{
"cells": [
 {
		   "cell_type": "markdown",
	   "metadata": {},
	   "source": [
       "# Chapter 6: Operational Amplifiers"
	   ]
	},
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.10: R1_and_Rf.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa 6.10\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"Ao = 10;\n",
"// Ao = (1+(R_F/R1));\n",
"//Given that maximum value of resistor should not exceed 30 kΩ, so we select\n",
"R_F= 27;// in k ohm\n",
"R1= R_F/(Ao-1);// in k ohm\n",
"disp(R_F,'The value of R_F in k ohm is');\n",
"disp(R1,'The value of R1 in k ohm is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.11: Output_voltage.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa 6.11\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"Va = 0.2;// in V\n",
"Vb = -0.5;// in V\n",
"Vc = 0.8;// in V\n",
"Ra = 33;// in k ohm\n",
"Rb = 22;// in  k ohm\n",
"Rc = 11;// in  k ohm\n",
"R_F = 66;// in k ohm\n",
"// Using Superposition theorm, the output voltage\n",
"Vo = (-((R_F/Ra)*Va)) -(((R_F/Rb)*Vb)) -(((R_F/Rc)*Vc));// in V\n",
"disp(Vo,'The output voltage in V is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.13: Output_voltage.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa 6.13\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"Va = 6;// in V\n",
"Vb = -3;// in V\n",
"Vc = -0.75;// in V\n",
"Ra = 10;// in k ohm\n",
"Rb = 2.5;// in k ohm\n",
"Rc = 4;// in k ohm\n",
"R_F = 10;// in k ohm\n",
"// The output voltage \n",
"Vo = (-((R_F/Ra)*Va)) -(((R_F/Rb)*Vb)) -(((R_F/Rc)*Vc));// in V\n",
"disp(Vo,'The output voltage in V is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.14: Closed_loop_differential_gain_and_output_voltage.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa 6.14\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R1 = 100;// in ohm\n",
"R2 = R1;// in ohm\n",
"R3 = 3.9;// in k ohm\n",
"R3 = R3 * 10^3;// in ohm\n",
"R_F = R3;// in ohm\n",
"Vx = -3.2;// in V\n",
"Vy = -3;// in V\n",
"// output voltage due to Vx, Vox = -(R_F/R1)*Vx and due to Vy, Voy = (R3/(R2+R3)) * (1+(R_F/R1))*Vy\n",
"// Vo = Vox + Voy =  -(R_F/R1)*Vx + (R_F/R1)*Vy   (as R1=R2 and R3=Rf)\n",
"//So, Aod = Vo/(Vx-Vy) = -R_F/R1;\n",
"Aod = -R_F/R1;\n",
"disp(Aod,'The closed loop differential gain is');\n",
"Vo = (-R_F/R1)*(Vx-Vy);// in V\n",
"disp(Vo,'The output voltage in V is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.1: Common_mode_gain.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa 6.1\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"CMRR = 10^5;\n",
"Ad = 10^5;\n",
"// CMRR = Ad/A_CM;\n",
"// The common mode gain of the op-amp \n",
"A_CM = Ad/CMRR;\n",
"disp(A_CM,'The common mode gain of the op-amp is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.2: Slew_rate.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa 6.2\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"del_V = 20;//change in voltage in V\n",
"del_t = 4;//change in time in µS\n",
"SR = del_V/del_t;//slew rate in V/µS\n",
"disp(SR,'The slew rate in V/µS is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.3: Slew_rate.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa 6.3\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"del_V = 0.75;//chagne in voltage in V\n",
"del_t = 50;//change in time in ns\n",
"// The slew rate \n",
"SR = del_V/(del_t*10^-3);// in µs\n",
"disp(SR,'The slew rate in V/µ-sec is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.4: Closed_loop_voltage_gain_and_input_impedance.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa 6.4\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R1 = 1;// in k ohm\n",
"R_F = 4.7;// in k ohm\n",
"//The closed loop voltage gain, Ao = Vo/Vin = -R_F/R1;\n",
"Ao = -R_F/R1;\n",
"disp(Ao,'The closed loop voltage gain is');\n",
"// The input impedance \n",
"Ri = R1;// in k ohm\n",
"disp(Ri,'The input impedance in k ohm is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.5: R1_and_R2.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa 6.5\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"Ao = -20;\n",
"Ri = 5;// in k ohm\n",
"R1 = Ri;// in k ohm\n",
"disp(R1,'The value of R1 in k ohm is');\n",
"// Closed loop voltage gain for inverting amplifier, Ao = -R_F/R1 or\n",
"R_F = -Ao*R1;// in k ohm\n",
"disp(R_F,'The value of R_F in k ohm is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.6: Output_voltage.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa 6.6\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R1 = 20;// in k ohm\n",
"R_F = 300;// in k ohm\n",
"Vin = 1.25;// in V\n",
"// Ao = Vo/Vin = -R_F/R1;\n",
"Ao = -R_F/R1;\n",
"// Output voltage,\n",
"Vo = Ao*Vin;// in V\n",
"disp(Vo,'The output voltage in V is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.7: R1_and_Rf.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa 6.7\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"Ao = -4;// in V/V\n",
"R_T= 100;// total resistance in k ohm\n",
"// R1+R_F= R_T          (i)\n",
"// Ao= -R_F/R1             (ii)\n",
"R_F= R_T/(1-1/Ao);// in k ohm           (From eq (i) and (ii))\n",
"R1= -R_F/Ao;// in k ohm\n",
"disp(R1,'The value of R1 in k ohm is');\n",
"disp(R_F,'The value of R_F in k ohm is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.8: Output_voltage.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa 6.8\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R1 = 15;// in k ohm\n",
"R_F = 450;// in k ohm\n",
"Vin = -0.25;// in V\n",
"// Vo = Ao*Vin\n",
"Vo = (1+R_F/R1)*abs(Vin);// in V    (on putting, Ao = 1+(R_F/R1))\n",
"disp(Vo,'The output voltage in V is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.9: R1_and_Rf.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa 6.9\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"Ao = 1.5;// in V/V\n",
"R = 10;// in k ohm\n",
"// Ao = (1+(R_F/R1))\n",
"disp('The relation of R1 and R_F can be implemented in two ways : ');\n",
"disp('(i) : When R_F= R || R, in this condition')\n",
"// When R_F= R || R\n",
"R1= R;//in k ohm\n",
"R_F= R1*(Ao-1);// in k ohm\n",
"disp(R1,'The value of R1 in k ohm is : ');\n",
"disp(R_F,'The value of R_F in k ohm is : ')\n",
"// When both resistor connected in series\n",
"disp('(ii) : When both resistor connected in series, in this condition')\n",
"R1= 2*R;// in k ohm\n",
"R_F= R1*(Ao-1);// in k ohm\n",
"disp(R1,'The value of R1 in k ohm is : ');\n",
"disp(R_F,'The value of R_F in k ohm is : ')\n",
""
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_10: Voltage_produced_at_output_terminal.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.10\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R_F = 60;// in ko hm\n",
"R1 = 20;// in k ohm\n",
"Vin1 = 2;// in V\n",
"Vin2 = 0.1;// in V\n",
"// The output voltage, by using super position theorm,\n",
"Vo = ((-R_F/R1)*Vin1) + ((1+(R_F/R1))*Vin2);// in V\n",
"disp(Vo,'The output voltage in V is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_11: Output_voltage.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.11\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R1 = 10;// in k ohm\n",
"R2 = 20;// in k ohm\n",
"R3 = 10;// in k ohm\n",
"R_F = 20;// in k ohm\n",
"Vin1 = 2;// in V\n",
"Vin2 = 1;// in V\n",
"// The output voltage,\n",
"Vo = ((-R_F/R1)*Vin1) - ((R_F/R2)*Vin2);// in V\n",
"disp(Vo,'The output voltage in V is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_12: Output_voltage.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.12\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R_F = 20;// in k ohm\n",
"R1 = 10;// in k ohm\n",
"R2 = 20;// in k ohm\n",
"Vin1 = 2;// in V\n",
"Vin2 = 2;// in V\n",
"Vin3 = 2;// in V\n",
"// The output voltage, by using super position theorm,\n",
"Vo = ((-R_F/R1)*Vin1) + (-Vin2*R_F/R2+Vin2) + ((R_F/(((R1*R2)/(R1+R2))))*Vin3);// in V\n",
"disp(Vo,'The voltage is appeared at the output terminal in V is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_13: Output_voltage.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.13\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R1 = 20;// in k ohm\n",
"R3 = 10;// in k ohm\n",
"R2 = R3;// in k ohm\n",
"R_F = 20;// in k ohm\n",
"Vin1 = 2;// in V\n",
"Vin2 = 2.1;// in V\n",
"// The input voltage at non-inverting terminal,\n",
"V_A = (R2*Vin2)/R1;// in V\n",
"// The output voltage, by using super position theorm,\n",
"Vo = ((-R_F/R1)*Vin1) + ((1+(R_F/R1))*(R1/(R2+R3))*V_A);// in V\n",
"disp(Vo,'The output voltage in V is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_15: Maximum_loop_voltage_gai.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.15\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"//Output voltage of the amplifier, Vo = (1+(Rf/Rin))*Vin and voltage gain, Av = Vo/Vin = 1+(Rf/Rin)\n",
"Rf = 0;\n",
"Rin = 2;// in k ohm\n",
"Avmin = 1+(Rf/Rin);\n",
"Rf = 100;// in k ohm\n",
"// The maximum loop voltage gain \n",
"Avmax = 1+(Rf/Rin);\n",
"disp(Avmax,'The maximum loop voltage gain is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_18: Output_voltage_and_percentage_error_due_to_common_mode.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.18\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"Ad = 5*10^5;// differential mode gain\n",
"CMRR = 80;// in dB\n",
"A_CM = Ad/(10^(CMRR/20));// common mode gain\n",
"V1 = 745;// in µV\n",
"V1 = V1 * 10^-6;// in V\n",
"V2 = 740;// in µV\n",
"V2 = V2 * 10^-6;// in V\n",
"// CMRR = 20*log( Ad/A_CM );\n",
"// //output voltage in differential mode gain\n",
"Vod = Ad*(V1-V2);// in V\n",
"disp(Vod,'The output voltage in differential mode gain in volts is : ')\n",
"//output voltage due to common mode gain \n",
"Vo_CM = A_CM*((V1+V2)/2);//in V\n",
"disp(Vo_CM,'The output voltage due to common mode gain in volts is : ')\n",
"Pr = (Vo_CM/Vod)*100;// percentage error in %\n",
"disp(Pr,'The percentage error due to common mode in % is')"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_19: Input_impedance_voltage_gain_and_power_gain.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.19\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R1 = 1;// in Mohm\n",
"// The input impedance \n",
"Rin = R1;// in Mohm\n",
"disp(Rin,'The input impedance in Mohm is');\n",
"R2 = 1;// in Mohm\n",
"// The voltage gain \n",
"Avf = -R2/R1;// Voltage gain\n",
"disp(Avf,'The voltage gain is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_1: CMRR.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.1\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('e',8)\n",
"// Given data\n",
"Vid = 1;// in mV\n",
"Vo = 120;// in mV\n",
"V_CM = 1;// in mV\n",
"Ad = Vo/Vid;\n",
"Vo = 20;// in µV\n",
"Vo = Vo * 10^-3;// in mV\n",
"A_CM = Vo/V_CM;\n",
"Vo = 120;// in mV\n",
"// The value of CMRR for the circuit \n",
"CMRR = Vo/A_CM;\n",
"disp(CMRR,'The value of CMRR for the circuit is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_21: Output_voltage.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.21\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"i1 = 1;//input current for first op-amp in mA\n",
"i1 = i1 * 10^-3;// in A\n",
"R_F = 1;// in k ohm\n",
"R_F = R_F * 10^3;// in ohm\n",
"// Output voltage at first op-amp stage\n",
"Vo = -i1*R_F;// in V\n",
"R1 = 10;// in k ohm\n",
"R2 = 1;// in k ohm\n",
"// The output voltage,\n",
"Vg1 = Vo*(1+(R1/R2));// in V\n",
"disp(Vg1,'The output volatge in V is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_22: Output_voltage.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.22\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R_S3 = 10;// in k ohm\n",
"R_S2 = R_S3;// in k ohm\n",
"R_S1 = R_S3;// in k ohm\n",
"Rf = 10;// in k ohm\n",
"Vs1 = 0.2;// in V\n",
"Vs2 = 0.5;// in V\n",
"Vs3 = 0.8;// in V\n",
"// I = I1+6I2+I3;\n",
"// I = (Vs1/R_S1) + (Vs2/R_S2) + (Vs3/R_S3);\n",
"// I = - If;\n",
"// Vo = -If*Rf;\n",
"Vo = (Rf/R_S1)*(Vs1+Vs2+Vs3);// in V  (as R_S1= R_S2=R_S3)\n",
"disp(Vo,'The value of Vo in volts is : ');\n",
"disp('But the supply voltage of 10 V is used, so the op-amp will reach in saturation.');\n",
"disp('Hence, output voltage is -10 volts.')"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_25: Current_through_RL_resistor.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.25\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"//Ratio of R2/R1 =  R3/R4 = 4 and R_L = -Vi/R3\n",
"Vi = 3.7;// in V\n",
"R3 = 2;// in k ohm\n",
"R3 = R3 * 10^3;// in ohm\n",
"// The current through R_L,\n",
"I_L = -Vi/R3;// in A\n",
"I_L= I_L*10^3;// in mA\n",
"disp(I_L,'The current through R_L in mA is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_2: Closed_loop_gai.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.2\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R1 = 10;// in k ohm\n",
"R_F = 1000;// in k ohm\n",
"// Vin/R1 = -Vo/R_F and Vo/Vin = Ao = -R_F/R1\n",
"Ao = abs(-R_F/R1);// in k ohm\n",
"disp(Ao,'The closed loop gain is');\n",
"Vin = 30;// in mV\n",
"Vin = Vin  * 10^-3;// in V\n",
"// The output voltage,\n",
"Vo =-Ao*Vin;// in V\n",
"disp(Vo,'The output voltage in V is');\n",
"\n",
"// Note: The loop gain will be unit less."
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_3: Range_of_voltage_gain.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.3\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R1min = 10;// in k ohm\n",
"R1max = 20;// in k ohm\n",
"R_F = 300;// in k ohm\n",
"// The closed loop voltage gain corresponding to R1min,\n",
"Ao_min = -R_F/R1min;\n",
"// The closed loop voltage gain corresponding to R1max,\n",
"Ao_max = -R_F/R1max;\n",
"disp('The range of voltage gain is : '+string(Ao_max)+' to '+string(Ao_min));"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_4: Range_of_output_voltage.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.4\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R_F = 500;// in k ohm\n",
"R_desh = 20;// in k ohm\n",
"Vin = 0.5;// in V\n",
"Rd_desh = 0;\n",
"R1min = 20;// in k ohm\n",
"R1max = 50;// in k ohm\n",
"// Ao = Vo/Vin = (1+(R_F/R1));\n",
"Vo_max = Vin*(1+(R_F/R1min));// output voltage corresponding to R1min\n",
"Vo_min = Vin*(1+(R_F/R1max));// output voltage corresponding to R1max\n",
"disp('Range of output voltage is : '+string(Vo_min)+' volts to '+string(Vo_max)+' volts.');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_5: Minimum_and_maximum_closed_loop_voltage_gain.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.5\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R1 = 2;// in k ohm\n",
"Rdas = 2;// in k ohm\n",
"R_Fmin = 2;// in k ohm\n",
"R_Fmax = 102;// in k ohm\n",
"// Ao = -R_F/R1;\n",
"// The minimum closed loop voltage gain \n",
"Aomin = -R_Fmin/R1;\n",
"disp(Aomin,'The minimum closed loop voltage gain is');\n",
"//The maximum closed loop voltage gain \n",
"Aomax = -R_Fmax/R1;\n",
"disp(Aomax,'The maximum closed loop voltage gain is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_6: Maximum_and_minimum_closed_loop_voltage_gain.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.6\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R1 = 10;// in k ohm\n",
"R_F = 0;\n",
"// Ao = (1+(R_F/R1));\n",
"// The minimum closed loop voltage gain \n",
"Aomin = (1+(R_F/R1));\n",
"disp(Aomin,'The minimum closed loop voltage gain is');\n",
"R_F = 100;// in k ohm\n",
"// The maximum closed loop voltage gain \n",
"Aomax = (1+(R_F/R1));\n",
"disp(Aomax,'The maximum closed loop voltage gain is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_7: Closed_loop_voltage_gai.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.7\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',7)\n",
"// Given data\n",
"R1 = 220;// in ohm\n",
"R_F = 47;// in k ohm\n",
"R_F =R_F * 10^3;// in ohm\n",
"// The closed loop voltage for switch position-1\n",
"Ao = -R_F/R1;\n",
"disp(Ao,'The closed loop voltage for switch position-1 is');\n",
"R_F = 18;// in k ohm\n",
"R_F = R_F * 10^3;// in ohm\n",
"// The closed loop voltage for switch position-2\n",
"Ao = -R_F/R1;\n",
"disp(Ao,'The closed loop voltage for switch position-2 is');\n",
"R_F = 39;// in k ohm\n",
"R_F = R_F * 10^3;// in ohm\n",
"// The closed loop voltage for switch position-3\n",
"Ao = -R_F/R1;\n",
"disp(Ao,'The closed loop voltage for switch position-3 is');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_8: Closed_loop_voltage_gai.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.8\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R_F = 120;// in k ohm\n",
"Rdas1 = 6;// in k ohm\n",
"Rddas1 = 3;// in k ohm\n",
"R1 = Rdas1;// in k ohm\n",
"// For switch position-1 , the closed loop voltage gain,\n",
"Ao = 1+(R_F/R1);\n",
"disp(Ao,'The closed loop voltage gain for switch position-1 is : ');\n",
"R1 = (Rdas1*Rddas1)/(Rdas1+Rddas1);// in k ohm\n",
"// For switch position-2, the closed loop voltage gain, \n",
"Ao = 1+(R_F/R1);\n",
"disp(Ao,'The closed loop voltage gain for switch position-2 is : ');"
   ]
   }
,
{
		   "cell_type": "markdown",
		   "metadata": {},
		   "source": [
			"## Example 6.m_9: Output_voltage.sce"
		   ]
		  },
  {
"cell_type": "code",
	   "execution_count": null,
	   "metadata": {
	    "collapsed": true
	   },
	   "outputs": [],
"source": [
"// Exa Misc. 6.9\n",
"clc;\n",
"clear;\n",
"close;\n",
"format('v',6)\n",
"// Given data\n",
"R_F = 20;// in k ohm\n",
"R1 = 20;// in k ohm\n",
"R2 = 10;// in k ohm\n",
"Vin1 = 2;// in V\n",
"Vin2 = 1;// in V\n",
"// The output voltage, by using super position theorm\n",
"Vo = ((-R_F/R1)*Vin1) + ((1+(R_F/R1))*Vin2);\n",
"disp(Vo,'The output voltage is');"
   ]
   }
],
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