// Book - Power System: Analysis & Design 5th Edition // Authors - J. Duncan Glover, Mulukutla S. Sharma, Thomas J. Overbye // Chapter - 5 : Example 5.6 // Scilab Version 6.0.0 : OS - Windows clc; clear; N = 4; // Number of Conductors l = 300; // Line lenght in km s = 1272000; // Size of the conductor in cmil Vs1 = 765; // Sending end voltage in kV V = 765; // Base Voltage Vr1 = 0.95*765; // Receiving end voltage in kV delta = 35; // Phase angle in degree Z1 = 97; // Absolute line paramter value in Ohm from Ex 5.5 thetaZ = 87.2; // Angle value of Parameter B in radians from Ex 5.5 A = 0.9313; // Absolute line paramter value in per unit from Ex 5.5 thetaA = 0.209; // Angle value of Parameter A in degree from Ex 5.5 Pr = (((Vr1*Vs1)/Z1)*cosd(thetaZ-delta))-(((A*(Vr1)^2)/Z1)*cosd(thetaZ-thetaA)); // The real power delivered to the receiving end in MW SIL = 2199; // Surge Impedance Load in MW taken from Ex 5.5 L = 1.49; // Loadability in per unit of SIL taken from fig 5.12 LL = L*SIL; // Practical Line loadability in MW using fig. 5.12 pf = 0.986; // Power factor IRFL = Pr/(sqrt(3)*Vr1*pf); // Full load receiving end current in kA A = 0.9313*exp(%i*0.209)*(%pi/180); // Line parameter value in per unit taken from Ex 5.2 B = 97.0*exp(%i*87.20)*(%pi/180); // Line parameter value in Ohm taken from Ex 5 theta = acos(pf); Irfl = 2.616*exp(%i*theta); Vs2 = Vs1/sqrt(3); // line Voltage in kV a = 0.8673; // coefficient of second order Vrfl from the equation in part c b = -54.24; // coefficient Vrfl from the equation in part c c = -130707.89; // coefficient constant from the equation in part c Vrfl = (-b+sqrt((b^2)-(4*a*c)))/(2*a); // Vrfl value from the 2nd order Quadratic equation Vrfl2 = Vrfl*sqrt(3); // Full load receiving end voltage in kVLL VRFL = Vrfl2/V; // Full load receiving end in per unit absA = 0.9313; // Absolute value of A taken from Ex 5.2 VRNL = V/absA; // The receiving end no load voltage in kVLL taken from 5.1.19 PercentVR = ((VRNL-Vrfl2)/Vrfl2)*100; // Full load voltage in percent J = N*1.2; // Approximate Current carrying capacity of 4 ACSR conductors in kA taken From table A.4 printf('\nPractical line loadability is (LL) = %0.0f MW', Pr); printf('\nFull load receiving end current is (Irfl) = %0.3f kA', IRFL); printf('\nFull load receiving end voltage is (VRFL) = %0.3f per unit', VRFL); printf('\nThe receiving end no load voltage is (VRNL) = %0.1f kVLL', VRNL); printf('\nFull load voltage is (PercentVR) = %0.2f Percent', PercentVR); printf('\nApproximate Current carrying capacity of 4 ACSR conductors is (J) = %0.1f kA', J);