-->//(Springs) Example 10.19 -->//Difference between the free lengths of the two springs dif (mm) -->dif = 15 dif = 15. -->//Maximum force acting on the composite spring P (N) -->P = 1000 P = 1000. -->//Wire diameter of the inner spring d2 (mm) -->d2 = 5 d2 = 5. -->//Mean coil diameter of the inner spring D2 (mm) -->D2 = 30 D2 = 30. -->//Wire diameter of the outer spring d1 (mm) -->d1 = 6 d1 = 6. -->//Mean coil diameter of the outer spring D1 (mm) -->D1 = 36 D1 = 36. -->//Number of active coils in outer spring N1 -->N1 = 10 N1 = 10. -->//Number of active coils in inner spring N2 -->N2 = 8 N2 = 8. -->//Modulus of rigidity for the spring G (N/mm2) -->G = 81370 G = 81370. Force transmitted by the outer spring(P1) = 706.021471 N Force transmitted by the inner spring(P2) = 293.978529 N Compression of the outer spring(delta1) = 24.988839 mm Compression of the inner spring(delta2) = 9.988839 mm Maximum torsional shear stress induced in the outer spring(tau1) = 375.305136 N/mm2 Maximum torsional shear stress induced in the inner spring(tau2) = 225.032219 N/mm2