(a)The exact moment of inertia of the rim considering difference of moment of inertia is
	I=1/2*mo*ro2 - 1/2*mi*ri2
I=293 kgm2

(b)/the approximate moment of inertia, considering the rim as a thin ring is:
	Iapprox=m*r2
Iapprox=288 kgm2

Percent error= 1.6