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//Example 4.11
clc
disp(" C_M = 2 pF")
fs=(1/(2*%pi*sqrt(2*0.01*10^-12)))*10^-6 // in MHz
format(6)
disp(fs,"Now f_s(in MHz) = 1 / 2*pi*sqrt(L*C) =")
ceq=(2*0.01*10^-24)/(2.01*10^-12) // in F
format(9)
disp(ceq," C_eq(in F) = C_M*C / C_M+C =")
fp=(1/(2*%pi*sqrt(2*9.95*10^-15)))*10^-6 // in MHz
format(6)
disp(fp," f_p = 1 / 2*pi*sqrt(L*C_eq) =")
disp("So f_sand f_p values are almost same.")
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