clc
//ex7.3
N=343.392;
//convert the integer and decimal parts into binary form separately
B_1='101010111';      //for 343 from ex7.1
B_2='0.011001';      //for 0.392 from ex7.2
//combining these two
B='101010111.011001';      //for N, given number
disp(B,'binary form of 343.392')