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diff --git a/code/linprog/AirforceBombDuality.sce b/code/linprog/AirforceBombDuality.sce
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+//Reference: J.K. Sharma,"OPerations Research Theory and Applications", Macmillan Publishers India Ltd., 5th edition, 2013, Chapter 4.
+
+//An Air Force is experimenting with three types of bombs P,Q and R in which three kinds of explosives, viz., A, B and C will be used. Taking the various factors into account, it has been decided to use the maximum 600 kg of explosive A, at least 480 kg of B and exactly 540 kg of explosive C. Bomb P requires 3,2,2 kg, bomb Q requires 1,4,3 kg and bomb R requires 4,2,3 kg of explosives A,B and C respectively. Bomb P is estimated to give the equivalent of a 2 ton explosion, bomb Q, a 3 ton of explosion and bomb R, a 4 ton of explosion respectively. Under what production schedule can the Air Force make the biggest bang?
+//=============================================================================
+// Copyright (C) 2018 - IIT Bombay - FOSSEE
+// This file must be used under the terms of the CeCILL.
+// This source file is licensed as described in the file COPYING, which
+// you should have received as part of this distribution.  The terms
+// are also available at
+// http://www.cecill.info/licences/Licence_CeCILL_V2-en.txt
+// Author: Remya Kommadath
+// Organization: FOSSEE, IIT Bombay
+// Email: toolbox@scilab.in
+//============================================================================
+
+clc; 
+// =============================Primal Model===================================
+nVar = 3;
+
+// Linear inequalities
+A = [3 1 4; -2 -4 -2];
+b = [600 -480]';
+nIneqCon = length(b);
+
+// Linear equality
+Aeq = [2 3 3];
+beq = 540;
+nEqCon = length(beq);
+
+lb = zeros(1,nVar);
+ub = [];
+
+Cost = -[2 3 4 ]';
+
+// =============================Dual Model===================================
+
+// Inequality constraints
+dual_A =  -[A;Aeq]';
+dual_beq = Cost;
+n_dualIneq = length(dual_beq);
+Coeff_Slack = [eye(n_dualIneq,n_dualIneq);];
+dual_Aeq = [dual_A Coeff_Slack];
+dual_Cost = [b;beq; zeros(n_dualIneq,1)];
+
+dual_nVar = length(dual_Cost);
+lb = [zeros(1,nIneqCon) -%inf*ones(nEqCon) zeros(1,(dual_nVar-nIneqCon-nEqCon))];
+ub = [];
+
+[xopt,fopt,exitflag,output,lambda]=linprog(dual_Cost, [],[], dual_Aeq, dual_beq, lb,ub);
+clc
+
+select exitflag
+case 0
+    disp(xopt(1:nIneqCon+nEqCon)',"Dual values of the primal constraints")
+    disp(xopt(nIneqCon+nEqCon+1:dual_nVar)',"Dual values of the primal variables")
+    TopRow = ["Variable     "  "Rate of change in optima"];
+    Table = string([(1:length(xopt))' -xopt]);
+    disp("The change in optima due to one unit increase in each variables are given as below")
+    disp([TopRow;Table])
+    disp(["The optimal cost is ", string(fopt)])
+case 1
+    disp("Primal Infeasible")
+case 2
+    disp("Dual Infeasible")
+case 3
+    disp("Maximum Number of Iterations Exceeded. Output may not be optimal")
+case 4
+    disp("Solution Abandoned")
+case 5
+    disp("Primal objective limit reached")
+case 6
+    disp("Dual objective limit reached")
+end