//chapter-10,Example10_7,pg 309

a1=3.81*10^-3

a2=-6.17*10^-7

//R1=(R2/2),i.e R2/R1=2

R1=10*10^3

R2=20*10^3

R5=4*10^3

R6=20*10^3

B=(R5/(R5+R6))

//using relation 10.68(b)

printf("(Vo/Vi)= (-3.05*10^-3)t/(1+0.76*10^-3)t\n")

printf("thus for, t<=130 C, Vo is approx. linear. this however can be extended with proper choice i.e R5 and R6 in relation to R1,R3 and R4")