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// Copyright (C) 2015 - IIT Bombay - FOSSEE
//
// Author: Harpreet Singh
// Organization: FOSSEE, IIT Bombay
// Email: harpreet.mertia@gmail.com
// This file must be used under the terms of the CeCILL.
// This source file is licensed as described in the file COPYING, which
// you should have received as part of this distribution. The terms
// are also available at
// http://www.cecill.info/licences/Licence_CeCILL_V2-en.txt
function [xopt,fopt,exitflag,output,lambda] = qpipopt (varargin)
// Solves a linear quadratic problem.
//
// Calling Sequence
// xopt = qpipopt(nbVar,nbCon,Q,p,LB,UB,conMatrix,conLB,conUB)
// xopt = qpipopt(nbVar,nbCon,Q,p,LB,UB,conMatrix,conLB,conUB,x0)
// xopt = qpipopt(nbVar,nbCon,Q,p,LB,UB,conMatrix,conLB,conUB,x0,param)
// [xopt,fopt,exitflag,output,lamda] = qpipopt( ... )
//
// Parameters
// nbVar : a double, number of variables
// nbCon : a double, number of constraints
// Q : a symmetric matrix of doubles, represents coefficients of quadratic in the quadratic problem.
// p : a vector of doubles, represents coefficients of linear in the quadratic problem
// LB : a vector of doubles, contains lower bounds of the variables.
// UB : a vector of doubles, contains upper bounds of the variables.
// conMatrix : a matrix of doubles, contains matrix representing the constraint matrix
// conLB : a vector of doubles, contains lower bounds of the constraints.
// conUB : a vector of doubles, contains upper bounds of the constraints.
// x0 : a vector of doubles, contains initial guess of variables.
// param : a list containing the the parameters to be set.
// xopt : a vector of doubles, the computed solution of the optimization problem.
// fopt : a double, the function value at x.
// exitflag : Integer identifying the reason the algorithm terminated.
// output : Structure containing information about the optimization. Right now it contains number of iteration.
// lambda : Structure containing the Lagrange multipliers at the solution x (separated by constraint type).It contains lower, upper and linear equality, inequality constraints.
//
// Description
// Search the minimum of a constrained linear quadratic optimization problem specified by :
// find the minimum of f(x) such that
//
// <latex>
// \begin{eqnarray}
// &\mbox{min}_{x}
// & 1/2*x'*Q*x + p'*x \\
// & \text{subject to} & conLB \leq C(x) \leq conUB \\
// & & lb \leq x \leq ub \\
// \end{eqnarray}
// </latex>
//
// We are calling IPOpt for solving the quadratic problem, IPOpt is a library written in C++.
//
// Examples
// //Find x in R^6 such that:
// conMatrix= [1,-1,1,0,3,1;
// -1,0,-3,-4,5,6;
// 2,5,3,0,1,0
// 0,1,0,1,2,-1;
// -1,0,2,1,1,0];
// conLB=[1;2;3;-%inf;-%inf];
// conUB = [1;2;3;-1;2.5];
// lb=[-1000;-10000; 0; -1000; -1000; -1000];
// ub=[10000; 100; 1.5; 100; 100; 1000];
// //and minimize 0.5*x'*Q*x + p'*x with
// p=[1; 2; 3; 4; 5; 6]; Q=eye(6,6);
// nbVar = 6;
// nbCon = 5;
// x0 = repmat(0,nbVar,1);
// param = list("MaxIter", 300, "CpuTime", 100);
// [xopt,fopt,exitflag,output,lambda]=qpipopt(nbVar,nbCon,Q,p,lb,ub,conMatrix,conLB,conUB,x0,param)
// // Press ENTER to continue
//
// Examples
// //Find the value of x that minimize following function
// // f(x) = 0.5*x1^2 + x2^2 - x1*x2 - 2*x1 - 6*x2
// // Subject to:
// // x1 + x2 ≤ 2
// // –x1 + 2x2 ≤ 2
// // 2x1 + x2 ≤ 3
// // 0 ≤ x1, 0 ≤ x2.
// Q = [1 -1; -1 2];
// p = [-2; -6];
// conMatrix = [1 1; -1 2; 2 1];
// conUB = [2; 2; 3];
// conLB = [-%inf; -%inf; -%inf];
// lb = [0; 0];
// ub = [%inf; %inf];
// nbVar = 2;
// nbCon = 3;
// [xopt,fopt,exitflag,output,lambda] = qpipopt(nbVar,nbCon,Q,p,lb,ub,conMatrix,conLB,conUB)
// Authors
// Keyur Joshi, Saikiran, Iswarya, Harpreet Singh
//To check the number of input and output argument
[lhs , rhs] = argn();
//To check the number of argument given by user
if ( rhs < 9 | rhs > 11 ) then
errmsg = msprintf(gettext("%s: Unexpected number of input arguments : %d provided while should be 9, 10 or 11"), "qpipopt", rhs);
error(errmsg)
end
nbVar = varargin(1);
nbCon = varargin(2);
Q = varargin(3);
p = varargin(4);
LB = varargin(5);
UB = varargin(6);
conMatrix = varargin(7);
conLB = varargin(8);
conUB = varargin(9);
if (size(LB,2)==0) then
LB = repmat(-%inf,nbVar,1);
end
if (size(UB,2)==0) then
UB = repmat(%inf,nbVar,1);
end
if (size(p,2)==0) then
p = repmat(0,nbVar,1);
end
if ( rhs<10 | size(varargin(10)) ==0 ) then
x0 = repmat(0,nbVar,1);
else
x0 = varargin(10);
end
if ( rhs<11 | size(varargin(11)) ==0 ) then
param = list();
else
param =varargin(11);
end
if (type(param) ~= 15) then
errmsg = msprintf(gettext("%s: param should be a list "), "qpipopt");
error(errmsg);
end
if (modulo(size(param),2)) then
errmsg = msprintf(gettext("%s: Size of parameters should be even"), "qpipopt");
error(errmsg);
end
options = list(..
"MaxIter" , [3000], ...
"CpuTime" , [600] ...
);
for i = 1:(size(param))/2
select param(2*i-1)
case "MaxIter" then
options(2*i) = param(2*i);
case "CpuTime" then
options(2*i) = param(2*i);
else
errmsg = msprintf(gettext("%s: Unrecognized parameter name ''%s''."), "qpipopt", param(2*i-1));
error(errmsg)
end
end
// Check if the user gives row vector
// and Changing it to a column matrix
if (size(p,2)== [nbVar]) then
p=p';
end
if (size(LB,2)== [nbVar]) then
LB = LB';
end
if (size(UB,2)== [nbVar]) then
UB = UB';
end
if (size(conUB,2)== [nbCon]) then
conUB = conUB';
end
if (size(conLB,2)== [nbCon]) then
conLB = conLB';
end
if (size(x0,2)== [nbVar]) then
x0=x0';
end
//IPOpt wants it in row matrix form
p = p';
LB = LB';
UB = UB';
conLB = conLB';
conUB = conUB';
x0 = x0';
//Checking the Q matrix which needs to be a symmetric matrix
if ( ~isequal(Q,Q') ) then
errmsg = msprintf(gettext("%s: Q is not a symmetric matrix"), "qpipopt");
error(errmsg);
end
//Check the size of Q which should equal to the number of variable
if ( size(Q) ~= [nbVar nbVar]) then
errmsg = msprintf(gettext("%s: The Size of Q is not equal to the number of variables"), "qpipopt");
error(errmsg);
end
//Check the size of p which should equal to the number of variable
if ( size(p,2) ~= [nbVar]) then
errmsg = msprintf(gettext("%s: The Size of p is not equal to the number of variables"), "qpipopt");
error(errmsg);
end
if (nbCon) then
//Check the size of constraint which should equal to the number of variables
if ( size(conMatrix,2) ~= nbVar) then
errmsg = msprintf(gettext("%s: The size of constraints is not equal to the number of variables"), "qpipopt");
error(errmsg);
end
end
//Check the number of constraint
if ( size(conMatrix,1) ~= nbCon) then
errmsg = msprintf(gettext("%s: The size of constraint matrix is not equal to the number of constraint given i.e. %d"), "qpipopt", nbCon);
error(errmsg);
end
//Check the size of Lower Bound which should equal to the number of variables
if ( size(LB,2) ~= nbVar) then
errmsg = msprintf(gettext("%s: The size of Lower Bound is not equal to the number of variables"), "qpipopt");
error(errmsg);
end
//Check the size of Upper Bound which should equal to the number of variables
if ( size(UB,2) ~= nbVar) then
errmsg = msprintf(gettext("%s: The size of Upper Bound is not equal to the number of variables"), "qpipopt");
error(errmsg);
end
//Check the size of constraints of Lower Bound which should equal to the number of constraints
if ( size(conLB,2) ~= nbCon) then
errmsg = msprintf(gettext("%s: The size of Lower Bound of constraints is not equal to the number of constraints"), "qpipopt");
error(errmsg);
end
//Check the size of constraints of Upper Bound which should equal to the number of constraints
if ( size(conUB,2) ~= nbCon) then
errmsg = msprintf(gettext("%s: The size of Upper Bound of constraints is not equal to the number of constraints"), "qpipopt");
error(errmsg);
end
//Check the size of initial of variables which should equal to the number of variables
if ( size(x0,2) ~= nbVar | size(x0,"*")>nbVar) then
warnmsg = msprintf(gettext("%s: Ignoring initial guess of variables as it is not equal to the number of variables"), "qpipopt");
warning(warnmsg);
end
//Check if the user gives a matrix instead of a vector
if ((size(p,1)~=1)& (size(p,2)~=1)) then
errmsg = msprintf(gettext("%s: p should be a vector"), "qpipopt");
error(errmsg);
end
if (size(LB,1)~=1)& (size(LB,2)~=1) then
errmsg = msprintf(gettext("%s: Lower Bound should be a vector"), "qpipopt");
error(errmsg);
end
if (size(UB,1)~=1)& (size(UB,2)~=1) then
errmsg = msprintf(gettext("%s: Upper Bound should be a vector"), "qpipopt");
error(errmsg);
end
if (nbCon) then
if ((size(conLB,1)~=1)& (size(b,2)~=1)) then
errmsg = msprintf(gettext("%s: Constraint Lower Bound should be a vector"), "qpipopt");
error(errmsg);
end
if (size(conUB,1)~=1)& (size(beq,2)~=1) then
errmsg = msprintf(gettext("%s: Constraint should be a vector"), "qpipopt");
error(errmsg);
end
end
// Check if the user gives infinity or negative infinity in conLB or conUB
for i = 1:nbCon
if (conLB(i) == %inf)
errmsg = msprintf(gettext("%s: Value of Lower Bound can not be infinity"), "qpipopt");
error(errmsg);
end
if (conUB(i) == -%inf)
errmsg = msprintf(gettext("%s: Value of Upper Bound can not be negative infinity"), "qpipopt");
error(errmsg);
end
end
[xopt,fopt,status,iter,Zl,Zu,lmbda] = solveqp(nbVar,nbCon,Q,p,conMatrix,conLB,conUB,LB,UB,x0,options);
xopt = xopt';
exitflag = status;
output = struct("Iterations" , []);
output.Iterations = iter;
lambda = struct("lower" , [], ..
"upper" , [], ..
"constraint" , []);
lambda.lower = Zl;
lambda.upper = Zu;
lambda.constraint = lmbda;
select status
case 0 then
printf("\nOptimal Solution Found.\n");
case 1 then
printf("\nMaximum Number of Iterations Exceeded. Output may not be optimal.\n");
case 2 then
printf("\nMaximum CPU Time exceeded. Output may not be optimal.\n");
case 3 then
printf("\nStop at Tiny Step\n");
case 4 then
printf("\nSolved To Acceptable Level\n");
case 5 then
printf("\nConverged to a point of local infeasibility.\n");
case 6 then
printf("\nStopping optimization at current point as requested by user.\n");
case 7 then
printf("\nFeasible point for square problem found.\n");
case 8 then
printf("\nIterates diverging; problem might be unbounded.\n");
case 9 then
printf("\nRestoration Failed!\n");
case 10 then
printf("\nError in step computation (regularization becomes too large?)!\n");
case 12 then
printf("\nProblem has too few degrees of freedom.\n");
case 13 then
printf("\nInvalid option thrown back by IPOpt\n");
case 14 then
printf("\nNot enough memory.\n");
case 15 then
printf("\nINTERNAL ERROR: Unknown SolverReturn value - Notify IPOPT Authors.\n");
else
printf("\nInvalid status returned. Notify the Toolbox authors\n");
break;
end
endfunction
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