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+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:13cb37b7bedc939f2932970f808cc63def43a3ee0a76b1e4d1958377aebef52c"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 1 : Introduction"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.1  Page No : 8"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\n",
+      "#Given \n",
+      "m = 100 #m is the mass of the object in kg\n",
+      "a = 10 #a is the acceeleration due to gravity in m/s**2\n",
+      "\n",
+      "#To determine the force exerted\n",
+      "F = m*a #F is the force exerted by the object in kg\n",
+      "print \"Force exerted by the object= \",\n",
+      "print \"%.6f\" %F,\n",
+      "print \"N\"\n",
+      "F = (1/9.8065)*m*a;#F is the force exerted by the object in kgf\n",
+      "print \"Force exerted by the object= \",\n",
+      "print \"%.6f\" %F,\n",
+      "print \"N\"\n",
+      "#end\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Force exerted by the object=  1000.000000 N\n",
+        "Force exerted by the object=  101.973181 N\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.4  Page No : 13"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\n",
+      "#Given\n",
+      "h = 100 #h is the height of the water fall in m\n",
+      "n = .855 #n is the efficiency of the turbine\n",
+      "g = 9.8 #g is the acceleration due to gravity in m/(s**2)\n",
+      "E = 100*10*3600;#E is the potential enery of water available to the bulb for 10 hours in watt or J/s\n",
+      "\n",
+      "#To determine the mass of water required\n",
+      "m = (E/(g*h*n)) #m is the mass of water required for lighting the bulb for 10 hours in Kg\n",
+      "print \"Mass of water required for lighting the bulb for 10 hours in Kg= \",\n",
+      "print \"%.6f\"%m,\n",
+      "print \"Kg\"\n",
+      "print \"Mass of water required for lighting the bulb for 10 hours in tonnes= \",\n",
+      "print \"%.6f\"%(m/907.2),\n",
+      "print \"Kg\"\n",
+      "#end\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Mass of water required for lighting the bulb for 10 hours in Kg=  4296.455424 Kg\n",
+        "Mass of water required for lighting the bulb for 10 hours in tonnes=  4.735952 Kg\n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.5  Page No : 17"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\n",
+      "#Given\n",
+      "n = 1. #n is the Kg mole of an ideal gas\n",
+      "P = 700.*(10**4) #P is the pressure of the system in N/(m**2)\n",
+      "W = 45. #W is the weight of the mass in Kg\n",
+      "M = 20. #M is the weight of the piston and piston rod together in Kg\n",
+      "T = 300. #T is the consmath.tant temperature of the bath in K\n",
+      "h = .4 #h is the height difference of the piston after expansion in m\n",
+      "\n",
+      "#To calculate the work obtained\n",
+      "a = (10**-4) #a is the cross sectional area of the cylinder in m**2\n",
+      "V = h*a #V is the volume changed as gas expands in m**3\n",
+      "\n",
+      "#(i). If gas alone is the system\n",
+      "#1Kgf = 9.8065Nm\n",
+      "P1 = ((W+M)*9.8065)/(10**-4) #P1 is the resisting pressure when the gas confined in the cylinder taken as a system\n",
+      "W1 = P1*V #W1 is the work done if the gas confined in the cylinder us taken as system\n",
+      "print \"Work done by the system if the gas confined in the cylinder is taken as a system is \",\n",
+      "print \"%.6f \"%W1,\n",
+      "print \"Nm\"\n",
+      "\n",
+      "#(ii). If gas + piston + piston rod is a system\n",
+      "P2 = ((W*9.8065)/(10**-4)) #P2 is the resisting pressure when the gas plus piston plus piston rod is taken as a system\n",
+      "W2 = P2*V #W2 is the Work done by the system if the gas plus piston plus piston rod is taken as a system\n",
+      "print \"Work done by the system if the gas plus piston plus piston rod is taken as system is \",\n",
+      "print \"%.6f\"%W2,\n",
+      "print \"Nm\"\n",
+      "\n",
+      "#(iii). If gas + piston + piston rod +weight is system\n",
+      "P3 = 0 #P3 is the resisting pressure when the gas plus piston plus piston rod plus weight is taken as a system\n",
+      "W3 = P3*V #W3 is the work done by the system if the gas plus piston plus piston rod plus weight is taken as a system\n",
+      "print \"Work done by the system if the gas plus piston plus piston rod plus weight is taken as a system is \",\n",
+      "print \"%.4f\"%W3,\n",
+      "#end\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Work done by the system if the gas confined in the cylinder is taken as a system is  254.969000  Nm\n",
+        "Work done by the system if the gas plus piston plus piston rod is taken as system is  176.517000 Nm\n",
+        "Work done by the system if the gas plus piston plus piston rod plus weight is taken as a system is  0.0000\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.6  Page No : 19"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\n",
+      "#Given\n",
+      "n = 1 #n is the Kg mole of ideal gas.\n",
+      "P1 = 700*(10**4) #P1 is the initial pressure of the system in N/(m**2)\n",
+      "P2 = 638*(10**4) #P2 is the final pressure of the system in N/(m**2)\n",
+      "T = 300 #T is temperature of the system in K\n",
+      "R = 8314.4 #R is gas consmath.tant in Nm/Kgmole deg K\n",
+      "\n",
+      "#To calculate the work done\n",
+      "W = n*R*T*math.log(P1/float(P2)) #W is the work done by the system in Nm\n",
+      "print \"Work done by the system is \",\n",
+      "print \"%.2e\"%W,\n",
+      "print \"Nm\"\n",
+      "#end"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Work done by the system is  2.31e+05 Nm\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
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