{
"cells": [
 {
		   "cell_type": "markdown",
	   "metadata": {},
	   "source": [
       "# Chapter 2: Fundamental concepts"
	   ]
	},
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 2.1: Potential_energy.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"clc\n",
"clear\n",
"//Initialization of variables\n",
"z=100 //ft\n",
"m=32.1739 //lbm\n",
"//calculations\n",
"PE=m*z\n",
"//results\n",
"printf('Potential energy = %.2f ft-lbm',PE)"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 2.3: Energy_and_mass_calculation.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"clc\n",
"clear\n",
"//Initialization of variables\n",
"m0=18.016 //lbm\n",
"gc=32.1739 //lbm ft/lbf sec^2\n",
"c=186000*5280\n",
"dU=94.4*10^6 //ft-lbf\n",
"//calculations\n",
"U=m0/gc *c^2\n",
"dm= -dU*gc/c^2\n",
"//results\n",
"printf('Absolute energy of this mixture = %.2e ft-lbf',U)\n",
"printf('\n In case b, there is no change in mass')\n",
"printf('\n Change in mass = %.2e lbm',dm)\n",
"disp('The answers are a bit different due to rounding off error in textbook.')"
   ]
   }
],
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		   "name": "scilab"
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		  "language_info": {
		   "file_extension": ".sce",
		   "help_links": [
			{
			 "text": "MetaKernel Magics",
			 "url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md"
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		   "name": "scilab",
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