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	   "source": [
       "# Chapter 1: FUNDAMENTALS OF POWER SYSTEMS"
	   ]
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		   "source": [
			"## Example 1.1: To_determine_the_Base_values_and_pu_values.sce"
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"// To determine the Base values and p.u values\n",
"clear\n",
"clc;\n",
"Sb=100;// base value of power(MVA)\n",
"Vb=33;// base value of voltage (Kv)\n",
"Vbl=Vb*110/32;\n",
"Vbm=Vbl*32/110;\n",
"Zp.ut=0.08*100*32*32/(110*33*33);\n",
"Zp.u.l=50*100/(Vbl^2);\n",
"Zp.um1=.2*100*30*30/(30*33*33);\n",
"Zp.um2=.2*100*30*30/(20*33*33);\n",
"Zp.um3=.2*100*30*30/(50*33*33);\n",
"mprintf('Base value of voltage in line = %.2f kV\n',Vbl);\n",
"mprintf('Base value of voltage in motor circuit=%.0f kV\n',Vbm);\n",
"mprintf('p.u value of reactance transformer =%.5f p.u\n',Zp.ut);\n",
"mprintf('p.u value of impedence of line=%.4f p.u\n',Zp.u.l);\n",
"mprintf('p.u value of reactance of motor 1 =%.4f p.u\n',Zp.um1);\n",
"mprintf('p.u value of reactance of motor 2 =%.3f p.u\n',Zp.um2);\n",
"mprintf('p.u value of reactance of motor 3 =%.4f p.u\n',Zp.um3);\n",
""
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