clear
//Given
Rh=1.097*10**7                         ///m
h=6.63*10**-34
c=3*10**8
n=2.0
n1=4.0

//Calculation
E=(h*c*Rh*(1/n**2-1/n1**2))/1.6*10**-19

//Result
printf("\n Minimum energy is %0.2f  ev",E*10**38)