{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# Chapter 11: Conduction Heat Transfer" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 11.1: Chapter_11_example_1.sce" ] }, { "cell_type": "code", "execution_count": null, "metadata": { "collapsed": true }, "outputs": [], "source": [ "clc\n", "//initialisation of variables\n", "T= 76 //F\n", "T1= 21 //F\n", "Tw= 67 //W\n", "h= 1.5 //Btu/\n", "A= 1 //ft^2\n", "h0= 6.5 //Btu/hr\n", "//CALCULATIONS\n", "q= h*A*(T-Tw)\n", "t= (q/(h0*A))+T1\n", "//results\n", "printf ('Outside wall temperature= %.1f F',t)" ] } , { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 11.2: chapter_11_example_2.sce" ] }, { "cell_type": "code", "execution_count": null, "metadata": { "collapsed": true }, "outputs": [], "source": [ "clc\n", "//initialisation of variables\n", "hi= 2 //Btu/hr ft^2 F\n", "l= 6 //in\n", "k= 0.5 //Btu/hr ft F\n", "h0= 10 //Btu/hr ft^2 F\n", "ti= 70 //F\n", "t0= 20 //F\n", "A= 1 //ft^2\n", "//CALCULATIONS\n", "U= 1/((1/hi)+((l*0.5)/(6*k))+(1/h0))\n", "q= U*A*(ti-t0)\n", "//RESULTS\n", "printf ('Thermal transmittance= %.2f ft^2 F',U)\n", "printf (' \n Heat transfer rate= %.1f Btu/hr',q)" ] } , { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 11.3: chapter_11_example_3.sce" ] }, { "cell_type": "code", "execution_count": null, "metadata": { "collapsed": true }, "outputs": [], "source": [ "clc\n", "//initialisation of variables\n", "Ti= 300 //F\n", "T0= 100 //F\n", "l= 0.25 //in\n", "li= 3 //in\n", "A= 12 //in/ft\n", "ks= 31.4 //Btu/hr ft F\n", "ki= 0.04 //Btu/hr ft F\n", "//CALCULATIONS\n", "q= (Ti-T0)/((l/(A*ks))+(li/(A*ki)))\n", "t= Ti-((q*l/12)/ks)\n", "//RESULTS\n", "printf ('Heat loss= %.f Btu/hr',q)\n", "printf (' \n Temperature at the interface of the steel and the insulation= %.2f F',t)" ] } , { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 11.4: chapter_11_example_4.sce" ] }, { "cell_type": "code", "execution_count": null, "metadata": { "collapsed": true }, "outputs": [], "source": [ "clc\n", "//initialisation of variables\n", "ti= 149 //C\n", "t0= 27 //C\n", "D0= 0.1149 //m\n", "l= 1 //m\n", "h0= 23 //W/m^2 C\n", "hi= 227 //W/m^2 C\n", "k= 0.19 //W/m C\n", "Di= 0.0889 //cm\n", "//CALCULATIONS\n", "D1= D0*100\n", "D2= Di*100\n", "R0=(1/(D0*%pi*l*h0))\n", "Rins=(log(D1/D2)/(2*%pi*k*l))\n", "Ri=1/(Di*%pi*l*hi)\n", "q= (ti-t0)/(R0+Rins+Ri)\n", "//RESULTS\n", "printf ('Heat loss= %.f W',q)" ] } , { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 11.5: chapter_11_example_5.sce" ] }, { "cell_type": "code", "execution_count": null, "metadata": { "collapsed": true }, "outputs": [], "source": [ "clc\n", "//initialisation of variables\n", "l= 0.2 //m\n", "l1= 0.5 //m\n", "k= 0.35 //W/m C\n", "t= 0.15 //m\n", "T1= 1100 //C\n", "T2= 150 //C\n", "//CALCULATIONS\n", "Ai= 6*l^2\n", "Ao= 6*l1^2\n", "q= 0.73*k*sqrt(Ai*Ao)*(T1-T2)/t\n", "//RESULTS\n", "printf ('Power consumption= %.f W',q)" ] } , { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 11.6: chapter_11_example_6.sce" ] }, { "cell_type": "code", "execution_count": null, "metadata": { "collapsed": true }, "outputs": [], "source": [ "clc\n", "//initialisation of variables\n", "h= 12 //W/m^2 C\n", "k= 0.19 //W/m C\n", "d= 0.6 //m\n", "//CALCULATIONS\n", "r= k/h\n", "d1=d/2\n", "if (r