clear;
clc;

// Example 2.3
printf('Example 2.3\n\n');
//Page no. 46
// Solution

//Basis 7.5 g mol of NaOH
m_NaOH = 40.0 ;//[lb]
lb = 454 ;//[g mol]
n = 7.50*1*m_NaOH/(lb*1);
printf('Number of pounds of NaOH is %.3f lb.\n',n);