//A tram car //refer fig.16.8 (a),(b) and (c) //frictional resistance W=120 //kN F=5*120/1000 //kN v=(20*1000)/(60*60) //m/sec // (1) on level track P1=F //kN //output power Pw1 Pw1=P1*v //kW eta1=0.8 //input power Ip1 Ip1=Pw1/0.8 //kW // (2) Up the plane P2=F+W*(1/300) //kN //output power required Pw2 Pw2=P2*v //kW //Input power of engine Ip2 Ip2=Pw2/0.8 //kW // (3) Down the incline plane Pd=F-W*(1/300) Pwd=0.2*5.5556 //kW //Input power Ipd=1.1111/0.8 //kW printf("\On level track Input Power=%.3f kW\nUp the plane Input Power=%.3f kW\nDown the incline plane Input Power=%.3f kW",Ip1,Ip2,Ipd)