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authorThomas Stephen Lee2015-08-28 16:53:23 +0530
committerThomas Stephen Lee2015-08-28 16:53:23 +0530
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+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:f4a83e38558e2bc6592fc86c02570a86bc0530de75031ae379e4ed7bef896b2d"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter13 - Voltage Regulators"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex 13.1 - page : 414"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from __future__ import division\n",
+ "deltaVin=4 #V\n",
+ "deltaVout=0.4 #V\n",
+ "Vout=20 #V\n",
+ "LR=(deltaVout/Vout)*100/deltaVin #%/V(Line Regulation)\n",
+ "print \"Line Regulation = %0.1f %%/V \" %LR"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Line Regulation = 0.5 %/V \n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex 13.2 - page : 414"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "VNL=18.0 #V\n",
+ "VFL=17.8 #V\n",
+ "IL=50.0 #mA\n",
+ "LR=(VNL-VFL)*100/VFL #%(Line Regulation)\n",
+ "LdR=LR/IL #%/mA(Load Regulation)\n",
+ "print \"Load Regulation = %0.3f %%/mA \" %LdR "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Load Regulation = 0.022 %/mA \n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex 13.3 - page : 419"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "VBE=0.65 #V\n",
+ "RCL=1.2 #ohm\n",
+ "ILmax=VBE/RCL #A\n",
+ "#For Vout=0, IL=ILmax\n",
+ "IL=ILmax #A\n",
+ "print \"Load current = %0.2f A \" %IL "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Load current = 0.54 A \n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex 13.4 - page : 420"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from __future__ import division\n",
+ "R=20 #kohm\n",
+ "R1=20 #kohm\n",
+ "R2=10 #kohm\n",
+ "VZ=4.7 #V\n",
+ "Vref=VZ #V\n",
+ "Vout=Vref*(1+R1/R2) #V\n",
+ "print \"Output Voltage = %0.1f V \" %Vout"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Output Voltage = 14.1 V \n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex 13.5 - page : 427"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from __future__ import division\n",
+ "Vout=15 #V\n",
+ "Vin=20 #V\n",
+ "INL=2 #mA(INL=Iadj+Iref)\n",
+ "Iadj=60 #mA(Assumed)\n",
+ "Iref=INL-Iadj/1000 #mA\n",
+ "Vref=1.25 #V\n",
+ "R1=Vref/Iref*1000 #ohm\n",
+ "VR2=Vout-Vref #V\n",
+ "R2=VR2/INL*1000 #ohm\n",
+ "print \"Design values are : \"\n",
+ "print \"Resistance, R1 = %0.f ohm \" %R1 \n",
+ "print \"Resistance, R2 = %0.3f kohm \" %(R2/1000 )"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Design values are : \n",
+ "Resistance, R1 = 644 ohm \n",
+ "Resistance, R2 = 6.875 kohm \n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex 13.6 - page : 429"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from __future__ import division\n",
+ "RL1=100 #ohm\n",
+ "RL2=1 #ohm\n",
+ "RCS=7 #ohm\n",
+ "VEB=0.7 #V\n",
+ "Beta=25 #unitless\n",
+ "#For 100 ohm Load\n",
+ "Vout=5 #V(as 7805 used)\n",
+ "IL=Vout/RL1 #A\n",
+ "VRCS=IL*RCS #V(Voltage across RCS)\n",
+ "#VRCS<VEB, hence Q1 is off\n",
+ "Iout=IL; Iin=IL #A\n",
+ "Iext=Iout-Iin #A\n",
+ "print \"For 100 ohm load, Output current Iext = %0.2f A \" %Iext\n",
+ "#For 1 ohm Load\n",
+ "Vout=5 #V(as 7805 used)\n",
+ "IL=Vout/RL2 #A\n",
+ "ILmax=IL #A\n",
+ "VRCS=IL*RCS #V(Voltage across RCS)\n",
+ "#VRCS>VEB, hence Q1 is on\n",
+ "Iout=(ILmax+Beta*VEB/RCS)/(Beta+1) #A\n",
+ "Iext=ILmax-Iout #A\n",
+ "print \"For 10 ohm load, Output current Iext = %0.3f A \" %Iext "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "For 100 ohm load, Output current Iext = 0.00 A \n",
+ "For 10 ohm load, Output current Iext = 4.712 A \n"
+ ]
+ }
+ ],
+ "prompt_number": 15
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex 13.7 - page : 431"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from __future__ import division\n",
+ "RL=range(1,11) #ohm\n",
+ "R1=5 #ohm\n",
+ "Vref=5 #V\n",
+ "IL=1 #A\n",
+ "IQ=0 #A\n",
+ "Iref=IL #A\n",
+ "R1=Vref/Iref #ohm\n",
+ "print \"Value of resistor R1 = %0.f ohm \" %R1"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Value of resistor R1 = 5 ohm \n"
+ ]
+ }
+ ],
+ "prompt_number": 17
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex 13.8 - page : 432"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from __future__ import division\n",
+ "Vout=range(15,21) #V\n",
+ "Vin=24 #V\n",
+ "VR1=12 #V\n",
+ "Vref=12 #V\n",
+ "I4=0 #A(Assumed)\n",
+ "Iout=1 #A(Assumed)\n",
+ "R1=VR1/Iout #ohm\n",
+ "#Vout=VR1*(1+R2/R1)\n",
+ "R2min=R1*(min(Vout)/VR1-1) #Putting min Vout\n",
+ "R2max=R1*(max(Vout)/VR1-1) #Putting min Vout\n",
+ "print \"Resistance R1 = %0.f ohm \" %R1 \n",
+ "print \"Minimum & maximum value of R2 are %0.f ohm & %0.f ohm \" %(R2min,R2max) \n",
+ "#A pot of 10 ohm should be used.\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Resistance R1 = 12 ohm \n",
+ "Minimum & maximum value of R2 are 3 ohm & 8 ohm \n"
+ ]
+ }
+ ],
+ "prompt_number": 22
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex 13.9 - page : 438"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from __future__ import division\n",
+ "Vout=6 #V\n",
+ "IL=100 #mA\n",
+ "Vref=7.15 #V(For LM 723)\n",
+ "Iref=1 #mA(Assumed)\n",
+ "R1=(Vref-Vout)/Iref #kohm\n",
+ "R2=Vout/Iref #kohm\n",
+ "print \"Design values are : \"\n",
+ "print \"R1 should be used 1.2kohm. Calculated R1 %0.2f kohm \" %R1 \n",
+ "print \"R2 should be used 6.2kohm. Calculated R2 = %0.2f kohm \" %R2 \n",
+ "R1=1.2; R2=6.2 #kohm\n",
+ "R3=R1*R2/(R1+R2) #kohm\n",
+ "print \"Resistance R3 = %0.f kohm \" %R3 \n",
+ "RCL=0.65/(IL/1000) #kohm\n",
+ "print \"Resistance RCL = %0.1f kohm \" %RCL "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Design values are : \n",
+ "R1 should be used 1.2kohm. Calculated R1 1.15 kohm \n",
+ "R2 should be used 6.2kohm. Calculated R2 = 6.00 kohm \n",
+ "Resistance R3 = 1 kohm \n",
+ "Resistance RCL = 6.5 kohm \n"
+ ]
+ }
+ ],
+ "prompt_number": 28
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex 13.10 - page : 442"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from __future__ import division\n",
+ "Vout=15 #V\n",
+ "IL=50 #mA\n",
+ "Vin=20 #V\n",
+ "PDmax=1 #W(For LM 723)\n",
+ "Iref=3 #mA(From datasheet)\n",
+ "PD=Vout*(IL+Iref) #mW\n",
+ "print \"Required PD = %0.3f W \" %(PD/1000) \n",
+ "print \"PDmax supplied by LM723 = %0.2f mW \" %PDmax \n",
+ "print \"PD<PDmax, so we can use it.\"\n",
+ "Vref=7.15 #V(For LM 723)\n",
+ "R3=1.5 #kohm(choosen)\n",
+ "R1BYR2=(Vout-Vref)/Vref \n",
+ "R1=R3*(R1BYR2+1) #ohm\n",
+ "print \"Resistance R1 = %0.2f kohm\" %R1 \n",
+ "R2=R1/R1BYR2 #ohm\n",
+ "print \"Resistance R2 = %0.2f kohm \" %R2 \n",
+ "print \"Resistance R3 = %0.2f kohm \" %R3 \n",
+ "RCL=0.65/(IL/1000) #ohm\n",
+ "print \"Resistance RCL = %0.2f ohm \" %RCL "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Required PD = 0.795 W \n",
+ "PDmax supplied by LM723 = 1.00 mW \n",
+ "PD<PDmax, so we can use it.\n",
+ "Resistance R1 = 3.15 kohm\n",
+ "Resistance R2 = 2.87 kohm \n",
+ "Resistance R3 = 1.50 kohm \n",
+ "Resistance RCL = 13.00 ohm \n"
+ ]
+ }
+ ],
+ "prompt_number": 32
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file