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| author | Jovina Dsouza | 2014-07-22 00:00:04 +0530 |
|---|---|---|
| committer | Jovina Dsouza | 2014-07-22 00:00:04 +0530 |
| commit | c8733e4b6b4bffcddf7eb45ff1c72ccc837aa3af (patch) | |
| tree | 0f7627eb79ddb66b8fa81efd380036bc75586ba8 /Electrical_Circuit_Theory_And_Technology/chapter_27-checkpoint_2.ipynb | |
| parent | e7deb0183418e63da824955296b8bb3598ba359d (diff) | |
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adding book
Diffstat (limited to 'Electrical_Circuit_Theory_And_Technology/chapter_27-checkpoint_2.ipynb')
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1 files changed, 205 insertions, 0 deletions
diff --git a/Electrical_Circuit_Theory_And_Technology/chapter_27-checkpoint_2.ipynb b/Electrical_Circuit_Theory_And_Technology/chapter_27-checkpoint_2.ipynb new file mode 100755 index 00000000..4d37718b --- /dev/null +++ b/Electrical_Circuit_Theory_And_Technology/chapter_27-checkpoint_2.ipynb @@ -0,0 +1,205 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h1>Chapter 27: A.c. bridges</h1>"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 1, page no. 485</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#determine the values of Rx and Cx at balance.\n",
+ "from __future__ import division\n",
+ "import math\n",
+ "import cmath\n",
+ "#initializing the variables:\n",
+ "R2 = 2500;# in ohms\n",
+ "C2 = 0.2E-6;# IN fARADS\n",
+ "R3 = 1;\n",
+ "R4 = 1;\n",
+ "w = 2000*math.pi;\n",
+ "#calculation:\n",
+ "Rx = R4*(1 + w*w*C2*C2*R2*R2)/(R2*R3*w*w*C2*C2)\n",
+ "Cx = R3*C2/(R4*(1 + w*w*C2*C2*R2*R2))\n",
+ "\n",
+ "#Results\n",
+ "print \"\\n\\n Result \\n\\n\"\n",
+ "print \"\\n (a)Resistance Rx = R4(1 + w*w*C2*C2*R2*R2)/(R2*R3*w*w*C2*C2) and Capacitance Cx = R3*C2/(R4*(1 + w*w*C2*C2*R2*R2))\"\n",
+ "print \"\\n (b)at balance Rx = \",round(Rx/1000,2),\"KOhm and Cx = \", round(Cx*1E9,2),\"nF\\n\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "\n",
+ "\n",
+ " Result \n",
+ "\n",
+ "\n",
+ "\n",
+ " (a)Resistance Rx = R4(1 + w*w*C2*C2*R2*R2)/(R2*R3*w*w*C2*C2) and Capacitance Cx = R3*C2/(R4*(1 + w*w*C2*C2*R2*R2))\n",
+ "\n",
+ " (b)at balance Rx = 2.75 KOhm and Cx = 18.4 nF"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 2, page no. 487</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Determine, when the bridge is balanced, (a) the value of resistance R1, and (b) the frequency of the bridge.\n",
+ "from __future__ import division\n",
+ "import math\n",
+ "import cmath\n",
+ "#initializing the variables:\n",
+ "R2 = 30000;# in ohms\n",
+ "R3 = 30000;# in ohms\n",
+ "R4 = 1000;# in ohms\n",
+ "C2 = 1e-9;# IN fARADS\n",
+ "C3 = 1e-9;# IN fARADS\n",
+ "\n",
+ "#calculation:\n",
+ " #the bridge is balanced\n",
+ "R1 = R4/((R3/R2) + (C2/C3))\n",
+ " #frequency, f\n",
+ "f = 1/(2*math.pi*((C2*C3*R2*R3)**0.5))\n",
+ "\n",
+ "\n",
+ "#Results\n",
+ "print \"\\n\\n Result \\n\\n\"\n",
+ "print \"\\n (a)Resistance R1 = \",R1,\" ohm\\n\"\n",
+ "print \"\\n (b)frequency, f is \",round(f,2),\"Hz\\n\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "\n",
+ "\n",
+ " Result \n",
+ "\n",
+ "\n",
+ "\n",
+ " (a)Resistance R1 = 500.0 ohm\n",
+ "\n",
+ "\n",
+ " (b)frequency, f is 5305.16 Hz"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 3, page no. 487</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#determine, when the bridge is balanced, \n",
+ "#(a) the value of resistance Rx, (b) the value of capacitance Cx,\n",
+ "#(c) the phase angle of the unknown arm, (d) the power factor of the unknown arm and (e) its loss angle.\n",
+ "from __future__ import division\n",
+ "import math\n",
+ "import cmath\n",
+ "#initializing the variables:\n",
+ "R3 = 600;# in ohms\n",
+ "R4 = 200;# in ohms\n",
+ "C2 = 0.2e-6;# IN fARADS\n",
+ "C3 = 4000e-12;# IN fARADS\n",
+ "f = 1500;#in Hz\n",
+ "\n",
+ "#calculation:\n",
+ " #the bridge is balanced\n",
+ " #Resistance, Rx\n",
+ "Rx = R4*C3/C2\n",
+ " #Capacitance, Cx\n",
+ "Cx = C2*R3/R4\n",
+ " #Phase angle\n",
+ "phi = math.atan(1/(2*math.pi*f*Cx*Rx))\n",
+ "phid = phi*180/math.pi# in degrees\n",
+ " #Power factor of capacitor\n",
+ "Pc = math.cos(phi)\n",
+ " #Loss angle,\n",
+ "de = 90 - phid\n",
+ "\n",
+ "\n",
+ "#Results\n",
+ "print \"\\n\\n Result \\n\\n\"\n",
+ "print \"\\n (a)Resistance Rx = \",round(Rx,2),\" ohm\\n\"\n",
+ "print \"\\n (b)capacitance, Cx is \",round(Cx*1E9,2),\"pFarad\\n\"\n",
+ "print \"\\n (c)phasor diagram = \",round(phid,2),\"deg lead \"\n",
+ "print \"\\n (d)power factor is \",round(Pc,2),\" \\n\"\n",
+ "print \"\\n (e)Loss angle = \",round(de,2),\"deg\\n\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "\n",
+ "\n",
+ " Result \n",
+ "\n",
+ "\n",
+ "\n",
+ " (a)Resistance Rx = 4.0 ohm\n",
+ "\n",
+ "\n",
+ " (b)capacitance, Cx is 600.0 pFarad\n",
+ "\n",
+ "\n",
+ " (c)phasor diagram = 88.7 deg lead \n",
+ "\n",
+ " (d)power factor is 0.02 \n",
+ "\n",
+ "\n",
+ " (e)Loss angle = 1.3 deg\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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