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+%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
+% Tutorial slides on Python.
+%
+% Author: FOSSEE <info at fossee dot in>
+% Copyright (c) 2005-2009, FOSSEE Team
+%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
+
+
+\documentclass[14pt,compress]{beamer}
+
+\mode<presentation>
+{
+ \useoutertheme{split}
+ \setbeamercovered{transparent}
+}
+
+\definecolor{darkgreen}{rgb}{0,0.5,0}
+
+\usepackage{listings}
+\lstset{language=Python,
+ basicstyle=\ttfamily\bfseries,
+ commentstyle=\color{red}\itshape,
+ stringstyle=\color{darkgreen},
+ showstringspaces=false,
+ keywordstyle=\color{blue}\bfseries}
+
+\newcommand{\kwrd}[1]{ \texttt{\textbf{\color{blue}{#1}}} }
+
+%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
+% Macros
+
+\newcounter{qno}
+\setcounter{qno}{0}
+\newcommand{\incqno}{\addtocounter{qno}{1}{Question \theqno}}
+
+%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
+% Title page
+\title[Basic Python]{Python: Quiz}
+
+\author[FOSSEE Team] {FOSSEE}
+
+\institute[IIT Bombay] {Department of Aerospace Engineering\\IIT Bombay}
+\date[] {11, October 2009\\Day 2}
+%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
+
+
+\begin{document}
+
+\begin{frame}
+ \titlepage
+\end{frame}
+
+\begin{frame}
+ \frametitle{Write your details...}
+On the top right hand corner please write down the following:
+ \begin{itemize}
+ \item Name:
+ \item Affliation:
+ \item Occupation:
+ \end{itemize}
+\end{frame}
+
+\begin{frame}[fragile]
+\frametitle{\incqno }
+\begin{lstlisting}
+ >>> x = array([[1,2,3,4],[3,4,2,5]])
+ >>> x.shape
+ (2, 4)
+\end{lstlisting}
+Change the shape of \lstinline+x+ to (4,2)
+\end{frame}
+
+\begin{frame}[fragile]
+\frametitle{\incqno }
+\begin{lstlisting}
+ >>> x = array([[1,2,3,4]])
+\end{lstlisting}
+How to change the third element of \lstinline+x+ to 0?
+\end{frame}
+
+\begin{frame}[fragile]
+\frametitle{\incqno }
+What would be the result?
+\begin{lstlisting}
+ >>> y = arange(3)
+ >>> x = linspace(0,3,3)
+ >>> x-y
+\end{lstlisting}
+\end{frame}
+
+\begin{frame}[fragile]
+\frametitle{\incqno }
+\begin{lstlisting}
+ >>> x = array([0, 1, 2, 3])
+ >>> x.shape = 2,2
+ >>> x
+ array([[0, 1],
+ [2, 3]])
+ >>> x[::2,::2]
+\end{lstlisting}
+What is the output?
+\end{frame}
+
+\begin{frame}[fragile]
+\frametitle{\incqno }
+What would be the result?
+\begin{lstlisting}
+ >>> x
+ array([[0, 1, 2],
+ [3, 4, 5],
+ [6, 7, 8]])
+ >>> x[::-1,:]
+\end{lstlisting}
+Hint:
+\begin{lstlisting}
+ >>> x = arange(9)
+ >>> x[::-1]
+ array([8, 7, 6, 5, 4, 3, 2, 1, 0])
+\end{lstlisting}
+\end{frame}
+
+\begin{frame}[fragile]
+\frametitle{\incqno }
+\begin{lstlisting}
+ >>> x
+ array([[ 0, 1, 2, 3],
+ [ 4, 5, 6, 7],
+ [ 8, 9, 10, 11],
+ [12, 13, 14, 15]])
+\end{lstlisting}
+How will you get the following \lstinline+x+?
+\begin{lstlisting}
+ array([[ 5, 7],
+ [ 9, 11]])
+\end{lstlisting}
+\end{frame}
+
+\begin{frame}[fragile]
+\frametitle{\incqno }
+\begin{lstlisting}
+ >>> x = array(([1,2,3,4],[2,3,4,5]))
+ >>> x[-2][-3] = 4
+ >>> x
+\end{lstlisting}
+What will be printed?
+\end{frame}
+
+\begin{frame}[fragile]
+\frametitle{\incqno }
+What would be the output?
+\begin{lstlisting}
+ >>> y = arange(4)
+ >>> x = array(([1,2,3,2],[1,3,6,0]))
+ >>> x + y
+\end{lstlisting}
+\end{frame}
+
+\begin{frame}[fragile]
+\frametitle{\incqno }
+\begin{lstlisting}
+ >>> line = plot(x, sin(x))
+\end{lstlisting}
+Use the \lstinline+set_linewidth+ method to set width of \lstinline+line+ to 2.
+\end{frame}
+
+\begin{frame}[fragile]
+\frametitle{\incqno }
+What would be the output?
+\begin{lstlisting}
+ >>> x = arange(9)
+ >>> y = arange(9.)
+ >>> x == y
+\end{lstlisting}
+\end{frame}
+
+
+\end{document}
+