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	   "source": [
       "# Chapter 8: Third Law of Thermodynamics"
	   ]
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		   "source": [
			"## Example 8.1: To_calculate_the_absolute_entropy_of_copper_at_300_K.sce"
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"//Chemical Engineering Thermodynamics\n",
"//Chapter 8\n",
"//Third Law of Thermodynamics\n",
"\n",
"//Example 8.1\n",
"clear;\n",
"clc;\n",
"\n",
"//Given\n",
"C_ps = 0.1;//Molal heat capacity of copper at 20 K\n",
"Ti = 0;//Initial temperature in K\n",
"Tf = 20;//melting point in K\n",
"Tb = 300;//boiling point in K\n",
"\n",
"//To calculate the absolute entropy of copper at 300 K\n",
"//From equation 8.4(page no 164)\n",
"a = C_ps/(Tf^3);// a is the charateristic constant\n",
"C_p = [0.1 0.80 1.94 3.0 3.9 5.0];\n",
"//T1 = log(T);\n",
"T1 = [1.301 1.6021 1.7782 1.9031 2.000 2.1761];\n",
"plot(T1,C_p);\n",
"xtitle('C_p vs T1','T1','Cp');\n",
"// Area under the curve is given as\n",
"A = 7.82;\n",
"//From equation 8.5(page no 164)\n",
"S = (a*((Tf^3)/3))+A;\n",
"mprintf('The absolute entropy of copper is %f Kcal/Kgmole',S);\n",
"//end"
   ]
   }
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