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// Check for the infeasible problem
C = [0.9501 0.7620 0.6153 0.4057
0.2311 0.4564 0.7919 0.9354
0.6068 0.0185 0.9218 0.9169
0.4859 0.8214 0.7382 0.4102
0.8912 0.4447 0.1762 0.8936];
d = [0.0578
0.3528
0.8131
0.0098
0.1388];
Aeq = [-1 0 0 0; 0 -1 0 0; 1 1 0 0 ];
beq = [-6 -6 11];
//Converged to a point of local infeasibility.
// lambda =
//
// lower: [0x0 constant]
// upper: [0x0 constant]
// eqlin: [0x0 constant]
// ineqlin: [0x0 constant]
// output =
//
// Iterations: 0
// exitflag =
//
// 5
// residual =
//
// 0.0578
// 0.3528
// 0.8131
// 0.0098
// 0.1388
// resnorm =
//
// 0.8083018
// xopt =
//
// []
[xopt,resnorm,residual,exitflag,output,lambda] = lsqlin(C,d,[],[],Aeq,beq)
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