added code files

1 files changed, 95 insertions, 0 deletions

diff --git a/code/fmincon/Tankprob.sci b/code/fmincon/Tankprob.sci
new file mode 100644
index 0000000..500090e
--- /dev/null
+++ b/code/fmincon/Tankprob.sci
@@ -0,0 +1,95 @@
+//Design a circular tank, closed at both ends, with a volume of 200 m3.The cost is proportional to the surface area of material, which is priced
+//at $400/m2. The tank is contained within a shed with a sloping roof,thus the height of the tank h is limited by h ≤ 12 − d/2, where d is
+//the tank diameter. Formulate the minimum cost problem and solve the design problem.
+//Ref:Diwekar, Urmila,Introduction to Applied Optimization, Introduction to Applied Optimization, Editor:Ding-Zhu Du, Springer Optimization and Its Applications Springer Optimization and Its Applications, VOL 22, Chapter 3
+
+// Copyright (C) 2018 - IIT Bombay - FOSSEE
+// This file must be used under the terms of the CeCILL.
+// This source file is licensed as described in the file COPYING, which
+// you should have received as part of this distribution.  The terms
+// are also available at
+// http://www.cecill.info/licences/Licence_CeCILL_V2-en.txt
+// Author:Debasis Maharana
+// Organization: FOSSEE, IIT Bombay
+// Email: toolbox@scilab.in
+//======================================================================
+
+clc;
+
+function cost = Tankprob(x)
+    r = x(1);h = x(2);
+    cost = (2*%pi*r*h+2*%pi*r^2)*400;
+endfunction
+
+function [ceq,c] = Nonlinearcon(x)
+    r = x(1);h = x(2);
+    c = [];
+    ceq = 200-%pi*r^2*h;
+endfunction
+
+function y=Gradobj(x)
+    y= [800*%pi*x(2) + 1600*%pi*x(1),800*%pi*x(1)];
+endfunction
+
+mprintf('\nDesign a circular tank, closed at both ends, with a volume of 200 m3 with minimum cost.\n The tank is contained within a shed with a sloping roof,thus the height of the tank h is limited')
+mprintf('\nCost of material is: %f',400);
+mprintf('The design variables are radius and height of the tank')
+
+A = [1 1];b = 12;
+
+x0 = input('Enter initial guess as vector:');
+if  (sum(x0<=0) | (length(x0)~=2))
+    x0 = [1 2];
+    mprintf('Incorrect initial guess...\n changing initial guess to r = %d and h = %d',x0(1),x0(2));
+end
+
+
+lb = [0 0];
+input('press enter to continue')
+options=list("MaxIter",1000,"GradObj", Gradobj);
+
+[xopt,fopt,exitflag,output1] = fmincon(Tankprob,x0,A,b,[],[],lb,[],Nonlinearcon,options);
+
+[xopt1,fopt1,exitflag1,output2] = fmincon(Tankprob,x0,A,b,[],[],lb,[],Nonlinearcon);
+
+clc
+select exitflag
+case 0
+    mprintf('Optimal Solution Found');
+    mprintf('\nThe optimal radius and height of the tank are %f m and %f m',xopt(1),xopt(2));
+    mprintf('\nThe volume of the tank is %f m^3',%pi*xopt(1)^2*xopt(2));
+    mprintf('\nThe total surface area and cost of the tank are %f m^2 and %f $',fopt/400,fopt)
+    mprintf('\nTime taken to solve the problem with gradient information is %f s and without gradient information is %f s',output1.Cpu_Time,output2.Cpu_Time);
+case 1
+    mprintf('Maximum Number of Iterations Exceeded. Output may not be optimal');
+    input('press enter to view results');
+    printf('\nThe optimal radius and height of the tank are %f m and %f m',xopt(1),xopt(2));
+    mprintf('\nThe volume of the tank is %f m^3',%pi*xopt(1)^2*xopt(2));
+    mprintf('\nThe total surface area and cost of the tank are %f m^2 and %f $',fopt/400,fopt)
+case 2
+    mprintf('Maximum amount of CPU Time exceeded. Output may not be optimal.');
+    input('press enter to view results');
+    printf('\nThe optimal radius and height of the tank are %f m and %f m',xopt(1),xopt(2));
+    mprintf('\nThe volume of the tank is %f m^3',%pi*xopt(1)^2*xopt(2));
+    mprintf('\nThe total surface area and cost of the tank are %f m^2 and %f $',fopt/400,fopt)
+case 3
+    mprintf('Stop at Tiny Step');
+    input('press enter to view results');
+    printf('\nThe optimal radius and height of the tank are %f m and %f m',xopt(1),xopt(2));
+    mprintf('\nThe volume of the tank is %f m^3',%pi*xopt(1)^2*xopt(2));
+    mprintf('\nThe total surface area and cost of the tank are %f m^2 and %f $',fopt/400,fopt)
+case 4
+    mprintf('Solved To Acceptable Level');
+    input('press enter to view results');
+    printf('\nThe optimal radius and height of the tank are %f m and %f m',xopt(1),xopt(2));
+    mprintf('\nThe volume of the tank is %f m^3',%pi*xopt(1)^2*xopt(2));
+    mprintf('\nThe total surface area and cost of the tank are %f m^2 and %f $',fopt/400,fopt)
+case 5
+    mprintf('Converged to a point of local infeasibility.');
+    input('press enter to view results');
+    printf('\nThe optimal radius and height of the tank are %f m and %f m',xopt(1),xopt(2));
+    mprintf('\nThe volume of the tank is %f m^3',%pi*xopt(1)^2*xopt(2));
+    mprintf('\nThe total surface area and cost of the tank are %f m^2 and %f $',fopt/400,fopt)
+end
+
+