clear ; clc; // Example 11.4 printf('Example 11.4\n\n'); // Page no. 322 // Solution fig E11.4 //Basis : M = 1000 lb M = 1000 ;//[lb] //Given F_s = 16/100 ;// Fraction of sugar in F F_w = 25/100 ;// Fraction of water in F F_p = 59/100 ; // Fraction of pulp in F D_p = 80/100 ; // Fraction of pulp in D E_s = 13/100 ;// Fraction of sugar in E E_p = 14/100 ;// Fraction of pulp in E G_p = 95/100 ;// Fraction of pulp in G H_s = 15/100 ;// Fraction of sugar in H K_s = 40/100 ;// Fraction of sugar in K // For crystallizer equations are K_w = 1 - K_s ;// summation of wt. fraction is 1 K = M/K_s ;// By sugar balance -[lb] L = K_w*K ;// By water balance -[lb] // For evaporator equations are H_w = 1- H_s ;//summation of wt. fraction is 1 H = K_s*K/H_s ;//By sugar balance -[lb] J = H - K; //By overall balance -[lb] // For screen equations are E_w = 1 - (E_p + E_s) ; // summation of wt. fraction is 1 // solve E and G by simultaneous eqn. obtained by overall and pulp balance a1 = [1 -1;E_p -G_p] ;// Matrix of coefficients of unknown b1 = [H;0] ;//Matrix of constants x1 = a1\b1 ;// Matrix of solutions ,x1(1) = E, x1(2) = G E = x1(1) ;//[lb] G = x1(2) ;//[lb] G_s = (E_s*E - H_s *H )/G ;// By sugar balance G_w = 1 -(G_s + G_p) ;// summation of wt. fraction is 1 // For mill equations are // solve F and D by simultaneous eqn. obtained by overall and pulp balance a2 = [1 -1;F_p -D_p] ;// Matrix of coefficients of unknown b2 = [E;E_p*E] ;//Matrix of constants x2 = a2\b2 ;// Matrix of solutions ,x2(1) = F, x2(2) = D F = x2(1) ;//[lb] D = x2(2) ;//[lb] D_s = (F_s*F - E_s *E )/D ;// By sugar balance D_w = 1 -(D_s + D_p) ; // summation of wt. fraction is 1 S_rec = M/(F*F_s) ; // Fraction of sugar recovered printf('\nFlow streams and their respective compositions.\n'); printf('\n M = %.0f lb \n',M); printf(' Sugar: %.2f \n',1); printf('\n L = %.0f lb \n',L); printf(' Water: %.2f\n',1); printf('\n K = %.0f lb \n',K); printf(' Sugar: %.2f\n',K_s); printf(' Water: %.2f\n',K_w); printf('\n J = %.0f lb \n',J); printf(' Water: %.2f \n',1); printf('\n H = %.0f lb \n',H); printf(' Sugar: %.2f\n',H_s); printf(' Water: %.2f\n',H_w); printf('\n G = %.0f lb \n',G); printf(' Sugar: %.3f\n',G_s); printf(' Water: %.3f\n',G_w); printf(' Pulp : %.2f\n',G_p); printf('\n E = %.0f lb \n',E); printf(' Sugar: %.2f\n',E_s); printf(' Water: %.2f\n',E_w); printf(' Pulp : %.2f\n',E_p); printf('\n D = %.0f lb \n',D); printf(' Sugar: %.3f\n',D_s); printf(' Water: %.3f\n',D_w); printf(' Pulp : %.2f\n',D_p); printf('\n F = %.0f lb \n',F); printf(' Sugar: %.2f\n',F_s); printf(' Water: %.2f\n',F_w); printf(' Pulp : %.2f\n',F_p);