//Problem 14.02:

//initializing the variables:

//calculation:
//For this reaction
//R1 = CO2; 
//R2 = H2; 
//R3 = CH3OH; 
//R4 = H2O; 
n10 = 3
n20 = 1
n30 = 0
n40 = 1

printf("\n\nResult\n\n")
printf("\n n1 = %.0f - e\n n2 = %.0f - 3e \n n3 = %.0f + e \n n4 = %.0f + e",n10,n20,n30,n40)