Added(A)/Deleted(D) following books

M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/README.txt M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter10_2.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter10_3.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter11.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter11_1.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter12_2.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter12_3.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter13_2.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter13_3.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter14_2.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter14_3.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter15_2.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter15_3.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter16_2.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter16_3.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter1_2.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter1_3.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter2_2.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter2_3.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter3.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter3_1.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter4.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter4_1.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter5.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter5_1.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter6_2.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter6_3.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter7_2.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter7_3.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter8_2.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter8_3.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter9_2.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter9_3.ipynb M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/screenshots/Screenshot_from_2016-01-14_17_01_00.png M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/screenshots/Screenshot_from_2016-01-14_17_01_00_1.png M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/screenshots/Screenshot_from_2016-01-14_17_01_25.png M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/screenshots/Screenshot_from_2016-01-14_17_01_25_1.png M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/screenshots/Screenshot_from_2016-01-14_17_02_44.png M 1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/screenshots/Screenshot_from_2016-01-14_17_02_44_1.png M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter25_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter25_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter25_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter26_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter26_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter26_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter27_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter27_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter27_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter28_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter28_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter28_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter29_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter29_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter29_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter30_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter30_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter30_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter31_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter31_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter31_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter32_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter32_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter32_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter33_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter33_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter33_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter34_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter34_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter34_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter35_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter35_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter35_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter36_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter36_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter36_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter37_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter37_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter37_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter38_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter38_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter38_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter39_4.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter39_5.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/chapter39_6.ipynb M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/screenshots/chapter29example32_4.png M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/screenshots/chapter29example32_5.png M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/screenshots/chapter29example32_6.png M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/screenshots/chapter29example33_4.png M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/screenshots/chapter29example33_5.png M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/screenshots/chapter29example33_6.png M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/screenshots/chapter32example30_4.png M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/screenshots/chapter32example30_5.png M A_Textbook_of_Electrical_Technology_:_AC_and_DC_Machines_(Volume_-_2)_by_A_K_Theraja_B_L_Thereja/screenshots/chapter32example30_6.png M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap10_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap11_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap12_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap13_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap16_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap17_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap18_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap19_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap20_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap21_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap22_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap23_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap24_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap25_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap26_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap27_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap28_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap29_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap30_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap31_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap32_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap33_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap34_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap3_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap5_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap7_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap8_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/Chap9_2.ipynb M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/README.txt M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/screenshots/11DrainCurrentGraph.png M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/screenshots/18VceVsIce.png M A_Textbook_of_Electronic_Circuits_by_R._S._Sedha/screenshots/24GainGraph.png M Analog_Electronics_by_U._A._Bakshi_And_A._P._Godse/README.txt M Applied_Thermodynamics_and_Engineering_by_T._D._Eastop_and_A._Mcconkey/README.txt A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter01.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter02.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter03.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter04.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter05.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter10.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter11.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter12.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter13.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter14.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter15.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter16.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter17.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter18.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter19.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter20.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter21.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter22.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter6.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter7.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter8.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter9.ipynb A Basic_And_Applied_Thermodynamics_by_P._K._Nag/screenshots/16.11.png A Basic_And_Applied_Thermodynamics_by_P._K._Nag/screenshots/3.3.png A Basic_And_Applied_Thermodynamics_by_P._K._Nag/screenshots/7.10.png R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/chapter1.ipynb -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/chapter1.ipynb R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/chapter10.ipynb -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/chapter10.ipynb R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/chapter13.ipynb -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/chapter13.ipynb R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/chapter14.ipynb -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/chapter14.ipynb R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/chapter15.ipynb -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/chapter15.ipynb R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/chapter2.ipynb -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/chapter2.ipynb R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/chapter3.ipynb -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/chapter3.ipynb R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/chapter4.ipynb -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/chapter4.ipynb R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/chapter5.ipynb -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/chapter5.ipynb R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/chapter6.ipynb -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/chapter6.ipynb R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/chapter7.ipynb -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/chapter7.ipynb R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/chapter8.ipynb -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/chapter8.ipynb R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/chapter9.ipynb -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/chapter9.ipynb R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/screenshots/Screenshot_(88).png -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/screenshots/Screenshot_(88).png R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/screenshots/Screenshot_(89).png -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/screenshots/Screenshot_(89).png R Basic_Electronics_(Electronics_Engineering)_by_J.B.Gupta/screenshots/Screenshot_(90).png -> Basic_Electronics_(Electronics_Engineering)_by_J_B_Gupta/screenshots/Screenshot_(90).png M Coulson_And_Richardsons_Chemical_Engineering,_Volume_2_by_J._M._Coulson,_J._F._Richardson,_J._R._Backhurst_And_J._H._Harker/README.txt M Digital_Communications_by_S._Haykin/Chapter1.ipynb M Digital_Communications_by_S._Haykin/Chapter2.ipynb M Digital_Communications_by_S._Haykin/Chapter3.ipynb M Digital_Communications_by_S._Haykin/Chapter4.ipynb M Digital_Communications_by_S._Haykin/Chapter5.ipynb M Digital_Communications_by_S._Haykin/Chapter6.ipynb M Digital_Communications_by_S._Haykin/Chapter7.ipynb M Digital_Communications_by_S._Haykin/Chapter8.ipynb M Digital_Communications_by_S._Haykin/Chapter9.ipynb M Digital_Communications_by_S._Haykin/screenshots/Ch-6_RaisedCosineSpectrum.png M Digital_Communications_by_S._Haykin/screenshots/Ch6_powerSpectralDensities.png M Digital_Communications_by_S._Haykin/screenshots/ch6_sinc_pilse.png M Electrical_Engineering_-_Principles_And_Applications_by_Allan._R._Hambley/README.txt M Electrical_Engineering_-_Principles_And_Applications_by_Allan._R._Hambley/chapter10_1.ipynb M Electrical_Engineering_-_Principles_And_Applications_by_Allan._R._Hambley/chapter11_1.ipynb M Electrical_Engineering_-_Principles_And_Applications_by_Allan._R._Hambley/chapter12_1.ipynb M Electrical_Engineering_-_Principles_And_Applications_by_Allan._R._Hambley/chapter13_1.ipynb M Electrical_Engineering_-_Principles_And_Applications_by_Allan._R._Hambley/chapter14_1.ipynb M Electrical_Engineering_-_Principles_And_Applications_by_Allan._R._Hambley/chapter15_1.ipynb M Electrical_Engineering_-_Principles_And_Applications_by_Allan._R._Hambley/chapter16_1.ipynb M Electrical_Engineering_-_Principles_And_Applications_by_Allan._R._Hambley/chapter17_1.ipynb M Electrical_Engineering_-_Principles_And_Applications_by_Allan._R._Hambley/chapter1_1.ipynb M 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Numerical_Methods_For_Engineers_by_S._C._Chapra_And_R._P._Canale/Chapter26_2.ipynb M Numerical_Methods_For_Engineers_by_S._C._Chapra_And_R._P._Canale/Chapter3_2.ipynb M Numerical_Methods_For_Engineers_by_S._C._Chapra_And_R._P._Canale/Chapter4_2.ipynb M Numerical_Methods_For_Engineers_by_S._C._Chapra_And_R._P._Canale/Chapter5_2.ipynb M Numerical_Methods_For_Engineers_by_S._C._Chapra_And_R._P._Canale/Chapter6_2.ipynb M Numerical_Methods_For_Engineers_by_S._C._Chapra_And_R._P._Canale/Chapter7_2.ipynb M Numerical_Methods_For_Engineers_by_S._C._Chapra_And_R._P._Canale/Chapter9_2.ipynb M Numerical_Methods_For_Engineers_by_S._C._Chapra_And_R._P._Canale/README.txt M Numerical_Methods_For_Engineers_by_S._C._Chapra_And_R._P._Canale/screenshots/image1.png M Numerical_Methods_For_Engineers_by_S._C._Chapra_And_R._P._Canale/screenshots/image2.png M Numerical_Methods_For_Engineers_by_S._C._Chapra_And_R._P._Canale/screenshots/image3.png M Optical_Fiber_Communication_System_by_Dr._M.K._Raina/README.txt 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modern_physics_by_Satish_K._Gupta/screenshots/image33_1.png M sample_notebooks/AdityaR/Chapter_5-Sample_Notebook.ipynb M sample_notebooks/AdityaR/Chapter_5.ipynb M sample_notebooks/AshvaniKumar/ch10.ipynb M "sample_notebooks/Deepak SinghAttri/Chapter17.ipynb" M sample_notebooks/Harshitgarg/Chapter_1-INTRODUCTION_TO_MECHANICS_OF_SOLIDS_.ipynb M sample_notebooks/Harshitgarg/Chapter_1-INTRODUCTION_TO_MECHANICS_OF_SOLIDS__1.ipynb M sample_notebooks/Harshitgarg/Chapter_1-INTRODUCTION_TO_MECHANICS_OF_SOLIDS__2.ipynb M "sample_notebooks/KARTHIKEYAN S/CHAPTER_1.ipynb" M sample_notebooks/MeenaChandrupatla/Chapter2_Gases.ipynb M sample_notebooks/MeenaChandrupatla/Chapter2_Gases_1.ipynb M sample_notebooks/MohdAsif/chapter1.ipynb M sample_notebooks/NityaL/Sample-Chapter_26.ipynb M sample_notebooks/NityaL/Sample.ipynb M "sample_notebooks/PRAVEENKUMAR C/STATICS_CHAPTER_1.ipynb" M sample_notebooks/PraveenKumar/chapter1.ipynb M sample_notebooks/PreetiRani/ch4.ipynb M sample_notebooks/PriyankaSaini/CHAPTER1.ipynb M "sample_notebooks/Reshma Ustad/Chapter_2_Properties_Of_Material.ipynb" M sample_notebooks/RuchiMittal/chpater3.ipynb M sample_notebooks/SPANDANAARROJU/Chapter5.ipynb M "sample_notebooks/Sai KumarMadem/Chapter2.ipynb" M sample_notebooks/ShantanuBhosale/chapter40.ipynb M sample_notebooks/ShantanuBhosale/chapter40_1.ipynb M sample_notebooks/SundeepKatta/Chapter7.ipynb M sample_notebooks/VineshSaini/ch10.ipynb M sample_notebooks/kapiljain/Chapter12.ipynb M sample_notebooks/karansingh/ch1.ipynb M sample_notebooks/kartiksankhla/Chapter2_1.ipynb M sample_notebooks/maheshvattikuti/Untitled-checkpoint.ipynb M sample_notebooks/pratiksonone/Chapter1_1.ipynb M sample_notebooks/ramcharanvattikuti/Untitled-checkpoint.ipynb
author: Trupti Kini 2016-09-02 23:32:06 +0600
committer: Trupti Kini 2016-09-02 23:32:06 +0600
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parent: a001e64f70ee1aaf6051d6e25ca337ca680effb3 (diff)
download: Python-Textbook-Companions-b417454ff6b5f8c2eb90f054723965a8f52e0268.tar.gz
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+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:b2f54f310fd29f155b5ab8bf6130bc373840081bfb6b07a6cc4e8d0ed69571ef"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 14: Refrigeration cycle"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex14.1:pg-602"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "T2 = -5.0 # Cold storage temperature in degree Celsius\n",
+      "T1 = 35.0 # Surrounding temperature in degree Celsius\n",
+      "COP = (T2+273)/((T1+273)-(T2+273))\n",
+      "ACOP = COP/3 # Actual COP\n",
+      "Q2 = 29.0 # Heat leakage in kW\n",
+      "W = Q2/ACOP\n",
+      "print \"\\n Example 14.1\\n\"\n",
+      "print \"\\n Power required to drive the plane is \",W ,\" kW\"\n",
+      "#The answers vary due to round off error\n",
+      "\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "\n",
+        " Example 14.1\n",
+        "\n",
+        "\n",
+        " Power required to drive the plane is  12.9850746269  kW\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex14.2:pg-603"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# At P = 0.14 MPa\n",
+      "h1 = 236.04 # Enthalpy at state 1 in kJ/kg\n",
+      "s1 = 0.9322 # Entropy at state 2 in kJ/kgK\n",
+      "s2 = s1 # Isenthalpic process\n",
+      "# At P = 0.8 MPa\n",
+      "h2 = 272.05 # Enthalpy at state 2 in kJ/kg\n",
+      "h3 = 93.42 # Enthalpy at state 3 in kJ/kg\n",
+      "h4 = h3 # Isenthalpic process\n",
+      "m = 0.06 # mass flow rate in kg/s\n",
+      "Q2 = m*(h1-h4) # Heat absorption\n",
+      "Wc = m*(h2-h1) # Compressor work\n",
+      "Q1 = m*(h2-h4) # Heat rejection in evaporator\n",
+      "COP = Q2/Wc # coefficient of performance\n",
+      "\n",
+      "print \"\\n Example 14.2\\n\"\n",
+      "print \"\\n The rate of heat removal is \",Q2 ,\" kW\"\n",
+      "print \"\\n Power input to the compressor is \",Wc ,\" kW\"\n",
+      "print \"\\n The heat rejection rate in the condenser is \",Q1 ,\" kW\"\n",
+      "print \"\\n COP is \",COP ,\" kW\"\n",
+      "#The answers vary due to round off error\n",
+      "\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "\n",
+        " Example 14.2\n",
+        "\n",
+        "\n",
+        " The rate of heat removal is  8.5572  kW\n",
+        "\n",
+        " Power input to the compressor is  2.1606  kW\n",
+        "\n",
+        " The heat rejection rate in the condenser is  10.7178  kW\n",
+        "\n",
+        " COP is  3.9605665093  kW\n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex14.3:pg-604"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "h1 = 183.19 # Enthalpy at state 1 in kJ/kg\n",
+      "h2 = 209.41 # Enthalpy at state 2 in kJ/kg\n",
+      "h3 = 74.59 # Enthalpy at state 3 in kJ/kg\n",
+      "h4 = h3 # Isenthalpic process\n",
+      "T1 = 40.0 # Evaporator temperature in degree Celsius \n",
+      "T2 = -10.0 # Condenser temperature in degree Celsius\n",
+      "W = 5.0 # Plant capacity in tonnes of refrigeration\n",
+      "w = (W*14000/3600)/(h1-h4) # Refrigerant flow rate\n",
+      "v1 = 0.077 # Specific volume of vapor in m**3/kg\n",
+      "VFR = w*v1 # volume flow rate\n",
+      "T = 48.0 # Compressor discharge temperature in degree Celsius\n",
+      "P2 = 9.6066 # Pressure after compression\n",
+      "P1 = 2.1912 # Pressure before compression\n",
+      "rp = P2/P1 # Pressure ratio\n",
+      "Q1 = w*(h2-h3) # Heat rejected in condenser\n",
+      "hf = 26.87 # Enthalpy of fluid in kJ/kg\n",
+      "hfg = 156.31# Latent heat of vaporization in kJ/kg\n",
+      "x4 = (h4-hf)/hfg # quality of refrigerant\n",
+      "COP_v = (h1-h4)/(h2-h1) # Actual coefficient of performance of cycle\n",
+      "PI = w*(h2-h1) # Power input\n",
+      "COP = (T2+273)/((T1+273)-(T2+273)) # Ideal coefficient of performance\n",
+      "r = COP_v/COP\n",
+      "print \"\\n Example 14.3\\n\"\n",
+      "print \"\\n Refrigerant flow rate is \",w ,\" kg/s\"\n",
+      "print \"\\n Volume flow rate is \",VFR ,\" m**3/s\"\n",
+      "print \"\\n Compressor discharge temperature is \",T ,\" degree Celsius \"\n",
+      "print \"\\n Pressure ratio is \",rp\n",
+      "print \"\\n Heat rejected to the condenser is \",Q1 ,\" kW\"\n",
+      "print \"\\n Flash gas percentage is \",x4*100 ,\" percent\"\n",
+      "print \"\\n COP is \",COP_v ,\" kW\"\n",
+      "print \"\\n Power required to drive the compressor is \",PI ,\" kW\"\n",
+      "print \"\\n Ratio of COP of cycle with  Carnot refrigerator is \",r\n",
+      "#The answers vary due to round off error\n",
+      "\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "\n",
+        " Example 14.3\n",
+        "\n",
+        "\n",
+        " Refrigerant flow rate is  0.179046449765  kg/s\n",
+        "\n",
+        " Volume flow rate is  0.0137865766319  m**3/s\n",
+        "\n",
+        " Compressor discharge temperature is  48.0  degree Celsius \n",
+        "\n",
+        " Pressure ratio is  4.38417305586\n",
+        "\n",
+        " Heat rejected to the condenser is  24.1390423573  kW\n",
+        "\n",
+        " Flash gas percentage is  30.5290768345  percent\n",
+        "\n",
+        " COP is  4.14187643021  kW\n",
+        "\n",
+        " Power required to drive the compressor is  4.69459791283  kW\n",
+        "\n",
+        " Ratio of COP of cycle with  Carnot refrigerator is  0.787428979127\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex14.4:pg-605"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "h3 = 882 # Enthalpy at state 3 in kJ/kg\n",
+      "h2 = 1034 # Enthalpy at state 2 in kJ/kg\n",
+      "h6 = 998 # Enthalpy at state 6 in kJ/kg\n",
+      "h1 = 1008 # Enthalpy at state 1 in kJ/kg\n",
+      "v1 = 0.084 # Specific volume at state 1 in m**3/kg\n",
+      "t4 = 25 # Temperature at state 4 in degree Celsius\n",
+      "m = 10 # mass flow rate in kg/s\n",
+      "h4 = h3-h1+h6 \n",
+      "h5 = h4 # isenthalpic process\n",
+      "w = (m*14000)/((h6-h5)*3600) # in kg/s\n",
+      "VFR = w*3600*v1 # Volume flow rate in m**3/h\n",
+      "ve = 0.8 # volumetric efficiency\n",
+      "CD = VFR/(ve*60) # Compressor displacement in m**3/min\n",
+      "N = 900 # Number of strokes per minute\n",
+      "n = 2 # number of cylinder\n",
+      "\n",
+      "D = ((CD*4)/(math.pi*1.1*N*n))**(1/3) # L = 1.1D L = length D = diameter\n",
+      "L = 1.1*D\n",
+      "COP = (h6-h5)/(h2-h1) # coefficient of performance\n",
+      "PI = w*(h2-h1) # Power input\n",
+      "\n",
+      "print \"\\n Example 14.4\\n\"\n",
+      "print \"\\n Refrigeration effect is \",h6-h5 ,\" kJ/kg\"\n",
+      "print \"\\n Refrigerant flow rate is \",w ,\" kg/s\"\n",
+      "print \"\\n Diameter of cylinder is \",D*100 ,\" cm\"\n",
+      "print \"\\n Length of cylinder is \",L*100 ,\" cm\"\n",
+      "print \"\\n COP is \",COP\n",
+      "print \"\\n Power required to drive the compressor is \",PI ,\" kW\"\n",
+      "\n",
+      "#The answers vary due to round off error\n",
+      "\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "\n",
+        " Example 14.4\n",
+        "\n",
+        "\n",
+        " Refrigeration effect is  126  kJ/kg\n",
+        "\n",
+        " Refrigerant flow rate is  0  kg/s\n",
+        "\n",
+        " Diameter of cylinder is  100.0  cm\n",
+        "\n",
+        " Length of cylinder is  110.0  cm\n",
+        "\n",
+        " COP is  4\n",
+        "\n",
+        " Power required to drive the compressor is  0  kW\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex14.5:pg-607"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "P2 = 1554.3 # Pressure at state 2 in kPa\n",
+      "P1 = 119.5# Pressure at state 1 in kPa\n",
+      "Pi = sqrt(P1*P2)\n",
+      "h1 = 1404.6 # Enthalpy at state1 in kJ/kg\n",
+      "h2 = 1574.3 # Enthalpy at state2 in kJ/kg\n",
+      "h3 = 1443.5 # Enthalpy at state3 in kJ/kg\n",
+      "h4 = 1628.1# Enthalpy at state4 in kJ/kg\n",
+      "h5 = 371.7 # Enthalpy at state5 in kJ/kg\n",
+      "h6 = h5 # Isenthalpic process\n",
+      "h7 = 181.5# Enthalpy at state7 in kJ/kg\n",
+      "w = 30 # capacity of plant in tonnes of refrigeration\n",
+      "m2_dot = (3.89*w)/(h1-h7) # mass flow rate in upper cycle\n",
+      "m1_dot = m2_dot*((h2-h7)/(h3-h6))# mass flow rate in lower cycle\n",
+      "Wc_dot = m2_dot*(h2-h1)+m1_dot*(h4-h3) # Compressor work\n",
+      "COP = w*3.89/Wc_dot # Coefficient of performance of cycle\n",
+      "# single stage\n",
+      "h1_ = 1404.6 #Enthalpy at state1 in kJ/kg \n",
+      "h2_ = 1805.1 # Enthalpy at state2 in kJ/kg \n",
+      "h3_ = 371.1 # Enthalpy at state3 in kJ/kg \n",
+      "h4_ = h3_ # Isenthalpic process\n",
+      "m_dot = (3.89*30)/(h1_-h4_) # mass flow rate in cycle\n",
+      "Wc = m_dot*(h2_-h1_) # Compressor work\n",
+      "COP_ = w*3.89/Wc # Coefficient of performance of cycle\n",
+      "IW = (Wc-Wc_dot)/Wc_dot # Increase in compressor work\n",
+      "ICOP = (COP-COP_)/COP_ # Increase in COP for 2 stage compression\n",
+      "print \"\\n Example 14.5\\n\"\n",
+      "print \"\\n Increase in work of compression for single stage  is \",IW*100 ,\" percent\"\n",
+      "print \"\\n Increase in COP for 2 stage compression is \",ICOP*100 ,\" percent\"\n",
+      "#The answers vary due to round off error\n",
+      "\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "\n",
+        " Example 14.5\n",
+        "\n",
+        "\n",
+        " Increase in work of compression for single stage  is  15.719846307  percent\n",
+        "\n",
+        " Increase in COP for 2 stage compression is  15.719846307  percent\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex14.6:pg-608"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Given that\n",
+      "te = -10 # Evaporator temperature in degree celsius\n",
+      "pc = 7.675 # Condenser pressure in bar\n",
+      "pf = 4.139 # Flash chamber pressure in bar\n",
+      "P = 100 # Power input to compressor in kW\n",
+      "print \"\\n Example 14.6\\n\"\n",
+      "# From the property table of R-134a,\n",
+      "h7 = 140.96 # In kJ/kg\n",
+      "hf = 113.29 # In kJ/kg\n",
+      "hfg = 300.5-113.29 # In kJ/kg\n",
+      "hg = 300.5 # In kJ/kg\n",
+      "h1 = 288.86 # In kJ/kg\n",
+      "s1 = 1.17189 # # In kJ/kgK\n",
+      "s2 =s1\n",
+      "#By interpolation \n",
+      "h2 = 303.468 # In kJ/kg\n",
+      "x8 = (h7-hf)/hfg\n",
+      "m1=x8\n",
+      "h5 = (1-m1)*h2 + m1*hg\n",
+      "# By interpolation\n",
+      "s5 = 1.7174 # In kJ/kgK\n",
+      "s6=s5\n",
+      "h6 = 315.79 # In kJ/kg\n",
+      "m = P/((h6-h5) + (1-m1)*(h2-h1))\n",
+      "m_e = (1-m1)*m\n",
+      "COP = m_e*(h1-hf)/P\n",
+      "print \"\\n The COP of the plant is \",COP ,\", \\n The mass flow rate of refrigerant in the evaporator is \",m_e ,\" kg/s\"\n",
+      "\n",
+      "\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "\n",
+        " Example 14.6\n",
+        "\n",
+        "\n",
+        " The COP of the plant is  5.93506047745 , \n",
+        " The mass flow rate of refrigerant in the evaporator is  3.38045251321  kg/s\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex14.7:pg-609"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "tsat = 120.2 # Saturation temperature in degree Celsius\n",
+      "hfg = 2201.9 # Latent heat of fusion in kJ/kg\n",
+      "T1 = 120.2 # Generator temperature in degree Celsius\n",
+      "T2 = 30 # Ambient temperature in degree Celsius\n",
+      "Tr = -10 # Operating temperature of refrigerator in degree Celsius\n",
+      "COP_max = (((T1+273)-(T2+273))*(Tr+273))/(((T2+273)-(Tr+273))*(T1+273)) # Ideal coefficient of performance \n",
+      "ACOP = 0.4*COP_max # Actual COP\n",
+      "L =  20 # Refrigeration load in tonnes\n",
+      "Qe = (L*14000)/3600 # Heat extraction in KW\n",
+      "Qg = Qe/ACOP # Heat transfer from generator \n",
+      "x = 0.9 # Quality of refrigerant\n",
+      "H = x*hfg # Heat extraction\n",
+      "SFR = Qg/H # Steam flow rate\n",
+      "print \"\\n Example 14.7\\n\"\n",
+      "print \"\\n Steam flow rate required is \",SFR ,\" kg/s\"\n",
+      "#The answers vary due to round off error\n",
+      "\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "\n",
+        " Example 14.7\n",
+        "\n",
+        "\n",
+        " Steam flow rate required is  0.0644023696678  kg/s\n"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex14.8:pg-611"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Given that\n",
+      "tf = 5 # Temperature of flash chamber in degree celsius\n",
+      "x = 0.98 # Quality of water vapour living the evaporator\n",
+      "t2 = 14 # Returning temperature of chilled water in degree celsius\n",
+      "t0 = 30 # Make up water temperature in degree celsius\n",
+      "m = 12 # Mass flow rate of chilled water in kg/s\n",
+      "nc = 0.8 # Compressor efficiecy \n",
+      "pc = 0.1 # Condenser pressure in bar\n",
+      "print \"\\n Example 14.8\\n\"\n",
+      "#From the steam table\n",
+      "hf = 58.62 # In kJ/kg at 14 degree celsius\n",
+      "hf_ = 20.93 # In kJ/kg at 5 degree celsius\n",
+      "hf__ = 125.73 # In kJ/kg at 30 degree celsius\n",
+      "hv = x*2510.7\n",
+      "Rc = m*(hf-hf_)/3.5\n",
+      "m_v = Rc*3.5/(hv-hf__)\n",
+      "# At 0.10 bar\n",
+      "hg = 2800 # In kJ/kg \n",
+      "Win = m_v*(hg-hv)/nc\n",
+      "COP = Rc*3.5/Win\n",
+      "print \"\\nCOP of the system is \",COP"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "\n",
+        " Example 14.8\n",
+        "\n",
+        "\n",
+        "COP of the system is  5.50140730574\n"
+       ]
+      }
+     ],
+     "prompt_number": 10
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex14.9:pg-611"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\n",
+      "T1 = 4.0 # Compressor inlet temperature in degree Celsius\n",
+      "T3 = 55.0 # Cooling limit in heat exchanger in degree Celsius\n",
+      "rp = 3.0 # Pressure ratio\n",
+      "g = 1.4 # Heat capacity ratio\n",
+      "cp = 1.005 # Constant volume heat capacity\n",
+      "L = 3.0 # Cooling load in tonnes of refrigeration\n",
+      "nc = 0.72 # compressor efficiency\n",
+      "T2s = (T1+273)*(rp**((g-1)/g)) # Ideal temperature after compression\n",
+      "T2 = (T1+273)+(T2s-T1-273)/nc # Actual temperature after compression\n",
+      "T4s = (T3+273)/(rp**((g-1)/g)) # Ideal temperature after expansion\n",
+      "T34 = 0.78*(T3+273-T4s) # Change in temperature during expansion process\n",
+      "T4 = T3+273-T34 # Actual temperature after expansion\n",
+      "COP = (T1+273-T4)/((T2-T1-273)-(T3+273-T4)) # Coefficient of performance of cycle\n",
+      "P = (L*14000)/(COP*3600) # Driving power required\n",
+      "m = (L*14000)/(cp*(T1+273-T4)) # Mass flow rate of air\n",
+      "print \"\\n Example 14.9\\n\"\n",
+      "print \"\\n COP of the refrigerator is \",COP\n",
+      "print \"\\n Driving power required is \",P ,\" kW\"\n",
+      "print \"\\n Mass flow rate is \",m/3600 ,\" kg/s\"\n",
+      "#The answers vary due to round off error"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "\n",
+        " Example 14.9\n",
+        "\n",
+        "\n",
+        " COP of the refrigerator is  0.245731992881\n",
+        "\n",
+        " Driving power required is  47.4771987558  kW\n",
+        "\n",
+        " Mass flow rate is  0.64768311581  kg/s\n"
+       ]
+      }
+     ],
+     "prompt_number": 11
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex14.10:pg-611"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "P1 = 2.4  #Compressor inlet pressure in bar\n",
+      "T1 = 0 # Compressor inlet temperature in degree Celsius\n",
+      "h1 = 188.9 # Enthalpy of refrigerant at state 1 in kJ/kg\n",
+      "s1 = 0.7177 # Entropy of refrigerant at state 1 in kJ/kgK\n",
+      "v1 = 0.0703 # Specific volume at state 1 in m**3/kg\n",
+      "P2 = 9 # Compressor outlet pressure in bar\n",
+      "T2 = 60 # Compressor outlet pressure in degree Celsius\n",
+      "h2 = 219.37 # Actual compressor outlet enthalpy in kJ/kgK\n",
+      "h2s = 213.27 # Ideal compressor outlet enthalpy in kJ/kgK\n",
+      "h3 = 71.93 # Enthalpy of refrigerant at state 3 in kJ/kg\n",
+      "h4 = h3 # Isenthalpic process\n",
+      "\n",
+      "A1V1 = 0.6/60 # volume flow rate in kg/s\n",
+      "m_dot = A1V1/v1 # mass flow rate\n",
+      "Wc_dot = m_dot*(h2-h1) # Compressor work\n",
+      "Q1_dot = m_dot*(h2-h3) # Heat extracted \n",
+      "COP = Q1_dot/Wc_dot # Coefficient of performance\n",
+      "nis = (h2s-h1)/(h2-h1) # Isentropic compressor efficiency\n",
+      "print \"\\n Example 14.10\\n\"\n",
+      "print \"\\n Power input is \",Wc_dot ,\" kW\"\n",
+      "print \"\\n Heating capacity is \",Q1_dot ,\" kW\"\n",
+      "print \"\\n COP is \",COP\n",
+      "print \"\\n The isentropic compressor efficiency is \",nis*100 ,\" percent\"\n",
+      "#The answers vary due to round off error"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "\n",
+        " Example 14.10\n",
+        "\n",
+        "\n",
+        " Power input is  4.33428165007  kW\n",
+        "\n",
+        " Heating capacity is  20.972972973  kW\n",
+        "\n",
+        " COP is  4.83885789301\n",
+        "\n",
+        " The isentropic compressor efficiency is  79.9803085002  percent\n"
+       ]
+      }
+     ],
+     "prompt_number": 12
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "\n",
+      "Ex14.11:pg-611"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\n",
+      "T1 = 275.0 # Temperature of air at entrance to compressor in K \n",
+      "T3 = 310.0 # Temperature of air at entrance to turbine in K \n",
+      "P1 = 1.0  # Inlet presure in bar\n",
+      "P2 = 4.0 # Outlet pressure in bar\n",
+      "nc = 0.8 # Compressor efficiency\n",
+      "T2s = T1*(P2/P1)**(.286) # Ideal temperature after compression\n",
+      "T2 = T1 + (T2s-T1)/nc # Actual temperature after compression\n",
+      "pr1 = 0.1 # Pressure loss in cooler in bar\n",
+      "pr2 = 0.08 #Pressure loss in condensor in bar \n",
+      "P3 = P2-0.1 # Actual pressure in condesor\n",
+      "P4 = P1+0.08 # Actual pressure in evaporator\n",
+      "PR = P3/P4 # Pressure ratio\n",
+      "T4s = T3*(1/PR)**(0.286) # Ideal temperature after expansion\n",
+      "nt = 0.85 # turbine efficiency\n",
+      "T4 = T3-(T3-T4s)*nt # Actual temperature after expansion\n",
+      "COP = (T1-T4)/((T2-T3)-(T1-T4)) # Coefficient of performance \n",
+      "print \"\\n Example 14.11\\n\"\n",
+      "print \"\\n Pressure ratio for the turbine is \",PR\n",
+      "print \"\\n COP is \",COP\n",
+      "#The answers vary due to round off error\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "\n",
+        " Example 14.11\n",
+        "\n",
+        "\n",
+        " Pressure ratio for the turbine is  3.61111111111\n",
+        "\n",
+        " COP is  0.533011099882\n"
+       ]
+      }
+     ],
+     "prompt_number": 13
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex14.12:pg-611"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Given that\n",
+      "L = 60.0 # Cooling load in kW\n",
+      "p = 1.0 # Pressure in bar\n",
+      "t = 20.0 # Temperature in degree celsius\n",
+      "v = 900.0 # Speed of aircraft in km/h\n",
+      "p1 = 0.35 # Pressure in bar\n",
+      "T1 = 255 # Temperature in K\n",
+      "nd = .85 # Diffuser efficiency \n",
+      "rp = 6.0 # Pressure ratio of compressor\n",
+      "nc = .85 # Copressor efficiency \n",
+      "E = 0.9 # Effectiveness of air cooler\n",
+      "nt = 0.88 # Turbine efficiency \n",
+      "p_ = 0.08 # Pressure drop in air cooler in bar\n",
+      "p5 =  1.08 # Pressure in bar\n",
+      "cp = 1.005 # Heat capacity of air at constant pressure in kJ/kgK\n",
+      "gama = 1.4 # Ratio of heat capacities of air\n",
+      "print \"\\n Example 14.12\\n\"\n",
+      "V = v*(5/18)\n",
+      "T2_ = T1 + (V**2)/(2*cp*1000)\n",
+      "T2 = T2_\n",
+      "p2_ = p1*((T2_/T1)**((gama/(gama-1))))\n",
+      "p2 = p1 + nd*(p2_-p1)\n",
+      "p3 = rp*p2\n",
+      "T3_ = T2*((p3/p2)**((gama-1)/gama))\n",
+      "T3 = T2 + (T3_-T2)/nc\n",
+      "P = cp*(T3-T2)\n",
+      "p4 = p3 - p_\n",
+      "T4 = T3 - E*(T3-T2)\n",
+      "T5_ = T4/((p4/p5)**(.286))\n",
+      "T5 = T4 - (T4-T5_)/nt\n",
+      "RE = cp*(t+273 - T5)\n",
+      "m = L/51.5\n",
+      "Pr = m*P\n",
+      "COP = L/Pr\n",
+      "print \"\\n Mass flow rate of air flowing through the cooling system is \",m\n",
+      "print \"\\n COP is \",COP\n",
+      "#The answers vary due to round off error"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "\n",
+        " Example 14.12\n",
+        "\n",
+        "\n",
+        " Mass flow rate of air flowing through the cooling system is  1.16504854369\n",
+        "\n",
+        " COP is  0.255512245083\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file
author	Trupti Kini	2016-09-02 23:32:06 +0600
committer	Trupti Kini	2016-09-02 23:32:06 +0600
commit	b417454ff6b5f8c2eb90f054723965a8f52e0268 (patch)
tree	466011c3926650f317396f0330586156abe58609 /Basic_And_Applied_Thermodynamics_by_P._K._Nag/Chapter14.ipynb
parent	a001e64f70ee1aaf6051d6e25ca337ca680effb3 (diff)
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