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+// An example with inequality and equality constraints
+c=[-1,-1/3]'
+A=[1,1;1,1/4;1,-1;-1/4,-1;-1,-1;-1,1]
+b=[2,1,2,1,-1,2]
+Aeq=[1,1/4]
+beq=[1/2]
+
+//Output
+//Optimal Solution.
+// lambda =
+//
+// reduced_cost: [0,0]
+// ineqlin: [-0.1111111,0,0,0,0,0]
+// eqlin: -0.8888889
+// output =
+//
+// Iterations: 0
+// constrviolation: 0
+// exitflag =
+//
+// 0.
+// fopt =
+//
+// - 0.6666667
+// xopt =
+//
+// 0.
+// 2.
+
+[xopt,fopt,exitflag,output,lambda]=linprog(c, A, b, Aeq, beq)
+
+