clear//

//Variables

I1 = 0.5 * 10**-3          //Diode current1 (in Ampere)
V1 = 340 * 10**-3          //Voltage1 (in volts)
I2 = 15 * 10**-3           //Diode current2 (in Ampere)
V2 = 440 * 10**-3          //Voltage2 (in volts)

//Calculation

n = 4/log(30)                //By solving both the given equations

//Result

printf("\n Value of n is  %0.2f .",n)