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| author | Jovina Dsouza | 2014-07-22 00:00:04 +0530 |
|---|---|---|
| committer | Jovina Dsouza | 2014-07-22 00:00:04 +0530 |
| commit | c8733e4b6b4bffcddf7eb45ff1c72ccc837aa3af (patch) | |
| tree | 0f7627eb79ddb66b8fa81efd380036bc75586ba8 /Electrical_Circuit_Theory_And_Technology/chapter_03-checkpoint.ipynb | |
| parent | e7deb0183418e63da824955296b8bb3598ba359d (diff) | |
| download | Python-Textbook-Companions-c8733e4b6b4bffcddf7eb45ff1c72ccc837aa3af.tar.gz Python-Textbook-Companions-c8733e4b6b4bffcddf7eb45ff1c72ccc837aa3af.tar.bz2 Python-Textbook-Companions-c8733e4b6b4bffcddf7eb45ff1c72ccc837aa3af.zip | |
adding book
Diffstat (limited to 'Electrical_Circuit_Theory_And_Technology/chapter_03-checkpoint.ipynb')
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diff --git a/Electrical_Circuit_Theory_And_Technology/chapter_03-checkpoint.ipynb b/Electrical_Circuit_Theory_And_Technology/chapter_03-checkpoint.ipynb new file mode 100755 index 00000000..f79d1396 --- /dev/null +++ b/Electrical_Circuit_Theory_And_Technology/chapter_03-checkpoint.ipynb @@ -0,0 +1,525 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h1>Chapter 3: Resistance variation</h1>"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 1, page no. 24</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Determine (a) the resistance of an 8 m length of the same wire,\n",
+ "#and (b) the length of the same wire when the resistance is 420\n",
+ "from __future__ import division\n",
+ "#initializing the variables:\n",
+ "R = 600; # in ohms\n",
+ "L = 5; # in meter\n",
+ "L1 = 8; # in meter\n",
+ "R2 = 420; # in ohms\n",
+ "\n",
+ "#calculation:\n",
+ "R1 = R*L1/L\n",
+ "L2 = R2*L/R\n",
+ "\n",
+ "#results\n",
+ "print \"a)Resistance\", R1,\"Ohms\"\n",
+ "print \"b)Length:\", L2,\"meters(m)\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "a)Resistance 960.0 Ohms\n",
+ "b)Length: 3.5 meters(m)"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 2, page no. 24</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Find (a) the resistance of a wire of the same length and material if the cross-sectional area is 5 mm2,\n",
+ "#(b) the cross-sectional area of a wire of the same length and material of resistance 750 \n",
+ "from __future__ import division\n",
+ "#initializing the variables:\n",
+ "R = 300; # in ohms\n",
+ "A = 2; # in mm2\n",
+ "A1 = 5; # in mm2\n",
+ "R2 = 750; # in ohms\n",
+ "\n",
+ "#calculation:\n",
+ "R1 = R*A/A1\n",
+ "A2 = R*A/R2\n",
+ "\n",
+ "#results\n",
+ "print \"(a)Resistance\", R1,\"Ohms\"\n",
+ "print \"(b)C.S.A:\", A2,\"mm^2\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a)Resistance 120.0 Ohms\n",
+ "(b)C.S.A: 0.8 mm^2"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 3, page no. 25</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#determine the resistance of the wire.\n",
+ "from __future__ import division\n",
+ "#initializing the variables:\n",
+ "R = 0.16; # in ohms\n",
+ "A = 3; # in mm2\n",
+ "L = 8; # in m\n",
+ "A1 = 1; # in mm2\n",
+ "\n",
+ "#calculation:\n",
+ "L1 = L*3\n",
+ "R1 = R*A*L1/(A1*L)\n",
+ "\n",
+ "#results\n",
+ "print \"Resistance\", R1,\"Ohms\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Resistance 1.44 Ohms"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 4, page no. 25</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate the resistance.\n",
+ "from __future__ import division\n",
+ "#initializing the variables:\n",
+ "A = 100E-6; # in m2\n",
+ "L = 2000; # in m\n",
+ "p = 0.03E-6; # in ohm m\n",
+ "\n",
+ "#calculation:\n",
+ "R = p*L/A\n",
+ "\n",
+ "#results\n",
+ "print \"Resistance\", R,\"Ohms\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Resistance 0.6 Ohms"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 5, page no. 25</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Calculate the cross-sectional area\n",
+ "from __future__ import division\n",
+ "#initializing the variables:\n",
+ "R = 0.25; # in ohms\n",
+ "L = 40; # in m\n",
+ "p = 0.02E-6; # in ohm m\n",
+ "\n",
+ "#calculation:\n",
+ "A = p*L*1E6/R\n",
+ "\n",
+ "#results\n",
+ "print \"C.S.A \", A,\"mm^2\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "C.S.A 3.2 mm^2"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 6, page no. 25</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Determine the resistivity of the wire.\n",
+ "from __future__ import division\n",
+ "#initializing the variables:\n",
+ "R = 150; # in ohms\n",
+ "L = 1500; # in m\n",
+ "A = 0.17E-6; # in m2\n",
+ "\n",
+ "#calculation:\n",
+ "p = R*A*1E6/L\n",
+ "\n",
+ "#results\n",
+ "print \"resistivity\", p,\"uOhm.m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "resistivity 0.017 uOhm.m"
+ ]
+ }
+ ],
+ "prompt_number": 18
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 7, page no. 26</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Determine the resistance\n",
+ "from __future__ import division\n",
+ "import math\n",
+ "#initializing the variables:\n",
+ "d = 0.012; # in m\n",
+ "L = 1200; # in m\n",
+ "p = 1.7E-8; # in ohm m\n",
+ "\n",
+ "#calculation:\n",
+ "A = math.pi*d*d/4\n",
+ "R = p*L/A\n",
+ "\n",
+ "#results\n",
+ "print \"resistance\", round(R,3),\"Ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "resistance 0.18 Ohm"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 8, page no. 27</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Determine its resistance\n",
+ "from __future__ import division\n",
+ "#initializing the variables:\n",
+ "R0 = 100; # in ohms\n",
+ "T0 = 0; # in \u00b0C\n",
+ "T1 = 70; # in \u00b0C\n",
+ "a0 = 0.0043; # in per\u00b0C\n",
+ "\n",
+ "#calculation:\n",
+ "R70 = R0*(1 + (a0*T1))\n",
+ "\n",
+ "#results\n",
+ "print \"Resistance\", R70,\"Ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Resistance 130.1 Ohm"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 9, page no. 27</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Determine its resistance\n",
+ "from __future__ import division\n",
+ "#initializing the variables:\n",
+ "R1 = 27; # in ohms\n",
+ "T0 = 0; # in \u00b0C\n",
+ "T1 = 35; # in \u00b0C\n",
+ "a0 = 0.0038; # in per\u00b0C\n",
+ "\n",
+ "#calculation:\n",
+ "R0 = R1/(1 + (a0*T1))\n",
+ "\n",
+ "#results\n",
+ "print \"resistance\", round(R0,2),\"Ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "resistance 23.83 Ohm"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 10, page no. 27</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Determine its resistance\n",
+ "from __future__ import division\n",
+ "#initializing the variables:\n",
+ "R0 = 1000; # in ohms\n",
+ "T0 = 0; # in \u00b0C\n",
+ "T1 = 80; # in \u00b0C\n",
+ "a0 = -0.0005; # in per\u00b0C\n",
+ "\n",
+ "#calculation:\n",
+ "R80 = R0*(1 + (a0*T1))\n",
+ "\n",
+ "#results\n",
+ "print \"resistance\", R80,\"Ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "resistance 960.0 Ohm"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 11, page no. 28</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#determine the resistance of the coil\n",
+ "from __future__ import division\n",
+ "#initializing the variables:\n",
+ "R20 = 10; # in ohms\n",
+ "T0 = 20; # in \u00b0C\n",
+ "T1 = 100; # in \u00b0C\n",
+ "a20 = 0.004; # in per\u00b0C\n",
+ "\n",
+ "\n",
+ "#calculation:\n",
+ "R100 = R20*(1 + (a20)*(T1 - T0))\n",
+ "\n",
+ "#results\n",
+ "print \"resistance\", R100,\"Ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "resistance 13.2 Ohm"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 12, page no. 28</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#determine the temperature to which the coil has risen\n",
+ "from __future__ import division\n",
+ "#initializing the variables:\n",
+ "R18 = 200; # in ohms\n",
+ "R1 = 240; # in ohms\n",
+ "T0 = 18; # in \u00b0C\n",
+ "a18 = 0.0039; # in per\u00b0C\n",
+ "\n",
+ "\n",
+ "#calculation:\n",
+ "T1 = (((R1/R18)-1)/a18) + T0\n",
+ "\n",
+ "#results\n",
+ "print \"Temperature\", round(T1,2),\"degC\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Temperature 69.28 degC"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "<h3>Example 13, page no. 29</h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Determine the resistance of the wire\n",
+ "from __future__ import division\n",
+ "#initializing the variables:\n",
+ "R20 = 200; # in ohms\n",
+ "T0 = 20; # in \u00b0C\n",
+ "T1 = 90; # in \u00b0C\n",
+ "a0 = 0.004; # in per\u00b0C\n",
+ "\n",
+ "\n",
+ "#calculation:\n",
+ "R90 = R20*(1 + (a0*T1))/(1 + (a0*T0))\n",
+ "\n",
+ "#results\n",
+ "print \"Resistance\", round(R90,0),\"ohms\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Resistance 252.0 ohms"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |