//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex7_4.sce. clc; clear; P=75e3; //power rating of transformer in KVA Np=500; //number of Primary turns Ns=100; //number of secondary turns rp=0.4; //primary winding resistance in ohms rs=0.02; //secondary winding resistance in ohms xp=1.5; //primary winding leakage reactance in ohms xs=0.045; //secondary winding leakage reactance in ohms Vs=2200; //supply voltage in volts //case1 printf("\n (a)") Re=rp+(Np/Ns)^2*rs; //Equivalent resistance in ohms Xe=xp+(Np/Ns)^2*xs; //Equivalent leakage reactance in ohms Ze=sqrt(Re^2+Xe^2); printf("\n Equivalent impedance referred to prinmary side=%1.3f ohms\n",Ze) //case2 printf("\n (b).1") I1=P/Vs; //full load primary current in A cos_pi2=0.8; sin_pi2=sind(acosd(0.8)); percentage_voltage_reg=((I1*((Re*cos_pi2)+(Xe*sin_pi2)))/Vs)*100; printf("\n Voltage regulation for 0.8 power factor lagging=%1.2f percentage \n",percentage_voltage_reg) NL_secondary_voltage=(Ns/Np)*Vs; //NL means "no load" del_V=(NL_secondary_voltage*percentage_voltage_reg)/100; FL_secondary_voltage=(NL_secondary_voltage)-(del_V); printf("\n Secodary terminal voltage at FL 0.8 power factor lagging=%3.3f V \n",FL_secondary_voltage) //case3 printf("\n (b).2") percentage_voltage_reg=((I1*((Re*cos_pi2)-(Xe*sin_pi2)))/Vs)*100; printf("\n Voltage regulation for 0.8 power factor leading=%1.3f percentage \n",percentage_voltage_reg) del_V=(NL_secondary_voltage*percentage_voltage_reg)/100; FL_secondary_voltage=(NL_secondary_voltage)-(del_V); printf("\n Secodary terminal voltage at FL 0.8 power factor leading=%4.4f V \n",FL_secondary_voltage) //The anwser vary dueto roundoff error