Added(A)/Deleted(D) following books

 A  f_by_df/abhishek.ipynb
A  f_by_df/abhishek_1.ipynb
A  f_by_df/screenshots/anshul.png
A  f_by_df/screenshots/blank1.png
A  f_by_df/screenshots/blog.png
A  f_by_df/screenshots/sai.png
A  f_by_df/screenshots/snippet1.png
A  f_by_df/screenshots/srinivas.png
A  hfgd_by_Gayakwad/README.txt
A  hfgd_by_Gayakwad/abhishek.ipynb
A  hfgd_by_Gayakwad/screenshots/anshul.png
A  hfgd_by_Gayakwad/screenshots/anshul_1.png
A  hfgd_by_Gayakwad/screenshots/anshul_2.png
A  rewrew_by_J._B._Gupta/README.txt
A  rewrew_by_J._B._Gupta/aviral.ipynb
A  rewrew_by_J._B._Gupta/screenshots/array_factor.png
A  rewrew_by_J._B._Gupta/screenshots/book.png
A  rewrew_by_J._B._Gupta/screenshots/error.png
A  sample_notebooks/JeevanLal/aditya.ipynb

19 files changed, 781 insertions, 0 deletions

diff --git a/f_by_df/abhishek.ipynb b/f_by_df/abhishek.ipynb
new file mode 100644
index 00000000..3f7271ea
--- /dev/null
+++ b/f_by_df/abhishek.ipynb
@@ -0,0 +1,112 @@
+{


+ "metadata": {


+  "name": "",


+  "signature": "sha256:cda4775b9259e49c042e3120b0a25eb239766f3373696622080f812fe1f53fa9"


+ },


+ "nbformat": 3,


+ "nbformat_minor": 0,


+ "worksheets": [


+  {


+   "cells": [


+    {


+     "cell_type": "heading",


+     "level": 1,


+     "metadata": {},


+     "source": [


+      "Chapter 01:Introduction"


+     ]


+    },


+    {


+     "cell_type": "heading",


+     "level": 2,


+     "metadata": {},


+     "source": [


+      "Ex1.1:pg-20"


+     ]


+    },


+    {


+     "cell_type": "code",


+     "collapsed": false,


+     "input": [


+      "# Given Data\n",


+      "d_r = 13640 # Density of mercury in kg/m^3\n",


+      "g = 9.79 # Acceleration due to gravity in m/s^2\n",


+      "z = 562e-03 # Difference in height in m\n",


+      "z0 = 761e-03 # Reading of barometer in m\n",


+      "P = (d_r*g*(z+z0))*(0.987/1e05) # Gas Pressure in atm\n",


+      "\n",


+      "print \"\\n Example 1.1\\n\"\n",


+      "print \"\\n Gas Pressure is \",round(P,2),\" atm\"\n",


+      "#The answers vary due to round off error\n"


+     ],


+     "language": "python",


+     "metadata": {},


+     "outputs": [


+      {


+       "output_type": "stream",


+       "stream": "stdout",


+       "text": [


+        "\n",


+        " Example 1.1\n",


+        "\n",


+        "\n",


+        " Gas Pressure is  1.74  atm\n"


+       ]


+      }


+     ],


+     "prompt_number": 3


+    },


+    {


+     "cell_type": "heading",


+     "level": 2,


+     "metadata": {},


+     "source": [


+      "Ex1.2:pg-21"


+     ]


+    },


+    {


+     "cell_type": "code",


+     "collapsed": false,


+     "input": [


+      "#Given Data\n",


+      "d_r = 13.6e03 # Density of mercury in kg/m^3\n",


+      "g = 9.81 # Acceleration due to gravity in m/s^2\n",


+      "z = 710e-03 # Steam flow pressure in m\n",


+      "z0 = 772e-03 # Reading of barometer in m\n",


+      "P = 1.4e06 # Gauge pressure of applied steam in Pa\n",


+      "P0 = d_r*g*z0 # Atmospheric pressure in Pa\n",


+      "Pi = P+P0  # Inlet steam pressure in Pa\n",


+      "Pc = d_r*g*(z0-z) # Condenser pressure in Pa\n",


+      "\n",


+      "print \"\\n Example 1.2\\n\"\n",


+      "print \"\\n Inlet steam pressure is\",round(Pi/1e6,2),\" MPa\"\n",


+      "print \"\\n Condenser pressure is\",round(Pc/1e3,2),\" kPa\"\n",


+      "#The answers vary due to round off error\n",


+      "\n",


+      "\n",


+      "\n"


+     ],


+     "language": "python",


+     "metadata": {},


+     "outputs": [


+      {


+       "output_type": "stream",


+       "stream": "stdout",


+       "text": [


+        "\n",


+        " Example 1.2\n",


+        "\n",


+        "\n",


+        " Inlet steam pressure is 1.5  MPa\n",


+        "\n",


+        " Condenser pressure is 8.27  kPa\n"


+       ]


+      }


+     ],


+     "prompt_number": 5


+    }


+   ],


+   "metadata": {}


+  }


+ ]


+}
\ No newline at end of file
diff --git a/f_by_df/abhishek_1.ipynb b/f_by_df/abhishek_1.ipynb
new file mode 100644
index 00000000..3f7271ea
--- /dev/null
+++ b/f_by_df/abhishek_1.ipynb
@@ -0,0 +1,112 @@
+{


+ "metadata": {


+  "name": "",


+  "signature": "sha256:cda4775b9259e49c042e3120b0a25eb239766f3373696622080f812fe1f53fa9"


+ },


+ "nbformat": 3,


+ "nbformat_minor": 0,


+ "worksheets": [


+  {


+   "cells": [


+    {


+     "cell_type": "heading",


+     "level": 1,


+     "metadata": {},


+     "source": [


+      "Chapter 01:Introduction"


+     ]


+    },


+    {


+     "cell_type": "heading",


+     "level": 2,


+     "metadata": {},


+     "source": [


+      "Ex1.1:pg-20"


+     ]


+    },


+    {


+     "cell_type": "code",


+     "collapsed": false,


+     "input": [


+      "# Given Data\n",


+      "d_r = 13640 # Density of mercury in kg/m^3\n",


+      "g = 9.79 # Acceleration due to gravity in m/s^2\n",


+      "z = 562e-03 # Difference in height in m\n",


+      "z0 = 761e-03 # Reading of barometer in m\n",


+      "P = (d_r*g*(z+z0))*(0.987/1e05) # Gas Pressure in atm\n",


+      "\n",


+      "print \"\\n Example 1.1\\n\"\n",


+      "print \"\\n Gas Pressure is \",round(P,2),\" atm\"\n",


+      "#The answers vary due to round off error\n"


+     ],


+     "language": "python",


+     "metadata": {},


+     "outputs": [


+      {


+       "output_type": "stream",


+       "stream": "stdout",


+       "text": [


+        "\n",


+        " Example 1.1\n",


+        "\n",


+        "\n",


+        " Gas Pressure is  1.74  atm\n"


+       ]


+      }


+     ],


+     "prompt_number": 3


+    },


+    {


+     "cell_type": "heading",


+     "level": 2,


+     "metadata": {},


+     "source": [


+      "Ex1.2:pg-21"


+     ]


+    },


+    {


+     "cell_type": "code",


+     "collapsed": false,


+     "input": [


+      "#Given Data\n",


+      "d_r = 13.6e03 # Density of mercury in kg/m^3\n",


+      "g = 9.81 # Acceleration due to gravity in m/s^2\n",


+      "z = 710e-03 # Steam flow pressure in m\n",


+      "z0 = 772e-03 # Reading of barometer in m\n",


+      "P = 1.4e06 # Gauge pressure of applied steam in Pa\n",


+      "P0 = d_r*g*z0 # Atmospheric pressure in Pa\n",


+      "Pi = P+P0  # Inlet steam pressure in Pa\n",


+      "Pc = d_r*g*(z0-z) # Condenser pressure in Pa\n",


+      "\n",


+      "print \"\\n Example 1.2\\n\"\n",


+      "print \"\\n Inlet steam pressure is\",round(Pi/1e6,2),\" MPa\"\n",


+      "print \"\\n Condenser pressure is\",round(Pc/1e3,2),\" kPa\"\n",


+      "#The answers vary due to round off error\n",


+      "\n",


+      "\n",


+      "\n"


+     ],


+     "language": "python",


+     "metadata": {},


+     "outputs": [


+      {


+       "output_type": "stream",


+       "stream": "stdout",


+       "text": [


+        "\n",


+        " Example 1.2\n",


+        "\n",


+        "\n",


+        " Inlet steam pressure is 1.5  MPa\n",


+        "\n",


+        " Condenser pressure is 8.27  kPa\n"


+       ]


+      }


+     ],


+     "prompt_number": 5


+    }


+   ],


+   "metadata": {}


+  }


+ ]


+}
\ No newline at end of file
diff --git a/f_by_df/screenshots/anshul.png b/f_by_df/screenshots/anshul.png
new file mode 100644
index 00000000..a8cec645
--- /dev/null
+++ b/f_by_df/screenshots/anshul.png
diff --git a/f_by_df/screenshots/blank1.png b/f_by_df/screenshots/blank1.png
new file mode 100644
index 00000000..e69de29b
--- /dev/null
+++ b/f_by_df/screenshots/blank1.png
diff --git a/f_by_df/screenshots/blog.png b/f_by_df/screenshots/blog.png
new file mode 100644
index 00000000..57995442
--- /dev/null
+++ b/f_by_df/screenshots/blog.png
diff --git a/f_by_df/screenshots/sai.png b/f_by_df/screenshots/sai.png
new file mode 100644
index 00000000..744dca5f
--- /dev/null
+++ b/f_by_df/screenshots/sai.png
diff --git a/f_by_df/screenshots/snippet1.png b/f_by_df/screenshots/snippet1.png
new file mode 100644
index 00000000..3dc79b8d
--- /dev/null
+++ b/f_by_df/screenshots/snippet1.png
diff --git a/f_by_df/screenshots/srinivas.png b/f_by_df/screenshots/srinivas.png
new file mode 100644
index 00000000..e947b0fb
--- /dev/null
+++ b/f_by_df/screenshots/srinivas.png
diff --git a/hfgd_by_Gayakwad/README.txt b/hfgd_by_Gayakwad/README.txt
new file mode 100644
index 00000000..55aba71c
--- /dev/null
+++ b/hfgd_by_Gayakwad/README.txt
@@ -0,0 +1,10 @@
+Contributed By: Jeevan Lal
+Course: me
+College/Institute/Organization: MPBtech. ECE, 6th SemVNIT Nagpur
+Department/Designation: MPBtech. ECE, 6th SemVNIT Nagpur
+Book Title: hfgd
+Author: Gayakwad
+Publisher: sdf
+Year of publication: 2001
+Isbn: 444
+Edition: 9
\ No newline at end of file
diff --git a/hfgd_by_Gayakwad/abhishek.ipynb b/hfgd_by_Gayakwad/abhishek.ipynb
new file mode 100644
index 00000000..3f7271ea
--- /dev/null
+++ b/hfgd_by_Gayakwad/abhishek.ipynb
@@ -0,0 +1,112 @@
+{


+ "metadata": {


+  "name": "",


+  "signature": "sha256:cda4775b9259e49c042e3120b0a25eb239766f3373696622080f812fe1f53fa9"


+ },


+ "nbformat": 3,


+ "nbformat_minor": 0,


+ "worksheets": [


+  {


+   "cells": [


+    {


+     "cell_type": "heading",


+     "level": 1,


+     "metadata": {},


+     "source": [


+      "Chapter 01:Introduction"


+     ]


+    },


+    {


+     "cell_type": "heading",


+     "level": 2,


+     "metadata": {},


+     "source": [


+      "Ex1.1:pg-20"


+     ]


+    },


+    {


+     "cell_type": "code",


+     "collapsed": false,


+     "input": [


+      "# Given Data\n",


+      "d_r = 13640 # Density of mercury in kg/m^3\n",


+      "g = 9.79 # Acceleration due to gravity in m/s^2\n",


+      "z = 562e-03 # Difference in height in m\n",


+      "z0 = 761e-03 # Reading of barometer in m\n",


+      "P = (d_r*g*(z+z0))*(0.987/1e05) # Gas Pressure in atm\n",


+      "\n",


+      "print \"\\n Example 1.1\\n\"\n",


+      "print \"\\n Gas Pressure is \",round(P,2),\" atm\"\n",


+      "#The answers vary due to round off error\n"


+     ],


+     "language": "python",


+     "metadata": {},


+     "outputs": [


+      {


+       "output_type": "stream",


+       "stream": "stdout",


+       "text": [


+        "\n",


+        " Example 1.1\n",


+        "\n",


+        "\n",


+        " Gas Pressure is  1.74  atm\n"


+       ]


+      }


+     ],


+     "prompt_number": 3


+    },


+    {


+     "cell_type": "heading",


+     "level": 2,


+     "metadata": {},


+     "source": [


+      "Ex1.2:pg-21"


+     ]


+    },


+    {


+     "cell_type": "code",


+     "collapsed": false,


+     "input": [


+      "#Given Data\n",


+      "d_r = 13.6e03 # Density of mercury in kg/m^3\n",


+      "g = 9.81 # Acceleration due to gravity in m/s^2\n",


+      "z = 710e-03 # Steam flow pressure in m\n",


+      "z0 = 772e-03 # Reading of barometer in m\n",


+      "P = 1.4e06 # Gauge pressure of applied steam in Pa\n",


+      "P0 = d_r*g*z0 # Atmospheric pressure in Pa\n",


+      "Pi = P+P0  # Inlet steam pressure in Pa\n",


+      "Pc = d_r*g*(z0-z) # Condenser pressure in Pa\n",


+      "\n",


+      "print \"\\n Example 1.2\\n\"\n",


+      "print \"\\n Inlet steam pressure is\",round(Pi/1e6,2),\" MPa\"\n",


+      "print \"\\n Condenser pressure is\",round(Pc/1e3,2),\" kPa\"\n",


+      "#The answers vary due to round off error\n",


+      "\n",


+      "\n",


+      "\n"


+     ],


+     "language": "python",


+     "metadata": {},


+     "outputs": [


+      {


+       "output_type": "stream",


+       "stream": "stdout",


+       "text": [


+        "\n",


+        " Example 1.2\n",


+        "\n",


+        "\n",


+        " Inlet steam pressure is 1.5  MPa\n",


+        "\n",


+        " Condenser pressure is 8.27  kPa\n"


+       ]


+      }


+     ],


+     "prompt_number": 5


+    }


+   ],


+   "metadata": {}


+  }


+ ]


+}
\ No newline at end of file
diff --git a/hfgd_by_Gayakwad/screenshots/anshul.png b/hfgd_by_Gayakwad/screenshots/anshul.png
new file mode 100644
index 00000000..a8cec645
--- /dev/null
+++ b/hfgd_by_Gayakwad/screenshots/anshul.png
diff --git a/hfgd_by_Gayakwad/screenshots/anshul_1.png b/hfgd_by_Gayakwad/screenshots/anshul_1.png
new file mode 100644
index 00000000..a8cec645
--- /dev/null
+++ b/hfgd_by_Gayakwad/screenshots/anshul_1.png
diff --git a/hfgd_by_Gayakwad/screenshots/anshul_2.png b/hfgd_by_Gayakwad/screenshots/anshul_2.png
new file mode 100644
index 00000000..a8cec645
--- /dev/null
+++ b/hfgd_by_Gayakwad/screenshots/anshul_2.png
diff --git a/rewrew_by_J._B._Gupta/README.txt b/rewrew_by_J._B._Gupta/README.txt
new file mode 100644
index 00000000..897785b9
--- /dev/null
+++ b/rewrew_by_J._B._Gupta/README.txt
@@ -0,0 +1,10 @@
+Contributed By: Jeevan Lal
+Course: me
+College/Institute/Organization: MPBtech. ECE, 6th SemVNIT Nagpur
+Department/Designation: MPBtech. ECE, 6th SemVNIT Nagpur
+Book Title: rewrew
+Author: J. B. Gupta
+Publisher: sdf
+Year of publication: 1
+Isbn: 2
+Edition: 9
\ No newline at end of file
diff --git a/rewrew_by_J._B._Gupta/aviral.ipynb b/rewrew_by_J._B._Gupta/aviral.ipynb
new file mode 100644
index 00000000..5780e6b5
--- /dev/null
+++ b/rewrew_by_J._B._Gupta/aviral.ipynb
@@ -0,0 +1,146 @@
+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Chapter 5:INTRODUCTION TO THERMAL POWER PLANT"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex5.1:pg-271"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 4,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "\n",
+      "The coal required per hour,W= 50.95  tons/hr\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Example 5_1\n",
+    " \n",
+    "# Given data\n",
+    "P=100.0;# Plant capacity in Mw\n",
+    "CV=25600.0;# Calorific value in kJ/kg\n",
+    "n_th=30.0;# The thermal efficiency of the plant in %\n",
+    "n_eg=92.0;# Electrical generation efficiency in %\n",
+    "\n",
+    "# Calculation\n",
+    "# Mechanical energy available=W*CV*(n_th/100) in kJ/hr\n",
+    "# Electrical energy available=W*CV*(n_th/100)*(n_eg/100) in kJ/hr\n",
+    "q_e=P*10**3*3600;# Heat equivalent in kJ/hr\n",
+    "W=(q_e/(CV*(n_th/100)*(n_eg/100)));# The coal required per hour in kg/hr\n",
+    "W=(W/1000);# The coal required per hour in tons/hr\n",
+    "print \"\\nThe coal required per hour,W=\",round(W,2),\" tons/hr\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex5.2:pg-273"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 5,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "\n",
+      " The capacity of the power plant,P= 62.05  MW\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Example 5_2\n",
+    " \n",
+    "# Given data\n",
+    "CV=28900.0;#kJ/kg\n",
+    "n_b=83.0;# The boiler efficiency in %\n",
+    "n_t=32.0;# The turbine efficiency in %\n",
+    "n_g=97.0;# The generator efficiency in %\n",
+    "W=30.0;# The coal consumption of the station in tons/hr\n",
+    "\n",
+    "# Calculation\n",
+    "P=((W*1000*CV)*(n_b/100)*(n_t/100)*(n_g/100))/(3600*1000);# The capacity of the power plant in MW\n",
+    "print \"\\n The capacity of the power plant,P=\",round(P,2),\" MW\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex5.3:pg-273"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 8,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The volume of gas required per hour,V= 450.0  m**3/hr\n"
+     ]
+    }
+   ],
+   "source": [
+    "#Example 5_3\n",
+    "\n",
+    "# Given values\n",
+    "P=100.0;# Power in kW\n",
+    "CV=4000.0;# Calorific value in kJ/m**3\n",
+    "n_o=0.20;# Over all efficiency of the plant\n",
+    "\n",
+    "# Calculation\n",
+    "V=(3600*P)/(CV*n_o);# m**3/hr\n",
+    "print \"The volume of gas required per hour,V=\",round(V,2),\" m**3/hr\"\n"
+   ]
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python 2",
+   "language": "python",
+   "name": "python2"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 2
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython2",
+   "version": "2.7.11"
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}
diff --git a/rewrew_by_J._B._Gupta/screenshots/array_factor.png b/rewrew_by_J._B._Gupta/screenshots/array_factor.png
new file mode 100644
index 00000000..9e294010
--- /dev/null
+++ b/rewrew_by_J._B._Gupta/screenshots/array_factor.png
diff --git a/rewrew_by_J._B._Gupta/screenshots/book.png b/rewrew_by_J._B._Gupta/screenshots/book.png
new file mode 100644
index 00000000..824a4542
--- /dev/null
+++ b/rewrew_by_J._B._Gupta/screenshots/book.png
diff --git a/rewrew_by_J._B._Gupta/screenshots/error.png b/rewrew_by_J._B._Gupta/screenshots/error.png
new file mode 100644
index 00000000..04a3d5f0
--- /dev/null
+++ b/rewrew_by_J._B._Gupta/screenshots/error.png
diff --git a/sample_notebooks/JeevanLal/aditya.ipynb b/sample_notebooks/JeevanLal/aditya.ipynb
new file mode 100644
index 00000000..a77ec491
--- /dev/null
+++ b/sample_notebooks/JeevanLal/aditya.ipynb
@@ -0,0 +1,279 @@
+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Chapter 5 General Case of Forces in a plane"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {
+    "collapsed": true
+   },
+   "source": [
+    "# Example 5.2 Equations of equilibrium"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 7,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "('The reaction at P is', 5656.85424949238, 'N')\n",
+      "('The reaction at Q is ', 4000.0, 'N')\n"
+     ]
+    }
+   ],
+   "source": [
+    "import math\n",
+    "\n",
+    "#Initialization of Variables\n",
+    "W=2000 #N\n",
+    "Lab=2 #m #length of the member from the vertical to the 1st load of 2000 N\n",
+    "Lac=5 #m #length of the member from the vertical to the 2nd load of 2000 N\n",
+    "Lpq=3.5 #m\n",
+    "\n",
+    "#Calculations\n",
+    "Rq=((W*Lab)+(W*Lac))/Lpq #N #take moment abt. pt P\n",
+    "Xp=Rq #N #sum Fx=0\n",
+    "Yp=2*W #N #sum Fy=0\n",
+    "Rp=math.sqrt(Xp**2+Yp**2) #N\n",
+    "\n",
+    "#Resuts\n",
+    "print('The reaction at P is' ,Rp ,'N')\n",
+    "print('The reaction at Q is ',Rq ,'N')"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {
+    "collapsed": true
+   },
+   "source": [
+    "# Example 5.3 Equations of equilibrium"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 6,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "('The reaction at A i.e Ra is ', matrix([[ 120.27406887]]), 'N')\n",
+      "('The reaction at B i.e Rb is ', matrix([[ 35.13703443]]), 'N')\n",
+      "('The required tension in the string is ', matrix([[ 40.57275258]]), 'N')\n"
+     ]
+    }
+   ],
+   "source": [
+    "import math,numpy\n",
+    "#Initilization of vaiables\n",
+    "W=25 #N # self weight of the ladder\n",
+    "M=75 #N # weight of the man standing o the ladder\n",
+    "theta=63.43 #degree # angle which the ladder makes with the horizontal\n",
+    "alpha=30 #degree # angle made by the string with the horizontal\n",
+    "Loa=2 #m # spacing between the wall and the ladder\n",
+    "Lob=4 #m #length from the horizontal to the top of the ladder touching the wall(vertical)\n",
+    "\n",
+    "#Calculations\n",
+    "#Using matrix to solve the simultaneous eqn's 3 & 4\n",
+    "A=numpy.matrix('2 -4; 1 -0.577')\n",
+    "B=numpy.matrix('100;100')\n",
+    "C=numpy.linalg.inv(A)*B\n",
+    "\n",
+    "#Results\n",
+    "print('The reaction at A i.e Ra is ',C[0] ,'N')\n",
+    "print('The reaction at B i.e Rb is ',C[1] ,'N')\n",
+    "\n",
+    "#Calculations\n",
+    "T=C[1]/math.cos(math.radians(alpha)) #N # from (eqn 1)\n",
+    "\n",
+    "#Results\n",
+    "print('The required tension in the string is ',T, 'N')"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {
+    "collapsed": true
+   },
+   "source": [
+    "# Example 5.4 Equations of Equilibrium"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 4,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "('The reaction at B i.e Rb is ', 25.0, 'N')\n",
+      "('The horizontal reaction at A i.e Xa is ', 21.650635094610966, 'N')\n",
+      "('The vertical reaction at A i.e Ya is ', 112.5, 'N')\n"
+     ]
+    }
+   ],
+   "source": [
+    "import math\n",
+    "#Initilization of variables\n",
+    "W=100 #N\n",
+    "theta=60 #degree angle made by the ladder with the horizontal\n",
+    "alpha=30 #degree angle made by the ladder with the vertical wall\n",
+    "Lob=4 #m  length from the horizontal to the top of the ladder touching the wall(vertical)\n",
+    "Lcd=2 #m  length from the horizontal to the centre of the ladder where the man stands\n",
+    "\n",
+    "#Calculations\n",
+    "Lab=Lob*(1/math.cos(math.radians(alpha))) #m length of the ladder\n",
+    "Lad=Lcd*math.tan(math.radians(alpha)) #m\n",
+    "Rb=(W*Lad)/Lab #N take moment at A\n",
+    "Xa=Rb*math.sin(math.radians(theta)) #N  From eq'n 1\n",
+    "Ya=W+Rb*math.cos(math.radians(theta)) #N From eq'n 2\n",
+    "\n",
+    "#Results\n",
+    "print('The reaction at B i.e Rb is ',Rb, 'N')\n",
+    "print('The horizontal reaction at A i.e Xa is ',Xa, 'N')\n",
+    "print('The vertical reaction at A i.e Ya is ',Ya,'N')\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {
+    "collapsed": true
+   },
+   "source": [
+    "# Example 5.5 Equations of Equilibrium"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 3,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "('The horizontal reaction at A i.e Xa is ', 28.867513459481287, 'N')\n",
+      "('The vertical reaction at A i.e Ya is ', 100, 'N')\n",
+      "('The reaction at B i.e Rb is ', 28.867513459481287, 'N')\n"
+     ]
+    }
+   ],
+   "source": [
+    "import math\n",
+    "#Initilization of variables\n",
+    "W=100 #N self weight of the man\n",
+    "alpha=30 #degree angle made by the ladder with the wall\n",
+    "Lob=4 #m  length from the horizontal to the top of the ladder touching the wall(vertical)\n",
+    "Lcd=2 #m\n",
+    "\n",
+    "#Calculations\n",
+    "# using the equiblirium equations\n",
+    "Ya=W #N  From eq'n 2\n",
+    "Lad=Lcd*math.tan(math.radians(alpha)) #m Lad is the distance fom pt A to the point where the line from the cg intersects the horizontal\n",
+    "Rb=(W*Lad)/Lob #N  Taking sum of moment abt A\n",
+    "Xa=Rb #N From eq'n 1\n",
+    "\n",
+    "#Results\n",
+    "print('The horizontal reaction at A i.e Xa is ',Xa, 'N')\n",
+    "print('The vertical reaction at A i.e Ya is ',Ya,'N' )\n",
+    "print('The reaction at B i.e Rb is ',Rb ,'N')\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {
+    "collapsed": true
+   },
+   "source": [
+    "# Example 5.6 Equations of Equilibrium"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 2,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "('The horizontal reaction at A i.e Xa is ', 3.84, 'N')\n",
+      "('The vertical reaction at A i.e Ya is ', 7.12, 'N')\n",
+      "('Therefore the reaction at A i.e Ra is ', 8.089499366462674, 'N')\n",
+      "('The reaction at D i.e Rd is ', 4.8, 'N')\n"
+     ]
+    }
+   ],
+   "source": [
+    "import math\n",
+    "#Initilization of variables\n",
+    "d=0.09 #m diametre of the right circular cylinder\n",
+    "h=0.12 #m height of the cyinder\n",
+    "W=10 #N  self weight of the bar\n",
+    "l=0.24 #m length of the bar\n",
+    "\n",
+    "#Calculations\n",
+    "theta=math.degrees(math.atan(h/d))  #angle which the bar makes with the horizontal\n",
+    "Lad=math.sqrt(d**2+h**2) #m Lad is the length of the bar from point A to point B\n",
+    "Rd=(W*h*(math.cos(theta*math.pi/180)))/Lad #N  Taking moment at A\n",
+    "Xa=Rd*(math.sin(theta*math.pi/180)) #N  sum Fx=0.... From eq'n 1\n",
+    "Ya=W-(Rd*(math.cos(theta*math.pi/180))) #N  sum Fy=0..... From eq'n 2\n",
+    "Ra=math.sqrt(Xa**2+Ya**2) #resultant of Xa & Ya\n",
+    "\n",
+    "#Results\n",
+    "print('The horizontal reaction at A i.e Xa is ',Xa, 'N')\n",
+    "print('The vertical reaction at A i.e Ya is ',Ya, 'N')\n",
+    "print('Therefore the reaction at A i.e Ra is ',Ra,'N')\n",
+    "print('The reaction at D i.e Rd is ',Rd,'N')"
+   ]
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python [Root]",
+   "language": "python",
+   "name": "Python [Root]"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 2
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython2",
+   "version": "2.7.12"
+  },
+  "widgets": {
+   "state": {},
+   "version": "1.1.2"
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+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}