\n",
-      "print\"%s %.2f %s\"%('\\nthe drain current= ',I_D,' mA\\n')\n",
-      "Vsd=Vdd-I_D*RD;\n",
-      "print\"%s %.2f %s\"%('\\nsource to drain voltage= ',Vsd,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vo=  2.50  V\n",
-        "\n",
-        "\n",
-        "source to gate voltage=  2.50  V\n",
-        "\n",
-        "\n",
-        "the drain current=  0.58  mA\n",
-        "\n",
-        "\n",
-        "source to drain voltage=  0.67  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg269"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.6\n",
-      "Vtn=2.;\n",
-      "Kn=80.*10**-3;\n",
-      "##x=W/L\n",
-      "x=4.;\n",
-      "I_D=0.5;\n",
-      "##I_D=Kn*x*((Vgs-Vtn)^2)/2;\n",
-      "Vgs=math.sqrt(I_D*2./(Kn*x))+2.;\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vgs,' V\\n')\n",
-      "##y=R1+R2\n",
-      "Rs=2.;\n",
-      "y=10./0.05;\n",
-      "print\"%s %.2f %s\"%('\\nR1+R2= ',y,' Kohm\\n')\n",
-      "##Vgs=Vg-Vs=(R2/(R1+R2)*10-5)-I_D*Rs+5\n",
-      "R2=(y/10.)*(Vgs+I_D*Rs);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n",
-      "R1=y-R2;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  3.77  V\n",
-        "\n",
-        "\n",
-        "R1+R2=  200.00  Kohm\n",
-        "\n",
-        "\n",
-        "R2=  95.36  KOhm\n",
-        "\n",
-        "\n",
-        "R1=  104.64  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg270"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.7\n",
-      "Vtn=0.8;\n",
-      "Kn=80.;\n",
-      "##x=W/L\n",
-      "x=3.;\n",
-      "I_D=250.;\n",
-      "Vd=2.5;\n",
-      "##I_D=Kn/2*x*(Vgs-Vtn)^2\n",
-      "Vgs=math.sqrt(I_D*2./(Kn*x))+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vgs,' V\\n')\n",
-      "Vs=-Vgs\n",
-      "##I_D=(5-Vd)/Rd\n",
-      "Rd=(5.-Vd)/I_D;\n",
-      "print\"%s %.2f %s\"%('\\nRd= ',Rd,' KOhm\\n')\n",
-      "Vds=Vd-Vs;\n",
-      "print\"%s %.2f %s\"%('\\nVds= ',Vds,' V\\n')\n",
-      "Vdssat=Vgs-Vtn\n",
-      "##since Vds>Vdssat transistor is biased in saturation region\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  2.24  V\n",
-        "\n",
-        "\n",
-        "Rd=  0.01  KOhm\n",
-        "\n",
-        "\n",
-        "Vds=  4.74  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg272"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "from sympy import *\n",
-      "##Example 5.8\n",
-      "Vtn=0.8;\n",
-      "Kn=0.05;\n",
-      "##I_D=Kn*(Vgs-Vtn)^2\n",
-      "##Vds=Vgs=5-I_D*Rs\n",
-      "##combining these two equations we obtain 0.5(Vgs)^2+0.2Vgs-4.68\n",
-      "import numpy\n",
-      "from numpy.polynomial import Polynomial as P\n",
-      "p = P([1, 5, 6])\n",
-      "p.roots()\n",
-      "\n",
-      "\n",
-      "print('',p.roots(),' V\\n')\n",
-      "##assuming transistor is conducting ,Vgs must be greater than threshold voltage\n",
-      "Vgs=2.87;\n",
-      "I_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',I_D,' mA\\n')\n",
-      "#ans is varying due to round of error in book calculations are done wrong\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "('', array([-0.5       , -0.33333333]), ' V\\n')\n",
-        "\n",
-        "drain current=  0.21  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg277"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 5.10\n",
-      "Vtn=-2.;\n",
-      "Kn=0.1;\n",
-      "Vdd=5.;\n",
-      "Rs=5.;\n",
-      "Vgs=0.;\n",
-      "I_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',I_D,' mA\\n')\n",
-      "Vds=Vdd-I_D*Rs;\n",
-      "print\"%s %.2f %s\"%('\\ndc drain to source voltage= ',Vds,' V\\n')\n",
-      "Vdssat=Vgs-Vtn\n",
-      "##since Vds>Vdssat transisyor is biased in saturation region\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "drain current=  0.40  mA\n",
-        "\n",
-        "\n",
-        "dc drain to source voltage=  3.00  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg277"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "\n",
-      "##Example 5.11\n",
-      "Vtnd=1;\n",
-      "Vtnl=-2;\n",
-      "Knd=50;\n",
-      "Knl=10;\n",
-      "Vt=5;\n",
-      "import numpy\n",
-      "from numpy.polynomial import Polynomial as P\n",
-      "p = P([4, -40, 5])\n",
-      "p.roots()\n",
-      "\n",
-      "\n",
-      "print('\\npossible solutions ::',p.roots(),'')\n",
-      "##since output voltage cannot be greater than supply voltage 5V\n",
-      "Vo=0.1;##(V)\n",
-      "I_D=Knl*(-Vtnl)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',I_D,' microA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "('\\npossible solutions ::', array([ 0.10128226,  7.89871774]), '')\n",
-        "\n",
-        "drain current=  40.00  microA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg282"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 5.13\n",
-      "Kn1=0.2;\n",
-      "Kn2=0.1;\n",
-      "Kn3=0.1;\n",
-      "Kn4=0.1;\n",
-      "Vtn1=1.;\n",
-      "Vtn2=1.;\n",
-      "Vtn3=1.;\n",
-      "Vtn4=1.;\n",
-      "V2=-5.;\n",
-      "Vgs3=(math.sqrt(Kn4/Kn3)*(-V2-Vtn4)+Vtn3)/(1.+math.sqrt(Kn4/Kn3));\n",
-      "print\"%s %.2f %s\"%('\\nVgs3= ',Vgs3,' V\\n')\n",
-      "Iq=Kn3*(Vgs3-Vtn3)**2;\n",
-      "print\"%s %.2f %s\"%('\\nbias current= ',Iq,' mA\\n')\n",
-      "Vgs1=math.sqrt(Iq/Kn1)+Vtn1;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage on M1= ',Vgs1,' V\\n')\n",
-      "Vds2=-V2-Vgs1;\n",
-      "print\"%s %.2f %s\"%('\\ndrain to source voltage on M2= ',Vds2,' V\\n')\n",
-      "Vgs2=Vgs3;\n",
-      "Vdssat=Vgs2-Vtn2\n",
-      "##since Vds2>Vdssat M2 is biased in saturation region\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs3=  2.50  V\n",
-        "\n",
-        "\n",
-        "bias current=  0.23  mA\n",
-        "\n",
-        "\n",
-        "gate to source voltage on M1=  2.06  V\n",
-        "\n",
-        "\n",
-        "drain to source voltage on M2=  2.94  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 16
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg284"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.14\n",
-      "I_D=0.5;\n",
-      "Vds=6.;\n",
-      "Kn=80.*10**-6;\n",
-      "Vgs=5.;\n",
-      "Vtn=1.;\n",
-      "##x=W/L\n",
-      "x=I_D*2./(Kn*(Vgs-Vtn)**2);\n",
-      "print(x,\"W/L \")\n",
-      "##maximum power dissipation in transistor \n",
-      "Pmax=Vds*I_D;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipation in transistor= ',Pmax,' W\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "(781.2500000000001, 'W/L ')\n",
-        "\n",
-        "maximum power dissipation in transistor=  3.00  W\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 17
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg293"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy  \n",
-      "##Example 5.16\n",
-      "Idss=2.;##(mA) saturation current\n",
-      "Vp=-3.5;##(V) pinch off voltage\n",
-      "Vgs=numpy.array([[0, Vp/4. ,Vp/2.]])\n",
-      "I_D=Idss*(1.-Vgs/Vp)**2;\n",
-      "print (I_D)\n",
-      "Vds=Vgs-Vp;\n",
-      "print (Vds)\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "[[ 2.     1.125  0.5  ]]\n",
-        "[[ 3.5    2.625  1.75 ]]\n"
-       ]
-      }
-     ],
-     "prompt_number": 18
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg295"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.17\n",
-      "Idss=5.;##mA\n",
-      "Vp=-4.;\n",
-      "Vdd=10.;\n",
-      "I_D=2.;\n",
-      "Vds=6.;\n",
-      "##I_D=Idss*(1-Vgs/Vp)^2\n",
-      "Vgs=(1.-math.sqrt(I_D/Idss))*Vp;\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vgs,' V\\n')\n",
-      "Rs=-Vgs/I_D;\n",
-      "print\"%s %.2f %s\"%('\\nRs= ',Rs,' KOhm\\n')\n",
-      "Rd=(Vdd-Vds-I_D*Rs)/I_D;\n",
-      "print\"%s %.2f %s\"%('\\nRd= ',Rd,' KOhm\\n')\n",
-      "Vgs-Vp\n",
-      "##since Vds>Vgs-Vp JFET is biased in saturation\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  -1.47  V\n",
-        "\n",
-        "\n",
-        "Rs=  0.74  KOhm\n",
-        "\n",
-        "\n",
-        "Rd=  1.26  KOhm\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 19,
-       "text": [
-        "2.5298221281347035"
-       ]
-      }
-     ],
-     "prompt_number": 19
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex19-pg298"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.19\n",
-      "Idss=2.5;\n",
-      "Vp=2.5;\n",
-      "I_D=0.8;\n",
-      "##I_D=Iq=0.8*10^-3=(Vd-(-9))/Rd\n",
-      "Vd=0.8*4.-9;\n",
-      "print\"%s %.2f %s\"%('\\nVd = ',Vd,'V\\n')\n",
-      "##I_D=Idss*(1-Vgs/Vp)^2;\n",
-      "Vgs=(1.-math.sqrt(I_D/Idss))*Vp;\n",
-      "print\"%s %.2f %s\"%('\\nVgs = ',Vgs,'V\\n')\n",
-      "Vs=1-Vgs;\n",
-      "print\"%s %.2f %s\"%('\\nVs= ',Vs,' V\\n')\n",
-      "Vsd=Vs-Vd;\n",
-      "print\"%s %.2f %s\"%('\\nVsd= ',Vsd,' V\\n')\n",
-      "Vp-Vgs\n",
-      "##since Vsd>Vp-Vgs JFET is biased in saturation\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vd =  -5.80 V\n",
-        "\n",
-        "\n",
-        "Vgs =  1.09 V\n",
-        "\n",
-        "\n",
-        "Vs=  -0.09  V\n",
-        "\n",
-        "\n",
-        "Vsd=  5.71  V\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 20,
-       "text": [
-        "1.414213562373095"
-       ]
-      }
-     ],
-     "prompt_number": 20
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex20-pg299"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.20\n",
-      "Vtn=0.24;\n",
-      "Kn=1.1;\n",
-      "##x=R1+R2=50000\n",
-      "x=50.;\n",
-      "Vgs=0.5;\n",
-      "Vds=2.5;\n",
-      "Vdd=4.;\n",
-      "Rd=6.7;\n",
-      "I_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',I_D,' mA\\n')\n",
-      "Vd=Vdd-I_D*Rd;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at drain= ',Vd,' V\\n')\n",
-      "Vs=Vd-Vds;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at source = ',Vs,'V\\n')\n",
-      "Rs=Vs/I_D;\n",
-      "print\"%s %.2f %s\"%('\\nsource resistance = ',Rs,'KOhm\\n')\n",
-      "Vg=Vgs+Vs;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at the gate= ',Vg,' V\\n')\n",
-      "##Vg=R2*Vdd/(R2+R1)\n",
-      "R2=Vg*x/Vdd;\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n",
-      "R1=x-R2;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n",
-      "Vgs-Vtn\n",
-      "##since Vds>Vgs-Vtn transistor is biased in saturation\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "drain current=  0.07  mA\n",
-        "\n",
-        "\n",
-        "voltage at drain=  3.50  V\n",
-        "\n",
-        "\n",
-        "voltage at source =  1.00 V\n",
-        "\n",
-        "\n",
-        "source resistance =  13.47 KOhm\n",
-        "\n",
-        "\n",
-        "voltage at the gate=  1.50  V\n",
-        "\n",
-        "\n",
-        "R2=  18.77  KOhm\n",
-        "\n",
-        "\n",
-        "R1=  31.23  KOhm\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 21,
-       "text": [
-        "0.26"
-       ]
-      }
-     ],
-     "prompt_number": 21
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter5_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter5_1_1.ipynb
deleted file mode 100755
index f4bc5a6b..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter5_1_1.ipynb
+++ /dev/null
@@ -1,812 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:94a278ecbe0a391fb4d9353ffc9aa9e2a6d1780bede99089ee306c07fa367982"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter5-The Field Effect Transistor "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg252"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.1\n",
-      "Vtn=0.75;##(V)\n",
-      "W=40.*10**-6;##(cm)\n",
-      "L=4.*10**-6;##(cm)\n",
-      "u=650.;##(cm)\n",
-      "Iox=450.*10**-11;\n",
-      "e=3.9*8.86*10**-14;\n",
-      "Kn=W*u*e/(2.*L*Iox);\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameter= ',Kn,' mA/V^2\\n')\n",
-      "Vgs=2.*Vtn;\n",
-      "i_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',i_D,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "conduction parameter=  0.25  mA/V^2\n",
-        "\n",
-        "\n",
-        "drain current=  0.14  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg256"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 5.2\n",
-      "Kp=0.2;##(mA/V^2)\n",
-      "Vtp=0.5;\n",
-      "iD=0.5;\n",
-      "Vsg=math.sqrt(iD/Kp)-Vtp;\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vsg,' V\\n')\n",
-      "##to bias in p channel MOSFET \n",
-      "Vsd=Vsg+Vtp;\n",
-      "print\"%s %.2f %s\"%('\\nVsd= ',Vsd,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  1.08  V\n",
-        "\n",
-        "\n",
-        "Vsd=  1.58  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg264"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 5.3\n",
-      "R1=30.;\n",
-      "R2=20.;\n",
-      "RD=20.;\n",
-      "Vdd=5.;\n",
-      "Vtn=1.;\n",
-      "Kn=0.1;\n",
-      "Vgs=R2*Vdd/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vgs,' V\\n')\n",
-      "I_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\nthe drain current= ',I_D,' mA\\n')\n",
-      "Vds=Vdd-I_D*RD;\n",
-      "print\"%s %.2f %s\"%('\\ndrain to source voltage= ',Vds,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  2.00  V\n",
-        "\n",
-        "\n",
-        "the drain current=  0.10  mA\n",
-        "\n",
-        "\n",
-        "drain to source voltage=  3.00  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg265"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.4\n",
-      "R1=50.;\n",
-      "R2=50.;\n",
-      "RD=7.5;\n",
-      "Vdd=5.;\n",
-      "Vtp=-0.8;\n",
-      "Vg=2.5;\n",
-      "Kp=0.2;\n",
-      "Vo=R2*Vdd/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\nVo= ',Vo,' V\\n')\n",
-      "Vsg=Vdd-Vg;\n",
-      "print\"%s %.2f %s\"%('\\nsource to gate voltage= ',Vsg,' V\\n')\n",
-      "I_D=Kp*(Vsg+Vtp)**2;\n",
-      "print\"%s %.2f %s\"%('\\nthe drain current= ',I_D,' mA\\n')\n",
-      "Vsd=Vdd-I_D*RD;\n",
-      "print\"%s %.2f %s\"%('\\nsource to drain voltage= ',Vsd,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vo=  2.50  V\n",
-        "\n",
-        "\n",
-        "source to gate voltage=  2.50  V\n",
-        "\n",
-        "\n",
-        "the drain current=  0.58  mA\n",
-        "\n",
-        "\n",
-        "source to drain voltage=  0.67  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg269"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.6\n",
-      "Vtn=2.;\n",
-      "Kn=80.*10**-3;\n",
-      "##x=W/L\n",
-      "x=4.;\n",
-      "I_D=0.5;\n",
-      "##I_D=Kn*x*((Vgs-Vtn)^2)/2;\n",
-      "Vgs=math.sqrt(I_D*2./(Kn*x))+2.;\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vgs,' V\\n')\n",
-      "##y=R1+R2\n",
-      "Rs=2.;\n",
-      "y=10./0.05;\n",
-      "print\"%s %.2f %s\"%('\\nR1+R2= ',y,' Kohm\\n')\n",
-      "##Vgs=Vg-Vs=(R2/(R1+R2)*10-5)-I_D*Rs+5\n",
-      "R2=(y/10.)*(Vgs+I_D*Rs);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n",
-      "R1=y-R2;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  3.77  V\n",
-        "\n",
-        "\n",
-        "R1+R2=  200.00  Kohm\n",
-        "\n",
-        "\n",
-        "R2=  95.36  KOhm\n",
-        "\n",
-        "\n",
-        "R1=  104.64  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg270"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.7\n",
-      "Vtn=0.8;\n",
-      "Kn=80.;\n",
-      "##x=W/L\n",
-      "x=3.;\n",
-      "I_D=250.;\n",
-      "Vd=2.5;\n",
-      "##I_D=Kn/2*x*(Vgs-Vtn)^2\n",
-      "Vgs=math.sqrt(I_D*2./(Kn*x))+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vgs,' V\\n')\n",
-      "Vs=-Vgs\n",
-      "##I_D=(5-Vd)/Rd\n",
-      "Rd=(5.-Vd)/I_D;\n",
-      "print\"%s %.2f %s\"%('\\nRd= ',Rd,' KOhm\\n')\n",
-      "Vds=Vd-Vs;\n",
-      "print\"%s %.2f %s\"%('\\nVds= ',Vds,' V\\n')\n",
-      "Vdssat=Vgs-Vtn\n",
-      "##since Vds>Vdssat transistor is biased in saturation region\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  2.24  V\n",
-        "\n",
-        "\n",
-        "Rd=  0.01  KOhm\n",
-        "\n",
-        "\n",
-        "Vds=  4.74  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg272"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "from sympy import *\n",
-      "##Example 5.8\n",
-      "Vtn=0.8;\n",
-      "Kn=0.05;\n",
-      "##I_D=Kn*(Vgs-Vtn)^2\n",
-      "##Vds=Vgs=5-I_D*Rs\n",
-      "##combining these two equations we obtain 0.5(Vgs)^2+0.2Vgs-4.68\n",
-      "import numpy\n",
-      "from numpy.polynomial import Polynomial as P\n",
-      "p = P([1, 5, 6])\n",
-      "p.roots()\n",
-      "\n",
-      "\n",
-      "print('',p.roots(),' V\\n')\n",
-      "##assuming transistor is conducting ,Vgs must be greater than threshold voltage\n",
-      "Vgs=2.87;\n",
-      "I_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',I_D,' mA\\n')\n",
-      "#ans is varying due to round of error in book calculations are done wrong\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "('', array([-0.5       , -0.33333333]), ' V\\n')\n",
-        "\n",
-        "drain current=  0.21  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg277"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 5.10\n",
-      "Vtn=-2.;\n",
-      "Kn=0.1;\n",
-      "Vdd=5.;\n",
-      "Rs=5.;\n",
-      "Vgs=0.;\n",
-      "I_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',I_D,' mA\\n')\n",
-      "Vds=Vdd-I_D*Rs;\n",
-      "print\"%s %.2f %s\"%('\\ndc drain to source voltage= ',Vds,' V\\n')\n",
-      "Vdssat=Vgs-Vtn\n",
-      "##since Vds>Vdssat transisyor is biased in saturation region\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "drain current=  0.40  mA\n",
-        "\n",
-        "\n",
-        "dc drain to source voltage=  3.00  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg277"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "\n",
-      "##Example 5.11\n",
-      "Vtnd=1;\n",
-      "Vtnl=-2;\n",
-      "Knd=50;\n",
-      "Knl=10;\n",
-      "Vt=5;\n",
-      "import numpy\n",
-      "from numpy.polynomial import Polynomial as P\n",
-      "p = P([4, -40, 5])\n",
-      "p.roots()\n",
-      "\n",
-      "\n",
-      "print('\\npossible solutions ::',p.roots(),'')\n",
-      "##since output voltage cannot be greater than supply voltage 5V\n",
-      "Vo=0.1;##(V)\n",
-      "I_D=Knl*(-Vtnl)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',I_D,' microA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "('\\npossible solutions ::', array([ 0.10128226,  7.89871774]), '')\n",
-        "\n",
-        "drain current=  40.00  microA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg282"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the \n",
-      "##Example 5.13\n",
-      "Kn1=0.2;\n",
-      "Kn2=0.1;\n",
-      "Kn3=0.1;\n",
-      "Kn4=0.1;\n",
-      "Vtn1=1.;\n",
-      "Vtn2=1.;\n",
-      "Vtn3=1.;\n",
-      "Vtn4=1.;\n",
-      "V2=-5.;\n",
-      "Vgs3=(math.sqrt(Kn4/Kn3)*(-V2-Vtn4)+Vtn3)/(1.+math.sqrt(Kn4/Kn3));\n",
-      "print\"%s %.2f %s\"%('\\nVgs3= ',Vgs3,' V\\n')\n",
-      "Iq=Kn3*(Vgs3-Vtn3)**2;\n",
-      "print\"%s %.2f %s\"%('\\nbias current= ',Iq,' mA\\n')\n",
-      "Vgs1=math.sqrt(Iq/Kn1)+Vtn1;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage on M1= ',Vgs1,' V\\n')\n",
-      "Vds2=-V2-Vgs1;\n",
-      "print\"%s %.2f %s\"%('\\ndrain to source voltage on M2= ',Vds2,' V\\n')\n",
-      "Vgs2=Vgs3;\n",
-      "Vdssat=Vgs2-Vtn2\n",
-      "##since Vds2>Vdssat M2 is biased in saturation region\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs3=  2.50  V\n",
-        "\n",
-        "\n",
-        "bias current=  0.23  mA\n",
-        "\n",
-        "\n",
-        "gate to source voltage on M1=  2.06  V\n",
-        "\n",
-        "\n",
-        "drain to source voltage on M2=  2.94  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 16
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg284"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.14\n",
-      "I_D=0.5;\n",
-      "Vds=6.;\n",
-      "Kn=80.*10**-6;\n",
-      "Vgs=5.;\n",
-      "Vtn=1.;\n",
-      "##x=W/L\n",
-      "x=I_D*2./(Kn*(Vgs-Vtn)**2);\n",
-      "print(x,\"W/L \")\n",
-      "##maximum power dissipation in transistor \n",
-      "Pmax=Vds*I_D;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipation in transistor= ',Pmax,' W\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "(781.2500000000001, 'W/L ')\n",
-        "\n",
-        "maximum power dissipation in transistor=  3.00  W\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 17
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg293"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy  \n",
-      "##Example 5.16\n",
-      "Idss=2.;##(mA) saturation current\n",
-      "Vp=-3.5;##(V) pinch off voltage\n",
-      "Vgs=numpy.array([[0, Vp/4. ,Vp/2.]])\n",
-      "I_D=Idss*(1.-Vgs/Vp)**2;\n",
-      "print (I_D)\n",
-      "Vds=Vgs-Vp;\n",
-      "print (Vds)\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "[[ 2.     1.125  0.5  ]]\n",
-        "[[ 3.5    2.625  1.75 ]]\n"
-       ]
-      }
-     ],
-     "prompt_number": 18
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg295"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.17\n",
-      "Idss=5.;##mA\n",
-      "Vp=-4.;\n",
-      "Vdd=10.;\n",
-      "I_D=2.;\n",
-      "Vds=6.;\n",
-      "##I_D=Idss*(1-Vgs/Vp)^2\n",
-      "Vgs=(1.-math.sqrt(I_D/Idss))*Vp;\n",
-      "print\"%s %.2f %s\"%('\\nVgs= ',Vgs,' V\\n')\n",
-      "Rs=-Vgs/I_D;\n",
-      "print\"%s %.2f %s\"%('\\nRs= ',Rs,' KOhm\\n')\n",
-      "Rd=(Vdd-Vds-I_D*Rs)/I_D;\n",
-      "print\"%s %.2f %s\"%('\\nRd= ',Rd,' KOhm\\n')\n",
-      "Vgs-Vp\n",
-      "##since Vds>Vgs-Vp JFET is biased in saturation\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgs=  -1.47  V\n",
-        "\n",
-        "\n",
-        "Rs=  0.74  KOhm\n",
-        "\n",
-        "\n",
-        "Rd=  1.26  KOhm\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 19,
-       "text": [
-        "2.5298221281347035"
-       ]
-      }
-     ],
-     "prompt_number": 19
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex19-pg298"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.19\n",
-      "Idss=2.5;\n",
-      "Vp=2.5;\n",
-      "I_D=0.8;\n",
-      "##I_D=Iq=0.8*10^-3=(Vd-(-9))/Rd\n",
-      "Vd=0.8*4.-9;\n",
-      "print\"%s %.2f %s\"%('\\nVd = ',Vd,'V\\n')\n",
-      "##I_D=Idss*(1-Vgs/Vp)^2;\n",
-      "Vgs=(1.-math.sqrt(I_D/Idss))*Vp;\n",
-      "print\"%s %.2f %s\"%('\\nVgs = ',Vgs,'V\\n')\n",
-      "Vs=1-Vgs;\n",
-      "print\"%s %.2f %s\"%('\\nVs= ',Vs,' V\\n')\n",
-      "Vsd=Vs-Vd;\n",
-      "print\"%s %.2f %s\"%('\\nVsd= ',Vsd,' V\\n')\n",
-      "Vp-Vgs\n",
-      "##since Vsd>Vp-Vgs JFET is biased in saturation\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vd =  -5.80 V\n",
-        "\n",
-        "\n",
-        "Vgs =  1.09 V\n",
-        "\n",
-        "\n",
-        "Vs=  -0.09  V\n",
-        "\n",
-        "\n",
-        "Vsd=  5.71  V\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 20,
-       "text": [
-        "1.414213562373095"
-       ]
-      }
-     ],
-     "prompt_number": 20
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex20-pg299"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 5.20\n",
-      "Vtn=0.24;\n",
-      "Kn=1.1;\n",
-      "##x=R1+R2=50000\n",
-      "x=50.;\n",
-      "Vgs=0.5;\n",
-      "Vds=2.5;\n",
-      "Vdd=4.;\n",
-      "Rd=6.7;\n",
-      "I_D=Kn*(Vgs-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',I_D,' mA\\n')\n",
-      "Vd=Vdd-I_D*Rd;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at drain= ',Vd,' V\\n')\n",
-      "Vs=Vd-Vds;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at source = ',Vs,'V\\n')\n",
-      "Rs=Vs/I_D;\n",
-      "print\"%s %.2f %s\"%('\\nsource resistance = ',Rs,'KOhm\\n')\n",
-      "Vg=Vgs+Vs;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at the gate= ',Vg,' V\\n')\n",
-      "##Vg=R2*Vdd/(R2+R1)\n",
-      "R2=Vg*x/Vdd;\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n",
-      "R1=x-R2;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n",
-      "Vgs-Vtn\n",
-      "##since Vds>Vgs-Vtn transistor is biased in saturation\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "drain current=  0.07  mA\n",
-        "\n",
-        "\n",
-        "voltage at drain=  3.50  V\n",
-        "\n",
-        "\n",
-        "voltage at source =  1.00 V\n",
-        "\n",
-        "\n",
-        "source resistance =  13.47 KOhm\n",
-        "\n",
-        "\n",
-        "voltage at the gate=  1.50  V\n",
-        "\n",
-        "\n",
-        "R2=  18.77  KOhm\n",
-        "\n",
-        "\n",
-        "R1=  31.23  KOhm\n",
-        "\n"
-       ]
-      },
-      {
-       "metadata": {},
-       "output_type": "pyout",
-       "prompt_number": 21,
-       "text": [
-        "0.26"
-       ]
-      }
-     ],
-     "prompt_number": 21
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter6.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter6.ipynb
deleted file mode 100755
index 27fe0eac..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter6.ipynb
+++ /dev/null
@@ -1,955 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:ddb81cb66c6e60e18386ce9465623c3e9136c0ad815bf2b64587c945fdfe08bd"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter6-Basic FET Amplifier"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg316"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.1\n",
-      "Vtn=1.;\n",
-      "##let x= u_n*Cox*1/2\n",
-      "x=20.*10**-3;\n",
-      "##let y=W/L\n",
-      "y=40.;\n",
-      "I_D=1.;\n",
-      "Kn=x*y;\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameter= ',Kn,' mA/V^2\\n')\n",
-      "g_m=2.*math.sqrt(Kn*I_D);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "conduction parameter=  0.80  mA/V^2\n",
-        "\n",
-        "\n",
-        "transconductance=  1.79  mA/V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg319"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.2\n",
-      "Vgsq=2.12;\n",
-      "Vdd=5.;\n",
-      "Rd=2.5;\n",
-      "Vtn=1.;\n",
-      "Kn=0.8;\n",
-      "##let lambda=y\n",
-      "y=0.02;##V^-1\n",
-      "Idq=Kn*(Vgsq-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',Idq,'mA\\n')\n",
-      "Vdsq=Vdd-Idq*Rd;\n",
-      "print\"%s %.2f %s\"%('\\ndrain to source voltage= ',Vdsq,' V\\n')\n",
-      "Vgs=1.82;\n",
-      "Vgs-Vtn\n",
-      "##since Vdsq>Vgs-Vtn transistor is biased in saturation\n",
-      "g_m=2.*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=(y*Idq)**-1;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Av=-g_m*ro*Rd/(ro+Rd);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "drain current=  1.00 mA\n",
-        "\n",
-        "\n",
-        "drain to source voltage=  2.49  V\n",
-        "\n",
-        "\n",
-        "transconductance=  1.79  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  49.82  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -4.27 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg326"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.3\n",
-      "Vdd=10.;\n",
-      "R1=70.9;##(Kohm)\n",
-      "R2=29.1;##(Kohm)\n",
-      "Rd=5.;##(Kohm)\n",
-      "Vtn=1.5;\n",
-      "Kn=0.5;##(mA/V^2)\n",
-      "##lambda=y\n",
-      "y=0.01;##V^-1\n",
-      "Rsi=4.;##(Kohm)\n",
-      "Vgsq=Vdd*R2/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage= ',Vgsq,' V\\n')\n",
-      "Idq=Kn*(Vgsq-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',Idq,' mA\\n')\n",
-      "Vdsq=Vdd-Idq*Rd;\n",
-      "print\"%s %.2f %s\"%('\\ndrain to source voltage= ',Vdsq,' V\\n')\n",
-      "g_m=2*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=(y*Idq)**-1;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Ri=R1*R2/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\namplifier input resistance= ',Ri,' Kohm\\n')\n",
-      "Av=-g_m*(ro*Rd/(ro+Rd))*Ri/(Ri+Rsi);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n",
-      "print\"%s %.2f %s\"%('\\namplifier input resistance= ',Ri,' Kohm\\n')\n",
-      "Ro=Rd*ro/(Rd+ro);\n",
-      "print\"%s %.2f %s\"%('\\namplifier output resistance= ',Ro,' Kohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "gate to source voltage=  2.91  V\n",
-        "\n",
-        "\n",
-        "drain current=  0.99  mA\n",
-        "\n",
-        "\n",
-        "drain to source voltage=  5.03  V\n",
-        "\n",
-        "\n",
-        "transconductance=  1.41  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  100.60  KOhm\n",
-        "\n",
-        "\n",
-        "amplifier input resistance=  20.63  Kohm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " -5.63 \n",
-        "\n",
-        "amplifier input resistance=  20.63  Kohm\n",
-        "\n",
-        "\n",
-        "amplifier output resistance=  4.76  Kohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg327"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.4\n",
-      "Vtn=1.;\n",
-      "Kn=1.;##(mA/V^2)\n",
-      "##lambda=y\n",
-      "y=0.015;##V^-1\n",
-      "Ri=100.;##(Kohm)\n",
-      "Idq=2.;##(mA)\n",
-      "Idt=4.;##(mA)\n",
-      "##Idt=4=Kn*(Vgst-Vtn)^2\n",
-      "Vgst=math.sqrt(Idt/Kn)+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgst= ',Vgst,' V\\n')\n",
-      "Vdst=Vgst-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVdst= ',Vdst,' V\\n')\n",
-      "Vdd=12.;\n",
-      "Vdsq=7.;\n",
-      "Rd=(Vdd-Vdsq)/Idq;\n",
-      "print\"%s %.2f %s\"%('\\nRd = ',Rd,'KOhm\\n')\n",
-      "Vgsq=math.sqrt(Idq/Kn)+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgsq= ',Vgsq,' V\\n')\n",
-      "R1=Ri*Vdd/Vgsq;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' Kohm\\n')\n",
-      "R2=Ri*R1/(R1-Ri);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' Kohm\\n')\n",
-      "g_m=2*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=(y*Idq)**-1;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Av=-g_m*(ro*Rd/(ro+Rd));\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgst=  3.00  V\n",
-        "\n",
-        "\n",
-        "Vdst=  2.00  V\n",
-        "\n",
-        "\n",
-        "Rd =  2.50 KOhm\n",
-        "\n",
-        "\n",
-        "Vgsq=  2.41  V\n",
-        "\n",
-        "\n",
-        "R1=  497.06  Kohm\n",
-        "\n",
-        "\n",
-        "R2=  125.19  Kohm\n",
-        "\n",
-        "\n",
-        "transconductance=  2.83  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  33.33  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -6.58 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg332"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.6\n",
-      "Vtn=0.8;\n",
-      "Kn=1.;##(mA/V^2)\n",
-      "Idq=0.5;\n",
-      "Vdd=5.;\n",
-      "Rd=7.;##(Kohm)\n",
-      "Vgsq=math.sqrt(Idq/Kn)+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgsq= ',Vgsq,' V\\n')\n",
-      "Vs=-Vgsq\n",
-      "Vdsq=Vdd-Idq*Rd-Vs;\n",
-      "print\"%s %.2f %s\"%('\\nVdsq=',Vdsq,' V\\n')\n",
-      "g_m=2.*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "Av=-g_m*Rd;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgsq=  1.51  V\n",
-        "\n",
-        "\n",
-        "Vdsq= 3.01  V\n",
-        "\n",
-        "\n",
-        "transconductance=  1.41  mA/V\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " -9.90 \n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg336"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.7\n",
-      "Vdd=12.;\n",
-      "R1=162.;\n",
-      "R2=463.;\n",
-      "Rs=0.75;\n",
-      "Kn=4.;\n",
-      "Vtn=1.5;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "Rsi=4.;\n",
-      "Idq=7.97;\n",
-      "Vgsq=2.91;\n",
-      "g_m=2.*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=(y*Idq)**-1.;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Ri=R1*R2/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\namplifier input resistance= ',Ri,' Kohm\\n')\n",
-      "x=Rs*ro/(Rs+ro);\n",
-      "Av=g_m*x*(Ri/(Ri+Rsi))/(1.+g_m*x);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  11.28  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  12.55  KOhm\n",
-        "\n",
-        "\n",
-        "amplifier input resistance=  120.01  Kohm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " 0.86 \n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg340"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.9\n",
-      "Rs=750.;##Ohm\n",
-      "ro=12500.;\n",
-      "g_m=11.3*10**-3;\n",
-      "x=1./g_m;\n",
-      "y=x*Rs/(x+Rs);\n",
-      "Ro=y*ro/(y+ro);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' ohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance=  78.66  ohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg348"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.11\n",
-      "Vtnd=1.;\n",
-      "Vtnl=1.;\n",
-      "Kn=30.;\n",
-      "##let W/L=x\n",
-      "xl=1.;\n",
-      "Vdd=5.;\n",
-      "Av=10.;\n",
-      "##Av=sqrt(xd/xl)\n",
-      "xd=(Av)**2*xl;\n",
-      "print\"%s %.2f %s\"%('\\nwidth to length ratio of driver transistor=\\n',xd,'')\n",
-      "Knd=xd*Kn*0.001/2.;\n",
-      "Knl=xl*Kn*0.001/2.;\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameter Knd= ',Knd,' mA/V^2\\n')\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameter Knl= ',Knl,' mA/V^2\\n')\n",
-      "##Vgsd-Vtnd=(Vdd-Vtnl)-sqrt(Knd/Knl)*(Vgsd-Vtnd)\n",
-      "y=math.sqrt(Knd/Knl);\n",
-      "Vgsd=(y+5.)/(1.+y);\n",
-      "print\"%s %.2f %s\"%('\\nVgsd= ',Vgsd,' V\\n')\n",
-      "Vdsd=Vgsd-1.;\n",
-      "print\"%s %.2f %s\"%('\\nVdsd= ',Vdsd,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "width to length ratio of driver transistor=\n",
-        " 100.00 \n",
-        "\n",
-        "conduction parameter Knd=  1.50  mA/V^2\n",
-        "\n",
-        "\n",
-        "conduction parameter Knl=  0.01  mA/V^2\n",
-        "\n",
-        "\n",
-        "Vgsd=  1.36  V\n",
-        "\n",
-        "\n",
-        "Vdsd=  0.36  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg352"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.12\n",
-      "Vtnd=0.8;\n",
-      "Vtnl=-1.5;\n",
-      "Knd=1.;\n",
-      "Knl=0.2;\n",
-      "##lambda=y\n",
-      "yd=0.01;\n",
-      "yl=0.01;\n",
-      "Idq=0.2;\n",
-      "gmd=2.*math.sqrt(Knd*Idq);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance of the driver= ',gmd,' mA/V\\n')\n",
-      "roD=1./(yd*Idq);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistances= ',roD,' Kohm\\n')\n",
-      "Av=-gmd*roD/2.;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance of the driver=  0.89  mA/V\n",
-        "\n",
-        "\n",
-        "output resistances=  500.00  Kohm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -223.61 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg354"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.13\n",
-      "Vtn=0.8;\n",
-      "Vtp=-0.8;\n",
-      "Kn=80.*10**-3;\n",
-      "Kp=40.*10**-3;\n",
-      "##x=W/L\n",
-      "xn=15.;\n",
-      "xp=10.;\n",
-      "##lambda=y\n",
-      "yn=0.01;\n",
-      "yp=0.01;\n",
-      "Ibias=0.2;\n",
-      "gm=2.*math.sqrt(Kn*xn*Ibias/2.);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance of the NMOS driver= ',gm,' mA/V^2\\n')\n",
-      "ron=1./(yn*Ibias);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistances= ',ron,' Kohm\\n')\n",
-      "Av=-gm*ron/2.;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance of the NMOS driver=  0.69  mA/V^2\n",
-        "\n",
-        "\n",
-        "output resistances=  500.00  Kohm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -173.21 \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg357"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.14\n",
-      "Kn1=500.*10**-3;\n",
-      "Kn2=200.*10**-3;\n",
-      "Vtn1=1.2;\n",
-      "Vtn2=Vtn1;\n",
-      "Idq1=0.2;\n",
-      "Idq2=0.5;\n",
-      "Vdsq1=6.;\n",
-      "Vdsq2=6.;\n",
-      "Ri=100.;\n",
-      "Rsi=4.;\n",
-      "Rs2=(10.-Vdsq2)/Idq2;\n",
-      "print\"%s %.2f %s\"%('\\nRs2= ',Rs2,' KOhm\\n')\n",
-      "Vgs2=math.sqrt(Idq2/Kn2)+Vtn2;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage for M2= ',Vgs2,' V\\n')\n",
-      "Vs2=-1.;\n",
-      "Vg2=Vs2+Vgs2;\n",
-      "print\"%s %.2f %s\"%('\\ngate voltage of M2= ',Vg2,' V\\n')\n",
-      "Vg1=Vg2;\n",
-      "Rd1=(5.-Vg1)/Idq1;\n",
-      "print\"%s %.2f %s\"%('\\nresistor Rd1= ',Rd1,' KOhm\\n')\n",
-      "Vs1=Vg1-Vdsq1;\n",
-      "print\"%s %.2f %s\"%('\\nsource voltage of M1= ',Vs1,' KOhm\\n')\n",
-      "Rs1=(Vs1+5.)/Idq1;\n",
-      "print\"%s %.2f %s\"%('\\nresistor Rs1= ',Rs1,' KOhm\\n')\n",
-      "Vgs1=math.sqrt(Idq1/Kn1)+Vtn1;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage for M1',Vgs1,' V\\n')\n",
-      "R1=Ri*10./(Vgs1+Idq1*Rs1);\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n",
-      "##Ri=R1*R2/(R1+R2)\n",
-      "R2=Ri*R1/(R1-Ri);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Rs2=  8.00  KOhm\n",
-        "\n",
-        "\n",
-        "gate to source voltage for M2=  2.78  V\n",
-        "\n",
-        "\n",
-        "gate voltage of M2=  1.78  V\n",
-        "\n",
-        "\n",
-        "resistor Rd1=  16.09  KOhm\n",
-        "\n",
-        "\n",
-        "source voltage of M1=  -4.22  KOhm\n",
-        "\n",
-        "\n",
-        "resistor Rs1=  3.91  KOhm\n",
-        "\n",
-        "\n",
-        "gate to source voltage for M1 1.83  V\n",
-        "\n",
-        "\n",
-        "R1=  382.61  KOhm\n",
-        "\n",
-        "\n",
-        "R2=  135.38  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg358"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.15\n",
-      "Vtn1=1.2;\n",
-      "Vtn2=1.2;\n",
-      "Kn1=0.8;\n",
-      "Kn2=0.8;\n",
-      "##x=R1+R2+R3=300\n",
-      "x=300.;\n",
-      "Rs=10.;\n",
-      "Idq=0.4;\n",
-      "Vdsq1=2.5;\n",
-      "Vdsq2=2.5;\n",
-      "Vs1=Idq*Rs-5.;\n",
-      "print\"%s %.2f %s\"%('\\ndc voltage at source of M1= ',Vs1,' V\\n')\n",
-      "Vgs=math.sqrt(Idq/Kn1)+Vtn1;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage= ',Vgs,' V\\n')\n",
-      "R3=(Vgs+Vs1)*x/5.;\n",
-      "print\"%s %.2f %s\"%('\\nR3= ',R3,' KOhm\\n')\n",
-      "Vs2=Vdsq2+Vs1;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at source of M2= ',Vs2,' V\\n')\n",
-      "##y=R2+R3\n",
-      "y=(Vgs+Vs2)*x/5.;\n",
-      "print\"%s %.2f %s\"%('\\nR2+R3= ',y,' KOhm\\n')\n",
-      "R2=150.;\n",
-      "R1=x-y;\n",
-      "print\"%s %.2f %s\"%('\\nR1=',R1,' KOhm\\n')\n",
-      "R3=y-R2;\n",
-      "print\"%s %.2f %s\"%('\\nR3= ',R3,' KOhm\\n')\n",
-      "Vd2=Vdsq2+Vs2;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at drain of M2 = ',Vd2,'V\\n')\n",
-      "Rd=(5.-Vd2)/Idq;\n",
-      "print\"%s %.2f %s\"%('\\ndrain resistance= ',Rd,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "dc voltage at source of M1=  -1.00  V\n",
-        "\n",
-        "\n",
-        "gate to source voltage=  1.91  V\n",
-        "\n",
-        "\n",
-        "R3=  54.43  KOhm\n",
-        "\n",
-        "\n",
-        "voltage at source of M2=  1.50  V\n",
-        "\n",
-        "\n",
-        "R2+R3=  204.43  KOhm\n",
-        "\n",
-        "\n",
-        "R1= 95.57  KOhm\n",
-        "\n",
-        "\n",
-        "R3=  54.43  KOhm\n",
-        "\n",
-        "\n",
-        "voltage at drain of M2 =  4.00 V\n",
-        "\n",
-        "\n",
-        "drain resistance=  2.50  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg361"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 6.17\n",
-      "Kn=0.8;\n",
-      "Vtn=1.2;\n",
-      "Vgs=1.91;\n",
-      "Rd=2.5;\n",
-      "gm=2.*Kn*(Vgs-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "Av=-gm*Rd;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  1.14  mA/V\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -2.84  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 13
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex18-pg364"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.18\n",
-      "##Determine the small signal voltage gain of a circuit in fig.6.55\n",
-      "Idss=12.;\n",
-      "Vp=-4.;\n",
-      "##lambda=y\n",
-      "y=0.008;\n",
-      "import numpy\n",
-      "from numpy.polynomial import Polynomial as P\n",
-      "p = P([26.4, 17.2, 2.025])\n",
-      "p.roots()\n",
-      "\n",
-      "\n",
-      "print('',p.roots(),' V\\n')\n",
-      "Vgsq=-2.01\n",
-      "Idq=Idss*(1.-Vgsq/Vp)**2;\n",
-      "print\"%s %.2f %s\"%('\\nquiescent drain current= ',Idq,' mA\\n')\n",
-      "gm=(-2*Idss/Vp)*(1.-Vgsq/Vp);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "ro=(1/(y*Idq));\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Rd=2.7;\n",
-      "Rl=4.;\n",
-      "x=Rd*Rl/(Rd+Rl);\n",
-      "Av=-gm*ro*x/(ro+x);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "('', array([-6.48281115, -2.01101602]), ' V\\n')\n",
-        "\n",
-        "quiescent drain current=  2.97  mA\n",
-        "\n",
-        "\n",
-        "transconductance=  2.99  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  42.09  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -4.63  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex19-pg366"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 6.19\n",
-      "Idss=12.;\n",
-      "Vp=-4.;\n",
-      "Rl=10.;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "Av=0.9;\n",
-      "##gm=(-2*Idss/Vp)*(1-Vgs/Vp)\n",
-      "gm=2.;\n",
-      "Vgs=(1.+gm*Vp/(2.*Idss))*Vp;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage= ',Vgs,' V\\n')\n",
-      "Idq=Idss*(1.-Vgs/Vp)**2;\n",
-      "print\"%s %.2f %s\"%('\\nquiescent drain current= ',Idq,' mA\\n')\n",
-      "Rs=(-Vgs+10.)/Idq;\n",
-      "print\"%s %.2f %s\"%('\\nRs= ',Rs,' KOhm\\n')\n",
-      "ro=(1./(y*Idq));\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "x=Rl*ro/(Rl+ro);\n",
-      "t=x*Rs/(x+Rs);\n",
-      "Av=gm*t/(1.+gm*t);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "gate to source voltage=  -2.67  V\n",
-        "\n",
-        "\n",
-        "quiescent drain current=  1.33  mA\n",
-        "\n",
-        "\n",
-        "Rs=  9.50  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  75.00  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  0.90  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 15
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter6_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter6_1.ipynb
deleted file mode 100755
index 27fe0eac..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter6_1.ipynb
+++ /dev/null
@@ -1,955 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:ddb81cb66c6e60e18386ce9465623c3e9136c0ad815bf2b64587c945fdfe08bd"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter6-Basic FET Amplifier"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg316"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.1\n",
-      "Vtn=1.;\n",
-      "##let x= u_n*Cox*1/2\n",
-      "x=20.*10**-3;\n",
-      "##let y=W/L\n",
-      "y=40.;\n",
-      "I_D=1.;\n",
-      "Kn=x*y;\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameter= ',Kn,' mA/V^2\\n')\n",
-      "g_m=2.*math.sqrt(Kn*I_D);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "conduction parameter=  0.80  mA/V^2\n",
-        "\n",
-        "\n",
-        "transconductance=  1.79  mA/V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg319"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.2\n",
-      "Vgsq=2.12;\n",
-      "Vdd=5.;\n",
-      "Rd=2.5;\n",
-      "Vtn=1.;\n",
-      "Kn=0.8;\n",
-      "##let lambda=y\n",
-      "y=0.02;##V^-1\n",
-      "Idq=Kn*(Vgsq-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',Idq,'mA\\n')\n",
-      "Vdsq=Vdd-Idq*Rd;\n",
-      "print\"%s %.2f %s\"%('\\ndrain to source voltage= ',Vdsq,' V\\n')\n",
-      "Vgs=1.82;\n",
-      "Vgs-Vtn\n",
-      "##since Vdsq>Vgs-Vtn transistor is biased in saturation\n",
-      "g_m=2.*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=(y*Idq)**-1;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Av=-g_m*ro*Rd/(ro+Rd);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "drain current=  1.00 mA\n",
-        "\n",
-        "\n",
-        "drain to source voltage=  2.49  V\n",
-        "\n",
-        "\n",
-        "transconductance=  1.79  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  49.82  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -4.27 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg326"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.3\n",
-      "Vdd=10.;\n",
-      "R1=70.9;##(Kohm)\n",
-      "R2=29.1;##(Kohm)\n",
-      "Rd=5.;##(Kohm)\n",
-      "Vtn=1.5;\n",
-      "Kn=0.5;##(mA/V^2)\n",
-      "##lambda=y\n",
-      "y=0.01;##V^-1\n",
-      "Rsi=4.;##(Kohm)\n",
-      "Vgsq=Vdd*R2/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage= ',Vgsq,' V\\n')\n",
-      "Idq=Kn*(Vgsq-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',Idq,' mA\\n')\n",
-      "Vdsq=Vdd-Idq*Rd;\n",
-      "print\"%s %.2f %s\"%('\\ndrain to source voltage= ',Vdsq,' V\\n')\n",
-      "g_m=2*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=(y*Idq)**-1;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Ri=R1*R2/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\namplifier input resistance= ',Ri,' Kohm\\n')\n",
-      "Av=-g_m*(ro*Rd/(ro+Rd))*Ri/(Ri+Rsi);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n",
-      "print\"%s %.2f %s\"%('\\namplifier input resistance= ',Ri,' Kohm\\n')\n",
-      "Ro=Rd*ro/(Rd+ro);\n",
-      "print\"%s %.2f %s\"%('\\namplifier output resistance= ',Ro,' Kohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "gate to source voltage=  2.91  V\n",
-        "\n",
-        "\n",
-        "drain current=  0.99  mA\n",
-        "\n",
-        "\n",
-        "drain to source voltage=  5.03  V\n",
-        "\n",
-        "\n",
-        "transconductance=  1.41  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  100.60  KOhm\n",
-        "\n",
-        "\n",
-        "amplifier input resistance=  20.63  Kohm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " -5.63 \n",
-        "\n",
-        "amplifier input resistance=  20.63  Kohm\n",
-        "\n",
-        "\n",
-        "amplifier output resistance=  4.76  Kohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg327"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.4\n",
-      "Vtn=1.;\n",
-      "Kn=1.;##(mA/V^2)\n",
-      "##lambda=y\n",
-      "y=0.015;##V^-1\n",
-      "Ri=100.;##(Kohm)\n",
-      "Idq=2.;##(mA)\n",
-      "Idt=4.;##(mA)\n",
-      "##Idt=4=Kn*(Vgst-Vtn)^2\n",
-      "Vgst=math.sqrt(Idt/Kn)+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgst= ',Vgst,' V\\n')\n",
-      "Vdst=Vgst-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVdst= ',Vdst,' V\\n')\n",
-      "Vdd=12.;\n",
-      "Vdsq=7.;\n",
-      "Rd=(Vdd-Vdsq)/Idq;\n",
-      "print\"%s %.2f %s\"%('\\nRd = ',Rd,'KOhm\\n')\n",
-      "Vgsq=math.sqrt(Idq/Kn)+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgsq= ',Vgsq,' V\\n')\n",
-      "R1=Ri*Vdd/Vgsq;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' Kohm\\n')\n",
-      "R2=Ri*R1/(R1-Ri);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' Kohm\\n')\n",
-      "g_m=2*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=(y*Idq)**-1;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Av=-g_m*(ro*Rd/(ro+Rd));\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgst=  3.00  V\n",
-        "\n",
-        "\n",
-        "Vdst=  2.00  V\n",
-        "\n",
-        "\n",
-        "Rd =  2.50 KOhm\n",
-        "\n",
-        "\n",
-        "Vgsq=  2.41  V\n",
-        "\n",
-        "\n",
-        "R1=  497.06  Kohm\n",
-        "\n",
-        "\n",
-        "R2=  125.19  Kohm\n",
-        "\n",
-        "\n",
-        "transconductance=  2.83  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  33.33  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -6.58 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg332"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.6\n",
-      "Vtn=0.8;\n",
-      "Kn=1.;##(mA/V^2)\n",
-      "Idq=0.5;\n",
-      "Vdd=5.;\n",
-      "Rd=7.;##(Kohm)\n",
-      "Vgsq=math.sqrt(Idq/Kn)+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgsq= ',Vgsq,' V\\n')\n",
-      "Vs=-Vgsq\n",
-      "Vdsq=Vdd-Idq*Rd-Vs;\n",
-      "print\"%s %.2f %s\"%('\\nVdsq=',Vdsq,' V\\n')\n",
-      "g_m=2.*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "Av=-g_m*Rd;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgsq=  1.51  V\n",
-        "\n",
-        "\n",
-        "Vdsq= 3.01  V\n",
-        "\n",
-        "\n",
-        "transconductance=  1.41  mA/V\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " -9.90 \n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg336"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.7\n",
-      "Vdd=12.;\n",
-      "R1=162.;\n",
-      "R2=463.;\n",
-      "Rs=0.75;\n",
-      "Kn=4.;\n",
-      "Vtn=1.5;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "Rsi=4.;\n",
-      "Idq=7.97;\n",
-      "Vgsq=2.91;\n",
-      "g_m=2.*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=(y*Idq)**-1.;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Ri=R1*R2/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\namplifier input resistance= ',Ri,' Kohm\\n')\n",
-      "x=Rs*ro/(Rs+ro);\n",
-      "Av=g_m*x*(Ri/(Ri+Rsi))/(1.+g_m*x);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  11.28  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  12.55  KOhm\n",
-        "\n",
-        "\n",
-        "amplifier input resistance=  120.01  Kohm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " 0.86 \n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg340"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.9\n",
-      "Rs=750.;##Ohm\n",
-      "ro=12500.;\n",
-      "g_m=11.3*10**-3;\n",
-      "x=1./g_m;\n",
-      "y=x*Rs/(x+Rs);\n",
-      "Ro=y*ro/(y+ro);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' ohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance=  78.66  ohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg348"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.11\n",
-      "Vtnd=1.;\n",
-      "Vtnl=1.;\n",
-      "Kn=30.;\n",
-      "##let W/L=x\n",
-      "xl=1.;\n",
-      "Vdd=5.;\n",
-      "Av=10.;\n",
-      "##Av=sqrt(xd/xl)\n",
-      "xd=(Av)**2*xl;\n",
-      "print\"%s %.2f %s\"%('\\nwidth to length ratio of driver transistor=\\n',xd,'')\n",
-      "Knd=xd*Kn*0.001/2.;\n",
-      "Knl=xl*Kn*0.001/2.;\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameter Knd= ',Knd,' mA/V^2\\n')\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameter Knl= ',Knl,' mA/V^2\\n')\n",
-      "##Vgsd-Vtnd=(Vdd-Vtnl)-sqrt(Knd/Knl)*(Vgsd-Vtnd)\n",
-      "y=math.sqrt(Knd/Knl);\n",
-      "Vgsd=(y+5.)/(1.+y);\n",
-      "print\"%s %.2f %s\"%('\\nVgsd= ',Vgsd,' V\\n')\n",
-      "Vdsd=Vgsd-1.;\n",
-      "print\"%s %.2f %s\"%('\\nVdsd= ',Vdsd,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "width to length ratio of driver transistor=\n",
-        " 100.00 \n",
-        "\n",
-        "conduction parameter Knd=  1.50  mA/V^2\n",
-        "\n",
-        "\n",
-        "conduction parameter Knl=  0.01  mA/V^2\n",
-        "\n",
-        "\n",
-        "Vgsd=  1.36  V\n",
-        "\n",
-        "\n",
-        "Vdsd=  0.36  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg352"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.12\n",
-      "Vtnd=0.8;\n",
-      "Vtnl=-1.5;\n",
-      "Knd=1.;\n",
-      "Knl=0.2;\n",
-      "##lambda=y\n",
-      "yd=0.01;\n",
-      "yl=0.01;\n",
-      "Idq=0.2;\n",
-      "gmd=2.*math.sqrt(Knd*Idq);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance of the driver= ',gmd,' mA/V\\n')\n",
-      "roD=1./(yd*Idq);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistances= ',roD,' Kohm\\n')\n",
-      "Av=-gmd*roD/2.;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance of the driver=  0.89  mA/V\n",
-        "\n",
-        "\n",
-        "output resistances=  500.00  Kohm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -223.61 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg354"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.13\n",
-      "Vtn=0.8;\n",
-      "Vtp=-0.8;\n",
-      "Kn=80.*10**-3;\n",
-      "Kp=40.*10**-3;\n",
-      "##x=W/L\n",
-      "xn=15.;\n",
-      "xp=10.;\n",
-      "##lambda=y\n",
-      "yn=0.01;\n",
-      "yp=0.01;\n",
-      "Ibias=0.2;\n",
-      "gm=2.*math.sqrt(Kn*xn*Ibias/2.);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance of the NMOS driver= ',gm,' mA/V^2\\n')\n",
-      "ron=1./(yn*Ibias);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistances= ',ron,' Kohm\\n')\n",
-      "Av=-gm*ron/2.;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance of the NMOS driver=  0.69  mA/V^2\n",
-        "\n",
-        "\n",
-        "output resistances=  500.00  Kohm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -173.21 \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg357"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.14\n",
-      "Kn1=500.*10**-3;\n",
-      "Kn2=200.*10**-3;\n",
-      "Vtn1=1.2;\n",
-      "Vtn2=Vtn1;\n",
-      "Idq1=0.2;\n",
-      "Idq2=0.5;\n",
-      "Vdsq1=6.;\n",
-      "Vdsq2=6.;\n",
-      "Ri=100.;\n",
-      "Rsi=4.;\n",
-      "Rs2=(10.-Vdsq2)/Idq2;\n",
-      "print\"%s %.2f %s\"%('\\nRs2= ',Rs2,' KOhm\\n')\n",
-      "Vgs2=math.sqrt(Idq2/Kn2)+Vtn2;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage for M2= ',Vgs2,' V\\n')\n",
-      "Vs2=-1.;\n",
-      "Vg2=Vs2+Vgs2;\n",
-      "print\"%s %.2f %s\"%('\\ngate voltage of M2= ',Vg2,' V\\n')\n",
-      "Vg1=Vg2;\n",
-      "Rd1=(5.-Vg1)/Idq1;\n",
-      "print\"%s %.2f %s\"%('\\nresistor Rd1= ',Rd1,' KOhm\\n')\n",
-      "Vs1=Vg1-Vdsq1;\n",
-      "print\"%s %.2f %s\"%('\\nsource voltage of M1= ',Vs1,' KOhm\\n')\n",
-      "Rs1=(Vs1+5.)/Idq1;\n",
-      "print\"%s %.2f %s\"%('\\nresistor Rs1= ',Rs1,' KOhm\\n')\n",
-      "Vgs1=math.sqrt(Idq1/Kn1)+Vtn1;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage for M1',Vgs1,' V\\n')\n",
-      "R1=Ri*10./(Vgs1+Idq1*Rs1);\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n",
-      "##Ri=R1*R2/(R1+R2)\n",
-      "R2=Ri*R1/(R1-Ri);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Rs2=  8.00  KOhm\n",
-        "\n",
-        "\n",
-        "gate to source voltage for M2=  2.78  V\n",
-        "\n",
-        "\n",
-        "gate voltage of M2=  1.78  V\n",
-        "\n",
-        "\n",
-        "resistor Rd1=  16.09  KOhm\n",
-        "\n",
-        "\n",
-        "source voltage of M1=  -4.22  KOhm\n",
-        "\n",
-        "\n",
-        "resistor Rs1=  3.91  KOhm\n",
-        "\n",
-        "\n",
-        "gate to source voltage for M1 1.83  V\n",
-        "\n",
-        "\n",
-        "R1=  382.61  KOhm\n",
-        "\n",
-        "\n",
-        "R2=  135.38  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg358"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.15\n",
-      "Vtn1=1.2;\n",
-      "Vtn2=1.2;\n",
-      "Kn1=0.8;\n",
-      "Kn2=0.8;\n",
-      "##x=R1+R2+R3=300\n",
-      "x=300.;\n",
-      "Rs=10.;\n",
-      "Idq=0.4;\n",
-      "Vdsq1=2.5;\n",
-      "Vdsq2=2.5;\n",
-      "Vs1=Idq*Rs-5.;\n",
-      "print\"%s %.2f %s\"%('\\ndc voltage at source of M1= ',Vs1,' V\\n')\n",
-      "Vgs=math.sqrt(Idq/Kn1)+Vtn1;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage= ',Vgs,' V\\n')\n",
-      "R3=(Vgs+Vs1)*x/5.;\n",
-      "print\"%s %.2f %s\"%('\\nR3= ',R3,' KOhm\\n')\n",
-      "Vs2=Vdsq2+Vs1;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at source of M2= ',Vs2,' V\\n')\n",
-      "##y=R2+R3\n",
-      "y=(Vgs+Vs2)*x/5.;\n",
-      "print\"%s %.2f %s\"%('\\nR2+R3= ',y,' KOhm\\n')\n",
-      "R2=150.;\n",
-      "R1=x-y;\n",
-      "print\"%s %.2f %s\"%('\\nR1=',R1,' KOhm\\n')\n",
-      "R3=y-R2;\n",
-      "print\"%s %.2f %s\"%('\\nR3= ',R3,' KOhm\\n')\n",
-      "Vd2=Vdsq2+Vs2;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at drain of M2 = ',Vd2,'V\\n')\n",
-      "Rd=(5.-Vd2)/Idq;\n",
-      "print\"%s %.2f %s\"%('\\ndrain resistance= ',Rd,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "dc voltage at source of M1=  -1.00  V\n",
-        "\n",
-        "\n",
-        "gate to source voltage=  1.91  V\n",
-        "\n",
-        "\n",
-        "R3=  54.43  KOhm\n",
-        "\n",
-        "\n",
-        "voltage at source of M2=  1.50  V\n",
-        "\n",
-        "\n",
-        "R2+R3=  204.43  KOhm\n",
-        "\n",
-        "\n",
-        "R1= 95.57  KOhm\n",
-        "\n",
-        "\n",
-        "R3=  54.43  KOhm\n",
-        "\n",
-        "\n",
-        "voltage at drain of M2 =  4.00 V\n",
-        "\n",
-        "\n",
-        "drain resistance=  2.50  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg361"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 6.17\n",
-      "Kn=0.8;\n",
-      "Vtn=1.2;\n",
-      "Vgs=1.91;\n",
-      "Rd=2.5;\n",
-      "gm=2.*Kn*(Vgs-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "Av=-gm*Rd;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  1.14  mA/V\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -2.84  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 13
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex18-pg364"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.18\n",
-      "##Determine the small signal voltage gain of a circuit in fig.6.55\n",
-      "Idss=12.;\n",
-      "Vp=-4.;\n",
-      "##lambda=y\n",
-      "y=0.008;\n",
-      "import numpy\n",
-      "from numpy.polynomial import Polynomial as P\n",
-      "p = P([26.4, 17.2, 2.025])\n",
-      "p.roots()\n",
-      "\n",
-      "\n",
-      "print('',p.roots(),' V\\n')\n",
-      "Vgsq=-2.01\n",
-      "Idq=Idss*(1.-Vgsq/Vp)**2;\n",
-      "print\"%s %.2f %s\"%('\\nquiescent drain current= ',Idq,' mA\\n')\n",
-      "gm=(-2*Idss/Vp)*(1.-Vgsq/Vp);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "ro=(1/(y*Idq));\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Rd=2.7;\n",
-      "Rl=4.;\n",
-      "x=Rd*Rl/(Rd+Rl);\n",
-      "Av=-gm*ro*x/(ro+x);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "('', array([-6.48281115, -2.01101602]), ' V\\n')\n",
-        "\n",
-        "quiescent drain current=  2.97  mA\n",
-        "\n",
-        "\n",
-        "transconductance=  2.99  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  42.09  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -4.63  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex19-pg366"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 6.19\n",
-      "Idss=12.;\n",
-      "Vp=-4.;\n",
-      "Rl=10.;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "Av=0.9;\n",
-      "##gm=(-2*Idss/Vp)*(1-Vgs/Vp)\n",
-      "gm=2.;\n",
-      "Vgs=(1.+gm*Vp/(2.*Idss))*Vp;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage= ',Vgs,' V\\n')\n",
-      "Idq=Idss*(1.-Vgs/Vp)**2;\n",
-      "print\"%s %.2f %s\"%('\\nquiescent drain current= ',Idq,' mA\\n')\n",
-      "Rs=(-Vgs+10.)/Idq;\n",
-      "print\"%s %.2f %s\"%('\\nRs= ',Rs,' KOhm\\n')\n",
-      "ro=(1./(y*Idq));\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "x=Rl*ro/(Rl+ro);\n",
-      "t=x*Rs/(x+Rs);\n",
-      "Av=gm*t/(1.+gm*t);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "gate to source voltage=  -2.67  V\n",
-        "\n",
-        "\n",
-        "quiescent drain current=  1.33  mA\n",
-        "\n",
-        "\n",
-        "Rs=  9.50  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  75.00  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  0.90  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 15
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter6_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter6_1_1.ipynb
deleted file mode 100755
index f26e210a..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter6_1_1.ipynb
+++ /dev/null
@@ -1,955 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:5f69c997f454918e67123a37f5caef5b8555309eb92b985bcafc07b0e579172b"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter6-Basic FET Amplifier"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg316"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.1\n",
-      "Vtn=1.;\n",
-      "##let x= u_n*Cox*1/2\n",
-      "x=20.*10**-3;\n",
-      "##let y=W/L\n",
-      "y=40.;\n",
-      "I_D=1.;\n",
-      "Kn=x*y;\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameter= ',Kn,' mA/V^2\\n')\n",
-      "g_m=2.*math.sqrt(Kn*I_D);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "conduction parameter=  0.80  mA/V^2\n",
-        "\n",
-        "\n",
-        "transconductance=  1.79  mA/V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg319"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.2\n",
-      "Vgsq=2.12;\n",
-      "Vdd=5.;\n",
-      "Rd=2.5;\n",
-      "Vtn=1.;\n",
-      "Kn=0.8;\n",
-      "##let lambda=y\n",
-      "y=0.02;##V^-1\n",
-      "Idq=Kn*(Vgsq-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',Idq,'mA\\n')\n",
-      "Vdsq=Vdd-Idq*Rd;\n",
-      "print\"%s %.2f %s\"%('\\ndrain to source voltage= ',Vdsq,' V\\n')\n",
-      "Vgs=1.82;\n",
-      "Vgs-Vtn\n",
-      "##since Vdsq>Vgs-Vtn transistor is biased in saturation\n",
-      "g_m=2.*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=(y*Idq)**-1;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Av=-g_m*ro*Rd/(ro+Rd);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "drain current=  1.00 mA\n",
-        "\n",
-        "\n",
-        "drain to source voltage=  2.49  V\n",
-        "\n",
-        "\n",
-        "transconductance=  1.79  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  49.82  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -4.27 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg326"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.3\n",
-      "Vdd=10.;\n",
-      "R1=70.9;##(Kohm)\n",
-      "R2=29.1;##(Kohm)\n",
-      "Rd=5.;##(Kohm)\n",
-      "Vtn=1.5;\n",
-      "Kn=0.5;##(mA/V^2)\n",
-      "##lambda=y\n",
-      "y=0.01;##V^-1\n",
-      "Rsi=4.;##(Kohm)\n",
-      "Vgsq=Vdd*R2/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage= ',Vgsq,' V\\n')\n",
-      "Idq=Kn*(Vgsq-Vtn)**2;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',Idq,' mA\\n')\n",
-      "Vdsq=Vdd-Idq*Rd;\n",
-      "print\"%s %.2f %s\"%('\\ndrain to source voltage= ',Vdsq,' V\\n')\n",
-      "g_m=2*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=(y*Idq)**-1;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Ri=R1*R2/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\namplifier input resistance= ',Ri,' Kohm\\n')\n",
-      "Av=-g_m*(ro*Rd/(ro+Rd))*Ri/(Ri+Rsi);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n",
-      "print\"%s %.2f %s\"%('\\namplifier input resistance= ',Ri,' Kohm\\n')\n",
-      "Ro=Rd*ro/(Rd+ro);\n",
-      "print\"%s %.2f %s\"%('\\namplifier output resistance= ',Ro,' Kohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "gate to source voltage=  2.91  V\n",
-        "\n",
-        "\n",
-        "drain current=  0.99  mA\n",
-        "\n",
-        "\n",
-        "drain to source voltage=  5.03  V\n",
-        "\n",
-        "\n",
-        "transconductance=  1.41  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  100.60  KOhm\n",
-        "\n",
-        "\n",
-        "amplifier input resistance=  20.63  Kohm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " -5.63 \n",
-        "\n",
-        "amplifier input resistance=  20.63  Kohm\n",
-        "\n",
-        "\n",
-        "amplifier output resistance=  4.76  Kohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg327"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.4\n",
-      "Vtn=1.;\n",
-      "Kn=1.;##(mA/V^2)\n",
-      "##lambda=y\n",
-      "y=0.015;##V^-1\n",
-      "Ri=100.;##(Kohm)\n",
-      "Idq=2.;##(mA)\n",
-      "Idt=4.;##(mA)\n",
-      "##Idt=4=Kn*(Vgst-Vtn)^2\n",
-      "Vgst=math.sqrt(Idt/Kn)+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgst= ',Vgst,' V\\n')\n",
-      "Vdst=Vgst-Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVdst= ',Vdst,' V\\n')\n",
-      "Vdd=12.;\n",
-      "Vdsq=7.;\n",
-      "Rd=(Vdd-Vdsq)/Idq;\n",
-      "print\"%s %.2f %s\"%('\\nRd = ',Rd,'KOhm\\n')\n",
-      "Vgsq=math.sqrt(Idq/Kn)+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgsq= ',Vgsq,' V\\n')\n",
-      "R1=Ri*Vdd/Vgsq;\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' Kohm\\n')\n",
-      "R2=Ri*R1/(R1-Ri);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' Kohm\\n')\n",
-      "g_m=2*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=(y*Idq)**-1;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Av=-g_m*(ro*Rd/(ro+Rd));\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgst=  3.00  V\n",
-        "\n",
-        "\n",
-        "Vdst=  2.00  V\n",
-        "\n",
-        "\n",
-        "Rd =  2.50 KOhm\n",
-        "\n",
-        "\n",
-        "Vgsq=  2.41  V\n",
-        "\n",
-        "\n",
-        "R1=  497.06  Kohm\n",
-        "\n",
-        "\n",
-        "R2=  125.19  Kohm\n",
-        "\n",
-        "\n",
-        "transconductance=  2.83  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  33.33  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -6.58 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg332"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.6\n",
-      "Vtn=0.8;\n",
-      "Kn=1.;##(mA/V^2)\n",
-      "Idq=0.5;\n",
-      "Vdd=5.;\n",
-      "Rd=7.;##(Kohm)\n",
-      "Vgsq=math.sqrt(Idq/Kn)+Vtn;\n",
-      "print\"%s %.2f %s\"%('\\nVgsq= ',Vgsq,' V\\n')\n",
-      "Vs=-Vgsq\n",
-      "Vdsq=Vdd-Idq*Rd-Vs;\n",
-      "print\"%s %.2f %s\"%('\\nVdsq=',Vdsq,' V\\n')\n",
-      "g_m=2.*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "Av=-g_m*Rd;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Vgsq=  1.51  V\n",
-        "\n",
-        "\n",
-        "Vdsq= 3.01  V\n",
-        "\n",
-        "\n",
-        "transconductance=  1.41  mA/V\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " -9.90 \n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg336"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.7\n",
-      "Vdd=12.;\n",
-      "R1=162.;\n",
-      "R2=463.;\n",
-      "Rs=0.75;\n",
-      "Kn=4.;\n",
-      "Vtn=1.5;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "Rsi=4.;\n",
-      "Idq=7.97;\n",
-      "Vgsq=2.91;\n",
-      "g_m=2.*Kn*(Vgsq-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',g_m,' mA/V\\n')\n",
-      "ro=(y*Idq)**-1.;\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Ri=R1*R2/(R1+R2);\n",
-      "print\"%s %.2f %s\"%('\\namplifier input resistance= ',Ri,' Kohm\\n')\n",
-      "x=Rs*ro/(Rs+ro);\n",
-      "Av=g_m*x*(Ri/(Ri+Rsi))/(1.+g_m*x);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  11.28  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  12.55  KOhm\n",
-        "\n",
-        "\n",
-        "amplifier input resistance=  120.01  Kohm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=\n",
-        " 0.86 \n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg340"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.9\n",
-      "Rs=750.;##Ohm\n",
-      "ro=12500.;\n",
-      "g_m=11.3*10**-3;\n",
-      "x=1./g_m;\n",
-      "y=x*Rs/(x+Rs);\n",
-      "Ro=y*ro/(y+ro);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',Ro,' ohm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance=  78.66  ohm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg348"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.11\n",
-      "Vtnd=1.;\n",
-      "Vtnl=1.;\n",
-      "Kn=30.;\n",
-      "##let W/L=x\n",
-      "xl=1.;\n",
-      "Vdd=5.;\n",
-      "Av=10.;\n",
-      "##Av=sqrt(xd/xl)\n",
-      "xd=(Av)**2*xl;\n",
-      "print\"%s %.2f %s\"%('\\nwidth to length ratio of driver transistor=\\n',xd,'')\n",
-      "Knd=xd*Kn*0.001/2.;\n",
-      "Knl=xl*Kn*0.001/2.;\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameter Knd= ',Knd,' mA/V^2\\n')\n",
-      "print\"%s %.2f %s\"%('\\nconduction parameter Knl= ',Knl,' mA/V^2\\n')\n",
-      "##Vgsd-Vtnd=(Vdd-Vtnl)-sqrt(Knd/Knl)*(Vgsd-Vtnd)\n",
-      "y=math.sqrt(Knd/Knl);\n",
-      "Vgsd=(y+5.)/(1.+y);\n",
-      "print\"%s %.2f %s\"%('\\nVgsd= ',Vgsd,' V\\n')\n",
-      "Vdsd=Vgsd-1.;\n",
-      "print\"%s %.2f %s\"%('\\nVdsd= ',Vdsd,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "width to length ratio of driver transistor=\n",
-        " 100.00 \n",
-        "\n",
-        "conduction parameter Knd=  1.50  mA/V^2\n",
-        "\n",
-        "\n",
-        "conduction parameter Knl=  0.01  mA/V^2\n",
-        "\n",
-        "\n",
-        "Vgsd=  1.36  V\n",
-        "\n",
-        "\n",
-        "Vdsd=  0.36  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg352"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.12\n",
-      "Vtnd=0.8;\n",
-      "Vtnl=-1.5;\n",
-      "Knd=1.;\n",
-      "Knl=0.2;\n",
-      "##lambda=y\n",
-      "yd=0.01;\n",
-      "yl=0.01;\n",
-      "Idq=0.2;\n",
-      "gmd=2.*math.sqrt(Knd*Idq);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance of the driver= ',gmd,' mA/V\\n')\n",
-      "roD=1./(yd*Idq);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistances= ',roD,' Kohm\\n')\n",
-      "Av=-gmd*roD/2.;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance of the driver=  0.89  mA/V\n",
-        "\n",
-        "\n",
-        "output resistances=  500.00  Kohm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -223.61 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg354"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.13\n",
-      "Vtn=0.8;\n",
-      "Vtp=-0.8;\n",
-      "Kn=80.*10**-3;\n",
-      "Kp=40.*10**-3;\n",
-      "##x=W/L\n",
-      "xn=15.;\n",
-      "xp=10.;\n",
-      "##lambda=y\n",
-      "yn=0.01;\n",
-      "yp=0.01;\n",
-      "Ibias=0.2;\n",
-      "gm=2.*math.sqrt(Kn*xn*Ibias/2.);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance of the NMOS driver= ',gm,' mA/V^2\\n')\n",
-      "ron=1./(yn*Ibias);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistances= ',ron,' Kohm\\n')\n",
-      "Av=-gm*ron/2.;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance of the NMOS driver=  0.69  mA/V^2\n",
-        "\n",
-        "\n",
-        "output resistances=  500.00  Kohm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain= \n",
-        " -173.21 \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg357"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.14\n",
-      "Kn1=500.*10**-3;\n",
-      "Kn2=200.*10**-3;\n",
-      "Vtn1=1.2;\n",
-      "Vtn2=Vtn1;\n",
-      "Idq1=0.2;\n",
-      "Idq2=0.5;\n",
-      "Vdsq1=6.;\n",
-      "Vdsq2=6.;\n",
-      "Ri=100.;\n",
-      "Rsi=4.;\n",
-      "Rs2=(10.-Vdsq2)/Idq2;\n",
-      "print\"%s %.2f %s\"%('\\nRs2= ',Rs2,' KOhm\\n')\n",
-      "Vgs2=math.sqrt(Idq2/Kn2)+Vtn2;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage for M2= ',Vgs2,' V\\n')\n",
-      "Vs2=-1.;\n",
-      "Vg2=Vs2+Vgs2;\n",
-      "print\"%s %.2f %s\"%('\\ngate voltage of M2= ',Vg2,' V\\n')\n",
-      "Vg1=Vg2;\n",
-      "Rd1=(5.-Vg1)/Idq1;\n",
-      "print\"%s %.2f %s\"%('\\nresistor Rd1= ',Rd1,' KOhm\\n')\n",
-      "Vs1=Vg1-Vdsq1;\n",
-      "print\"%s %.2f %s\"%('\\nsource voltage of M1= ',Vs1,' KOhm\\n')\n",
-      "Rs1=(Vs1+5.)/Idq1;\n",
-      "print\"%s %.2f %s\"%('\\nresistor Rs1= ',Rs1,' KOhm\\n')\n",
-      "Vgs1=math.sqrt(Idq1/Kn1)+Vtn1;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage for M1',Vgs1,' V\\n')\n",
-      "R1=Ri*10./(Vgs1+Idq1*Rs1);\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n",
-      "##Ri=R1*R2/(R1+R2)\n",
-      "R2=Ri*R1/(R1-Ri);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Rs2=  8.00  KOhm\n",
-        "\n",
-        "\n",
-        "gate to source voltage for M2=  2.78  V\n",
-        "\n",
-        "\n",
-        "gate voltage of M2=  1.78  V\n",
-        "\n",
-        "\n",
-        "resistor Rd1=  16.09  KOhm\n",
-        "\n",
-        "\n",
-        "source voltage of M1=  -4.22  KOhm\n",
-        "\n",
-        "\n",
-        "resistor Rs1=  3.91  KOhm\n",
-        "\n",
-        "\n",
-        "gate to source voltage for M1 1.83  V\n",
-        "\n",
-        "\n",
-        "R1=  382.61  KOhm\n",
-        "\n",
-        "\n",
-        "R2=  135.38  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg358"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.15\n",
-      "Vtn1=1.2;\n",
-      "Vtn2=1.2;\n",
-      "Kn1=0.8;\n",
-      "Kn2=0.8;\n",
-      "##x=R1+R2+R3=300\n",
-      "x=300.;\n",
-      "Rs=10.;\n",
-      "Idq=0.4;\n",
-      "Vdsq1=2.5;\n",
-      "Vdsq2=2.5;\n",
-      "Vs1=Idq*Rs-5.;\n",
-      "print\"%s %.2f %s\"%('\\ndc voltage at source of M1= ',Vs1,' V\\n')\n",
-      "Vgs=math.sqrt(Idq/Kn1)+Vtn1;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage= ',Vgs,' V\\n')\n",
-      "R3=(Vgs+Vs1)*x/5.;\n",
-      "print\"%s %.2f %s\"%('\\nR3= ',R3,' KOhm\\n')\n",
-      "Vs2=Vdsq2+Vs1;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at source of M2= ',Vs2,' V\\n')\n",
-      "##y=R2+R3\n",
-      "y=(Vgs+Vs2)*x/5.;\n",
-      "print\"%s %.2f %s\"%('\\nR2+R3= ',y,' KOhm\\n')\n",
-      "R2=150.;\n",
-      "R1=x-y;\n",
-      "print\"%s %.2f %s\"%('\\nR1=',R1,' KOhm\\n')\n",
-      "R3=y-R2;\n",
-      "print\"%s %.2f %s\"%('\\nR3= ',R3,' KOhm\\n')\n",
-      "Vd2=Vdsq2+Vs2;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage at drain of M2 = ',Vd2,'V\\n')\n",
-      "Rd=(5.-Vd2)/Idq;\n",
-      "print\"%s %.2f %s\"%('\\ndrain resistance= ',Rd,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "dc voltage at source of M1=  -1.00  V\n",
-        "\n",
-        "\n",
-        "gate to source voltage=  1.91  V\n",
-        "\n",
-        "\n",
-        "R3=  54.43  KOhm\n",
-        "\n",
-        "\n",
-        "voltage at source of M2=  1.50  V\n",
-        "\n",
-        "\n",
-        "R2+R3=  204.43  KOhm\n",
-        "\n",
-        "\n",
-        "R1= 95.57  KOhm\n",
-        "\n",
-        "\n",
-        "R3=  54.43  KOhm\n",
-        "\n",
-        "\n",
-        "voltage at drain of M2 =  4.00 V\n",
-        "\n",
-        "\n",
-        "drain resistance=  2.50  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg361"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 6.17\n",
-      "Kn=0.8;\n",
-      "Vtn=1.2;\n",
-      "Vgs=1.91;\n",
-      "Rd=2.5;\n",
-      "gm=2.*Kn*(Vgs-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "Av=-gm*Rd;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  1.14  mA/V\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -2.84  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 13
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex18-pg364"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 6.18\n",
-      "##Determine the small signal voltage gain of a circuit in fig.6.55\n",
-      "Idss=12.;\n",
-      "Vp=-4.;\n",
-      "##lambda=y\n",
-      "y=0.008;\n",
-      "import numpy\n",
-      "from numpy.polynomial import Polynomial as P\n",
-      "p = P([26.4, 17.2, 2.025])\n",
-      "p.roots()\n",
-      "\n",
-      "\n",
-      "print('',p.roots(),' V\\n')\n",
-      "Vgsq=-2.01\n",
-      "Idq=Idss*(1.-Vgsq/Vp)**2;\n",
-      "print\"%s %.2f %s\"%('\\nquiescent drain current= ',Idq,' mA\\n')\n",
-      "gm=(-2*Idss/Vp)*(1.-Vgsq/Vp);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "ro=(1/(y*Idq));\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "Rd=2.7;\n",
-      "Rl=4.;\n",
-      "x=Rd*Rl/(Rd+Rl);\n",
-      "Av=-gm*ro*x/(ro+x);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "('', array([-6.48281115, -2.01101602]), ' V\\n')\n",
-        "\n",
-        "quiescent drain current=  2.97  mA\n",
-        "\n",
-        "\n",
-        "transconductance=  2.99  mA/V\n",
-        "\n",
-        "\n",
-        "output resistance=  42.09  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  -4.63  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex19-pg366"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 6.19\n",
-      "Idss=12.;\n",
-      "Vp=-4.;\n",
-      "Rl=10.;\n",
-      "##lambda=y\n",
-      "y=0.01;\n",
-      "Av=0.9;\n",
-      "##gm=(-2*Idss/Vp)*(1-Vgs/Vp)\n",
-      "gm=2.;\n",
-      "Vgs=(1.+gm*Vp/(2.*Idss))*Vp;\n",
-      "print\"%s %.2f %s\"%('\\ngate to source voltage= ',Vgs,' V\\n')\n",
-      "Idq=Idss*(1.-Vgs/Vp)**2;\n",
-      "print\"%s %.2f %s\"%('\\nquiescent drain current= ',Idq,' mA\\n')\n",
-      "Rs=(-Vgs+10.)/Idq;\n",
-      "print\"%s %.2f %s\"%('\\nRs= ',Rs,' KOhm\\n')\n",
-      "ro=(1./(y*Idq));\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance= ',ro,' KOhm\\n')\n",
-      "x=Rl*ro/(Rl+ro);\n",
-      "t=x*Rs/(x+Rs);\n",
-      "Av=gm*t/(1.+gm*t);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "gate to source voltage=  -2.67  V\n",
-        "\n",
-        "\n",
-        "quiescent drain current=  1.33  mA\n",
-        "\n",
-        "\n",
-        "Rs=  9.50  KOhm\n",
-        "\n",
-        "\n",
-        "output resistance=  75.00  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  0.90  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 15
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter7.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter7.ipynb
deleted file mode 100755
index cdaa4721..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter7.ipynb
+++ /dev/null
@@ -1,1012 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:f18f9d847269f9edf29c736ee46e70f983f60a1586ec020e9b0c78d7d24ae225"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter7-Frequency Response"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg393"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 7.1\n",
-      "Rs=1000.;\n",
-      "Rp=10000.;\n",
-      "Cs=1.*10**-6;\n",
-      "Cp=3.*10**-12;\n",
-      "Ts=(Rs+Rp)*Cs;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Ts,' s\\n')\n",
-      "f=1/(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency= ',f,' Hz\\n')\n",
-      "x=20.*math.log10(Rp/(Rp+Rs));\n",
-      "print\"%s %.2f %s\"%('\\nmaximum magnitude = ',x,'dB\\n')\n",
-      "Rp=10.;##KOhm\n",
-      "Rs=1.;##Kohm\n",
-      "Cp=3.;##pF\n",
-      "Tp=Cp*Rs*Rp/(Rs+Rp);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=2.73*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency = ',f,'MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "time constant=  0.01  s\n",
-        "\n",
-        "\n",
-        "corner frequency=  14.47  Hz\n",
-        "\n",
-        "\n",
-        "maximum magnitude =  -0.83 dB\n",
-        "\n",
-        "\n",
-        "time constant=  2.73  ns\n",
-        "\n",
-        "\n",
-        "corner frequency =  58.30 MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg396"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.2\n",
-      "Rs=1000.;\n",
-      "Rp=10000.;\n",
-      "Cs=1*10**-6;\n",
-      "Cp=3*10**-12;\n",
-      "Ts=(Rs+Rp)*Cs;\n",
-      "print\"%s %.2f %s\"%('\\nopen circuit time constant= ',Ts,' s\\n')\n",
-      "Rs=1.;##KOhm\n",
-      "Rp=10.;##KOhm\n",
-      "Cp=3.;##pF\n",
-      "Tp=Cp*Rs*Rp/(Rs+Rp);\n",
-      "print\"%s %.2f %s\"%('\\nshort circuit time constant= ',Tp,' ns\\n')\n",
-      "fL=1./(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency fL= ',fL,' Hz\\n')\n",
-      "Tp=2.73*10**-3;##microsec\n",
-      "fH=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency fH= ',fH,' MHz\\n')\n",
-      "fL=14.5*10**-6;##MHz\n",
-      "fbw=fH-fL;\n",
-      "print\"%s %.2f %s\"%('\\nbandwidth = ',fbw,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "open circuit time constant=  0.01  s\n",
-        "\n",
-        "\n",
-        "short circuit time constant=  2.73  ns\n",
-        "\n",
-        "\n",
-        "corner frequency fL=  14.47  Hz\n",
-        "\n",
-        "\n",
-        "corner frequency fH=  58.30  MHz\n",
-        "\n",
-        "\n",
-        "bandwidth =  58.30  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg400"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.3\n",
-      "R1=51.2;\n",
-      "R2=9.6;\n",
-      "Rc=2.;\n",
-      "Re=.4;\n",
-      "Rsi=.1;\n",
-      "Vt=0.026;\n",
-      "Cc=1.;\n",
-      "Vcc=10.;\n",
-      "Vbe=0.7;\n",
-      "b=100.;\n",
-      "Rb=8.08;\n",
-      "Icq=1.81;\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\ndiffusion resistance= ',r,' KOhm\\n')\n",
-      "x=r+(1.+b)*Re;\n",
-      "y=x*R2/(x+R2);\n",
-      "Ri=y*R1/(R1+y);\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri,' KOhm\\n')\n",
-      "Ts=(Rsi+Ri)*Cc;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Ts, 'ms')\n",
-      "Ts=6.87*10**-3;##Sec\n",
-      "fL=1/(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency fL= ',fL,' Hz\\n')\n",
-      "Rib=r+(1.+b)*Re;\n",
-      "print\"%s %.2f %s\"%('\\nRib= ',Rib,' KOhm\\n')\n",
-      "Av=(gm*r*Rc/(Rsi+Ri))*Rb/(Rb+Rib);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  69.62  mA/V\n",
-        "\n",
-        "\n",
-        "diffusion resistance=  1.44  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance=  6.78  KOhm\n",
-        "\n",
-        "\n",
-        "time constant=  6.88 ms\n",
-        "\n",
-        "corner frequency fL=  23.17  Hz\n",
-        "\n",
-        "\n",
-        "Rib=  41.84  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  4.71 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg402"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.4\n",
-      "fL=20.*10**-3;##KHz\n",
-      "Rd=6.7;\n",
-      "Rl=10;\n",
-      "Ts=1./(2.*math.pi*fL);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Ts,' ms\\n')\n",
-      "Cc=Ts/(Rd+Rl);\n",
-      "print\"%s %.2f %s\"%('\\ncoupling capacitance= ',Cc,' microF\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "time constant=  7.96  ms\n",
-        "\n",
-        "\n",
-        "coupling capacitance=  0.48  microF\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg403"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.5\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Rs=500.;\n",
-      "Rb=100000.;\n",
-      "Re=10000.;\n",
-      "Rl=10000.;\n",
-      "Va=120.;\n",
-      "Ccc2=1*10**-6;\n",
-      "Icq=0.838*0.001;\n",
-      "r=3100.;##small signal parameter\n",
-      "gm=32.2*0.001;\n",
-      "ro=143000.;\n",
-      "x=(r+Rs*Rb/(Rs+Rb))/(1+b);\n",
-      "y=ro*x/(ro+x);\n",
-      "Ro=Re*y/(Re+y);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of emitter= ',Ro,' Ohm\\n')\n",
-      "Ts=(Ro+Rl)*Ccc2;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Ts,' s\\n')\n",
-      "fL=1/(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\n3dB frequency= ',fL,' Hz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance of emitter=  35.48  Ohm\n",
-        "\n",
-        "\n",
-        "time constant=  0.01  s\n",
-        "\n",
-        "\n",
-        "3dB frequency=  15.86  Hz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg406"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.6\n",
-      "Rs=3.2;\n",
-      "Rd=10.;\n",
-      "Rl=20.;\n",
-      "Cl=10.;\n",
-      "Vtp=-2.;\n",
-      "Kp=0.25;\n",
-      "Idq=0.5;\n",
-      "Vsgq=3.41;\n",
-      "Vsdq=3.41;\n",
-      "gm=2.*Kp*(Vsgq+Vtp);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "Tp=Cl*Rd*Rl/(Rd+Rl);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=66.7*10**-3;##micro sec\n",
-      "fH=1./(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency= ',fH,' MHz\\n')\n",
-      "Av=(gm*Rd*Rl/(Rd+Rl))/(1+gm*Rs);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum small signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance =  0.71 mA/V\n",
-        "\n",
-        "\n",
-        "time constant=  66.67  ns\n",
-        "\n",
-        "\n",
-        "corner frequency=  2.39  MHz\n",
-        "\n",
-        "\n",
-        "maximum small signal voltage gain=\n",
-        " 1.44 \n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg409"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.7\n",
-      "Vbe=0.7;\n",
-      "b=100.;\n",
-      "Re=.5;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "R1=40.;\n",
-      "Cc=10.;\n",
-      "R2=5.7;\n",
-      "Rs=.1;\n",
-      "Vt=0.026;\n",
-      "Icq=0.99;\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\ndiffusion resistance= ',r,' KOhm\\n')\n",
-      "Ri=r+(1.+b)*Re;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri,' KOhm\\n')\n",
-      "x=Rc*Rl/(Rc+Rl);\n",
-      "y=R1*R2/(R1+R2);\n",
-      "t=y*Ri/(y+Ri);\n",
-      "Av=gm*r*x*(y/(y+Ri))*(1./(Rs+t));\n",
-      "print\"%s %.2f %s\"%('\\nmaximum small signal voltage gain=\\n',Av,'')\n",
-      "Ts=(Rs+t)*Cc;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant=\\n',Ts,'ms')\n",
-      "Ts=46.6*0.001;##sec\n",
-      "Cl=15.;\n",
-      "Tp=x*Cl;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant ',Tp,' ns\\n')\n",
-      "fL=1/(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\nlower corner frequency= ',fL,' Hz\\n')\n",
-      "Tp=50.*10**-3;##micro sec\n",
-      "fH=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\nupper corner frequency= ',fH,' MHz\\n')\n",
-      "fL=3.4*10**-6;##MHz\n",
-      "fbw=fH-fL;\n",
-      "print\"%s %.2f %s\"%('\\nbandwidth = ',fbw,'MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  38.08  mA/V\n",
-        "\n",
-        "\n",
-        "diffusion resistance=  2.63  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance=  53.13  KOhm\n",
-        "\n",
-        "\n",
-        "maximum small signal voltage gain=\n",
-        " 6.14 \n",
-        "\n",
-        "time constant=\n",
-        " 46.61 ms\n",
-        "\n",
-        "time constant  50.00  ns\n",
-        "\n",
-        "\n",
-        "lower corner frequency=  3.42  Hz\n",
-        "\n",
-        "\n",
-        "upper corner frequency=  3.18  MHz\n",
-        "\n",
-        "\n",
-        "bandwidth =  3.18 MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg412"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 7.8\n",
-      "Re=4.;\n",
-      "Rc=2.;\n",
-      "Rs=0.5;\n",
-      "Vt=0.026;\n",
-      "Ce=1*10**-3;\n",
-      "V1=5.;\n",
-      "Icq=1.06;\n",
-      "V2=-5.;\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\ndiffusion resistance= ',r,' KOhm\\n')\n",
-      "Ta=Re*Ce;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant Ta= ',Ta,'f s\\n')\n",
-      "Tb=(Re*Ce*(Rs+r))/(Rs+r+(1+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant Tb= ',Tb,' s\\n')\n",
-      "fA=1/(2.*math.pi*Ta);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency = ',fA,'Hz\\n')\n",
-      "Tb=2.9*0.01;##msec\n",
-      "fB=1/(2.*math.pi*Tb);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency =',fB,'khz')\n",
-      "Av=(gm*r*Rc)/(Rs+r+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nlimiting low frequency horizontal asymptote= \\n',Av,'')\n",
-      "Av=gm*r*Rc/(Rs+r);\n",
-      "print\"%s %.2f %s\"%('\\nnlimiting high frequency horizontal asymptote=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance =  40.77 mA/V\n",
-        "\n",
-        "\n",
-        "diffusion resistance=  2.45  KOhm\n",
-        "\n",
-        "\n",
-        "time constant Ta=  0.00 f s\n",
-        "\n",
-        "\n",
-        "time constant Tb=  0.00  s\n",
-        "\n",
-        "\n",
-        "corner frequency =  39.79 Hz\n",
-        "\n",
-        "\n",
-        "corner frequency = 5.49 khz\n",
-        "\n",
-        "limiting low frequency horizontal asymptote= \n",
-        " 0.49 \n",
-        "\n",
-        "nlimiting high frequency horizontal asymptote=\n",
-        " 67.73 \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg420"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.9\n",
-      "r=2600.;\n",
-      "C1=2.*10**-6;\n",
-      "C2=0.1*10**-6;\n",
-      "fB=1/(2.*math.pi*r*(C1+C2));\n",
-      "print\"%s %.2f %s\"%('\\n3dB frequency= ',fB,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "3dB frequency=  29.15  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg421"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.10\n",
-      "fT=500.;\n",
-      "Ic=1.;\n",
-      "b=100.;\n",
-      "Vt=0.026;\n",
-      "C2=0.3*10**-12;\n",
-      "fB=fT/b;\n",
-      "print\"%s %.2f %s\"%('\\nbandwidth= ',fB,' MHz\\n')\n",
-      "gm=Ic/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,'mA/V\\n')\n",
-      "fT=500000000.;\n",
-      "gm=38.5*0.001;\n",
-      "C1=gm/(fT*2.*math.pi)-C2;\n",
-      "print\"%s %.2e %s\"%('\\ncapacitance = ',C1,'F\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "bandwidth=  5.00  MHz\n",
-        "\n",
-        "\n",
-        "transconductance=  38.46 mA/V\n",
-        "\n",
-        "\n",
-        "capacitance =  1.20e-11 F\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg430"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.12\n",
-      "Kn=0.25;\n",
-      "Vtn=1.;\n",
-      "Cgd=0.04*10**-3;\n",
-      "Cgs=0.2*10**-3;\n",
-      "Vgs=3.;\n",
-      "gm=2.*Kn*(Vgs-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "fT=gm/(2.*math.pi*(Cgd+Cgs));\n",
-      "print\"%s %.2f %s\"%('\\nunity gain bandwidth= ',fT,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance =  1.00 mA/V\n",
-        "\n",
-        "\n",
-        "unity gain bandwidth=  663.15  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg432"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 7.13\n",
-      "gm=1.;\n",
-      "Cgd=0.04;\n",
-      "Rl=10.;\n",
-      "Cgs=0.2;\n",
-      "Cm=Cgd*(1.+gm*Rl);\n",
-      "print\"%s %.2f %s\"%('\\nMiller capacitance= ',Cm,' pF\\n')\n",
-      "Cm=0.44*0.001;##nF\n",
-      "Cgs=0.2*0.001;##nF\n",
-      "fT=gm/(2.*math.pi*(Cgs+Cm));\n",
-      "print\"%s %.2f %s\"%('\\ncutoff frequency= ',fT,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Miller capacitance=  0.44  pF\n",
-        "\n",
-        "\n",
-        "cutoff frequency=  248.68  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg435"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.14\n",
-      "V1=5.;\n",
-      "V=-5.;\n",
-      "Rs=0.1;\n",
-      "Rb=40.;\n",
-      "R2=5.72;\n",
-      "Re=0.5;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "b=150.;\n",
-      "Vbe=0.7;\n",
-      "C1=35*10**-3;\n",
-      "C2=4.;\n",
-      "Vt=0.026;\n",
-      "Icq=1.02;\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal parameter= ',r,' KOhm\\n')\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "Cm=C2*(1+gm*Rc*Rl/(Rc+Rl));\n",
-      "print\"%s %.2f %s\"%('\\nMiller capacitance= ',Cm,' pF\\n')\n",
-      "Cm=527.*10**-3;\n",
-      "x=Rb*Rs/(Rb+Rs);\n",
-      "y=r*x/(r+x);\n",
-      "fH=1/(2.*math.pi*y*(C1+Cm));\n",
-      "print\"%s %.2f %s\"%('\\nupper corner frequency = ',fH,'MHz\\n')\n",
-      "t=Rb*r/(Rb+r);\n",
-      "p=Rc*Rl/(Rc+Rl);\n",
-      "Av=gm*p*t/(t+Rs);\n",
-      "print\"%s %.2f %s\"%('\\nmidband gain= ',Av,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal parameter=  3.82  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  39.23  mA/V\n",
-        "\n",
-        "\n",
-        "Miller capacitance=  527.08  pF\n",
-        "\n",
-        "\n",
-        "upper corner frequency =  2.91 MHz\n",
-        "\n",
-        "\n",
-        "midband gain=  127.13 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 13
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg439"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.15\n",
-      "V1=5.;\n",
-      "V=-5.;\n",
-      "Rs=0.1;\n",
-      "R1=40.;\n",
-      "R2=5.72;\n",
-      "Re=0.5;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "b=150.;\n",
-      "Vbe=0.7;\n",
-      "C1=35.;\n",
-      "C2=4.;\n",
-      "Vt=0.026;\n",
-      "Icq=1.02;\n",
-      "gm=39.2;\n",
-      "r=3.82;\n",
-      "x=Re*Rs/(Re+Rs);\n",
-      "t=r/(1.+b);\n",
-      "y=t*x/(t+x);\n",
-      "Tp=y*C1;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=0.679*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\nupper frequency = ',f,'MHz\\n')\n",
-      "T=C2*Rc*Rl/(Rc+Rl);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',T,' ns\\n')\n",
-      "T=13.3*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*T);\n",
-      "print\"%s %.2f %s\"%('\\nupper frequency= ',f,' MHz\\n')\n",
-      "x=Rc*Rl/(Rc+Rl);\n",
-      "y=Re*t/(Re+t);\n",
-      "Av=gm*x*(y/(y+Rs));\n",
-      "print\"%s %.2f %s\"%('\\nmidband voltage gain \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "time constant=  0.68  ns\n",
-        "\n",
-        "\n",
-        "upper frequency =  234.40 MHz\n",
-        "\n",
-        "\n",
-        "time constant=  13.33  ns\n",
-        "\n",
-        "\n",
-        "upper frequency=  11.97  MHz\n",
-        "\n",
-        "\n",
-        "midband voltage gain \n",
-        " 25.36 \n"
-       ]
-      }
-     ],
-     "prompt_number": 14
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg443"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.16\n",
-      "V1=5.;\n",
-      "V=-5.;\n",
-      "Rs=0.1;\n",
-      "R1=42.5;\n",
-      "R2=20.5;\n",
-      "R3=28.3;\n",
-      "Re=5.4;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "b=150.;\n",
-      "Vbe=0.7;\n",
-      "C1=35.;\n",
-      "C2=4.;\n",
-      "Vt=0.026;\n",
-      "Icq=1.02;\n",
-      "gm=39.2;\n",
-      "r=3.820;\n",
-      "Rb=R2*R3/(R2+R3);\n",
-      "x=Rb*r/(Rb+r);\n",
-      "y=Rs*x/(x+Rs);\n",
-      "Tp=y*(C1+2*C2);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=Tp*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\n3dB frequency = ',f,'MHz\\n')\n",
-      "T=C2*Rc*Rl/(Rc+Rl);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',T,'ns\\n')\n",
-      "T=T*0.001;##micro sec\n",
-      "f=1/(2.*math.pi*T);\n",
-      "print\"%s %.2f %s\"%('\\nupper frequency= ',f,' MHz\\n')\n",
-      "x=Rc*Rl/(Rc+Rl);\n",
-      "y=Rb*r/(Rb+r);\n",
-      "Av=gm*x*(y/(y+Rs));\n",
-      "print\"%s %.2f %s\"%('\\nmidband voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "time constant=  4.16  ns\n",
-        "\n",
-        "\n",
-        "3dB frequency =  38.29 MHz\n",
-        "\n",
-        "\n",
-        "time constant=  13.33 ns\n",
-        "\n",
-        "\n",
-        "upper frequency=  11.94  MHz\n",
-        "\n",
-        "\n",
-        "midband voltage gain=  126.30  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 15
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg447"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##Example 7.17\n",
-      "V1=5.;\n",
-      "V=-5.;\n",
-      "Rs=0.1;\n",
-      "R1=40;\n",
-      "R2=5.720;\n",
-      "Re=0.5;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "b=150.;\n",
-      "Vbe=0.7;\n",
-      "C1=35.;\n",
-      "C2=4.;\n",
-      "Vt=0.026;\n",
-      "Icq=1.02;\n",
-      "gm=39.2;\n",
-      "r=3.820;\n",
-      "t=r/(1.+b);\n",
-      "t=t*0.001;\n",
-      "f=1/(2.*math.pi*C1*t);\n",
-      "print'%s %.2f %s'%('\\nthe zero occurs at this frequency= ',f,' MHz\\n')\n",
-      "x=1+gm*Re*Rl/(Re+Rl);\n",
-      "Rb=R1*R2/(R1+R2)\n",
-      "d=x*r;\n",
-      "y=d*Rb/(d+Rb);\n",
-      "t=y*Rs/(y+Rs);\n",
-      "Tp=t*(C2+C1/x);\n",
-      "print'%s %.2f %s'%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=Tp*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*Tp);\n",
-      "print'%s %.2f %s'%('\\n3dB frequency= ',f,' MHz\\n')"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the zero occurs at this frequency=  179.75  MHz\n",
-        "\n",
-        "\n",
-        "time constant=  0.57  ns\n",
-        "\n",
-        "\n",
-        "3dB frequency=  281.24  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 17
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter7_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter7_1.ipynb
deleted file mode 100755
index cdaa4721..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter7_1.ipynb
+++ /dev/null
@@ -1,1012 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:f18f9d847269f9edf29c736ee46e70f983f60a1586ec020e9b0c78d7d24ae225"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter7-Frequency Response"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg393"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 7.1\n",
-      "Rs=1000.;\n",
-      "Rp=10000.;\n",
-      "Cs=1.*10**-6;\n",
-      "Cp=3.*10**-12;\n",
-      "Ts=(Rs+Rp)*Cs;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Ts,' s\\n')\n",
-      "f=1/(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency= ',f,' Hz\\n')\n",
-      "x=20.*math.log10(Rp/(Rp+Rs));\n",
-      "print\"%s %.2f %s\"%('\\nmaximum magnitude = ',x,'dB\\n')\n",
-      "Rp=10.;##KOhm\n",
-      "Rs=1.;##Kohm\n",
-      "Cp=3.;##pF\n",
-      "Tp=Cp*Rs*Rp/(Rs+Rp);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=2.73*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency = ',f,'MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "time constant=  0.01  s\n",
-        "\n",
-        "\n",
-        "corner frequency=  14.47  Hz\n",
-        "\n",
-        "\n",
-        "maximum magnitude =  -0.83 dB\n",
-        "\n",
-        "\n",
-        "time constant=  2.73  ns\n",
-        "\n",
-        "\n",
-        "corner frequency =  58.30 MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg396"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.2\n",
-      "Rs=1000.;\n",
-      "Rp=10000.;\n",
-      "Cs=1*10**-6;\n",
-      "Cp=3*10**-12;\n",
-      "Ts=(Rs+Rp)*Cs;\n",
-      "print\"%s %.2f %s\"%('\\nopen circuit time constant= ',Ts,' s\\n')\n",
-      "Rs=1.;##KOhm\n",
-      "Rp=10.;##KOhm\n",
-      "Cp=3.;##pF\n",
-      "Tp=Cp*Rs*Rp/(Rs+Rp);\n",
-      "print\"%s %.2f %s\"%('\\nshort circuit time constant= ',Tp,' ns\\n')\n",
-      "fL=1./(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency fL= ',fL,' Hz\\n')\n",
-      "Tp=2.73*10**-3;##microsec\n",
-      "fH=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency fH= ',fH,' MHz\\n')\n",
-      "fL=14.5*10**-6;##MHz\n",
-      "fbw=fH-fL;\n",
-      "print\"%s %.2f %s\"%('\\nbandwidth = ',fbw,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "open circuit time constant=  0.01  s\n",
-        "\n",
-        "\n",
-        "short circuit time constant=  2.73  ns\n",
-        "\n",
-        "\n",
-        "corner frequency fL=  14.47  Hz\n",
-        "\n",
-        "\n",
-        "corner frequency fH=  58.30  MHz\n",
-        "\n",
-        "\n",
-        "bandwidth =  58.30  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg400"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.3\n",
-      "R1=51.2;\n",
-      "R2=9.6;\n",
-      "Rc=2.;\n",
-      "Re=.4;\n",
-      "Rsi=.1;\n",
-      "Vt=0.026;\n",
-      "Cc=1.;\n",
-      "Vcc=10.;\n",
-      "Vbe=0.7;\n",
-      "b=100.;\n",
-      "Rb=8.08;\n",
-      "Icq=1.81;\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\ndiffusion resistance= ',r,' KOhm\\n')\n",
-      "x=r+(1.+b)*Re;\n",
-      "y=x*R2/(x+R2);\n",
-      "Ri=y*R1/(R1+y);\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri,' KOhm\\n')\n",
-      "Ts=(Rsi+Ri)*Cc;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Ts, 'ms')\n",
-      "Ts=6.87*10**-3;##Sec\n",
-      "fL=1/(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency fL= ',fL,' Hz\\n')\n",
-      "Rib=r+(1.+b)*Re;\n",
-      "print\"%s %.2f %s\"%('\\nRib= ',Rib,' KOhm\\n')\n",
-      "Av=(gm*r*Rc/(Rsi+Ri))*Rb/(Rb+Rib);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  69.62  mA/V\n",
-        "\n",
-        "\n",
-        "diffusion resistance=  1.44  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance=  6.78  KOhm\n",
-        "\n",
-        "\n",
-        "time constant=  6.88 ms\n",
-        "\n",
-        "corner frequency fL=  23.17  Hz\n",
-        "\n",
-        "\n",
-        "Rib=  41.84  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  4.71 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg402"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.4\n",
-      "fL=20.*10**-3;##KHz\n",
-      "Rd=6.7;\n",
-      "Rl=10;\n",
-      "Ts=1./(2.*math.pi*fL);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Ts,' ms\\n')\n",
-      "Cc=Ts/(Rd+Rl);\n",
-      "print\"%s %.2f %s\"%('\\ncoupling capacitance= ',Cc,' microF\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "time constant=  7.96  ms\n",
-        "\n",
-        "\n",
-        "coupling capacitance=  0.48  microF\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg403"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.5\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Rs=500.;\n",
-      "Rb=100000.;\n",
-      "Re=10000.;\n",
-      "Rl=10000.;\n",
-      "Va=120.;\n",
-      "Ccc2=1*10**-6;\n",
-      "Icq=0.838*0.001;\n",
-      "r=3100.;##small signal parameter\n",
-      "gm=32.2*0.001;\n",
-      "ro=143000.;\n",
-      "x=(r+Rs*Rb/(Rs+Rb))/(1+b);\n",
-      "y=ro*x/(ro+x);\n",
-      "Ro=Re*y/(Re+y);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of emitter= ',Ro,' Ohm\\n')\n",
-      "Ts=(Ro+Rl)*Ccc2;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Ts,' s\\n')\n",
-      "fL=1/(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\n3dB frequency= ',fL,' Hz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance of emitter=  35.48  Ohm\n",
-        "\n",
-        "\n",
-        "time constant=  0.01  s\n",
-        "\n",
-        "\n",
-        "3dB frequency=  15.86  Hz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg406"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.6\n",
-      "Rs=3.2;\n",
-      "Rd=10.;\n",
-      "Rl=20.;\n",
-      "Cl=10.;\n",
-      "Vtp=-2.;\n",
-      "Kp=0.25;\n",
-      "Idq=0.5;\n",
-      "Vsgq=3.41;\n",
-      "Vsdq=3.41;\n",
-      "gm=2.*Kp*(Vsgq+Vtp);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "Tp=Cl*Rd*Rl/(Rd+Rl);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=66.7*10**-3;##micro sec\n",
-      "fH=1./(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency= ',fH,' MHz\\n')\n",
-      "Av=(gm*Rd*Rl/(Rd+Rl))/(1+gm*Rs);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum small signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance =  0.71 mA/V\n",
-        "\n",
-        "\n",
-        "time constant=  66.67  ns\n",
-        "\n",
-        "\n",
-        "corner frequency=  2.39  MHz\n",
-        "\n",
-        "\n",
-        "maximum small signal voltage gain=\n",
-        " 1.44 \n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg409"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.7\n",
-      "Vbe=0.7;\n",
-      "b=100.;\n",
-      "Re=.5;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "R1=40.;\n",
-      "Cc=10.;\n",
-      "R2=5.7;\n",
-      "Rs=.1;\n",
-      "Vt=0.026;\n",
-      "Icq=0.99;\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\ndiffusion resistance= ',r,' KOhm\\n')\n",
-      "Ri=r+(1.+b)*Re;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri,' KOhm\\n')\n",
-      "x=Rc*Rl/(Rc+Rl);\n",
-      "y=R1*R2/(R1+R2);\n",
-      "t=y*Ri/(y+Ri);\n",
-      "Av=gm*r*x*(y/(y+Ri))*(1./(Rs+t));\n",
-      "print\"%s %.2f %s\"%('\\nmaximum small signal voltage gain=\\n',Av,'')\n",
-      "Ts=(Rs+t)*Cc;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant=\\n',Ts,'ms')\n",
-      "Ts=46.6*0.001;##sec\n",
-      "Cl=15.;\n",
-      "Tp=x*Cl;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant ',Tp,' ns\\n')\n",
-      "fL=1/(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\nlower corner frequency= ',fL,' Hz\\n')\n",
-      "Tp=50.*10**-3;##micro sec\n",
-      "fH=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\nupper corner frequency= ',fH,' MHz\\n')\n",
-      "fL=3.4*10**-6;##MHz\n",
-      "fbw=fH-fL;\n",
-      "print\"%s %.2f %s\"%('\\nbandwidth = ',fbw,'MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  38.08  mA/V\n",
-        "\n",
-        "\n",
-        "diffusion resistance=  2.63  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance=  53.13  KOhm\n",
-        "\n",
-        "\n",
-        "maximum small signal voltage gain=\n",
-        " 6.14 \n",
-        "\n",
-        "time constant=\n",
-        " 46.61 ms\n",
-        "\n",
-        "time constant  50.00  ns\n",
-        "\n",
-        "\n",
-        "lower corner frequency=  3.42  Hz\n",
-        "\n",
-        "\n",
-        "upper corner frequency=  3.18  MHz\n",
-        "\n",
-        "\n",
-        "bandwidth =  3.18 MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg412"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 7.8\n",
-      "Re=4.;\n",
-      "Rc=2.;\n",
-      "Rs=0.5;\n",
-      "Vt=0.026;\n",
-      "Ce=1*10**-3;\n",
-      "V1=5.;\n",
-      "Icq=1.06;\n",
-      "V2=-5.;\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\ndiffusion resistance= ',r,' KOhm\\n')\n",
-      "Ta=Re*Ce;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant Ta= ',Ta,'f s\\n')\n",
-      "Tb=(Re*Ce*(Rs+r))/(Rs+r+(1+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant Tb= ',Tb,' s\\n')\n",
-      "fA=1/(2.*math.pi*Ta);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency = ',fA,'Hz\\n')\n",
-      "Tb=2.9*0.01;##msec\n",
-      "fB=1/(2.*math.pi*Tb);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency =',fB,'khz')\n",
-      "Av=(gm*r*Rc)/(Rs+r+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nlimiting low frequency horizontal asymptote= \\n',Av,'')\n",
-      "Av=gm*r*Rc/(Rs+r);\n",
-      "print\"%s %.2f %s\"%('\\nnlimiting high frequency horizontal asymptote=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance =  40.77 mA/V\n",
-        "\n",
-        "\n",
-        "diffusion resistance=  2.45  KOhm\n",
-        "\n",
-        "\n",
-        "time constant Ta=  0.00 f s\n",
-        "\n",
-        "\n",
-        "time constant Tb=  0.00  s\n",
-        "\n",
-        "\n",
-        "corner frequency =  39.79 Hz\n",
-        "\n",
-        "\n",
-        "corner frequency = 5.49 khz\n",
-        "\n",
-        "limiting low frequency horizontal asymptote= \n",
-        " 0.49 \n",
-        "\n",
-        "nlimiting high frequency horizontal asymptote=\n",
-        " 67.73 \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg420"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.9\n",
-      "r=2600.;\n",
-      "C1=2.*10**-6;\n",
-      "C2=0.1*10**-6;\n",
-      "fB=1/(2.*math.pi*r*(C1+C2));\n",
-      "print\"%s %.2f %s\"%('\\n3dB frequency= ',fB,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "3dB frequency=  29.15  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg421"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.10\n",
-      "fT=500.;\n",
-      "Ic=1.;\n",
-      "b=100.;\n",
-      "Vt=0.026;\n",
-      "C2=0.3*10**-12;\n",
-      "fB=fT/b;\n",
-      "print\"%s %.2f %s\"%('\\nbandwidth= ',fB,' MHz\\n')\n",
-      "gm=Ic/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,'mA/V\\n')\n",
-      "fT=500000000.;\n",
-      "gm=38.5*0.001;\n",
-      "C1=gm/(fT*2.*math.pi)-C2;\n",
-      "print\"%s %.2e %s\"%('\\ncapacitance = ',C1,'F\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "bandwidth=  5.00  MHz\n",
-        "\n",
-        "\n",
-        "transconductance=  38.46 mA/V\n",
-        "\n",
-        "\n",
-        "capacitance =  1.20e-11 F\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg430"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.12\n",
-      "Kn=0.25;\n",
-      "Vtn=1.;\n",
-      "Cgd=0.04*10**-3;\n",
-      "Cgs=0.2*10**-3;\n",
-      "Vgs=3.;\n",
-      "gm=2.*Kn*(Vgs-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "fT=gm/(2.*math.pi*(Cgd+Cgs));\n",
-      "print\"%s %.2f %s\"%('\\nunity gain bandwidth= ',fT,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance =  1.00 mA/V\n",
-        "\n",
-        "\n",
-        "unity gain bandwidth=  663.15  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg432"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 7.13\n",
-      "gm=1.;\n",
-      "Cgd=0.04;\n",
-      "Rl=10.;\n",
-      "Cgs=0.2;\n",
-      "Cm=Cgd*(1.+gm*Rl);\n",
-      "print\"%s %.2f %s\"%('\\nMiller capacitance= ',Cm,' pF\\n')\n",
-      "Cm=0.44*0.001;##nF\n",
-      "Cgs=0.2*0.001;##nF\n",
-      "fT=gm/(2.*math.pi*(Cgs+Cm));\n",
-      "print\"%s %.2f %s\"%('\\ncutoff frequency= ',fT,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Miller capacitance=  0.44  pF\n",
-        "\n",
-        "\n",
-        "cutoff frequency=  248.68  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg435"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.14\n",
-      "V1=5.;\n",
-      "V=-5.;\n",
-      "Rs=0.1;\n",
-      "Rb=40.;\n",
-      "R2=5.72;\n",
-      "Re=0.5;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "b=150.;\n",
-      "Vbe=0.7;\n",
-      "C1=35*10**-3;\n",
-      "C2=4.;\n",
-      "Vt=0.026;\n",
-      "Icq=1.02;\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal parameter= ',r,' KOhm\\n')\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "Cm=C2*(1+gm*Rc*Rl/(Rc+Rl));\n",
-      "print\"%s %.2f %s\"%('\\nMiller capacitance= ',Cm,' pF\\n')\n",
-      "Cm=527.*10**-3;\n",
-      "x=Rb*Rs/(Rb+Rs);\n",
-      "y=r*x/(r+x);\n",
-      "fH=1/(2.*math.pi*y*(C1+Cm));\n",
-      "print\"%s %.2f %s\"%('\\nupper corner frequency = ',fH,'MHz\\n')\n",
-      "t=Rb*r/(Rb+r);\n",
-      "p=Rc*Rl/(Rc+Rl);\n",
-      "Av=gm*p*t/(t+Rs);\n",
-      "print\"%s %.2f %s\"%('\\nmidband gain= ',Av,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal parameter=  3.82  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  39.23  mA/V\n",
-        "\n",
-        "\n",
-        "Miller capacitance=  527.08  pF\n",
-        "\n",
-        "\n",
-        "upper corner frequency =  2.91 MHz\n",
-        "\n",
-        "\n",
-        "midband gain=  127.13 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 13
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg439"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.15\n",
-      "V1=5.;\n",
-      "V=-5.;\n",
-      "Rs=0.1;\n",
-      "R1=40.;\n",
-      "R2=5.72;\n",
-      "Re=0.5;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "b=150.;\n",
-      "Vbe=0.7;\n",
-      "C1=35.;\n",
-      "C2=4.;\n",
-      "Vt=0.026;\n",
-      "Icq=1.02;\n",
-      "gm=39.2;\n",
-      "r=3.82;\n",
-      "x=Re*Rs/(Re+Rs);\n",
-      "t=r/(1.+b);\n",
-      "y=t*x/(t+x);\n",
-      "Tp=y*C1;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=0.679*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\nupper frequency = ',f,'MHz\\n')\n",
-      "T=C2*Rc*Rl/(Rc+Rl);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',T,' ns\\n')\n",
-      "T=13.3*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*T);\n",
-      "print\"%s %.2f %s\"%('\\nupper frequency= ',f,' MHz\\n')\n",
-      "x=Rc*Rl/(Rc+Rl);\n",
-      "y=Re*t/(Re+t);\n",
-      "Av=gm*x*(y/(y+Rs));\n",
-      "print\"%s %.2f %s\"%('\\nmidband voltage gain \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "time constant=  0.68  ns\n",
-        "\n",
-        "\n",
-        "upper frequency =  234.40 MHz\n",
-        "\n",
-        "\n",
-        "time constant=  13.33  ns\n",
-        "\n",
-        "\n",
-        "upper frequency=  11.97  MHz\n",
-        "\n",
-        "\n",
-        "midband voltage gain \n",
-        " 25.36 \n"
-       ]
-      }
-     ],
-     "prompt_number": 14
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg443"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.16\n",
-      "V1=5.;\n",
-      "V=-5.;\n",
-      "Rs=0.1;\n",
-      "R1=42.5;\n",
-      "R2=20.5;\n",
-      "R3=28.3;\n",
-      "Re=5.4;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "b=150.;\n",
-      "Vbe=0.7;\n",
-      "C1=35.;\n",
-      "C2=4.;\n",
-      "Vt=0.026;\n",
-      "Icq=1.02;\n",
-      "gm=39.2;\n",
-      "r=3.820;\n",
-      "Rb=R2*R3/(R2+R3);\n",
-      "x=Rb*r/(Rb+r);\n",
-      "y=Rs*x/(x+Rs);\n",
-      "Tp=y*(C1+2*C2);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=Tp*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\n3dB frequency = ',f,'MHz\\n')\n",
-      "T=C2*Rc*Rl/(Rc+Rl);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',T,'ns\\n')\n",
-      "T=T*0.001;##micro sec\n",
-      "f=1/(2.*math.pi*T);\n",
-      "print\"%s %.2f %s\"%('\\nupper frequency= ',f,' MHz\\n')\n",
-      "x=Rc*Rl/(Rc+Rl);\n",
-      "y=Rb*r/(Rb+r);\n",
-      "Av=gm*x*(y/(y+Rs));\n",
-      "print\"%s %.2f %s\"%('\\nmidband voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "time constant=  4.16  ns\n",
-        "\n",
-        "\n",
-        "3dB frequency =  38.29 MHz\n",
-        "\n",
-        "\n",
-        "time constant=  13.33 ns\n",
-        "\n",
-        "\n",
-        "upper frequency=  11.94  MHz\n",
-        "\n",
-        "\n",
-        "midband voltage gain=  126.30  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 15
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg447"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##Example 7.17\n",
-      "V1=5.;\n",
-      "V=-5.;\n",
-      "Rs=0.1;\n",
-      "R1=40;\n",
-      "R2=5.720;\n",
-      "Re=0.5;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "b=150.;\n",
-      "Vbe=0.7;\n",
-      "C1=35.;\n",
-      "C2=4.;\n",
-      "Vt=0.026;\n",
-      "Icq=1.02;\n",
-      "gm=39.2;\n",
-      "r=3.820;\n",
-      "t=r/(1.+b);\n",
-      "t=t*0.001;\n",
-      "f=1/(2.*math.pi*C1*t);\n",
-      "print'%s %.2f %s'%('\\nthe zero occurs at this frequency= ',f,' MHz\\n')\n",
-      "x=1+gm*Re*Rl/(Re+Rl);\n",
-      "Rb=R1*R2/(R1+R2)\n",
-      "d=x*r;\n",
-      "y=d*Rb/(d+Rb);\n",
-      "t=y*Rs/(y+Rs);\n",
-      "Tp=t*(C2+C1/x);\n",
-      "print'%s %.2f %s'%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=Tp*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*Tp);\n",
-      "print'%s %.2f %s'%('\\n3dB frequency= ',f,' MHz\\n')"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the zero occurs at this frequency=  179.75  MHz\n",
-        "\n",
-        "\n",
-        "time constant=  0.57  ns\n",
-        "\n",
-        "\n",
-        "3dB frequency=  281.24  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 17
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter7_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter7_1_1.ipynb
deleted file mode 100755
index ad03d9ee..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter7_1_1.ipynb
+++ /dev/null
@@ -1,1012 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:dffc3a2403edde165f33b6308fbd20345cecf1da13bbb808db0bb00e10439bb7"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter7-Frequency Response"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1-pg393"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 7.1\n",
-      "Rs=1000.;\n",
-      "Rp=10000.;\n",
-      "Cs=1.*10**-6;\n",
-      "Cp=3.*10**-12;\n",
-      "Ts=(Rs+Rp)*Cs;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Ts,' s\\n')\n",
-      "f=1/(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency= ',f,' Hz\\n')\n",
-      "x=20.*math.log10(Rp/(Rp+Rs));\n",
-      "print\"%s %.2f %s\"%('\\nmaximum magnitude = ',x,'dB\\n')\n",
-      "Rp=10.;##KOhm\n",
-      "Rs=1.;##Kohm\n",
-      "Cp=3.;##pF\n",
-      "Tp=Cp*Rs*Rp/(Rs+Rp);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=2.73*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency = ',f,'MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "time constant=  0.01  s\n",
-        "\n",
-        "\n",
-        "corner frequency=  14.47  Hz\n",
-        "\n",
-        "\n",
-        "maximum magnitude =  -0.83 dB\n",
-        "\n",
-        "\n",
-        "time constant=  2.73  ns\n",
-        "\n",
-        "\n",
-        "corner frequency =  58.30 MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg396"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.2\n",
-      "Rs=1000.;\n",
-      "Rp=10000.;\n",
-      "Cs=1*10**-6;\n",
-      "Cp=3*10**-12;\n",
-      "Ts=(Rs+Rp)*Cs;\n",
-      "print\"%s %.2f %s\"%('\\nopen circuit time constant= ',Ts,' s\\n')\n",
-      "Rs=1.;##KOhm\n",
-      "Rp=10.;##KOhm\n",
-      "Cp=3.;##pF\n",
-      "Tp=Cp*Rs*Rp/(Rs+Rp);\n",
-      "print\"%s %.2f %s\"%('\\nshort circuit time constant= ',Tp,' ns\\n')\n",
-      "fL=1./(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency fL= ',fL,' Hz\\n')\n",
-      "Tp=2.73*10**-3;##microsec\n",
-      "fH=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency fH= ',fH,' MHz\\n')\n",
-      "fL=14.5*10**-6;##MHz\n",
-      "fbw=fH-fL;\n",
-      "print\"%s %.2f %s\"%('\\nbandwidth = ',fbw,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "open circuit time constant=  0.01  s\n",
-        "\n",
-        "\n",
-        "short circuit time constant=  2.73  ns\n",
-        "\n",
-        "\n",
-        "corner frequency fL=  14.47  Hz\n",
-        "\n",
-        "\n",
-        "corner frequency fH=  58.30  MHz\n",
-        "\n",
-        "\n",
-        "bandwidth =  58.30  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg400"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.3\n",
-      "R1=51.2;\n",
-      "R2=9.6;\n",
-      "Rc=2.;\n",
-      "Re=.4;\n",
-      "Rsi=.1;\n",
-      "Vt=0.026;\n",
-      "Cc=1.;\n",
-      "Vcc=10.;\n",
-      "Vbe=0.7;\n",
-      "b=100.;\n",
-      "Rb=8.08;\n",
-      "Icq=1.81;\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\ndiffusion resistance= ',r,' KOhm\\n')\n",
-      "x=r+(1.+b)*Re;\n",
-      "y=x*R2/(x+R2);\n",
-      "Ri=y*R1/(R1+y);\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri,' KOhm\\n')\n",
-      "Ts=(Rsi+Ri)*Cc;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Ts, 'ms')\n",
-      "Ts=6.87*10**-3;##Sec\n",
-      "fL=1/(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency fL= ',fL,' Hz\\n')\n",
-      "Rib=r+(1.+b)*Re;\n",
-      "print\"%s %.2f %s\"%('\\nRib= ',Rib,' KOhm\\n')\n",
-      "Av=(gm*r*Rc/(Rsi+Ri))*Rb/(Rb+Rib);\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal voltage gain= ',Av,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  69.62  mA/V\n",
-        "\n",
-        "\n",
-        "diffusion resistance=  1.44  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance=  6.78  KOhm\n",
-        "\n",
-        "\n",
-        "time constant=  6.88 ms\n",
-        "\n",
-        "corner frequency fL=  23.17  Hz\n",
-        "\n",
-        "\n",
-        "Rib=  41.84  KOhm\n",
-        "\n",
-        "\n",
-        "small signal voltage gain=  4.71 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex4-pg402"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.4\n",
-      "fL=20.*10**-3;##KHz\n",
-      "Rd=6.7;\n",
-      "Rl=10;\n",
-      "Ts=1./(2.*math.pi*fL);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Ts,' ms\\n')\n",
-      "Cc=Ts/(Rd+Rl);\n",
-      "print\"%s %.2f %s\"%('\\ncoupling capacitance= ',Cc,' microF\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "time constant=  7.96  ms\n",
-        "\n",
-        "\n",
-        "coupling capacitance=  0.48  microF\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg403"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.5\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "Rs=500.;\n",
-      "Rb=100000.;\n",
-      "Re=10000.;\n",
-      "Rl=10000.;\n",
-      "Va=120.;\n",
-      "Ccc2=1*10**-6;\n",
-      "Icq=0.838*0.001;\n",
-      "r=3100.;##small signal parameter\n",
-      "gm=32.2*0.001;\n",
-      "ro=143000.;\n",
-      "x=(r+Rs*Rb/(Rs+Rb))/(1+b);\n",
-      "y=ro*x/(ro+x);\n",
-      "Ro=Re*y/(Re+y);\n",
-      "print\"%s %.2f %s\"%('\\noutput resistance of emitter= ',Ro,' Ohm\\n')\n",
-      "Ts=(Ro+Rl)*Ccc2;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Ts,' s\\n')\n",
-      "fL=1/(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\n3dB frequency= ',fL,' Hz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "output resistance of emitter=  35.48  Ohm\n",
-        "\n",
-        "\n",
-        "time constant=  0.01  s\n",
-        "\n",
-        "\n",
-        "3dB frequency=  15.86  Hz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex6-pg406"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.6\n",
-      "Rs=3.2;\n",
-      "Rd=10.;\n",
-      "Rl=20.;\n",
-      "Cl=10.;\n",
-      "Vtp=-2.;\n",
-      "Kp=0.25;\n",
-      "Idq=0.5;\n",
-      "Vsgq=3.41;\n",
-      "Vsdq=3.41;\n",
-      "gm=2.*Kp*(Vsgq+Vtp);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "Tp=Cl*Rd*Rl/(Rd+Rl);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=66.7*10**-3;##micro sec\n",
-      "fH=1./(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency= ',fH,' MHz\\n')\n",
-      "Av=(gm*Rd*Rl/(Rd+Rl))/(1+gm*Rs);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum small signal voltage gain=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance =  0.71 mA/V\n",
-        "\n",
-        "\n",
-        "time constant=  66.67  ns\n",
-        "\n",
-        "\n",
-        "corner frequency=  2.39  MHz\n",
-        "\n",
-        "\n",
-        "maximum small signal voltage gain=\n",
-        " 1.44 \n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg409"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.7\n",
-      "Vbe=0.7;\n",
-      "b=100.;\n",
-      "Re=.5;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "R1=40.;\n",
-      "Cc=10.;\n",
-      "R2=5.7;\n",
-      "Rs=.1;\n",
-      "Vt=0.026;\n",
-      "Icq=0.99;\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\ndiffusion resistance= ',r,' KOhm\\n')\n",
-      "Ri=r+(1.+b)*Re;\n",
-      "print\"%s %.2f %s\"%('\\ninput resistance= ',Ri,' KOhm\\n')\n",
-      "x=Rc*Rl/(Rc+Rl);\n",
-      "y=R1*R2/(R1+R2);\n",
-      "t=y*Ri/(y+Ri);\n",
-      "Av=gm*r*x*(y/(y+Ri))*(1./(Rs+t));\n",
-      "print\"%s %.2f %s\"%('\\nmaximum small signal voltage gain=\\n',Av,'')\n",
-      "Ts=(Rs+t)*Cc;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant=\\n',Ts,'ms')\n",
-      "Ts=46.6*0.001;##sec\n",
-      "Cl=15.;\n",
-      "Tp=x*Cl;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant ',Tp,' ns\\n')\n",
-      "fL=1/(2.*math.pi*Ts);\n",
-      "print\"%s %.2f %s\"%('\\nlower corner frequency= ',fL,' Hz\\n')\n",
-      "Tp=50.*10**-3;##micro sec\n",
-      "fH=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\nupper corner frequency= ',fH,' MHz\\n')\n",
-      "fL=3.4*10**-6;##MHz\n",
-      "fbw=fH-fL;\n",
-      "print\"%s %.2f %s\"%('\\nbandwidth = ',fbw,'MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance=  38.08  mA/V\n",
-        "\n",
-        "\n",
-        "diffusion resistance=  2.63  KOhm\n",
-        "\n",
-        "\n",
-        "input resistance=  53.13  KOhm\n",
-        "\n",
-        "\n",
-        "maximum small signal voltage gain=\n",
-        " 6.14 \n",
-        "\n",
-        "time constant=\n",
-        " 46.61 ms\n",
-        "\n",
-        "time constant  50.00  ns\n",
-        "\n",
-        "\n",
-        "lower corner frequency=  3.42  Hz\n",
-        "\n",
-        "\n",
-        "upper corner frequency=  3.18  MHz\n",
-        "\n",
-        "\n",
-        "bandwidth =  3.18 MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg412"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 7.8\n",
-      "Re=4.;\n",
-      "Rc=2.;\n",
-      "Rs=0.5;\n",
-      "Vt=0.026;\n",
-      "Ce=1*10**-3;\n",
-      "V1=5.;\n",
-      "Icq=1.06;\n",
-      "V2=-5.;\n",
-      "b=100.;\n",
-      "Vbe=0.7;\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\ndiffusion resistance= ',r,' KOhm\\n')\n",
-      "Ta=Re*Ce;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant Ta= ',Ta,'f s\\n')\n",
-      "Tb=(Re*Ce*(Rs+r))/(Rs+r+(1+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant Tb= ',Tb,' s\\n')\n",
-      "fA=1/(2.*math.pi*Ta);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency = ',fA,'Hz\\n')\n",
-      "Tb=2.9*0.01;##msec\n",
-      "fB=1/(2.*math.pi*Tb);\n",
-      "print\"%s %.2f %s\"%('\\ncorner frequency =',fB,'khz')\n",
-      "Av=(gm*r*Rc)/(Rs+r+(1.+b)*Re);\n",
-      "print\"%s %.2f %s\"%('\\nlimiting low frequency horizontal asymptote= \\n',Av,'')\n",
-      "Av=gm*r*Rc/(Rs+r);\n",
-      "print\"%s %.2f %s\"%('\\nnlimiting high frequency horizontal asymptote=\\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance =  40.77 mA/V\n",
-        "\n",
-        "\n",
-        "diffusion resistance=  2.45  KOhm\n",
-        "\n",
-        "\n",
-        "time constant Ta=  0.00 f s\n",
-        "\n",
-        "\n",
-        "time constant Tb=  0.00  s\n",
-        "\n",
-        "\n",
-        "corner frequency =  39.79 Hz\n",
-        "\n",
-        "\n",
-        "corner frequency = 5.49 khz\n",
-        "\n",
-        "limiting low frequency horizontal asymptote= \n",
-        " 0.49 \n",
-        "\n",
-        "nlimiting high frequency horizontal asymptote=\n",
-        " 67.73 \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg420"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.9\n",
-      "r=2600.;\n",
-      "C1=2.*10**-6;\n",
-      "C2=0.1*10**-6;\n",
-      "fB=1/(2.*math.pi*r*(C1+C2));\n",
-      "print\"%s %.2f %s\"%('\\n3dB frequency= ',fB,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "3dB frequency=  29.15  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex10-pg421"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.10\n",
-      "fT=500.;\n",
-      "Ic=1.;\n",
-      "b=100.;\n",
-      "Vt=0.026;\n",
-      "C2=0.3*10**-12;\n",
-      "fB=fT/b;\n",
-      "print\"%s %.2f %s\"%('\\nbandwidth= ',fB,' MHz\\n')\n",
-      "gm=Ic/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,'mA/V\\n')\n",
-      "fT=500000000.;\n",
-      "gm=38.5*0.001;\n",
-      "C1=gm/(fT*2.*math.pi)-C2;\n",
-      "print\"%s %.2e %s\"%('\\ncapacitance = ',C1,'F\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "bandwidth=  5.00  MHz\n",
-        "\n",
-        "\n",
-        "transconductance=  38.46 mA/V\n",
-        "\n",
-        "\n",
-        "capacitance =  1.20e-11 F\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex12-pg430"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.12\n",
-      "Kn=0.25;\n",
-      "Vtn=1.;\n",
-      "Cgd=0.04*10**-3;\n",
-      "Cgs=0.2*10**-3;\n",
-      "Vgs=3.;\n",
-      "gm=2.*Kn*(Vgs-Vtn);\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance = ',gm,'mA/V\\n')\n",
-      "fT=gm/(2.*math.pi*(Cgd+Cgs));\n",
-      "print\"%s %.2f %s\"%('\\nunity gain bandwidth= ',fT,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "transconductance =  1.00 mA/V\n",
-        "\n",
-        "\n",
-        "unity gain bandwidth=  663.15  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex13-pg432"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 7.13\n",
-      "gm=1.;\n",
-      "Cgd=0.04;\n",
-      "Rl=10.;\n",
-      "Cgs=0.2;\n",
-      "Cm=Cgd*(1.+gm*Rl);\n",
-      "print\"%s %.2f %s\"%('\\nMiller capacitance= ',Cm,' pF\\n')\n",
-      "Cm=0.44*0.001;##nF\n",
-      "Cgs=0.2*0.001;##nF\n",
-      "fT=gm/(2.*math.pi*(Cgs+Cm));\n",
-      "print\"%s %.2f %s\"%('\\ncutoff frequency= ',fT,' MHz\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "Miller capacitance=  0.44  pF\n",
-        "\n",
-        "\n",
-        "cutoff frequency=  248.68  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex14-pg435"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.14\n",
-      "V1=5.;\n",
-      "V=-5.;\n",
-      "Rs=0.1;\n",
-      "Rb=40.;\n",
-      "R2=5.72;\n",
-      "Re=0.5;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "b=150.;\n",
-      "Vbe=0.7;\n",
-      "C1=35*10**-3;\n",
-      "C2=4.;\n",
-      "Vt=0.026;\n",
-      "Icq=1.02;\n",
-      "r=b*Vt/Icq;\n",
-      "print\"%s %.2f %s\"%('\\nsmall signal parameter= ',r,' KOhm\\n')\n",
-      "gm=Icq/Vt;\n",
-      "print\"%s %.2f %s\"%('\\ntransconductance= ',gm,' mA/V\\n')\n",
-      "Cm=C2*(1+gm*Rc*Rl/(Rc+Rl));\n",
-      "print\"%s %.2f %s\"%('\\nMiller capacitance= ',Cm,' pF\\n')\n",
-      "Cm=527.*10**-3;\n",
-      "x=Rb*Rs/(Rb+Rs);\n",
-      "y=r*x/(r+x);\n",
-      "fH=1/(2.*math.pi*y*(C1+Cm));\n",
-      "print\"%s %.2f %s\"%('\\nupper corner frequency = ',fH,'MHz\\n')\n",
-      "t=Rb*r/(Rb+r);\n",
-      "p=Rc*Rl/(Rc+Rl);\n",
-      "Av=gm*p*t/(t+Rs);\n",
-      "print\"%s %.2f %s\"%('\\nmidband gain= ',Av,'\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "small signal parameter=  3.82  KOhm\n",
-        "\n",
-        "\n",
-        "transconductance=  39.23  mA/V\n",
-        "\n",
-        "\n",
-        "Miller capacitance=  527.08  pF\n",
-        "\n",
-        "\n",
-        "upper corner frequency =  2.91 MHz\n",
-        "\n",
-        "\n",
-        "midband gain=  127.13 \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 13
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex15-pg439"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.15\n",
-      "V1=5.;\n",
-      "V=-5.;\n",
-      "Rs=0.1;\n",
-      "R1=40.;\n",
-      "R2=5.72;\n",
-      "Re=0.5;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "b=150.;\n",
-      "Vbe=0.7;\n",
-      "C1=35.;\n",
-      "C2=4.;\n",
-      "Vt=0.026;\n",
-      "Icq=1.02;\n",
-      "gm=39.2;\n",
-      "r=3.82;\n",
-      "x=Re*Rs/(Re+Rs);\n",
-      "t=r/(1.+b);\n",
-      "y=t*x/(t+x);\n",
-      "Tp=y*C1;\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=0.679*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\nupper frequency = ',f,'MHz\\n')\n",
-      "T=C2*Rc*Rl/(Rc+Rl);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',T,' ns\\n')\n",
-      "T=13.3*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*T);\n",
-      "print\"%s %.2f %s\"%('\\nupper frequency= ',f,' MHz\\n')\n",
-      "x=Rc*Rl/(Rc+Rl);\n",
-      "y=Re*t/(Re+t);\n",
-      "Av=gm*x*(y/(y+Rs));\n",
-      "print\"%s %.2f %s\"%('\\nmidband voltage gain \\n',Av,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "time constant=  0.68  ns\n",
-        "\n",
-        "\n",
-        "upper frequency =  234.40 MHz\n",
-        "\n",
-        "\n",
-        "time constant=  13.33  ns\n",
-        "\n",
-        "\n",
-        "upper frequency=  11.97  MHz\n",
-        "\n",
-        "\n",
-        "midband voltage gain \n",
-        " 25.36 \n"
-       ]
-      }
-     ],
-     "prompt_number": 14
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16-pg443"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 7.16\n",
-      "V1=5.;\n",
-      "V=-5.;\n",
-      "Rs=0.1;\n",
-      "R1=42.5;\n",
-      "R2=20.5;\n",
-      "R3=28.3;\n",
-      "Re=5.4;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "b=150.;\n",
-      "Vbe=0.7;\n",
-      "C1=35.;\n",
-      "C2=4.;\n",
-      "Vt=0.026;\n",
-      "Icq=1.02;\n",
-      "gm=39.2;\n",
-      "r=3.820;\n",
-      "Rb=R2*R3/(R2+R3);\n",
-      "x=Rb*r/(Rb+r);\n",
-      "y=Rs*x/(x+Rs);\n",
-      "Tp=y*(C1+2*C2);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=Tp*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*Tp);\n",
-      "print\"%s %.2f %s\"%('\\n3dB frequency = ',f,'MHz\\n')\n",
-      "T=C2*Rc*Rl/(Rc+Rl);\n",
-      "print\"%s %.2f %s\"%('\\ntime constant= ',T,'ns\\n')\n",
-      "T=T*0.001;##micro sec\n",
-      "f=1/(2.*math.pi*T);\n",
-      "print\"%s %.2f %s\"%('\\nupper frequency= ',f,' MHz\\n')\n",
-      "x=Rc*Rl/(Rc+Rl);\n",
-      "y=Rb*r/(Rb+r);\n",
-      "Av=gm*x*(y/(y+Rs));\n",
-      "print\"%s %.2f %s\"%('\\nmidband voltage gain= ',Av,' \\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "time constant=  4.16  ns\n",
-        "\n",
-        "\n",
-        "3dB frequency =  38.29 MHz\n",
-        "\n",
-        "\n",
-        "time constant=  13.33 ns\n",
-        "\n",
-        "\n",
-        "upper frequency=  11.94  MHz\n",
-        "\n",
-        "\n",
-        "midband voltage gain=  126.30  \n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 15
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex17-pg447"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##Example 7.17\n",
-      "V1=5.;\n",
-      "V=-5.;\n",
-      "Rs=0.1;\n",
-      "R1=40;\n",
-      "R2=5.720;\n",
-      "Re=0.5;\n",
-      "Rc=5.;\n",
-      "Rl=10.;\n",
-      "b=150.;\n",
-      "Vbe=0.7;\n",
-      "C1=35.;\n",
-      "C2=4.;\n",
-      "Vt=0.026;\n",
-      "Icq=1.02;\n",
-      "gm=39.2;\n",
-      "r=3.820;\n",
-      "t=r/(1.+b);\n",
-      "t=t*0.001;\n",
-      "f=1/(2.*math.pi*C1*t);\n",
-      "print'%s %.2f %s'%('\\nthe zero occurs at this frequency= ',f,' MHz\\n')\n",
-      "x=1+gm*Re*Rl/(Re+Rl);\n",
-      "Rb=R1*R2/(R1+R2)\n",
-      "d=x*r;\n",
-      "y=d*Rb/(d+Rb);\n",
-      "t=y*Rs/(y+Rs);\n",
-      "Tp=t*(C2+C1/x);\n",
-      "print'%s %.2f %s'%('\\ntime constant= ',Tp,' ns\\n')\n",
-      "Tp=Tp*10**-3;##micro sec\n",
-      "f=1/(2.*math.pi*Tp);\n",
-      "print'%s %.2f %s'%('\\n3dB frequency= ',f,' MHz\\n')"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "the zero occurs at this frequency=  179.75  MHz\n",
-        "\n",
-        "\n",
-        "time constant=  0.57  ns\n",
-        "\n",
-        "\n",
-        "3dB frequency=  281.24  MHz\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 17
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter8.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter8.ipynb
deleted file mode 100755
index fd68eb2b..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter8.ipynb
+++ /dev/null
@@ -1,447 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:92d1830ec3843ba385a218c6a4322e578c945c5df33293c6543963425e76ab14"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter8-Ouput Stages and Power Amplifier "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg478"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.1\n",
-      "##let thermal resistance parameters be R\n",
-      "Rdcase=1.75;##degree celsius per watt\n",
-      "Rcsnk=1.;##degree celsius per watt\n",
-      "Rsamb=5.;##degree celsius per watt\n",
-      "Rcamb=50.;##degree celsius per watt\n",
-      "Tamb=30.;##ambient temperature \n",
-      "Tjmax=150.;##maximum junction temperature\n",
-      "Tdev=150.;##device temperature\n",
-      "##when no heat sink is used\n",
-      "P=(Tjmax-Tamb)/(Rdcase+Rcamb);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipation= ',P,' W\\n')\n",
-      "##when heat sink is used\n",
-      "P=(Tjmax-Tamb)/(Rdcase+Rcsnk+Rsamb);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipation= ',P,' W\\n')\n",
-      "\n",
-      "\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "maximum power dissipation=  2.32  W\n",
-        "\n",
-        "\n",
-        "maximum power dissipation=  15.48  W\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg479"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.3\n",
-      "Rcsnk=1.;##degree celsius per watt\n",
-      "Rsamb=5.;##degree celsius per watt\n",
-      "Tjmax=175.;##maximum junction temperature\n",
-      "Toc=25.;\n",
-      "Tamb=25.;\n",
-      "Pr=20.;##rated power W\n",
-      "Rdcase=(Tjmax-Toc)/Pr;\n",
-      "print\"%s %.2f %s\"%('\\ndevice to case thermal resistance= ',Rdcase,' C/W\\n')\n",
-      "P=(Tjmax-Tamb)/(Rdcase+Rcsnk+Rsamb);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipation= ',P,' W\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "device to case thermal resistance=  7.50  C/W\n",
-        "\n",
-        "\n",
-        "maximum power dissipation=  11.11  W\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg492"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.7\n",
-      "Vdd=10.;\n",
-      "Rl=20.;\n",
-      "K=0.2;\n",
-      "Vt=1.;\n",
-      "vo=5.;\n",
-      "iL=vo/20.;\n",
-      "print\"%s %.2f %s\"%('\\niL= ',iL,' A\\n')\n",
-      "Idq=0.05;\n",
-      "##Idq=K*(Vbb/2-Vt)\n",
-      "Vbb=(math.sqrt(Idq/K)+1.)*2.;\n",
-      "print\"%s %.2f %s\"%('\\nVbb= ',Vbb,' V\\n')\n",
-      "iD=iL;\n",
-      "Vgsn=math.sqrt(iD/K)+Vt;\n",
-      "print\"%s %.2f %s\"%('\\nVgsn= ',Vgsn,' V\\n')\n",
-      "Vsgp=Vbb-Vgsn;\n",
-      "print\"%s %.2f %s\"%('\\nVsgp= ',Vsgp,' V\\n')\n",
-      "vi=vo+Vgsn-Vbb/2.;\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage= ',vi,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "iL=  0.25  A\n",
-        "\n",
-        "\n",
-        "Vbb=  3.00  V\n",
-        "\n",
-        "\n",
-        "Vgsn=  2.12  V\n",
-        "\n",
-        "\n",
-        "Vsgp=  0.88  V\n",
-        "\n",
-        "\n",
-        "input voltage=  5.62  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg498"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 8.8\n",
-      "Vcc=24.;\n",
-      "Rl=8.;\n",
-      "P=5.;\n",
-      "Vbe=0.7;\n",
-      "b=100.;\n",
-      "Vp=math.sqrt(2.*Rl*P);\n",
-      "print\"%s %.2f %s\"%('\\npeak output voltage= ',Vp,' V\\n')\n",
-      "Ip=Vp/Rl;\n",
-      "print\"%s %.2f %s\"%('\\npeak output current = ',Ip,'A\\n')\n",
-      "a=0.9*Vcc/Vp;\n",
-      "print\"%s %.2f %s\"%('\\na= ',a,'\\n')\n",
-      "Icq=Ip/(0.9*a);\n",
-      "print\"%s %.2f %s\"%('\\nIcq= ',Icq,' A\\n')\n",
-      "Pq=Vcc*Icq;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipated in the transistor= ',Pq,' W\\n')\n",
-      "Ibq=Icq/b;\n",
-      "Ibq=Ibq*1000.;##mA\n",
-      "print\"%s %.2f %s\"%('\\nbase current Ibq= ',Ibq,' mA\\n')\n",
-      "Rth=2.500;\n",
-      "##Vth=Vcc*Rth/R1 and Vth=Ibq*Rth+Vbe\n",
-      "R1=Vcc*Rth/(Ibq*Rth+Vbe);\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n",
-      "R2=Rth*R1/(R1-Rth);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "peak output voltage=  8.94  V\n",
-        "\n",
-        "\n",
-        "peak output current =  1.12 A\n",
-        "\n",
-        "\n",
-        "a=  2.41 \n",
-        "\n",
-        "\n",
-        "Icq=  0.51  A\n",
-        "\n",
-        "\n",
-        "maximum power dissipated in the transistor=  12.35  W\n",
-        "\n",
-        "\n",
-        "base current Ibq=  5.14  mA\n",
-        "\n",
-        "\n",
-        "R1=  4.42  KOhm\n",
-        "\n",
-        "\n",
-        "R2=  5.75  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg500"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.9\n",
-      "Iso=3*10**-14;\n",
-      "Isq=10**-13;\n",
-      "b=75.;\n",
-      "Vt=0.026;\n",
-      "Rl=8.;\n",
-      "P=5.;\n",
-      "Vp=math.sqrt(2.*Rl*P);\n",
-      "print\"%s %.2f %s\"%('\\npeak voltage Vp= ',Vp,' V\\n')\n",
-      "Vcc=Vp/0.8;\n",
-      "print\"%s %.2f %s\"%('\\nsupply voltage= ',Vcc,' V\\n')\n",
-      "Ien=Vp/Rl;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ien,' A\\n')\n",
-      "Ibn=Ien/(1.+b);\n",
-      "Ibn=Ibn*1000.;##mA\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ibn,' mA\\n')\n",
-      "iD=0.020;\n",
-      "Vbb=2.*Vt*math.log(iD/Iso);\n",
-      "print\"%s %.2f %s\"%('\\nVbb= ',Vbb,' V\\n')\n",
-      "Icq=Isq*math.exp((Vbb/2.)/Vt);\n",
-      "Icq=Icq*1000.;##mA\n",
-      "print\"%s %.2f %s\"%('\\nquiescent collector current= ',Icq,' mA\\n')\n",
-      "Ibias=20.;##mA\n",
-      "iD=Ibias-Ibn;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',iD,' mA\\n')\n",
-      "iD=iD*0.001;##A\n",
-      "Vbb=2.*Vt*math.log(iD/Iso);\n",
-      "print\"%s %.2f %s\"%('\\nVbb= ',Vbb,' V\\n')\n",
-      "Icn=1.12;\n",
-      "Vben=Vt*math.log(Icn/Isq);\n",
-      "print\"%s %.2f %s\"%('\\nB-E voltage of Qn= ',Vben,' V\\n')\n",
-      "Vebp=Vbb-Vben;\n",
-      "print\"%s %.2f %s\"%('\\nemitter base voltage of Qp= ',Vebp,' V\\n')\n",
-      "Icp=Isq*math.exp(Vebp/Vt);\n",
-      "Icp=Icp*1000.;##mA\n",
-      "print\"%s %.2f %s\"%('\\nIcp ',Icp,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "peak voltage Vp=  8.94  V\n",
-        "\n",
-        "\n",
-        "supply voltage=  11.18  V\n",
-        "\n",
-        "\n",
-        "emitter current=  1.12  A\n",
-        "\n",
-        "\n",
-        "base current=  14.71  mA\n",
-        "\n",
-        "\n",
-        "Vbb=  1.42  V\n",
-        "\n",
-        "\n",
-        "quiescent collector current=  66.67  mA\n",
-        "\n",
-        "\n",
-        "drain current=  5.29  mA\n",
-        "\n",
-        "\n",
-        "Vbb=  1.35  V\n",
-        "\n",
-        "\n",
-        "B-E voltage of Qn=  0.78  V\n",
-        "\n",
-        "\n",
-        "emitter base voltage of Qp=  0.57  V\n",
-        "\n",
-        "\n",
-        "Icp  0.28  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg505"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.11\n",
-      "R1=2.;##KOhm\n",
-      "R2=R1;\n",
-      "Rl=.1;##KOhm\n",
-      "b=60.;\n",
-      "Vbe=0.6;\n",
-      "Veb=0.6;\n",
-      "V1=15.;\n",
-      "V2=V1;\n",
-      "iR1=(V1-Vbe)/R1;\n",
-      "##iR1=iR2=iE1=iE2\n",
-      "print\"%s %.2f %s\"%('\\niR1= ',iR1,' mA\\n')\n",
-      "vo=10.;\n",
-      "io=vo/Rl;\n",
-      "print\"%s %.2f %s\"%('\\noutput current= ',io,' mA\\n')\n",
-      "iB3=100./61.;\n",
-      "print\"%s %.2f %s\"%('\\niB3= ',iB3,'mA\\n')\n",
-      "iR1=(V1-(10.+Vbe))/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent in R1= ',iR1,' mA\\n')\n",
-      "iE1=iR1-iB3;\n",
-      "print\"%s %.2f %s\"%('\\niE1= ',iE1,' mA\\n')\n",
-      "iB1=iE1/(1.+b);\n",
-      "iB1=iB1*1000.;##micro A\n",
-      "print\"%s %.2f %s\"%('\\niB1= ',iB1,' microA\\n')\n",
-      "iE2=(10-0.6+15.)/R1;\n",
-      "print\"%s %.2f %s\"%('\\niE2= ',iE2,' mA\\n')\n",
-      "iB2=iE2/(1.+b);\n",
-      "iB2=iB2*1000.;\n",
-      "print\"%s %.2f %s\"%('\\niB2= ',iB2,' microA\\n')\n",
-      "Ii=iB2-iB1;\n",
-      "print\"%s %.2f %s\"%('\\ninput current= ',Ii,' microA\\n')\n",
-      "Ii=Ii*0.001;##mA\n",
-      "Ai=io/Ii;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent gain=\\n',Ai,'')\n",
-      "Ai=(1.+b)*R1/(2.*Rl);\n",
-      "print\"%s %.2f %s\"%('\\npredicted current gain=\\n',Ai,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "iR1=  7.20  mA\n",
-        "\n",
-        "\n",
-        "output current=  100.00  mA\n",
-        "\n",
-        "\n",
-        "iB3=  1.64 mA\n",
-        "\n",
-        "\n",
-        "current in R1=  2.20  mA\n",
-        "\n",
-        "\n",
-        "iE1=  0.56  mA\n",
-        "\n",
-        "\n",
-        "iB1=  9.19  microA\n",
-        "\n",
-        "\n",
-        "iE2=  12.20  mA\n",
-        "\n",
-        "\n",
-        "iB2=  200.00  microA\n",
-        "\n",
-        "\n",
-        "input current=  190.81  microA\n",
-        "\n",
-        "\n",
-        "current gain=\n",
-        " 524.08 \n",
-        "\n",
-        "predicted current gain=\n",
-        " 610.00 \n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter8_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter8_1.ipynb
deleted file mode 100755
index fd68eb2b..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter8_1.ipynb
+++ /dev/null
@@ -1,447 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:92d1830ec3843ba385a218c6a4322e578c945c5df33293c6543963425e76ab14"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter8-Ouput Stages and Power Amplifier "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg478"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.1\n",
-      "##let thermal resistance parameters be R\n",
-      "Rdcase=1.75;##degree celsius per watt\n",
-      "Rcsnk=1.;##degree celsius per watt\n",
-      "Rsamb=5.;##degree celsius per watt\n",
-      "Rcamb=50.;##degree celsius per watt\n",
-      "Tamb=30.;##ambient temperature \n",
-      "Tjmax=150.;##maximum junction temperature\n",
-      "Tdev=150.;##device temperature\n",
-      "##when no heat sink is used\n",
-      "P=(Tjmax-Tamb)/(Rdcase+Rcamb);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipation= ',P,' W\\n')\n",
-      "##when heat sink is used\n",
-      "P=(Tjmax-Tamb)/(Rdcase+Rcsnk+Rsamb);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipation= ',P,' W\\n')\n",
-      "\n",
-      "\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "maximum power dissipation=  2.32  W\n",
-        "\n",
-        "\n",
-        "maximum power dissipation=  15.48  W\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg479"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.3\n",
-      "Rcsnk=1.;##degree celsius per watt\n",
-      "Rsamb=5.;##degree celsius per watt\n",
-      "Tjmax=175.;##maximum junction temperature\n",
-      "Toc=25.;\n",
-      "Tamb=25.;\n",
-      "Pr=20.;##rated power W\n",
-      "Rdcase=(Tjmax-Toc)/Pr;\n",
-      "print\"%s %.2f %s\"%('\\ndevice to case thermal resistance= ',Rdcase,' C/W\\n')\n",
-      "P=(Tjmax-Tamb)/(Rdcase+Rcsnk+Rsamb);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipation= ',P,' W\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "device to case thermal resistance=  7.50  C/W\n",
-        "\n",
-        "\n",
-        "maximum power dissipation=  11.11  W\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg492"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.7\n",
-      "Vdd=10.;\n",
-      "Rl=20.;\n",
-      "K=0.2;\n",
-      "Vt=1.;\n",
-      "vo=5.;\n",
-      "iL=vo/20.;\n",
-      "print\"%s %.2f %s\"%('\\niL= ',iL,' A\\n')\n",
-      "Idq=0.05;\n",
-      "##Idq=K*(Vbb/2-Vt)\n",
-      "Vbb=(math.sqrt(Idq/K)+1.)*2.;\n",
-      "print\"%s %.2f %s\"%('\\nVbb= ',Vbb,' V\\n')\n",
-      "iD=iL;\n",
-      "Vgsn=math.sqrt(iD/K)+Vt;\n",
-      "print\"%s %.2f %s\"%('\\nVgsn= ',Vgsn,' V\\n')\n",
-      "Vsgp=Vbb-Vgsn;\n",
-      "print\"%s %.2f %s\"%('\\nVsgp= ',Vsgp,' V\\n')\n",
-      "vi=vo+Vgsn-Vbb/2.;\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage= ',vi,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "iL=  0.25  A\n",
-        "\n",
-        "\n",
-        "Vbb=  3.00  V\n",
-        "\n",
-        "\n",
-        "Vgsn=  2.12  V\n",
-        "\n",
-        "\n",
-        "Vsgp=  0.88  V\n",
-        "\n",
-        "\n",
-        "input voltage=  5.62  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg498"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 8.8\n",
-      "Vcc=24.;\n",
-      "Rl=8.;\n",
-      "P=5.;\n",
-      "Vbe=0.7;\n",
-      "b=100.;\n",
-      "Vp=math.sqrt(2.*Rl*P);\n",
-      "print\"%s %.2f %s\"%('\\npeak output voltage= ',Vp,' V\\n')\n",
-      "Ip=Vp/Rl;\n",
-      "print\"%s %.2f %s\"%('\\npeak output current = ',Ip,'A\\n')\n",
-      "a=0.9*Vcc/Vp;\n",
-      "print\"%s %.2f %s\"%('\\na= ',a,'\\n')\n",
-      "Icq=Ip/(0.9*a);\n",
-      "print\"%s %.2f %s\"%('\\nIcq= ',Icq,' A\\n')\n",
-      "Pq=Vcc*Icq;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipated in the transistor= ',Pq,' W\\n')\n",
-      "Ibq=Icq/b;\n",
-      "Ibq=Ibq*1000.;##mA\n",
-      "print\"%s %.2f %s\"%('\\nbase current Ibq= ',Ibq,' mA\\n')\n",
-      "Rth=2.500;\n",
-      "##Vth=Vcc*Rth/R1 and Vth=Ibq*Rth+Vbe\n",
-      "R1=Vcc*Rth/(Ibq*Rth+Vbe);\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n",
-      "R2=Rth*R1/(R1-Rth);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "peak output voltage=  8.94  V\n",
-        "\n",
-        "\n",
-        "peak output current =  1.12 A\n",
-        "\n",
-        "\n",
-        "a=  2.41 \n",
-        "\n",
-        "\n",
-        "Icq=  0.51  A\n",
-        "\n",
-        "\n",
-        "maximum power dissipated in the transistor=  12.35  W\n",
-        "\n",
-        "\n",
-        "base current Ibq=  5.14  mA\n",
-        "\n",
-        "\n",
-        "R1=  4.42  KOhm\n",
-        "\n",
-        "\n",
-        "R2=  5.75  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg500"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.9\n",
-      "Iso=3*10**-14;\n",
-      "Isq=10**-13;\n",
-      "b=75.;\n",
-      "Vt=0.026;\n",
-      "Rl=8.;\n",
-      "P=5.;\n",
-      "Vp=math.sqrt(2.*Rl*P);\n",
-      "print\"%s %.2f %s\"%('\\npeak voltage Vp= ',Vp,' V\\n')\n",
-      "Vcc=Vp/0.8;\n",
-      "print\"%s %.2f %s\"%('\\nsupply voltage= ',Vcc,' V\\n')\n",
-      "Ien=Vp/Rl;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ien,' A\\n')\n",
-      "Ibn=Ien/(1.+b);\n",
-      "Ibn=Ibn*1000.;##mA\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ibn,' mA\\n')\n",
-      "iD=0.020;\n",
-      "Vbb=2.*Vt*math.log(iD/Iso);\n",
-      "print\"%s %.2f %s\"%('\\nVbb= ',Vbb,' V\\n')\n",
-      "Icq=Isq*math.exp((Vbb/2.)/Vt);\n",
-      "Icq=Icq*1000.;##mA\n",
-      "print\"%s %.2f %s\"%('\\nquiescent collector current= ',Icq,' mA\\n')\n",
-      "Ibias=20.;##mA\n",
-      "iD=Ibias-Ibn;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',iD,' mA\\n')\n",
-      "iD=iD*0.001;##A\n",
-      "Vbb=2.*Vt*math.log(iD/Iso);\n",
-      "print\"%s %.2f %s\"%('\\nVbb= ',Vbb,' V\\n')\n",
-      "Icn=1.12;\n",
-      "Vben=Vt*math.log(Icn/Isq);\n",
-      "print\"%s %.2f %s\"%('\\nB-E voltage of Qn= ',Vben,' V\\n')\n",
-      "Vebp=Vbb-Vben;\n",
-      "print\"%s %.2f %s\"%('\\nemitter base voltage of Qp= ',Vebp,' V\\n')\n",
-      "Icp=Isq*math.exp(Vebp/Vt);\n",
-      "Icp=Icp*1000.;##mA\n",
-      "print\"%s %.2f %s\"%('\\nIcp ',Icp,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "peak voltage Vp=  8.94  V\n",
-        "\n",
-        "\n",
-        "supply voltage=  11.18  V\n",
-        "\n",
-        "\n",
-        "emitter current=  1.12  A\n",
-        "\n",
-        "\n",
-        "base current=  14.71  mA\n",
-        "\n",
-        "\n",
-        "Vbb=  1.42  V\n",
-        "\n",
-        "\n",
-        "quiescent collector current=  66.67  mA\n",
-        "\n",
-        "\n",
-        "drain current=  5.29  mA\n",
-        "\n",
-        "\n",
-        "Vbb=  1.35  V\n",
-        "\n",
-        "\n",
-        "B-E voltage of Qn=  0.78  V\n",
-        "\n",
-        "\n",
-        "emitter base voltage of Qp=  0.57  V\n",
-        "\n",
-        "\n",
-        "Icp  0.28  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg505"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.11\n",
-      "R1=2.;##KOhm\n",
-      "R2=R1;\n",
-      "Rl=.1;##KOhm\n",
-      "b=60.;\n",
-      "Vbe=0.6;\n",
-      "Veb=0.6;\n",
-      "V1=15.;\n",
-      "V2=V1;\n",
-      "iR1=(V1-Vbe)/R1;\n",
-      "##iR1=iR2=iE1=iE2\n",
-      "print\"%s %.2f %s\"%('\\niR1= ',iR1,' mA\\n')\n",
-      "vo=10.;\n",
-      "io=vo/Rl;\n",
-      "print\"%s %.2f %s\"%('\\noutput current= ',io,' mA\\n')\n",
-      "iB3=100./61.;\n",
-      "print\"%s %.2f %s\"%('\\niB3= ',iB3,'mA\\n')\n",
-      "iR1=(V1-(10.+Vbe))/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent in R1= ',iR1,' mA\\n')\n",
-      "iE1=iR1-iB3;\n",
-      "print\"%s %.2f %s\"%('\\niE1= ',iE1,' mA\\n')\n",
-      "iB1=iE1/(1.+b);\n",
-      "iB1=iB1*1000.;##micro A\n",
-      "print\"%s %.2f %s\"%('\\niB1= ',iB1,' microA\\n')\n",
-      "iE2=(10-0.6+15.)/R1;\n",
-      "print\"%s %.2f %s\"%('\\niE2= ',iE2,' mA\\n')\n",
-      "iB2=iE2/(1.+b);\n",
-      "iB2=iB2*1000.;\n",
-      "print\"%s %.2f %s\"%('\\niB2= ',iB2,' microA\\n')\n",
-      "Ii=iB2-iB1;\n",
-      "print\"%s %.2f %s\"%('\\ninput current= ',Ii,' microA\\n')\n",
-      "Ii=Ii*0.001;##mA\n",
-      "Ai=io/Ii;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent gain=\\n',Ai,'')\n",
-      "Ai=(1.+b)*R1/(2.*Rl);\n",
-      "print\"%s %.2f %s\"%('\\npredicted current gain=\\n',Ai,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "iR1=  7.20  mA\n",
-        "\n",
-        "\n",
-        "output current=  100.00  mA\n",
-        "\n",
-        "\n",
-        "iB3=  1.64 mA\n",
-        "\n",
-        "\n",
-        "current in R1=  2.20  mA\n",
-        "\n",
-        "\n",
-        "iE1=  0.56  mA\n",
-        "\n",
-        "\n",
-        "iB1=  9.19  microA\n",
-        "\n",
-        "\n",
-        "iE2=  12.20  mA\n",
-        "\n",
-        "\n",
-        "iB2=  200.00  microA\n",
-        "\n",
-        "\n",
-        "input current=  190.81  microA\n",
-        "\n",
-        "\n",
-        "current gain=\n",
-        " 524.08 \n",
-        "\n",
-        "predicted current gain=\n",
-        " 610.00 \n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter8_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter8_1_1.ipynb
deleted file mode 100755
index c0c5ebd2..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter8_1_1.ipynb
+++ /dev/null
@@ -1,447 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:cdd1f791d4e53fd374d40ced42151b47691b22d0170edabcbe64af78e36e0de3"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter8-Ouput Stages and Power Amplifier "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex2-pg478"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.1\n",
-      "##let thermal resistance parameters be R\n",
-      "Rdcase=1.75;##degree celsius per watt\n",
-      "Rcsnk=1.;##degree celsius per watt\n",
-      "Rsamb=5.;##degree celsius per watt\n",
-      "Rcamb=50.;##degree celsius per watt\n",
-      "Tamb=30.;##ambient temperature \n",
-      "Tjmax=150.;##maximum junction temperature\n",
-      "Tdev=150.;##device temperature\n",
-      "##when no heat sink is used\n",
-      "P=(Tjmax-Tamb)/(Rdcase+Rcamb);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipation= ',P,' W\\n')\n",
-      "##when heat sink is used\n",
-      "P=(Tjmax-Tamb)/(Rdcase+Rcsnk+Rsamb);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipation= ',P,' W\\n')\n",
-      "\n",
-      "\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "maximum power dissipation=  2.32  W\n",
-        "\n",
-        "\n",
-        "maximum power dissipation=  15.48  W\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex3-pg479"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.3\n",
-      "Rcsnk=1.;##degree celsius per watt\n",
-      "Rsamb=5.;##degree celsius per watt\n",
-      "Tjmax=175.;##maximum junction temperature\n",
-      "Toc=25.;\n",
-      "Tamb=25.;\n",
-      "Pr=20.;##rated power W\n",
-      "Rdcase=(Tjmax-Toc)/Pr;\n",
-      "print\"%s %.2f %s\"%('\\ndevice to case thermal resistance= ',Rdcase,' C/W\\n')\n",
-      "P=(Tjmax-Tamb)/(Rdcase+Rcsnk+Rsamb);\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipation= ',P,' W\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "device to case thermal resistance=  7.50  C/W\n",
-        "\n",
-        "\n",
-        "maximum power dissipation=  11.11  W\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex7-pg492"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.7\n",
-      "Vdd=10.;\n",
-      "Rl=20.;\n",
-      "K=0.2;\n",
-      "Vt=1.;\n",
-      "vo=5.;\n",
-      "iL=vo/20.;\n",
-      "print\"%s %.2f %s\"%('\\niL= ',iL,' A\\n')\n",
-      "Idq=0.05;\n",
-      "##Idq=K*(Vbb/2-Vt)\n",
-      "Vbb=(math.sqrt(Idq/K)+1.)*2.;\n",
-      "print\"%s %.2f %s\"%('\\nVbb= ',Vbb,' V\\n')\n",
-      "iD=iL;\n",
-      "Vgsn=math.sqrt(iD/K)+Vt;\n",
-      "print\"%s %.2f %s\"%('\\nVgsn= ',Vgsn,' V\\n')\n",
-      "Vsgp=Vbb-Vgsn;\n",
-      "print\"%s %.2f %s\"%('\\nVsgp= ',Vsgp,' V\\n')\n",
-      "vi=vo+Vgsn-Vbb/2.;\n",
-      "print\"%s %.2f %s\"%('\\ninput voltage= ',vi,' V\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "iL=  0.25  A\n",
-        "\n",
-        "\n",
-        "Vbb=  3.00  V\n",
-        "\n",
-        "\n",
-        "Vgsn=  2.12  V\n",
-        "\n",
-        "\n",
-        "Vsgp=  0.88  V\n",
-        "\n",
-        "\n",
-        "input voltage=  5.62  V\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex8-pg498"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      " \n",
-      "##Example 8.8\n",
-      "Vcc=24.;\n",
-      "Rl=8.;\n",
-      "P=5.;\n",
-      "Vbe=0.7;\n",
-      "b=100.;\n",
-      "Vp=math.sqrt(2.*Rl*P);\n",
-      "print\"%s %.2f %s\"%('\\npeak output voltage= ',Vp,' V\\n')\n",
-      "Ip=Vp/Rl;\n",
-      "print\"%s %.2f %s\"%('\\npeak output current = ',Ip,'A\\n')\n",
-      "a=0.9*Vcc/Vp;\n",
-      "print\"%s %.2f %s\"%('\\na= ',a,'\\n')\n",
-      "Icq=Ip/(0.9*a);\n",
-      "print\"%s %.2f %s\"%('\\nIcq= ',Icq,' A\\n')\n",
-      "Pq=Vcc*Icq;\n",
-      "print\"%s %.2f %s\"%('\\nmaximum power dissipated in the transistor= ',Pq,' W\\n')\n",
-      "Ibq=Icq/b;\n",
-      "Ibq=Ibq*1000.;##mA\n",
-      "print\"%s %.2f %s\"%('\\nbase current Ibq= ',Ibq,' mA\\n')\n",
-      "Rth=2.500;\n",
-      "##Vth=Vcc*Rth/R1 and Vth=Ibq*Rth+Vbe\n",
-      "R1=Vcc*Rth/(Ibq*Rth+Vbe);\n",
-      "print\"%s %.2f %s\"%('\\nR1= ',R1,' KOhm\\n')\n",
-      "R2=Rth*R1/(R1-Rth);\n",
-      "print\"%s %.2f %s\"%('\\nR2= ',R2,' KOhm\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "peak output voltage=  8.94  V\n",
-        "\n",
-        "\n",
-        "peak output current =  1.12 A\n",
-        "\n",
-        "\n",
-        "a=  2.41 \n",
-        "\n",
-        "\n",
-        "Icq=  0.51  A\n",
-        "\n",
-        "\n",
-        "maximum power dissipated in the transistor=  12.35  W\n",
-        "\n",
-        "\n",
-        "base current Ibq=  5.14  mA\n",
-        "\n",
-        "\n",
-        "R1=  4.42  KOhm\n",
-        "\n",
-        "\n",
-        "R2=  5.75  KOhm\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg500"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.9\n",
-      "Iso=3*10**-14;\n",
-      "Isq=10**-13;\n",
-      "b=75.;\n",
-      "Vt=0.026;\n",
-      "Rl=8.;\n",
-      "P=5.;\n",
-      "Vp=math.sqrt(2.*Rl*P);\n",
-      "print\"%s %.2f %s\"%('\\npeak voltage Vp= ',Vp,' V\\n')\n",
-      "Vcc=Vp/0.8;\n",
-      "print\"%s %.2f %s\"%('\\nsupply voltage= ',Vcc,' V\\n')\n",
-      "Ien=Vp/Rl;\n",
-      "print\"%s %.2f %s\"%('\\nemitter current= ',Ien,' A\\n')\n",
-      "Ibn=Ien/(1.+b);\n",
-      "Ibn=Ibn*1000.;##mA\n",
-      "print\"%s %.2f %s\"%('\\nbase current= ',Ibn,' mA\\n')\n",
-      "iD=0.020;\n",
-      "Vbb=2.*Vt*math.log(iD/Iso);\n",
-      "print\"%s %.2f %s\"%('\\nVbb= ',Vbb,' V\\n')\n",
-      "Icq=Isq*math.exp((Vbb/2.)/Vt);\n",
-      "Icq=Icq*1000.;##mA\n",
-      "print\"%s %.2f %s\"%('\\nquiescent collector current= ',Icq,' mA\\n')\n",
-      "Ibias=20.;##mA\n",
-      "iD=Ibias-Ibn;\n",
-      "print\"%s %.2f %s\"%('\\ndrain current= ',iD,' mA\\n')\n",
-      "iD=iD*0.001;##A\n",
-      "Vbb=2.*Vt*math.log(iD/Iso);\n",
-      "print\"%s %.2f %s\"%('\\nVbb= ',Vbb,' V\\n')\n",
-      "Icn=1.12;\n",
-      "Vben=Vt*math.log(Icn/Isq);\n",
-      "print\"%s %.2f %s\"%('\\nB-E voltage of Qn= ',Vben,' V\\n')\n",
-      "Vebp=Vbb-Vben;\n",
-      "print\"%s %.2f %s\"%('\\nemitter base voltage of Qp= ',Vebp,' V\\n')\n",
-      "Icp=Isq*math.exp(Vebp/Vt);\n",
-      "Icp=Icp*1000.;##mA\n",
-      "print\"%s %.2f %s\"%('\\nIcp ',Icp,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "peak voltage Vp=  8.94  V\n",
-        "\n",
-        "\n",
-        "supply voltage=  11.18  V\n",
-        "\n",
-        "\n",
-        "emitter current=  1.12  A\n",
-        "\n",
-        "\n",
-        "base current=  14.71  mA\n",
-        "\n",
-        "\n",
-        "Vbb=  1.42  V\n",
-        "\n",
-        "\n",
-        "quiescent collector current=  66.67  mA\n",
-        "\n",
-        "\n",
-        "drain current=  5.29  mA\n",
-        "\n",
-        "\n",
-        "Vbb=  1.35  V\n",
-        "\n",
-        "\n",
-        "B-E voltage of Qn=  0.78  V\n",
-        "\n",
-        "\n",
-        "emitter base voltage of Qp=  0.57  V\n",
-        "\n",
-        "\n",
-        "Icp  0.28  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex11-pg505"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 8.11\n",
-      "R1=2.;##KOhm\n",
-      "R2=R1;\n",
-      "Rl=.1;##KOhm\n",
-      "b=60.;\n",
-      "Vbe=0.6;\n",
-      "Veb=0.6;\n",
-      "V1=15.;\n",
-      "V2=V1;\n",
-      "iR1=(V1-Vbe)/R1;\n",
-      "##iR1=iR2=iE1=iE2\n",
-      "print\"%s %.2f %s\"%('\\niR1= ',iR1,' mA\\n')\n",
-      "vo=10.;\n",
-      "io=vo/Rl;\n",
-      "print\"%s %.2f %s\"%('\\noutput current= ',io,' mA\\n')\n",
-      "iB3=100./61.;\n",
-      "print\"%s %.2f %s\"%('\\niB3= ',iB3,'mA\\n')\n",
-      "iR1=(V1-(10.+Vbe))/R1;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent in R1= ',iR1,' mA\\n')\n",
-      "iE1=iR1-iB3;\n",
-      "print\"%s %.2f %s\"%('\\niE1= ',iE1,' mA\\n')\n",
-      "iB1=iE1/(1.+b);\n",
-      "iB1=iB1*1000.;##micro A\n",
-      "print\"%s %.2f %s\"%('\\niB1= ',iB1,' microA\\n')\n",
-      "iE2=(10-0.6+15.)/R1;\n",
-      "print\"%s %.2f %s\"%('\\niE2= ',iE2,' mA\\n')\n",
-      "iB2=iE2/(1.+b);\n",
-      "iB2=iB2*1000.;\n",
-      "print\"%s %.2f %s\"%('\\niB2= ',iB2,' microA\\n')\n",
-      "Ii=iB2-iB1;\n",
-      "print\"%s %.2f %s\"%('\\ninput current= ',Ii,' microA\\n')\n",
-      "Ii=Ii*0.001;##mA\n",
-      "Ai=io/Ii;\n",
-      "print\"%s %.2f %s\"%('\\ncurrent gain=\\n',Ai,'')\n",
-      "Ai=(1.+b)*R1/(2.*Rl);\n",
-      "print\"%s %.2f %s\"%('\\npredicted current gain=\\n',Ai,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "iR1=  7.20  mA\n",
-        "\n",
-        "\n",
-        "output current=  100.00  mA\n",
-        "\n",
-        "\n",
-        "iB3=  1.64 mA\n",
-        "\n",
-        "\n",
-        "current in R1=  2.20  mA\n",
-        "\n",
-        "\n",
-        "iE1=  0.56  mA\n",
-        "\n",
-        "\n",
-        "iB1=  9.19  microA\n",
-        "\n",
-        "\n",
-        "iE2=  12.20  mA\n",
-        "\n",
-        "\n",
-        "iB2=  200.00  microA\n",
-        "\n",
-        "\n",
-        "input current=  190.81  microA\n",
-        "\n",
-        "\n",
-        "current gain=\n",
-        " 524.08 \n",
-        "\n",
-        "predicted current gain=\n",
-        " 610.00 \n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter9.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter9.ipynb
deleted file mode 100755
index 9ad477cc..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter9.ipynb
+++ /dev/null
@@ -1,136 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:d282b66b032984b081a8c690d9d63b875908c2e44c5ac2a36021797d10bf6331"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter9-The Ideal Operational Amplifier"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg541"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 9.5\n",
-      "Zl=0.1;\n",
-      "R1=10.;\n",
-      "R2=1.;\n",
-      "R3=1.;\n",
-      "Rf=10.;\n",
-      "Vt=-5.;\n",
-      "iL=-Vt/R2;\n",
-      "print\"%s %.2f %s\"%('\\nload current= ',iL,' mA\\n')\n",
-      "vL=iL*Zl;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage across the load= ',vL,' V\\n')\n",
-      "i4=vL/R2;\n",
-      "print\"%s %.2f %s\"%('\\ni4= ',i4,' mA\\n')\n",
-      "i3=i4+iL;\n",
-      "print\"%s %.2f %s\"%('\\ni3= ',i3,' mA\\n')\n",
-      "Vo=i3*R3+vL;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',Vo,' V\\n')\n",
-      "i1=Vt/R1;\n",
-      "i2=i1;\n",
-      "print\"%s %.2f %s\"%('\\ni1= ',i1,' mA\\n')\n",
-      "print\"%s %.2f %s\"%('\\ni2= ',i2,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "load current=  5.00  mA\n",
-        "\n",
-        "\n",
-        "voltage across the load=  0.50  V\n",
-        "\n",
-        "\n",
-        "i4=  0.50  mA\n",
-        "\n",
-        "\n",
-        "i3=  5.50  mA\n",
-        "\n",
-        "\n",
-        "output voltage=  6.00  V\n",
-        "\n",
-        "\n",
-        "i1=  -0.50  mA\n",
-        "\n",
-        "\n",
-        "i2=  -0.50  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg552"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "import scipy\n",
-      "from scipy import integrate\n",
-      " \n",
-      "##Example 9.9\n",
-      "##Vo=(-1/R1*C2)*integrate((-1)dt) \n",
-      "def fun(x):\n",
-      "    y=-1\n",
-      "    return y\n",
-      "Vo=10.;\n",
-      "I=scipy.integrate.quad(fun, 0, 1);\n",
-      "I1=I[0]\n",
-      "##let y=R1*C2\n",
-      "y1=I1/Vo;\n",
-      "print\"%s %.2f %s\"%('\\nR1C2= ',y1,' ms\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "R1C2=  -0.10  ms\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter9_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter9_1.ipynb
deleted file mode 100755
index 9ad477cc..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter9_1.ipynb
+++ /dev/null
@@ -1,136 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:d282b66b032984b081a8c690d9d63b875908c2e44c5ac2a36021797d10bf6331"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter9-The Ideal Operational Amplifier"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg541"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 9.5\n",
-      "Zl=0.1;\n",
-      "R1=10.;\n",
-      "R2=1.;\n",
-      "R3=1.;\n",
-      "Rf=10.;\n",
-      "Vt=-5.;\n",
-      "iL=-Vt/R2;\n",
-      "print\"%s %.2f %s\"%('\\nload current= ',iL,' mA\\n')\n",
-      "vL=iL*Zl;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage across the load= ',vL,' V\\n')\n",
-      "i4=vL/R2;\n",
-      "print\"%s %.2f %s\"%('\\ni4= ',i4,' mA\\n')\n",
-      "i3=i4+iL;\n",
-      "print\"%s %.2f %s\"%('\\ni3= ',i3,' mA\\n')\n",
-      "Vo=i3*R3+vL;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',Vo,' V\\n')\n",
-      "i1=Vt/R1;\n",
-      "i2=i1;\n",
-      "print\"%s %.2f %s\"%('\\ni1= ',i1,' mA\\n')\n",
-      "print\"%s %.2f %s\"%('\\ni2= ',i2,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "load current=  5.00  mA\n",
-        "\n",
-        "\n",
-        "voltage across the load=  0.50  V\n",
-        "\n",
-        "\n",
-        "i4=  0.50  mA\n",
-        "\n",
-        "\n",
-        "i3=  5.50  mA\n",
-        "\n",
-        "\n",
-        "output voltage=  6.00  V\n",
-        "\n",
-        "\n",
-        "i1=  -0.50  mA\n",
-        "\n",
-        "\n",
-        "i2=  -0.50  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg552"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "import scipy\n",
-      "from scipy import integrate\n",
-      " \n",
-      "##Example 9.9\n",
-      "##Vo=(-1/R1*C2)*integrate((-1)dt) \n",
-      "def fun(x):\n",
-      "    y=-1\n",
-      "    return y\n",
-      "Vo=10.;\n",
-      "I=scipy.integrate.quad(fun, 0, 1);\n",
-      "I1=I[0]\n",
-      "##let y=R1*C2\n",
-      "y1=I1/Vo;\n",
-      "print\"%s %.2f %s\"%('\\nR1C2= ',y1,' ms\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "R1C2=  -0.10  ms\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter9_1_1.ipynb b/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter9_1_1.ipynb
deleted file mode 100755
index 01be9a77..00000000
--- a/Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen/Chapter9_1_1.ipynb
+++ /dev/null
@@ -1,136 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:32f4ddc547fad5eac3ccd22992e1c23752ad6ef6cf432bf032a216c1338d002f"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter9-The Ideal Operational Amplifier"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex5-pg541"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "\n",
-      "##Example 9.5\n",
-      "Zl=0.1;\n",
-      "R1=10.;\n",
-      "R2=1.;\n",
-      "R3=1.;\n",
-      "Rf=10.;\n",
-      "Vt=-5.;\n",
-      "iL=-Vt/R2;\n",
-      "print\"%s %.2f %s\"%('\\nload current= ',iL,' mA\\n')\n",
-      "vL=iL*Zl;\n",
-      "print\"%s %.2f %s\"%('\\nvoltage across the load= ',vL,' V\\n')\n",
-      "i4=vL/R2;\n",
-      "print\"%s %.2f %s\"%('\\ni4= ',i4,' mA\\n')\n",
-      "i3=i4+iL;\n",
-      "print\"%s %.2f %s\"%('\\ni3= ',i3,' mA\\n')\n",
-      "Vo=i3*R3+vL;\n",
-      "print\"%s %.2f %s\"%('\\noutput voltage= ',Vo,' V\\n')\n",
-      "i1=Vt/R1;\n",
-      "i2=i1;\n",
-      "print\"%s %.2f %s\"%('\\ni1= ',i1,' mA\\n')\n",
-      "print\"%s %.2f %s\"%('\\ni2= ',i2,' mA\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "load current=  5.00  mA\n",
-        "\n",
-        "\n",
-        "voltage across the load=  0.50  V\n",
-        "\n",
-        "\n",
-        "i4=  0.50  mA\n",
-        "\n",
-        "\n",
-        "i3=  5.50  mA\n",
-        "\n",
-        "\n",
-        "output voltage=  6.00  V\n",
-        "\n",
-        "\n",
-        "i1=  -0.50  mA\n",
-        "\n",
-        "\n",
-        "i2=  -0.50  mA\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex9-pg552"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "import scipy\n",
-      "from scipy import integrate\n",
-      " \n",
-      "##Example 9.9\n",
-      "##Vo=(-1/R1*C2)*integrate((-1)dt) \n",
-      "def fun(x):\n",
-      "    y=-1\n",
-      "    return y\n",
-      "Vo=10.;\n",
-      "I=scipy.integrate.quad(fun, 0, 1);\n",
-      "I1=I[0]\n",
-      "##let y=R1*C2\n",
-      "y1=I1/Vo;\n",
-      "print\"%s %.2f %s\"%('\\nR1C2= ',y1,' ms\\n')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "\n",
-        "R1C2=  -0.10  ms\n",
-        "\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
author	kinitrupti	2017-05-12 18:40:35 +0530
committer	kinitrupti	2017-05-12 18:40:35 +0530
commit	64d949698432e05f2a372d9edc859c5b9df1f438 (patch)
tree	012fd5b4ac9102cdcf5bc56305e49d6714fa5951 /Electronic_Circuit_Analysis_And_Design_by_D._A._Neamen
parent	9c6ab8cbf3e1a84c780386abf4852d84cdd32d56 (diff)
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