// Example 16_15 clc;funcprot(0); // Given data M_in=0.890;// The inlet Mach number p_osi=314.7;// kPa p_ose=249.3;// kPa k=1.40;// The specific heat ratio // Calculation // (a) n_D=(((((1+((((k-1)/2)*M_in^2)))*(p_ose/p_osi)^((k-1)/k)))-1)/(((k-1)*M_in^2)/2))*100;// % // (b) p_i=p_osi/((1+(((k-1)/2)*M_in^2))^(k/(k-1)));// kPa C_p=(p_ose-p_i)/(p_osi-p_i);// The diffuser’s pressure recovery coefficient printf("\n(a)The diffuser’s efficiency,n_D=%2.1f percentage \n(b)The diffuser’s pressure recovery coefficient,C_p=%0.3f",n_D,C_p);