clear; clc; // Illustration 10.7 // Page: 525 printf('Illustration 10.7 - Page: 525\n\n'); // solution //****Data****// // c:Water d:Toulene Density_c = 998;// [kg/cubic m] viscosity_c = 0.95*10^(-3);// [kg/m.s] Dc = 2.2*10^(-9);// [square m/s] Density_d = 865;// [kg/cubic m] viscosity_d = 0.59*10^(-3);// [kg/m.s] Dd = 1.5*10^(-9);// [square m/s] sigma = 0.022;// [N/m] Dist = 20.8;// [Distribution Coeffecient] d = 0.5;// [m] h = 0.5;// [m] di = 0.15;// [m] N = 13.3;// [r/s] g = 9.81;// [m/s^2] qC = 3*10^(-3);// [cubic m/s] qD = 3*10^(-4);// [cubic m/s] //********// V = %pi*h*d^2/4;// [Vessel volume,cubic m] phi_DF = qD/(qD+qC);// [Volume fraction toulene] // Assume: phi_Dbyphi_DF = 0.9; phi_D = phi_Dbyphi_DF*phi_DF; phi_W = 1-phi_D; // From Eqn. 10.56: Density_M = (Density_c*phi_W)+(Density_d*phi_D);// [kg/cubic m] if phi_W>0.4 viscosity_M = (viscosity_c/phi_W)*(1+(6*viscosity_d*phi_D/(viscosity_d+viscosity_c)));// [kg/m s] else viscosity_M = (viscosity_c/phi_D)*(1-(1.5*viscosity_c*phi_W/(viscosity_d+viscosity_c)));// [kg/m s] end // Impeller Reynold's Number: IRe = (di^2*N*Density_M/viscosity_M); // From Fig 6.5 (Pg 152), curve g: Po = 0.72; P = Po*Density_M*N^3*di^5;// [W] // From Eqn. 10.61: Value1 = P*qD*viscosity_c^2/(V*sigma^3); Value2 = viscosity_c^3/(qD*Density_c^2*sigma); Value3 = Density_c/(Density_c-Density_d); Value4 = sigma^3*Density_c/(viscosity_c^4*g); Value5 = viscosity_d/viscosity_c; phi_Dbyphi_DF = 3.39*Value1^0.247*Value2^0.427*Value3^0.430*Value4^0.401*Value5^0.0987; // The value of phi_Dbyphi_DF is sufficiently close to the value 0.90 assumed earlier. phi_D = phi_Dbyphi_DF*phi_DF; // From Eqn. 10.6: Value6 = viscosity_c/Density_c;// [square m/s] Value7 = P/(V*Density_M); Value8 = sigma/Density_c; dp = 10^(-2.066+(0.732*phi_D))*Value6^0.0473*Value7^(-0.204)*Value8^(0.274);// [m] a = 6*phi_D/dp;// [square m/cubic m] Sca = viscosity_c/(Density_c*Dc); // From Eqn. 10.65: Shc = 65.3; kLc = Shc*Dc/dp;// [kmol/square m s (kmol/cubic m)] thetha = V/(qD+qC);// [s] // From Table 10.1 (Pg 524): // lambda = [lambda1 lambda2 lambda3] lambda = [1.359 7.23 17.9]; // B = [B1 B2 B3] B = [1.42 0.603 0.317]; Val = zeros(1,3); Sum = 0; for n = 1:3 Val(n) = (B(n)^2)*exp((-lambda(n))*64*Dd*thetha/dp^2); Sum = Sum+Val(n); end // From Eqn. 10.66: kLd = -(dp/(6*thetha))*log((3/8)*Sum); mCD = 1/Dist; // From Eqn. 10.67: KLd = 1/((1/kLd)+(1/(mCD*kLc)));// [kmol/square m s (kmol/cubic m)] Z = 0.5;// [m] Vd = qD/(%pi*Z^2/4);// [m/s] // From Eqn.10.70: NtoD = Z/(Vd/(KLd*a)); // From Eqn. 10.71: EMD = NtoD/(NtoD+1); printf("Expected stage efficiency: %f\n",EMD);