-->//(Brakes) Example 12.6
 
-->//Limit of the product pv
 
-->pv = 2
 pv  =
 
    2.  
 
-->//Coefficient of friction between the drum and the friction lining mu
 
-->mu = 0.2
 mu  =
 
    0.2  
 
-->//Gear ratio between the brake and cable drum g
 
-->g = 4
 g  =
 
    4.  
 
-->//Permissible intensity of pressure on friction lining pmax (N/mm2)
 
-->pmax = 1
 pmax  =
 
    1.  
 
-->//Radius of the brake drum Rb (mm)
 
-->Rb = 200
 Rb  =
 
    200.  
 
-->//Radius of the cable drum Rc (mm)
 
-->Rc = 150
 Rc  =
 
    150.  
 
-->//Mass attached to the cable drum m (kg)
 
-->m = 500
 m  =
 
    500.  
 

Brake shoe force(P) = 4598.437500 N

Area of friction lining(A) = 4598.437500 mm2

Uniform velocity at which the mass can be lowered(v1) = 0.375000 m/s or 22.500000 m/min