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| author | hardythe1 | 2015-06-03 15:27:17 +0530 |
|---|---|---|
| committer | hardythe1 | 2015-06-03 15:27:17 +0530 |
| commit | 47d7279a724246ef7aa0f5359cf417992ed04449 (patch) | |
| tree | c613e5e4813d846d24d67f46507a6a69d1a42d87 /Digital_Fundamentals/chapterno1.ipynb | |
| parent | 435840cef00c596d9e608f9eb2d96f522ea8505a (diff) | |
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| -rwxr-xr-x | Digital_Fundamentals/chapterno1.ipynb | 126 |
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diff --git a/Digital_Fundamentals/chapterno1.ipynb b/Digital_Fundamentals/chapterno1.ipynb new file mode 100755 index 00000000..5ff2285e --- /dev/null +++ b/Digital_Fundamentals/chapterno1.ipynb @@ -0,0 +1,126 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:a1ed470be69235951f179c73fc3f7daca02bf5e071f528ddce3fb4f1444cb8ef"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 1: INTRODUCTORY DIGITAL CONCEPTS"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 1-1,Page No-6"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Variable Declaration\n",
+ "T=10*10**-3\n",
+ "tw=1*10**-3\n",
+ "\n",
+ "#Calculations\n",
+ "#Part A\n",
+ "f=1/T\n",
+ "\n",
+ "#Part C\n",
+ "Duty_Cycle=(tw/T)*100\n",
+ "\n",
+ "\n",
+ "#Results\n",
+ "print\"The Period is measured from the edge of the next pulse. In this case T is measured from leading edge to leading edge,as indicated.T equals 10*10^-3\"\n",
+ "print\"f=\",f,\"Hz\"\n",
+ "print\"Duty Cycle=\",Duty_Cycle,\"%\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The Period is measured from the edge of the next pulse. In this case T is measured from leading edge to leading edge,as indicated.T equals 10*10^-3\n",
+ "f= 100.0 Hz\n",
+ "Duty Cycle= 10.0 %\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 1-2, Page No-8"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Variable Declaration\n",
+ "f=100*10**-3\n",
+ "time=8\n",
+ "T=1/f\n",
+ "print\"Since the frequency of the clock is 100kHz,the period is\",T,\"usec\"\n",
+ "print\"It takes 10*10**-6to transfer each bit in the waveform.The total transfer time for 8 bits is time\"\n",
+ "print\"Time is\",time,\"usec\"\n",
+ "\n",
+ "print\"To detrmine the sequence of bits,examine the waveform during each bit time.If waveform A is HIGH during the bit time, a 1 is transferred. If waveform A is LOW during the bit time,a0 is transferred. The bit sequence is illustrated .The left mosst bit is the first to be transferred.\"\n",
+ "\n",
+ "print\"A parallel transfer would take 10*10**-6 for all eight bits.\"\n",
+ " \n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Since the frequency of the clock is 100kHz,the period is 10.0 usec\n",
+ "It takes 10*10**-6to transfer each bit in the waveform.The total transfer time for 8 bits is time\n",
+ "Time is 8 usec\n",
+ "To detrmine the sequence of bits,examine the waveform during each bit time.If waveform A is HIGH during the bit time, a 1 is transferred. If waveform A is LOW during the bit time,a0 is transferred. The bit sequence is illustrated .The left mosst bit is the first to be transferred.\n",
+ "A parallel transfer would take 10*10**-6 for all eight bits.\n"
+ ]
+ }
+ ],
+ "prompt_number": 14
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [],
+ "language": "python",
+ "metadata": {},
+ "outputs": [],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [],
+ "language": "python",
+ "metadata": {},
+ "outputs": []
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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