removing unwanted and adding book

1 files changed, 0 insertions, 329 deletions

diff --git a/Electrical_Circuit_Theory_And_Technology/Chapter_01-checkpoint_2.ipynb b/Electrical_Circuit_Theory_And_Technology/Chapter_01-checkpoint_2.ipynb
deleted file mode 100755
index b33db331..00000000
--- a/Electrical_Circuit_Theory_And_Technology/Chapter_01-checkpoint_2.ipynb
+++ /dev/null
@@ -1,329 +0,0 @@
-{

- "metadata": {

-  "name": ""

- },

- "nbformat": 3,

- "nbformat_minor": 0,

- "worksheets": [

-  {

-   "cells": [

-    {

-     "cell_type": "markdown",

-     "metadata": {},

-     "source": [

-      "<h1>Chapter 1: Units Associated with Basic Electrical Quantities</h1>"

-     ]

-    },

-    {

-     "cell_type": "markdown",

-     "metadata": {},

-     "source": [

-      "<h3>Example 1, page no. 4</h3>"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "#find the quantity of electricity transferred.\n",

-      "from __future__ import division\n",

-      "#initializing the variables:\n",

-      "I = 5;   # in Ampere\n",

-      "t = 120; # in sec\n",

-      "\n",

-      "#calculation:\n",

-      "Q = I*t\n",

-      "\n",

-      "#results\n",

-      "print \"Charge, Q = \", Q,\"coulomb(C)\""

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "Charge, Q =  600 coulomb(C)"

-       ]

-      }

-     ],

-     "prompt_number": 1

-    },

-    {

-     "cell_type": "markdown",

-     "metadata": {},

-     "source": [

-      "<h3>Example 2, page no. 5</h3>"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "#Determine the force needed.\n",

-      "from __future__ import division\n",

-      "#initializing the variables:\n",

-      "M = 5; # in Kg\n",

-      "a = 2; # in m/s2\n",

-      "\n",

-      "#calculation:\n",

-      "F = M*a\n",

-      "\n",

-      "#results\n",

-      "print \"Force:\", F,\"Newton(N)\""

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "Force: 10 Newton(N)"

-       ]

-      }

-     ],

-     "prompt_number": 2

-    },

-    {

-     "cell_type": "markdown",

-     "metadata": {},

-     "source": [

-      "<h3>Example 3, page no. 5</h3>"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "#Find the force acting vertically downwards\n",

-      "from __future__ import division\n",

-      "#initializing the variables:\n",

-      "M = 0.2; # in Kg\n",

-      "g = 9.81; # in m/s2\n",

-      "\n",

-      "#calculation:\n",

-      "F = M*g\n",

-      "\n",

-      "#results\n",

-      "print \"Force:\", F,\"Newton(N)\""

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "Force: 1.962 Newton(N)"

-       ]

-      }

-     ],

-     "prompt_number": 3

-    },

-    {

-     "cell_type": "markdown",

-     "metadata": {},

-     "source": [

-      "<h3>Example 4, page no. 6</h3>"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "#Calculate Work Done and Average Power?\n",

-      "from __future__ import division\n",

-      "#initializing the variables:\n",

-      "F = 200; # in Newton\n",

-      "d = 20; # in m\n",

-      "t = 25; # in sec\n",

-      "\n",

-      "#calculation:\n",

-      "W = F*d\n",

-      "P = W/t\n",

-      "\n",

-      "#results\n",

-      "print \"Power:\", P,\"watt(W)\"\n",

-      "print \"Work Done:\", W,\"Nm\""

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "Power: 160.0 watt(W)\n",

-        "Work Done: 4000 Nm"

-       ]

-      }

-     ],

-     "prompt_number": 1

-    },

-    {

-     "cell_type": "markdown",

-     "metadata": {},

-     "source": [

-      "<h3>Example 5, page no. 6</h3>"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "#What is (a) the work done and (b) the power developed?\n",

-      "from __future__ import division\n",

-      "#initializing the variables:\n",

-      "M = 1000; # in Kg\n",

-      "h = 10; # in m\n",

-      "t = 20; # in sec\n",

-      "g = 9.81 # in m/s2\n",

-      "\n",

-      "#calculation:\n",

-      "W = M*g*h\n",

-      "P = W/t\n",

-      "\n",

-      "#results\n",

-      "print \"Work Done:\", W,\"Joule(J)\"\n",

-      "print \"Power:\", P,\"watt(W)\""

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "Work Done: 98100.0 Joule(J)\n",

-        "Power: 4905.0 watt(W)"

-       ]

-      }

-     ],

-     "prompt_number": 5

-    },

-    {

-     "cell_type": "markdown",

-     "metadata": {},

-     "source": [

-      "<h3>Example 6, page no. 7</h3>"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "#Find the conductance of a conductor of resistances\n",

-      "from __future__ import division\n",

-      "#initializing the variables:\n",

-      "R1 = 10; # in ohm\n",

-      "R2 = 5000; # in ohm\n",

-      "R3 = 0.1; # in ohm\n",

-      "#calculation:\n",

-      "G1 = 1/R1\n",

-      "G2 = 1/R2\n",

-      "G3 = 1/R3\n",

-      "\n",

-      "#results\n",

-      "print \"conductance(G1):\", G1,\"seimen(S)\"\n",

-      "print \"conductance(G2):\", G2,\"seimen(S)\"\n",

-      "print \"conductance(G3):\", G3,\"seimen(S)\""

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "conductance(G1): 0.1 seimen(S)\n",

-        "conductance(G2): 0.0002 seimen(S)\n",

-        "conductance(G3): 10.0 seimen(S)"

-       ]

-      }

-     ],

-     "prompt_number": 6

-    },

-    {

-     "cell_type": "markdown",

-     "metadata": {},

-     "source": [

-      "<h3>Example 7, page no. 7</h3>"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "#How much energy is provided in this time?\n",

-      "from __future__ import division\n",

-      "#initializing the variables:\n",

-      "V = 5; # in Volts\n",

-      "I = 3; # in Ampere\n",

-      "t = 600; # in sec\n",

-      "#calculation:\n",

-      "P = V*I\n",

-      "E = P*t\n",

-      "\n",

-      "#results\n",

-      "print \"Energy(E):\", E,\"Joule(J)\""

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "Energy(E): 9000 Joule(J)"

-       ]

-      }

-     ],

-     "prompt_number": 7

-    },

-    {

-     "cell_type": "markdown",

-     "metadata": {},

-     "source": [

-      "<h3>Example 8, page no. 8</h3>"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "#Find the power rating of the heater and the current taken from the supply.\n",

-      "from __future__ import division\n",

-      "#initializing the variables:\n",

-      "E = 18E5; # in Joule\n",

-      "V = 250; # in Volts\n",

-      "t = 1800; # in sec\n",

-      "\n",

-      "#calculation:\n",

-      "P = E/t\n",

-      "I = P/V\n",

-      "\n",

-      "#results\n",

-      "print \"Power(P):\", P,\"Watt(W)\"\n",

-      "print \"Current(I):\", I,\"Ampere(A)\""

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "Power(P): 1000.0 Watt(W)\n",

-        "Current(I): 4.0 Ampere(A)"

-       ]

-      }

-     ],

-     "prompt_number": 9

-    }

-   ],

-   "metadata": {}

-  }

- ]

-}
\ No newline at end of file