{
"cells": [
 {
		   "cell_type": "markdown",
	   "metadata": {},
	   "source": [
       "# Chapter 1: DC circuits"
	   ]
	},
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 1.10: Calculate_current.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"//Ex 1.10\n",
"clc;clear;close;\n",
"format('v',6);\n",
"I1=2.5;//A\n",
"I2=-1.5;//A\n",
"//I1+I2+I3=0//from KCL\n",
"I3=-I1-I2;//A\n",
"disp(I3,'Current I3(A)');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 1.11: Determine_the_currents.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"//Ex 1.11\n",
"clc;clear;close;\n",
"format('v',6);\n",
"I1=3;//A\n",
"I3=1;//A\n",
"I6=1;//A\n",
"//I1-I2-I3=0//from KCL at point a\n",
"I2=I1-I3;//A\n",
"//I2+I4-I6=0//from KCL at point b\n",
"I4=I6-I2;//A\n",
"//I3-I4-I5=0//from KCL at point c\n",
"I5=I3-I4;//A\n",
"disp(I2,'Current I2(A)');\n",
"disp(I4,'Current I4(A)');\n",
"disp(I5,'Current I5(A)');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 1.12: Determine_I1_and_I2.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"//Ex 1.12\n",
"clc;clear;close;\n",
"format('v',6);\n",
"R1=30;//ohm\n",
"R2=60;//ohm\n",
"R3=30;//ohm\n",
"I3=1;//A\n",
"I1=I3*(R2+R3)/R2;//A\n",
"I2=I1-I3;//A\n",
"disp(I1,'Current I1(A)');\n",
"disp(I2,'Current I2(A)');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 1.13: Determine_V1_and_V3.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"//Ex 1.13\n",
"clc;clear;close;\n",
"format('v',6);\n",
"E=12;//V\n",
"V2=8;//V\n",
"V4=2;//V\n",
"V1=E-V2;//V\n",
"//-V2+V3+V4=0;//for Loop B\n",
"V3=V2-V4;//V\n",
"disp(V1,'Voltage V1(V)');\n",
"disp(V3,'Voltage V3(V)');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 1.14: Calculate_VAB.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"//Ex 1.14\n",
"clc;clear;close;\n",
"format('v',6);\n",
"V=20;//V\n",
"R1=25;//ohm\n",
"R2=40;//ohm\n",
"R3=15;//ohm\n",
"R4=10;//ohm\n",
"VAC=R3*V/(R1+R3);//V\n",
"VBC=R4*V/(R2+R4);//V\n",
"//0=VAB+VBC-VAC;///from KVL\n",
"VAB=-VBC+VAC;//V\n",
"disp(VAB,'Voltage VAB(V)');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 1.15: Voltage_and_emf.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"//Ex 1.15\n",
"clc;clear;close;\n",
"format('v',6);\n",
"E1=10;//V\n",
"V2=6;//V\n",
"V3=8;//V\n",
"//E1=V1+V2;//KCL for left loop\n",
"V1=E1-V2;//V\n",
"//-E2=-V2-V3;//KCL for right loop\n",
"E2=V2+V3;//V\n",
"disp(V1,'Voltage V1(V)');\n",
"disp(E2,'Voltage E2(V)');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 1.1: Current_in_the_circuit.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"//Ex 1.1\n",
"clc;clear;close;\n",
"format('v',4);\n",
"R=3;//kohm\n",
"V=220;//V\n",
"//First Case\n",
"I=V/R;//mA\n",
"disp(I,'1st case : Current in the circuit(mA)');\n",
"//Second Case\n",
"Req=R+R;//ohm(Equivalent resistance)\n",
"I=V/Req;//mA\n",
"disp(I,'2nd case : Current in the circuit(mA)');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 1.2: Voltage_across_resistor.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"//Ex 1.2\n",
"clc;clear;close;\n",
"format('v',5);\n",
"I=1.5;//A\n",
"R1=2;//ohm\n",
"R2=3;//ohm\n",
"R3=8;//ohm\n",
"V1=I*R1;//V\n",
"V2=I*R2;//V\n",
"V3=I*R3;//V\n",
"disp(V1,'Voltage across R1(V)');\n",
"disp(V2,'Voltage across R2(V)');\n",
"disp(V3,'Voltage across R3(V)');\n",
"V=V1+V2+V3;//V(Supply voltage)\n",
"disp(V,'Supply Voltage(V)');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 1.3: Circuit_current.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"//Ex 1.3\n",
"clc;clear;close;\n",
"format('v',6);\n",
"Vs=100;//V(Supply voltage)\n",
"R1=40;//ohm\n",
"R2=50;//ohm\n",
"R3=70;//ohm\n",
"R=R1+R2+R3;//ohm(Equivalent resistance)\n",
"I=Vs/R;//A(Current in the circuit)\n",
"disp(I,'Circuit current(A)');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 1.4: Resistance_R1.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"//Ex 1.4\n",
"clc;clear;close;\n",
"format('v',6);\n",
"Vo=10;//V(Output voltage)\n",
"Vin=30;//V(Input voltage)\n",
"R2=100;//ohm\n",
"//V2/V=R2/(R1+R2)//Voltage divider rule\n",
"R1=(Vin*R2-Vo*R2)/Vo;//ohm\n",
"disp(R1,'Resistance of R1(ohm)');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 1.5: Supply_Current.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"//Ex 1.5\n",
"clc;clear;close;\n",
"format('v',6);\n",
"V=110;//V\n",
"R1=22;//ohm\n",
"R2=44;//ohm\n",
"I1=V/R1;//A\n",
"I2=V/R2;//A\n",
"I=I1+I2;//A\n",
"disp(I,'Supply current(A)');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 1.6: Effective_resistance_and_Supply_current.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"//Ex 1.6\n",
"clc;clear;close;\n",
"format('v',5);\n",
"V=12;//V\n",
"R1=6.8;//ohm\n",
"R2=4.7;//ohm\n",
"R3=2.2;//ohm\n",
"R=1/(1/R1+1/R2+1/R3);//ohm(Effective resistance)\n",
"I=V/R;//A(Supply current)\n",
"disp(R,'Effective resistance(ohm)')\n",
"disp(I,'Supply current(A)');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 1.7: Current_in_the_resistor.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"//Ex 1.7\n",
"clc;clear;close;\n",
"format('v',4);\n",
"I=8;//A\n",
"R2=2;//ohm\n",
"// Part (a) \n",
"R1=2;//ohm\n",
"I2=I*R1/(R1+R2);//A\n",
"disp(I2,'(a) Current in 2 ohm resistance(A)');\n",
"// Part (b) \n",
"R1=4;//ohm\n",
"I2=I*R1/(R1+R2);//A\n",
"disp(I2,'(b) Current in 2 ohm resistance(A)');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 1.8: Calculate_current.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"//Ex 1.8\n",
"clc;clear;close;\n",
"format('v',6);\n",
"I1=3;//A\n",
"I2=-4;//A\n",
"I4=2;//A\n",
"//I1-I2+I3-I4=0//from KCL\n",
"I3=-I1+I2+I4;//A\n",
"disp(I3,'Current I3(A)');"
   ]
   }
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			{
			 "text": "MetaKernel Magics",
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