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| author | hardythe1 | 2014-07-25 13:33:31 +0530 |
|---|---|---|
| committer | hardythe1 | 2014-07-25 13:33:31 +0530 |
| commit | 5571c8f5bda1334edf8ef9d8c69928d46cc9f163 (patch) | |
| tree | bceb7fb14d7903bfb160b856cad72ce1db35b5a9 /Electrical_Circuit_Theory_And_Technology/chapter_39.ipynb | |
| parent | 0d4b70aada9bbc982f00c27afb1337e2b314eb43 (diff) | |
| download | Python-Textbook-Companions-5571c8f5bda1334edf8ef9d8c69928d46cc9f163.tar.gz Python-Textbook-Companions-5571c8f5bda1334edf8ef9d8c69928d46cc9f163.tar.bz2 Python-Textbook-Companions-5571c8f5bda1334edf8ef9d8c69928d46cc9f163.zip | |
removing unwanted and adding book
Diffstat (limited to 'Electrical_Circuit_Theory_And_Technology/chapter_39.ipynb')
| -rw-r--r-- | Electrical_Circuit_Theory_And_Technology/chapter_39.ipynb | 200 |
1 files changed, 200 insertions, 0 deletions
diff --git a/Electrical_Circuit_Theory_And_Technology/chapter_39.ipynb b/Electrical_Circuit_Theory_And_Technology/chapter_39.ipynb new file mode 100644 index 00000000..6edb5773 --- /dev/null +++ b/Electrical_Circuit_Theory_And_Technology/chapter_39.ipynb @@ -0,0 +1,200 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:1ec371cb843067028dd1e055f435f5ad6cdc4ce9c5ed963c08c525b60770abca"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h1>Chapter 39: Dielectrics and dielectric loss</h1>"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 1, page no. 717</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "from __future__ import division\n",
+ "import math\n",
+ "#initializing the variables:\n",
+ "Rs = 1.5;# in ohms\n",
+ "Cs = 400E-12;# in Farads\n",
+ "f = 8E6;# in Hz\n",
+ "\n",
+ "#calculation: \n",
+ " #for a series equivalent circuit,\n",
+ " #tan(del) = Rs*w*Cs\n",
+ " #loss angle,\n",
+ "de = math.atan(Rs*Cs*(2*math.pi*f))\n",
+ " #power factor\n",
+ "pf = math.cos(de)\n",
+ " #the Q-factor\n",
+ "Q = 1/math.tan(de)\n",
+ " #dissipation factor,\n",
+ "D = 1/Q\n",
+ "\n",
+ "\n",
+ "#Results\n",
+ "print \"\\n\\n Result \\n\\n\"\n",
+ "print \"\\n (a)loss angle \",round(de,2),\" rad.\"\n",
+ "print \"\\n (b)power factor \",round(de,2),\" rad.\"\n",
+ "print \"\\n (c)Q-factor is \",round(Q,2)\n",
+ "print \"\\n (d)dissipation factor \",round(D,2),\" rad.\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "\n",
+ "\n",
+ " Result \n",
+ "\n",
+ "\n",
+ "\n",
+ " (a)loss angle 0.03 rad.\n",
+ "\n",
+ " (b)power factor 0.03 rad.\n",
+ "\n",
+ " (c)Q-factor is 33.16\n",
+ "\n",
+ " (d)dissipation factor 0.03 rad."
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 2, page no. 718</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "from __future__ import division\n",
+ "import math\n",
+ "#initializing the variables:\n",
+ "de = 0.025;# in rad.\n",
+ "V = 5000;# in Volts\n",
+ "PL = 20;# power loss\n",
+ "f = 50;# in Hz\n",
+ "\n",
+ "#calculation: \n",
+ " #power loss = w*C*V**2*tan(del)\n",
+ "Cp = PL/(2*math.pi*f*V*V*math.tan(de))\n",
+ " #for a parallel equivalent circuit,\n",
+ " #tan(del) = 1/(Rp*w*Cp)\n",
+ "Rp = 1/(2*math.pi*f*Cp*math.tan(de))\n",
+ "\n",
+ "\n",
+ "#Results\n",
+ "print \"\\n\\n Result \\n\\n\"\n",
+ "print \"\\n capacitance C \",round(Cp*1E6,2),\"uF and parallel resistance \",round(Rp,2),\"ohm.\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "\n",
+ "\n",
+ " Result \n",
+ "\n",
+ "\n",
+ "\n",
+ " capacitance C 0.1 uF and parallel resistance 1250000.0 ohm."
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 3, page no. 718</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "from __future__ import division\n",
+ "import math\n",
+ "#initializing the variables:\n",
+ "P = 500E-6;# in Watt\n",
+ "C = 2000E-12;# in Farads\n",
+ "V = 20;# in Volts\n",
+ "f = 10000;# in Hz\n",
+ "\n",
+ " #calculation: \n",
+ " #power loss = w*C*V**2*tan(del)\n",
+ " #loss angle\n",
+ "de = math.atan(P/(2*math.pi*f*V*V*C))\n",
+ " #for an equivalent series circuit,\n",
+ " #tan(del) = (Rs*w*Cs)\n",
+ "Cs = C\n",
+ "Rs = (math.tan(de))/(2*math.pi*f*Cs)\n",
+ " #for an equivalent parallel circuit\n",
+ " #tan(del) = 1/(Rp*w*Cp)\n",
+ "Cp = C\n",
+ "Rp = 1/(2*math.pi*f*Cp*math.tan(de))\n",
+ "\n",
+ "\n",
+ "#Results\n",
+ "print \"\\n\\n Result \\n\\n\"\n",
+ "print \"\\n (a)loss angle \",round(de*180/math.pi,2),\"deg\"\n",
+ "print \"\\n (b)series resistance \",round(Rs,2),\" ohm.\"\n",
+ "print \"\\n (c)parallel resistance \",round(Rp/1000,2),\"Kohm.\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "\n",
+ "\n",
+ " Result \n",
+ "\n",
+ "\n",
+ "\n",
+ " (a)loss angle 0.57 deg\n",
+ "\n",
+ " (b)series resistance 79.16 ohm.\n",
+ "\n",
+ " (c)parallel resistance 800.0 Kohm."
+ ]
+ }
+ ],
+ "prompt_number": 1
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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